Feynman-Kac representation for the parabolic Anderson model driven by fractional noise
Kamran Kalbasi, Thomas S. Mountford

TL;DR
This paper establishes a Feynman-Kac representation for the parabolic Anderson model driven by fractional noise with any Hurst parameter, using Stratonovich integration and Gaussian approximations.
Contribution
It introduces a unified approach to represent solutions of the fractional noise-driven parabolic Anderson model via Feynman-Kac formula for all Hurst parameters.
Findings
Feynman-Kac representation is valid for the fractional noise case.
The approach works uniformly for all Hurst parameters in (0,1).
Provides a rigorous solution framework for fractional noise-driven PDEs.
Abstract
We consider the parabolic Anderson model driven by fractional noise: where is a diffusion constant, is the discrete Laplacian defined by , and is a family of independent fractional Brownian motions with Hurst parameter , indexed by . We make sense of this equation via a Stratonovich integration obtained by approximating the fractional Brownian motions with a family of Gaussian processes possessing absolutely continuous sample paths. We prove that the Feynman-Kac representation \begin{equation} u(t,x)=\mathbb{E}^x\Bigl[u_o(X(t))\exp \int_0^t…
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Feynman-Kac representation for the parabolic Anderson model driven by fractional noise
Kamran Kalbasi
and
Thomas S. Mountford
Department of Mathematics, Ecole Polytechnique Fédérale de Lausanne, CH-1015 Lausanne, Switzerland
Abstract.
We consider the parabolic Anderson model driven by fractional noise:
[TABLE]
where is a diffusion constant, is the discrete Laplacian defined by \boldsymbol{\Delta}f(x)=\frac{1}{2d}\sum_{|y-x|=1}\bigl{(}f(y)-f(x)\bigr{)}, and is a family of independent fractional Brownian motions with Hurst parameter , indexed by . We make sense of this equation via a Stratonovich integration obtained by approximating the fractional Brownian motions with a family of Gaussian processes possessing absolutely continuous sample paths. We prove that the Feynman-Kac representation
[TABLE]
is a mild solution to this problem. Here is the initial value at site , is a simple random walk with jump rate , started at and independent of the family and is expectation with respect to this random walk. We give a unified argument that works for any Hurst parameter .
Key words and phrases:
Feynman-Kac formula, parabolic Anderson model, stochastic heat equation, fractional Brownian motion, Malliavin calculus
1. Introduction
The parabolic Anderson model(PAM)named after the Nobel laureate physicist Philip W. Anderson, is the parabolic partial differential equation
[TABLE]
where is a diffusion constant and is the discrete Laplacian defined by \boldsymbol{\Delta}f(x)=\frac{1}{2d}\sum_{|y-x|=1}\bigl{(}f(y)-f(x)\bigr{)}. The potential can be a random or deterministic field and even a Schwartz distribution.
The parabolic Anderson model which has been extensively studied, particularly in the last twenty years, has many applications and connections to problems in chemical kinetics, magnetic fields with random flow and the spectrum of random Schrödinger operators, to mention a few. The solution of (2) has also a population dynamics interpretation as the average number of particles at site and time conditioned on a realization of the medium , where the particles perform branching random walks in random media. In this case, the first right-hand-side term of (2) signifies the diffusion and the second term represents the birth/death of the particles. We refer to the classical work of Carmona and Molchanov [1] and the survey by Gärtner and König [2].
We consider the parabolic Anderson model with the potential for and , where is a family of independent fractional Brownian motions(fBM) of Hurst parameter , indexed by .
As the paths of fBM are almost surely nowhere differentiable, this equation doesn’t make sense a priori in the classical sense and we reformulate it in a mild sense:
[TABLE]
where the stochastic integral is Stratonovich type in the sense that the fractional Brownian motion is approximated by a family of smooth processes and the integral is defined by the limit of the family as tends to zero. We assume that is a bounded measurable function.
We will show that the following Feynman-Kac formula gives a solution to (3):
[TABLE]
where is a simple random walk with jump rate , started at and independent of the family and is expectation with respect to this random walk. Here the stochastic integral is nothing other than a summation. Indeed, suppose that are the jump times of the time-reversed random walk with the additional convention and . Let also for be the value of at time interval . Then we have
[TABLE]
Carmona and Molchanov in their classical memoir [1] proved that for bounded and i.e. standard Brownian motion, the Feynman-Kac formula (4) solves equation (3). The asymptotic behavior of the Feynman-Kac expression (4) as the partition function of a directed polymer in a random environment has been studied in [14], but its connection with the PAM has not been investigated. The Feynman-Kac representation for PAM on driven by fractional noise was established in [4] for Hurst parameters and in [3] for . Our method is able to prove this property without any restriction on due to the fact that in the discrete case one deals with locally constant random walk instead of Brownian motion which is only locally -Hölder continuous for .
The paper is organized as follows:
In section 2 we collect some important background material that we will use in the succeeding sections.
In section 3 we outline our methodology including the approximation scheme that we apply to fractional Brownian motion. We show that the problem reduces to demonstrating the convergence of three expressions , and .
It section 4, we prove that piecewise-constant integrals with respect to the approximating processes introduced in section 3 converge to integrals with respect to fractional Brownian motion.
The remaining chapters are devoted to showing the convergence of , and .
2. Preliminaries
A Gaussian random process is called a fractional Brownian motion of Hurst parameter , if it has continuous sample paths and its covariance function is of the following form:
[TABLE]
This process was first introduced by Kolmogorov in [6], but the term “Fractional Brownian motion” was coined by Mandelbrot and Van Ness in [8].
Let be a family of independent fractional Brownian motions indexed by all with Hurst parameter .
Similar to [3], let be the Hilbert space defined by the completion of the linear span of indicator functions for and under the scalar product
[TABLE]
where is the Kronecker delta. Here we assume the convention for negative . The mapping can be extended to a linear isometry from onto the Gaussian Hilbert space spanned by .
Similar to [3], for any piecewise constant function , and every , and we define the following functions on :
[TABLE]
[TABLE]
[TABLE]
It can be easily shown that , and are all in , and moreover
[TABLE]
[TABLE]
and
[TABLE]
where \dot{W_{\varepsilon}}(t,x):=\frac{1}{2\varepsilon}\bigl{(}W(t+\varepsilon,x)-W(t-\varepsilon,x)\bigr{)} for any and .
Let be a Gaussian Hilbert space, a Hilbert space and a Hilbert space isometry between and . By a Gaussian Hilbert space we mean a set of zero-mean Gaussian random variables which is a Hilbert space with respect to covariance as its inner product [5]. Define as the space of random variables of the form:
[TABLE]
where and with and all its partial derivatives having polynomial growth. The Malliavin derivative of denoted by , is defined (see e.g. [3, 5, 9, 11]) as the -valued random variable given by
[TABLE]
The operator extends to the Sobolev space which is defined as the closure of with respect to the following norm [3, 5]:
[TABLE]
The divergence operator is the adjoint of the derivative operator , determined by the duality relationship [3, 5]
[TABLE]
The space of -valued Malliavin derivable random variables with derivatives, denoted by , is contained in the domain of , and moreover for any , we have
[TABLE]
For any random variable and the change of variable formula [3, 5]:
[TABLE]
For more on Malliavin calculus we refer to [5, 9].
We will use the following lemma in several occasions:
Lemma 2.1**.**
Let be a measure space and , be Banach spaces. Let also be a continuous linear operator and a separably-valued measurable function, i.e. there exists a separable subspace of such that almost surely. If then
[TABLE]
Proof.
As is separably-valued, there exists [5, 7] a sequence of simple functions of the form with and with the property that
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As is linear, it commutes with integration on . As is continuous we have for some positive constant , so
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and also
[TABLE]
Hence commutes with integration for too. ∎
3. Setting
As explained in the previous section we aim to approximate the fractional Brownian motions with a family of smooth Gaussian processes. There are two obvious ways to approximate a (fractional) Brownian motion. First the so-called Wong-Zakai approximation scheme [13] which is the piecewise linear approximation of (fractional) Brownian motion paths. The second natural scheme is as follows: The time derivative of a fractional Brownian motion does not exist in the classical sense but only in the distributional sense. The idea is to approximate the ‘derivative’ of the fractional Brownian motion and then integrate it. Indeed we define the approximate derivative of as
[TABLE]
Proposition 4.1 shows in particular that the integral of this family of Gaussian processes converges to fractional Brownian motion.
While the first scheme doesn’t seem to be easy to work with, the second one has been proved to be very suitable in our setting where we use the Wiener space technics and Malliavin calculus [3].
Now let first replace the fBM family in equation (3) by a family of absolutely continuous functions , or equivalently replace the family of fractional noises by a family of locally integrable functions where for every and . Carmona and Molchanov in [1] showed that the Feynman-Kac formula
[TABLE]
solves the PAM driven by the potential if this expression is finite for every and .
If we approximate every fractional Brownian motion by a family of stochastic processes which converge to and with the property that every has absolutely continuous sample paths, we expect that should also converge . On the other hand, if we denote by the solution of equation (3) with replaced by , we also expect that should converge to the solution of (3) with the integral understood in the Stratonovich sense. The reason is that for the stochastic differential equations with Brownian motion or more generally semi-martingale terms, if the Brownian motions (semi-martingales) are approximated by a family of processes with absolutely continuous sample paths, the sequence of solutions converges to the Stratonovich solution of the original differential equation [12, 10]. Note that for each sample path of an such processes, a solution in the classical sense exists.
So we consider the approximation scheme of equation (10). In the rest of the paper, without any loss of generality we will assume that . We also denote by the expectation with respect to the fractional Brownian field and by the expectation with respect to the random walk .
Let
[TABLE]
where is defined in (10).
By lemma 5.4, we have for every and . So almost surely, is finite for every and . On the other hand, the sample paths of are locally integrable. So by the above mentioned theorem of Carmona and Molchanov [1] the field solves the following equation
[TABLE]
We aim to show that (4) gives a solution to (3) with the Stratonovich integral defined in the following natural manner which was also used in [3].
Definition 3.1**.**
For a random field , the Stratonovich integral
[TABLE]
is defined [3] as the following limit (if it exists)
[TABLE]
Using the same methodology of [3] we will show that the Stratonovich integral of the Feynman-Kac formula (4) exists and moreover it satisfies (3).
Indeed equation (12) can be integrated to
[TABLE]
Once we show that (given by (11)) converges to (given by (4)) in sense and uniformly in as goes down to zero, along with equation (13), it would imply the -convergence of \int\bigl{(}u_{\varepsilon}\dot{W_{\varepsilon}}\bigr{)} to some random variable. If moreover one shows that \int\bigl{(}u_{\varepsilon}\dot{W_{\varepsilon}}-u\dot{W_{\varepsilon}}\bigr{)} converges in to zero, it would imply the convergence of \int\bigl{(}u\dot{W_{\varepsilon}}\bigr{)} and hence the existence of the Stratonovich integral . But this means that satisfies equation (3).
Let be defined as in equation (5). So we have and by the change of variable formula (9) we obtain
[TABLE]
where .
Hence it suffices to show that and both converge to zero as goes to zero. In sections 5, 6 and 7 we will deal with the convergence of , and .
4. Approximation rate
In this section we prove the following theorem that establishes the approximation of by . In the proof we will use some ideas of [3] as well as simple properties of random walk.
Proposition 4.1**.**
Let , , , , …, be some positive real numbers with and a jump function on with values in and jump times , i.e. for . Then
[TABLE]
where is a constant depending only on and and
[TABLE]
Proof.
First we show that for every and , , and any fractional Brownian motion with Hurst parameter we have
[TABLE]
where is the symmetric -derivative of :
[TABLE]
and is some positive constant depending only on and . We have to calculate and bound
[TABLE]
Let and be the first and second terms on the right hand side of this equation and be the third term without its factor.
Using the following equality
[TABLE]
we have:
[TABLE]
[TABLE]
and
[TABLE]
We will show that both and converge to .
Step I: Limiting behavior of
By a change of variable we can replace the integration interval with with the integrand remaining intact. But as the integrand is symmetric in and , we may calculate the integral over a triangular surface hence getting:
[TABLE]
By a change of variable of we get:
[TABLE]
We will show that converges to with the following rate of convergence for
[TABLE]
and
[TABLE]
for . Here is some constant depending only on and . For the simplicity of notation let . Defining , (16) can be written as:
[TABLE]
As is continuous everywhere and is continuous everywhere except for the origin when and everywhere when , this equation can be written as:
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Let and first suppose that .
Case i) :
[TABLE]
Case ii) :
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The first term equals and the second term equals which is bounded by .
Case iii) :
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Noting that , inequality (17) is proved.
Now we consider the case of .
Case i) :
[TABLE]
As we have which shows that the above integral is bounded by and hence by .
Case ii) : Equation (21) remains valid with its first term bounded by which is smaller than , assuming . As , the absolute value of the second term equals:
[TABLE]
The last inequality is true because . So we get the bound .
Case iii) : Equation (22) works without any change and we get the bound .
Noting the proof of inequality (18) is complete with .
In the regime we can establish the following alternative bound which will be used in section 5
[TABLE]
It is shown case by case
- •
For case i), using the first equality in equation (23) and noting we have the bound .
- •
For case ii), the second term on the right hand side in (21) can be bounded by and the first term by .
- •
In case iii), using the first equality in (22) it can be bounded by .
So we have the bound .
Step II: Limiting behavior of
By setting and two changes of variables, can be written as
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So
[TABLE]
Let’s first assume . Let’s break this integral into three sub-integrals:
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and call them , and , respectively.
We bound these terms separately for and .
First suppose .
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For the second term we have
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Finally:
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So for :
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Now for : we again examine each of the terms:
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As equation (4) remains valid for , we have:
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For we use the same trick as in (27):
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Now we address the case where . Here we need to break the integral in (25) into three sub-integrals:
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Let’s call the terms as , , , , respectively.
One can check easily that the same procedures used for bounding and work for and . For and we have
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and
[TABLE]
Hence
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So in brief the same bounds found above for for the case remain valid for the case too. So inequality (14) is proved.
Now we turn back to the proof of proposition 4.1. we have:
[TABLE]
∎
5. Convergence of
In this section, using simple random walk properties we prove that and its Malliavin derivative both converge to zero in .
Proposition 5.1**.**
* converges to [math] in uniformly in , i.e.*
[TABLE]
Let be a piecewise constant function on the lattice with jump times . Let also and . For any given we may chop up into calm periods and rough ones. A calm period is defined as an interval in which all the consecutive jumps are at least apart, and a rough period as one in which all the consecutive jumps are at most apart. We additionally require that these intervals begin with a jump and end with another.
We also define as the number of jumps in that are within distance of their previous one. In other words, is defined to be the cardinality of
Lemma 5.2**.**
Consider a Poisson process with intensity and let (=) be defined for any sample path of the Poisson process as above. Then for any given , we have
[TABLE]
where is a constant that depends only on and .
Proof.
Let be the event of having at least one jump in which is within of a previous one and be the event of having at least one jump in . Let also be the number of jumps in and . We have
[TABLE]
Using the fact that the expectation of is and noting the inequality , we get , where . In particular is increasing in .
Now we define as the first jump time that is within of the previous one, i.e. . Having defined we define as the first jump time after that is within of the previous one, i.e. . We have
[TABLE]
As is an increasing function in we have the following uniform bound:
[TABLE]
So
[TABLE]
So by induction
[TABLE]
Now noticing that implies , we get
[TABLE]
∎
Lemma 5.3**.**
For a Poisson process of intensity and for any given , let be the total length of its rough periods in and be the number of rough periods in . Then there exists a constant depending only on and such that
[TABLE]
and
[TABLE]
Proof.
As and , any of or implies . The result follows from the previous lemma. ∎
Now we are ready to prove the following lemma.
Lemma 5.4**.**
For any , there exists such that is bounded uniformly in . is also bounded uniformly in .
Proof.
First consider .
[TABLE]
So it is enough to find a uniform bound on \operatorname*{var}\bigl{[}\int_{0}^{t}W\bigl{(}\mathrm{d}s,X(t-s)\bigr{)}\bigr{]}. For any sample path of simple random walk on let be the jump times of the reversed path and , , …, be its values. Let also and . We have
[TABLE]
For we have
[TABLE]
As is a Poisson random variable, is finite for any constant .
For we use the well-known property that disjoint increments of a fractional Brownian motion with Hurst parameter less than half are negatively correlated. So we have
[TABLE]
In the last inequality we have used the fact that for , the expression achieves its maximum when all ’s are equal and the maximum is hence .
Again as is Poisson, is finite for any constants and .
Now let us consider :
[TABLE]
Again we need to distinguish between larger and less than half.
When is larger than a half, being equal to introduced in section 4, is bounded by by inequality (24). With the above notation
[TABLE]
Again we get a multiple of and hence a finite bound.
When , the situation is more complicated. Let be the increasingly ordered jump times of with additional convention of and . We decompose into calm and rough periods of with respect to . Let increasingly enumerate the set of indices as . In other words, we single out and enumerate those time intervals whose length is larger than or equal to . It is evident that such intervals constitute the calm periods. Let also be the integral of over the time interval , i.e. . Let also be the sum of the integrals over all rough periods. Using equation (29), Cauchy-Schwartz and the simple inequality , we have
[TABLE]
Once again we will use the negativeness of the covariance of disjoint increments of a fractional Brownian motion with Hurst parameter less than half.
First we consider the integral over the rough periods, i.e. the first term above. Let be the union of all the rough intervals in .
We notice that for , and a fractional Brownian motion of Hurst parameter we have
[TABLE]
which is nothing but the negative correlation of non-overlapping increments of a fBM, and
[TABLE]
which is easily followed by a simple calculation.
This shows that for , there are only two possibilities: either \dot{W_{\varepsilon}}\bigl{(}\alpha,X(t-\alpha)\bigr{)} and \dot{W_{\varepsilon}}\bigl{(}\beta,X(t-\beta)\bigr{)} have negative correlation or they are uncorrelated, depending on whether is the same as or not. So we have
[TABLE]
where is the total length of rough periods, i.e. the length of .
So
[TABLE]
As has exponential tail by lemma 5.3, the above expectation is finite for small enough.
For the second term, , observe that the length of each time interval is larger than which means the distance of every two non-neighboring such intervals is at least . But this means that only consecutive ’s can be positively correlated because for any two intervals and that are at least apart, the integrals and are negatively correlated which in turn is a consequence of the negative correlation of disjoint intervals of a fractional Brownian motion with . So
[TABLE]
In the first inequality we have used the fact that for non-consecutive and , their covariance is negative and in the last inequality we have used . Using equation (17) we have
[TABLE]
So noting , where denotes the number of jumps in and using the fact that is bounded by for which is a consequence of concavity of , we get
[TABLE]
∎
Proof of proposition 5.1.
We give the same argument used in [3].
Since is bounded, for simplicity and without any loss of generality we drop it from now on.
For arbitrary, using the inequalities and and also Hölder’s and Jensen’s inequalities we get
[TABLE]
where in the second inequality we have used the fact that for Gaussian random variables all the -norms are equivalent to 2-norm.
So by applying lemma 5.4 and proposition 4.1 we obtain
[TABLE]
For the convergence of , we use the fact that for a separably-valued -valued random variable with a probability space independent of the underlying Gaussian space of , we have provided that , where the expectations are taken with respect to . This follows from lemma 2.1.
So we have
[TABLE]
[TABLE]
So
[TABLE]
If we apply the Schwartz inequality and note that , along with fact that for Gaussian random variables all norms are equivalent to the -norm, using equation (30), lemma 5.4 and proposition 4.1 we get
[TABLE]
∎
6. Convergence of
For we use basically the same proof as in [3]. As one can easily show that
[TABLE]
where denotes the Sobolev space of -valued random variables with Malliavin derivatives, we can apply lemma 2.1 to get:
[TABLE]
where
[TABLE]
So using inequality (8), we have
[TABLE]
For the first right hand side term we have
[TABLE]
where . Here taking the integration out of the inner product is justified by once more using lemma 2.1.
\int_{0}^{t}\int_{0}^{t}\bigl{|}\mathbb{E}\bigl{(}\dot{W_{\varepsilon}}(s_{1},x)\dot{W_{\varepsilon}}(s_{2},x)\bigr{)}\bigr{|}\mathrm{d}s_{1}\mathrm{d}s_{2} being the same as the term in equation (15), is uniformly upper-bounded using equations (17) and (18). On the other hand, goes to zero as . So it follows that \mathbb{E}\bigr{(}\|\psi_{\varepsilon}\|_{\mathcal{H}}^{2}\bigl{)} converges to zero.
For the second term, applying lemma 2.1 to the derivative operator and inner product we get
[TABLE]
where .
The same argument given for the first term above shows that \mathbb{E}\bigl{(}\|\nabla\psi_{\varepsilon}\|_{\mathcal{H}\otimes\mathcal{H}}^{2}\bigr{)} also converges to zero as goes down to zero.
7. Convergence of
Establishing the convergence of is more involved. First applying lemma 2.1 to and for the derivative operator we get
[TABLE]
and
[TABLE]
Let
[TABLE]
and
[TABLE]
Hence we have
[TABLE]
Let
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and
[TABLE]
So we will show in two steps that each of these terms converge to zero in .
Step I: Convergence of . For the first term, using Hölder inequality for we have
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In fact equation (30) also proves that for any
[TABLE]
So if we can show that is bounded by some constant which depends only on and we are done because then
[TABLE]
where means less than up to a constant. So either , where we get as an upper bound or , where we get the upper bound .
Let be the jump times of the path up to time , and . Let then be the set of indices for which stays at site in the time interval . Now applying the definitions (5)-(7) we get
[TABLE]
where is a fractional Brownian motion of the same Hurst parameter . We split this expression into two terms
[TABLE]
and
[TABLE]
For the first term, using the same reasoning as in (19) and (20), we have
[TABLE]
where and hence .
Letting and noting that is exponentially distributed, we have
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As we can restrict ourselves to and hence and as , we have
[TABLE]
So if we choose such that , we get a finite bound on and hence a bound on that only depends on and .
Now for the second term, , let
[TABLE]
We have because either which implies that and and hence or in which case we may write as the following
[TABLE]
Letting again , we have and so
[TABLE]
which gives .
So we have
[TABLE]
So is bounded (up to a constant) by either for , or for . The case can also be treated easily using the inequality for any positive. So as , can be bounded by a constant only dependant on and . So this competes the proof showing that , for some and a constant only dependant on and .
Step II: Convergence of . For establishing the convergence of we will use the dominated convergence theorem.
In ‘step I’ we showed that
[TABLE]
where is defined in (33).
Now let and be as in ‘step I’, i.e. be the jump times of the path up to time , and and the set of indices for which stays at site in the time interval . So we have
[TABLE]
where
[TABLE]
We will show that converges to zero. For doing so we shall show that [\frac{1}{4\varepsilon}\bigl{(}|t_{1}+\varepsilon|^{2H}-|t_{1}-\varepsilon|^{2H}\big{)}-\frac{1}{2}\int_{0}^{t_{1}}f^{\varepsilon}(r)\,\mathrm{d}r] converges to zero and that every also converges to zero.
By equations (31) and (32), we have
[TABLE]
So for a fixed positive this converges to . On the other hand \frac{1}{4\varepsilon}\bigl{(}|t_{1}+\varepsilon|^{2H}-|t_{1}-\varepsilon|^{2H}\big{)} also converges to .
For , we will show that converges to zero and then apply the dominated convergence to the integral.
Using (34) it can be easily shown that
[TABLE]
By simply recognizing the definition of derivative we have
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So it remains to find an integrable -independent upper bound. As shown in the paragraph following (33), is bounded by and for , restricting to be less than , where is the first index in after , we have for all
[TABLE]
But then as it gives as an upper bound on . This completes the proof for convergence to zero of .
Now, for applying the dominated convergence theorem to we only need to find an -independent upper bound on having the property that \mathbb{E}\bigl{(}\int_{0}^{t}\mathbb{E}^{x}(G)\bigr{)}^{2}<\infty. For such an upper bound has been established in step I above. It remains to find an upper bound on .
For the situation is quite trivial because using equation (35) we easily get
[TABLE]
When , equation (36) remains valid for any value of and . As for any we have
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hence we get an upper bound dependant only on t and H.
So we consider now the case of . For and any we have
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This is true because either in which case
[TABLE]
or , where we have
[TABLE]
So by (35) we have
[TABLE]
where is the number of jumps in .
Applying the Hölder inequality with we have
[TABLE]
So we just need to pick a with , in which case the exponential distribution of implies
[TABLE]
In fact the proof of lemma 5.4 also shows that for any , is uniformly bounded in . As has a Poisson distribution is also finite.
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