In absence of long chordless cycles, large tree-width becomes a local phenomenon
Daniel Wei{\ss}auer

TL;DR
This paper proves that graphs with sufficiently large tree-width necessarily contain either large bipartite subgraphs or long chordless cycles, revealing a local-global structural property.
Contribution
It establishes a new relationship between large tree-width and the presence of specific subgraphs, specifically long chordless cycles or complete bipartite graphs.
Findings
Graphs with large tree-width contain long chordless cycles or large bipartite subgraphs.
The result links global tree-width to local subgraph structures.
Provides a structural characterization relevant for graph theory and algorithms.
Abstract
We prove that, for all and , every graph of sufficiently large tree-width contains either a complete bipartite graph or a chordless cycle of length greater than .
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In absence of long chordless cycles, large tree-width becomes a local phenomenon
Daniel Weißauer
Abstract
We prove that, for all and , every graph of sufficiently large tree-width contains either a complete bipartite graph or a chordless cycle of length greater than .
1 Introduction
In an effort to make the statement in the title precise, let us call a graph parameter global if there is a constant such that for all and there exists a graph for which every subgraph of order at most satisfies , while . The intention here is that being small, even bounded by a constant, on subgraphs of bounded order does not provide a bound on .
Tree-width is a global parameter (we may take ), as is the chromatic number (with ). Indeed, it is a classic result of Erdős [6] that for all and there exists a graph of chromatic number for which every subgraph on at most vertices is a forest.
It is well-known (see [4]) that the situation changes when we restrict ourselves to chordal graphs, graphs without chordless cycles of length :
[TABLE]
Hence the only obstruction for a chordal graph to have small tree-width is the presence of a large clique. Since the chromatic number of a graph is at most its tree-width plus one ([4]), the same is true for the chromatic number. In particular, tree-width and chromatic number are local parameters for the class of chordal graphs.
In 1985, Gyárfás [8] made a famous conjecture which implies that chromatic number is a local parameter111Indeed, in terms of our earlier definition, (2) implies that given any integer , there exists a such that every -chordal graph of chromatic number has a subgraph of order and chromatic number . for the larger class of -chordal graphs, those which have no chordless cycle of length :
[TABLE]
This conjecture remained unresolved for 30 years and was proved only recently by Chudnovsky, Scott and Seymour [3]. In view of (1), it is tempting to think that an analogue of (2) might hold with tree-width in place of chromatic number. Complete bipartite graphs, however, are examples of triangle-free 4-chordal graphs of large tree-width. Therefore a verbatim analogue of (2) is not possible and any graph whose presence we can hope to force by assuming -chordality and large tree-width will be bipartite.
On the positive side, Bodlaender and Thilikos [2] showed that every star can be forced as a subgraph in -chordal graphs by assuming large tree-width (see Section 3). However, since stars have tree-width 1, this does not establish locality of tree-width in the sense of our earlier definition. Our main result is that in fact any bipartite graph can be forced as a subgraph:
Theorem 1**.**
Let be an integer and a graph. Then is bipartite if and only if there exists an integer such that every -chordal graph of tree-width contains as a subgraph.
This shows that tree-width is local for -chordal graphs: Given any integer , there exists an integer such that every -chordal graph of tree-width has a subgraph isomorphic to , which has order and tree-width .
Theorem 1 also has an immediate application to an Erdős-Pósa type problem. Kim and Kwon [9] showed that chordless cycles of length have the Erdős-Pósa property:
Theorem 2** ([9]).**
For every integer there exists an integer such that every graph either contains vertex-disjoint chordless cycles of length or a set of at most vertices such that is chordal.
They also constructed, for every integer , a family of graphs showing that the analogue of Theorem 2 for chordless cycles of length fails. We complement their negative result by proving that the Erdős-Pósa property does hold when restricting the host graphs to graphs not containing as a subgraph.
Corollary 3**.**
For all and there exists an integer such that every -free graph either contains vertex-disjoint chordless cycles of length or a set of at most vertices such that is -chordal.
The paper is organised as follows. Section 2 contains some basic definitions. Theorem 1, our main result, is proved in Section 3. In Section 4 we formally introduce the Erdős-Pósa property, restate Corollary 3 in that language and give a proof thereof. Section 5 closes with some open problems.
2 Notation and definitions
All graphs considered here are finite and undirected and contain neither loops nor parallel edges. Our notation and terminology mostly follow that of [4].
For two graphs and , we say that is -free if does not contain a subgraph isomorphic to . Given a tree and , we write for the unique --path in . Given a graph and a set of vertices of , a path is an -path if it contains at least one edge and meets precisely in its endvertices. A separation of is a tuple with such that there are no edges between and . The order of is the number of vertices in . We call the separation tight if for all , both and contain an --path with no internal vertices in .
Given an integer , a set of at least vertices of is a -block if it is inclusion-maximal with the property that for every separation of order , either or . By Menger’s Theorem, then contains internally disjoint paths between any two non-adjacent vertices in .
A tree-decomposition of is a pair , where is a tree and a family of sets of vertices of such that for every , the set of with induces a non-empty subtree of and for every edge there is a with . If is a tree-decomposition of , then every induces a separation of , where is the union of for all for which . Note that . We call tight if every separation induced by an edge of is tight.
Given , the torso at is the graph obtained from by adding, for every neighbor of , an edge between any two non-adjacent vertices in .
Given graphs and , a subdivision of in consists of an injective map and a map which assigns to every edge an --path so that the paths are internally disjoint and no has an internal vertex in . The vertices in are called branchvertices. For an integer , the subdivision is a -subdivision if every path has length at most . When is a complete graph, the map is irrelevant and we only keep track of the set of branchvertices and the family .
3 Proof of Theorem 1
As observed in the introduction, the complete bipartite graphs show that no bound on the tree-width of -free -chordal graphs exists if is not bipartite. We now prove that being bipartite is sufficient. Since every bipartite graph is a subgraph of some , it suffices to prove Theorem 1 for the case .
Our proof is a cascade with three steps. First, we show that sufficiently large tree-width forces the presence of a -block.
Lemma 4**.**
Let and be positive integers. Then every -chordal graph of tree-width contains a -block.
We then prove that the existence of a -block yields a bounded-length subdivision of a complete graph.
Lemma 5**.**
Let and be positive integers. Then every -chordal graph that contains a -block contains a -subdivision of .
In the last step, we show that such a bounded-length subdivision gives rise to a copy of .
Lemma 6**.**
For all integers and there exists a such that the following holds. Let be positive integers with . Then every -chordal graph that contains a -subdivision of contains as a subgraph.
It is immediate that Theorem 1 follows once we have established these three lemmas.
3.1 Proof of Lemma 4
A trivial obstacle to our search for a copy of is the absence of vertices of high degree. Bodlaender and Thilikos [2] showed, however, that -chordal graphs of bounded degree have bounded tree-width. Their exponential bound was later improved by Kosowski, Li, Nisse and Suchan [10] and by Seymour [17].
Theorem 7** ([17]).**
Let and be positive integers and a graph. If is -chordal and has no vertices of degree greater than , then the tree-width of is at most .
By demanding large tree-width, we can therefore guarantee a large number of vertices of high degree. We now show that these are not all just scattered about the graph. It was shown by the author in [19] that either there is a -block or there is a tree-decomposition which separates the set of vertices of high degree into small pieces. This also follows, without explicit bounds, from a far more general result of Dvořák [5].
Theorem 8** ([19]).**
Let be a positive integer and a graph. If has no -block, then there is a tight tree-decomposition of such that every torso has fewer than vertices of degree at least .
In fact, tightness of the tree-decomposition is not explicit in [19, Theorem 1], but is established in the proof as Lemma 6.
Now let and be positive integers. Let be an -chordal graph with no -block. For , this means that is acyclic and therefore has tree-width 1. Suppose from now on that . We show that the tree-width of is less than .
By Theorem 8, there is a tight tree-decomposition of such that every torso has fewer than vertices of degree at least . Let arbitrary, let be the set of neighbors of in and let be the torso at . We claim that is -chordal.
Let be a chordless cycle. For every edge , there is some with . Since is tight, there exists an --path in which meets only in its endpoints. Observe that for every , contains at most two vertices of and these are adjacent in . Hence we can replace every edge by and obtain a chordless cycle of with . Since is -chordal, it follows that . This proves our claim.
Now, let be the set of all vertices of degree in . Then is -chordal and has no vertices of degree . By Theorem 7, the tree-width of is at most . Therefore
[TABLE]
We have shown that every torso has tree-width . We can then take a tree-decomposition of width of each torso and combine all these to a tree-decomposition of width of . ∎
3.2 Proof of Lemma 5
In general, the presence of a -block does not guarantee the existence of any subdivision of for . For example, take a rectangular -grid, add new vertices to the outer face and make each of these adjacent to consecutive vertices on the perimeter of the grid (see Figure 1). These new vertices are then a -block in the resulting planar graph.
Our aim in this section is to show that for -chordal graphs, sufficiently large blocks do indeed yield bounded-length subdivisions of complete graphs.
Let and be positive integers. Let be an -chordal graph and a -block of . Let . Assume for a contradiction that contained no -subdivision of . Let non-adjacent. Then contains a set of internally disjoint --paths. Taking subpaths, if necessary, we may assume that each path in is induced. Let .
Claim: Fewer than paths in have length .
Proof of Claim.
Let be the set of all paths in of length and . Assume for a contradiction that . Let . Then is a cycle of length . Since is -chordal, has a chord. This chord must join an internal vertex of to an internal vertex of . Choose such vertices and so that the cycle has minimum length. Note that is an induced cycle and therefore has length at most . In particular, the segment of joining to has length at most and similarly for and .
For , let be a minimal subpath of containing every vertex , . Then is a family of disjoint paths, each of length at most , and contains an edge between any two of them. Fix an arbitrary with . Since , every contains a vertex which has neighbors on at least different paths in .
Let . We iteratively construct a -subdivision of with branchvertices in . Let and enumerate the pairs of vertices of arbitrarily as . In the -th step, we assume that we have constructed a family of internally disjoint -paths of length at most , so that joins the vertices of and meets at most two paths in . We now find a suitable path .
Let with . At most paths in meet any of the paths in . Since is adjacent to vertices on at least different paths in , there is a which is disjoint from every , , and contains a neighbor of . We similarly find a path for . Since either or has an edge between and , induces a connected subgraph of and therefore contains a --path of length at most , which meets only two paths in .
Proceeding like this, we find the desired subdivision of after steps. This contradiction finishes the proof of the claim. ∎
Let with . For any two non-adjacent , let be the set of all of length at most which have no internal vertices in . By the claim above, we have
[TABLE]
Pick one path for each pair of non-adjacent vertices in turn, disjoint from all previously chosen paths. Since and each path only has at most internal vertices which future paths need to avoid, we can always find a suitable such path . Together with all edges between adjacent vertices of , this yields a -subdivision of in with branchvertices in . ∎
We would like to point out that a modification of the above argument can be used to produce a -subdivision of if is significantly larger.
Indeed, suppose we find a family of disjoint paths, each of length at most , such that contains an edge between any two of them. Then the subgraph induced by has at most vertices and at least edges. One can then use a classic result of Kövari, Sós and Turán [11] to show that contains a copy of if is sufficiently large. Since contains a -subdivision of , this establishes an upper bound on the number of paths of length in any . The rest of the proof remains the same.
3.3 Proof of Lemma 6
The combination of Lemma 4 and Lemma 5 already establishes that tree-width is a local parameter for -chordal graphs. The purpose of Lemma 6 is merely to narrow the set of bounded-order obstructions down as far as possible. We will use the following theorem of Kühn and Osthus [13].
Theorem 9** ([13]).**
For every integer and every graph there exists a so that every graph with average degree at least either contains as a subgraph or contains an induced subdivision of .
In fact, we only need the special case . This special case has a simpler proof which can be found in Kühn’s PhD-thesis [12]. Fix an integer so that every -chordal graph of average degree at least contains as a subgraph. We prove the assertion of Lemma 6 with .
Let be positive integers with and let be an -chordal graph containing a )-subdivision of . Let be the set of branchvertices and the family of paths of the subdivision. Taking subpaths, if necessary, we may assume that every path is induced.
Assume for a contradiction that contained no copy of . By Theorem 9, every subgraph of contains a vertex of degree . In particular, there is an independent set with . Let be the subgraph of induced by . Note that .
Call an edge of red if it joins a vertex to an internal vertex of a path with . Call an edge of blue if it joins an internal vertex of a path to an internal vertex of a path with . We will show that must contain many edges which are either red or blue, so that the average degree of is at least .
Fix an arbitrary cycle with . For any with , obtain the cycle with by contracting every -path of to a single edge. We then get a cycle by replacing every edge with the path . Since each path has length at least 2 and is -chordal, the cycle must have a chord. Since is independent and every path is induced, the chord must be a red or blue edge of .
Consider a red edge with , and . If this edge is a chord for a cycle , then . Hence it can only occur as a chord for at most
[TABLE]
choices of . Similarly, every blue edge with , and can only be a chord of if . This also happens for at most
[TABLE]
choices of . Let be the number of edges of which are either red or blue. Since every with gives rise to a chord, it follows that
[TABLE]
This shows that the average degree of is
[TABLE]
By Theorem 9, contains a copy of . ∎
4 Erdős-Pósa for long chordless cycles
A classic theorem of Erdős and Pósa [7] asserts that for every integer there is an integer such that every graph either contains disjoint cycles or a set of at most vertices meeting every cycle. This result has been the starting point for an extensive line of research, see the survey by Raymond and Thilikos [15].
Let be classes of graphs and a containment relation between graphs. We say that has the Erdős-Pósa property for with respect to if there exists a function such that for every and every integer , either there are disjoint such that for every there is an with , or there is a with such that for every . When is the class of all graphs, we simply say that has the Erdős-Pósa property with respect to . We write if is isomorphic to a subgraph of and if is isomorphic to an induced subgraph of .
The theorem of Erdős and Pósa then asserts that the class of cycles has the Erdős-Pósa property with respect to . This implies that cycles also have the Erdős-Pósa property with respect to . It is known that for every , the class of cycles of length has the Erdős-Pósa property with respect to , see [18, 1, 14]. Recently, Kim and Kwon [9] proved that cycles of length possess the Erdős-Pósa property with respect to :
Theorem 10** ([9]).**
There exists a constant such that for every integer , every graph either contains vertex-disjoint chordless cycles of length or a set of at most vertices such that is chordal.
In contrast, Kim and Kwon [9] showed that, for any given , cycles of length do not have the Erdős-Pósa property with respect to . For any given , they constructed a graph with no two disjoint chordless cycles of length , for which no set of fewer than vertices meets every chordless cycle of length in . This graph contains a copy of . We show that this is essentially necessary:
Corollary 11**.**
For all integers and , the class of cycles of length has the Erdős-Pósa property for the class of -free graphs with respect to .
This follows from Theorem 1 by a standard argument. Since the proof is quite short, we provide it for the sake of completeness. First, recall the following consequence of the Grid Minor Theorem of Robertson and Seymour [16].
Theorem 12** ([16]).**
For all positive integers and there exists an such that for every graph with tree-width , there are disjoint such that has tree-width for every .
Proof of Corollary 11.
Let be an integer. By Theorem 1 there exists an integer such that every -chordal graph with tree-width contains . By Theorem 12, there exists an such that every graph with tree-width has vertex-disjoint subgraphs of tree-width .
Let be a -free graph. We show that either contains disjoint chordless cycles of length or there is a set of at most vertices whose deletion leaves an -chordal graph.
Suppose first that the tree-width of was greater than . Let be disjoint sets of vertices such that has tree-width for every . Then, by Theorem 1, every must contain a chordless cycle of length , since . Therefore contains disjoint chordless cycles of length .
Suppose now that had a tree-decomposition of width . For every chordless cycle of length , let be the subtree of all with . If there are disjoint such subtrees , then are also disjoint and we are done. Otherwise, there exists with which meets every subtree . Then meets every chordless cycle of length in and .
∎
5 Open problems
A large amount of research is dedicated to the study of -boundedness of graph classes, introduced by Gyárfás [8]. Here, a class of graphs is called -bounded if there exists a function so that for every integer and , either contains a clique on vertices or is -colourable. This is a strengthening of the statement that chromatic number is a local parameter for , with cliques being the only bounded-order subgraphs to look for.
As we have seen, cliques are not the only reasonable local obstruction to having small tree-width. Nontheless, we may still ask
For which classes of graphs is tree-width a local parameter? 2. 2.
What kind of bounded-order subgraphs can we force on these classes? 3. 3.
For which classes can we force large cliques by assuming large tree-width?
We have seen in Section 4 that long chordless cycles have the Erdős-Pósa property for the class of -free graphs. For which other classes is this true? Kim and Kwon [9] raised this question for the class of graphs without chordless cycles of length four.
The reference list from the paper itself. Each links out to its DOI / PubMed record.
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- 2[2] Hans L. Bodlaender and Dimitrios M. Thilikos. Treewidth for graphs with small chordality. Discrete Appl. Math. , 79(1-3):45–61, 1997. 4th Twente Workshop on Graphs and Combinatorial Optimization (Enschede, 1995).
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