Central Limit theorem and cohomological equation on homogeneous spaces
Ronggang Shi

TL;DR
This paper extends Livšic type results and proves a central limit theorem for Birkhoff averages in partially hyperbolic homogeneous space systems, revealing nonzero variance under certain conditions.
Contribution
It introduces a Livšic type theorem for noncompact, nonaccessible homogeneous systems and establishes a central limit theorem for horospherical orbit averages.
Findings
Livšic type result extended to noncompact systems
Central limit theorem proven for Birkhoff averages
Variance is nonzero for functions with nonzero mean
Abstract
The dynamics of one parameter diagonal group actions on finite volume homogeneous spaces has a partially hyperbolic feature. In this paper we extend the Liv\v{s}ic type result to these possibly noncompact and nonaccessible systems. We also prove a central limit theorem for the Birkhoff averages of points on a horospherical orbit. The Liv\v{s}ic type result allows us to show that the variance of the central limit theorem is nonzero provided that the test function has nonzero mean with respect to an invariant probability measure.
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Taxonomy
TopicsMathematical Dynamics and Fractals · Geometry and complex manifolds · Geometric and Algebraic Topology
Central Limit theorem and cohomological equation on homogeneous spaces
Ronggang Shi
Shanghai Center for Mathematical Sciences, Jiangwan Campus, Fudan University, No.2005 Songhu Road, Shanghai, 200433, China
Abstract.
The dynamics of one parameter diagonal group actions on finite volume homogeneous spaces has a partially hyperbolic feature. In this paper we extend the Livšic type result to these possibly noncompact and nonaccessible systems. We also prove a central limit theorem for the Birkhoff averages of points on a horospherical orbit. The Livšic type result allows us to show that the variance of the central limit theorem is nonzero provided that the test function has nonzero mean with respect to an invariant probability measure.
Key words and phrases:
homogeneous dynamics, central limit theorem, cohomological equation
2010 Mathematics Subject Classification:
Primary 37C85; Secondary 60F05, 37D30.
The author is supported by NSFC 11871158.
1. Introduction
Let be a finite volume homogeneous space, where is a connected noncompact semisimple Lie group with finite center and is an irreducible lattice of . Recall that a lattice is said to be irreducible if for any noncompact simple factor of the group is dense in . The left translation action of on is (strongly) mixing with respect to the probability Haar measure . The mixing is exponential when the action of on has a strong spectral gap, i.e., the action of each noncompact simple factor of on has a spectral gap. Recall that the action of a closed subgroup of on is said to have a spectral gap, if there exists and a compactly supported probability measure on such that for all one has
[TABLE]
It was proved by Mozes [19] that the system is mixing of all orders. The effective version of multiple mixing was proved by Björklund-Einsiedler-Gorodnik [3] under the assumption of the existence of the strong spectral gap. As an application, they obtained a central limit theorem in [4]. The aim of this paper is to give a sufficient condition of nonzero variance and prove new central limit theorems based on [24] where the author proved effective multiple correlations for the trajectory of certain measure singular to .
The irreducibility assumption for is unnecessary, so we assume from now on that is just a lattice of . We consider the action of a one parameter -diagonalizable subgroup on . Here -diagonalizable means the image of through the adjoint representation of is diagonal with respect to some basis of the Lie algebra.
Let be a continuous function integrable with respect to , and let be a probability measure on . It is said that obeys the central limit theorem if the random variables
[TABLE]
converge as to the normal distribution with mean zero and variance , i.e., for any bounded continuous function ,
[TABLE]
If , then the right hand side of (1.2) is interpreted to be and we say the central limit theorem is degenerate.
Let be the space of compactly supported smooth and real valued functions on . It was proved in [4] that obeys the central limit theorem if and the action of on is exponential mixing of all orders, e.g., the action of on has a strong spectral gap [3]. Some special cases were known earlier in [25][21][15] when is the isometric group of a hyperbolic manifold with constant negative curvature. If in addition is compact, then the characterization of nonzero variance is well understood. It was proved by Ratner [21] that if and only if the system of cohomological equations parameterized by
[TABLE]
has a measurable solution . Here a measurable solution means (1.3) holds for almost every . Using Livšic’s theorem [16] which says that a measurable solution to (1.3) is equal to a continuous function almost everywhere, Melbourne and Török [18] showed that if and only if
[TABLE]
Our first main result is to extend Livšic’s theorem to the homogeneous space . This will allow us to give a sufficient condition of nonzero variance similar to (1.4). For , we use to denote the group generated by the unstable horospherical subgroup and the stable horospherical subgroup , where
[TABLE]
Here and hereafter denotes the identity element of a group . The group is a connected semisimple Lie group without compact factors and it is normal in . Let be the set of functions which can be written as a sum of a function in and a constant.
Theorem 1.1**.**
Let where is a connected semisimple Lie group with finite center and is a lattice. Let be a one parameter -diagonalizable subgroup of and let be the probability Haar measure on . Suppose and the action of on has a spectral gap. If is a measurable solution to the cohomological equation where , then and there is a smooth function such that almost everywhere with respect to .
In the case where is compact and accessible, Theorem 1.1 is a special case of Wilkinson [26, Thm. A]. The accessible assumption in our setting is the same as . Our result is new in the case where nonaccessible or is noncompact. The spectral gap assumption is always satisfied if is nontrivial, has no compact factors and is irreducible, see Kelmer-Sarnak [13]. We prove the smoothness of along orbits using the method of [26] and Avila-Santamaria-Viana [1]. The method allows us to prove the Hölder continuity of along orbits if we only assume is Hölder. The Hölder continuity in the case where is due to Le Borgne [17]. This part doesn’t use the spectral gap assumption. To prove the smoothness of along the central foliations of we need to use the spectral gap assumption which implies the dynamical system is exponential mixing. Here we use some ideas from Gorodnik-Spatzier [11] and Fisher-Kalinin-Spatzier [10]. The smoothness of then follows from a result of Journé [12] which says that a function uniformly smooth on transverse family of foliations is smooth. We will prove Theorem 1.1 as well as its refinements where is only assumed to be Hölder continuous in §5 and §6.
Now we state our result on the central limit theorem and give sufficient conditions for the nonzero variance. In order to define the measure singular to we need to review some concepts from [24]. We first setup the notation.
- (n.1)
is a connected normal subgroup of without compact factors. 2. (n.2)
is an absolutely proper parabolic subgroup of , i.e., contains none of the simple factors of . 3. (n.3)
is the unipotent radical of . 4. (n.4)
is a maximal -diagonalizable subgroup of contained in .
The group is said to be -expanding for some if, for any nontrivial irreducible representation on a finite dimensional real vector space , one has
[TABLE]
The expanding cone of in is
[TABLE]
and it has nice dynamical properties while translating -slices on . One of the main results of [24] is to explicitly describe the expanding cone of in . We postpone the explicit description of to §2 where we also review effective multiple correlations. Here we only give an example which is the motivation of this concept.
Example 1.2**.**
Let be positive integers.
[TABLE]
where and are the identity matrices of rank and , respectively, is the identity component of diagonal matrices in , and
[TABLE]
Suppose is a regular element, where regular refers to the projection of to each simple factor of is not the identity element. Let be the unstable horospherical subgroup of in . We assume that , and the conjugation of expands , i.e.,
[TABLE]
The assumption is always checkable due to the explicit description of , see §2 for more details.
Let be a probability measure on given by a compactly supported nonnegative smooth function on and in the following way:
[TABLE]
where is a fixed Haar measure on with . Now we are ready to state the central limit theorem.
Theorem 1.3**.**
Let and be as in Theorem 1.1. Let and be as in -. Suppose is a one parameter subgroup of satisfying for a regular element and is a probability measure on given by (1.6) for and . Then for all with , the system obeys the central limit theorem with variance
[TABLE]
It can be seen from (1.7) that the variance does not depend on and is the same as . So the sufficient condition for the nonzero below can also be applied to the central limit theorem proved in [4]. In the setting of Example 1.2 with , Theorem 1.3 is due to Björklund-Gorodnik [5]. The difference between our proof and that in [5] is that we do not use commulants.
Theorem 1.4**.**
Let the notation and the assumptions be as in Theorem 1.3. Then the variance in (1.7) is equal to zero if and only if the system of cohomological equations
[TABLE]
has a measurable solution .
This theorem together with Theorem 1.1 allow us to give a sufficient condition for the nonzero variance.
Definition 1.5**.**
A function is said to be dynamically null with respect to if for any -invariant probability measure on one has .
Theorem 1.6**.**
Let the notation and assumptions be as in Theorem 1.3. If the variance in (1.7) is zero, then the function is dynamically null with respect to .
The above theorem says that the central limit theorem is nondegenerate if the integral of with respect to an -invariant probability measure is nonzero.
Acknowledgements: I would like to thank Seonhee Lim, Weixiao Shen and Jiagang Yang for the discussions related to this work.
2. preliminary
In this section we review some facts and prove a couple of auxiliary results. Let the notation and assumptions be as in Theorem 1.3. Some results in this section are also used in the proof of Theorem 1.1 where we take .
We first state the explicit description of the expanding cone and the result of effective multiple correlations in [24]. Let and be the Lie algebras of and , respectively. Let and be the adjoint representations of the Lie group and the Lie algebra, respectively.
Recall that we assume holds, namely, belongs to the expanding cone and the conjugation of expands a horospherical subgroup contained in . The latter means that the eigenvalues of on the Lie algebra of are bigger than one. The assumption is also easy to check and the details are given below.
Let be the set of nonzero linear forms on such that there exists a nonzero with
[TABLE]
Let be the Killing form on . Then for each , there exists a unique such that
[TABLE]
Theorem 2.1**.**
[24*]**
The expanding cone where .*
In the statement of the effective multiple correlations we need to use the -Sobolev norm for a positive integer . Recall that a vector field on a smooth manifold is a smooth section of the tangent bundle of . A vector field on defines a partial differential operator on . Give where are vector fields on we take and . We also allow to be the null set where is the identity operator and .
Elements of the Lie algebra are naturally identified with the right invariant vector fields on which descend naturally to vector fields on . For every we use the same notation for the induced vector field on . We fix a basis of consisting of eigenvectors of and denote
[TABLE]
where the maximum is taken over all the -tuples () with alphabet .
We fix an inner product on such that elements of are orthogonal to each other. Let be the Riemannian distance on given by a right invariant Riemannian manifold structure induced from the inner product on . The advantage of is that there exists such that
[TABLE]
for any and . The Lipschitz norm on is defined by
[TABLE]
The sup norm on is defined by
[TABLE]
Recall that is a fixed probability measure on given by and through the formula (1.6).
Theorem 2.2** ([24] Thm. 4.5).**
There exists an absolute constant , and with the following properties: for any positive integer , any and any real numbers one has
[TABLE]
where is the norm on given by
[TABLE]
We make it convention in this paper that the product indexed by the null set is and the sum indexed by the null set is [math]. So in (2.2), if then .
Lemma 2.3**.**
There exists and such that for any functions and any one has
[TABLE]
Proof.
Recall that we assume the action of on has a spectral gap and has nontrivial projection to each simple factor of . So the conclusion follows from [7, §6.2.2]. ∎
Actually the dynamical system is mixing of all orders. This fact is proved in [3, Thm. 1.1] under the assumption of strong spectral gap. It might be possible to get a proof from [3] under our weaker assumption, but we give a simpler proof here using the method of [24] for the completeness. The exponential mixing of all orders will follow from an estimate similar to (2.2) with replaced by . During the proof we will use the notation for two nonnegative functions which means for some positive constant possibly depending on .
Lemma 2.4**.**
The conclusion of Theorem 2.2 holds with replaced by .
Sketch of Proof.
The proof is the same as that of [24, Thm. 4.5], so we only give a sketch of the key steps. The main difference is that instead of using quantitative nonescape of mass [24, Thm. 1.3] we need to use the effective estimate of the volume in the cusp.
We use to denote the open ball of radius in centered at the the identity element. The injectivity radius at is defined by
[TABLE]
For , let . We claim that there exist such that
[TABLE]
We don’t have a direct proof of this fact, but it is a corollary of the equidistribution of measures in [24, Thm. 1.4] and the quantitative nonescape of mass in [24, Thm. 1.3]. More precisely, we fix a Haar measure on such that the open ball of radius in (denoted by ) has measure . Since the action of on has a spectral gap, there exists such that is dense in . Therefore, by [24, Thm. 1.4] we have for any ,
[TABLE]
On the other hand, by [24, Thm. 1.3], there exists and such that
[TABLE]
In view of (2.4) and (2.5), if and , then . Now (2.3) follows from taking a sequence of increasing functions which converges to the characteristic function of .
To prove the lemma, we assume without loss of generality that
[TABLE]
since otherwise the conclusion is trivial. Let where be as in Lemma 2.3 and which is given by [24, (4.9)]. There is a smooth function such that is contained in the ball of radius in and .
Let be the unstable horospherical subgroup of in . Since is a normal subgroup of , one has is a subgroup of . Then
[TABLE]
where satisfies . So
[TABLE]
Using (2.7), we can effectively replace on the right hand side of (2.6) by , and reduce the estimate of (2.6) to the estimate of
[TABLE]
We have an effective estimate of for using [24, Lemma 4.3]. We have an effective estimate of the volume of using (2.3). These two estimates together allow us to give an effective estimate of (2.8). ∎
In the proof of the central limit theorem, we need to know the growth of the norm of the functions for . Clearly, for all we have . For the other two norms we have the following lemma.
Lemma 2.5**.**
There exists such that for all and one has
[TABLE]
Therefore, .
Proof.
Let which is considered as a right invariant vector field and let be the value of at the identity element. Let be the lift of to . For ,
[TABLE]
where we use the assumption that consists of eigenvectors of so that there exists with . In general for any there exists such that
[TABLE]
Therefore the first inequality of (2.9) holds for any .
For with , we have
[TABLE]
Suppose for some . Then by the right invariance of , the definition of and (2.1), we have
[TABLE]
Therefore the second inequality of (2.9) holds. ∎
Lemma 2.6**.**
For any sequence of functions in one has
[TABLE]
Proof.
It suffices to show that (2.10) holds if we replace the norm in the left hand side by any of the three norms used to define . It is clear that this is true for .
For different , we have
[TABLE]
Therefore RHS of (2.10).
Let where . The product rule of the differential operators implies
[TABLE]
where there are terms in the summation and at most of the are are not the identity operator. Therefore,
[TABLE]
which completes the proof.
∎
3. Variance
In this section we prove the finiteness of the variance in (1.7) and Theorem 1.4. All of them are contained in the following lemma.
Lemma 3.1**.**
Let the notation and the assumptions be as in Theorem 1.3. In particular and . For a real number , let be the function . Then
- (i)
* converges to a nonnegative real number, i.e., of (1.7) is well-defined and nonnegative.* 2. (ii)
[TABLE] 3. (iii)
* if and only if there exists such that for all *
[TABLE]
Proof.
(i) In view of Lemmas 2.3, there exists such that for all . Therefore, converges as . This proves that is well-defined.
To prove is nonnegative, we show that it is equal to
[TABLE]
which is obviously nonnegative. By the symmetry of and , the invariance of under , we have
[TABLE]
We make change of variables , then
[TABLE]
Since for , the value is uniformly bounded for all . So , and hence .
(ii) Suppose and . For every with , we apply (2.2) for , the function and , then we have
[TABLE]
We decompose the function on defined by
[TABLE]
into , where
[TABLE]
To calculate we make change of variables and apply Fubini’s theorem:
[TABLE]
On the other hand, by (2.2) with , and ,
[TABLE]
By (3.4), (3.5) and (3.6), we have
[TABLE]
We show that the left hand side of (3.7) is arbitrarily close to provided that is sufficiently large. Given , in view of (i), there exists such that
[TABLE]
For this fixed we have provided that is sufficiently large. Therefore (3.1) holds.
(iii) Suppose (3.2) holds for all . Recall that we have proved in (i) that
[TABLE]
By (3.2), for -a.e. . This together with (3.8) and imply .
Now we assume . We claim that
the -norm of is uniformly bounded for all .
Let and . Then the claim is equivalent to the -norm of is uniformly bounded for all .
Since is -invariant,
[TABLE]
[TABLE]
We solve from the above equation and plug it in (3.9), then
[TABLE]
Note that the function . So Lemma 2.3 implies
[TABLE]
which converges to zero as . So the absolute value of the first term of (3.10) is uniformly bounded for all . Similarly, we can uniformly bound the second term of (3.10) as
[TABLE]
Therefore, the -norm of is uniformly bounded for all and the proof of the claim is complete.
Note that the Hilbert space is self-dual. So the claim and the Alaoglu’s theorem imply that there exists a subsequence of natural numbers and such that in the weak∗ topology. We show that (3.2) holds for this . It is not hard to see that the function is a weak∗ limit of the sequence in . Therefore, in the weak∗ topology we have
[TABLE]
On the other hand, given any , by Lemma 2.3
[TABLE]
Therefore in the weak∗ topology. This observation together with (3.11) imply (3.2). ∎
4. Proof of the central limit theorem
Let the notation and the assumptions be as in Theorem 1.3. In particular, we fix a function and take . In this section the dependence of constants on and the probability measure will not be specified. By possibly replacing by we assume without loss of generality that . We assume that is not identically zero, since otherwise the conclusion holds trivially. Let and so that Theorem 2.2 and Lemma 2.5 hold.
We need to show that the random variables
[TABLE]
converges as to the normal distribution with mean zero and variance . Our main tool is the following so called the second limit theorem in the theory of probability.
Theorem 4.1** ([9]).**
If for every
[TABLE]
then as the distribution of random variables on converges to the normal distribution with mean zero and variance .
Note that (4.1) obviously holds for and . The case of is proved in Lemma 3.1(ii). So we assume in the rest of this section unless otherwise stated. We will estimate
[TABLE]
for each fixed . Write , , and
[TABLE]
By the symmetry of the variables of and the Fubini’s theorem,
[TABLE]
An ordered partition
[TABLE]
of determines positive integers and vice versa. We use to denote is an ordered partition of . Let be the cardinality of and let . Although and depend on , we will not specify it for simplicity. We fix a positive real number
[TABLE]
and set
[TABLE]
We will always assume
[TABLE]
so that for any . This will allow us to avoid ambiguity in the discussions below.
Lemma 4.2**.**
The set is a disjoint union of where is taken over all the ordered partitions of .
Proof.
Given , we show that there exists a such that . We find the blocks of from the top to the bottom. Let
[TABLE]
where we interpret if the set before taking the maximum is empty. This is . To find other we do the same calculation for the set . The process must terminates with in finite steps and it gives a partition such that . It is not hard to see from the construction that is uniquely determined by . So is a disjoint union of . ∎
In view of (4.2) and Lemma 4.2, we have
[TABLE]
Now we estimate for each fixed partition . We write according to the partition , i.e. . For and we let
[TABLE]
Let
[TABLE]
Let
[TABLE]
where . By slightly abuse of notation we write by identifying with for .
Lemma 4.3**.**
The volume of with respect to is at most .
Proof.
This is almost a trivial estimate by noting that if for some , then . ∎
Lemma 4.4**.**
One has
[TABLE]
Proof.
Since is a subset of , one has
[TABLE]
which gives the lower bound in (4.6).
To prove the upper bound we need more precise information about . Let
[TABLE]
We set , and . We claim that
[TABLE]
If , then and (4.7) holds. Suppose . If , then by definition . So there exists such that . In view of the definition of in (4.4), one has
[TABLE]
On the other hand, if (4.8) holds for some , then is nonempty and hence . The formula (4.7) follows from (4.8).
Now we prove the upper bound in (4.6). Note that the length of
[TABLE]
is at most . So
[TABLE]
∎
Corollary 4.5**.**
If , then
Proof.
Recall that we assume . So by Lemmas 4.3 and 4.4
[TABLE]
The conclusion follows from the above estimate and the assumption that .
∎
Now we estimate for using Theorem 2.2. By Lemma 2.5, for . So in view of the definition of in (4.4) and the assumption
[TABLE]
where in the last estimate we use . In (4.10), we interpret if there is no integer satisfying . By Lemma 2.6, the assumption and (4.10),
[TABLE]
where in the last estimate we use .
For , using Theorem 2.2 with the product of functions and , we have
[TABLE]
where we use and set . The definition of in (4.4) implies
[TABLE]
By (4.11), (4.12) and (4.13) we have for
[TABLE]
where in the last line we use in (4.3) and in (4.5).
Remark 4.6*.*
The estimate (4.14) also holds for provided that , which will be used later.
By (4.14) and the assumption we have
[TABLE]
Lemma 4.7**.**
Suppose and , then
Proof.
If , then the partition must contains a single number. Since , there exists such that . Therefore,
[TABLE]
This equality and (4.15) implies ∎
Now there are two cases left, namely,
[TABLE]
Lemma 4.8**.**
If is even, and is given by (4.17), then for
[TABLE]
Proof.
Let
[TABLE]
where . It can be checked directly from the definition that for every ,
[TABLE]
By Fubini’s theorem and (4.19)
[TABLE]
Similar to (4.15) and using Remark 4.6 we have
[TABLE]
On the other hand, similar to (4.9), we have
[TABLE]
By Lemma 4.3, (4.22) and the assumption
[TABLE]
[TABLE]
To sum up, by (4.23)
[TABLE]
∎
Lemma 4.9**.**
If is odd, and is given by (4.16), then
[TABLE]
Proof.
Recall that and . By (4.15)
[TABLE]
So (4.25) follows from the above estimate and the observation . ∎
Proof of Theorem 1.3.
By Theorem 4.1 it suffices to prove (4.1). As noted after Theorem 4.1 that (4.1) holds for and . For an odd integer , one has
[TABLE]
Then it follows from Corollary 4.5, Lemma 4.7 and Lemma 4.9 that (4.1) holds for odd . For an even integer , one has
[TABLE]
So it follows from Corollary 4.5, Lemma 4.7 and Lemma 4.8 that (4.1) holds for even . ∎
5. Regularity along stable and unstable leaves
Let be a lattice of a connected semisimple Lie group with finite center and be -diagonalizable. We assume in this section that the action of on is ergodic with respect to the probability Haar measure . In view of the Mautner’s phenomenon [2, Thm. III.1.4] and the Ratner’s measure classification theorem [22, Thm. 3], the ergodicity assumption is equivalent to is dense is .
A function on a metric space is said to be -Hölder if
[TABLE]
Here the upper bound of the distances between and is only needed in the case where is noncompact. Recall that we have fixed a right invariant metric on which induces a metric on . Any closed subgroup of is considered as a metric space with the metric inherited from that of .
Let be a closed subgroup of with Lie algebra . Recall from §2 that each defines a differential operator on . A function is said to be uniformly smooth along orbits of a subset if for any bounded open subset of , any and any basis of , there exists such that
[TABLE]
It is not hard to see that to show (5.1) holds for any it suffices to prove it for a fixed .
A useful tool to find a continuous function which is equal to a given measurable function is to assign the density value at every point of measurable continuity. Recall that a point is a point of measurable continuity of if there is such that is a Lebesgue density point of for every neighborhood of in . The value is called the density value of at . Let be the set of measurable continuity points of , and let be the map which sends to the density value of at .
Theorem 5.1**.**
Suppose is ergodic and is -Hölder. Let be a measurable solution to the cohomological equation
[TABLE]
Let be the map which sends to the density value of at . Then the followings hold:
- (i)
* is a -invariant full measure subset of and almost everywhere;* 2. (ii)
* is continuous on ;* 3. (iii)
The Hölder norms of functions on are uniformly bounded; 4. (iv)
If , then is uniformly smooth along and orbits of .
For every and we define the stable holonomy map by
[TABLE]
In the context of [1], is a map from the fiber of to the fiber of in the fiber bundle . We do not use the fiber bundle language but adopt the name holonomy map. Similarly, for , the unstable holonomy map is defined by
[TABLE]
Since is -Hölder, both of the holonomy maps are well-defined and continuous for .
A measurable function is said to be essentially invariant if there is a full measure subset such that for all with , one has
[TABLE]
We define essentially invariant in a similar way.
Lemma 5.2**.**
If is a measurable solution to the cohomological equation (5.2), then is essentially and invariant.
Proof.
By Lusin’s theorem, there is a compact subset of such that is uniformly continuous on and . Since is ergodic, there exists an -invariant full measure subset such that the Birkhoff average of the characteristic function of at any converges to . By assumption, there is an -invariant full measure subset of such that (5.2) holds for all . We will show that is essentially invariant by taking .
Suppose and . Since is -invariant, we have for all . Using (5.2) for all and , we have
[TABLE]
where the existence of infinite sum on the left hand of (5.6) follows form the Hölder property of . So converges. Since , there are infinitely many with and belong to . Since is uniformly continuous on and
[TABLE]
we know that . Therefore (5.5) holds. This proves that is essentially invariant. The proof of the essential invariance is similar. ∎
Lemma 5.3**.**
If is a measurable solution to the cohomological equation (5.2), then the set is -invariant and
[TABLE]
where .
Proof.
We show that is -invariant and (5.7) holds for . One can prove the invariance of and (5.7) for similarly. Since is generated by and , the invariance of is a direct corollary. The argument here is essentially the same as that in [1] but much simpler. We provide details here for the completeness.
By Lemma 5.2, the function is essentially invariant. So there exists a full measure subset such that (5.5) holds for all and where . Let and . Suppose is the density value of at . We will show that is the density value of at . Let be a neighborhood of . In view of the continuity of , there exist open neighborhoods and of and , respectively, such that
[TABLE]
As is a diffeomorphism preserving , both and are full measure subsets. Since , it is a Lebesgue density point of
[TABLE]
It follows that is a Lebesgue density point of
[TABLE]
We claim that . The claim will imply that is a point of measurable continuity of with density value .
To prove the claim let be an arbitrary point of . So and . Since , one has . On the other hand, since and , it follows from (5.8) that . So . This completes the proof of the claim and hence the lemma. ∎
Proof of Theorem 5.1.
(i) By [1, Lem. 7.10], the set has full measure with respect to and almost everywhere. It follows from Lemma 5.3 that is -invariant.
(ii) To simplify the notation, we set . In view of (5.5) and (5.7), the map on which sends to
[TABLE]
is continuous on . Similarly is continuous for .
In general, given , there exists and such that the map
[TABLE]
contains an open neighborhood of , see [6, §2.2]. Moreover, we can write for such that is an open map in a neighborhood of . Let
[TABLE]
be the map given by . For one has
[TABLE]
So is continuous on . Since is an open map in a neighborhood of , the map is continuous at . Therefore, is a continuous function on .
(iii) Next we prove the uniform boundedness of the Hölder norms. Recall that the metric on is induced from the right invariant metric on . So it suffices to prove that there is an open neighborhood of the identity in and such that for any and
[TABLE]
There is a map as in (5.10) such that the and the differential of at is surjective. Therefore, there is a submanifold passing through such that is a diffeomorphism onto its image. In particular, is a bi-Lipschitz map onto . So for all and we have
[TABLE]
So for and , by (5.9) and (5.13), we have
[TABLE]
The same estimate holds for . So for any and , by (5.11) and (5.14), we have
[TABLE]
from which (5.12) follows.
(iv) Let be a basis of the Lie algebra of consisting of eigenvectors of . We assume without loss of generality that all the eigenvalues of are positive. Suppose and where satisfies . We use to denote the differentiable operator on with respect to the variable Then
[TABLE]
whose sum over converges uniformly for in a fixed compact subset and . So by (5.9) and (5.15), for any and , we have
[TABLE]
Therefore is uniformly smooth along orbits of . By similar arguments one can prove that is uniformly smooth along orbits of .
∎
6. Livšic type theorem
Let the notation and assumptions be as in Theorem 1.1. In particular, the action of on has a spectral gap. This implies that the action of on where is the probability Haar measure is mixing. As a consequence, the dynamical system is ergodic, hence Theorem 5.1 holds.
Lemma 6.1**.**
Suppose is a measurable solution to the cohomological equation where . Then and .
Proof.
Since the dynamical system is ergodic, the measurable solution to the cohomological equation is unique up to constants. Therefore, it suffices to prove that it has a solution in , i.e., is cohomologous to [math] in . Since the action of on has a spectral gap, the dynamical system is exponential mixing of all orders by Lemma 2.4. Therefore, by [4, Thm. 1.1] the random variables
[TABLE]
converges as to the normal distribution with mean zero and variance
[TABLE]
We claim that the random variables converges to zero in distribution as . To see this, given , there is such that . Since the measure is -invariant, for any
[TABLE]
from which the claim follows. Therefore, the central limit theorem has to be degenerate and . It follows from [20, Thm. 2.11.3] that is cohomologous to [math] in . ∎
Recall that an element is identified with the a right invariant vector field on and it descents to a vector field on with the same notation .
Lemma 6.2**.**
Suppose and . Then
[TABLE]
Proof.
For any nonzero real number and we let
[TABLE]
The functions are uniformly bounded by the mean value theorem. So the dominated convergence theorem implies
[TABLE]
On the other hand, since preserves , we have for all . Therefore (6.2) holds. ∎
Lemma 6.2 allows us to define the distribution derivative of . For each , we define as a linear functional on such that
[TABLE]
In view of Lemma 6.2, this definition is consistent with the usual definition in the sense that the distribution derivative of a function is represented by the function . This property implies that our definition of distribution derivative is independent of the choice of coordinates and coincides with the definition using local charts. Let and be the Lie algebras of and , respectively. Let be the Lie algebra of . For a square integrable function on and , one can define the distribution derivative in a similar way. Moreover, this definition coincides with the definition using local charts.
Lemma 6.3**.**
Suppose and is an solution to the cohomological equation . Then for all and , one has
[TABLE]
Proof.
According to the definition and the assumption ,
[TABLE]
As the action of on is mixing and , we have
[TABLE]
On the other hand, by Lemma 2.3 the mixing is exponential for functions in . So by (6.3) and Lemma 6.2,
[TABLE]
∎
A vector field on is said to be tangent to orbits if its value at each point is tangent to the submanifold . The space of all such vector fields is denoted by . We fix a basis of consisting of eigenvectors of and let .
Lemma 6.4**.**
Suppose . Then there exists a family of smooth functions such that
[TABLE]
Proof.
Since the values of at any point form a basis of the tangent space of the point, the conclusion is clear for . We prove the general case by induction. Suppose the conclusion holds for and where . By the induction hypothesis
[TABLE]
where and are smooth functions on . Let be a test function. Then
[TABLE]
So the conclusion holds for . ∎
Proof of Theorm 1.1.
We have proved in Lemma 6.1. Next we show that is equal to a smooth function almost surely. By possibly replacing by , we assume that . In view of Theorem 5.1, we assume that is defined on the -invariant full measure subset so that the conclusions of Theorem 5.1 hold. We will show that and is smooth.
The question is local, so we fix . We choose open neighborhoods , and of the identity in , and , respectively, such that is diffeomorphic to its image via the map . Let be defined by We fix Haar measures on and so that a fundamental domain of has measure and
[TABLE]
Since , the function is square integrable.
Suppose and . Note that normalizes and . So by (5.7), (5.3) and (5.4)
[TABLE]
where
[TABLE]
For , let be the differential operator with respect to the variable . Then
[TABLE]
whose sum over negative integers converges uniformly with respect to and . Similar statement holds for . Therefore, (6.6) converges uniformly on and
[TABLE]
The uniform convergence of (6.6) implies that is continuous on . In view of (6.5), if is equal to a continuous function almost everywhere, then is equal to a continuous function almost everywhere. This implies that and is continuous on . It follows from (6.5), (6.6), (6.7) and (6.8) that if is smooth on , then for any we have exists for all and these values are uniformly bounded on . On the other hand, by Theorem 5.1(iv), the function is uniformly smooth along and orbits of . Therefore, if is equal to a smooth function almost everywhere, then is defined everywhere on and all the partial derivatives of along foliations are uniformly bounded on . So a theorem of Journé [12] implies that is smooth on .
Therefore, it suffices to show that is equals to a smooth function almost everywhere. Let be the dimension of . We assume that there is a coordinate map where is an open ball in . Moreover, we assume there is a smooth function that is bounded from above and below by some positive constants so that is mapped by to the Lebesgue measure on . For a compactly supported smooth function , we consider the Fourier transform of defined by
[TABLE]
which is a continuous function on . We claim that for any positive integer and , we have
[TABLE]
Assume the claim, then it follows from the Fourier inversion formula that equals to a smooth function almost everywhere, see for example Folland [8, Thm. 8.22.d, 8.26]. By choosing with arbitrarily large support, we have is equal to a smooth function almost everywhere.
Now we prove the claim. We will use the usual multiple index notation for the partial derivatives on (see [8, §8.1]). For example, if is a multiple index, then
[TABLE]
We have
[TABLE]
where refers to the distribution derivative. By the product rule
[TABLE]
where the sum is taken over all the multiple indices such that has nonnegative entries and each appears times. Since is a compactly supported function on , there are differential operators and such that
[TABLE]
where .
[TABLE]
By Lemma 6.4, for each one has
[TABLE]
where are smooth functions. In view of (6.13) and (6.14)
[TABLE]
where are compactly supported smooth functions on .
Now we lift all the to compactly supported smooth functions on . Let be a compactly supported smooth function such that
[TABLE]
Each function is lifted to as follows:
[TABLE]
By (6.4), (6.5) and the Fubini’s theorem we have
[TABLE]
where
[TABLE]
By (6.8) and the uniform convergence of (6.6), the function is smooth on and for any
[TABLE]
For any , by (6.16) and (6.17), we have
[TABLE]
Write , then by (6.18)
[TABLE]
By Lemma 6.3,
[TABLE]
By Lemma 2.3,
[TABLE]
[TABLE]
On the other hand,
[TABLE]
By (6.19), (6.22) and (6.23), we have
[TABLE]
Using (6.24) to estimate each term of the right hand side of (6.15), we get
[TABLE]
For any positive integer , we sum the left hand side of (6.25) for all where is the standard basis of , then
[TABLE]
from which the claim (6.9) follows.
∎
Proof of Theorem 1.6.
Suppose the variance is zero, then Theorem 1.4 implies that there is a measurable solution to the system of cohomological equations (1.8). Note that belongs to and is a measurable solution to the cohomological equation . By assumption, the projection of to each simple factor of is nontrivial, so the action of on has a spectral gap. Theorem 1.1 implies that there is a smooth function on such that almost everywhere. This means that there is a continuous function such that (1.8) holds for all and .
To prove is dynamically null with respect to , it suffices to show that for any -invariant and ergodic probability measure on the integral . By Birkhoff ergodic theorem and Poincaré recurrence theorem, there is such that is in the closure of for any and
[TABLE]
The above two properties together with the continuity of imply . ∎
The reference list from the paper itself. Each links out to its DOI / PubMed record.
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