Mass Transportation on sub-Riemannian structures of rank two in dimension four
Zeinab Badreddine

TL;DR
This paper investigates the Monge optimal transport problem on rank-two sub-Riemannian manifolds of dimension four, focusing on existence and uniqueness of optimal maps despite the presence of many singular geodesics.
Contribution
It extends previous results by establishing existence and uniqueness of optimal transport maps in complex sub-Riemannian structures with numerous singular geodesics.
Findings
Existence of optimal transport maps in the specified structures
Uniqueness of these maps under certain conditions
Handling of singular minimizing geodesics in the analysis
Abstract
This paper is concerned with the study of the Monge optimal transport problem in sub-Riemannian manifolds where the cost is given by the square of the sub-Riemannian distance. Our aim is to extend previous results on existence and uniqueness of optimal transport maps to cases of sub-Riemannian structures which admit many singular minimizing geodesics. We treat here the case of sub-Riemannian structures of rank two in dimension four.
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Taxonomy
TopicsGeometric Analysis and Curvature Flows · Geometry and complex manifolds · Nonlinear Partial Differential Equations
Mass transportation on sub-Riemannian structures of rank two in dimension four
Z. BADREDDINE Université Côte d’Azur, Inria, CNRS, LJAD, France; Université de Bourgogne, Institut de Mathématiques de Bourgogne, France
Abstract
This paper is concerned with the study of the Monge optimal transport problem in sub-Riemannian manifolds where the cost is given by the square of the sub-Riemannian distance. Our aim is to extend previous results on existence and uniqueness of optimal transport maps to cases of sub-Riemannian structures which admit many singular minimizing geodesics. We treat here the case of sub-Riemannian structures of rank two in dimension four.
Introduction
Let be a smooth connected manifold without boundary of dimension . The problem of optimal transportation, raised by Monge [Mon81] in , was concerned with the transport of a pile of soil into an excavation. Given two probability measures on , we call the transport map from to , any measurable application such that (we say that is pushing forward to , ie. for every measurable set in , ).Therefore, the Monge problem was modelized as an optimal transport problem consisting in minimizing the transportation cost
[TABLE]
among all the transport maps .
Here, represents the cost of transporting a unit of mass from a position to some position . The fact that the condition is nonlinear with respect to , is the main difficulty in solving the Monge problem.
In , Kantorovitch [Ka42] proved a duality theorem to study the relaxed form of the problem. He replaced the transport map by a transport plan where is the set of probability measures in the product with and ( where the projection map into the i-th component). Hence, Kantorovitch problem consists in minimizing
[TABLE]
The Kantorovitch’s approach leads to a dual formulation (see Chapter 5 [Vil08]) given by:
[TABLE]
This leads to find a pair of integrable functions optimal on the right-hand side, and a transport plan optimal on the left-hand side. The pair of functions should satisfy . Then, for a given , will be the infinimum of among all . For a given , will be the supremum of among all . We may indeed assume that is a c-convex function and satisfying the two equations below:
[TABLE]
The pair is called the Kantorovitch potentials.
We refer the reader to the textbooks [Vil03, Vil08] by Villani for more details on the optimal transport theory.
Several techniques developed by Brenier [Br91], McCann [Mc01], Cavalletti and Huesmann [CH15] and others allow to show that in certain cases, optimal transport plans yields indeed optimal transport maps, solutions to the Monge problem.
This paper will be concerned with the study of the Monge problem for the quadratic geodesic sub-Riemannian cost. Let be a complete sub-Riemannian structure on , where is a totally nonholonomic distribution on of rank and a smooth Riemannian metric on , that is for every , is a scalar product on . We recall that a distribution is called totally nonholonomic if, for every , there exist an open neighborhood of and a local frame on such that
[TABLE]
Let . A continuous path is said to be horizontal with respect to if it is absolutely continuous with square integrable derivative and satisfies
[TABLE]
The length of an horizontal path is given by
[TABLE]
We define the sub-Riemannian distance between two points and of as the infinimum of lengths of horizontal paths joining to , that is,
[TABLE]
A minimizing geodesic is an horizontal path with constant speed minimizing for the sub-Riemannian distance between its end-points. We shall say that the sub-Riemannian structure on is complete if the metric space is complete. Thanks to the Hopf-Rinow theorem (see [Rif14]), if is a complete sub-Riemannian structure on , then minimizing geodesics exist between any pair of points in . Let be smooth vector fields generating (see proposition [Rif14]), that is for every ,
[TABLE]
Given and , the End-point mapping from is defined by
[TABLE]
where is the unique solution to the Cauchy problem:
[TABLE]
A control is called singular if and only if it is a critical point of , and regular if not. An horizontal path is said to be singular (resp. regular) if and only if any control associated to (i.e. solution of (3)) is singular (resp. regular) for .
For every and every , we denote by the set of regular minimizing geodesics starting at . We also denote by the set of singular minimizing geodesics starting at .
The notion of singular curves play a major role in this paper. In absence of singular minimizing geodesics, sub-Riemannian distances enjoy the same kind of regularity as Riemannian distances at least outside the diagonal. We recall that the diagonal of is the set of all pairs of the form with . Following previous results by Ambrosio-Rigot [AR04] and Agrachev-Lee [AL09], Figalli and Rifford (see [FR10]) proved that local lipschitzness of the sub-Riemannian distance outside the diagonal is sufficient to guarantee existence and uniqueness of optimal transport maps (see also the textbook [Rif14] by Rifford).
In general, we do not know if the Monge problem (for the sub-Riemannian quadratic cost) admits solutions if there are singular minimizing curves. For a two-rank distribution on a three-dimensional manifold , we have existence and uniqueness of optimal transport maps for the sub-Riemannian quadratic cost because non-trivial singular horizontal paths are included in the Martinet surface given by which has Lebesgue measure zero. The first relevant case to consider is the one of rank-two distributions in dimension four. In this case, as shown by Sussman [Sus96], singular horizontal paths can be seen (locally) as the orbits of a smooth vector field, at least, outside a set of Lebesgue measure zero.
The definition of a real analytic manifold is similar to that of a smooth manifold. We begin by recalling that an analytic function is an infinitely differentiable function such that the Taylor series at any point in its domain, converges to for in a neighborhood of . We say that a manifold of dimension is real analytic if transition maps are analytic. We provide with a real analytic distribution of rank , that is for each , there is an open neighborhood containing and analytic vector fields on such that
[TABLE]
In this case, the Cauchy problem given in (3), has a real analytic solution on for and some .
The aim of this paper is to show that, in the case of rank-two analytic distribution in dimension four, we have existence and uniqueness of optimal transport maps for the sub-Riemannian quadratic cost, as soon as the distribution satisfies some growth condition.
We recall that the support of a measure , denoted by , refers to the smallest closed set of full mass .
Our main result is the following:
Theorem 1**.**
Let be a real analytic manifold of dimension and be a complete analytic sub-Riemannian structure of rank on such that
[TABLE]
where
[TABLE]
*Let , be two probability measures with compact support on such that is absolutely continuous with respect to the Lebesgue measure .
Then, there is existence and uniqueness of an optimal transport map from to for the sub-Riemmannian quadratic cost defined by:*
[TABLE]
Our strategy to prove Theorem 1 is twofold. It combines the technique used by Figalli-Rifford [FR10] (see also the paper by Agrachev-Lee [AL09]) which is based on the regularity of the distance function outside the diagonal in absence of singular minimizing curves, together with a localized contraction property for singular curves in the spirit of a previous work by Cavalletti and Huesmann [CH15].
The paper is organized as follows. In Section 1, we give more details on the strategy of proof. Then Section 2-3 are devoted to prove some required results to achieve existence and uniqueness of optimal transport maps. In Section 4, we finalize the proof of Theorem 1.
1 Strategy of proof
From now on, we assume that the manifold has dimension and is equipped with a complete sub-Riemannian structure of rank such that
[TABLE]
We fix two probability measures compactly supported on such that is absolutely continuous with respect to the Lebesgue measure. As it is well-know (see [Vil08]), since is continuous on , the Kantorovitch transport problem between and with cost admits at least one solution and there is a pair of Kantorovitch potentials solution of the dual problem satisfying the equations (2a) and (2b). Moreover, we denote by the contact set of the pair given by
[TABLE]
We get that (see Corollary 3.2.14 [Rif14]):
a transport plan is optimal if and only if .
In other words, the problem of existence and uniqueness of optimal transport maps can be reduced to prove that is concentrated on a graph, that is to show that for –almost every point the set
[TABLE]
Following [FR10], let us introduce the following definition:
Definition 1**.**
We call "moving" set and "static" set respectively the sets defined as follows:
[TABLE]
[TABLE]
We note that is an open subset of . In fact, we can easily check that coincides with the set
[TABLE]
which is open by continuity of and .
Since both and are compact and the metric space is complete, there are and a constant such that
[TABLE]
where is the open ball in centered at of radius .
As a consequence, any minimizing geodesic from to is contained in .
From now on, we work in the compact set of diameter and so, we proceed as if were a compact manifold.
supp supp
As in [FR10], we shall show that "static" points do not move, i.e. almost every is transported to itself. For sake of completeness, the proof of Lemma 1 is given in Appendix A.
Lemma 1**.**
For , we have .
We need now to show that almost every moving point is sent to a singleton. To this aim, we need to distinguish between two types of moving points.
Definition 2**.**
Let . For every , we set
[TABLE]
and
[TABLE]
Moreover, we let
[TABLE]
Note that, by construction, for every , . Furthermore, if there are no non-trivial singular minimizing curves then .
First, using techniques reminiscent to the previous works by Agrachev-Lee [AL09] and Figalli-Rifford [FR10], we prove that
Proposition 1**.**
For -a.e. , is a singleton.
Then, using a localized contraction property for singular curves which holds thanks to (4), the technique developed by Cavalletti and Huesmann [CH15] allows to show that
Proposition 2**.**
For -a.e. , is a singleton.
It remains to show that for almost every , is a singleton. Again this will follow from a local contraction property together with the approach of Cavalletti and Huesmann [CH15], see Section 4.
2 Proof of Proposition 1
Argue by contradiction, by assuming that there is a compact set of positive Lebesgue measure such that
[TABLE]
We may assume that is contained in a chart of . Without loss of generality, we may assume that is an open subset of where we can use the local set of coordinates .
For every , we define the set
[TABLE]
where denotes the closed ball in centered at with radius .
The set is well-defined, up to a change of coordinates, for large enough.
Lemma 2**.**
**
Proof of Lemma 2.
Let , then there are and
a regular horizontal path steering to . There exist an open neighborhood of and an orthonormal family (with respect to ) of two vector fields such that
[TABLE]
According to a change of coordinates if necessary, we can assume that is an open subset of . Moreover, there is a control associated to , ie.
[TABLE]
We recall that the set of minimizing geodesics between and is compact with respect to the uniform topology: if is a sequence converging uniformly to then, the sequence of minimizing geodesics joining to converges uniformly to and the sequence of controls associated to converges uniformly to in . Then, there exists an open neighborhood of such that , every minimizing geodesic joining to is contained in .
Since is regular, there exist such that the linear operator
[TABLE]
is invertible.
Recall that is dense in , we can assume that we have in .
Define locally
[TABLE]
This mapping is well-defined and of class in the neighborhood of zero. It satisfies and its differential at [math] is invertible.
By the Local Inverse Function Theorem, there exist an open ball of centered at and a function of class such that
[TABLE]
[TABLE]
\mathcal{V}$$\bullet$$\bar{x}$$\bullet$$\bar{y}$$\bar{\gamma}\leftrightarrow\bar{u}$$=E^{\bar{y}}(\bar{u})$$\mathcal{B}$$\bullet$$z$$\displaystyle{\bar{u}+\sum_{i=1}^{n}(\mathcal{G}(z))_{i}v^{i}}
Define , . Then, we conclude that there is a function such that
[TABLE]
Recall that, by the definition of the Kantorovitch potentials, for every , we have
[TABLE]
Then, ,
[TABLE]
Define . Hence, we put locally a function under the graph of with a uniform control on the norm of . Then, for , we can find such that there is with verifying
[TABLE]
∎
We are ready to complete the proof of Proposition 1.
Since (by Lemma 2), there exists such that
[TABLE]
Let be a density point of and . By the definition of the Kantorovitch potentials, we have that
[TABLE]
[TABLE]
We define the function \begin{array}[]{lccl}\rho^{\bar{x}}:&M&\rightarrow&\mathbb{R}\\ &z&\mapsto&\rho^{\bar{x}}(z):=\varphi(\bar{x})+d_{SR}^{2}(\bar{x},\bar{y})-\varphi(z)\end{array} verifying
[TABLE]
Let . For every , there is , such that
[TABLE]
We define the function as follows
[TABLE]
where
[TABLE]
We claim that for every , . Let us prove our claim.
In fact, for every ,we have
[TABLE]
that is
[TABLE]
In particular, for , we obtain
[TABLE]
Assume that there is such that .
Then, there is , such that
[TABLE]
that is
[TABLE]
Or, , then .
So,
[TABLE]
[TABLE]
which contradicts inequality (9). And the conclusion follows.
Moreover, let be fixed. There exists a neighborhood of contained in such that for every , there is such that , we have
[TABLE]
Take , we obtain
[TABLE]
This means that for every , is locally semiconvex on . According to Lemma 14 in Appendix B, since is the supremum of local semiconvex functions among all , then is locally semiconvex on . By the Rademacher Theorem, is differentiable almost everywhere on .
We also define the function
[TABLE]
such that
[TABLE]
Here, is fixed and is a function of . By the definition of , as is differentiable at almost every , is also differentiable almost everywhere on .
On the other hand, following the proof of Lemma 2, for and , there are an open set in containing and a function such that
[TABLE]
Consequently, by (8), (10), (11), we obtain
[TABLE]
and
[TABLE]
Note that is a function and is differentiable almost everywhere on . Then,
[TABLE]
It means that there is a unique such that
[TABLE]
with the sub-Riemannian exponential map from . This contradicts assumption (5) and the conclusion follows.
Remark 1**.**
The above argument can be used to prove the required result in the general case, with a smooth connected manifold of dimension equipped with a complete sub-Riemannian structure of rank .
3 Proof of Proposition 2
Our aim is to prove that
for almost every , is a singleton.
First, we need to construct a line field, defined on a set of full Lebesgue measure, whose orbits correspond to the singular curves.
The following holds (see [Sus96], [Rif14], [LS95]) :
Lemma 3**.**
*There is an open set of full Lebesgue measure on such that:
[TABLE]
Proof of Lemma 3.
We denote by the set given by
[TABLE]
It is clear that is a closed set on such that condition (12) is verified on its complementary set. Let us prove that is of Lebesgue measure zero on . For sake of simplicity, we will work locally. In other terms, given , there are a local set of coordinates in an open neighborhood of and two vector fields linearly independent on such that
[TABLE]
By hypothesis (4) in Theorem 1, we have
[TABLE]
As a consequence, is a totally nonholonomic distribution of rank in dimension with
[TABLE]
where
According to a change of coordinates if necessary, we can assume that
[TABLE]
where , are analytic functions.
Hence, , we have
[TABLE]
and
[TABLE]
For every , we denote by the smooth vector field constructed by the Lie brackets of as follows
[TABLE]
Note the length of the Lie brackets . Since is totally nonholonomic distribution, there exists a positive integer such that
[TABLE]
For every of , there exists a function such that
[TABLE]
We define the following sets
[TABLE]
We have \displaystyle{\Sigma_{\delta}=\bigcup_{k=2}^{r}\Bigl{(}\mathcal{A}_{k}\textbackslash\mathcal{A}_{k+1}\Bigr{)}}.
By the Implicit Function Theorem, each set can be covered by a countable union of smooth hypersurfaces. Fix .
There exists some of length such that .
Put . Then
[TABLE]
Hence,
[TABLE]
We deduce that
[TABLE]
It shows that is a closed 3-rectifiable set in , so is of Lebesgue measure zero on . We can indeed take the complementary set of in . ∎
We need another lemma.
Lemma 4**.**
There exists a line subbundle of such that the singular horizontal curves defined on are exactly the trajectories described on .
Proof of Lemma 4.
It is sufficient to prove the result in a neighborhood of each point in . So, let us consider a local frame such that
[TABLE]
Let be a trajectory associated to some control . In local coordinates, singular curves can be characterized as follows (see Proposition 1.3.3 [Rif14]):
is singular with respect to if there is satisfying :
[TABLE]
[TABLE]
Derivative two times yields for almost every such that
[TABLE]
and
[TABLE]
Since has dimension four and \Delta+\Bigl{[}\Delta,\Delta\Bigr{]} has dimension three, there is locally a smooth non-vanishing 1-form such that
[TABLE]
Then, by (14), (15)-(16), we infer that for almost every such that , we have:
[TABLE]
By above assumption, for every , the linear form
[TABLE]
has a kernel of dimension one. This shows that there is a smooth line field (a distribution of rank one) on such that the singular horizontal curves are exactly the integral curves of . ∎
We are ready now to prove Proposition 2. Without loss of generality, it is sufficient to prove the result locally. We can assume that denotes the coordinates in an open neighborhood in and consider a local frame of such that
[TABLE]
Doing a change of coordinates if necessary, we can assume that
[TABLE]
where are smooth functions.
For the upcoming results, it is important to keep in mind the following notations.
Notation 1**.**
*We denote by the partial derivative with respect to the variable , and the second partial derivative with respect to the variable and , of and respectively.
*We compute the Lie brackets of and :
[TABLE]
[TABLE]
[TABLE]
with \left\{\begin{array}[]{lcl}\vspace*{0.5cm}\par E&=&A_{x_{2}x_{1}}+AA_{x_{3}x_{1}}+BA_{x_{1}x_{4}}-A_{x_{1}}A_{x_{3}}-B_{x_{1}}A_{x_{4}},\\ F&=&B_{x_{2}x_{1}}+AB_{x_{3}x_{1}}+BB_{x_{1}x_{4}}-A_{x_{1}}B_{x_{3}}-B_{x_{1}}B_{x_{4}}.\end{array}\right.
By hypothesis (4) and (17), we can assume that
[TABLE]
We denote by the complementary set of on given by
[TABLE]
Thus, is a closed set of Lebesgue measure zero on .
The above discussion implies indeed the following lemma.
Lemma 5**.**
There exists an analytic horizontal vector field given by
[TABLE]
with smooth functions given by
[TABLE]
*( and smooth functions defined in Notation 1).
*The vector field vanishes on and any solution of the Cauchy problem is analytic and singular.
Proof of Lemma 5.
Let and let be a singular control and
be a solution to the Cauchy problem
[TABLE]
There exists an absolutely continuous arc such that
[TABLE]
[TABLE]
Taking the derivatives in (20) gives
[TABLE]
which implies that ,
[TABLE]
Assume that condition (18) is true, then we obtain
[TABLE]
By taking the derivatives in (21), we obtain for every
[TABLE]
[TABLE]
We can write
[TABLE]
Assume that , we obtain
[TABLE]
∎
Lemma 6**.**
There is a positive constant such that
[TABLE]
Proof of Lemma 6.
Let us compute the divergence of . For every ,
.
By (22), we can write and .
Hence,
As we noticed before, without loss of generality, we proceed as if is a compact manifold. Then, \Big{(}\displaystyle{E/A_{x_{1}}+div_{x}X^{2}}\Big{)} and \Big{(}\displaystyle{A_{x_{1}x_{1}}/A_{x_{1}}}\Big{)} are bounded functions on . There exist such that
[TABLE]
Thus,
[TABLE]
[TABLE]
with positive constant. ∎
The following process is equivalent to the process introduced by Belotto and Rifford [BR16] to set the contraction property.
Let and , we denote by the analytic flow of the vector field generating locally singular minimizing geodesics.
For every subset in , we set
[TABLE]
We denote by
where stands form the norm of with respect to .
We recall that there is , already defined in section 1, such that for every , we have
[TABLE]
We state now divergence formulas, one of the main tool of the present paper (see [BR16], Proposition B.1).
Lemma 7**.**
*For every compact in , there is a smooth function
such that for every , we have:*
[TABLE]
[TABLE]
and
[TABLE]
The following result is an immediate corollary of Lemma 7.
Lemma 8**.**
Let . For every subset in , we have
[TABLE]
Proof of Lemma 8.
Let be a subset in . By Lemma 6, there is a constant such that
[TABLE]
Therefore, by (26), we infer that, ,
[TABLE]
∎
The following result whose proof is based on the local contraction property, is fundamental.
Lemma 9**.**
Let . The closed set given by
[TABLE]
is of Lebesgue measure zero on .
Proof of Lemma 9.
Let be a subset of of positive Lebesgue measure. Without loss of generality, we can assume that is contained in an open set in . We argue by contradiction by assuming that
[TABLE]
By Lemma 5, there is an analytic horizontal vector field defined on generating singular minimizing geodesic defined on .
A$$\bullet$$x$$\mathcal{H}^{c}$$A^{S}_{t}$$\bullet$$\varphi^{X}_{\varepsilon t}(x)
Moreover, vanishes on . Then, for every , the flow of starting at requires an infinite time to reach , that is
[TABLE]
Let , we obtain that .
By Lemma (8), we have
[TABLE]
By (23), we obtain
[TABLE]
Hence,
[TABLE]
When , we obtain
[TABLE]
which implies the contradiction. ∎
In the spirit of [CH15], we have the following result.
Lemma 10**.**
Let , be two subsets of such that
- (i)
* and .* 2. (ii)
.
Then,
Proof of Lemma 10.
Set . We can assume that is contained in an open set in . Let . For every , we define
[TABLE]
Since , we have
[TABLE]
For fixed, we define .
A$$P^{2}(\Lambda_{2})$$P^{2}(\Lambda_{1})$$A^{S,\Lambda_{1}}_{t}$$A^{S,\Lambda_{2}}_{t}$$A^{\delta}
\geq\displaystyle{2\ exp\Bigl{(}-C\ l(A,t)\Bigr{)}\mathcal{L}^{4}(A)}.
Since , we have very close to . So we can choose
sufficiently small, that is
[TABLE]
Hence, we obtain ∎
We are ready to complete the proof of Proposition 2.
Consider the following set
and assume that has positive measure. It follows that there is such that the set given by
has positive Lebesgue measure.
Without loss of generality, we can assume that the manifold can be covered by finitely many open balls of diameter less or equal to . From , we construct a finite family of open sets pairwise disjoint covering by proceeding as follows
\left\{\begin{array}[]{lcl}\mathcal{V}_{1}&=&\mathcal{U}_{1}\\ \mathcal{V}_{2}&=&\mathcal{U}_{2}\textbackslash\mathcal{U}_{1}\\ &\vdots&\\ \mathcal{V}_{n}&=&\mathcal{U}_{n}\textbackslash(\mathcal{U}_{1}\cup\mathcal{U}_{2}\cup\dots\cup\mathcal{U}_{n-1})\\ &\vdots&\end{array}\right.
such that .
Therefore, for any , there are with such that
[TABLE]
Denote by
[TABLE]
and
[TABLE]
We notice that such that
[TABLE]
We also have since for any , , for . Using lemma 10, we obtain , which contradicts assumption .
We conclude that for a.e. is a singleton.
4 End of the proof of Theorem 1
In the previous sections, we have shown that
[TABLE]
and
[TABLE]
To complete the proof of Theorem 1, it remains to prove that
[TABLE]
For this purpose, we will use again the technique introduced by Cavalletti and Huesmann [CH15]. First, we will show a localized contraction property for regular horizontal curves.
Lemma 11**.**
There is a positive constant such that for and for every set in ,
[TABLE]
with
[TABLE]
Proof of Lemma 11.
Let be a compact set of of positive measure. Since (by Lemma 2), for every point of , there exists
such that
[TABLE]
so there is with verifying
[TABLE]
Let . As in section 2, we define the function
[TABLE]
For any , is locally semiconvex on . By the Alexandrov Theorem, is twice differentiable at a.e. . Moreover, there exists a constant such that
[TABLE]
where is the identity matrix.
We notice that . Denote by the constant given by
[TABLE]
Then,
[TABLE]
By section 2, for almost every , there exists a unique given by
[TABLE]
Then, the curve defined by
[TABLE]
is the unique regular minimizing geodesic joining to .
For every , we define the function
[TABLE]
Note that, , then we have
[TABLE]
However, the function results from the composition of the two following functions
[TABLE]
By computing the Jacobien of , we obtain
[TABLE]
Here, is smooth on and by (30), there is a constant such that
[TABLE]
By (31), this implies
[TABLE]
∎
We conclude with the following lemma.
Lemma 12**.**
* has Lebesgue measure zero on .*
Proof of Lemma 12.
Assume that there is a set of such that
[TABLE]
Let and . For every , we define the two following intermediate subsets by
[TABLE]
and
[TABLE]
For every , we have , then there is such that
[TABLE]
As a matter of fact, regular minimizing geodesics are analytic as projections of the analytic sub-Riemannian Hamiltonian system and singular minimizing geodesic are analytic as the analytic flow of . Without loss of generality, we can assume that there is such that for every
[TABLE]
and
[TABLE]
We denote by
[TABLE]
We may assume that has positive Lebesgue measure. Notice that for , when , and converge to , then one has
[TABLE]
where , for a given .
The inequality (33) follows from Lemmas 8 and 11 according to which we have
[TABLE]
As , we can choose sufficiently small, that is
[TABLE]
It implies that And the conclusion follows. ∎
Appendix A Proof of Lemma 1
For every , the function is locally Lipschitz with respect to the sub-Riemannian distance. Then, ,
[TABLE]
is also locally Lipschitz with respect to .
Fix , there are an open neighborhood of and an orthonormal family of vector fields such that , . By a change of coordinates if necessary, we can write the vector fields as the following form:
[TABLE]
By the Pansu-Rademacher theorem, since is absolutely continuous with respect to the Lebesgue measure, then is differentiable with respect to the vector fields , . Hence, we have:
[TABLE]
Let , be the integral flow associated to starting at . Then,
[TABLE]
Recall that , .
Then, , .
.
In particular, .
This implies that . Hence, , .
Assume now that there exists such that . Let
be a minimizing geodesic joining to .
, ,
For small enough, there is a contradiction since .
Appendix B Local semiconvexity
Let be a sub-Riemannian structure of rank on the manifold .
We recall here the definition of local semiconvexity of a given function.
Definition 3**.**
*A function , defined on the open set , is called locally semiconvex on if for every there exist a neighborhood of and a smooth diffeomorphism such that is locally semiconvex on the open subset .
By the way, we recall that the function is locally semiconvex on the open subset if for every there exist such that
[TABLE]
[TABLE]
where is the open ball in centered at with radius .
The following result is useful to prove the local semiconvexity of a given function.
Lemma 13**.**
Let be a function defined on an open set . Assume that for every , there exist a neighborhood of and a positive real number such that, for every , there is such that
[TABLE]
Then, the function is locally semiconvex on .
Proof of Lemma 13.
Let be fixed and be the neighborhood given by assumption. Without loss of generality, we can assume that is an open ball . Let and . The point belongs to . By assumption, there exists such that
[TABLE]
Hence, we easily get
[TABLE]
[TABLE]
[TABLE]
and the conclusion follows. ∎
Remark 2**.**
*Thanks to Lemma 13, a way to prove that a given function
is locally semiconvex on is to show that for every , we can put a support function of class under the graph of at with a uniform control of norm of .*
Let us derive another important consequence of the definition of semiconvexity.
Lemma 14**.**
Let be a subset of and be a family of functions defined on and semiconvex. Then, the function is also semiconvex on .
Proof of Lemma 14.
Take and .
Given any , we can find such that
[TABLE]
Then we have, for ,
[TABLE]
[TABLE]
[TABLE]
Since is arbitrary, we obtain the assertion. ∎
More details of local semiconvexity of a given function are given in the textbook [CS04].
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