# The effect of the neutron and proton numbers ratio in colliding nuclei at formation of the evaporation residues in the $^{34}$S+$^{208}$Pb and $^{36}$S+$^{206}$Pb reactions

## TL;DR

This paper investigates how the neutron-to-proton ratio in colliding nuclei influences the formation of evaporation residues, highlighting differences in capture cross sections and fusion barriers between sulfur-lead reactions.

## Contribution

It provides a detailed analysis of the impact of N/Z ratios on fusion barriers and capture cross sections in specific sulfur-lead nuclear reactions, introducing a model based on DNS and transport equations.

## Key findings

- Higher capture cross section for $^{36}$S+$^{206}$Pb due to more attractive potential.
- Lower intrinsic fusion barrier $B^*_{fus}$ for $^{36}$S+$^{206}$Pb.
- N/Z ratio differences affect the fusion process via nucleon transfer.

## Abstract

The difference between observed cross sections of the evaporation residues (ER) of the $^{34}$S+$^{208}$Pb and $^{36}$S+$^{206}$Pb reactions formed in the 2n and 3n channels has been explained by two reasons related with the entrance channel characteristics of these reactions. The first reason is that the capture cross section of the latter reaction is larger than the one of the $^{34}$S+$^{208}$Pb reaction since the nucleus-nucleus potential is more attractive in the $^{36}$S+$^{206}$Pb reaction due to two more neutrons in isotope $^{36}$S. The second reason is the difference in the heights of the intrinsic fusion barrier $B^*_{\rm fus}$ appearing on the fusion trajectory by nucleon transfer between nuclei of the DNS formed after the capture. The value of $B^*_{\rm fus}$ calculated for the $^{34}$S+$^{208}$Pb reaction is higher than the one obtained for the $^{36}$S+$^{206}$Pb reaction. This fact has been caused by the difference between the $N/Z$-ratios in the light fragments of the DNS formed during the capture in these reactions. The $N/Z$-ratio has been found by solution of the transport master equations for the proton and neutron distributions between fragments of the DNS formed at capture with the different initial neutron numbers $N=18$ and $N=20$ for the reactions with the $^{34}$S and $^{36}$S, respectively.