Virtually abelian subgroups of $IA_n(Z/3)$ are abelian
Michael Handel, Lee Mosher

TL;DR
The paper proves that any virtually abelian subgroup of $IA_n(Z/3)$ is actually abelian, clarifying the structure of subgroups in this context.
Contribution
It establishes that within $IA_n(Z/3)$, virtual abelianness implies actual abelianness, providing a key structural insight.
Findings
Virtually abelian subgroups of $IA_n(Z/3)$ are abelian.
The result simplifies the analysis of subgroup properties in $IA_n(Z/3)$.
Supports the use of finite index subgroups to study subgroup properties.
Abstract
When studying subgroups of , one often replaces a given subgroup with one of its finite index subgroups so that virtual properties of become actual properties of . In many cases, the finite index subgroup is . For which properties is this a good choice? Our main theorem states that being abelian is such a property. Namely, every virtually abelian subgroup of is abelian.
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