Maximal $\tau_d$-rigid pairs
Karin M. Jacobsen, Peter Jorgensen

TL;DR
This paper extends the bijection between cluster tilting objects and support $ au$-tilting pairs to higher $(d+2)$-angulated categories, introducing maximal $ au_d$-rigid pairs as a higher analogue.
Contribution
It establishes a higher analogue of the known bijection in 2-Calabi--Yau categories, using maximal $ au_d$-rigid pairs in $(d+2)$-angulated categories.
Findings
Established a bijection between maximal $ au_d$-rigid pairs and support $ au_d$-tilting pairs.
Extended known results from 2-Calabi--Yau categories to higher $(d+2)$-angulated categories.
Introduced the concept of maximal $ au_d$-rigid pairs as a higher analogue.
Abstract
Let be a -Calabi--Yau triangulated category, a cluster tilting object with endomorphism algebra . Consider the functor . It induces a bijection from the isomorphism classes of cluster tilting objects to the isomorphism classes of support -tilting pairs. This is due to Adachi, Iyama, and Reiten. The notion of -angulated categories is a higher analogue of triangulated categories. We show a higher analogue of the above result, based on the notion of maximal -rigid pairs.
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Maximal -rigid pairs
Karin M. Jacobsen
Jacobsen: Norwegian University of Science and Technology, Department of Mathematical Sciences, Sentralbygg 2, Gløshaugen, 7491 Trondheim, Norway
[email protected] Fakultät für Mathematik, Universität Bielefeld, 33501 Bielefeld, Germany and
Peter Jørgensen
Jørgensen: School of Mathematics and Statistics, Newcastle University, Newcastle upon Tyne NE1 7RU, United Kingdom
[email protected] http://www.staff.ncl.ac.uk/peter.jorgensen
Abstract.
Let be a -Calabi–Yau triangulated category, a cluster tilting object with endomorphism algebra . Consider the functor . It induces a bijection from the isomorphism classes of cluster tilting objects to the isomorphism classes of support -tilting pairs. This is due to Adachi, Iyama, and Reiten.
The notion of -angulated categories is a higher analogue of triangulated categories. We show a higher analogue of the above result, based on the notion of maximal -rigid pairs.
Key words and phrases:
-abelian category, -angulated category, higher homological algebra, maximal -rigid object, maximal -rigid pair
2010 Mathematics Subject Classification:
16G10, 18E10, 18E30
0. Introduction
In triangulated categories, the notions of cluster tilting objects (introduced in [4, p. 583]) and maximal rigid objects have recently been extensively investigated. They frequently coincide, by [22, thm. 2.6], and they are closely linked to the notion of support -tilting pairs in abelian categories (introduced in [1, def. 0.3]). Indeed, there is often a bijection between the cluster tilting objects in a triangulated category and the support -tilting pairs in a suitable (abelian) module category, see [1, thm. 4.1].
This paper investigates the analogous theory in -angulated and -abelian categories, which are the main objects of higher homological algebra, see [8, def. 2.1] and [15, def. 3.1]. Several key properties from the classic case do not carry over. For example, cluster tilting objects are maximal -rigid, but the converse is rarely true. Moreover, the higher analogue of support -rigid pairs permit a bijection to the maximal -rigid objects, but not to the cluster tilting objects.
For further reading in higher homological algebra a number of references have been included in the bibliography, see [3], [6], [7], [8], [9], [10], [11], [12], [13], [14], [15], [16], [17], [18], [19], [20], [21].
Let be an algebraically closed field, an integer, a -linear -finite -angulated category with split idempotents, see [8, def. 2.1]. Assume that is -Calabi–Yau, see [21, def. 5.2], and let denote the -suspension functor of .
**Cluster tilting and maximal -rigid objects. ** An object is -rigid if . We recall three important definitions.
Definition 0.1** ([21, def. 5.3]).**
An object is Oppermann–Thomas cluster tilting in if:
- (i)
is -rigid. 2. (ii)
For any there exists a -angle
[TABLE]
with for all .
Definition 0.2**.**
An object is -self-perpendicular in if
[TABLE]
Definition 0.3**.**
An object is maximal -rigid in if
[TABLE]
Our first main result is:
*Theorem A. ** is Oppermann–Thomas cluster tilting is -self-perpendicular is maximal -rigid. *
We prove this in Theorem 1.1. Of equal importance is that the implications cannot be reversed in general, see Remark 1.2. In particular, when , the class of maximal -rigid objects is typically strictly larger than the class of Oppermann–Thomas cluster tilting objects, in contrast to the classic case where the two classes usually coincide, see [22, thm. 2.6].
Maximal -rigid pairs. Let be an Oppermann–Thomas cluster tilting object and let . Recall the following result.
Theorem 0.4** ([14, thm. 0.6]).**
Consider the essential image of the functor . Then is a -cluster tilting subcategory of . There is a commutative diagram, as shown below, where the vertical arrow is the quotient functor and the diagonal arrow is an equivalence of categories:
\mathscr{T}$$\mathscr{T}/\operatorname{add}\Sigma^{d}T.\mathscr{D}$$\scriptstyle\overline{(-)}$$\scriptstyle{\mathscr{T}(T,-)}$$\sim
The category is a -abelian category by [15, thm. 3.16]. It has a -Auslander–Reiten translation , which is a higher analogue of the classic Auslander–Reiten translation , see [12, sec. 1.4.1]. A module is called -rigid if .
Remark 0.5**.**
The classic --correspondence holds, as restricts to an equivalence . The functor also restricts to an equivalence . [14, lem. 2.1]
It is natural to ask if permits a higher analogue of the -tilting theory of [1]. We will not answer this question, but will instead introduce the following definitions inspired by it.
Definition 0.6**.**
A pair with and is called a -rigid pair in if is -rigid and .
Definition 0.7**.**
A pair with and is called a maximal -rigid pair in if it satisfies:
- (i)
If then
[TABLE] 2. (ii)
If , then
[TABLE]
A maximal -rigid pair is a -rigid pair.
Our second main result is:
**Theorem B. ** If each indecomposable object of is -rigid, then there is a bijection
[TABLE]
We prove this in Section 3. If , then is a maximal -rigid pair if and only if it is a support -tilting pair in the sense of [1, def. 0.3(b)], see [1, def. 0.3, prop. 2.3, and cor. 2.13]. Hence Theorem B is a higher analogue of the bijection
[TABLE]
which exists by [1, thm. 4.1] when is triangulated, i.e. in the case . However, when , we do not think of maximal -rigid pairs as support -tilting pairs. The reason is that by Theorem B, maximal -rigid pairs are linked to maximal -rigid objects in higher angulated categories. As remarked above, this class is typically strictly larger than the class of Oppermann–Thomas cluster tilting objects when .
Note that [19] makes an approach to higher support tilting theory.
This paper is organised as follows: Section 1 proves Theorem A, Section 2 investigates the precise relation between spaces in and , Section 3 proves Theorem B, and Section 4 gives an example.
Setup 0.8**.**
Throughout the paper we use the following notation:
**: **
An algebraically closed field.
**: **
The duality functor .
**: **
A -linear, -finite, -angulated category with split idempotents. We assume that is -Calabi–Yau, that is naturally in .
**: **
The -suspension functor on .
**: **
An Oppermann–Thomas cluster tilting object in .
**: **
The canonical functor , whose target is the naive quotient category of modulo the morphisms which factor through an object in .
**: **
The endomorphism ring .
**: **
The Nakayama functor on .
**: **
The -Auslander–Reiten translation on .
**: **
The essential image of the functor .
1. Proof of Theorem A
Theorem 1.1**.**
Let be given.
- (i)
There are implications
[TABLE] 2. (ii)
If each indecomposable object in is -rigid, then
[TABLE]
Proof.
(i), the first implication: Suppose is Oppermann–Thomas cluster tilting. We must prove the equality in Definition 0.2, and the inclusion is clear. For the inclusion , suppose . Then each morphism with is zero. This applies in particular to the -angle with , which exists since is Oppermann–Thomas cluster tilting. But then the morphism is a split monomorphism, and applying gives a split monomorphism proving .
(i), the second implication: Suppose that is -self-perpendicular. We must prove the equality in Definition 0.3, and the inclusion is clear. For the inclusion , suppose . Then in particular, , whence .
(i), the third implication: This is clear.
(ii): Suppose that each indecomposable object in is -rigid. Because of part (i), it is enough to prove the implication in (ii), so suppose that is maximal -rigid. We must prove the equality in Definition 0.2, and is clear.
For the inclusion , observe that is closed under direct sums and summands by additivity of . Hence it is enough to suppose that is an indecomposable object in this set and prove . However, implies because is -Calabi–Yau, and by assumption. Finally, is -rigid by part (i), so . Combining these equalities shows , and follows. ∎
Remark 1.2**.**
The implications in Theorem 1.1(i) cannot be reversed in general:
- –
An example of a -self-perpendicular object which is not Oppermann–Thomas cluster tilting is given in Section 4. In fact, the objects in the last three rows of Figure 4 are such examples. The example was originally given in [21, p. 1735].
- –
An example of a maximal -rigid object which is not -self-perpendicular can be obtained by combining proposition 2.6 and corollary 2.7 in [5]. These results give a maximal -rigid object which is not cluster tilting, but in the triangulated setting of [5], cluster tilting is equivalent to -self-perpendicular, see [5, bottom of p. 963].
- –
Finally, an example of a -rigid object which is not maximal -rigid is the zero object, as soon as has a non-zero -rigid object.
We end the section by observing that Theorem 1.1(ii) can be applied to an important class of categories.
Proposition 1.3**.**
Let be a -representation finite algebra, the -angulated cluster category associated to in [21, thm. 5.2]. Then each satisfies
[TABLE]
Proof.
Each indecomposable in is -rigid by [21, Lemma 5.41], so the equivalence follows from Theorem 1.1(ii). ∎
2. A dimension formula for
Recall from Setup 0.8 that is a fixed Oppermann–Thomas cluster tilting object in , and that is -Calabi–Yau, that is, naturally in .
Lemma 2.1**.**
There is a natural isomorphism
[TABLE]
for .
Proof.
By the 2-Calabi-Yau property we have
[TABLE]
By [14, Lemma 2.2(i)],
[TABLE]
Finally, by definition we have
[TABLE]
see [2, def. III.2.8]. ∎
Lemma 2.2**.**
If has no non-zero direct summands in , then there exists a -angle
[TABLE]
in with the following properties: Each is in , and applying the functor gives a complex
[TABLE]
which is the start of the augmented minimal projective resolution of .
Proof.
Given , there exists a -angle
[TABLE]
with each in by Definition 0.1. Since has no non-zero direct summands in , the first morphism in the -angle is in the radical of . By dropping trivial summands of the form , we can assume that so are the other morphisms except the last morphism.
By [8, prop. 2.5(a)], applying the functor gives an exact sequence
[TABLE]
By Theorem 0.4, applying the functor is, up to isomorphism, just to apply a quotient functor, and this preserves radical morphisms. So in the exact sequence each morphism, except possibly , is in the radical of . This proves the claim of the lemma. ∎
Lemma 2.3**.**
If has no non-zero direct summands in , then there is a natural isomorphism
[TABLE]
Proof.
As has no non-zero direct summands in , we can consider the -angle from Lemma 2.2. Apply to get the following part of an augmented minimal projective resolution in :
[TABLE]
Using the Nakayama functor and Lemma 2.1 we get the following commutative diagram.
0\tau_{d}\mathscr{T}(T,X)$$\nu_{\Gamma}\mathscr{T}(T,T_{d})$$\cdots$$\nu_{\Gamma}\mathscr{T}(T,T_{0})[math]\mathscr{T}(T,\Sigma^{d}X)$$\mathscr{T}(T,\Sigma^{2d}T_{d})$$\cdots$$\mathscr{T}(T,\Sigma^{2d}T_{0})$$\sim$$\sim
The top sequence is exact by the definition of , see [12, sec. 1.4.1]. The bottom sequence is exact because it is obtained by applying to a -angle in , see [8, prop. 2.5(a)]. The first term of the bottom sequence is actually , but this is zero. Since we have , the diagram implies
[TABLE]
∎
We write
Lemma 2.4**.**
There is a natural isomorphism
[TABLE]
for .
Proof.
Pick a -angle in :
[TABLE]
with . Use to obtain the morphism . This is a homomorphism of -vector spaces, hence we can talk about the image of . We first note that any morphism in the image of must factor through . Now suppose factors through . We have the following commutative diagram, where the lower row is a part of the -angle above:
\cdots$$T_{0}$$Y$$\Sigma^{d}T_{d}.\cdots$$T^{\prime}$$T^{\prime}[math]X$$1_{T^{\prime}}$$f
The dashed arrow exists by completing the commutative square to a morphism of -angles. We conclude that . Hence
[TABLE]
We now return to the long exact sequence
[TABLE]
Using the duality functor and Serre duality we get the following diagram with exact rows:
\operatorname{D}\!\mathscr{T}(X,\Sigma^{d}T_{d})$$\operatorname{D}\!\mathscr{T}(X,Y)$$\operatorname{D}\!\mathscr{T}(X,T_{0})$$\mathscr{T}(\Sigma^{d}T_{d},\Sigma^{2d}X)$$\mathscr{T}(Y,\Sigma^{2d}X)$$\mathscr{T}(T_{0},\Sigma^{2d}X)$$\scriptstyle{\operatorname{D}\!\Psi}$$\scriptstyle{\alpha^{\prime}}$$\scriptstyle{\beta^{\prime}}$$\sim$$\sim$$\sim$$[\operatorname{add}\Sigma^{d}T](Y,\Sigma^{2d}X)$$\mathscr{T}(Y,\Sigma^{2d}X)/[\operatorname{add}\Sigma^{d}T](Y,\Sigma^{2d}X)$$\scriptstyle{\alpha}$$\scriptstyle{\beta}
Analogous to the above discussion, the space is the image of the map . Hence is the kernel of and (by isomorphism). The morphism is by definition the cokernel of , and is thus the image of . Thus we have
[TABLE]
∎
Lemma 2.5**.**
Suppose .Then we have a short exact sequence
[TABLE]
Proof.
By the definition of the quotient functor we have a short exact sequence
[TABLE]
We have . By Lemma 2.4 we have
[TABLE]
We also know that , so the conclusion follows. ∎
Lemma 2.6**.**
Suppose have no non-zero direct summands in . Then we have a short exact sequence
[TABLE]
Proof.
Consider the short exact sequence from Lemma 2.5. By Theorem 0.4 we know that
[TABLE]
Applying Lemma 2.3 we have
[TABLE]
Similarly we can show \operatorname{Hom}_{\mathscr{T}/\operatorname{add}\Sigma^{d}T}(\overline{X},\overline{\Sigma^{d}Y})\cong\operatorname{Hom}_{\Gamma}\big{(}\mathscr{T}(T,X),\tau_{d}\mathscr{T}(T,Y)\big{)}. ∎
The map defined next will eventually induce the equivalence of Theorem B.
Definition 2.7**.**
For each , pick an isomorphism such that has no non-zero direct summands in and . Let
[TABLE]
This is a pair of -modules where is in and is in .
Proposition 2.8**.**
Given , set and , where is the map in Definition 2.7. Then
[TABLE]
Proof.
By additivity of we have
[TABLE]
As is -rigid, we see that , and hence we have
[TABLE]
From Lemma 2.6 we have the short exact sequence:
[TABLE]
which means that
[TABLE]
We see that
[TABLE]
The third isomorphism follows from [14, Lemma 2.2(i)] and the fact that . Similarly,
[TABLE]
Thus we have
[TABLE]
Substituting (2.2), (2.3), and (2.4) into (2.1) gives the result. ∎
As a consequence we have:
Corollary 2.9**.**
Given , set and . Then
[TABLE]
3. Proof of Theorem B
The following results use the map from Definition 2.7.
Lemma 3.1**.**
Given , set and . Then if and only if .
Proof.
Let be the decomposition from Definition 2.7, where has no non-zero direct summands from while is in . We have (M,P)=\big{(}\mathscr{T}(T,X^{\prime}),\mathscr{T}(T,\Sigma^{-d}X^{\prime\prime})\big{)}. Similarly, (N,Q)=\big{(}\mathscr{T}(T,Y^{\prime}),\mathscr{T}(T,\Sigma^{-d}Y^{\prime\prime})\big{)}.
The condition is equivalent to by the --correspondence, (see Remark 0.5). The condition is equivalent to by Theorem 0.4 because have no non-zero direct summands in . The result follows. ∎
Lemma 3.2**.**
The category is skeletally small. The map induces a bijection
[TABLE]
where denotes the set of isomorphism classes of a skeletally small category.
Proof.
Let denote the class of isomorphisms of a category. For a skeletally small category we have that . Note that since a module category over a ring is skeletally small, we have that are skeletally small.
It is clear that induces a well-defined map of the form
[TABLE]
To see that is injective, argue like the proof of Lemma 3.1, replacing membership of with isomorphism.
It follows that is skeletally small. We can thus replace with the map from (3.1).
To see that is surjective, let be a pair with and . By Theorem 0.4 there is an object with no non-zero direct summands in such that . By the add-proj correspondence, see Remark 0.5, there is an object such that . Setting gives . ∎
Lemma 3.3**.**
If is -self-perpendicular, then is a maximal -rigid pair.
Proof.
Let and be given. By Lemma 3.2, there is an object such that . Then
[TABLE]
where the equivalences, respectively, are by Lemma 3.1, Definition 0.2, and Corollary 2.9.
The conditions of Definition 0.7 are recovered by setting respectively ∎
Lemma 3.4**.**
Let be given. If is a maximal -rigid pair, then is -self-perpendicular.
Proof.
Let be given and set . Then
[TABLE]
where the equivalences, respectively, are by Corollary 2.9, Definition 0.7, and Lemma 3.1. ∎
Theorem 3.5**.**
Recall that the map from Definition 2.7 induces the bijection from Lemma 3.2.
- (i)
* restricts to a bijection*
[TABLE] 2. (ii)
* restricts further to a bijection*
[TABLE]
Proof.
(i): Consider and set . Then
[TABLE]
by Corollary 2.9, so the result follows.
(ii): See Lemmas 3.3 and 3.4. ∎
*Proof *(of Theorem B from the introduction). Combine Theorems 3.5(ii) and 1.1(ii).
4. An example
In this section we let and . This is the -angulated (higher) cluster category of type , see [21, def. 5.2, sec. 6, and sec. 8]. The indecomposable objects can be identified with the elements of the set
[TABLE]
see [21, sec. 8]. The AR quiver of is shown in Figure 1.
By [21, thm. 5.5 and sec. 8], the object
[TABLE]
is Oppermann–Thomas cluster tilting.
If are indecomposable objects, then
[TABLE]
see [21, prop. 6.1 and def. 6.9]. It follows that , where
[TABLE]
and is the ideal generated by all compositions of two consecutive arrows. The action of the functor on indecomposable objects is shown in Figure 2, where and denote the indecomposable projective and injective modules associated to the vertex .
Note that the essential image of is
[TABLE]
This is a -cluster tilting subcategory of and hence it is -abelian.
The -suspension functor acts on the AR quiver by moving four steps clockwise. Combined with our knowledge of , this shows that if is a fixed indecomposable object in , then the indecomposable objects with are precisely the two objects furthest from in the AR quiver, see Figure 3.
Based on this, we can compute all basic -self-perpendicular objects in , and by Proposition 1.3 they coincide with the basic maximal -rigid objects in . For each such object , there is a maximal -rigid pair \Delta(X)=\big{(}\mathscr{T}(T,X^{\prime}),\mathscr{T}(T,\Sigma^{-3}X^{\prime\prime})\big{)} by Theorem B. See Figure 4.
Note that the first nine objects in Figure 4 are Oppermann–Thomas cluster tilting, but the three last objects are not.
Acknowledgement. This work was supported by EPSRC grant EP/P016014/1 “Higher Dimensional Homological Algebra”. Karin M. Jacobsen is grateful for the hospitality of Newcastle University during her visit in October 2018.
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