The Krzy\.z Conjecture and an Entropy Conjecture
Jim Agler, John E. McCarthy

TL;DR
This paper links the Krzyz conjecture to an entropy minimization problem for polynomials with roots on the unit circle, proposing that certain entropy conditions imply the conjecture's validity.
Contribution
It establishes a conditional connection between entropy minimization and the Krzyz conjecture, offering a new approach to its proof under generic hypotheses.
Findings
Entropy minimization for polynomials with roots on the unit circle relates to the Krzyz conjecture.
Conditional proof of the Krzyz conjecture based on entropy and extremum hypotheses.
Provides a new perspective linking polynomial root distributions to complex analysis conjectures.
Abstract
We show that if the minimum entropy for a polynomial with roots on the unit circle is attained by polynomials with equally spaced roots, then, under a generic hypothesis about the nature of the extremum, the Krzyz conjecture on the maximum modulus of the Taylor coefficients of a holomorphic function that maps the disk to the punctured disk is true.
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The Krzyż Conjecture and an Entropy Conjecture
Jim Agler Partially supported by National Science Foundation Grant DMS 1665260
John E. McCarthy Partially supported by National Science Foundation Grant DMS 1565243
Abstract: We show that if the minimum entropy for a polynomial with roots on the unit circle is attained by polynomials with equally spaced roots, then, under a generic hypothesis about the nature of the extremum, the Krzyz conjecture on the maximum modulus of the Taylor coefficients of a holomorphic function that maps the disk to the punctured disk is true.
1 Introduction
Let denote the set of holomorphic functions that map the unit disk to . The Krzyż conjecture, due to J. Krzyż [krz68], is the following conjecture about the size of Taylor coefficients of functions in .
Conjecture 1.1**.**
Let be a positive integer. Then
[TABLE]
Moreover, equality is obtained in (1.2) only for functions of the form
[TABLE]
where and are unimodular constants.
For any function defined and holomorphic on a neighborhood of the origin, we use to denote the Taylor coefficient at [math], so
[TABLE]
For a history of the Krzyż conjecture and a summary of known results, see Section 2.
The purpose of this note is to establish a connection between the Krzyż conjecture and the following conjecture about the entropy of polynomials with roots on the unit circle .
Conjecture 1.4**.**
Let be a non-constant polynomial, all of whose roots lie on , and normalized so that . Then
[TABLE]
Moreover, equality occurs in (1.5) only for polynomials of the form
[TABLE]
where and are unimodular constants, and is a positive integer.
We shall let denote the Herglotz class, the holomorphic functions on the unit disk that have non-negative real part. A function is in if and only if there is a function so that
[TABLE]
Given an -tuple of complex numbers, we shall say that is solvable Herglotz data if there exists satisfying
[TABLE]
We shall say that is extremal Herglotz data if it is solvable but for any , the data is not solvable.
We shall say that is -extremal if is in and . It was proved in [hsz] that if is -extremal, and , then the first Taylor coefficients of are extremal Herglotz data (we give a proof of this in Lemma 3.3). By a theorem of G. Pick [pi16], this means must have the form
[TABLE]
where , the number satisfies , each , and each is a distinct point on . We shall let denote the set of rational functions that have the form (1.7) (that is, rational functions of degree that are -fold covers of the right-half plane by the unit disk), and we shall let .
Our first main result analyzes the critical points for the Krzyż functional. We prove in Theorem 5.1 that if is in (and is normalized in a way described in Section 6), then is a critical point for with critical value if and only if
[TABLE]
where is a polynomial of degree of unit norm in the kernel of , where is the compression of the unilateral shift to polynomials of degree less than or equal to , and the notation means that the functions have the same Taylor coefficients up to degree .
We use this result to prove that if the extremals for the Krzyż problem have of full degree, then the entropy conjecture implies the Krzyż conjecture.
Theorem 1.8**.**
Let be -extremal, and assume that is in . If Conjecture 1.4 is true, then has the form (1.3).
We prove Theorem 1.8 in Section 7. In Section 8 we study critical points of the entropy functional from (1.5). In Section 9, we prove a special case of Conjecture 1.4. Finally, in Section 10, we show how Conjecture 1.4 would follow from Conjecture 2.2, due to A. Baernstein II.
2 History of the Krzyż conjecture
J. Krzyż proved Conjecture 1.1 for , and conjectured it for all . The case was proved by J. Hummel, S. Scheinberg and L. Zalcman [hsz]; they also proved Lemma 3.3 below, and that (1.3) is a strict local minimum for (1.2) (after normalizing so that and are both positive). The case was proved first by D. Tan [ta83], and later by a different method by J. Brown [br87]. The case was proved by N. Samaris [sam03].
C. Horowitz [hor78] proved that there is some constant such that for all ; his proof showed . This was improved by R. Ermers to [erm90].
In [msuv15], M. Martin, E. Sawyer, I. Uriarte-Tuero, and D. Vukotić prove that 16 different conditions are all equivalent to the Krzyż conjecture. The paper also includes a useful historical summary.
Conjecture 1.4 may be compared with the following sharp inequality, conjectured by I. Hirschman [hi57] and proved by W. Beckner [be75]:
If has norm , and denotes the Fourier transform of , then
[TABLE]
Equality is obtained in (2.1) for Gaussians.
A. Baernstein II made the following conjecture in 2008 [ba08], where the quasi-norms are with respect to normalized Lebesgue measure on the circle. By we mean .
Conjecture 2.2**.**
Let . Then for all , and for all non-constant polynomials with all their roots on the unit circle,
[TABLE]
In Section 10 we show how Baernstein’s conjecture implies the entropy conjecture.
3 Preliminaries
Suppose and are analytic functions on a neighborhood of [math], and . Say
[TABLE]
if for . We leave the proof of the following lemma to the reader.
Lemma 3.1**.**
Suppose and are analytic on a neighborhood of zero. Assume that , and is analytic in a neighborhood of . If , then .
The following result is due to G. Pick [pi16], and can be found in any book on Pick interpolation such as [bgr90, foi-fra, ampi].
Lemma 3.2**.**
If is extremal Herglotz data, then there exists a unique function such that for . Moreover, . Conversely, if , then is extremal Herglotz data.
Lemma 3.3**.**
Fix and assume that is -extremal. Define by . Then .
Proof: We know that must be in , so by Lemma 3.2, if is not in , then for some we have a function such that
[TABLE]
Then is in , and by Lemma 3.1, , so
[TABLE]
This contradicts the claim that is extremal.
Corollary 3.4**.**
[TABLE]
Given that , Corollary 3.4 suggests the following optimization problem. For each , define
[TABLE]
Remark 3.5**.**
As is a dense open set in , we have . However, whereas a normal families argument guarantees that an extremal function for always exists, it is not obvious that an extremal for exists. If Krzyż’s conjecture is true, then the supremum is attained. **
4 The critical points of
4.1 The definition of critical points
For the rest of the paper, will be a positive integer. There are a number of equivalent ways to view as a topological vector space.
Using the parameters of (1.7) (where ). 2. 2.
As the subset of the space of extremal Herglotz data points with the property that is not extremal. 3. 3.
With the topology of uniform convergence on compact subsets of .
We would like to consider the local maxima of the function defined by
[TABLE]
Let denote the set of complex polynomials of degree less than or equal to , and the polynomials of degree exactly .
Definition 4.2**.**
Let . We say is an admissible direction at if and there exists such that
[TABLE]
is solvable Herglotz data for all in . We say that is a critical point for if
[TABLE]
whenever is an admissible direction at . If is a critical point for , then we refer to as the critical value. **
4.2 A Hilbert space setting for the analysis of critical points
Let denote the classical Hardy space on the unit disk. We shall think of as a subspace of , and let be the orthogonal projection from onto . Define an operator on by the formula
[TABLE]
The operator is the truncated shift, and is nilpotent of order . Hence if is any holomorphic function on a neighborhood of [math], we can define by the Riesz functional calculus, or by either of the two equivalent formulas
[TABLE]
Observe that if and are both holomorphic on a neighborhood of [math], then
[TABLE]
The following two propositions are basically a reformulation of Lemma 3.2 to the Hilbert space interpretation of interpolation.
Proposition 4.4**.**
Let be an -tuple of complex numbers. Then is solvable Herglotz data if and only if
[TABLE]
Moreover is extremal Herglotz data if and only if is positive semi-definite but not positive definite.
Proposition 4.5**.**
Assume .
** 2. 2.
The function is in if and only if is singular. 3. 3.
If , then if and only if .
4.3 Local maxima are critical points
We need to show that there is enough smoothness at local maxima to make sense of (4.3), at least when the local maximum is in .
Proposition 4.6**.**
Let be defined by (4.1). If is a local maximum for , then is a critical point for .
Proof: Let be an admissible direction for . Thus by Proposition 4.4 there exists so that
[TABLE]
Let denote the smallest eigenvalue of , so for each we have is positive semidefinite and singular. By Proposition 4.4, for every there exists such that
[TABLE]
Since is a local maximum, we have as , and . As is open in , this means for some , we have for all in . As is a local maximum for , we have
[TABLE]
As
[TABLE]
it is differentiable with respect to , and as
[TABLE]
this derivative is nonpositive at [math].
4.4 Some lemmas about critical points
We shall let denote the -norm, so
[TABLE]
We shall let be fixed, and write for for legibility.
Lemma 4.7**.**
If , then there exists a unique vector in such that , and . Furthermore, if
[TABLE]
then
[TABLE]
where
[TABLE]
Proof: By Proposition 4.5, . Hence there exists some nonzero vector in . We will show that for each , and then define
[TABLE]
As
[TABLE]
we have
[TABLE]
Since each , we can only have if for each we have
[TABLE]
As
[TABLE]
we get
[TABLE]
Therefore implies that vanishes at each , as claimed.
Lemma 4.8**.**
Let and let be the vector described in Lemma 4.7. For , the following hold:
If is an admissible direction at , then . 2. 2.
If , then is an admissible direction at if and only if . 3. 3.
If , then is an admissible direction for every .
Proof: 1. Since for small and positive, we must have
[TABLE]
- If , then
[TABLE]
The right-hand side is non-negative for all and small positive if and only if .
- If , then
[TABLE]
By Cauchy-Schwarz, for any fixed , the right-hand side is non-negative for positive and sufficiently small.
Lemma 4.9**.**
Let and let be the vector described in Lemma 4.7. If is a critical point for and satisfies , then
[TABLE]
Proof: By Lemma 4.8, for all we have is admissible, so by Proposition 4.6 we have
[TABLE]
Now let .
Lemma 4.10**.**
If is analytic on a neighborhood of [math] and , then
[TABLE]
Proof: Computation.
5 The Critical Point Equation
We fix , and write for . For , define by
[TABLE]
So if , then . We shall say is self-inversive if .
Theorem 5.1**.**
Let and let be the vector described in Lemma 4.7. Then is a critical point of with critical value if and only if
[TABLE]
Proof: Suppose is a critical point of with critical value . If and , then by Lemma 4.9,
[TABLE]
Hence if , so for all , we get by Lemma 4.10
[TABLE]
As this holds for all , we get that
[TABLE]
Equivalently,
[TABLE]
By duality (in the finite dimensional space ), this means there exists so that
[TABLE]
Letting in (5.4), we get . So for , (5.4) gives
[TABLE]
Therefore , as desired.
Conversely, suppose (5.2) holds. Reversing the logic, we get that (5.3) holds. This means that on the -dimensional subspace of given by
[TABLE]
we have
[TABLE]
The orthocomplement of the subspace (5.5) is spanned by the function . An arbitrary polynomial in can be written as , where is in (5.5) and . By Lemma 4.8, this is an admissible direction if and only if . By Lemma 4.10, and using (5.2),
[TABLE]
and this is less than or equal to [math] whenever . This means is a critical point. Finally,
[TABLE]
6 Normalization
If is as in (1.7) and is a local maximum for , then is also a local maximum for any unimodular and real . We can choose and so that and .
Definition 6.1**.**
If , we say that is normalized if has the form
[TABLE]
where .
Lemma 6.3**.**
Let be a local maximum for with critical value and let be as in Lemma 4.7. Assume is chosen in the range . Then is normalized if and only if and is self-inversive.
Proof: We have
[TABLE]
So by Lemma 4.7, if and only if . From (1.7), we have
[TABLE]
and from Theorem 5.1, we have
[TABLE]
So if , then is positive if and only if is a multiple of .
Proposition 6.4**.**
If is a normalized local maximum for with critical value then
[TABLE]
Proof: Since is normalized, we have
[TABLE]
So from Theorem 5.1, we have
[TABLE]
Then (6.5) follows from Lemma 3.1.
Proposition 6.6**.**
If is a normalized local maximum for with critical value then
[TABLE]
For ,
[TABLE]
Proof: Expand both sides of (6.5) into power series and equate coefficients. From (6.2),
[TABLE]
We have
[TABLE]
Comparing these we get the result.
7 The proof of Theorem 1.8
Let us assume that the Entropy Conjecture 1.4 holds, and that is a normalized local maximum for with critical value . Let be as in Lemma 4.7.
By Proposition 4.6, is a critical point for , and by Theorem 5.1 and Proposition 6.4, the -by- Toeplitz matrix is the same as the Toeplitz matrix on whose entries come from the Fourier series of . In particular, for any polynomials , we have
[TABLE]
Let , and observe that the left-hand side of (7.1) vanishes, so
[TABLE]
If Conjecture 1.4 holds, then
[TABLE]
and so .
8 Entropy Conjecture
Let us establish some notation. We shall fix a positive integer. All integrals are integrals over the unit circle with respect to normalized Lebesgue measure, and norms and inner products are in with respect to this measure.
If is self-inversive, then all its zeroes either occur on , the unit circle, or occur in pairs , or occur at the origin if . We shall let denote the set of polynomials in that are self-inversive and have all their zeroes on , and denote the unit sphere of , viz. the polynomials of norm in .
We shall let be the orthogonal projection from onto , i.e.
[TABLE]
If are in , we shall write to mean , i.e.
[TABLE]
Note that if , then
[TABLE]
in particular if and are both self-inversive, then their inner product is real.
If , then denotes the polynomial
[TABLE]
In terms of Fourier coefficients,
[TABLE]
Lemma 8.1**.**
If is in , then so is .
Proof: A calculation shows that for self-inversive
[TABLE]
So has zeroes at the local maxima of on ; these interleave the zeroes of . If has a zero of order at some point on , then (8.2) vanishes to order at , so has a zero of order . Counting them all up, we get that has zeroes on , and since it is of degree , it must be in .
Observe that for all self-inversive in .
Let
[TABLE]
If is norm one and , then minimizing over all , one gets that
[TABLE]
with equality when . The entropy conjecture 1.4 is equivalent to the conjecture that the minimum of over all (not just those of norm one) is , and that, up to the normalization of requiring that and are positive, this value is attained uniquely by the polynomial
[TABLE]
For any function in , we shall let \big{[}f\big{]} denote the -by- Toeplitz matrix with entry . We shall think of this as acting on . If , then
[TABLE]
Theorem 8.5**.**
Suppose is a local minimum for on , and that all the zeroes of are distinct. Then
[TABLE]
[TABLE]
Proof: Since all the zeroes of are distinct, it is any self-inversive polynomial in , then for small and real, is self-inversive, and the zeroes must be close to the zeroes of , so they must all lie on the circle. Therefore if we expand in powers of , the first order term must vanish, since is a critical point, and the coefficient of must be non-negative, since is a local minimum.
Calculating, using the fact that if is self-inversive, then on the unit circle , and writing
[TABLE]
we get,
[TABLE]
Since at a critical point the coefficient of must vanish for all , we get \big{[}\log|\gamma|^{2}\big{]}\gamma+\gamma=0, giving (8.6). The non-negativity of the coefficient of gives (8.7).
At a critical point, \big{[}\log|\gamma|^{2}\big{]} will have one eigenvalue equal to , so the inequality in (8.7) cannot be strict.
Proposition 8.8**.**
Suppose is in and
[TABLE]
Then
[TABLE]
Proof: Equation (8.9) can be written as
[TABLE]
Differentiate both sides with respect to . Writing for the derivative with respect to , then (8.11) becomes
[TABLE]
So
[TABLE]
Therefore
[TABLE]
This yields (8.10).
It is plausible that the only polynomial satisfying (8.6) and (8.7) and with positive and coefficients is (8.4), but we cannot resolve whether this is true.
9 A special case of the Entropy Conjecture
Self-inversive polynomials in can be written as
[TABLE]
where is a polynomial in , with . Specifically, if is odd, then is an arbitrary polynomial in , and defined by
[TABLE]
if is even, then is a polynomial in whose coefficient is real (and half of the coefficient for ).
Theorem 9.2**.**
Let be a self-inversive non-constant polynomial of degree , and write as in (9.1). If has no zeroes in the closed unit disk, then Inequality 1.5 holds, with strict inequality unless is given by (1.6).
Proof: Let us decompose the integral into two pieces, + :
[TABLE]
To estimate , the first term on the right-hand side of (9.3), write
[TABLE]
Note that
[TABLE]
since . So if we apply Jensen’s inequality to the convex function and the probability measure , we get
[TABLE]
This gives
[TABLE]
Therefore we have .
To estimate , first assume that is odd. Note that by the maximum principle, has modulus less than one in the unit disk, so is analytic on the unit disk and has only logarithmic singularities on the unit circle, and therefore its Fourier series agrees with its Maclaurin series. Therefore
[TABLE]
so
[TABLE]
Now assume is even. Write
[TABLE]
so
[TABLE]
When expanding we get
[TABLE]
Therefore
[TABLE]
Therefore
[TABLE]
as required.
Finally, note that the inequality for using Jensen’s inequality is strict unless is constant.
Note that a simple continuity argument applied to shows that (1.5) holds provided has no zeroes in the open unit disk.
10 Baernstein’s conjecture implies the entropy conjecture
Assume Baernstein’s conjecture 2.2 holds. Let and be any non-constant polynomial with all its roots on the unit circle, and with . Let , and let be the conjugate exponent. Then, taking logarithms of 2.3 we have
[TABLE]
This means
[TABLE]
Let denote the left-hand side of (10.1). We have that for , and . Therefore . Calculating, we get
[TABLE]
Since both and have -norm , we get that
[TABLE]
Since , we get
[TABLE]
which is (1.5).
References
