
TL;DR
This paper proves that Planar 3-SAT remains NP-complete even with a specific Hamiltonian cycle restriction on the incidence graph, and it also shows that certain monotone instances are always satisfiable, clarifying previous open questions.
Contribution
It introduces a new graph restriction involving a Hamiltonian cycle in the incidence graph and proves NP-completeness under this restriction, while also resolving the complexity of monotone instances with three variables per clause.
Findings
NP-completeness persists under the new cycle restriction
Monotone instances with three variables per clause are always satisfiable
Clarifies the complexity status of specific Planar 3-SAT variants
Abstract
In the Planar 3-SAT problem, we are given a 3-SAT formula together with its incidence graph, which is planar, and are asked whether this formula is satisfiable. Since Lichtenstein's proof that this problem is NP-complete, it has been used as a starting point for a large number of reductions. In the course of this research, different restrictions on the incidence graph of the formula have been devised, for which the problem also remains hard. In this paper, we investigate the restriction in which we require that the incidence graph can be augmented by the edges of a Hamiltonian cycle that first passes through all variables and then through all clauses, in a way that the resulting graph is still planar. We show that the problem of deciding satisfiability of a 3-SAT formula remains NP-complete even if the incidence graph is restricted in that way and the Hamiltonian cycle is given. This…
Peer Reviews
No public reviews on file for this paper yet. If you reviewed it on a platform where reviews are public (OpenReview, ICLR, NeurIPS, ICML), you can paste yours below so the community can read it here.
Videos
No videos yet. Explain this paper in a talk, walkthrough, or lecture? Add one.
