A classification of monotone ribbons with full Schur support with application to the classification of full equivalence classes
Olga Azenhas, Ricardo Mamede

TL;DR
This paper classifies monotone ribbons with full Schur support, providing linear inequalities for their structure, and connects this to the classification of full equivalence classes, advancing understanding of ribbon Schur functions.
Contribution
It offers a complete characterization of when ribbon Schur functions attain full support, linking it to the classification of full equivalence classes for monotone ribbons.
Findings
Derived linear inequalities for ribbon shapes with full Schur support
Established the equivalence between full Schur support and full equivalence class for monotone ribbons
Connected the necessary condition for full equivalence class to the support of ribbon Schur functions
Abstract
We consider ribbon shapes, not necessarily connected, whose rows, with at least two boxes in each, are in monotone length order. These ribbons are uniquely defined by a pair of partitions: the row partition consisting of the row lengths in decreasing order, and the overlapping partition whose entries count the total number of columns with two boxes in the successive ribbon shapes obtained by sequentially subtracting the longest row. The support of such ribbon Schur functions, considered as a subposet of the dominance order lattice on partitions, has the row partition as bottom element, and, as top element, the partition whose two parts consist of the total number of columns, and the total number of columns of length two respectively. We give a complete system of linear inequalities in terms of the partition pair defining the aforesaid ribbon shape under which the ribbon Schur function…
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TopicsAdvanced Combinatorial Mathematics · Geometric and Algebraic Topology · Advanced Mathematical Identities
A classification of monotone ribbons with full Schur support
with application to the classification of full equivalence classes
Olga Azenhas
CMUC, Department of Mathematics, University of Coimbra, Apartado 3008, 3001–454 Coimbra, Portugal
and
Ricardo Mamede
CMUC, Department of Mathematics, University of Coimbra, Apartado 3008, 3001–454 Coimbra, Portugal
Abstract.
We consider ribbon shapes, not necessarily connected, whose rows, with at least two boxes in each, are in monotone length order. These ribbons are uniquely defined by a pair of partitions: the row partition consisting of the row lengths in decreasing order, and the overlapping partition whose entries count the total number of columns with two boxes in the successive ribbon shapes obtained by sequentially subtracting the longest row. The support of such ribbon Schur functions, considered as a subposet of the dominance order lattice, has the row partition as bottom element, and, as top element, the partition whose two parts consist of the total number of columns, and the total number of columns of length two respectively. We give a complete system of linear inequalities in terms of the partition pair defining the aforesaid ribbon shape under which the ribbon Schur function attains all the Schur interval when expanded in the basis of Schur functions. We then conclude that the Gaetz-Hardt-Sridhar necessary condition for a connected ribbon to have full equivalence class is equivalent to the condition for a monotone connected ribbon to have full Schur support. That is, the set of partitions with full equivalence class is a subset of those monotone connected ribbons with full Schur support. M. Gaetz, W. Hardt and S. Sridhar conjectured that the necessary condition is also sufficient which translates now to every monotone connected ribbon with full Schur support has full equivalence class. The main tool of our analysis is the structure of the companion tableau of a ribbon Littlewood-Richardson (LR) tableau detected by the descent set defined by the composition whose parts are the ribbon row lengths.
Key words and phrases:
Schur functions, Schur support, ribbons, companion tableau of a ribbon Littlewood-Richardson tableau.
2000 Mathematics Subject Classification:
05A17, 05E05, 05E10, 68Q17
This work was partially supported by the Centre for Mathematics of the University of Coimbra – UID/MAT/00324/2013, funded by the Portuguese Government through FCT/MCTES and co-funded by the European Regional Development Fund through the Partnership Agreement PT2020, and by the FCT sabbatical grant SFRH/BSAB/113584/2015. The first author wishes to acknowledge the hospitality of University of Vienna where her sabbatical leaving in the academic year 2015/2016 took place and this work was partially developed.
1. Introduction and statement of results
Littlewood-Richardson (LR) coefficients, non negative integers, arise in a variety of areas of mathematics [Fu00]. Determining its positivity without evaluating its actual value is of importance. There exists a variety of combinatorial models, collectively called Littlewood-Richardson rules (the original model conjectured in [LiRi34] and proved in [Sch77, Tho78]) to compute LR coefficients, and to show their positivity it is enough to exhibit an object in a chosen combinatorial model. Linear inequalities on triples of partitions guaranteeing their positivity have arisen from studying eigenvalues of a sum of Hermitian matrices [Ho62, Kl98, KnTa99, Fu00]. Given the skew partition , with partitions, it is known that it uniquely defines a subposet in the dominance order lattice of partitions of , the number of boxes of , where the bottom element is the partition formed by the row lengths of , and the top element is the conjugate of the partition formed by the column lengths of . The meaning of this interval is that, given the partition of , the LR coefficient only if and, in particular, (see,for instance, [Az99, Mc08] and references therein). Indeed it is not enough to guarantee that [KnTa99, Fu00].
The LR coefficient is a structure coefficient. It arises, for example, as the multiplicity of the Specht module in the decomposition of the skew Specht module into irreducible representations of the symmetric group ,
[TABLE]
and, in the algebra of symmetric functions, as a coefficient of the Schur function in the expansion of the skew Schur function in the basis of Schur functions ,
[TABLE]
The expansion (1.2) is also the image of the character of under the Frobenius characteristic map. Another way to look either at expansions (1.1) or (1.2) is that given , , they generate all possible positive LR coefficients . In view of these expansions, is then the Schur interval of the skew shape , and the Schur support of the skew shape is the set of partition shapes where either appears with positive multiplicity in (1.1) or appears with nonzero coefficient in (1.2),
[TABLE]
The skew shape is said to have full Schur support when in (1.3) the support coincides with the Schur interval.
A very general problem in the calculus of shapes is the classification of skew shapes whose Schur support consists of the whole interval in the dominance order lattice of partitions. (See also Question 5.1 in [McWi12, Section 5].) In other words, given the partition of , we ask under which conditions one has, if and only if . In the special case of requiring all coefficients , the multiplicity free full interval, a classification was given in [ACM17]. We here give, in Theorem 1.4, a full Schur support classification for monotone ribbon shapes, not necessarily connected, with at least two boxes in each row, in terms of linear inequalities (1.8) satisfied by the partition pair consisting of the row and overlapping partitions defining the monotone ribbon shape (see Proposition 3.2). The significance of this classification also amounts to the classification of connected ribbons with full equivalence class ([GaHaSr17, Definition 7]), that is, connected ribbons whose Schur support is invariant under any order rearrangement of the rows. More precisely, monotone connected ribbons with full equivalence class only exist among those with full Schur support. This is a recent input on our study of monotone ribbons having full Schur support and comes from the work by Gaetz, Hardt, Sridhar and Quoc Tran [GaHaSr17, GaHaSrTr17] where the support equality among connected ribbon Schur functions under any order rearrangement of the rows is addressed. The set of connected ribbons with full equivalence class has partitions as ribbon representatives. Lemma 1.7 shows that the Gaetz-Hardt-Sridhar necessary condition [GaHaSr17, Theorem II.1] for connected ribbons to have full equivalence class is equivalent to our classification, in Theorem 1.4, of monotone connected ribbons with full Schur support. Theorem 1.8 concludes that a monotone connected ribbon with full equivalence class has full Schur support. For monotone connected ribbons with at most four rows, ribbons with full equivalence class coincide with ribbons with full Schur support.
Earlier work on calculus of skew shapes are, for instance, Schur support containments by Pylyavskyy, McNamara and van Willigenburg [DoPy07, McWi12], skew shapes with the same Schur support or skew Schur function equalities by McNamara and van Willigenburg [Mc08, McWi09]. In particular, ribbon Schur functions were already considered by MacMahon [Mac17, 199–202] and Foulkes [Fo76] with representation-theoretic significance by the last. Finally, it is worth noting that Reiner, Shimozono [ReShi98] and R. I. Liu [Liu12] have considered Specht modules and, therefore, Schur functions for more general diagrams than skew shapes. However, apart percentage-avoiding diagrams [ReShi98], the combinatorial description of the coefficients for the Schur expansion is not known in general.
1.1. Overlapping partition of a monotone ribbon and descent set of a SYT
Arbitrary connected ribbons (diagrams corresponding to skew shapes containing no rectangle) are in bijection with compositions assigning to the ribbon the row lengths. Thanks to the -rotation symmetry of LR coefficients [St99, ACM09], the Schur support classification of LR monotone ribbons may be reduced to ribbons with row lengths in monotone decreasing order. Decreasing monotone ribbons with rows in length at least two, have at most columns of length two which occur exactly when two rows overlap: the overlapping partition , read in reverse order, records sequentially, by accumulation, the number of columns of length two from the bottom to the top rows of the ribbon (see Section 3 and Definition 3.1). Proposition 3.2 shows that monotone ribbons, not necessarily connected, with at least two boxes in each row in monotone length order, are in bijection, up to an antipodal rotation, with partition pairs where the parts of the row lengths partition are in length at least two, and the parts of the overlapping partition are assigned by a multiset of of cardinality with . We often denote these ribbons by , or just say the partition with overlapping partition to mean that is the overlapping partition of the ribbon . The Schur interval of our ribbon , with connected components, is
[TABLE]
Example 1.1*.*
The partition pair where and , defines the monotone ribbon , below, with 3 connected components, and Schur interval ,
[TABLE]
Our classification is based on the fact that given a monotone ribbon with row lengths at least two, defined by the partition pair , the existence of a companion tableau [LecLen17, Nak05, Appendix] for an LR filling of with content , is equivalent to show that the triple of partitions , and satisfy a certain system of linear inequalities (1.6) in Theorem 1.2. The companion tableau of a LR connected ribbon is detected by the descent set of its standardization (see sections 2.1 and 2.2). The following alternative description of the LR coefficients in the expansion (1.2) is known [Fo76, Ge84, Ge93], counting exactly standardized companion tableaux of connected LR ribbons.
Theorem 1.1**.**
[Fo76, Ge84, Ge93]**. Let be any composition of and the corresponding connected ribbon shape. Then
[TABLE]
where runs on the set of partitions of , and is the number of standard Young tableaux (SYT) of shape and descent set
This means that given the connected ribbon , the LR ribbon coefficient is positive if and only if there exists a semistandard Young tableau (SSYT) tableau of shape and content whose standardization has descent set . For ordered compositions with parts of length at least two, we show, in Theorem 1.2, that the existence of such standard Young tableau guaranteeing the positivity of is equivalent to require that the triple of partitions , and satisfy a certain system of linear inequalities (1.6). More generally, we prove that the characterization is valid for monotone ribbons with components by replacing the stair partition of with a multiset of of cardinality , where . Our method then consists of explicitly identifying in a SSYT of shape and content the partition , the obstructions for being a companion tableau for a monotone LR ribbon, with the goal to remove them through a rotation procedure (see Subsection 4.2). This removal is possible whenever linear inequalities (1.6) are satisfied by the triple of partitions . More precisely, the effective obstructions, detected by the overlapping partition , correspond to some elements in which are not in the descent set of the standardized tableau. Thus to exhibit the positivity of a such LR ribbon coefficient one just needs to exhibit a companion tableau for the ribbon LR filling. To minimize the number of obstructions that we have to deal with we work out on a SSYT with canonical filling (see Section 2.4).
1.2. Monotone ribbons: witness vectors and their slacks
Put where is a real number. To a monotone ribbon , we associate a sequence of witness vectors, and to each witness we assign the slack , for .
Definition 1.1**.**
Let be a partition with parts at least two and with overlapping partition . For each i\in\{1,$$\dots, , put the rest of order of , that is, the total number of columns in the last rows of . Define the *-witness vector * of to be the nonnegative vector where The slack of the -witness vector is , for . If , has no witness vectors.
The size of the -witness vector is said to fit its slack, if , otherwise is said to be oversized.
Remark 1.1*.*
For i\in\{1,$$\dots, , exceeds the total number of columns in the last rows of . In any LR filling of the ’s are filled in the last rows, and thereby its number is . For i\in\{1,$$\dots, , if and only if .
1.3. Statement of main results
Our key result is Theorem 1.2 which determines without determining its actual value. It gives a set of linear inequalities on the partition triple as necessary and sufficient conditions for the positivity of . The inequalities are explained by the combinatorial interpretation of in the dominance order on partitions (see Remark 2.1), and the obstruction of the overlapping partition to the partitions dominating . When , we have no such obstruction, is a Kostka number, and characterizes completely the aforesaid positivity.
Theorem 1.2**.**
Let be a partition with parts at least two and overlapping partition , and a partition of . Then
[TABLE]
In particular, when , that is, , , there exists a SYT of shape with descent set if and only if the right hand side of (1.6) is satisfied.
The necessary and sufficient condition (1.6) is easily read: is in the support of if and and only if the , with , for . With this on hand we give a criterion to decide when has full Schur support, that is, when one has if and only if The test assigns to each the -witness vector of and compares its size with the slack . The existence of a single witness fitting its slack prevents the full Schur support because it can be used to construct a partition in the Schur interval but not in the support. This is the case of a witness of size zero, that is, when the partition has for some .
Theorem 1.3**.**
Let be a partition with parts , and overlapping partition . Then if and only if and, for some , the size of the -witness vector fits its slack, that is,
[TABLE]
In this case, , , whose decreasing rearrangement is the partition of in the Schur interval of but not in the support of .
The equivalent statement for full Schur support is
Theorem 1.4**.**
Let be a partition with parts , and overlapping partition . Then if and only if either or and, in this case, for every , the -witness vector of is oversized with respect to its slack, that is,
[TABLE]
Remark 1.2*.*
has full support only if
[TABLE]
The following is a generalization of [GaHaSrTr17, Theorem 3.6] to monotone disconnected ribbons with which contain the monotone connected ribbons of length .
Corollary 1.5**.**
In particular,
* when , if and only if*
[TABLE]
* when , if and only if*
[TABLE]
In [GaHaSr17, Theorem II.1], that we reproduce below as Theorem 1.6 for the reader convenience, a necessary condition is given for a connected ribbon with parts at least two, to have full equivalence class [GaHaSr17, Definition 7]. This necessary condition combined with Theorem 1.4 shows that a monotone connected ribbon with parts has full equivalence class only if it has full Schur support. That is, full equivalence classes only exist among monotone connected ribbons with full Schur support.
Theorem 1.6**.**
[GaHaSr17, Theorem II.1]** Let be a partition with parts and a connected ribbon. If has full equivalence class then
[TABLE]
For monotone connected ribbons, inequality (1.11) is equivalent to inequality (1.8) in Theorem 1.4 characterizing full Schur support.
Lemma 1.7**.**
For all ,
[TABLE]
In addition, combining Theorem 1.4 with [GaHaSrTr17, Theorem 3.6], one has
Theorem 1.8**.**
Let be a partition with parts and a connected ribbon. If has full equivalence class then has full support. When , has full equivalence class if and only if has full support.
Proofs of main results will be delayed until sections 4, 5 and 6.
1.4. Organization of the paper
This paper is organized in seven sections with the following contents. The next section, divided in seven subsections, contains the basic terminology, definitions and results that we shall be using throughout the paper. We highlight the concepts of descent set of a semistandard Young tableau versus SYT and Proposition 2.1 in Subsection 2.2, the combinatorial interpretation of dominance order on partitions, in Subsection 2.3, enlightening inequalities (1.6), and companion tableau of an LR tableau, in Subsection 2.6, our key tool in the proof of the existence of a monotone ribbon LR filling with given shape and content or the positivity of a ribbon LR coefficient.
Section 3 is divided in four subsections. Subsection 3.1 defines (Definition 3.1) and discusses overlapping partition of a ribbon, with row lengths at least two, that we shall use in the (connected or not) monotonic case, and, in the last section, in the connected case with row lengths in any order. It is shown that monotone ribbons not necessarily connected are uniquely defined by the row lengths partition and the overlapping partition. It is recalled in Subsection 3.2 that the descent set of a standard Young tableau detects the companion tableau of a LR connected ribbon. The enumerative characterization of LR connected ribbon coefficients in Theorem 1.1 is generalized to disconnected ribbons.
Given a SSYT of shape and weight the descent set of the standardization of is a subset of . As our study reduces to ribbons with a partition, the serious rejection for to be a companion tableau for a LR ribbon of shape occurs when it leads to a filling of with the same letter in a column of length two. In Subsection 3.3, we translate the numbers in and not in the descent set of the standardized , giving rise to the aforesaid violation, to the critical numbers set of , a subset of . In addition, as our monotone ribbons may be disconnected, the overlapping partition is used to detect the effectiveness of the critical numbers of a companion tableau of a LR ribbon of shape , as explained in Subsection 3.4.
Section 4 gives the proof of Theorem 1.2 which determines by means of a set of linear inequalities on the partition triple , the positivity without determining its actual value. Assuming the linear inequalities on the right hand side of (1.6), the goal is to exhibit a companion tableau for a LR filling of the shape . The semistandard tableau of shape and weight with canonical filling (Subsection 2.4) is picked, and then if necessary one modifies its filling according to a certain rotation procedure to avoid -effective critical numbers so that the new tableau is a companion tableau of an LR filling with weight of the shape . The linear inequalities on the right hand side of (1.6) guarantee that our rotation procedure is successful. Section 5 gives the proof of Theorem 1.3 and Theorem 1.4, logically equivalent, which classify the monotone ribbons with full Schur support, and Corollary 1.5 which gives a simple version of those inequalities in the case where the overlapping partition has at most length four. Illustrative examples are also provided.
In section 6, the bridge between the classification of monotone connected ribbons with full Schur support and those with full equivalence class [GaHaSr17] is established. More precisely, Lemma 1.7 shows that for monotone connected ribbons, the inequality (1.11), in Theorem 1.6, [GaHaSr17, Theorem II.1], giving a necessary condition for full equivalence class, is equivalent to the inequality (1.8), in Theorem 1.4, characterizing the full Schur support. The bridge allows to prove Theorem 1.8 which states that every partition with full equivalence class has full Schur support. Instances on the coincidence of these two classifications are provided. More importantly, Corollary 6.2 shows, as observed in Remark 6.1, that a non monotone connected ribbon of length three may have full Schur support while its monotone rearrangement does not have.
Section 7 generalizes, in Theorem 7.1, the necessary condition, in Theorem 1.2, for the LR coefficient positivity, with a partition, to connected ribbons with a composition. Remark 7.1 shows that if these inequalities on the triple with a composition and the overlapping partition of , are also sufficient, then the classification on partitions having full equivalence class and full Schur support is the same, and, henceforth, the Gaez-Hardt-Shridar conjecture [GaHaSr17, Conjecture II.4] claiming that the necessary condition (1.11) for a partition to have full equivalence class is also sufficient, is true.
Acknowledgements. We are thankful to the organizers of workshop Positivity in Algebraic Combinatorics, BIRS, Banff, Alberta, August 14-16, 2015, for the opportunity to present our work on full Schur supports, to João Gouveia for useful discussions and suggesting the phrasing of witness vector with its slack which allowed economy and clarification in our redaction, and to M. Gaez, W. Hardt, S. Sridhar and P. Pylyavskyy for letting us know the paper [GaHaSr17] on full equivalence classes.
2. Preliminaries
2.1. Partitions, compositions and tableaux
A partition is an ordered list of positive integers where are the parts and the length of . We say that is the size of and that is a partition of . It is convenient to set for . The Young diagram of the partition , or Young diagram of shape , is the collection of boxes arranged in left-aligned rows, in the lower right quadrant of the plane, where the th row has boxes, for . We shall identify a partition with its Young diagram. Given the partition , the conjugate or transpose partition is the partition obtained by transposing the Young diagram of . A filling of a Young diagram of shape with positive integers is called semistandard if the integers increase weakly across rows (row semistandard condition) and strictly down columns (column standard condition). Such a filled-in Young diagram of shape is called a semistandard Young tableau (SSYT) of shape . The weight or content of a SSTY is the sequence , where is the number of integers in the filling of the tableau.
A composition with parts is a sequence of positive integers. The partition is the monotone nonincreasing rearranging of . The size of is defined to be , in which case we say is a composition of . The length of is . If is another composition, we define the concatenation of and to be the composition of length .
We denote by the set of all SSYTs of shape and content the composition . For a partition and a composition of , the Kostka number is defined to be .
A skew shape or (skew Young diagram) is obtained by removing the Young diagram from the top-left corner of the Young diagram , when is contained in as Young diagrams, or equivalently, when , for all . In particular, when is the empty partition [math], we have . The size of is . An horizontal strip is a skew diagram which has at most one box in each column. The basic form of a skew shape is the skew diagram obtained by deleting any empty row and any empty column. The skew shape in the basic form defines the composition that we simply write if there is no danger of confusion. A skew shape is said to be connected if there exists a path between any two boxes of the diagram using only north, east, south and west steps such that the path is contained in the diagram. A SSYT of skew shape and weight is a semistandard filling of the the skew-shape of weight .
2.2. Descent set of a standard tableau
If a SSYT of size ( boxes) has entries in , each necessarily appearing exactly once, then is said to be a standard Young tableau (SYT).
A SSYT in may also be regarded as a sequence of partitions such that each skew shape is an horizontal strip of size . Simply insert an in each box of the strip [St99]. The standard order on a semistandard Young tableau is the numerical ordering of the labels with priority, in the case of equality, given by the rule southwest=smaller, northeast=larger. The standardization of a semistandard tableau is the enumeration of the labeled boxes according to the standard order of , that is, the enumeration of the boxes across the sequence where each horizontal strip of size is read SW-NE. For instance, the following are SSYT’s with shape and content , and their standardizations, respectively:
[TABLE]
The descent set of a SYT of shape is defined to be the subset of formed by those entries of for which appears in a strict lower row of than . There is a one-to-one natural correspondence between subsets of and compositions of [St99, Fo76]. The composition gives rise to the subset , with cardinality , of , and vice-versa. Hence a SYT of shape has descent set for some composition of . In (2.1), for example,
[TABLE]
However, is also the standardization of with . In particular, has a sole element whose standardization has descent set the empty set, and has a sole element whose standardization has descent set .
Given , the descent set of the SSYT is the subset of that consists of for which there exists a pair of entries and in such that appears in a strict lower row of than . When is a SYT, that is, , we recover the notion of descent set in a SYT, where is a subset of . We show next that a SYT of shape has descent set if and only if it is the standardization of some SSYT in with descent set . A SYT of shape has descent set if and only if it is the standardization of some SSYT in with descent set and .
Proposition 2.1**.**
Given a partition and a composition of , there exists a bijection between and the set of all SYT’s of shape with descent set a subset of , defined by the map . Moreover, if and then with such that , and .
Proof.
Let be the sequence of partitions defining . The standardization of a SSYT is the enumeration of the boxes across the sequence defining where each horizontal strip of size is read SW-NE. This means that is a SYT of shape and its descent set where consists of for which the most SW box in appears strictly below the most NE box in .
Given a SYT of shape and with descent set for some composition of , the standardization may be reversed to give a SSYT in . A SYT of shape with descent set defines the sequence of partitions where each consists of the boxes of with the entries given by . Therefore filling each horizontal strip with ’s, for all gives a SSYT in . Because , given , for some . Then we may fill the boxes of the horizontal strip , from SW-NE, with ’s, ’s, , ’s to obtain a SSYT in . ∎
2.3. Dominance order on partitions
The dominance order on partitions of the same size , is defined by setting if and
[TABLE]
for . Equivalently, the Young diagram of is obtained by lifting at least one box in the Young diagram of . Observe that if and only if . The pair with the set of all partitions of is a lattice with maximum element and minimum element , and is self dual under the map which sends each partition to its conjugate. The interval in denotes the set of all partitions such that .
Remark 2.1*.*
Note that if , the inequalities , for , are always satisfied. For , either is obtained by lifting boxes from to , in which case, , or is obtained by lifting boxes from to , in which case, .
2.4. The canonical filling in
Let be an arbitrary composition and a partition such that . We exhibit a representative element of , see also [JaVi17]. The proof provides an -weight canonical filling of a Young diagram of shape . The canonical filling enjoys descent properties to be used later, see Section 3.3 and Proposition 3.6.
Lemma 2.2**.**
Let be any composition and a partition such that . Then, and has a canonical filling representative of the shape with weight . It is constructed by filling horizontal strips greedily, from the bottom to the top of , starting with the longest columns, while rows are filled from right to left.
Proof.
Assume that . Then , and the shape has rows and columns. We will show by induction on that we can construct a SSYT of shape and weight by filling horizontal strips greedily, from bottom to the top of , starting with the longest columns, while rows are filled from right to left. The case is trivial. So, assume . If , then fill in, as above, entries of the shape with letters . The remaining shape satisfy and, by the inductive step, there is a filling as above of the shape with content . Therefore, there is also a filling of the shape as above, with content .
Consider now the case , where the entry is in position . Let and be transpositions of the symmetric group . Write . From the previous case, there is a filling of the shape with content . Consider now the two bottom row strips filled with letters , and letters . We refill these strips first with letters , and then with letters , to obtain a filling of the shape with content . Subtracting the strip filled with , we get a shape filled with content . By the inductive hypotheses, it can also be filled in the way described above with content . Rejoining the strip we get the desired filling. ∎
Example 2.1*.*
Below are examples of SSYT’s of partition shape with canonical filling:
[TABLE]
The previous lemma gives a constructive proof of the only if part of in the next proposition.
Proposition 2.3**.**
[Fu97, Sa01, St99]* Let be a composition and a partition of . Then*
* ,*
* ,*
* *
For instance, in (2.1), .
2.5. Skew-Schur functions, LR tableaux and Littlewood-Richardson rule
Let denote the ring of symmetric functions in the variables over , say. The Schur functions form an orthonormal basis for , with respect to the Hall inner product, and may be defined in terms of SSYT by
[TABLE]
where the sum is over all SSYT of shape and is the number of occurrences of in [St99]. The notion of Schur functions can be generalized to apply to skew shapes . Replacing by in (2.3) gives the definition of the skew Schur function as a sum of monomial weights over all SSYTs of skew shape . We identify with the skew Schur function indexed by the skew Young diagram in the basic form.
The reading word of a SSYT is the word obtained by reading the entries of from right to left and top to bottom. If, for all positive integers and , the first letters of includes at least as many s as s, then we say that is a Yamanouchi word. Clearly, the content of a Yamanouchi word is a partition. Yamanouchi words of content are in bijection with standard Young tableaux of shape [Fu97, Section 5.3]. Each SYT of shape specifies a Yamanouch word of content , in the alphabet , where the number is in the th row of the SYT, and this map is one-to-one. Moreover, one has unless in which case . In (2.1), for example,
[TABLE]
are Yamanouchi words of content , where and .
A Littlewood–Richardson (LR) tableau [LiRi34] is a SSYT whose reading word is Yamanouchi. We denote by the set of all LR tableaux of shape and content . When is empty, and the LR tableau of shape and content , denoted , is called the Yamanouchi tableau of shape . In fact, is the unique SSYT of shape and content , precisely, the SSYT that is filled with ’s in row . The structure constants in the expansion (1.2) of the skew Schur function , in the basis of Schur functions, are given by the Littlewood–Richardson rule which states that the Littlewood–Richardson coefficient , the number of LR tableaux with skew shape and content [LiRi34, St99].
2.6. LR tableaux and companion tableaux
LR tableaux in can be replaced by their companion tableaux which are certain SSYTs in whose standardizations encode the Yamanouchi reading words of the LR tableaux in . Given , the containment of the descent set of in guarantees that the filling of with Yamanouchi reading word satisfies the row semistandard condition. Thus any tableau specifies through a filling of the skew shape with the Yamanouchi reading word of content with the row semistandard condition satisfied but not necessarily the standard condition of the column filling. In addition, by Proposition 2.1, we know that, a filling of the skew shape with a Yamanouchi reading word satisfying the row semistandard condition is encoded by a SYT of shape with descent set in . For example, the two Yamanouchi words in (2.4) give fillings for the skew shape where all satisfy the row semistandard condition. The word does not garantee the column standard condition in the filling
[TABLE]
Given the companion tableau of is the SSYT in whose entries of each row of are the numbers of the rows of where the ’s are filled in. This defines a bijection between and a subset , of that sends to . Therefore, the LR coefficient in (1.2) also satisfies
[TABLE]
The set may be characterized in several ways: by linear inequalities as in [GeZe86]; or observing that is a subset of the -crystal consisting of all SSYTs of shape in the alphabet , , [Kwo09, BumSch16]. The highest weight element of is and consists of the vertices in such that is a highest weight element of weight of [Kwo09, Section 4.3].
Given , for each , and , let denote the multiplicity of letter in row of . Note that, for , , whenever . Fix so that . One then has the bijection,
[TABLE]
such that is the -weight semistandard filling of by putting letters , starting from the left, in row of the skew-shape , for , and . The reading word of is precisely the Yamanouchi word of weight , . That is, consists of those tableaux in assigning to the skew shape a semistandard filling of content whose reading word is the Yamanouchi (hence an LR filling). Theorem 1.1 characterises in the case of connected ribbons .
2.7. Schur support and symmetries
The definition (1.3) of Schur support of the skew shape can be rephrased as follows: if and only if , equivalently, .
LR coefficients satisfy a number of symmetries [St99, ACM09, AKT16], including: , where is the -rotation of , and . As a consequence and where
[TABLE]
The full support of one of the shapes , or implies the full support of any of the others. When is not connected, and consists of two connected components and , and may themselves be either Young diagrams or skew Young diagrams, then the combinatorial definition of (skew) Schur function (2.3) gives [St99] This means that a skew Schur function is invariant under permutation and rotation of the connected components.
3. Ribbons
A ribbon is a skew shape which does not contain a block as a subdiagram and it is connected when each pair of consecutive rows intersects in exactly one column. Thus, any composition determines a unique connected ribbon consisting of rows (or parts) of length , for , from top to bottom.
Given the composition , will denote a ribbon (not necessarily connected) where row lengths from top to bottom are given by the parts of and adjacent rows overlap in at most one column. If each row is at least two boxes in length then the column length is at most two otherwise the column length might be bigger than two. If is another composition, the direct sum of the ribbons and , is the ribbon where the ribbons and have no edge in common. In general, is a direct sum of connected ribbons unless otherwise stated.
.
3.1. Overlapping partition of a ribbon with parts at least two
In this subsection, we only consider compositions with parts , and therefore the ribbon has columns of length at most two.
Definition 3.1**.**
Let be an arbitrary composition with parts . The * overlapping partition* of is the partition , , such that is the number of columns of length two among the smallest rows of in lowest position, for . When is a partition, is the number of columns of length two in the last rows of for .
Observe that is the number of columns of , for . In particular, is the number of columns of and thus the Schur interval of a ribbon with overlapping partition is . When is a partition, one obtains (1.4) as a special case of this interval.
Proposition 3.1**.**
Let be a composition with parts . For , let be the number of connected components (ribbons) of . Then , for , with , and
[TABLE]
where the set of distinct entries of is contained in .
Proof.
Observe that, and by induction on , is the first entry of the overlapping partition of , . Henceforth , for . ∎
A ribbon is connected if and only if , otherwise . It is an horizontal strip if . When , a ribbon (not necessarily connected) is uniquely defined by the partition and its overlapping partition and hence denotes such ribbon. In fact, more can be said. It is shown next that monotone ribbons with at least two boxes in each row are in bijection with pairs of partitions where the parts of are assigned by a multiset of of cardinality with . Recall Example 1.1, is defined by the partition pair and .
Proposition 3.2**.**
Let be a partition with parts and let . There is a bijection between ribbons with connected components and multisets of of cardinality assigning the parts of the overlapping partition .
Proof.
Let with connected components. One has , and, for , if rows and of do not overlap, and otherwise. In particular, . Henceforth the parts of form a multiset of of cardinality . Let and be two distinct ribbons (skew shapes do not coincide) with connected components and overlapping partitions and respectively. Let us choose the first such that rows and in one of them overlap and in the other do not. Then , for , and and or reciprocally, and thus .
Let us consider a multiset of of cardinality , and the partition where is the given multiset. We have to construct a ribbon with components and overlapping partition . Put the last rows of pairwise disconnected and, observing that , whenever rows and of do not overlap, and otherwise for . ∎
Remark 3.1*.*
Observe that if is not a partition, in general and do not uniquely define a disconnected ribbon with more than two connected components. For instance, below , and , are distinct ribbons with the same overlapping partition ,
[TABLE]
Example 3.1*.*
Ribbons with shape , for , :
[TABLE]
with and . The sequence of ribbons , , is depicted below
\young
(::::: ,::: ,:: , ), \young(:::: ,:: , ), \young(::: ,: ), \young(: ).
3.2. LR ribbons and companion tableaux
Let be an arbitrary composition. As we have seen in (2.6), if one picks to be the companion tableau of some LR ribbon in the Yamanouchi word has to guarantee in the filling of the standard condition in the columns. The overlapping of two consecutive rows reduces to at most one column. Thus for ribbon shapes one has just to avoid the violation of the standard condition on the overlapping row pairs which just occurs in one column. In other words, whenever, in , rows and overlap then in the reading word the subword is strictly increasing which means is a descent of . In the case of connected ribbons , this is exactly the content of Theorem 1.1: to avoiding the violation of the semistandard condition on the overlapping row pairs it requires the descent set of the standardization of the companion tableau to be equal to . To figure out what are the conditions to be imposed on the entries of a SSYT to be the companion of an LR ribbon, we take into account the bijection (2.6), whose domain we now extend to the set . Thanks to Proposition 2.1 we may define the bijection
Definition 3.2**.**
Let be a partition and an arbitrary composition of . Given , for each , and , let denote the multiplicity of letter in row of . Given a ribbon , define the map
[TABLE]
such that is the filling of by putting letters in each row strip , starting from the left, for , and , that is, the reading word of is .
Remark 3.2*.*
When is an horizontal strip, the map is a bijection and .
Example 3.2*.*
Let and .
Let with and . Considering the overlapping sequence for , we get the tableau
[TABLE]
with Yamanouchi reading word satisfying both requirements of semistandard property. Thus, and is the companion tableau of .
Next, one exhibits the violation of the column semistandard condition of in the two possible ways. Consider now and in where , , , , and , , .
If , the strict increasing filling along columns of and fails in the overlapping of the rows and , and and , respectively:
[TABLE]
In the first case, , if we instead consider the overlapping sequence , then becomes the companion tableau of .
In the second case, , we keep but change to , where , then is the companion tableau of ,
[TABLE]
Example 3.3*.*
Let and . Let
[TABLE]
The descent set ; and the descent set . The tableaux and are companion tableaux of the following LR fillings for ,
[TABLE]
From Proposition 2.1 we easily conclude
Proposition 3.3**.**
Let and a ribbon. Then
* if and only if whenever two consecutive rows and of overlap then is in the descent set of .*
* if is connected, is an LR ribbon if and only if .*
* if is a direct sum of connected ribbons, is an LR ribbon if and only if .*
Corollary 3.4**.**
* Let be a connected ribbon and a partition such that . Then*
- (1)
\rm LR_{\nu,R_{\alpha}}=\{G\in Tab(\nu,\alpha):\text{ \mathcal{S}(\alpha)=\mathcal{D}(\widehat{G}) }\}. 2. (2)
* the number of standard Young tableaux of shape with descent set .*
* Let and a direct sum of connected ribbons . Then*
- (1)
\rm LR_{\nu,R_{\alpha}}=\{G\in Tab(\nu,\alpha):\text{ \mathcal{S}(\alpha)\setminus{\sum_{i=1}^{r}|\tilde{\alpha}_{i}|,1\leq r\leq k}\subseteq\mathcal{D}(\widehat{G}) }\}. 2. (2)
* is the number of standard Young tableaux of shape whose descent set, a subset of , contains .*
3.3. The critical set of a SSYT in
We now reduce our study to compositions with parts . Given , recall that . The goal is to identify in the SSYT the entries of that are elements of . More precisely, the numbers in the filling of such that in the word (Subsection 2.5) either it occurs ; or . See Example 3.2 , .
The serious rejection for to be a companion tableau of a LR ribbon in occurs when one has repeated letters in a column of length of . This means that we are collecting in the filling of the numbers verifying . This numbers define a subset of called the critical set of . The set of critical numbers of verifies
[TABLE]
[TABLE]
[TABLE]
From Proposition 3.3 and Corollary 3.4, we conclude that detects the elements in the alphabet for which are not in the descent set of and give rise in to a filling of a column of length with two repeated letters. This column of length two is obtained in the overlapping of the rows and of and is filled with a same letter . Henceforth, because is a sequence of partitions , the right most box of the horizontal strip is glued with the left most box of , and one has
Proposition 3.5**.**
Let and . The number or is a critical number of , if for some , , and for all and . In this case, we also say that the integer generates the critical row of .
The numbers in giving rise to the violation by inverting the increasing order in the filling of a column of length two in are negligible critical numbers, because they may be removed anytime without creating new ones. In the SSYT we collect the numbers verifying condition . In fact, if, in a such column of , resulting from the overlapping of rows, say, and of , one has , with , we may easily correct this Yamanouchi filling, without creating new violations in the new Yamanouchi filling, by just reordering the entries of that column, , with , to obtain an LR ribbon. This tells that appears in only in row and possibly below, and only appears in row and above. (The horizontal strip is strictly below the horizontal strip .) Henceforth, we should replace in row of the left most entry with , and replace in row of the rightmost entry with . One then says is a negligible critical number of . See Example 3.2, , .
Canonical fillings of SSYTs do not have negligible critical numbers and the critical numbers have an easier formulation. Note that the multiplicity of letter in row of satisfies .
Proposition 3.6**.**
Let with canonical filling and . Then is a critical number of if and only if and for some .
Proof.
Recall . If has canonical filling and with for all , then below row the entries are empty or bigger than . Therefore there is no need to put ’s in rows above because positions of row have been used to put the letter , that is, one also has for all . Hence . Similarly for all because has to be filled first and there are no below row . Hence . ∎
We then may conclude
Proposition 3.7**.**
Let without negligible critical numbers. Then if and only if has a critical number such that rows and of overlap. In this case, the column of length two obtained in the overlapping of rows and of is filled with a same letter .
3.4. Effectiveness of critical numbers
The ribbon , with rows of length at least two, is now assumed to be connected or monotone up to a permutation and rotation of the connected components of . Since the ribbon can be monotone and disconnected, the overlapping partition is used to detect the effectiveness of the critical numbers of a companion tableau in .
Definition 3.3**.**
Let and let be an overlapping partition for . A critical number of is said to be -effective if rows and of overlap. Otherwise, the critical number is said to be -ineffective.
This is a reformulation of Corollary 3.4 for ribbons uniquely determined by and .
Theorem 3.8**.**
Let and an overlapping partition for . Then,
* only if ,*
* if has no negligible critical numbers and , if and only if every critical number of is -ineffective.*
Proof.
The number of columns of length two of is . Since has no negligible critical numbers, to avoid columns of length two filled with the same letter, we need that the descent set of has at least elements.
It is the translation of Proposition 3.7 according to the Definition 3.3. ∎
4. Characterization of monotone ribbon LR coefficients positivity by means of linear inequalities
Throughout this section we consider a partition with parts of length at least , and overlapping partition . Theorem 3.8 says that if and only if, whenever there exists without negligible critical numbers and , then every critical number of is -ineffective. Theorem 1.2 gives a set of linear inequalities on the triple of partitions as necessary and sufficient conditions for the positivity of . We split the proof of the only if and if parts of Theorem 1.2 into two subsections respectively.
4.1. Proof of the only if part of Theorem 1.2
If then there exists and . Let where is a multiset of such that and with , , the connected components of . Therefore with for some subset satisfying
[TABLE]
Observe that , for . Because , by Remark 2.1, , for . On the other hand, the ’s constitute the -th horizontal strip of whose rows belong to the first rows of , for . Consider the SYT and . If , , is a descent of in the th row of , then belongs to a row of strictly below row . That is, for , if is a descent of , then either belongs to a row of strictly above row , or belongs to a row of strictly below row . Observe that is the maximum number of descents of in row , and, simultaneously, is at least equal to the overlapping number , the number of columns of length two among the last rows of ,
[TABLE]
Hence , for .
4.2. Proof of the if part of Theorem 1.2
Given the triple of partitions, , and , with parts , and overlapping partition , satisfying the linear inequalities on the right hand side of (1.6), the goal is now to exhibit a SSYT . In other words, assuming the linear inequalities on the right hand side of (1.6), we construct a SSYT without negligible critical numbers and -effective critical numbers. In more detail, we pick with the canonical filling, thus without negligible critical numbers, and then, if it has -effective critical numbers, one modifies its filling according to a certain rotation procedure to remove them so that the new tableau is in . The application of rotation procedure does not create negligible critical numbers. The linear inequalities on the right hand side of (1.6) guarantee that our rotation procedure is successful.
Remark 4.1*.*
Let and an overlapping partition for .
If , given , the first entry of each row of is and has no critical numbers of any kind. The descent set of is and every is a companion tableau for an LR filling of . In this case, the linear inequalities (1.6) are trivially satisfied because below each row of one has at least entries and thereby . Also .
If then , , and . The descent set of the sole is , and linear inequalities (1.6) are trivially satisfied with . One has .
We shall consider with at least two rows and less than rows, .
We start with the case .
Lemma 4.1**.**
Let with , such that
[TABLE]
Then, .
Proof.
Let . Let , with the canonical filling, and note that since , then the first column of has all letters of , for some , and necessarily row contains letters . That is, the first entry of row of is , for , and is for . Thus, , , , , , and , . The only row of which can potentially be critical is row , since by Proposition 3.6, and . That is, the rows and of look like
[TABLE]
or
[TABLE]
where the word , , may be empty. If is not a critical number, or if it is a -ineffective critical number (4.3) then, by Proposition 3.7, is a skew SSYT.
Assume now that is -effective critical number of (4.4). In particular, this means that . Notice that if , then
[TABLE]
which implies . That is, rows and of do not overlap, which contradicts the fact that is -effective critical. So, we must have , and, in particular, row of has at least one integer . Table 4.1 depicts rows and of , where denotes boxes with the letter , or the empty cell if ,
Perform the procedure Rotation described in Table 4.2 with , and on the tableau .
That is, rotate the highlight letters and of (Table 4.1) in anticlockwise order to obtain the rows shown in Table 4.3, and denote by the tableau obtained from by this operation.
We recall that we are assuming a partition and thus . The new tableau is still semistandard and the integer is no longer critical, since . Notice, however, that if in , then in the integer is critical. Therefore, if in , or in and is -ineffective critical, then is a skew SSYT. So, assume , -effective critical in , and in addition rows and of overlap ( is -effective in ). If , (Table 4.4) then and ,
and that is, A contradiction, then the rows and of cannot overlap, and is not -effective critical in .
So we must have , and there must be integers other than in row of , since otherwise the rows of below row would have only one box, which in turn would imply , a contradiction. So there are letters in row and the number of letters below row is (Table 4.5). Apply the procedure Rotation with and to ,
and let be the resulting tableau (Table 4.6),
This new tableau is semistandard and is no longer a critical number, since there is now a letter in row . Also, since , there must be integers below row . Thus, does not have critical numbers and then is a skew SSYT. ∎
Remark 4.2*.*
Notice that when applying the procedures, described in the proof of the result above, to a tableau with only one critical number in row , we only modify rows and of . Moreover, in row , only the integers , and possible , are acted upon. The rows above row , as well as the letters in row to the left of the letters , are not considered for the application of the procedure.
Example 4.1*.*
Let and , and consider the tableau
[TABLE]
The tableau has only one critical number: the integer , that is, the descent of is . If , equivalently, , then is SSYT and the integer is not -effective critical, and so
[TABLE]
is a skew SSYT. Note also, .
If then , is a -effective critical number and is not SSYT. Perform the procedure Rotation on with and to get
[TABLE]
The tableau has no effective critical numbers for the overlapping partition , the descent set of is , and therefore
[TABLE]
is a skew SSYT. There is no connected LR ribbon of shape and content : if , .
Example 4.2*.*
Let and , and consider the tableau
[TABLE]
The letter is the only critical number of , and is effective when we consider the overlapping partition . So, we apply the procedure Rotation on with and :
[TABLE]
In , the number is no longer critical. However, a new critical number was created: the number . So we apply Rotation on with and to get the tableau
[TABLE]
which has no critical numbers. It follows that
[TABLE]
is a skew SSYT. Note , , .
Lemma 4.2**.**
Let with , , and satisfying
[TABLE]
If is the SSYT with canonical filling in and has with , for , then, .
Proof.
Let be the canonical filling in with such that for . Then, the first column of has all letters of , and row has letters , for . We are assuming that is critical but is not, row also has letters and letters , thus, row of satisfy
[TABLE]
that is,
[TABLE]
where . The number of -effective critical numbers of , which are at most , must be less than or equal to . Thus, by (4.5), there are at least integers greater than or equal to below row of and we can perform procedure Rotation 1 on with and .
Let be the tableau resulting from the application of Procedure Rotation 1 (Table 4.7) on . Notice that the assumption of a partition and the canonical filling of asserts that is semistandard. Moreover, the integers are not critical numbers of since there are letters below row . However, the operations performed on to produce may create new critical numbers, all of which are in row . This only happens when all letters of an integer, say , are sent to row . Note that must be one of the first letters below row which are greater or equal to the rightmost letter of row . Let be the new critical numbers created in . If they are -effective, then by (4.5), we must have
[TABLE]
This means that below row of there exist at least integers greater or equal to the rightmost letter of row , and we can perform procedure Rotation 1 on with and , obtaining a new tableau , where are not critical . Again, new critical numbers , with may occur, in which case we repeat the process. Note that since the number of -effective critical numbers cannot exceed , this process must terminate.
Therefore, the tableau obtained after this procedure is semistandard and has no critical numbers. We can conclude that is semistandard. ∎
Remark 4.3*.*
Notice that Lemma 4.1 is a special case of Lemma 4.2. Also, notice that the tableau obtained after the process described in the result above only differs from between the rows , the ones having the critical numbers, and some row below it, say , from the leftmost integer of until the last integer in row that has been rotated to row .
Example 4.3*.*
Let , , and consider the overlapping vector and the tableau
[TABLE]
The letters and are consecutive -effective critical numbers of . Apply procedure Rotation 1 with and :
[TABLE]
Now, the letter is the only critical number of the resulting tableau . So, we apply Rotation 1 again on with and :
[TABLE]
Now, the letter is the only critical number of the resulting tableau . So, we apply Rotation 1 again on with and :
[TABLE]
The tableau has no critical numbers and thus is a skew SSYT.
We now can prove the general case.
Theorem 4.3**.**
Let where , , and satisfying
[TABLE]
Then, .
Proof.
Let with the canonical filling, and . Write
[TABLE]
the set partition of such that in each set all critical numbers are consecutive, and if and , for some , then and .
Notice that in this case, the letters must be all in some row , and the letters must be all in some row of , with .
Apply the procedure described in Lemma 4.2 to the set of consecutive critical numbers in . This procedure may use some integers from in its Rotation routines. If this is the case, then in the resulting tableau , some of the critical numbers in may no longer be critical numbers, since some of them may have been brought, by rotation, to a higher row of the tableau. Nevertheless, no new critical numbers are created by this process. So, in , the critical numbers can be partitioned as
[TABLE]
where for all .
Repeating the process, until no more critical points remain, we obtain a tableau such that is a skew SSYT. ∎
Example 4.4*.*
Let , and . The tableau
[TABLE]
has the critical points , which can be partitioned as
[TABLE]
according to the proof of the theorem above. We start by removing the critical numbers in :
[TABLE]
[TABLE]
After the application of the procedure described in Lemma 4.2 to the critical numbers in , we get the tableau , whose only critical olga number is
[TABLE]
So, we apply the procedure described in Lemma 4.2 again to the critical number in :
[TABLE]
The resulting tableau has no critical numbers and thus, the skew tableau
[TABLE]
is a skew SSYT.
5. Classification of monotone ribbons with full Schur support
Theorem 1.2, characterizing the positivity of monotone ribbon LR coefficients, , by means of linear inequalities, may be rephrased in the language of the Schur support of . Let , a partition with parts . Then
[TABLE]
By Remark 2.1, if one has , for . Hence, if then , and because one has , for , the inequalities (5.1) are always satisfied for . Note that, when , , . Recall Definition 1.1 and , where is the total number of columns in the last rows of , for .
Remark 5.1*.*
Because the parts of are , and or , .
Thus, the negation of (5.1) characterizes the partitions in the interval which are not in the support of .
Corollary 5.1**.**
Let and a partition with parts . Then, if , , and, if , the following are equivalent
* if and only if there exists such that*
[TABLE]
* if and only if, for some , exceeds the number of columns in the last rows of .*
* [ACM17, Lemma 4.8] if and only if, there exists such that after placing ’s, in row of , for , there is no space to place ’s in the remain rows of without avoiding the violation of the column standard condition of the filling.*
* , if, for every , there exists such that .*
Example 5.1*.*
Consider the partition with the overlapping partition . The partition is in the Schur interval of , but not in its support since . Therefore,
Theorem 1.3 characterizes the monotone ribbons with full Schur support in terms of their partition skew shape and the overlapping partition . In Definition 1.1 a sequence of witness vectors with its slack , , is introduced to test the fullness of the Schur support of . Theorem 1.3 says that if, for some , the size of the witness vector fits the slack , that is , then has not full Schur support. In this case the vector witnesses that the Schur support is not full in the sense that it can be used to exhibit a partition in the Schur interval that is not in . More precisely, , with the total number of columns in the last rows of , is a partition of in the Schur interval of but not in the support of .
5.1. Proof of Theorem 1.3
The “only if” part. Let such that . Then, on one hand, since , , , and on the other hand, since , by Corollary 5.1, , , and there exists with such that
[TABLE]
We want to show that the -witness vector of fits its slack . It follows that , otherwise, we would have
[TABLE]
contradicting the equality .
Let (indeed ) and . Put if .
Claim: There exist , , such that
[TABLE]
[TABLE]
In these conditions, defining , , and , , one has ,
[TABLE]
and
[TABLE]
so that for . It follows that the witness vector , with for , fits its slack:
[TABLE]
Proof of the Claim: We prove the claim by double induction on and .
For there is nothing to prove whatever is . Let . For , one has and with . Since and , for some , we may write
[TABLE]
Thus .
Let , and where , for some , and , . We distinguish two situations:
: , , for some , and , for . We have and we may write
[TABLE]
where . Also
: for some and , . One has , henceforth
[TABLE]
Thus and .
Since , by induction, there exist with , , such that
[TABLE]
Indeed, one has , with , , such that . Define recursively the non negative integers
[TABLE]
and put Therefore, there exists such that and
[TABLE]
Hence,
[TABLE]
as required.
The “if” part. Let , . Suppose now that there is an i-witness vector of for some , with , such that . Let be the partition of formed by the rearrangement of the composition
[TABLE]
where
We will show that is a partition in the Schur interval of the ribbon that is not in its support. Indeed, the inequality shows that all entries in (5.4) are non negative, and . Thus, is well defined and is a partition of .
Recall that is the total number of columns of and that is the number of columns of length two in this same ribbon. Therefore, we have . Moreover, for each , we have
[TABLE]
It follows that . This means that the last two entries of are and . In particular, it follows from Corollary 5.1, , that is not in the Schur support of .
It remains to prove that is a partition in the Schur interval . We start by showing that . From (5.5), we find that for each ,
[TABLE]
and since , Finally, since is a partition of , we get . To prove that we also have , notice that by (5.5) and Remark 5.1, is either equal to or to , and . Therefore, we have . Clearly, , from which it follows that .
Remark 5.2*.*
Let be a partition with parts and overlapping partition with . Recall Definition 1.1, , and , for . Observe that the following are equivalent:
for some , the size of the -witness vector fits its slack, that is,
[TABLE]
for some , there exist integers with , such that
[TABLE]
Indeed, (5.7) says that, for , other ”witness vectors” can be found depending on how big is the slack . Simultaneously (5.7) tells that the selected witness in Definition 1.1 is entrywise the smallest,
[TABLE]
If our selected witness does not fit (is over the size of) its slack, no other (any other) choice for the witness vector will fit (oversize) it.
In the conditions of , it can be shown that with ( has the possible biggest size) is a partition of in the Schur interval of but not in the support of .
Example 5.2*.*
Consider the same example as before, and the ribbon with . Applying Theorem 1.3 with , one has , and the -witness vector , satisfy . Therefore, the support is not the full Schur interval. The partition
[TABLE]
is in the Schur interval but not in the support .
Furthermore, considering , with , , the partitions and are in the interval but not in the support of .
5.2. Proof of Remark 1.2 and Corollary 1.5
. Theorem 1.4 is logically equivalent to Theorem 1.3 and says that if every -witness vector of , for , is oversized, with respect to its slack , then has full Schur support. In particular, has full support only if for every . In fact, if, for some , , then and This implies that is not in which is absurd.
When , one has , and if and only if . In fact, if , (1.9) means
[TABLE]
When , one has , and if and only if . In fact, if , (1.10) means
[TABLE]
[TABLE]
Example 5.3*.*
Let with . We use the characterization given by the Theorem 1.4 to prove that has full support . Since and , we have two inequalities to check:
[TABLE]
6. Connected ribbons with full equivalence class and full Schur support
Building on [Mc08], M. Gaetz, W. Hardt and S. Sridhar have introduced in [GaHaSr17] the family of connected ribbons with full equivalence class.
Definition 6.1**.**
[GaHaSr17, Definition 7] Let be a partition with parts and . The connected ribbon is said to have full equivalence class if , for any rearrangement of the entries of .
Definition 6.2**.**
[GaHaSr17] Three integers are said to satisfy the strict triangle inequality if . In this case, the multiset is said to satisfy the strict triangle inequality.
The set of connected ribbons with full equivalence class have partitions as representatives. For monotone connected ribbons, the inequality (1.11), in Theorem 1.6, [GaHaSr17, Theorem II.1], giving a necessary condition for full equivalence class, is equivalent to inequality (1.8), in Theorem 1.4, characterizing the full Schur support.
**Proof of Lemma 1.7 ** Let and From the definition of , one has . Then
Proof of Theorem 1.8. Because is connected, and, in Definition 1.1, , for . Suppose that does not have full Schur support. Then Theorem 1.4 says that for some ,
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Inequality (6.1) implies in the definition of , (1.11), that with . Henceforth, by Theorem 1.6, [GaHaSr17, Theorem 1.2], one concludes that does not have full equivalence class. When , by Theorem 1.3, has full support if and only if (strict triangle inequality). Theorem 3.4, in [GaHaSrTr17], also shows that has full equivalence class if and only if . When , by Theorem 1.3 , has full support if and only if (1.10) are satisfied. Theorem 3.6, in [GaHaSrTr17], also shows that has full equivalence class if and only if (1.10) are satisfied.
Next theorem gives a sufficient condition for a monotone connected ribbon to have full equivalence class [GaHaSr17, Corollary1.4] which in turn, thanks to Theorem 1.8, also gives a sufficient condition for monotone connected ribbons to have full Schur support.
Theorem 6.1**.**
Let be a composition with parts and . If all 3-multisets contained in satisfy the strict triangle inequality then the connected ribbon has
* [GaHaSr17, Corollary 1.4] full equivalence class; and*
* full Schur support .*
The strict triangle inequality condition given by the previous theorem is sufficient for a connected ribbon to have full support, but it is not necessary. For instance, not all 3-subsets of the partition satisfy the strict triangular inequality , but as we have seen in Example 5.3, the connected ribbon has full support. Nevertheless, for partitions with length the connected ribbon has full support (full support) if and only if satisfy the strict triangular inequality (1.9).
Next statement classifies arbitrary compositions with length with respect to the full support where we may verify that for non monotone compositions the strict triangular inequality is not a necessary condition. This means that the full Schur support classification for non monotone compositions and for partitions is not the same.
Corollary 6.2**.**
Let be a composition of length 3 with each part . Then, the connected ribbon has full support except when or with , in which cases, the partition is in the Schur interval but not in the support of .
Proof.
By the previous theorem, we know that if satisfies the strict triangle inequality, , then has full support. There remains three cases to analyse: , or , or , with . Since the support of is invariant under 180 degrees rotation of the ribbon , the first two cases can be reduced to the first one. Suppose that satisfies and , and recall that the overlapping partition is . Applying Theorem 1.3 with one has and , and henceforth, the support of is not the entire Schur interval, since the partition is in the Schur interval but not in the support of . The same partition proves the result when . Note that an LR filling of with content would oblige to fill the first row with 1’s and the last two rows with 2’s. Since the two last rows of overlap such a filling violates the column semistandard condition.
Finally, in the case of the connected ribbon satisfying , it is easy to show that for any partition in the Schur interval . Indeed if , any is such that . If , consider the canonical filling , . Then the second row of has ’s and because , (otherwise ), the first row of has ’s and at least one two. In case, , the 2nd row of has ’s and the , ’s are all in the first row of , in which case we swap the rightmost in the first row with the leftmost in the second row to get a new tableau in . The descent set of this new tableau is . ∎
Remark 6.1*.*
If the composition satisfies the connected ribbon has full support while does not have full support because .
Corollary 6.3**.**
[McWi12, Theorem 1.5.]** Let be an arbitrary composition with parts . Connected ribbons whose column and row lengths differ at most one have full support. They also have full equivalence class except when , .
Proof.
Let and a connected ribbon in the conditions of the statement. Observe that the transpose of is still in the conditions of the statement. If or its transpose consists only of one or two rows is trivial. Suppose that has at least three rows. If for all , then , for all , and any three parts of satisfy the strict triangle inequality By Theorem 6.1, , has full support and full equivalence class. If then , , and transposing we fall in one of the previous cases: with , and again has full support and full equivalence class. If or , by 180 degrees-rotation, we may assume the last inequality and we have with . Put and let be the Schur interval of , . By the previous cases, the support of is the full interval .
The Schur interval of is and it is self conjugate. Its partitions are obtained using one extra box in the construction of the elements of . There are three possible positions to put the extra box in one element of and obtain : far right of the first row; below the last row; or far right of the last row.
Because and , by transposition of , we may reduce to . Hence if then the SSYT , obtained by adding one box filled with below the last row of , is in with . Note that . It remains to prove that obtained in is in . If the last row of has at most one then just add one box filled with at the end of the this row to obtain . If the last row of has two ’s also add one box filled with at the end of this row. At least one entry in the row above is not in the last row and choose that in the rightmost position: it is the far right entry:
, T=\begin{array}[]{ccccc}\cdots\\ \cdots&a&b&(s-1)\\ \cdots&s&s&(s+1)\\ \end{array}\rightarrow T_{\Box}=\begin{array}[]{ccccc}\cdots\\ \cdots&a&b&s\\ \cdots&s-1&s&(s+1)\\ \end{array},a<s-1,b\leq s-1
, T=\begin{array}[]{ccccc}\cdots\\ \cdots&d&c&a\\ \cdots&s&s&(s+1)\\ \end{array}\rightarrow T_{\Box}=\begin{array}[]{ccccc}\cdots\\ \cdots\cdots&d&c&s\\ \cdots a&\cdots&s&(s+1)\\ \end{array},c\leq a<s-1,d<a, enters in the last row of bumping to the right the left most strictly bigger entry; otherwise, T=\begin{array}[]{ccccc}\cdots\\ \cdots&d&c&a&x\\ \cdots&x&s&s&(s+1)\\ \end{array}\rightarrow T_{\Box}=\begin{array}[]{ccccc}\cdots\\ \cdots&d&c&x&s\\ \cdots a&\cdots&x&s&(s+1)\\ \end{array},d<a<x\leq s-1,c\leq a, enters in the last row of bumping to the right the left most strictly bigger entry. In any case and .
Indeed, and , , do not have the same Schur interval. The Schur interval of the latter is with and henceforth , does not have full equivalence class. ∎
7. Towards to a coincidence between full Schur support monotone connected ribbons and full equivalence classes
In this section we consider connected ribbons with parts arranged in any order. The necessary condition, given by Theorem 1.2, for the LR coefficient to be positive, with a partition, is generalized to a connected ribbon where , , is a -permutation of the entries of . Thanks to the -rotation symmetry of LR coefficients, , it is sufficient to consider partitions of length . That is, we already know that . Recall the definition of overlapping partition of a connected ribbon with row lengths in arbitrary order, Definition 3.1, and that the overlapping partition of the connected ribbon satisfies (3.1), , that is, , and , .
Theorem 7.1**.**
Let be a partition with parts , and a connected ribbon with overlapping partition . Let . Then
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Proof.
We prove the contrapositive assertion: if there exists such that then . (Indeed and .)
Let and let be the smallest element in such that . Since and , one has
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If we place ’s, ’s, ’s in to obtain an LR filling then at least the first rows of are completely filled because one can not place in them numbers . Henceforth, in the best case one has , so that it remains rows of to place ’s. Because is connected the number of columns of length two among them is . (In fact, in this case, one has the equality . Because one has the equality of the multisets and by definition is the number of columns of length two among the rows of the ribbon which in this the same as among the rows of .) It means that in the best case the number of available boxes to fill with , ’s, is in fact
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which is not enough. Therefore . ∎
Remark 7.1*.*
Under the assumption that row lengths are , and have the same the Schur interval, , for all .
Assuming in Theorem 7.1 that inequalities (7.1) are also sufficient for , we have the following result. If with a partition, and then
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Therefore, , for any . If has full Schur support, , for any , and has full equivalence class. Thereby, does not have full equivalence class if and only if , for some .
In other words, the connected ribbon with a partition with parts has full support only if has full equivalence class. This implies that the Gaetz-Hardt-Sridhar conjecture [GaHaSr17, Conjecture II.4] claiming that the necessary condition on full equivalence classes (1.11) is also sufficient, is true.
Conjecture 7.2**.**
Let be a partition with parts and a connected ribbon. Then the following are equivalent
* has full Schur support, that is, ;*
* has full equivalence class;*
* For all ,*
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