The Beltrami Equation with Parameters and Uniformization of Foliations with Hyperbolic Leaves
Arseniy Shcherbakov

TL;DR
This paper studies foliations of compact complex manifolds with hyperbolic leaves, establishing conditions under which a fiberwise homeomorphism exists, reducing the problem to a Beltrami equation with parameters.
Contribution
It introduces a new approach to uniformization of foliations with hyperbolic leaves via solving a parameter-dependent Beltrami equation.
Findings
Existence of a finitely smooth fiberwise homeomorphism in generic cases.
Reduction of the uniformization problem to a Beltrami equation with controlled coefficient growth.
Application to foliations with negative tangent line bundle on complex manifolds.
Abstract
We consider foliations of compact complex manifolds by analytic curves. We suppose that the line bundle tangent to the foliation is negative. We show that in a generic case there exists a finitely smooth homeomophism, holomorphic on the fibers and mapping fiberwise the manifold of universal coverings over the leaves passing through some transversal onto some domain in with continuous boundary. depending on the leaves. The problem can be reduced to a study of the Beltrami equation with parameters on the unit disk in the case, when derivatives of the corresponding coefficient Beltrami grow no faster than some negative power of the distance to the boundary of the disk.
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Taxonomy
TopicsAdvanced Differential Equations and Dynamical Systems · Holomorphic and Operator Theory · Meromorphic and Entire Functions
The Beltrami equation with parameters and uniformization of holomorphic foliations
with hyperbolic leaves††thanks: The work was supported by grant RFBR 16-01-00748.
A.A. Shcherbakov E-mail: [email protected]
MSC: 32Q30 (53C12)
Key words: foliations, Beltrami equation, almost complex structures
Introduction
Let be a complex manifold. We say that a foliation with singularities is defined on if there exists an analytic subset of codimension at least two and a foliation of its complement by analytic curves that cannot be extended to a neighborhood of any point of . A foliation can be locally defined by polynomial vector fields. In generic case the singular set consists of isolated points.
A covering manifold of leaves of a foliation was defined in [Il1], [Il2]. Let be a foliation with singularities on a complex manifold and let be transversal cross-section. Let be a leaf passing through a point and let be the universal covering over this leaf with the marked point . Define . It is shown in [Il1], [Il2] that at least in affine case or, in more general Stein case, a topology and a complex structure on this union can be defined so that it is a complex manifold with locally biholomorphic projection and a holomorphic section right inverse to the holomorphic retraction . For any leaf the restriction of to is the universal covering map over . For a foliation of a compact manifold the manifold of universal coverings can be non-Hausdorff but in a generic case it is Hausdorff (see [Br1], [Br2]). It is possible to define a Hausdorff universal covering for general foliations of compact Kahler manifolds if we include the singular points in the leaves in some not generic cases ([Br1], [Br3]) but here we don’t consider such situations.
Let be the linear bundle tangent to the leaves. If this bundle is negative, then there exists an hermitean metric on and restriction of this metric on each leaf has a negative curvature. For generic such foliation each leaf is hyperbolic ([Gl1] or [LN]). In particular, it’s true for a generic foliation of . The uniformizing map of every leaf is unique modulo authomorphisms of the disk, and after some normalization (to get uniqueness) we may ask: how the uniformizing map of depends on the point ? Equivalently, we may put on every leaf its Poincare metric, i. e., the unique complete hermitian metric of curvature -1 and ask about dependence of this metric on the point . It is known that the Poincare metric is continuous [V] and even Holder-continuous [DNS]. The simultaneous uniformization conjecture states that there exists an analytic in biholomorphizm of onto an appropriate -depending domain on the Riemann sphere. It is known that this conjecture is wrong for general foliation in dimension of more than two or even for foliations of general two-dimensional manifolds [Gl2]. It is not known is this conjecture true or not for generic foliations of or .
One of the main problems of the theory of holomorphic foliations is the problem of analytic continuation of the Poincare map defined on a transversal to the leaves and the related problem of the persistence of cycles. It was shown in [Il3] that these problems have the positive solution if there exists an analytic simultaneous uniformization and the image domains continuously depend on the initial conditions. In the absence of an analytic simultaneous uniformization we can consider the results below as its more feeble version. We hope that these results can be useful in following attempts to clear the situation with the persistence problems. Though the situation can not be simple. There exists examples of the non-extendability of the Poincare map though for rather special cases [CDFG].
There were shown in [Sh1], [Sh2] that for generic foliation with negative we can define the complex structure on as an almost complex structure on the product ( is the unit disk) and this almost complex structure can be defined by forms of type (1,0)
[TABLE]
[TABLE]
where is the dimension of , are charts on and correspondingly, is a smooth vector-function, , is a smooth function satisfying the estimate for some non-negative . I.e., we can say that this almost complex structure is quasiconformal on each fiber.
The conclusion made in [Sh1] that the Poincare metric smoothly depends on a base point isn’t correct because there isn’t satisfied the sufficient condition: uniform boundedness along the fibers of derivatives with respect to the parameters, i.e., to the coordinates on the base (see [AhB]). It was shown by B. Deroin that the Poincare metric isn’t smooth for the foliation of a neighborhood of a hyperbolic singular point.
However in a generic case there exists a finitely smooth map holomorphic on the fibers and mapping each fiber on a bounded domain in continuously depending on a base point. Moreover, there exist estimates for derivatives of this map similar to the estimates of and obtained in [Sh2]. Now we formulate our main result. We denote by any derivative with respect to the variable of the total order .
Theorem 1
Suppose is a compact complex manifold of dimension and is a holomorphic foliation of with negative with . Suppose that the singular set is finite and in some neighborhood of each singular point the vector field locally defining the foliation is analytically linearizable and the linear part is diagonalizable. Let be a manifold of universal covering with simply connected base and let the complex structure on be defined by forms (0.1), (0.2). Then for every integer there exists a fiberwise map differentiable up to the order , holomorphic on the fibers, continuously depending on a base point in and satisfying the estimates
[TABLE]
[TABLE]
[TABLE]
Here is some uniform constant and is a constant depending on .
Since our complex structure is defined by forms (0.1), (0.2) the assertion that is holomorphic on the fibers means that satisfies the Beltrami equation . The proof of the theorem is based on the estimates obtained in [Sh2] and the present article can be considered as a continuation of that work. In fact, all that follows is a study of the Beltrami equation with a coefficient depending on parameters and satisfying the estimates of [Sh2].
1 Preliminary notes and the sketch of the proof
In what follows is the unit disk, is the disk or radii centered at zero, is the disk or radii centered at . Suppose is a function of a vector variable of dimension and of a scalar variable , and is a multi-index . We denote by or the derivative and define . Also, sometimes we shall use double multi-indexes and denote by or the derivatives . In this case we define . The main result of [Sh2] is the theorem about almost complex structures on manifolds of universal coverings:
Theorem ACS. Suppose is a compact complex manifold of dimension and is a holomorphic foliation of with negative . Suppose that the singular set is finite and in some neighborhood of each singular point the vector field locally defining the foliation is analytically linearizable and the linear part is diagonalizable. Let be a manifold of universal covering with a simply connected base . Then the complex structure on can be defined as an almost complex structure on the product ( is the unit disk) and this almost complex structure can be defined by forms (0.1), (0,2) of type (1,0). There is a smooth vector-function, is a smooth function and we have the estimates
[TABLE]
[TABLE]
[TABLE]
for any pair and multi-index . The constant in these estimates depends on or on , the constant doesn’t depend.
In fact, we don’t need in the exact exponent in estimate (1.2). It is enough only to know that this exponent is negative and depends only on . From the other hand, exact estimate (1.1) is essential.
Applying Theorem ACS, we can reformulate Theorem 1.
Theorem 1 (second formulation). Suppose is a compact complex manifold of dimension and is a holomorphic foliation of with negative . Suppose that the singular set is finite and in some neighborhood of each singular point the vector field locally defining the foliation is analytically linearizable and the linear part is diagonalizable. Let be a manifold of universal coverings with a simply connected base . Then for any the manifold is diffeomorphic by a -smooth fiberwise diffeomorphism to a domain having continuous boundary and fibered by topological disks . The domain is an image of under the diffeomorphism satisfying estimates (0.3) - (0.5). As a complex manifold is biholomorphic to the manifold supplied with an almost complex structure defined by the forms
[TABLE]
[TABLE]
where have the same sense as in (0.1), (0.2) and the vector-function satisfies the estimates
[TABLE]
for with the constants and depending only on .
Theorem 1 in either formulation reduces to the next theorem about the Beltrami equation with parameters:
Theorem 2
Suppose is a -smooth function of a variable and a vector variable belonging to some domain . Let satisfies the estimates
[TABLE]
[TABLE]
[TABLE]
for with constants and depending only on . Then there exists a solution to the Beltrami equation
[TABLE]
that is continuous in as a function of , is -smooth with respect to all variables, at every maps homeomorphically onto some bounded subdomain of , and satisfies the estimates
[TABLE]
[TABLE]
[TABLE]
The constants and depend only on .
The proof of this theorem starts in Section 2. Now we present some motivations for the below considerations and outline main steps of the proof.
Remind at first the classical construction of homeomorphic solutions to the Beltramy equation for a compactly supported (see, for example [Al] or [As]). Recall the definition of the classical integral operators acting on functions : the Cauchy transform
[TABLE]
and the Beorling transform
[TABLE]
Here is the usual measure on the -plane and the second integral we understand in terms of its principal value. The Cauchy transform is right inverse to the Cauchy-Riemann operator
[TABLE]
and
[TABLE]
If is a Holder conjugate pair, then the Cauchy transform extends to a bounded linear mapping from into . The Beorling transform extends to a continuous operator from to for all . The norm of this operator tends to 1 as (the Kalderon-Zygmund inequality).
Suppose has a compact support and . For every with a compact support there exists a unique solution to the inhomogeneous Beltrami equation
[TABLE]
with derivatives in and decay at infinity. We obtain this solution in the following way. The operator defined by the Neumann series
[TABLE]
is bounded in for close enough to 2. It is easy to see that
[TABLE]
is a solution to (1.9) and this solution has the required properties. We obtain a solution to the Beltrami equation if we put in (1.11) and set . It is an unique solution to the Beltramy equation with belonging to for close enough to 2 and normalized by the condition as . Such solution is called principal solution. We have
[TABLE]
In fact, the principal solution is a homeomorphism of the complex plane. At first suppose that . There is the solution to equation (1.9) with . We put
[TABLE]
Since near , it follows that and . Hence, belongs to and near . satisfies the Beltrami equation and, by uniqueness of the principal solution, we have . Further, and is a local homeomorphism. Since we can extend to by setting , we find that is a local homeomorphism and, hence, is a global homeomorphism by the monodromy theorem. For compactly supported measurable we approximate by convolutions in for proper and obtain the principal solution as a limit of smooth conformal mappings.
We can remove the restriction that is compactly supported and find a homeomorphism satisfying the Beltramy equation as a composition of solutions to the equations with the coefficients having supports in and in the closer of .
Now suppose . Applying the extension of by symmetry we obtain a unique -quasiconformal homeomorphism normalized by the conditions
[TABLE]
We call this map a normal solution or a normal mapping.
If smoothly depends on a parameter , then the principal solution and the normal solution aren’t necessarily -differentiable. The normal solution has -derivative only when has uniformly bounded -derivative ([AlB] or [Al]). Indeed, in general case we can’t differentiate, for example, series (1.10). The integrals and aren’t defined if grows sufficiently rapidly near the boundary of .
However, when derivatives of satisfy estimates (1.4), (1.5), we can attempt to find -differentiable solutions to the Beltramy equation if we replace the transforms and by integral operators with counter-items. Suppose . We define
[TABLE]
[TABLE]
Here we used the identity
[TABLE]
Define also
[TABLE]
[TABLE]
Again is right-inverse to the Cauchy-Riemann operator on and .
Definition 1
We say that a function on belongs to , if the function belongs to . We denote by the -norm of the function . A function belongs to if is uniformly bounded. We denote by the -norm of the function .
If , , then is a bounded mapping from into . The transform acts as continuous operator from to for all , . In what follows we shall prove these estimates in more general setting.
If satisfies estimates (1.4), (1.5) we can seek solutions to the Beltrami equation analogous to (1.12) or (1.13) replacing the operators and by and correspondingly. That is, we can write
[TABLE]
For any -derivatives or mixed derivatives up to the order of the items of series (1.14) will be defined if is large enough. But there appear two difficulties.
First, though the operator is bounded in , its norm isn’t close to 1 if . It implies that estimate (1.3) isn’t enough for convergence of series (1.14). The constant in (1.3) must be small enough.
Second, even if we shall find a locally homeomorphic solution analogously to (1.13), we can’t extend this solution to and apply the topological argument to prove its global univalence.
We apply some results of theory of univalent functions to overcome this obstacle. A function holomorphic on and mapping 0 to 0 is univalent if
[TABLE]
(See [Pom]). If is a solution to the equation , then satisfies the equation
[TABLE]
Conversely, if we find a solution to this equation, then we can find a solution to the Beltrami equation by integration. It appears, we can find a solution to equation (1.16) with the estimate for any if the constant in the right side of (1.4) is small enough for several first . Further, for any -quasiholomorhic function on we have the decomposition into the product , where is the normal mapping and is holomorphic. It implies that if we have sufficiently good estimates for the derivatives of and for , then satisfies estimate (1.15). Thus will be univalent and homeomorphic.
Now we outline the main steps of the proof of Theorem 2. First, in Section 2 we obtain estimates for derivatives of the normal solutions when satisfies estimates (1.3), (1.4). In Section 3 we obtain estimates for the differences of these derivatives when we have the normal solutions with the complex dilatations and . For family satisfying estimates (1.5) we obtain Heolder estimates for differences of -derivatives. In application to foliations we can consider this result as some generalization of the result of [DNS] on existence of Heolder estimates for the Poincare metrics on the leaves.
In Section 4, applying the obtained estimates, we approximate the family of normal mappings with satisfying estimates (1.4), (1.5) by a finitely smooth family of -quasiconformal homeomorphisms with approximating in terms of -norms. The family maps onto some domain fibered by topological disks . For functions on we define the spaces and as in Definition 1 replacing the difference by . The mappings decompose into the products , where are -quasiconformal mappings with small and having derivatives up to some finite order small in terms of -norms. As a result, we reduce Theorem 2 to the analogous theorem with defined on and small with derivatives in terms of -norms.
In Section 5 we define integral operators analogous to and on the domains . In Sections 6 and 7 we obtain estimates for these operators in appropriate norms.
To obtain univalence we must find a solution to equation (1.16) on satisfying the uniform estimate with sufficiently small . It appears possible if is small in terms of -norms. It is essential that appearing singular integral operators are bounded in appropriate Holder norms.
2 Estimates for derivatives of normal mappings
In the following estimates we shall often use the expression ”uniform constant” in a sense that we shall specify in each case. In what follows or often means an indeterminate uniform constant. For example, in inequalities of the type in the right side in two cases isn’t necessary the same.
In this section is a multi-index of type and is the derivative .
Lemma 1
Suppose is a -quasiconformal normal mapping and for we have the estimates
[TABLE]
[TABLE]
Then we have the estimates
[TABLE]
with uniform , and we can put these constants tending to 1 as and tend to 0.
[TABLE]
with depending only on and , . If are small enough, then
[TABLE]
for with some uniform independent of .
In this section we say that an estimate or a constant is uniform if it depends only on the constants of Lemma 1.
Proof of Lemma 1. 1)Reduction to the case , .
The map
[TABLE]
maps and the point to zero. Note that
[TABLE]
also.
Define , . Then maps zero to zero. There is the useful inequality
[TABLE]
for some uniform , depending only on . Indeed, if , then, by distortion theorems for quasiconformal mappings, (see, for example, [L])
[TABLE]
and we can put in (2.4) , . Notice that we can put the bounds independent of for for any .
We need in estimates for derivatives of .
Proposition 1
We have
[TABLE]
with independent of . In particular,
[TABLE]
on every disk , where depends on but not depends on .
Proof. We have
[TABLE]
Denote . We have
[TABLE]
Since
[TABLE]
we obtain
[TABLE]
We need in an estimate of the difference from above. Note that
[TABLE]
Let be the angle between and , , . We have
[TABLE]
[TABLE]
Hence,
[TABLE]
and
[TABLE]
From this estimate and (2.8) we obtain
[TABLE]
We get an analogous estimate for . We obtained estimate (2.5) for the derivatives of first order.
Now we shall get estimates for derivatives of higher orders. We have
[TABLE]
[TABLE]
Here in the second line we have the sum of items with , , , . We estimate these items by induction. Denote by terms having uniform estimates.
The multiple has the estimate (we apply (2.8) and (2.9))
[TABLE]
with depending only on . After differentiation we obtain the multiple with the estimate
[TABLE]
[TABLE]
Any multiple of type has the estimate
[TABLE]
and the multiple is of the type
[TABLE]
Thus at every differentiation there appears either the multiple either the multiple , and in the estimates we must replace . It finishes the proof of estimate (2.5).
Let be the map . Then
[TABLE]
The map maps onto some ellipsis. Let be the conformal map mapping this ellipsis onto and having real derivative at zero. Let be the composition . We have
[TABLE]
Define the map
[TABLE]
The complex dilatation is
[TABLE]
In particular, . The map and its inverse have all derivatives bounded uniformly with respect to . It follows that for derivatives of we have estimates analogous to the estimates of Proposition 1.
In what follows we adopt the notation .
Proposition 2
. We have the estimates
[TABLE]
Here doesn’t depend on if for any , for example, if . In particular,
[TABLE]
on any disk .
Proof Almost all assertions were already proved. The assertion about constant in (2.11) holds because is quasiconformal with the complex dilatation , is bounded from below and from above by constants depending only on , and tends to 1 uniformly as tends to zero, all other derivatives of are also bounded by constants depending only on , and we can put these constants arbitrary small as tends to zero.
Now we return to the original map .
Proposition 3
a) We have the estimates
[TABLE]
with some uniform . These constants depend on but we can put them independent of for for any .
[TABLE]
with some uniform .
Proof. We have
[TABLE]
We adopt the notations: is the derivative of a function with respect to its analytic argument and is the derivative with respect to the conjugate variable. We have
[TABLE]
[TABLE]
In particular, recalling that , we obtain
[TABLE]
The fraction is uniformly bounded from below and from above by (2.4) and we can set the bounds independent of for for any . The same holds for the value . We obtain (2.13).
Now differentiating (2.16) we see that the derivative is the sum of terms of the types
[TABLE]
[TABLE]
[TABLE]
[TABLE]
and of analogous terms containing derivatives of and . All these terms have estimates .
At further differentiations we obtain each time either the multiple either the term, where the multiple is replaced by the multiple , which also results in multiplication by . Also, if we had some item containing a product , then, after differentiation, we obtain the term of the same type with the sum higher no more, than by 1. By induction we see that the derivative at can be represented as a sum of items of the types
[TABLE]
where , and is a multiple uniformly bounded and independent of in conditions of point b). Estimate (2.14) follows immediately.
We see that to prove Lemma 1 it is enough to show that is uniformly bounded from below and from above and that derivatives , are uniformly bounded.
2)Transition to the logarithmic chart
Define the logarithmic coordinates
[TABLE]
We shall use the notation for represented in the logarithmic coordinates . The complex dilatation is
[TABLE]
Consider the first terms of the power series decomposition for
[TABLE]
In the logarithmic coordinates we have the decomposition at (we assume , )
[TABLE]
[TABLE]
Consider the higher terms. If the term of order in the decomposition of is
[TABLE]
then the term of order in the decomposition of is
[TABLE]
where is a sum of products of multiples containing only the coefficients of the decomposition of degrees less than . Thus uniform estimates for coefficients of decomposition (2.18) follow from uniform estimates for coefficients of decomposition (2.20). Note also that we can write expression (2.20) as
[TABLE]
Indeed, each term in the decomposition of yields the term . We see also that if we obtain uniform estimates for the coefficients of decomposition (2.21), then we also obtain uniform estimates for the coefficients .
- Integral operators in the logarithmic chart.
Let be the stripe and be a space of -periodic functions on with usual -norm. We adopt the notations for the space of functions belonging to with a support in the left half-stripe and for the space of functions supported in the set .
We define an integral transform acting on -periodic functions on
[TABLE]
Proposition 4
The transform is right inverse to the operator for smooth functions belonging to at . Suppose , . Then
[TABLE]
with depending on and .
Proof. At first we prove that the operator is right inverse to the Cauchy-Riemann operator. We have
[TABLE]
[TABLE]
where is a holomorphic function. Hence, we have
[TABLE]
and
[TABLE]
To proof estimate (2.22) it is enough to show that considered as a function of has a uniform estimate with respect to in for . Here is the ”step”: if and if .
Suppose at first . The integral
[TABLE]
is uniformly bounded and the integral
[TABLE]
has the estimate with some depending only on . Hence we obtain an uniform estimate for the kernel.
If , then the integral over the domain is obviously uniformly bounded (we should consider only the integral over the intersection of this disk with the semi-plane ). From the other hand, the integral
[TABLE]
at also has an uniform estimate because the function is uniformly bounded.
Now we define
[TABLE]
where the integral is defined in terms of its principal value.
Proposition 5
The operator is bounded in at and its -norm tends to 1 when tends to 2.
Proof. If is a -periodic function with support in some vertical stripe, then at large positive or negative decreases as . In the following standard calculations all possible integrals over the boundary equal zero because transforms periodic functions into periodic ones.
[TABLE]
[TABLE]
Now we prove the - boundedness. We have
[TABLE]
[TABLE]
[TABLE]
The first integral is the usual Beurling transform of a function with support in and has an estimate in by the Calderon-Zigmund theorem. The second integral is a convolution of the function with the function
[TABLE]
where is the characteristic function of the unit disk. This function belongs to and the integral has an -estimate by the Yung inequality. The -norms of these integrals are no greater then its -norms. The last integral can be considered as a bounded operator on and on . Indeed, if we denote by the kernel (i.e., the function in the square brackets), than we can easy see that
[TABLE]
has an uniform estimate as a function of and, by a symmetry, the integral
[TABLE]
also has an uniform estimate as a function of . We obtain an -estimate of the last integral in (2.23)
[TABLE]
[TABLE]
for some . Analogously,
[TABLE]
We obtain -boundedness of the last integral in (2.23) for by the Riesz-Thorin interpolation theorem.
The -norm of the operator tends to 1 as tends to 2 also by the Riesz-Thorin theorem.
- Solution to the Beltramy equation in the logarithmic chart.
Suppose is some -periodic function with the properties:
a) for some ,
b) has the support in some domain ,
c) for some .
Since the function is bounded in , the series
[TABLE]
converge in for sufficiently close to 2, as in the classical case, and we have for the -norm of the function the estimate with some depending only on . By Proposition 4, with, possibly, some new . We see that
[TABLE]
is a solution to the Beltrami equation with the Beltrami coefficient . We call this solution the principal logarithmic solution.
Proposition 6
The principal logarithmic solution is a homeomorphism of the plane satisfying the estimate
[TABLE]
Proof Estimate (2.24) follows from Propositions 4 and 5. Prove that is a homeomorphism.
The map is a quasiholomorphic function on the punctured plane with the compactly supported complex dilatation. From (2.24) follows that the estimate
[TABLE]
holds at zero and at infinity. From the other hand, extends as a quasiholomorphic function to zero. Indeed, after the change of the chart by a quasiconformal homeomorphism we obtain a holomorphic function with a removable singularity. Further, since is holomorphic outside some disk, we obtain from (2.25) that at infinity this map has the asymptotics , . Subtracting and dividing by we obtain a quasiholomorphic map with a compactly supported complex dilatation and with the asymptotics at infinity. It implies that it is the principal solution to the corresponding Beltrami equation, which is unique and homeomorphic. It follows that also is a homeomorphism.
Proposition 7
The coefficient satisfy conditions a) - c) for with estimates uniform with respect to . The operator is invertible in if for some , which can be made arbitrary large if are small enough. Here and are the constants from the formulation of Lemma 1. Moreover, we have the estimate
[TABLE]
where doesn’t depend .
Proof. If we have, applying (2.17) and estimate (2.12)
[TABLE]
[TABLE]
Also,
[TABLE]
with some uniform if . We see that and
[TABLE]
Analogously, we can see that the function has -norm no greater, than . By definition of and applying estimate (2.24), we obtain (2.26).
- The proof of estimate (2.1) We shall show that the map has a representation in terms of principal logarithmic solutions.
Define the map
[TABLE]
This map is ”symmetrical” to with respect to the imaginary axis. Its complex dilatation is . Now we define the function
[TABLE]
Proposition 8
The coefficient satisfies conditions a) - c) with uniform constants. More, we have the estimate
[TABLE]
where are from the formulation of Lemma 1 and doesn’t depend on if .
Proof. Obviously . We see that has a support in some half-plane with an uniform and, since for we have the estimate of Proposition 6, we have the estimate at with some uniform . We finish the proof analogously to the proof of Proposition 7.
Consider the map
[TABLE]
In the chart it is the map
[TABLE]
Proposition 9
[TABLE]
for .
Proof. is a quasiconformal map with the complex dilatation . The map , obtained after transition to the chart , is a solution to the Beltrami equation on the punctured plane with the Beltrami coefficient symmetrical with respect to the unit circle and equal to if . Also, this solution satisfies the uniform estimate , where for and we have the estimates
[TABLE]
according to Propositions 6,7 and 8. As in the proof of Proposition 6 we can extend to zero and obtain the quasiconformal map fixing zero and infinity. Suppose . Then has uniform estimates from below and from above. Dividing by we obtain a map fixing 0, and 1, i.e., the normal map. This map is unique and symmetrical with respect to the unit circle. It means that on it coincides with up to, possibly, some rotation ( doesn’t map necessarily 1 to 1).
We see that the map differs from the map at only by a constant multiple. We can find this multiple from the condition
[TABLE]
i.e., . We obtain
[TABLE]
Corollary. If and are small enough, then
[TABLE]
with some uniform .
Proof. It follows from Propositions 7 and 8 and (2.28).
Proof of estimate (2.1). Since and equal to 1 by modulus, and for we have estimate , where and satisfy estimate (2.29), we obtain the estimate
[TABLE]
with uniform don’t depending on . Now estimate (2.1) follows from estimate (2.15) of Proposition 3 because tends to 1 as .
- Estimates for derivatives of the mappings , and . For convenience we place here these estimates, which we shall use in the next section.
Proposition 10
a)
[TABLE]
with some uniform , and we have for an estimate analogous to the right inequality.
b)
[TABLE]
with some uniform , and is uniformly bounded at . We have the same estimates for .
c)
[TABLE]
with some uniform at and is uniformly bounded at .
Proof. a) Remind that , where . The map is quasiconformal with the complex dilatation , is bounded from below and from above by constants depending only on . Thus it is enough to prove estimate analogous to (2.31) for if we replace by . We have
[TABLE]
[TABLE]
Applying (2.4) we see that
[TABLE]
Thus,
[TABLE]
Since is uniformly bounded from below and from above, we obtain (2.31). The estimate for -derivative is analogous.
b) The map written in the chart is the map . The function is uniformly bounded at . It means that is a quasiconformal homeomorphism of with the complex dilatation and with derivatives at zero uniformly bounded from below and from above. We can represent it on as , where is a holomorphic univalent uniformly bounded function with the derivative at zero uniformly bounded from below and from above. For such functions we have estimates ([Pom])
[TABLE]
Also, for a variable , is a family of quasiconformal mappings of onto itself with uniformly bounded dilatations and, hence, there are the estimates
[TABLE]
. with uniform .
Further, at
[TABLE]
By left inequality (2.31), estimate (2.35), and right inequality (2.34), we obtain
[TABLE]
at . Analogously, right inequality (2.31) and left inequality (2.34) together with (2.35) yield right estimate (2.32).
On the functions are univalent holomorphic, uniformly bounded away from zero and having uniformly bounded derivatives at infinity. Thus there is also the uniform estimates . We obtain estimates (2.32) also at .
The case of is analogous.
c) From (2.28) follows that we have for the derivatives of the estimates analogous to (2.31). Since we have
[TABLE]
and by left estimate (2.32) applied to , we obtain
[TABLE]
at . The rest of the proposition is obvious.
- Inductive change of variables. Now we pass to estimates of derivatives of higher orders. Consider the decomposition of at
[TABLE]
Let be a function equal to 1 at and to 0 at with the derivative less then 1 by modulus. We define some successive change of variables. Put if and if with some large enough by modulus in both cases and define the new variable
[TABLE]
The derivative of the function is less then 1/4, has uniform bounds independent of , and we can set also independently of . We obtain the estimates , . Hence, is a homeomorphism of the left half-plain onto itself. We get the new map with the asymptotics
[TABLE]
[TABLE]
Suppose we have uniform estimates for the coefficients of the expansion of at zero up to order . Define the variable
[TABLE]
We get the map
[TABLE]
Analogously, we define the variable ,
[TABLE]
After successive changes of variables we obtain the map
[TABLE]
Here we returned to the notation for the variable.
In the chart we get the transformations
[TABLE]
…
[TABLE]
…
and the resulting mapping ,
[TABLE]
By the inductive assumption, we have uniform estimates for the coefficients of the expansion of at zero up to order . It is easy to see that to obtain estimates for the derivatives at zero of order it is enough to estimate the coefficients . Indeed, if we have decomposition (2.18) for , then (and analogously other coefficients at the terms of order ) has the representation
[TABLE]
where is a polynomial from , with .
Let be the composition . The complex dilatation of the map is
[TABLE]
[TABLE]
where
[TABLE]
The coefficients ,…, can be represented as polynomials in the variables , the coefficients of of the expansion of at zero up to order , and the coefficients of order of . All these coefficients are uniformly bounded either by the inductive assumption either by Proposition 2. It follows that ,…, are uniformly bounded. Thus it is enough only to estimate the coefficient . Define the new transformation
[TABLE]
Again adopting the notation for the chart we obtain the map
[TABLE]
with the complex dilatation .
Note that we obtained the relations
[TABLE]
where is a polynomial in with and in , . From (2.42) follow the inverse relations
[TABLE]
Here and is a polynomial in with , .
Proposition 11
Suppose we have uniform estimates for the coefficients of the expansion of at zero up to order . Then we can put such that will be homeomorphisms with uniformly bounded derivatives of order up to . The first derivatives , and all derivatives , will be uniformly bounded on the disk .
If the coefficients of the expansion of at zero of order , have the estimates with some uniform and are small enough with some uniform estimates, we can put such that
[TABLE]
[TABLE]
on with uniform independent of .
Proof. We already proved that is homeomorphic and here we give only a more explicit estimate. By (2.39), (2.38),
[TABLE]
[TABLE]
if , and
[TABLE]
if . Since , we can see that
[TABLE]
Also, applying estimate (2.30), we see that
[TABLE]
with some uniform for small enough. Analogously,
[TABLE]
[TABLE]
if , and
[TABLE]
if . We obtain the estimate
[TABLE]
with some uniform at small enough.
Note that we can chose independent of and , for example, we can put .
Now, by (2.39) for ,
[TABLE]
Here is a homogeneous polynomial in the variables of order . Its coefficients have uniform estimates by the inductive assumption. Moreover, these coefficients are polynomials in with without a term of zero order. By the second inductive assumption, we can estimate them as if are small enough. Remind that only if . Suppose the coefficients of are bounded by the constant . Then , . If we put , then we obtain . If are small enough, then we can put and obtain the estimate
[TABLE]
Also,
[TABLE]
and we obtain the estimate in the general case and the estimate
[TABLE]
if are small enough.
Consider at last the derivative
[TABLE]
The polynomial is the sum and the coefficients have the representation , where is a polynomial in with without a term of zero order. Applying Proposition 2 and the inductive assumptions we obtain for these coefficients an uniform estimate in the general case and the estimate if are small enough. As above, we obtain the estimate at an appropriate . If are small enough, we can put and obtain
[TABLE]
Analogously,
[TABLE]
and we obtain an uniform estimate in the general case and the estimate
[TABLE]
if are small enough.
We proved that are homeomorphic if we set as above. Put . By definition, , and we obtain estimates (2.44) from (2.48), (2.48’), (2.50), (2.50’), (2.52), (2.52’) and corollary of Proposition 9.
Now consider derivatives of the right parts of (2.46), (2.47), (2.46’) and (2.47’). In the first derivatives there appear the terms of the types and . Since derivatives of the function don’t equal zero only at , we obtain the estimates
[TABLE]
Derivatives of order are sums of items containing multiples of the types , and with some integer . At each differentiation there appears no more than one multiple , and we see that we have the estimate
[TABLE]
with some uniform . Remind that we can put . At small and we obtain the estimate with independent of and .
We estimate derivatives of and analogously. Differentiating the right parts of (2.49), (2.49’), (2.51) and (2.51’) we obtain terms of order for derivatives of order . At our choice of we have uniform estimates in the general case and the estimate if , , …, are small.
Now we have
[TABLE]
Now the proposition follows from the estimates for derivatives of and Proposition 2.
- Estimates for higher derivatives. From the next proposition we obtain by induction estimate (2.2) and estimate (2.3).
Proposition 12
a) Suppose that we have uniform bounds for the coefficients of the expansion of at zero up to order . Then the derivative is uniformly bounded.
b) If the coefficients of the expansion of at zero of order , have the estimates with some uniform and are small enough with some uniform estimate, then .
Proof. a) Denote by the Beltrami coefficient of the map . We have
[TABLE]
at . All derivatives in zero of the first integral in (2.53) are uniformly bounded. Now we have
[TABLE]
The first derivatives of the function and derivatives of of order are uniformly bounded on by Proposition 11.
Now , where
[TABLE]
where is the sum of modulus of derivatives of order . Hence, is uniformly bounded on .
The integrals
[TABLE]
are all uniformly bounded. We get
[TABLE]
From the other hand, we have the estimate
[TABLE]
with some uniform . We see that integral (2.55) has derivatives at zero and its -derivative of order is equal to .
b) Remind that at . Applying corollary of Proposition 9, we see that all derivatives at zero of order higher than 1 of the first integral in (2.53) have the estimate . To estimate the derivatives of the second integral in (2.52) we need to estimate integrals (2.54). We obtain the estimates by Proposition 11.
Now we finish the proof of Lemma 1.
Proof of estimate (2.3). Applying inductive relations (2.43) we obtain the estimates for the derivatives at zero of from the estimates for . The corollary follows now from Proposition 3.
We shall use in the next section the following estimate:
Proposition 13
[TABLE]
with some uniform at .
Proof. Estimate at first the second derivatives of the map . Analogously to the proof of Proposition 10 a) it is enough to obtain the estimates for . We have
[TABLE]
[TABLE]
[TABLE]
Applying (2.4) we see that
[TABLE]
Applying estimates (2.1), (2.8), and (2.9) we obtain
[TABLE]
and, hence,
[TABLE]
Obviously we have analogous estimates for other derivatives of second order.
Return now to the map . As in the proof of Proposition 10 b) we can represent it in the chart on as , where is a holomorphic univalent uniformly bounded function with derivative at zero uniformly bounded from below and from above. For such functions we have estimates (2.34) and ([Pom])
[TABLE]
Applying this estimate and (2.31), (2.35), (2.56), we obtain at
[TABLE]
[TABLE]
[TABLE]
at and analogous estimates for other second derivatives of . Obviously, for derivatives of we have the same estimates.
On the functions are univalent holomorphic with uniformly bounded derivatives at infinity and uniformly bounded away from zero. Hence, there is the uniform estimate . Thus at . We obtain the estimates for other derivatives of second order analogously.
In conclusion of this section we obtain some estimates for derivatives of the principal solutions. Remind the construction of the normal solutions (see, for example, [Ah]).
Let be the principal solutions with the Beltrami coefficient and put . Put and
[TABLE]
Let be the corresponding principal solution and . Define
[TABLE]
That is
[TABLE]
Then
[TABLE]
where .
Proposition 14
At assumptions of Lemma 1 we have the estimates
[TABLE]
[TABLE]
with depending only on and .
[TABLE]
with depending only on . Analogous estimates hold for .
[TABLE]
also with depending only on and .
Proof. We have the representation on : , where is a holomorphic univalent function mapping zero to zero and is the normal mapping. Since is bounded on with a bound depending only on and we have estimate (2.1), it follows that the function is bounded and has the derivatives at zero bounded from above by a constant depending only on . Let show that its -derivative at zero is bounded also from below. It is enough to prove that is bounded from below, that is, to prove estimate (2.60).
Since differs from by the multiple equal to 1 by modulus, we see that with depending only on and . Also, with also depending only on and . It means that
[TABLE]
and, hence,
[TABLE]
It means that we obtain estimate (2.60). Thus is bounded also from below and we can apply estimates (2.34) and (2.57) to . Applying also (2.4) we obtain estimates (2.61), (2.62) at .
On the function is univalent holomorphic with uniformly bounded derivatives at infinity. Also, on this domain is uniformly bounded away from zero. We obtain estimates (2.61) and (2.62) as in Propositions 10 and 13. The estimates for follow by symmetry.
Solving the system
[TABLE]
[TABLE]
we obtain
[TABLE]
Estimates (2.63) follow from (2.61) and from boundedness from below and from above of
3 Estimates for differences of derivatives of the normal mappings with different complex dilatations.
The proof of the lemma below is long and tedious but essentially simple. We adopt the notation for the supremum of such that the series converge in if .
Lemma 2
Let be functions on satisfying assumptions of Lemma 1 with the same . Let be the corresponding normal mappings. Then we have the estimates:
a)
[TABLE]
where and depends only on and .
b) Let be a multi-index, . Fix some . Then, for ,
[TABLE]
[TABLE]
where is such that for some depending only on , is some uniform constant and depends only on , .
In the proof we shall use the terminology and the notations of the previous section.
Proof of estimate 3.1. We put, as in Proposition 14, , ,
[TABLE]
By definition, is the corresponding principal solution, , , .
By Proposition 14,
[TABLE]
[TABLE]
[TABLE]
We must estimate the value
[TABLE]
Since , it is enough to estimate the difference
[TABLE]
Proposition 15
Let , be the principal solutions corresponding to compactly supported Beltrami coefficients . Then
[TABLE]
[TABLE]
[TABLE]
for .
Proof. Let be the solution to the equation . (Remind that here and below is the Beorling transform and is the Cauchy transform). We have
[TABLE]
Further,
[TABLE]
That is,
[TABLE]
and
[TABLE]
with some constant depending only on . Since , we obtain the first two estimates of the proposition from (3.8).
Prove the third estimate. Suppose . Then
[TABLE]
We can apply this proposition to , and, hence, to , . Also we have
[TABLE]
[TABLE]
Here we applied estimate (2.60).
We must estimate the right part of inequality (3.7). We proceed in several steps. In all inequalities below all constants such as or depend only on and .
[TABLE]
Proof. Fix some and some . Applying Proposition 15 and estimate (3.4) we can write
[TABLE]
[TABLE]
The second integral we estimate by the Heolder inequality , . We obtain
[TABLE]
[TABLE]
If we define from the equation , i.e., if we put , we get the estimate
[TABLE]
- At
[TABLE]
Proof. It follows from step 1 and estimate (3.9).
[TABLE]
Here is the characteristic function of .
Proof. The proof in step 1 depends only on the right side of the first inequality of Proposition 15. Since the second inequality has the same right part, we obtain our assertion from (3.9).
[TABLE]
Proof. Again fix some and some . Applying Proposition 15 and estimate (3.5) we can write
[TABLE]
[TABLE]
The second integral we again estimate by the Heolder inequality and obtain
[TABLE]
[TABLE]
But
[TABLE]
where is the Jacobian of the transformation . Since belongs to , we see that restricted on the ring belongs to . Hence, by the Geolder inequality
[TABLE]
We obtain
[TABLE]
If we put , then we obtain the estimate
[TABLE]
[TABLE]
Proof. Since we have representation (3.3), we can see that
[TABLE]
[TABLE]
We obtain estimates for all terms in the right side by the same method as in the steps above.
The first term we can write as
[TABLE]
Since only on , we can apply the estimate of in . Also, from (3.4) follows the estimate if . Fix some . We obtain
[TABLE]
[TABLE]
We put and obtain
[TABLE]
Consider the second term in (3.10). Remind that . Again fix some . Applying step 2 and the third inequality of Proposition 15 we obtain
[TABLE]
[TABLE]
[TABLE]
[TABLE]
Here is the same as in step 2) and we again recall that belongs to .
We put and obtain
[TABLE]
Consider the third term in (3.10). We have
[TABLE]
We see that we must estimate .
Applying left estimate (3.4) to and acting as above we see that the third term in (3.10) is no greater than
[TABLE]
for any . Here we use the uniform boundedness of the third term in (3.12) and again recall the estimate . We have
[TABLE]
[TABLE]
Applying step 3) we obtain for the third term the estimate
[TABLE]
where we set as in step 3). We put and obtain the estimate
[TABLE]
Consider the last term in (3.10). Denote . We must estimate -norm of the sum
[TABLE]
Analogously to the previous case we get for this -norm the estimate
[TABLE]
for any . Now at , applying estimate (3.6) and step 2), we have
[TABLE]
[TABLE]
Now we put . In this case and, hence, is small by comparison with and we, indeed, can apply estimate (3.11). We obtain the estimate
[TABLE]
We obtained the estimate of the first difference in the right side of inequality (3.7). We finish the proof of the proposition with estimation of the second difference.
- For
[TABLE]
Proof. The estimate follows from step 2) and the well-known inequality , which holds for any compactly supported , and (see, for example [Al]).
Now we begin the proof of estimate (3.2). Analogously to the notations we adopt the notations and so on. At first we shall obtain estimates for the difference and its derivatives.
Proposition 16
a) Suppose . There is the estimate
[TABLE]
[TABLE]
where
[TABLE]
with some uniform independent of . In fact, it depends only on the maximal dilatation of and we can put if , are small enough.
b) Let , . Then
[TABLE]
[TABLE]
In all these inequalities is some uniform constant.
Proof. a) Recalling (2.10) we see that any derivative is a sum of items of the types
[TABLE]
where , , , is the derivative of order of the fraction
[TABLE]
considered as a function of . That is is an uniformly bounded rational function of , and can be either either . It follows that we can represent any difference as a sum of terms of the types
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
where denotes each time a product of the multiples such as in (3.15) with omitted term corresponding to the written difference. All these multiples are either derivatives of , either derivatives of in the point , either derivatives of with respect to . The derivatives of and of are uniformly bounded.
is a real analytic function of equal to identically at and, hence, we can estimate the differences in (3.20) and (3.21) as . From the other hand, the products in the square brackets in these cases have the estimates
[TABLE]
It follows from estimate (2.5). We obtain for terms (3.20), (3.21) the estimate
[TABLE]
The difference in (3.16) is no more than
[TABLE]
Now we have
[TABLE]
with depending only on .
[TABLE]
It implies
[TABLE]
where is such that
[TABLE]
with some depending only in the right side of (3.23), i.e. , on maximal dilatations of , . This constant can be made close to 1 if , are small enough. In this case we can set .
The product in the square brackets in (3.16) has the same estimate as in (3.20), (3.21). We obtain for term (3.16) the estimate
[TABLE]
Consider now term (3.17). The function has bounded derivatives as a function of , and is an analytic function of with a bounded derivative. Applying (2.5) and (3.23), we see that the difference in (3.17) is no more than
[TABLE]
[TABLE]
Since the product in the square brackets in (3.17) has the same estimate , we obtain for term (3.17) the estimate
[TABLE]
Considering term (3.18) we have
[TABLE]
where is the homogeneous polynomial in the variables of degree . Thus for the difference in (3.18) we have the estimate
[TABLE]
Now remind expression (2.7) for . We have the obvious estimates
[TABLE]
where we denote .
We see that any derivative is a sum of items of the types
[TABLE]
where , , each can be either either and the corresponding derivative is either in either in . Applying (3.27), we see that we can represent any difference as a sum of terms with the estimates
[TABLE]
Here we apply (3.24) and take into consideration that . We obtain for the difference in (3.18) the estimate
[TABLE]
The product in the square brackets in (3.18) doesn’t contain the term and, hence, has the estimate: . We obtain for term (3.18) the estimate
[TABLE]
At last, the difference in (3.19) is no greater, than
[TABLE]
where is the homogeneous polynomial in the variables of degree . Thus we can estimate this difference as
[TABLE]
[TABLE]
[TABLE]
Analogously to the previous case we obtain for term (3.19) the estimate
[TABLE]
From (3.22), (3.25), (3.26), (3.28) and (3.29) follows (3.12).
b) Applying (2.10), we have
[TABLE]
[TABLE]
[TABLE]
Consider the first integral. We have
[TABLE]
since the Jacobian of is uniformly bounded from above and from below. Also, applying (2.7), we have
[TABLE]
where is the Jacobian of the map . This Jacobian is equal to and there is the estimate
[TABLE]
Indeed,
[TABLE]
[TABLE]
[TABLE]
[TABLE]
Further, the integral
[TABLE]
is uniformly bounded. Thus we obtain
[TABLE]
[TABLE]
for any . From the other hand, if , then from (3.31) follows the estimate
[TABLE]
Consider the second integral in (3.30). Applying estimate (2.5), we have for any
[TABLE]
[TABLE]
[TABLE]
That is,
[TABLE]
If we put , i.e., , then we obtain
[TABLE]
At last, we estimate the third integral in (3.30) analogously to the difference in (3.20): it is no greater than
[TABLE]
Collecting (3.30) and (3.33)-(3.35) we obtain (3.14).
We also need in an estimate for the norm of in . Remind that is the stripe and is the space of -periodic functions on with usual -norm. In what follows we don’t write the index in our notations.
Proposition 17
Let , . There is the estimate
[TABLE]
[TABLE]
where with some depending only on . If , are small enough, then we can take .
Proof. Remind equation (2.17). Since , , and the first derivatives of are uniformly bounded on (see (2.12)), we have
[TABLE]
[TABLE]
[TABLE]
The first integral in the right side has the obvious estimate
[TABLE]
Applying estimate (3.12) we see that the integral is no greater than
[TABLE]
We apply estimates (3.14) to the second integral in (3.37). As a result we obtain estimate (3.36).
Our next step will be the proof of estimate (3.2) for the derivatives of first order. It is a consequence of estimate (3.36) and the next proposition.
Proposition 18
Let , be the normal solutions corresponding to the Beltrami coefficients and satisfying conditions of Theorem 1 with the same bounds . There is the estimate
[TABLE]
with some uniform and some , depending only on . For the difference of -derivatives we have the analogous estimate.
Proof. By (2.15) and (2.28),
[TABLE]
Remind that and , where is defined in subsection 5) of Section 2.
We can see that all multiples in (3.40) are uniformly bounded. For the multiple it follows from the notion that belongs to the unit circle and is uniformly bounded from below on the unit circle. According to (3.38) we can represent the difference as a sum of the terms
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
In fact, since the fractions are uniformly bounded, it is enough, instead of (3.41), to estimate
[TABLE]
The difference we estimate by inequality (3.1).
We can estimate term (3.40) as
[TABLE]
For term (3.41) we have the estimate
[TABLE]
To estimate term (3.42) we use the next proposition:
Proposition 19
Let be the principal logarithmic solution corresponding to the coefficient , . Then
[TABLE]
for .
The proof is analogous to the proof for the principal solution in the classical case.
Now, since and , we obtain for term (3.42) the estimate
[TABLE]
For term (3.43) we have the estimate
[TABLE]
and for term (3.44)
[TABLE]
We see that to prove Proposition 18 it remains to estimate the difference
[TABLE]
We proceed analogously to the proof of estimate (3.1) but we use now the principal logarithmic solutions. Instead of Proposition 15 we have
Proposition 20
Let and be the principal logarithmic solutions corresponding to the coefficients and , . Then, for ,
[TABLE]
[TABLE]
[TABLE]
for .
Proof. The proof of is completely analogous to the proof of Proposition 15, we only change and to and correspondingly.
Proposition 21
Suppose , , . Then
[TABLE]
[TABLE]
[TABLE]
[TABLE]
where and depend only on , and is uniform.
Proof. Consider the first estimate. By Proposition 20 we must estimate . But belongs to with the norm bounded by a constant depending only on the maximal dilatation of if . Also, we have estimate (2.33). Fix some and some . We have
[TABLE]
[TABLE]
[TABLE]
Since the restriction of the Jacobian on the domain belongs to with an uniform norm, we obtain for the last integral the estimate
[TABLE]
Now we put , i.e, . We obtain the estimate
[TABLE]
Analogously, to obtain the second estimate of the proposition we proceed applying (2.34) and the second inequality of Proposition 20
[TABLE]
[TABLE]
for some and some . Putting we obtain
[TABLE]
The prove of the last two estimates of the proposition is analogous.
Return now to the proof of Proposition 18. To estimate the first difference in (3.45) we apply Propositions 20 and 21. We must estimate the norm . We have
[TABLE]
[TABLE]
Consider the first difference in the right side. Since is a homeomorphism of the plane, we can write
[TABLE]
[TABLE]
From (2.32) follows the estimate
[TABLE]
Also, restriction of on the domain belongs to with an uniform estimate. We apply our usual method. We have for any
[TABLE]
[TABLE]
We determine from the equation . I.e., we put and obtain
[TABLE]
Consider the second term in the right side of (3.46). We can assume that is small with some uniform estimate that we shall specify below. Applying (2.11), (2.17) and the obvious estimate for : with uniform , we get the estimate if , . By the last inequality of Proposition 21,
[TABLE]
Suppose
[TABLE]
Applying estimate (3.47), we can write
[TABLE]
[TABLE]
where is the same as in Proposition 21. If satisfies conditions (3.49), we have
[TABLE]
[TABLE]
Since the restriction of the Jacobian on the domain belongs to , we estimate the last integral as
[TABLE]
Now we put , i.e., . We see that conditions (3.49) are satisfied at small enough. We obtain
[TABLE]
Consider the third term in (3.46). We have
[TABLE]
For we have estimate (2.34). Acting as above, we can see that the third term in (3.48) is no greater than
[TABLE]
for any . Applying estimate (3.47), we obtain
[TABLE]
[TABLE]
Applying the second inequality of Proposition 21, we see that the third term in (3.46) satisfies the estimate
[TABLE]
where is the same as in Proposition 21. If we put , i.e., , we obtain the estimate
[TABLE]
Consider the last term in (3.46). Denote , . We must estimate -norm of the sum
[TABLE]
Let be such that
[TABLE]
Analogously to the previous case we obtain for this -norm the estimate
[TABLE]
Now, by Proposition 21 and the estimate of Proposition 13,
[TABLE]
[TABLE]
Applying (3.47), we obtain for the integral in (3.53) the estimate
[TABLE]
Now we determine from the equation , that is, . In this case is small by comparison with and condition (3.52) is satisfied. We obtain the estimate
[TABLE]
Collecting (3.48), (3.50), (3.51), and (3.54), we obtain the estimate for the first difference in the right side of (3.45).
It remains to estimate the second difference in (3.45). From Propositions 19 and 21 follows
[TABLE]
[TABLE]
It finishes the proof of Proposition 18.
Now we begin the prove of estimate (3.2) for derivatives of order higher than one. We use notations of step 7) of Section 2 with obvious modifications, in other words, , instead of , instead of and so on. Remind that at .
Proposition 22
There are the estimates
a) If , , then
[TABLE]
[TABLE]
b) If , then
[TABLE]
c) For
[TABLE]
[TABLE]
Proof. a) and b) Remind that . We have
[TABLE]
Any derivative is a sum of items of the types
[TABLE]
where , is an uniformly bounded rational function of , can be any function from the tuple , any can be either either , and . It follows that we can represent any difference as a sum of terms of the types
[TABLE]
[TABLE]
terms
[TABLE]
[TABLE]
[TABLE]
[TABLE]
the analogous terms with , and
[TABLE]
[TABLE]
where denotes each time the product of the multiples such as in (3.55), where we omit the term corresponding to the written difference. All these multiples are either derivatives of , either derivatives of in the point , either derivatives of with respect to , or . All these derivatives are uniformly bounded. For derivatives of it holds because belongs to the disk and for derivatives of it follows from Proposition 11.
For terms (3.56) -(3.63) we have the estimates:
For term (3.56)
[TABLE]
For term (3.57)
[TABLE]
For term (3.58)
[TABLE]
For term (3.59)
[TABLE]
For term (3.60):
[TABLE]
For term (3.61)
[TABLE]
For term (3.62)
[TABLE]
For term (3.63)
[TABLE]
Here we take into consideration that all derivatives of , and , are uniformly bounded on . Terms (3.56’) and (3.58’) yield the term in the estimate of .
We must estimate , , and on . Consider at first the difference .
The map is the composition
[TABLE]
We can write the difference as a sum of terms of the types
[TABLE]
and
[TABLE]
where denotes products having uniform estimates in . We don’t write analogous terms containing differences of derivatives of , .
Consider at first difference (3.65). It has the estimate
[TABLE]
We can represent the last difference as a sum of terms of the types
[TABLE]
[TABLE]
for .
The following considerations are analogous to the reasoning leading to relations (2.42), (2.43). In more details, let be the coefficients of the form . By (2.37) - (2.40), we can see that is a function of ; , are functions of , and is a function of , . All these functions have uniformly bounded derivatives of any order at . The same holds for . When we consider , we denote by the coefficients of the corresponding forms . These coefficients are polynomial in and in derivatives in zero of function and, hence, they are uniformly bounded. It follows that differences (3.66), (3.66’) have estimates
[TABLE]
for or .
Further, the coefficients or are functions of with and . All these functions have bounded derivatives. We get for terms of type (3.65) the estimate
[TABLE]
From the other hand, -derivatives of are also functions of the same variables , and . We obtain for the terms of type (3.64) the same estimate (3.67). Thus we proved estimate b).
Obviously, we get analogous estimate for . Also, is no greater, than and, hence, we also get for such term estimate (3.67). Since we have estimates (3.56’) - (3.63’), we obtain a).
c) Since at , the estimate follows from a).
Our next step will be estimates for and . Also we obtain estimates for .
Proposition 23
We have for some depending only on and some uniform a)
[TABLE]
b)
[TABLE]
[TABLE]
c) for
[TABLE]
[TABLE]
Proof. a) Using the representation , we see that we must estimate the sum
[TABLE]
[TABLE]
Considering as a function of and applying inequality (2.4), we get that we can estimate the first term as
[TABLE]
Applying estimate (3.1), we obtain
[TABLE]
The second term in (3.68) we estimate as
[TABLE]
Again we obtain the estimate
[TABLE]
Further, we have the estimate , it is a particular case of estimate (2.31). We see that the third term in (3.68) we can estimate as
[TABLE]
[TABLE]
with some uniform .
b) We must estimate the terms
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
We don’t write the analogous terms containing -derivatives.
To estimate term (3.69) we proceed as in the case of the first difference in (3.68). The derivatives of with respect to have the estimate . The derivative has the estimate . Other multiples are uniformly bounded. Applying estimate (3.1), we obtain for term (3.69) the estimate
[TABLE]
For term (3.70) we obtain analogous estimate because the second derivative of has the estimate .
In all other terms there is the multiple .
Thus for term (3.71) we have the estimate
[TABLE]
[TABLE]
by Proposition 18.
Consider term (3.72). Denote , . We see that we have the estimate
[TABLE]
Now, if ,
[TABLE]
[TABLE]
Since for some uniform and , we obtain the estimate
[TABLE]
For term (3.73) we have the estimate
[TABLE]
[TABLE]
at . We obtain the estimate
[TABLE]
At last, for term (3.74) we have the estimate
[TABLE]
Collecting estimates (3.69’) - (3.74’) we obtain b).
c) From the representation: , , follows that we must estimate the terms of the types
[TABLE]
[TABLE]
[TABLE]
[TABLE]
We don’t write the analogous term with the difference . Multiples in the square brackets are uniformly bounded because derivatives of are uniformly bounded and derivatives of are uniformly bounded on .
For the first term we have estimate b)
[TABLE]
The second term is no greater than
[TABLE]
and, by point b) of Proposition 22, we get the estimate
[TABLE]
The same estimate holds for the terms of third and fourth types. Indeed, these terms are the particular cases of terms (3.65) and (3.66). Applying (2.43) we obtain c).
Proof of estimate (3.2). At first we estimate . We have representations (2.53) and the decomposition analogous to (2.55) but cut on the term of order . Thus,
[TABLE]
Here we take into consideration that for .
For the first difference in the right side we have the first estimate of Proposition 23
[TABLE]
We must estimate the integral in (3.75). We have
[TABLE]
[TABLE]
Consider the first integral in the right side. Applying third estimate of Proposition 23, we have
[TABLE]
[TABLE]
[TABLE]
Consider the second integral in the right side of (3.77). Remind that . It means that for any we can write
[TABLE]
By Proposition 22, we obtain
[TABLE]
[TABLE]
Gathering estimates (3.76), (3.78) and (3.79), we obtain by induction
[TABLE]
[TABLE]
[TABLE]
Now, if , we have once more by induction, applying relations (2.43),
[TABLE]
[TABLE]
Further, by (3.12) we obtain
[TABLE]
[TABLE]
where with some uniform . Also, Proposition 17 yields
[TABLE]
[TABLE]
where we can take any . Thus we obtain
[TABLE]
[TABLE]
[TABLE]
with some new .
Now suppose that estimate (3.2) holds for multi-indexes with . Recalling representation (2.15 we see that we can represent the derivative , as a sum of products, in which multiples have the types , , , , where . It implies that we can represent the difference as a sum of items of the types
[TABLE]
[TABLE]
[TABLE]
[TABLE]
Items of type (3.82) have the estimate
[TABLE]
Here we apply estimate (3.1) and recall that . Also, term (3.83) has the estimate
[TABLE]
Term (3.84) we estimate as
[TABLE]
At last, for term (3.85) we have estimate (3.81). We obtain
[TABLE]
[TABLE]
[TABLE]
if . Estimate (3.2) follows immediately.
4 Approximation of a family of normal mappings by a smooth family
In this section we suppose that depends on a vector parameter and satisfies conditions of Theorem 2. In this section and in what follows the word ”uniform” applied to an estimate or to a constant means, also, that it doesn’t depend on . We denote by the chart on a fiber. We adopt the notations or with double multi-indexes, as it was described in Section 1. Also, we denote by derivatives in , and by derivatives in with the multi-index . We use the notations or when we aren’t in danger to mix them with notations for derivatives.
The next proposition is a corollary of Lemma 2. It shows that for -derivatives of the normal mappings we have a Holder continuity with respect to the parameters .
Proposition 24
In conditions of Theorem 2 let be the -quasyconformal normal mapping. Then
[TABLE]
for uniform and some and depending only on and .
Proof. By estimate (3.2) of Lemma 2, we have
[TABLE]
[TABLE]
where can be arbitrary radius less than 1 and is such that
[TABLE]
for some uniform . From the other hand, by inequality (1.5), we have
[TABLE]
where depends only on if and is uniform.
Consider the right side of inequality (4.2). Set some . We have
[TABLE]
Put such that , i.e., . We obtain
[TABLE]
Also,
[TABLE]
Put such that , i.e, . We obtain
[TABLE]
At last, by (4.4) and (4.3),
[TABLE]
We obtain for the sum in the right part of inequality (4.2) the estimate , where we can put , .
The main result of this section is the next lemma about approximations:
Lemma 3
In the above assumptions for every and natural there exists a family of mappings smoothly depending on and approximating the family up to derivatives of order
[TABLE]
on . The maps are quasiconformal with complex dilatations and map homeomorphically onto some domain . The mapping is continuous.
There exists the decomposition
[TABLE]
where is the normal map with with the complex dilatation and is a holomorphic univalent function on satisfying the estimate
[TABLE]
at . Derivatives of satisfy estimates analogous to (1.5)
[TABLE]
where is uniform and doesn’t depend on (though it can depend om ).
Proof. Let be a ”cap”, , . We shall consider the approximations
[TABLE]
Since at , we obtain by Proposition 24
[TABLE]
for some and if and .
Now we make depending on . Namely we pick some and define
[TABLE]
Then estimate (4.10) yields
[TABLE]
if .
Introduce also approximations of the functions for
[TABLE]
As a particular case of (4.11) we have the estimates
[TABLE]
at .
Now we describe the construction of our approximation. In what follows . We adopt the notations , , .
We define the functions as the approximations of for . Now, if , we put
[TABLE]
[TABLE]
Analogously, define by induction at , ,
[TABLE]
In particular,
[TABLE]
We prove that at small enough satisfies all conditions of the lemma.
At first, applying (4.11) and (4.12), we see that, if at there holds the inequality , then at
[TABLE]
It follows that , and by induction
[TABLE]
In particular,
[TABLE]
Show now that -derivatives of approximate the corresponding -derivatives of up to degree . In the calculations below it is essential that depends only on and, hence, there don’t appear ”large” derivatives originating from . Consider at first . We have
[TABLE]
[TABLE]
[TABLE]
Thus, applying (4.13) at , we obtain
[TABLE]
Now,
[TABLE]
[TABLE]
Again applying (4.13), we see that
[TABLE]
Proceeding in the same way we obtain at last
[TABLE]
and we have analogous estimates for other differences , . But, by definition of ,
[TABLE]
and, by (4.13) with ,
[TABLE]
Evidently, we have analogous estimates for other derivatives, appearing in the process. Collecting (4.15) - (4.21), we obtain
[TABLE]
where is some integer-valued function of , which we don’t specify here because it is not essential for us. The analogous estimate we have for .
Now consider the -derivative of difference (4.15). We apply to the right part the operator . We have
[TABLE]
[TABLE]
where is the value at zero. When we apply the operator , we obtain the terms
[TABLE]
[TABLE]
and
[TABLE]
We consider these terms exactly as we considered the right side of (4.15). We again reduce the problem to the estimate at . In the same way we proceed with derivatives of the term . The derivative of the multiple yields only the item .
At differentiation of the second term in (4.15)) (the first integral) we obtain the terms
[TABLE]
[TABLE]
and
[TABLE]
All our derivatives are regular at zero. It means that terms of the type , originating from initial values at zero, must annihilate. Subtracting these initial items we obtain for terms (4.25), (4.26) the estimates
[TABLE]
[TABLE]
with some uniform by definition of
Considering term (4.27) we must, analogously, estimate the mixed derivatives of and . Estimate, for example, the first difference. By (4.17), we see that we must estimate , , and . The first two differences are of order by (4.13) and, proceeding as after (4.17), we can see that we can estimates these terms through with , i.e., these terms also are of order .
When we apply operator to the third term in (4.15) (the second integral) we obtain the terms
[TABLE]
[TABLE]
and
[TABLE]
To estimate the first two terms we must estimate the -derivatives of and . We already made it when we considered term (4.27). To estimate the last term we must estimate the the -derivatives of and . Differentiating (4.17) with respect to and we obtain the terms analogous to already considered and the term
[TABLE]
Again analogously to (4.19) - (4.21) we reduce estimation to the inequality at .
The case of derivatives of higher degree is analogous. Applying, for example, operator to the right side of (4.15) we obtain the terms of the types
[TABLE]
[TABLE]
[TABLE]
where is some integer depending on the term. Also, we obtain integrals of the types
[TABLE]
and
[TABLE]
Again the singular parts must annihilate and terms (4.28) -(4.30) have estimates
[TABLE]
and
[TABLE]
Integrals (4.31), (4.32) have the estimates analogous to (4.33), (4.34), only and could be equal to . Analogously to the considerations after (4.17) (see (4.18) - (4.21)) we reduce estimates for right sides of (4.33), ( 4.34) to estimates (4.13) for at , . The maximal degree occurs for the terms
[TABLE]
We proved estimate (4.5).
To show that the mapping is continuous it is enough to prove it for the mapping . By (4.9), this follows from continuity of the mapping . But the last follows from estimate (4.1) of Proposition 24: for any we have as .
Suppose now . We have decomposition (4.6) with some holomorphic . Consider the map . Let be the Beltramy coefficient of the map . By uniqueness, the normal map coincides with . Denote . We have
[TABLE]
since
[TABLE]
We see that, if we fix any , than at appropriate (i.e., at appropriate approximation of )
[TABLE]
[TABLE]
By Lemma 1 for any at appropriate
[TABLE]
From the other hand, since approximate up to second derivatives, we obtain analogous estimates for . Thus we obtain estimates (4.7). Hence, is an univalent function ([Pom]) and is a homeomorphism.
At last consider estimate (4.8). It is enough to prove it for the derivatives of approximation (4.9). We have, for example,
[TABLE]
It follows that (see (4.10), (4.11))
[TABLE]
Also,
[TABLE]
[TABLE]
We again obtain an estimate of type (4.8). We obtain estimates for higher derivatives analogously.
Corollary 1
The form after the change of the variable and division by transforms into the form defined on , where satisfies the estimates
[TABLE]
where and can be made arbitrary small at appropriate approximation and we have the estimate
[TABLE]
with some , .
Proof. It is obvious that there are the estimates
[TABLE]
[TABLE]
But
[TABLE]
for some uniform . Indeed, there is decomposition , where for we have inequalities (2.4) and has the derivative close to 1.
As a result we obtained the important reduction. To prove Theorem 2 it is enough to prove the next theorem:
Theorem 2’. Let be a domain fibered by topological disks and suppose , where is a -quasiconformal map with uniformly bounded away from 1, and the mapping is continuous as a mapping from to . We suppose that satisfies the estimates
[TABLE]
for some uniform ,
[TABLE]
at , ,
[TABLE]
at with some uniform , , and . Also, we suppose that there is a decomposition , where is the -quasiconformal normal map and is a holomorphic univalent function satisfying the estimates
[TABLE]
with some uniform .
Let be a function on satisfying the estimates
[TABLE]
[TABLE]
at
[TABLE]
at . The constant here and in (4.37) can depend on but the exponent doesn’t depend.
Then, if and the constant in (4.39), (4.40) is small enough, there exists a solution to the Beltramy equation
[TABLE]
which is continuous in as a function of , is finitely smooth with respect to all variable up some be-degree , where and can be arbitrary large if and are large enough, at every maps homeomorphically onto some bounded subdomain of , and satisfies the estimates
[TABLE]
[TABLE]
[TABLE]
at ,
[TABLE]
for some uniform and at .
The conditions , are of technical character, we shall use them in Section 7.
5 Extension of quasiconformal mappings
In this section we consider a family of quasiconformal mappings satisfying estimate (4.35) -(4.38) of Theorem 2’. Mostly we have deal with an individual map and we shall omit dependence on . Thus is a -quasiconformal map, mapping onto the domain and
[TABLE]
[TABLE]
at ,
[TABLE]
at with some uniform and . The last two inequalities follow from (4.35) -(4.37). There is the decomposition and, in addition to estimates (4.38), from lemma 1 and (4.36) follows
[TABLE]
at with some uniform . Also, we have the obvious estimates
[TABLE]
for some uniform .
In what follows we shall need estimates for derivatives of the normal mappings in the particular case when all derivatives of are uniformly bounded. ]
Proposition 25
Suppose is smooth, has the support in , and smoothly depends on a vector parameter . Suppose the derivatives satisfy the estimate
[TABLE]
at , with some constant uniform with respect to the parameters. Then the derivatives of the normal mapping satisfy the estimate
[TABLE]
at with some uniform .
Proof. At first we estimate the derivatives of the principal solution . Consider the derivative of first order in . Namely we must estimate -derivatives of the function , where is the solution to the equation
[TABLE]
Differentiating by we obtain
[TABLE]
The -norm of the right side is no greater than and for we obtain the estimate . It follows that for we also have the estimate with some uniform .
At further differentiation we obtain the equation
[TABLE]
where for we obtain by induction the estimate . Thus .
Now remind that for a smooth compactly supported we can represent the function as , where satisfies the equation
[TABLE]
and tends to zero at infinity, i.e., , where is the unique solution to the equation
[TABLE]
For we obtain the equation
[TABLE]
Since , we obtain the estimate . For we obtain by induction the equation analogous to (5.8) with the right side such that and, hence, the same estimate for .
Now, , where satisfies the equation obtained by differentiation of equation (5.7)
[TABLE]
But is holomorphic outside of and tends to zero when . Hence, all derivatives of order higher than one also tend to zero at infinity and the same holds for the function . It implies that , where is the unique solution to the equation
[TABLE]
For we obtain the equation
[TABLE]
Since , we see that , and the right side of equation (5.9) has the -estimate . At further differentiation by parameters we obtain for the equation with the right part estimated in as .
When we consider derivatives with respect to of higher order we analogously can see that we obtain equations with right sides having the estimate with the exponent rising by 1 at each differentiation. As a result, we obtain the estimate
[TABLE]
Consider now the normal solution . By (2.58), (2.59), we can represent as a sum of terms of the types
[TABLE]
where , , . For the product according (5.10) we have the estimate . From the other hand, can be represented as a sum of items of the types
[TABLE]
where is a multiple bounded by a constant independent of , , . But , , according to (5.10). We obtain . We apply estimate (5.10) to and obtain the estimates . for the terms in (5.11). As a result, we obtain for product (5.11) the estimate .
Now we shall motivate the following constructions of this section. When we defined the transforms and in Section 1, we introduced into the kernels the counter-items of the types
[TABLE]
We want to solve the Beltrami equation on the domain , and we need to define analogous counter-items to neutralize the growth of derivatives near the boundary. Namely we must find some map replacing the mapping when we deal with the domain instead of the disk . For that we define some extension of the map on the domain . It appears, we can find a sufficiently good extension if in (4.38) is sufficiently small.
Lemma 4
. Let the family of maps satisfy conditions of Theorem 2’. If is small enough we can define for each an extension of to a quasyconformal homeomorphisms of the plane ; we denote by its restriction on . For the map we have the estimates
[TABLE]
[TABLE]
at ,
[TABLE]
with some depending only on in inequality (4.37) at ,
[TABLE]
[TABLE]
All constants in these inequalities are uniform.
Proof. In most part of the proof we fix some and omit -dependence.
Let , be some sequence tending to 1 and consider the sequence of disks of radii centered at zero. Let be a smooth function on the real axis , . Let , be the functions , . Let be the normal -quasyconformal homeomorphism mapping onto itself and be the map . The homeomorphism maps onto some domain with a smooth boundary and the sequence converges to uniformly on compact subsets of .
On any disk the map can be represented as the composition , where is some function holomorphic on .
From (5.1) - (5.4) and (4.38) immediately follow the estimates
[TABLE]
[TABLE]
at ,
[TABLE]
at ,
[TABLE]
[TABLE]
at . Also, we have the estimate analogous to (4.35), (4.36), and (5.5)
[TABLE]
[TABLE]
at ,
[TABLE]
All constants in these estimates are uniform and independent of and . Below in this section ”uniform” means, in particular, that estimate or constant is independent of and .
From Proposition 25 we obtain
[TABLE]
[TABLE]
with some independent of at .
Proposition 26
There exists some uniform such that at
a)
[TABLE]
[TABLE]
b)
[TABLE]
[TABLE]
c)
[TABLE]
[TABLE]
Everywhere depends only on in (5.1).
Proof. a) The second inequality is a limit case of the first one. We apply inequality (3.2) of Lemma 2 to estimate . We estimate different terms in the right-side. At first consider .
The functions and differ only in the ring . Hence,
[TABLE]
[TABLE]
with some depending on . Thus,
[TABLE]
Now, since on , we obtain putting
[TABLE]
At last, for such that . Thus we obtain (5.28) with .
b) Let prove inequality (5.30).
[TABLE]
But
[TABLE]
[TABLE]
Here we applied estimates (4.38). Hence,
[TABLE]
according estimates (2.4).
Also, applying (4.38), (2.4), estimate (3.1) of Lemma 2, and (5.34), we have
[TABLE]
for some depending only on in (5.1).
At last,
[TABLE]
on and, hence, . Thus,
[TABLE]
by (5.29), if . Taking into consideration (5.35) and (5.36), we obtain (5.30).
The proof of inequality (5.31) is analogous. We have
[TABLE]
Applying (4.38) and (5.4), we can see that
[TABLE]
[TABLE]
Hence,
[TABLE]
Also, applying (5.4), (2.4), estimate (3.1) of Lemma 2, and (5.34), we obtain
[TABLE]
for some depending only on in (5.1).
As above, from (5.37) we have . Thus,
[TABLE]
[TABLE]
Consider the right side.
[TABLE]
by (4,38), (2.4) and (5.29).
[TABLE]
by Lemma 1 and (5.38). At last, the difference we estimate by inequality (3.2) of Lemma 2. From, in fact, the same considerations as in the proof of inequality (5.28), we can see that
[TABLE]
Thus,
[TABLE]
Collecting inequalities (5.39) - (5.41) we obtain (5.31).
c) We have
[TABLE]
[TABLE]
The required estimates follow from (5.38) and (5.41). .
Now we shall prove the lemma itself. We proceed in several steps.
- First extension of the map .
We use the modified construction of the Loewner chains from the theory of univalent functions. For a function we write .
We say that the family of functions ( is a Loewner chain if there exists a function such that and
[TABLE]
For any vector is the vector of the outer normal at a boundary point of the set . Condition (5.42) means that
[TABLE]
and this means that the velocity vector on the boundary points out of this set.
Instead of conditions (5.42), (5.43) we shall use the equivalent condition
[TABLE]
In what follows we denote by the operators
[TABLE]
For define the function . It is the symmetrical extension of .
Now define for
[TABLE]
Let check for this function condition (5.44) at . We denote by the chart in the image of maps and and by the chart in the preimage of this map. We have
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
Applying inequalities (2.4) and estimate (2.1) of lemma 1 to , we obtain
[TABLE]
for some independent of at . Hence,
[TABLE]
[TABLE]
[TABLE]
for some independent of . The last inequality holds since at , and .
Also,
[TABLE]
[TABLE]
Hence,
[TABLE]
Also,
[TABLE]
at for some independent of . Thus dividing by and applying estimates (5.18) and (5.21) we obtain
[TABLE]
for some uniform . We see that is a Loewner chain at small enough if .
Now we define
[TABLE]
at .
We prove that is a quasyconformal homeomorphism of extending . At first we note that for represented in the form , . Thus in some neighborhood of the unite circle the function maps the point into a point on the trajectory of the vector field starting at . As it follows from (5.18), (5.21), the map extends to a -diffeomorphism of the unit circle onto the boundary . Our vector field is transversal to this boundary and we obtain homeomorphism of some neighborhood of extending .
Now we prove that is a local homeomorphism at any point with the complex dilatation bounded by some constant less than 1 depending only on . We denote . We have
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
We have analogously to (5.45)
[TABLE]
[TABLE]
Thus,
[TABLE]
[TABLE]
for some depending only on . Taking into consideration (5.46), (5.47), we see that is bounded away from zero and is bounded by some uniform constant .
We don’t consider behavior of our mapping at infinity because on the next step we modify it outside some .
- Modification of .
At we define
[TABLE]
Let be some monotonic smooth function, , , . Set some and define at
[TABLE]
Proposition 27
There exists some uniform such that at
[TABLE]
where is the exponent from Proposition 26, the map defined on as and on as is a quasiconformal homeomorphism of the plane with uniformly bounded dilatation and with derivative uniformly bounded from below and from above.
Proof. At first we prove that we can find such that on the domain the map is a local homeomorphism.
Analogously to (5.49), (5.50) and applying (5.51), we obtain
[TABLE]
[TABLE]
[TABLE]
[TABLE]
Applying estimates (5.30), (5.31) and (5.51), we see that
[TABLE]
[TABLE]
with some uniform . Taking into consideration inequalities (2.4), we see that at appropriate uniform the map is a local homeomorphism on the domain .
To consider behavior of our mapping at infinity we put and consider the function . It is easy to see that as and , . It implies that extends as a local homeomorphism on infinity.
It remains to prove that is a local homeomorphism on the domain . Indeed, then the map extends to a a local homeomorphism of the sphere and, hence, is a homeomorphism by the monodromy theorem.
On the domain
[TABLE]
where . We have
[TABLE]
By (5.52) and (5.59),
[TABLE]
Also, by (5.53) and (5.60),
[TABLE]
Thus in the domain
[TABLE]
[TABLE]
with some uniform , if we set as in (5.56).
Consider now . Since , we have
[TABLE]
But
[TABLE]
since is uniformly bounded. Also, taking into consideration (5.34),
[TABLE]
Thus,
[TABLE]
According to (5.48) and (5.54) and applying also estimate (5.30), we obtain
[TABLE]
Since , we see that if we set as in (5.56), then
[TABLE]
and analogous estimate holds for .
Recalling also (5.61), (5.62) we see that in the domain we have the estimates
[TABLE]
[TABLE]
We see that at appropriate uniform is a local homeomorphism. The assertions about the dilatation and the derivative follow from estimates (5.52), (5.53) for , (5.59), (5.60) and the last estimates.
- The final extension of and the extension of .
Now we define new extensions . Fix and put . As on the previous step, is some monotonic smooth function, , , . Let , be some sequence of constants, which we shall specify later. We define
[TABLE]
at ,
[TABLE]
at ,
………….
[TABLE]
at .
Now we specify the sequences , and . We put
[TABLE]
where and are the constants from Proposition 27.
Proposition 28
If we define the sequences , and according to (5.63) with some appropriate uniform , then the map extended on as will be a quasiconformal homeomorphism of the plane, and the derivative will be uniformly bounded from below and from above. On each domain ,
[TABLE]
Proof. It is easy to see that, if we set according to (5.63), the map will be described by expression (5.64) on each ring , . We must check only that it is a local diffeomorphism on any such domain. By induction, it is enough to check it for .
We have
[TABLE]
where . The analogous expression we have for . We have
[TABLE]
By (5.57), (5.59), (5.31), and taking into consideration (2.4),
[TABLE]
[TABLE]
[TABLE]
[TABLE]
Now, applying (5.28) and (5.32), we have
[TABLE]
[TABLE]
with some uniform .
Now remind that is uniformly bounded from below and from above since the first derivatives of and are uniformly bounded from below and from above, and since by properties of univalent functions (see [Pom]).
We see that the second difference in the right side of (5.65) is no greater then the sum of the terms: first,
[TABLE]
[TABLE]
since (see (3.1) and (5.34)); second,
[TABLE]
[TABLE]
by (5.51) and (5.28); and third,
[TABLE]
[TABLE]
by (5.51) and (5.32).
Thus,
[TABLE]
Analogously we obtain
[TABLE]
with some uniform .
Now we shall estimate . Since , we see that if . We must only estimate the difference of the terms containing and . We have
[TABLE]
by (3.1) and (5.34), and
[TABLE]
by (5.51) and (5.31).
Since , we see that
[TABLE]
in the ring . For we have an analogous estimate.
As a result, collecting (5.66), (5.67), and the last estimates, we obtain
[TABLE]
[TABLE]
where is the constant from inequality (5.56) and is some uniform constant independent of . At appropriate we obtain that is a quasyconformal map with uniformly bounded dilatation and the derivative uniformly bounded from below and from above.
Now we define the extension as the limit of . By definition, if . Thus converge to a quasiconformal map on with derivative uniformly bounded from below and from above. Also, the map defined as on and as on is a one-to-one mapping. Indeed, if , then the domains and must intersect at great enough . Thus we obtained a homeomorphism of the plane and proved estimate (5.13).
- Proof of estimates (5.14) and (5.15).
It is enough to prove that these estimates hold for at .
The maps and satisfy the estimates , . From the equation by successive differentiation we obtain the estimate
[TABLE]
Also, we have estimates (5.26), (5.27) for and .
According to representations (5.64), (5.54) the derivative is a sum of items containing the multiples , , which don’t influence an order in and multiples of the types
[TABLE]
and analogous terms containing , . Also, there can be the multiples
[TABLE]
At differentiation of each multiple of type (5.68) we increase in order in by one. From the other hand, differentiation of multiple (5.69) results in the additional multiple . On our ring it is a value of order . By induction, we obtain estimate (5.14).
Now derivatives with respect to the parameter of terms of types (5.67) all have estimates for some by (5.26) and (5.27). But, if we set , and according to (5.63), we have
[TABLE]
Again differentiation of terms with results in multiples with some . Thus on the ring we obtain estimate (5.15) with some uniform and .
5). Proof of estimates (5.16), (5.17).
We know that is a quasiconformal homeomorphism mapping onto with complex dilatation . We can represent as a composition , where is a normal homeomorphism mapping onto itself and is an univalent holomorphic function. From estimates ((5.13) and (5.14) at follows that at . By Lemma 1, for some constants , . Applying (5.13), we see that for we have analogous estimates. But for any univalent function we have
[TABLE]
with some uniform (see [Pom]). Since for we have estimates (2.4), we obtain (5.16).
Let prove (5.17). The left inequality follows from (5.16) because .
Suppose now that . Now, by (5.64), we must estimate and . Applying (5.54) and (5.51), we obtain
[TABLE]
But at and, hence, . Analogously, we can see that . Also,
[TABLE]
[TABLE]
By (5.51), this difference has the estimate . As a result, we obtain right inequality (5.17).
6 Integral operators. -estimates.
We adopt the notations of the previous section. For , we define
[TABLE]
Proposition 29
There are the estimates
[TABLE]
[TABLE]
[TABLE]
[TABLE]
with uniform , . .
Proof. The first estimate follows immediately from (5.17). The second one, also, follows from (5.16) and (5.17), taking into consideration that
[TABLE]
Prove left estimate (6.4). It is enough to prove that the map has uniformly bounded derivatives. But , where has a bounded derivative and is the normal map with the Beltramy coefficient , and by Lemma 1 and estimate (2.4) at . Again by Lemma 1 we obtain that are uniformly bounded. Analogously,
[TABLE]
Now let be a point on closest to (there can be several such points but it isn’t essential). Suppose at first that . Then
[TABLE]
for some uniform . From the other hand, if , then, applying (6.5) and (6.6), we obtain
[TABLE]
for some uniform .
From the other hand, according to (4.35) and (5.13), the map extended on as is a Lipshitz homeomorphism of the plane with an uniformly bounded Lipshitz constant. Thus we obtain right estimate (6.4).
Now we define integral transforms, which allow as to find solutions to the Beltrami equation on with required estimates on the boundary. We define
[TABLE]
[TABLE]
The last representation follows from the identity
[TABLE]
Differentiating in we obtain the transform
[TABLE]
[TABLE]
Here we understand the integral in terms of its principal value. In the chart we have
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
Definition 2
We say that a function on belongs to if the function belongs to . We denote by the -norm of the function . A function belongs to if is uniformly bounded. We denote by the -norm of the function .
The equivalent conditions are: belongs to and is uniformly bounded on . Corresponding norms are equivalent to the norms of the Definition.
We will need in the following estimates:
Proposition 30
Define the integrals
[TABLE]
[TABLE]
Suppose . Then
[TABLE]
where , .
Proof. a) Applying estimates (6.4) and (6.5) we can see that we must show that the integral
[TABLE]
has the estimate
[TABLE]
and that the analogous integral
[TABLE]
has the estimate
[TABLE]
Let be the map
[TABLE]
We have
[TABLE]
[TABLE]
The Jacobian of the change of the variable is
[TABLE]
After this change of the variable we can write integral (6.12) as
[TABLE]
But for some uniform , and we see that it is enough to show that the integral
[TABLE]
is uniformly bounded. But we can write this integral as a sum of the integral over the disk and of the integral over the ring . The first integral is no greater, than
[TABLE]
And the second one is no greater, than
[TABLE]
Both these integral are uniformly bounded and, hence, integral (6.14) has the estimate .
Now notice that also reduces to integral (6.14), and we obtain estimate (6.13) exactly as (6.12) .
The following estimate is a corollary of this proposition.
Proposition 31
Let belongs to . Then
[TABLE]
with some uniform .
Proof. By (6.3), we have
[TABLE]
We apply first estimate (6.11).
Proposition 32
Define the operators:
[TABLE]
and
[TABLE]
where is uniformly bounded function. These operators are bounded in , . As a consequence, the operators and are bounded in , .
Proof. Consider the operator . From boundedness of the derivatives of and estimates (6.4), (6.5) follows that we can write
[TABLE]
where and are uniformly bounded from below and from above.
The operator obviously is bounded in any for functions supported in any domain . Suppose that the support of is contained in the domain . Go to the chart on the disk . Recalling that the Jacobian of the transformation is uniformly bounded, we see that we must estimate the norm of the operator
[TABLE]
Introduce a new variable . Then . Integral (6.15) transforms to
[TABLE]
where , and is the Jacobian of the transformation . Here we take the integral over . Remind that support is contained in the domain , the Jacobian is uniformly bounded on this domain, and . The below considerations follow the method described in [Ah, Ch. 5, D].
Let be . Our integral is of the type
[TABLE]
where We have
[TABLE]
We can suppose that the functions and are real. We have
[TABLE]
for some and, hence,
[TABLE]
Let this maximum corresponds to . The norm in the right side doesn’t change if we replace by . If we denote , the integral in the right side becomes
[TABLE]
The point doesn’t belong to the support of and the value of the integral doesn’t change if we extend the function of : as zero on the domain , extend the integral over this domain, and take the principal value. Hence,
[TABLE]
for some by one-dimensional Calderon-Zigmund inequality. Now we get for the two-dimensional norm
[TABLE]
[TABLE]
Since the functions and have equal -norms and the -norm of can be estimated through -norm of , we obtain the required estimate.
Consider now the operator . The first item under the integral in the right side of (6.8) is the Beurling transform bounded in . The other items are the integrals
[TABLE]
These integrals are of the type considered above for .
The case of the operators and is analogous. It is even simpler because we don’t need now in the change of the variables . The proof with this exception repeats the proof for .
Proposition 33
Suppose an operator satisfies the estimate
[TABLE]
Then this operator is bounded in for .
Proof We shall prove the boundedness in and . Then the general case will follow from the Riesz-Thorin interpolation theorem (see, for example, [RS]). We have
[TABLE]
[TABLE]
by the second estimate of Proposition 30.
From the other hand,
[TABLE]
[TABLE]
by the first estimate of Proposition 30.
Proposition 34
Let , , be the operators
[TABLE]
[TABLE]
[TABLE]
. These operators are bounded in for at .
Proof. Suppose at first that , . Than the operators satisfy the estimate of the previous proposition.
Suppose that , . We have
[TABLE]
[TABLE]
[TABLE]
where is an operator of the type considered in Proposition 22, and we obtain the estimate in .
Now suppose , . We have
[TABLE]
[TABLE]
In the right side we have the sum of two integrals, where the first one is of the type considered in Proposition 22 and the second one satisfies estimate of Proposition 23.
Suppose now . We have
[TABLE]
Again we obtain the sum of two integrals, where the first one is of the type of Proposition 22 and the second one is .
The case of is analogous. We prove estimate only for , which we shall apply below.
[TABLE]
[TABLE]
Again we have the term satisfying conditions of Proposition 22 and the term satisfying the estimate of Proposition 23.
Consider now the operator . We can write in the form
[TABLE]
[TABLE]
The first integral is bounded in by the Kalderon-Zigmund inequality. The second integral after multiplying by is
[TABLE]
[TABLE]
[TABLE]
All items of the both sums are of the types considered in Proposition 34. For example, the last item of the first sum is and the last item of the second sum is .
For the completeness we consider also the case of non-integer , though it isn’t very essential. It is easy to see that boundedness in of the operator is equivalent to boundedness in of the operator , where
[TABLE]
. Indeed, , where .
Define the family of operators , ,
[TABLE]
It is an analytic family of operators. On the left and right boundaries of the strip the -norms of are uniformly bounded. Indeed, these operators differ from the cases already considered only by the multiple under the integral, which we can include in the function , and by the multiple , which doesn’t change the -norm. Thus the conditions of the Stein interpolation theorem (see, for example, [RS]) for this family of operators are satisfied, and we obtain -estimates for all .
Proposition 35
The operators are bounded in for , , .
Proof. Denote . It is enough to prove the estimate
[TABLE]
Recalling (6.8), we see that the estimates for in follow from the estimates for the integrals and obtained in the previous proposition.
7 The operator and uniform estimates.
Now we return to the program described in Section 1. Our purpose is to prove Theorem 2’. We can find a solution to the Beltrami equation with satisfying conditions of Theorem 2’ analogously to the classical method replacing the transforms and by the transforms and . In such a way we obtain the solution with estimates of its derivatives with respect to the parameters, but this solution isn’t necessary a homeomorphism mapping of onto its image.
But we can obtain a -quasiconformal homeomorphism if we find a solution to the Beltramy equation , which is -quasiholomorpic and satisfies the estimate
[TABLE]
with sufficiently small . Indeed, , where satisfies estimates (4.38), and is quasiholomorphic on with the complex dilatation . It isn’t difficult to check that we can write as , where is the -normal map and is holomorphic, and if the constants in (4.38) and in (7.1) are small enough. Here we don’t give details because we shall return to these matters in the next section. It follows that is univalent (see [Pom]) and, hence, is a homeomorphism.
Now, if is a -quasiholomorphic map, then satisfies the equation
[TABLE]
We can solve this equation by iteration method. On the first step we find a function satisfying the equation . If is such that with sufficiently small , then we shall solve the equation and so on. On each step we must solve the equation
[TABLE]
where for some . We can hope that there exist solutions represented as
[TABLE]
with appropriate and that these solutions have the estimate . There is a difficulty, the transform hasn’t good uniform estimates. The key observation is that we can change the order of integration in each term of series (7.3) and write these series as
[TABLE]
[TABLE]
where is the kernel of the operator
[TABLE]
and is the transform
[TABLE]
This operator has the same kernel as but with transposed and .
The main reason, why it is useful to change the order of integration is that contains the multiple , and isn’t a variable of integration. As a result, has better uniform estimates than . For example, the integral
[TABLE]
is bounded and the integral
[TABLE]
isn’t.
Thus we can write the sum of series (7.3) (defined at this moment only formally) as
[TABLE]
where satisfy the equation
[TABLE]
Suppose this equation has a solution that we can represent as
[TABLE]
where is an uniformly bounded function. Than, applying the estimates of Proposition 29 and the first estimate of Proposition 30, we obtain for integral (7.6) the estimate . Thus we must prove that for the solution to equation (7.7) there exists representation (7.8).
In fact, we shall prove a more general assertion.
Lemma 5
Suppose and satisfy the conditions of Theorem 2’. Suppose a function can be written in the form
[TABLE]
where is uniformly bounded and
[TABLE]
with some uniform . Then at the equation
[TABLE]
has a unique solution representable in the form
[TABLE]
where is uniformly bounded.
Proposition 36
The function satisfies conditions (7.9), (7.10).
Proof. The only nontrivial part is to prove estimate (7.10) for
[TABLE]
Note at first that for some and we have an analogous estimate for . From estimate (6.2) follows that for some . Hence, if , then for some uniform the derivatives and are no greater than on the segment , and we obtain estimate (7.10).
Suppose now that . Then for some and inequality (7.10) is trivial because is uniformly bounded. .
We shall prove Lemma 5 in the next section. Now we shall obtain some estimates necessary to the proof.
Apply the transform to a function of type (7.12). We have
[TABLE]
Since
[TABLE]
we see that, if satisfies equation (7.11), then must satisfy the equation
[TABLE]
where is the transform
[TABLE]
[TABLE]
We denote by the kernel of this operator. In the rest of this section we study the operator .
In what follows we denote by the characteristic function of the domain . As we shall show below, even at the action of on there appears the term with singular derivatives. Therefore, when we consider the action of the transform , we must distinguish the ”bad” part and study the action of on this part. The next proposition describes the situation.
Proposition 37
Suppose and satisfy the conditions of Theorem 2’. Let , be the functions
[TABLE]
Suppose . Then
[TABLE]
with some uniform independent of ( is the constant from estimate (4.40)).
Fix a point . Then
[TABLE]
where satisfies the estimate
[TABLE]
with some uniform independent of .
Proof. In what follows we denote
[TABLE]
We have the representations
[TABLE]
where
[TABLE]
There exists some uniform such that the disks and centered at and of radii and correspondingly are contained in . In what follows we shall specify and .
We need in some estimates, which we collect in the next proposition.
Proposition 38
For there are the estimates
[TABLE]
[TABLE]
For we have the estimates
[TABLE]
[TABLE]
[TABLE]
and analogous estimates we have for multi-indexes containing and -derivatives. All constants are uniform.
Proof. Denote by the function . By (5.13), (5.14), we have the estimates
[TABLE]
We prove only estimates (7.19) - (7.23). The cases of and -derivatives are analogous.
To prove inequalities (7.19) we must estimate and at . In what follows we denote by fractions of the type
[TABLE]
where , , .
The derivative contains the terms of the types
[TABLE]
The first two terms obviously have estimates (we apply first estimate (7.24)). The last term has estimate . At it is equivalent to the estimate .
Consider now . There appear the terms
[TABLE]
[TABLE]
[TABLE]
Again applying first estimate (7.24) and taking into consideration that , we obtain for all these terms the estimate .
Estimate (7.20) easily follows from (7.24).
First two estimates (7.21) follow from (7.19) if we put . To prove the third estimate we consider the derivative at . Analogously to (7.25) - (7.27), there appear the terms
[TABLE]
[TABLE]
As above, we see that all these terms have the estimate (here we must apply also second estimate (7.24)).
To prove inequalities (7.22) we estimate and -derivatives of terms (7.28), (7.29). Again, when we differentiate , there appears the multiples
[TABLE]
All these multiples are of order . Other multiples appearing at differentiation are
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
As above, we obtain the estimate at .
To prove inequality (7.23) we must estimate . As above, at each differentiation we either obtain the additional multiples or either replace a derivative of the function by a derivative of order higher by 1. In either case we obtain an expression of order .
Remark. The fact that we must differentiate up to the forth order and use estimate (7.23) explains the conditions , of Theorem 2’.
Return now to Proposition 37. We shall consider the cases corresponding to various items in the kernel of integral (7.14).
- Consider at first the integral
[TABLE]
Proof of representation (7.16) for . Suppose at first that and consider the integral over the domain . We have representation (7.18) and the representation
[TABLE]
where satisfies the estimates
[TABLE]
for some uniform .
Thus we consider the integral
[TABLE]
At first we estimate the integral
[TABLE]
The first integral in the right side up to the multiple is the value of the Beurling transform of the function in the point . But it is easy to obtain this transform in the explicit form. Indeed, consider the function equals to
[TABLE]
in and to
[TABLE]
in . This function is continuous, tends to zero at infinity, and its -derivative (in the sense of distributions) equals to . Hence, -derivative of this function is the Beurling transform of . Thus,
[TABLE]
at . We see that we can write the first integral in the right side of (7.32) as
[TABLE]
where is uniformly bounded. Below we shall prove that satisfies estimate (7.17).
Now we can estimate the second integral in the right side of (7.32) as
[TABLE]
for some uniform . We obtain for the representation
[TABLE]
with uniformly bounded .
Now to finish with integral (7.31) we must estimate the integral
[TABLE]
where , , and we have analogous estimate for according to (7.30), (7.20). Consider at first the integral over . Under the integral we have the function
[TABLE]
where -derivatives of the function we can estimate as
[TABLE]
Thus we can estimate integral (7.33) over as
[TABLE]
for some since is a disk of radii . We estimate integral (7.33) over analogously to the second integral in (7.32) applying estimate (7.34).
Now, let , and consider the integral over . Instead of (7.31) we use the representation
[TABLE]
Here for and we have estimates (7.30) and (7.18). We act as above but this case is more simple, we don’t need in estimates (7.20). We estimate the integral
[TABLE]
as
[TABLE]
for some uniform .
Instead of (7.33) we have the integral
[TABLE]
where . Acting as above we obtain the estimate .
Now we estimate the integral over .
We set , . Let be the function
[TABLE]
and define . Note that .
Since and , it is enough to estimate the integral
[TABLE]
[TABLE]
where is the Jacobian of the change of the variable .
Now, by inequality (6.4), we have
[TABLE]
for some uniform . But
[TABLE]
From the other hand, the domain contains some domain
[TABLE]
where is some uniform constant. Thus on . In particular, the domain contains some disk of radius uniformly bounded from below. Applying (7.35), we see that on
[TABLE]
for some uniform . We see that it is enough to estimate the integral
[TABLE]
Applying (6.2) and (6.5), we see that we must estimate the integral
[TABLE]
We have
[TABLE]
[TABLE]
[TABLE]
where we denote
[TABLE]
We see that integral (7.35) equals to
[TABLE]
[TABLE]
This integral is uniformly bounded at .
For convenience we write here the ”general term” that appears in various integrals when we make the change of the variable: and neglect uniformly bounded multiples. We denote
[TABLE]
We write our correspondence in the form
[TABLE]
Proof of estimate (7.17) for .
Fix some . Note that it is enough to prove estimate (7.17) when . Indeed, with some uniform if and we obviously have estimate (7.17) since .
Let , , be three disks centered at of radii , , . There can be the case when at least one of the points or belongs to . We set in this case. The other point then belongs to and both disks and are contained in . We put in this case and if both or don’t belong to . Thus we can consider only the cases:
a) contains and , ,
b) both and don’t belong to , .
In the following proof we shall consider cases a) and b) separately.
Case a). The difference of the integrals over .
We estimate the difference of the integrals
[TABLE]
We represent this difference as
[TABLE]
[TABLE]
We shall estimate the difference of these integrals in several steps. The integral
[TABLE]
equals to , as we already saw. Now , where and at and . It follows
[TABLE]
[TABLE]
[TABLE]
Thus we obtained the representation
[TABLE]
where
[TABLE]
Now consider the integral
[TABLE]
[TABLE]
We represent the expression in the square brackets under the integral as
[TABLE]
[TABLE]
where, by (7.20), we have the estimates
[TABLE]
and, by (7.21), (7.22),
[TABLE]
[TABLE]
where means -derivative with multi-index .
Return now to integral (7.44). At first we consider the integral
[TABLE]
We must calculate the difference in the points and of the Beurling transform of the function . But this transform equals to
[TABLE]
if . Indeed, the Cauchy transform of the last function equals to
[TABLE]
in and
[TABLE]
in . Indeed, this function is continuous, tends to zero at infinity, and its -derivative (in the sense of distributions) equals to . Hence, -derivative of this function is the Beurling transform of . We see that integral (7.48) equals to
[TABLE]
We obtain the estimate
[TABLE]
since the first order derivatives of the function have the uniform estimate , and for we have estimate (7.45).
Now consider the difference
[TABLE]
We make the change of the variable in the first integral and denote by the domain . We get the sum
[TABLE]
[TABLE]
We represent the first integral as
[TABLE]
[TABLE]
We consider the first integral in right side analogously to integral (7.33). We see that we must estimate
[TABLE]
[TABLE]
But for some . We apply inequalities (7.46) and (7.47) and obtain the estimate . From the other hand, we can represent the difference
[TABLE]
as , where for we have the estimates , , . We see that we can estimate the second integral in the right side of (7.49) as
[TABLE]
[TABLE]
Here we again apply estimates (7.45), (7.46).
The second and third integrals in (7.49) are over the lunules and of width . We estimate, for example, the second integral as
[TABLE]
[TABLE]
since for some and we have estimates (7.45), (7.46).
Now to finish with integral (7.44) we must estimate the integral
[TABLE]
Applying (7.45), (7.46), we obtain the estimate
[TABLE]
Case a). Difference of the integrals over .
We put . We must estimate the difference of the integrals
[TABLE]
[TABLE]
where
[TABLE]
Here is the Jacobian of the transformation .
It is enough to estimate the -derivative of the integral over . Now we can differentiate under the integral, i.e., we must estimate the expression
[TABLE]
We have
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
Now it is easy to see that for we have the same estimate (7.42) as for
[TABLE]
Applying (7.52) and (7.36), we see that difference (7.51) has the estimate at .
Case b). The difference of the integrals over and .
This case is more simple. We put . In the integrals over and we change the variable and correspondingly. Thus we must estimate the integral
[TABLE]
Applying estimate (7.19) and estimates for derivatives of we represent the difference in the square brackets as
[TABLE]
where with some uniform . Further,
[TABLE]
and
[TABLE]
It proves the estimate in our case.
Case b). The difference of the integrals over and . At first we unify the domains of integration.
Proposition 39
Suppose, as above, , . If is small enough with some uniform estimate there exists a homeomorphism mapping the ring onto the domain . We can represent the map as a composition
[TABLE]
where is a homeomorphism mapping the ring onto the domain . Denote . For the map we get the estimates
[TABLE]
[TABLE]
Proof. The domain with the boundary transforms under the mapping onto some domain with the boundary, described by the equation
[TABLE]
If is small enough with some uniform estimate, then this domain is star-like with respect to . Indeed, we have the estimates
[TABLE]
Hence, we can write
[TABLE]
where if belongs to the curve described by equation (7.56). Also,
[TABLE]
where , . Thus we can write -derivative of the left side of equation (7.56) in the form
[TABLE]
[TABLE]
where with some uniform . The right side of (7.57) by modulus is no less, than and non-equal to zero for sufficiently small . It follows that the domain with boundary (7.56) is star-like.
Applying the change of the variable we obtain the domain with the boundary described by the equation:
[TABLE]
Here we use the same notations in the chart : . This domain is also star-like with respect to zero and we see that its boundary can be described also by the equation . By differentiation of equation (7.58) we get the estimates for the derivatives
[TABLE]
[TABLE]
By homothety along radii we define a diffeomorphism mapping the ring onto the domain . We use the same notation for the chart in the preimage of . The estimates for yield following estimates for
[TABLE]
and we have analogous estimates for derivatives containing or .
The map maps the chart onto the original chart . We obtain estimates (7.53), (7.54) applying (7.59), estimates for derivatives of , and the estimate
[TABLE]
at .
Return now to the integral over the domain . We can write it as
[TABLE]
where
[TABLE]
Here is the Jacobian of the transformation .
As above, to estimate the difference of the integrals over and it is enough to estimate -derivative of this integral.
Again we can differentiate under the integral, i.e., we must estimate the integral
[TABLE]
[TABLE]
[TABLE]
We have
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
Now we note that and apply estimate (7.42). Also, we can apply formulas (7.35) and (7.38) - (7.40) with . For derivatives of we have estimates (7.53), (7.54). We obtain
[TABLE]
[TABLE]
[TABLE]
[TABLE]
Again
[TABLE]
in our domain analogously to estimate (7.36). We see that the first integral in (7.60) has the estimate
[TABLE]
We obtain estimate at . Analogously, the second integral in (7.60) has the estimate (here we apply estimate (7.53))
[TABLE]
We also obtain estimate at .
Consider the last integral in (7.60). Applying (7.53), we have
[TABLE]
Again applying estimate (7.42) to , we obtain
[TABLE]
at . Also,
[TABLE]
Applying (7.53), we get for this function the estimate
[TABLE]
Again applying (7.42), we obtain
[TABLE]
at . It finishes the proof of estimate (7.17) for .
[TABLE]
We follow the same steps as in case 1).
Proof of representation (7.16) for . At first we consider the case and the integral over , i.e., we consider the integral
[TABLE]
We set and consider at first the integral over .
The integral
[TABLE]
up to the multiple is the Cauchy transform of the function . This Cauchy transform equals to
[TABLE]
at and
[TABLE]
at . Indeed, this function is continuous, tends to zero at infinity, and its -derivative (in the sense of distributions) equals to .
Analogously to case 1) we obtain the representation
[TABLE]
where is uniformly bounded and, as in case 1), we shall show that it satisfies estimate (7.17).
The integral
[TABLE]
we estimate as
[TABLE]
since .
To estimate the part of the integral over the domain it is enough now to estimate the integral
[TABLE]
where . This integral obviously has the estimate .
If we estimate the integral
[TABLE]
essentially as in case 1). We obtain the estimate
[TABLE]
Consider now the integral over . Analogously to case 1) we make the change of the variable . We have
[TABLE]
[TABLE]
where is defined by (7.41). Applying (7.36), (7.42) and (7.63), we see that it is enough to estimate the integral
[TABLE]
We obtain an uniform boundedness at .
We obtained the representation
[TABLE]
where . Note that the sum of the coefficients and of cases 1) and 2) equals 1.
Proof of estimate (7.17) for . We can assume, as above, .
Let , , , be four disks centered at of radii , , , . There can be the case when at least one of the points or belongs to . We put in this case. The other point then belongs to and both disks and are contained in . We put in this case. If both or don’t belong to we put . In the last case we can set such that and . Thus we can consider two different cases: .
a) and belong to , ,
b) both and don’t belong to , , .
Again in the proof we consider cases a) and b) separately.
Case a). The difference of the integrals over .
We consider the difference
[TABLE]
We represent this difference as
[TABLE]
[TABLE]
Consider at first the difference of the integrals over . As in case 1), there is the term
[TABLE]
[TABLE]
and .
It remains to estimate the integral (see (7.44)
[TABLE]
[TABLE]
where , , satisfy estimates (7.45) - (7.47).
The integral
[TABLE]
up to the constant is the difference in the points and of the Cauchy transform of the function . As above, this difference equals to
[TABLE]
and, as in case 1), we obtain the estimate .
Now consider the difference
[TABLE]
As in case 1), we make the change of the variable: in the first integral and denote by the domain . We obtain the sum
[TABLE]
[TABLE]
We again represent the first integral as
[TABLE]
[TABLE]
Applying the estimate
[TABLE]
and acting as in case 1), we see that integral (7.67) is no greater, than
[TABLE]
[TABLE]
Applying (7.45), (7.46), we obtain for integral (7.67) the estimate
[TABLE]
The second and third integrals in (7.66) we estimate analogously to the corresponding terms in (7.49). We estimate, for example, the second integral as
[TABLE]
Now to finish with integral (7.65) we must estimate the integral
[TABLE]
Applying (7.45), we obtain the estimate
[TABLE]
Case a). The difference of the integrals over .
We act as in case 1). After the change of the variable we differentiate under the integral and analogously to (7.51) we get the integral
[TABLE]
We apply (7.52), (7.53), (7.36) and take into consideration that for some uniform if . We obtain the estimate for integral (7.68) at .
Case b).
There is a difference by comparison with case 1). We have an additional pole in and, after transition to the chart on , we can’t differentiate under the integral.
We use the decomposition
[TABLE]
We define
[TABLE]
and
[TABLE]
We write
[TABLE]
[TABLE]
[TABLE]
In what follows we consider several cases corresponding to different terms in the right side.
The difference of the integrals and over and .
We must estimate the difference
[TABLE]
As in case 1), we change the variable and in the integrals over and correspondingly and denote . We get the integral
[TABLE]
If and , then at we use the estimates
[TABLE]
[TABLE]
Thus for integral (7.70) we obtain the estimate
[TABLE]
The difference of the integrals and over and .-
We proceed analogously to case 1) and apply Proposition 39. After change of the variable and differentiation we obtain the expression
[TABLE]
[TABLE]
[TABLE]
The distinction from integrals (7.60) is that we replace the multiple with the multiple in the first and third integrals and replace the multiple with the multiple in the second integral. As a result, these integrals have the uniform estimate instead of . Together with estimate (7.73) it yields the estimate
[TABLE]
Since for some in our case, we obtain the estimate for the first term in the right side of identity (7.69).
The difference .
The singular term doesn’t depend on and we can differentiate under the integral. Namely we must show that the integral
[TABLE]
is uniformly bounded. After obvious calculations we can write
[TABLE]
[TABLE]
where
[TABLE]
The last term in (7.75) by modulus is no greater than . After the change of the variable applying (7.63), (7.42) and (7.39) we obtain the estimate for integral (7.74)
[TABLE]
This integral is uniformly bounded at .
The last term in identity (7.69).
We have
[TABLE]
[TABLE]
We already proved the uniform estimate for . Thus we estimate (7.17) for all terms in(7.69).
[TABLE]
After two ”difficult” cases this case is ”simple”. We estimate the integral introducing our usual chart . Applying (7.35), (7.39), and (7.42), we see that we can estimate our integral as
[TABLE]
We obtain the estimate at .
Proof of estimate (7.17) for .
If we set and as in case 1), we again can consider two cases:
a) contains and , ,
b) both and don’t belong to , .
Case a) The difference of the integrals over .
We represent the integral as
[TABLE]
[TABLE]
[TABLE]
where for , and we have estimates (7.45), (7.46). As above, the first difference equals to
[TABLE]
and has the estimate . In the second integral the expression before the brackets has the estimate and its -derivatives have the estimate . Following essentially the same considerations as for integral (7.66) we obtain the estimate The estimate for the last integral in (7.76) follows from the estimate for .
Case a). The difference of the integrals over .
Analogously to case 1) (integral (7.51)) we must estimate the expression
[TABLE]
[TABLE]
where the integrals are over . The difference with integral (7.51) is that in the two first integrals we replace one multiple in the denominator by the multiple and in the third integral the denominator is instead of . Such replacing doesn’t change the order in and in and we have the same estimate as in case at as in case 1.
Case b).
We consider the difference of the integrals over and analogously to cases 1) and 2). We must estimate the integral
[TABLE]
Applying estimates (7.71), (7.72) and the estimate
[TABLE]
we obtain for integral (7.77) the estimate .
We consider, as in case 1), the difference of the integrals over and . We apply Proposition 39 and again see that the difference with case 1) is that we replace the multiples or by the multiple or in the denominators of the expressions under the integrals. As a result, we obtain the same estimate as in case 1): at . .
[TABLE]
This case is most simple. We write the integral in the chart , Applying (7.39), (7.42), and (7.63), we obtain the estimate
[TABLE]
at .
Now in the our case the differentiation with respect to doesn’t lead to new singularities and for estimation of the difference it is enough to estimate the integral from the derivative of the expression under the integral. It follows that we must estimate the integral
[TABLE]
Again introducing the chart and applying (7.39), (7.42), (7.63), and (7.75), we get the estimate
[TABLE]
We obtain the estimate at .
Proposition 40
Let be a function defined on and satisfying the estimates
[TABLE]
Then for every satisfies the Holder estimate
[TABLE]
Proof. Define . From the identity it follows that
[TABLE]
if . From the other hand, if , then .
Proposition 41
Let be a function defined on equal to zero in and satisfying the estimates
[TABLE]
[TABLE]
for some . Then
[TABLE]
[TABLE]
for some uniform .
Proof. We apply notations of Proposition 37, in particular we use the notations , , , . Again we consider four cases.
[TABLE]
Proof of uniform boundedness. Consider at first the integral over . satisfies estimates of Proposition 40 with some uniform constants. We have
[TABLE]
[TABLE]
with some uniform since for some uniform .
For the integral over we can apply the estimate of Proposition 37, case 1) since is uniformly bounded. Thus we obtain .
Proof of estimate (7.79). It is enough to check inequality (7.79) if . Indeed, in the opposite case for some uniform .
Let be the disk of radius centered at . Applying breaking of the identity we reduce the problem to estimations of integrals of the functions and with the supports in and and satisfying Holder estimates of type (7.79) with constants .
We have the representation
[TABLE]
where satisfies estimates (7.19), (7.20),
[TABLE]
The first integral in right side of (7.80) is the Beurling transform of the function , which is bounded with the norm in the Holder space [As]. Consider the difference
[TABLE]
Following the same lines as in the proof of Proposition 38 we change the variable in the first integral . The disk transforms into the disk and we get the sum of the integrals
[TABLE]
[TABLE]
The first integral is no greater by modulus than
[TABLE]
[TABLE]
[TABLE]
[TABLE]
But
[TABLE]
at and we obtain the estimate for the first integral in (7.81) .
We estimate the second and third integrals in (7.81) as in the proof of Proposition 37 taking into consideration that the ”width” of the lunules and is of order and for we have estimate (7.19). We obtain the estimate and, hence, as above, .
Now consider the integral
[TABLE]
Applying Proposition 39 we see that we must estimate the difference
[TABLE]
,
[TABLE]
[TABLE]
, The first integral in the right side up to the bounded multiples is the integral considered in case 1) of Proposition 37. We have for this term the estimate . For the second integral we have the estimate
[TABLE]
[TABLE]
[TABLE]
at . Here we applied estimates (7.54) and (7.39), (7.42) with .
[TABLE]
Proof of uniform boundedness. As in the proof of Proposition 37 we can consider two cases:
a) , ,
b) .
Consider case a). We use the estimate
[TABLE]
for some . Here is a disk of radius centered at zero, . Indeed, if lies outside of the union of the disks and , then and we see that integral (7.82) is no greater than
[TABLE]
[TABLE]
Now we consider integral over . Since , we get applying (7.82)
[TABLE]
[TABLE]
Analogously, in case b)
[TABLE]
From the other hand, the integral over has the same estimate as the integral over in case 2 of Proposition 37, t.e., it is uniformly bounded.
Proof of estimate (7.79). As in the proof of Proposition 37 we consider two cases:
a) contains and ,
b) and .
In case a) we must consider the difference of the integrals over . Remind the representation
[TABLE]
where . We represent our difference as
[TABLE]
[TABLE]
Applying (7.82) we estimate the first integral as
[TABLE]
Passing to the second integral in (7.83) we suppose at first that . Suppose, for certainty, that this maximum equals to . Applying (7.82) and taking into consideration that and are no less than at , we get
[TABLE]
[TABLE]
[TABLE]
[TABLE]
Suppose now that . Suppose again that this maximum equals to . It also means that . Denote by the disk , by , and by the disks and correspondingly, We estimate separately the integrals over , and . We have
[TABLE]
[TABLE]
[TABLE]
Now consider the difference
[TABLE]
We change the variable in the second integral and represent this difference as the sum of the integrals
[TABLE]
[TABLE]
The first integral we estimate as
[TABLE]
[TABLE]
[TABLE]
[TABLE]
[TABLE]
(since if )
[TABLE]
The second and third items in (7.84) are integrals over the lunules and of width . They have the estimates
[TABLE]
Now let estimate the integral over . Note that if belongs to this domain, then and . We have
[TABLE]
[TABLE]
[TABLE]
Consider now the third integral in (7.83). We represent it as the sum
[TABLE]
The first integral has the estimate
[TABLE]
The second integral in (7.85) we estimate by our usual method. After the change of the variable the domain transforms into the domain . We must estimate the sum
[TABLE]
[TABLE]
The first integral has the estimate
[TABLE]
[TABLE]
The second and third integrals are over the lunules of width of order and have the estimates
[TABLE]
Consider now case b) and estimate the difference of the integrals
[TABLE]
We again apply the change of the variable in the second integral. Denote . Applying the estimates for derivatives of and recalling that now for some uniform , we obtain
[TABLE]
[TABLE]
[TABLE]
[TABLE]
We have an analogous estimate for the integral over .
At last consider the integrals
[TABLE]
in case a) and
[TABLE]
in case b). As in case 1) we can write these integral as sums of the terms that up to the bounded multiples are the integrals considered in case 2) of Proposition 37 and the terms containing differences of values of the function . We estimate these terms as in case 1) and obtain the required estimate.
[TABLE]
Let prove the uniform boundedness. The integral over has the estimate
[TABLE]
[TABLE]
since for some uniform . Hence, the integral is bounded. The integral over reduces to the integral of case 3) of Proposition 37.
Let prove estimate (7.79) in our case. The difference
[TABLE]
we estimate by the usual method, applying the change of the variable in the second integral. Denote by the disk . In the usual way, applying estimates for , and we obtain
[TABLE]
[TABLE]
[TABLE]
[TABLE]
and for the integral over we obtain an analogous estimate.
We obtain an estimate for the difference of the integrals over and analogously to the previous cases.
[TABLE]
Again applying the inequality with some uniform , we can see that this integral is no greater by modulus than
[TABLE]
Estimation of the difference again presents no difficulties since we can differentiate under the integral and we obtain the estimate analogously to case 4) of Proposition 37..
8 Solutions to the Beltrami equation with estimates of derivatives
Proof of Lemma 5. Remind that to prove Lemma 5 means to show that equation (7.13) has an unique bounded solution. We represent the right side of this equation as
[TABLE]
where
Remind the notation , and put identically. Introduce a linear space such that elements of are functions on of the type
[TABLE]
where the sum converges uniformly and the function equals to zero at , has a finite -norm, and satisfies the Holder condition with some . The norm on this space is defined as
[TABLE]
where is defined as
[TABLE]
By Proposition 40 the function belongs to .
The operator isn’t, in general, contracting on but, however, we can obtain the solution to equation (7.13) by an iterations process if we put
[TABLE]
[TABLE]
at and prove that for some .
We shall prove by induction
[TABLE]
where and
[TABLE]
for some uniform .
Note at first that, by Proposition 37 at ,
[TABLE]
and
[TABLE]
where, by Propositions 37 and 40,
[TABLE]
for some uniform . Also, by Proposition 37,
[TABLE]
Applying Propositions 37, 40, and 41, we get
[TABLE]
[TABLE]
[TABLE]
with some uniform . In what follows we denote by the value .
From inductive relations (8.2) and (8.4) - (8.7) follows that the tuple is majorated by the tuple , for which we have the inductive relations
[TABLE]
[TABLE]
[TABLE]
[TABLE]
and we can put, replacing, if it is necessary, the constant : . By induction we easy get
[TABLE]
and, hence, we can rewrite our inductive relations as
[TABLE]
[TABLE]
[TABLE]
Now, at small enough, and . We shall prove by induction that , , . Indeed, we have
[TABLE]
We obtain the estimates for and analogously.
We get from (8.8) and, hence,
[TABLE]
We obtain estimates (8.1) with , where is the constant from (8.4) - (8.6).
We obtained the bounded solution to equation (7.13) and, hence, a solution to equation (7.11) of type (7.12).
A corollary of Lemma 5 is
Proposition 42
Suppose a function defined on satisfies the estimate
[TABLE]
Then
[TABLE]
at , the constant depends on .
Proof. We follow the method explained before formulation of Lemma 5. We can write as the sum
[TABLE]
Recall that is the kernel of
[TABLE]
and denote by the kernel of
[TABLE]
In each term of sum (8.10) we can change the order of integration, for example,
[TABLE]
[TABLE]
[TABLE]
We see that sum (8.10) equals to
[TABLE]
By Lemma 5 at , we can represent the expression as a function of type (7.12) for , . Therefore,
[TABLE]
is another form of sum (8.10) and, by Proposition 30, this integral satisfies estimate (8.9).
Now we have all instruments to prove Theorem 2’.
Let be a quasiconformal local homeomorphism with the complex dilatation defined on . Then satisfies the equation
[TABLE]
From the other hand, if we have a solution to this equation we can find a -quasiholomorphic function such that . Indeed, if we define , then equation (8.11) implies and we can define the function
[TABLE]
Here the integral doesn’t depend on a way. Now we have
[TABLE]
Hence, we can define
[TABLE]
This map is -quasiholomorphic and .
A generalization of equation (8.11) is the equation for :
[TABLE]
Here , are defined by induction functions from , where
[TABLE]
Suppose now that we have a solution to equation (8.13) with some functions not necessary satisfying relations (8.14). We define
[TABLE]
From (8.13) follows and the function
[TABLE]
is well-defined (i.e., it doesn’t depend on a way of integration). Suppose now that we have the relations
[TABLE]
Than, by induction, these functions are well-defined and relations (8.14) are satisfied. Also, by induction, we obtain the relations
[TABLE]
Thus to obtain a solution to equation (8.13) with functions satisfying relations (8.14), (8.17) it is enough to satisfy equations (8.13), (8.15), and (8.16). We shall consider these equations as a system and we shall find a solution to this system satisfying estimates of Theorem 2’.
Remark. It seems, the important case is . The equations for higher derivatives we consider mainly for completeness.
Proposition 43
. In conditions of Theorem 2’ there exists a solution to system(8.13), (8.15), (8.16) satisfying estimates
[TABLE]
Proof. We can write as
[TABLE]
where are integer.
We solve system (8.13), (8.15), (8.16) by an iteration method. On the first step we solve the equation
[TABLE]
We have the solution to this equation
[TABLE]
Since we have the estimate , we obtain by Proposition 42
[TABLE]
with some uniform .
Now we define the iterations
[TABLE]
[TABLE]
By induction, applying representation (8.19), we can see that
[TABLE]
Here , seems, can depend on but, in fact, iteration process (8.23), (8.24) converges in (see Definition 2). Indeed,
[TABLE]
By (8.19),
[TABLE]
and, hence, analogously to (8.22),
[TABLE]
From (8.24) follows
[TABLE]
The constant in these inequalities doesn’t depend on . Thus at small enough the iterations converge.
In particular, is a solution to equation (8.11) satisfying the estimate . Formula (8.12) defines then a -quasiholomorphic function such that with some uniform . It is easy to obtain estimates for other derivatives of . We have
[TABLE]
and we get the estimate . Also,
[TABLE]
and we again obtain the estimate . Also, applying estimates (8.18) we get
[TABLE]
By integration we obtain the estimate
[TABLE]
with some uniform . I.e.,
[TABLE]
It is estimate (4.42).
Proposition 44
* is a homeomorphism.*
Proof. In conditions of Theorem 2’ , where is holomorphic and satisfies estimates (4.38) (we omit here the index ). The map is quasiholomorphc on with the Beltramy coefficient . We have at
[TABLE]
[TABLE]
Analogously, at
[TABLE]
with some uniform . We get for the normal map the estimates of Lemma 1 with small coefficients. From the other hand,
[TABLE]
with some holomorphic . Denote . From Lemma 1 follows
[TABLE]
for some uniform , . We see that satisfies the estimate
[TABLE]
By the criterium of univalence (for example [Pom]) is an univalent function if . This condition is satisfied and, hence, is a homeomorphism.
Proof of estimates for derivatives with respect to parameters. In what follows some constants can depend on and we shall supply these constants by the subscript .
We at first consider equation (8.20). We can write solution (8.21) as , where satisfies the equation
[TABLE]
For a derivative with respect to a parameter we get the equation
[TABLE]
where is the function and is the operator with the kernel and is the kernel of . is a sum of items of the types
[TABLE]
where or . According to (6.1) and (5.15), we have estimate for some and . From the other hand, from the equation follows for some uniform .
The operators with kernels (8.27) are of the types considered in Proposition 34. We obtain
[TABLE]
for great enough, and close enough to 2. From the other hand, and also belong to with some, maybe new, . We get for the equation
[TABLE]
where belongs to for some and has an uniform norm. Applying Proposition 35, we see that the operator is invertible in for great enough and small enough. Thus belongs to . From the other hand,
[TABLE]
where is the operator with the kernel
[TABLE]
Since and belong to , we obtain
[TABLE]
where and is the function
[TABLE]
But
[TABLE]
and we obtain
[TABLE]
with some uniform .
We obtain estimates for higher derivatives of and by induction. At differentiation there appears derivatives of the function and operators with kernels of the types considered in Proposition 34.
Analogously to (8.28) we obtain the estimate
[TABLE]
with some new and if is great enough.
Consider now iterations (8.23), (8.24).
We see that , where satisfies the equation
[TABLE]
Also,
[TABLE]
[TABLE]
For the derivative we get the equation
[TABLE]
[TABLE]
From (8.19) follows that we can write the difference as a sum of terms of the types
[TABLE]
where and
We have the estimates
[TABLE]
for some and and
[TABLE]
for some uniform .
By (8.30, (8.31), applying (8.25), (8.26), we get inductively
[TABLE]
We also have from (8.25), (8.26)
[TABLE]
for some uniform and .
Denote by the sum . Then
[TABLE]
for some uniform , and . We get from (8.29)
[TABLE]
[TABLE]
Analogously to (8.28) we obtain
[TABLE]
for some uniform , and . Estimate now the term
[TABLE]
in (8.34). Suppose that
[TABLE]
with the same as in (8.35). Then, applying (8.33), we get
[TABLE]
with the same and and some independent of . Applying Proposition 42. we obtain that term (8.36) has the estimate by modulus
[TABLE]
with some uniform independent of and .
By (8.34), (8.35), and (8.38), we get
[TABLE]
Now, by (8.24), applying estimates (8.32) and (8.33), it isn’t difficult to obtain
[TABLE]
with some and independent of . It is an estimate of type (8.37). Modifying, if necessary, and in (8.39) we can suppose that these constants are the same as in (8.40). We get the estimate
[TABLE]
where .
Modifying , if necessary, we can suppose that with the same as in (8.35). Then . We put , and , . Using (8.41), we obtain inductively
[TABLE]
At small enough the iterations converge in .
We can obtain estimates for higher derivatives with respect to the parameters by the same method. Instead of (8.34) we obtain the equation for differences with multi-index
[TABLE]
where for we have the estimate with some and . Other modifications are obvious. .
Thus we finished the proof of Theorem 2’ and, hence, Theorem 2.
Remark. It seems, we can prove the estimates for derivatives with respect to parameters not applying the -estimates of Section 6. For it we need in generalization of the estimates of Section 7 on operators of the types and and similar ones, containing -derivatives. However the -estimates can be useful, and it is of some interest that we have estimates for the growth in also.
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