Trigonal deformations of rank one and Jacobians
Valentina Beorchia, Gian Pietro Pirola, Francesco Zucconi

TL;DR
This paper investigates special infinitesimal deformations of trigonal curves that preserve certain structures, revealing that for high genus or general conditions, the deformation space is very limited, and it clarifies relations between Jacobians and hyperelliptic loci.
Contribution
It characterizes the infinitesimal deformations of trigonal curves with rank 1 IVHS, completing previous results and identifying the hyperelliptic locus as a unique sub-locus with specific Jacobian domination properties.
Findings
Deformation locus is zero dimensional for genus ≥8 or genus 6,7 with Maroni generality.
The hyperelliptic locus is the only 2g-1-dimensional sub-locus with Jacobian domination.
Confirmed and extended results of Naranjo and Pirola regarding Jacobian structures.
Abstract
In this paper we study the infinitesimal deformations of a trigonal curve that preserve the trigonal series and such that the associate infinitesimal variation of Hodge structure (IVHS) is of rank 1. We show that if the genus g is greater or equal to 8 or g=6,7 and the curve is Maroni general, this locus is zero dimensional. Moreover, we complete a result of Naranjo and Pirola. We show in fact that if the genus g is greater or equal to 6, the hyperelliptic locus is the only 2g-1-dimensional sub-locus Y of the moduli space of curves of genus g, such that for the general element [C] in Y, its Jacobian J(C) is dominated by a hyperelliptic Jacobian of genus g' greater or equal to g.
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Trigonal deformations of rank one
and Jacobians
Valentina Beorchia, Gian Pietro Pirola and Francesco Zucconi
Dipartimento di Matematica e Geoscienze, Dipartimento di Eccellenza 2018-2022, Università di Trieste, via Valerio 12/b, 34127 Trieste, Italy, ORCID ID 0000-0003-3681-9045, [email protected]
Dipartimento di Matematica, Dipartimento di Eccellenza 2018-2022, Università di Pavia, Via Ferrata 1, 27100 Pavia, Italy, [email protected]
Dipartimento di Scienze Matematiche, Informatiche e Fisiche, Università degli studi di Udine, 33100 Udine, Italy, [email protected]
Abstract.
In this paper we study the infinitesimal deformations of a trigonal curve that preserve the trigonal series and such that the associate infinitesimal variation of Hodge structure (IVHS) is of rank We show that if or and the curve is Maroni general, this locus is zero dimensional. Moreover, we complete the result [NP, Theorem 1.6]. We show in fact that if , the hyperelliptic locus is the only -dimensional sub-locus of the moduli space of curves of genus , such that for the general element , its Jacobian is dominated by a hyperelliptic Jacobian of genus .
Introduction
Let be the locus in the moduli space of smooth curves of genus given by points such that is a trigonal curve, that is admits a triple covering of and is not hyperelliptic.
In this paper we study infinitesimal deformations which come from families of trigonal curves and in particular the ones having the associated infinitesimal variation of Hodge structure (IVHS) of rank
Our main motivation was to complete the characterization of -dimensional families of curves with Jacobian family dominated by a hyperelliptic Jacobian family. Indeed in [NP, Theorem 1.6] it is shown that if is a -dimensional closed irreducible subvariety of with , such that the Jacobian of its generic element is dominated by a hyperelliptic Jacobian, then , where denotes the hyperelliptic locus, or . In this paper we rule out the trigonal case. Our main result is the following:
Theorem 0.1**.**
If then is the unique closed irreducible subvariety of dimension such that for its generic element there exists such that .
We point out that, in principle, we have to consider all the codimension- subvarieties of The argument goes as follows. If is smooth and trigonal the Babbage-Enriques-Petri theorem gives that the intersection of all the quadric that contain the canonical image of is a ruled surface This surface can be also embedded, by an extension of the bicanonical morphism of , in the projective space , where is the tangent sheaf of . We identify with the tangent space of at , by possibly adding a level structure or by considering the moduli stack , if is a singular point of the moduli space. By the work of Griffiths, the points of the surface correspond to the locus of infinitesimal deformations with IVHS of rank one (see [Gri1]) and Lemma 3.2).
Now, in [NP, Proof of Theorem 1.6, p.13 ], it is shown that, under the conditions of theorem (0.1), if , then for the generic there must exist a non-degenerate rational curve which corresponds to a dimensional component of the intersection , where is the tangent space to the trigonal locus at . We show that cannot contain such a , by analysing the geometry on the Hirzebruch surface isomorphic to . We recall that the integer is classically called the Maroni invariant of ; we shall perform our study in terms of the Maroni degree for trigonal curves, that is in terms of the degree of a non positive section in the extended canonical embedding in , see subsection 2. We show:
Theorem 0.2**.**
If , or and Maroni degree , or and , then has dimension [math].
The proof will follow from Proposition 3.12 and Proposition 3.14.
In the special cases and we need to deepen our analysis. We consider the locus of trigonal curves with Maroni degree and we define the intersection . We show:
Theorem 0.3**.**
If or and Maroni degree and is generic, then is irreducible and has dimension [math].
Moreover, if is reducible, then does not contain any rational curve , such that is nondegenerate.
The result will be a consequence of Proposition 4.2 for and Proposition 4.3 if
From the two theorems we deduce that there are no non-degenerate rational curve , which implies our main result.
Our point of view is also related to problems concerning the relative irregularity of families of curves, see for instance [BGN],[FNP],[GST], and [Gon], since our result gives an infinitesimal version of a result of Xiao [X, Corollary 4, page 462]. To shorten the paper we do not include this here as well as some partial computation on genus case, but we only finally remark that hopefully, this can shed some new light on the slope problem as treated in [BZ1] and [BZ2].
Acknowledgments: The authors are grateful to Juan Carlos Naranjo for some useful conversations.
The authors are members of GNSAGA of INdAM.
The first and third authors are supported by national MIUR funds, PRIN project Geometria delle varietà algebriche (2015).
The first author is also supported by national MIUR funds Finanziamento Annuale Individuale delle Attività Base di Ricerca - 2018.
The second author is partially supported by PRIN project Moduli spaces and Lie theory (2015) and by MIUR: Dipartimenti di Eccellenza Program (2018-2022) - Dept. of Math. Univ. of Pavia.
The third author is supported by Università degli Studi di Udine - DIMA project Geometry PRID ZUCC 2017.
2010 Mathematics Subject Classification: 14J10, 14D07.
1. A Gaussian lemma
Let be a smooth curve and let be line bundle of degree on . Consider a base point free linear system subspace . We can associate two objects with , the Gaussian section and the Euler class, which we recall.
Let be the projective morphism given by and
[TABLE]
the exact sequence associated with its differential. We tensor it by the canonical sheaf :
[TABLE]
Then we can consider the section
[TABLE]
obtained as the image of , and represents the differential .
Definition 1.1**.**
We call the Gaussian section of the morphism .
We want to relate to the Euler class whose definition we briefly recall.
It is well known that and that the Euler sequence
[TABLE]
is given by a non trivial class . The pull-back to of the Euler sequence gives
[TABLE]
The extension class of the sequence (3) determines an element : we call it the Euler class of .
Following [ACG, Page 804], we recall that to a line bundle on a smooth curve we can associate a sheaf , determined by the Chern class . Let
[TABLE]
be the extension determined by .
By taking into account the sequence (1), we get a commutative diagram
[TABLE]
and we observe that the differential determines a map of complexes, and the image of the bottom extension is the upper extension.
Lemma 1.2**.**
(Gaussian Lemma)* Consider the natural map given by the cup product and duality*
[TABLE]
Then we have
[TABLE]
As a consequence, the Gaussian section does not belong to the image of the map
[TABLE]
Remark 1.3**.**
We will use Lemma 1.2 in the case where induces a on . We stress that if then the ramification scheme of is the zero locus of the Gaussian section, which is a section
[TABLE]
2. Trigonal curves and Gaussian sections
Let be a canonical trigonal curve of genus which has no and let be its graded ideal. By the Babbage-Enriques-Petri theorem the hyperquadrics containg intersect in a smooth rational ruled surface of minimal degree in and the trigonal series is cut on by the ruling of .
Let us fix some notations and recall some known results concerning the Hirzebruch surfaces . The Picard group of satisfies , where is a section of minimal self-intersection and a fiber in the ruling of the projection . The basic intersection formulae are:
[TABLE]
Definition 2.1**.**
Let be a trigonal curve of genus and let be the line bundle of degree computing the unique trigonal series. We set . The Maroni degree of can be characterized as the unique number such that
[TABLE]
The following bounds on have been established by Maroni [M] and are well known
[TABLE]
It turns out that is an embedding of the Hirzebruch surface via the linear system . Moreover we have
[TABLE]
We recall that . We recall that a class is ample if and only if and , that is , and respectively nef if . Finally, if , then is big and nef.
The following results will be useful in the sequel:
Lemma 2.2**.**
If and , then the multiplication map
[TABLE]
is surjective.
Proof.
Set . We tensor the sequence
[TABLE]
by where and . By the free pencil trick the cokernel of injects into which is the dual of by Serre duality and the fact that the canonical divisor is . By the hypotheses on and , the divisor is big and nef, therefore . ∎
Proposition 2.3**.**
The map is surjective.
Proof.
As in the proof of Lemma (2.2) we only need to show that . By the remarks above we have . It is easy to show that is -connected, gives a morphism to a surface. We conclude by applying Ramanujam’s vanishing theorem[R]. ∎
Now consider the exact sequence:
[TABLE]
and the restriction map
[TABLE]
Now let us observe that in the trigonal case, the Gaussian section .
Corollary 2.4**.**
The Gaussian section does not belong to the image of .
Proof.
By contradiction assume that . By Proposition 2.3 we have which would imply that belongs to the image of the multiplication map . This is in contradiction with the Gaussian Lemma 1.2. ∎
3. The locus of rank infinitesimal deformations
Let be the degree two part of the homogeneous ideal of a trigonal canonical curve , and let be the ruled surface. By a simple computation we see that
[TABLE]
If we consider the bicanonical map
[TABLE]
we observe that it extends to an embedding . Since is not hyperelliptic, the multiplication map
[TABLE]
is surjective. By definition the kernel of is . By Serre duality we obtain:
[TABLE]
The inclusion is given by where is the quadric associated with the co-boundary homomorphism
[TABLE]
of the extension class ; see [Gri1].
Definition 3.1**.**
We define the rank of as the rank of its associated quadric .
By the standard properties of the Veronese embedding
[TABLE]
it follows that
[TABLE]
We have:
Lemma 3.2**.**
The image of the embedding of satisfies:
[TABLE]
Proof.
It follows from the sequence (12) and its dual. See also: [Gri1, p. 271]. ∎
3.1. Trigonal deformations of rank
In the present section we shall study the locus of corresponding to deformations which preserve the property of having a trigonal series.
As in the Introduction we denote by the trigonal locus and let be the locus of trigonal curves with Maroni degree . We define
[TABLE]
the tangent spaces to respectively and at .
Consider the natural homomorphism
[TABLE]
given by the cup-product . It holds:
Lemma 3.3**.**
If then
[TABLE]
Proof.
Let be the infinitesimal family associated with . Since , the trigonal morphism lifts to . By standard arguments it follows that the Gaussian section lifts to . This implies that the cup product . Since and since the cup product is easily seen to be surjective by dualizing the map, we have that
[TABLE]
On the other hand . Then the claim follows. ∎
Remark 3.4**.**
Dually, the annihilator of in is , where is the ramification divisor.
By taking into account the isomorphisms in (11), such a space corresponds to the subspace
[TABLE]
where is the ideal sheaf of the subscheme .
We shall denote by
[TABLE]
Next we would like to determine the intersection of with the surface .
Definition 3.5**.**
The locus is called the locus of trigonal deformation of rank .
3.2. Proof of Theorem 0.2
In what follows with we shall always denote the Maroni degree. For the reader’s convenience we fix the relations and classes in , which we shall use:
- •
is the ruling inducing the trigonal linear system on ;
- •
is a section of minimal self-intersection of , and ;
- •
is the tautological divisor of ;
- •
;
- •
is the hyperplane divisor of the canonical embedding, , and ;
- •
.
Recalling the bounds on given in (7), we shall distinguish two cases: or .
3.3. The case and : curves of even genus with Maroni invariant zero
We shall show that in this case the subscheme is a complete intersection of two divisors , and since , they determine a pencil in with base locus exactly ; as a consequence we will obtain that the base locus of satisfies .
Let be a trigonal curve of genus . In this case we have that
[TABLE]
Proposition 3.6**.**
If with , then the base locus of satisfies and .
Proof.
We observe that
[TABLE]
Indeed, we have
[TABLE]
and since , we have , so there is an isomorphism
[TABLE]
We consider in particular the pencil in , and the corresponding pencil in under the isomorphism (14). By construction we have the base locus . We claim that
[TABLE]
We first show that contains no divisors. If by contradiction it contains a divisor in some linear system with
[TABLE]
then we must have
[TABLE]
hence
[TABLE]
On the other hand, the base points of the moving part of the pencil must contain the residual part of , hence we must have
[TABLE]
This gives the inequality
[TABLE]
We observe that if , then (17) gives .
If , then by (17) and (15) we get ; in this case we would have and , but this is not the case since by Corollary 2.4 the Gaussian section .
Finally, observe that the case can not occur, as by construction the moving part of the pencil is not cut out by fibers of the ruling.
Therefore . Since , we get the statement of the Proposition.
∎
3.4. The case , and
The argument is similar to the one of the previous section. We shall show that in this case the subscheme is a complete intersection of two divisors and , and since , the bounds (7) imply and with the additional hypothesis we have also
[TABLE]
As a consequence we will obtain that the base locus of is .
Finally, we shall prove that in the remaining cases and , the linear system has a one dimensional fixed component.
Since we are assuming , the ruled surface admits a negative section .
Lemma 3.7**.**
There exists a unique divisor containing . Moreover we have
[TABLE]
and is not a component of .
Proof.
By observing that one can easily see that the restriction morphism is an isomorphism.
To prove the second claim, we note that . Since is big and nef, then . On the other hand we have , therefore , which concludes the proof. ∎
Next we consider the linear system .
Lemma 3.8**.**
The restriction map is an isomorphism.
Proof.
Note that . The claim easily follows since is an irreducible curve and is a regular surface. ∎
Next we note that the sublinear system of has dimension
[TABLE]
Indeed, we have . Hence
[TABLE]
By Riemann Roch for curves the claim follows.
Now we consider the sublinear system on which is isomorphic to the sublinear system on .
Corollary 3.9**.**
There exists such that
[TABLE]
Proof.
Note that is a -dimensional sublinear system of . Hence by (19) the claim follows. ∎
Proposition 3.10**.**
The divisors and have no common component.
Proof.
Assume by contradiction that there exists a component such that and where and .
We observe that can not be a bisecant divisor on . Indeed, we first note that we can’t have , since by Corollary 3.9.
Assume now that
[TABLE]
for some . As is a subscheme of both and and as , it would follow that is necessarily a subscheme of .
On the other hand, we have by construction, so the relations in (20) would imply that the subscheme is contained in , which is a contradiction.
Next we claim that we have the following bounds:
- (1)
if , then ; 2. (2)
if , then .
Indeed, as is the base locus of , we have in particular . Consider the sublinear system
[TABLE]
The subscheme of is contained in the base locus of . Hence we have
[TABLE]
Assume now and . In this case . This would imply that there exists a fiber of such that the subscheme of contains the subscheme , that is a divisor in the trigonal series. This is impossible.
Finally, assume and . In this case where . Since , then where . This implies that . Then and this contradicts Lemma 2.4.
∎
Corollary 3.11**.**
The subscheme is a complete intersection of and .
As a consequence we have .
Proof.
We have . Since is a subscheme both of and and it is of length , the claim follows.
Finally, as can be embedded in by multiplication of a base point free linear system we have the last assertion. ∎
3.5. Proof of Theorem 0.3
In this section we shall treat the remaining cases and .
Proposition 3.12**.**
If and then the base locus od satisfies
[TABLE]
Proof.
In this case we have , and , where denotes the tautological divisor of .
Note that . Since , and , by computing the cohomology of it easily follows that it exists a unique such that . ∎
We can describe very explicitly the linear subspace . Let be a basis of the pencil and let be an irreducible section. If then any trigonal curve can be written with an equation of the type
[TABLE]
where are general homogeneous polynomials of degree , so that is smooth. A simple computation shows that
[TABLE]
Remark 3.13**.**
By Proposition 3.12 we can write:
[TABLE]
Proposition 3.14**.**
If and then we have
[TABLE]
Proof.
In this case we have , , . This case differs from the analogue case where because all quadrics vanishing on actually vanish also on a scheme of length on ; note that . We observe that the point is a subscheme of So we can conclude in a similar way as in Proposition 3.12. ∎
Remark 3.15**.**
Note that if and , by Proposition 3.14 we can write:
[TABLE]
4. Hyperelliptic families and trigonal deformations
Let be a closed irreducible subvariety where and . Assume that for a very general there exists a dominant morphism where belongs to the hyperelliptic locus , . By standard arguments we can assume the existence of a family of surjective maps of Jacobians:
[TABLE]
such that the moduli map induces a generically finite dominant map . Moreover we can also assume that and , for every . Let be the isomorphic image of via the codifferential of . In [NP, Proof of Theorem 1.6, p. 13] they show that if is not hyperelliptic there exists a rational dominant map where is a curve contained in the locus of rank trigonal deformations of .
Proposition 4.1**.**
If or and then is the unique closed irreducible subvariety of dimension such that for its generic element there exists such that .
Proof.
Assume that the general is not hyperelliptic. By [NP, Theorem] it follows that is trigonal. In particular the curve recalled above is a curve contained inside the fix part of . This contradicts Corollary 3.11. ∎
4.1. Rational curves of rank- trigonal deformations
If and there can exist rational curves in the locus of rank trigonal deformations, but we claim that they cannot be non degenerate. By [NP, Theorem] and by Proposition 4.1, to show our claim, we have to study the rational curves inside the schematic intersection
[TABLE]
where . Note that must be a proper subscheme of .
Proposition 4.2**.**
If , and is generic then is smooth, irreducible and is a finite scheme. Moreover if is reducible then does not contain any non degenerate curve.
Proof.
By Proposition 3.12 and the explicit equations (21) and (22) the first claim follows. Assume now that is smooth but non generic and that is a union of at least two components. By Lemma 2.4, cannot contain as one of its components. Hence where since is not a subdivisor of . This implies that both components of are degenerate curves for the embedding . In particular does not contain non degenerate rational curves. ∎
Proposition 4.3**.**
If , then either is irreducible or if it is reducible it does not contain any non degenerate rational curve. In particular does not contain any non degenerate rational curve.
Proof.
The proof is similar to the one of Proposition 4.2 by using Proposition 3.14. ∎
4.2. The proof of the main Theorem 0.1
By Proposition 4.1 we have to consider only the cases where , . We consider the diagram (23). Note that is a nondegenerate curve since it is obtained by projection of the canonical image of which is a rational normal curve since is hyperelliptic. On the other hand we also have . By Proposition 4.2 and by Proposition 4.3 we see that such a non degenerate curve cannot exist.
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