Examples of non-autonomous basins of attraction
Sayani Bera, Ratna Pal, Kaushal Verma

TL;DR
This paper explores examples of non-autonomous basins of attraction in complex spaces, proving biholomorphic equivalences and constructing special types of Short ^k^k^k spaces with various geometric properties, advancing understanding of complex dynamical systems.
Contribution
It provides new examples of non-autonomous basins of attraction and constructs specific Short ^k^k^k spaces with desired properties, addressing questions related to Bedford's Conjecture.
Findings
Non-autonomous basins from pairs of automorphisms are biholomorphic to ^2.
Existence of (k-1) disjoint Short ^k^k^k in ^k for k \u2265 3.
Construction of a Short ^k that contains a Fatou-Bieberbach domain and avoids a codimension 2 algebraic variety.
Abstract
The purpose of this paper is to present several examples of non--autonomous basins of attraction that arise from sequences of automorphisms of . In the first part, we prove that the non-autonomous basin of attraction arising from a pair of automorphisms of of a prescribed form is biholomorphic to . This, in particular, provides a partial answer to a question raised in connection with Bedford's Conjecture about uniformizing stable manifolds. In the second part, we describe three examples of Short 's with specified properties. First, we show that for , there exist mutually disjoint Short 's in . Second, we construct a Short , large enough to accommodate a Fatou-Bieberbach domain, that avoids a given algebraic variety of codimension . Lastly, we discuss examples of Short…
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Taxonomy
TopicsMeromorphic and Entire Functions · Mathematical Dynamics and Fractals · Advanced Differential Equations and Dynamical Systems
Examples of non–autonomous basins of attraction
Sayani Bera, Ratna Pal and Kaushal Verma
Sayani Bera: Mathematics, Harish-Chandra Research Institute, HBNI, Allahabad-211019, India
Ratna Pal: Department of Mathematics, Indian Institute of Science, Bangalore 560012, India
Current Address: Department of Mathematics, Indian Institute of Science Education and Research, Pune, Maharashtra-411008, India
Kaushal Verma: Department of Mathematics, Indian Institute of Science, Bangalore 560012, India
Abstract.
The purpose of this paper is to present several examples of non–autonomous basins of attraction that arise from sequences of automorphisms of . In the first part, we prove that the non–autonomous basin of attraction arising from a pair of automorphisms of of a prescribed form is biholomorphic to . This, in particular, provides a partial answer to a question raised in [2] in connection with Bedford’s Conjecture about uniformizing stable manifolds. In the second part, we describe three examples of Short ’s with specified properties. First, we show that for , there exist mutually disjoint Short ’s in . Second, we construct a Short , large enough to accommodate a Fatou–Bieberbach domain, that avoids a given algebraic variety of codimension . Lastly, we discuss examples of Short ’s with (piece–wise) smooth boundaries.
1991 Mathematics Subject Classification:
Primary: 32H02 ; Secondary : 32H50
1. Introduction
Let be a holomorphic automorphism of a complex manifold equipped with a Riemannian metric, say . Suppose is an invariant compact set on which is uniformly hyperbolic. For , let be the stable manifold of through , i.e.,
[TABLE]
By the Stable manifold theorem, is an immersed complex submanifold, say of dimension and this turns out to be diffeomorphic to . The question of whether is biholomorphic to for every was raised by Bedford in [3]. While this is known to be true in several cases (see for example [14], [1] and [16]), a result of Fornæss–Stensønes in [11] shows that is biholomorphic to a domain in for every . This was done by studying a related question which, more importantly, is a reformulation of Bedford’s question:
Conjecture: Let be a sequence of automorphisms of satisfying
[TABLE]
for (the unit ball around the origin) and . Then the basin of attraction of at the origin defined as
[TABLE]
is biholomorphic to .
On the other hand, the necessity of having such uniform bounds for each on the unit ball was shown by Fornæss in [10]. In particular, if is a sequence of automorphisms of of the form
[TABLE]
where and , then the corresponding basin is not biholomorphic to since it was shown to admit a non-constant bounded plurisubharmonic function. Note that the ’s do not satisfy a uniform bound condition near the origin. In this case, can be written as the limit of an increasing union of domains each of which is biholomorphic to the unit ball in . Furthermore, the infinitesimal Kobayashi metric on vanishes identically. Thus, is neither all of nor a Fatou–Bieberbach domain. Such a domain was christened Short (or more generally, a Short if the domain sits in , ) in [10].
As explained in [10], the existence of such domains is intrinsically linked with a version of the Levi problem namely, to decide whether the union of an increasing sequence of Stein domains is Stein. A counterexample constructed by Fornaess [9] shows that this is not true in general if . However, in , Fornaess–Sibony [8] were able to classify those domains which arise as the increasing union of biholomorphic images of the ball and which additionally satisfy the property that the Kobayashi metric does not vanish identically. The other possibility is when the Kobayashi metric vanishes identically – and this is where Short ’s make their appearance.
The purpose of this paper is two fold. First, we will study a seemingly straightforward version of the conjecture mentioned above that was stated as Problem in [2]. We recall the statement below:
Problem: Let and be automorphisms of both having an attracting fixed point at the origin. Let be a sequence in which each is either or . Is the basin of attraction biholomorphic to ?
Furthermore in [2], the maps defined by
[TABLE]
where and (for example, let and ) were proposed as test cases to study. A moment’s thought shows that this problem reduces to studying the non–autonomous basin of attraction of the sequence where and
[TABLE]
This observation is used to prove the following result:
Theorem 1.1**.**
Let and be automorphisms of with an attracting fixed point at the origin such that the matrices and are as follows:
[TABLE]
with for some Then the basin of attraction of at the origin is biholomorphic to in the following cases:
- (i)
For every , is bounded, and 2. (ii)
For every , is bounded, and .
Moreover, we will use methods similar to those in [15] to obtain a related result for more specific automorphisms of .
Proposition 1.2**.**
Consider the automorphisms
[TABLE]
where for . Let be a sequence in which each is either or . Then the non–autonomous basin of attraction at the origin of is biholomorphic to .
Second, let us recall a classical result of Rosay–Rudin [17] which shows that if an automorphism of has an attracting fixed point, then the associated basin of attraction is a Fatou–Bieberbach domain. This result forms the basis of several examples of Fatou–Bieberbach domains with prescribed properties that were constructed by them in [17]. In the same vein, it is natural to ask whether it is possible to construct Short ’s with specified properties. In what follows, we provide several examples of Short ’s that satisfy additional properties – these being much in the spirit of what is known for Fatou–Bieberbach domains.
For the first example, recall that a shift–like map of type (where ) is an automorphism of given by
[TABLE]
where is an entire function on and . These maps were introduced and studied by Bedford–Pambuccian [4]. By working with suitable shift–like maps and the filtration they preserve, it is possible to create a mutually disjoint finite collection of Short ’s.
Theorem 1.3**.**
For , there exist Short ’s, say , , such that
[TABLE]
For the second example, recall that Hubbard–Buzzard [5] have constructed a Fatou–Bieberbach domain that avoids a given algebraic variety of codimension in for . Again, by working with suitable shift–like maps and by controlling the rate of convergence of their linear parts, we have:
Theorem 1.4**.**
Let , , be an algebraic variety of codimension . Then there exists a Short , say and a Fatou–Bieberbach domain, say such that .
Let us recall the methods of constructing a Short from [10]:
- •
Let be a sequence of automorphisms of of the form
[TABLE]
where and . Let and be defined as
[TABLE]
where
[TABLE]
Here, and in what follows is the standard projection map on the th coordinate for . Then for every , the –sublevel set of , i.e.,
[TABLE]
is a Short . Moreover, the sublevel set of is the non–autonomous basin of attraction for the sequence .
- •
Let be a Hénon map of the form
[TABLE]
Then for every , the –sublevel set of the positive Green’s function of , i.e.,
[TABLE]
is a Short .
Both and are known to be pluriharmonic on the sets
[TABLE]
respectively. Hence, by Sard’s theorem, for most values of in the admissible range, the –sublevel sets of either or are Short ’s with smooth boundary. However, this does not ensure that the [math]–sublevel set of , which is the non–autonomous basin of attraction at the origin, always has smooth boundary. In this regard, we have:
Theorem 1.5**.**
There exists a Short with –smooth boundary that arises as the non-autonomous basin of attraction for a sequence of automorphisms having an attracting fixed point at the origin.
This is motivated by Stensønes’s proof of the existence of Fatou–Bieberbach domains with –smooth boundary (see [18]). We follow a similar approach for Short ’s as well, namely we try to control the behaviour of the boundary on a large enough polydisc and then exhaust all of with polydiscs of increasing size. A construction of a Short with –smooth boundary on a fixed polydisc was also given by Console in [7].
By adopting some methods from Globevnik’s work [13] and [7], it is possible to retain boundary smoothness and at the same time avoid a given variety of codimension .
Theorem 1.6**.**
Let , , be an algebraic variety of codimension . Then there exists a sequence of automorphisms of with a common attracting fixed point, say such that the basin of attraction at is a piecewise smooth Short that does not intersect .
Acknowledgements: The authors would like to thank Greg Buzzard, Josip Globevnik and Han Peters for their encouragement and very helpful pointers.
2. Proof of Theorem 1.1 and Proposition 1.2
Let us recall the following from [15].
Definition 2.1**.**
Let be an automorphism of , having a fixed point at the origin such that is a lower triangular matrix. We say is correctly ordered if the diagonal entries of , i.e., (from upper left to lower right) satisfy the condition
[TABLE]
for and any
Definition 2.2**.**
A family of correctly ordered automorphisms of , is said to be uniformly attracting if there exist such that for every and
[TABLE]
and there exists such that
[TABLE]
for and any
Theorem 2.3** (Peters, H).**
Let be a uniformly attracting sequence of automorphisms of , Then the basin of attraction of at the origin is biholomorphic to
We will use the following version of this theorem which is valid when .
Let be a uniformly attracting sequence of automorphisms of and let , be the diagonal entries of . Since is a lower triangular matrix by assumption, and are the eigenvalues of . If there exists such that
[TABLE]
the basin of attraction of the sequence at the origin is biholomorphic to .
However, by assumption is a uniformly attracting sequence of automorphisms and hence there exists such that
[TABLE]
for each . Therefore (2.1) reduces to
[TABLE]
for some , where .
We will complete the proof of Theorem 1.1 by showing the existence of a suitable so that (2.2) holds.
Proof of Theorem 1.1.
It can be seen that
[TABLE]
and hence
[TABLE]
for all
It is sufficient to find a uniform so that
[TABLE]
for all . First, some reductions are in order. If for , then for all large enough . In this case, Rosay–Rudin [17] show that the basin of attraction of is all of We can therefore assume that for infinitely many ’s. The same reasoning applies to as well. Further, by the assumptions in Theorem 1.1 (i), there exists a uniform such that for all . There are two possibilities for , namely or depending on . If , we leave undisturbed. Else, if , let where . Observe that
[TABLE]
In other words, is the composition of maps, all of which are of the form with and . Therefore, it is possible to create a new sequence, still denoted by , from the given one so that
[TABLE]
We may assume, by rearranging the sequence if needed, that both and are maximal in their ranges for every . The boundedness of both and ensures that the sequence has a uniform bound on the rate of contraction on a sufficiently small ball around the origin.
Case 1: Suppose that . In this case, note that
[TABLE]
where the last inequality holds since . Here, in this case, we do not have to worry about how and are related.
Case 2: Suppose that . In this case, let be such that
[TABLE]
Note that . Then
[TABLE]
Simplifying the exponent of and noting that , the last term above is dominated by
[TABLE]
Hence, if then
[TABLE]
It remains to note that any such that works. This completes the proof of Theorem 1.1 (i).
Let
[TABLE]
where . Then
[TABLE]
and if
[TABLE]
and is bounded, a similar calculation applied to shows that the basin of attraction of is biholomorphic to .
The shaded regions in Figures (1(a)) and (1(b)) correspond to those sequences for which the non–autonomous basins are biholomorphic to
∎
Proof of Proposition 1.2.
By the given condition, there exists such that and , and each satisfies
[TABLE]
on a sufficiently small ball .
Now corresponding to the sequence , we will associate another sequence of automorphisms defined as
[TABLE]
Let be an automorphism of of the form
[TABLE]
where Also let be a sequence of polynomial endomorphisms of defined inductively by
[TABLE]
where means that the degree terms are truncated from the expression. A simple computation by expanding (2.3) gives
[TABLE]
for every , i.e., is a sequence of lower triangular automorphisms of It can be checked that
[TABLE]
if and
[TABLE]
otherwise. Let be a sequence of affine maps of defined as
[TABLE]
From [15], there exists a such that is bounded for every . If we let , then is a bounded sequence of automorphisms of
By Lemma 14 from [2], it follows that the basin of attraction of at the origin is biholomorphic to the basin of attraction of the sequence But the ’s are upper triangular maps with an attracting fixed point at the origin and hence the basin of attraction of at the origin is all of This completes the proof. ∎
3. Proof of Theorem 1.3
For and , consider the sequence of mappings
[TABLE]
where for every The non–autonomous basin of attraction of this sequence, i.e., will be a Short . The arguments used to prove this fact are similar to Fornæss ’s proof in [10]. However, we will briefly rewrite the proof for the sake of completeness.
Let denote the polydisk of radius at the origin and
[TABLE]
Theorem 3.1**.**
The set has the following properties:
- (i)
* is a non–empty open connected set.* 2. (ii)
, , and each is biholomorphic to the unit ball in 3. (iii)
The infinitesimal Kobayashi metric on vanishes identically. 4. (iv)
There exists a plurisubharmonic function such that
[TABLE]
Proof.
Let denote the polydisk of polyradius , Then
[TABLE]
for every , i.e., Pick such that and let
Claim: For , there exists large enough such that
Since for every ,
[TABLE]
for sufficiently large. So we get
[TABLE]
i.e.,
[TABLE]
Hence the claim is true.
Now define
[TABLE]
Then for sufficiently large , i.e., for every and ,
[TABLE]
uniformly on So we have But now note that if , then for sufficiently large , i.e., for large. Hence This proves statement (i).
Let Then for every , Note that for and for every , there exists such that
[TABLE]
i.e., Thus we have
[TABLE]
i.e., , which proves (ii).
Pick a point and Let and for every Note that , hence consequently, as Fix , a sufficiently large value. Now define maps from the unit disc as follows:
[TABLE]
Depending on , there exists such that for Let Note that Thus and Since it is possible to construct a map for every , it follows that the infinitesimal Kobayashi metric on vanishes.
Let
[TABLE]
i.e, denotes the th component at the th stage. Define the functions as:
[TABLE]
Lemma 3.2**.**
Let
[TABLE]
Then where is plurisubharmonic on
Proof.
There are two cases to consider:
Case 1: Let Since ,
[TABLE]
Case 2: Let Then
[TABLE]
Thus for every
[TABLE]
Now define
[TABLE]
Then is a monotonically decreasing sequence of plurisubharmonic functions and hence its limit will be plurisubharmonic. But note that and hence the proof. ∎
Lemma 3.3**.**
**
Proof.
Suppose , i.e., for large there exists such that
[TABLE]
This implies that for and sufficiently large or equivalently as Thus For the other inclusion suppose Then for large which implies that Suppose Then for every Then for sufficiently large ,
[TABLE]
Since is plurisubharmonic and there exists such that and for every , the subaveraging property of plurisubharmonic functions shows that in ∎
We will need the following observations about the sequence :
- (i)
Except the first one every component of is of the form 2. (ii)
For , there exists such that if and then for every
[TABLE] 3. (iii)
Each function is a composition of shift maps, i.e.,
[TABLE]
where, for
[TABLE]
and
[TABLE]
We will show that the filtration properties of shift–like maps in that were proved in [4], extend to our case as well.
Let and
[TABLE]
for Also let
[TABLE]
Observe that , and form a disjoint collection where union is all of
Lemma 3.4**.**
* for every *
Proof.
Let Then for some By (3.1)
[TABLE]
Now
[TABLE]
Hence is not contained in or , i.e., ∎
Also from the above proof, if , then for every and , i.e., Hence which proves that is not all of
Now we will show that is non–constant. Suppose not. Let on all of . Pick a point Choose such that and Let Since we know that
Now for sufficiently small , the value of should be bounded above by its average on the ball But now on and since is upper semicontinuous, i.e.,
[TABLE]
i.e.,
[TABLE]
where is the dimensional Lebesgue measure of Now as and , for
[TABLE]
Choose such that
[TABLE]
where As , 3.2 reduces to
[TABLE]
This is a contradiction and hence is non–constant on ∎
Thus we have proved that the non–autonomous basin of attraction at the origin of the sequence is a Short .
Now Theorem 1.3 follows as an application of Theorem 3.1 and Lemma 3.4.
Proof of Theorem 1.3.
By Theorem 3.1, there exists a positive real number and a Short , say such that is properly contained in , i.e., for every either
[TABLE]
For , let be the involution which interchanges the th coordinate and the th coordinate and fixes all others, i.e.,
[TABLE]
Let
[TABLE]
Note that each is a Short and Also, for a given constant , let denote the affine map of given by
[TABLE]
For every define as
[TABLE]
Claim: For every and ,
Suppose Pick . As , without loss of generality one can assume that
Since , it follows that and
Case 1: If , then
[TABLE]
In particular, and
[TABLE]
As , we have that
[TABLE]
Hence , i.e., But this means
[TABLE]
which is a contradiction. Therefore,
Case 2: If , then
[TABLE]
Now if then which is a contradiction. Hence But that will mean
[TABLE]
which is again a contradiction. Thus the claim follows and this completes the proof. ∎
4. Properties of shift–like maps and proof of Theorem 1.4
For , let and Let be be an algebraic variety of codimension in , . For , let
[TABLE]
and
[TABLE]
Being algebraic there exists (see [5], [6]) a complex linear map such that
Proposition 4.1**.**
Let , be an an algebraic variety of codimension Then there exists a short that avoids
Proof.
Let , , and be as obtained in the proof of Theorem 3.1. There exists a change of coordinates such that with Now we further compose this map with an affine map
[TABLE]
Claim:
It is enough to show that . Pick Then
[TABLE]
and for this point and
Case 1: If then
[TABLE]
i.e., and . Hence
Case 2: If , then two cases arise. Either , i.e., and a similar analysis as above shows that . Otherwise, for some if , then
[TABLE]
Hence , i.e.,
Thus for , is a Short which does not intersect the algebraic variety ∎
Remark 4.2*.*
Note that Proposition 4.1 does not apriori ensure that the Short contains a Fatou–Bieberbach domain. The known technique to construct a Short containing a Fatou–Bieberbach domain is to look at sub–level sets of the positive Green’s function of a Hénon map with an attracting fixed point.
To prove Theorem 1.4, we will study some properties of sub–level sets of Green’s function associated with a shift–like maps.
Let be a polynomial shift–like map of degree and type From [4] we know that the positive Green’s Function associated to is defined as:
[TABLE]
and the negative Green’s Function associated to is
[TABLE]
Recall from [4] that
[TABLE]
is a filtration and the set of zeros of the positive Green’s function is contained in the union of and i.e.,
[TABLE]
Proposition 4.3**.**
Let
[TABLE]
be a shift–like automorphism of of type and degree where Then for every there exists such that for every , , i.e.,
[TABLE]
Proof.
The th iterate of is:
[TABLE]
Suppose Then for For sufficiently large
[TABLE]
This can be rewritten as
[TABLE]
Claim: For every
[TABLE]
It is clear from the above calculations that the claim is true when Now assume that (4.3) is true for some We will show that it is true for Since and ,
[TABLE]
i.e., for some But now for every
[TABLE]
whereas from (4) and (4.2), it follows that
[TABLE]
hence for some Now from (4),
[TABLE]
Hence the claim is true.
Now there exists such that (4.3) can be further modified as
[TABLE]
Since for every and , (4.4) can be modified as
[TABLE]
It follows from (4.5) that
[TABLE]
Now can be appropriately modified such that (here is the given constant) for every , i.e.,
[TABLE]
or equivalently
[TABLE]
∎
As a corollary of Proposition 4.3, Proposition 4.1 we prove the following result:
Theorem 4.4**.**
For , let
[TABLE]
be a shift–like automorphisms of type in for some and For a given and an algebraic variety of codimension 2, there exists an appropriate change of coordinates such that the sublevel set of the positive Green’s function, i.e.,
[TABLE]
does not intersect in the new coordinate system.
Lemma 4.5**.**
Let be the sequence of automorphisms as in Theorem 3.1. If there exists such that , where , then is a Short .
Proof.
Let . Note that and
Induction statement: For every ,
The above statement is true for So assume it is true for some Then
[TABLE]
From the induction statement it follows that
[TABLE]
Hence from Theorem 3.1, it follows that is a Short . ∎
Now we can complete the proof of Theorem 1.4.
Proof of Theorem 1.4..
Choose and let be a sequence of automorphisms of defined as follows:
[TABLE]
where Then
[TABLE]
From Lemma 4.5, it follows that is a Short . Moreover from Proposition 4.1, for a given algebraic variety of codimension 2, there exists an appropriate linear change of coordinates (say ) of such that does not intersect
Claim: contains a Fatou–Bieberbach domain.
Consider the shift–like automorphism of given by
[TABLE]
Clearly the basin of attraction of at the origin (say ) is a Fatou–Bieberbach domain by Rosay–Rudin ([17]).
For a given constant , let denote the linear map from to given by
[TABLE]
Note that
[TABLE]
Then for , there exists sufficiently large such that , i.e.,
[TABLE]
Thus is a Fatou–Bieberbach domain contained in . The Short and Fatou–Bieberbach domain claimed in Theorem 1.4 are then and respectively. ∎
5. Controlling the boundary of a Short on a fixed polydisk
In this section, we will construct a Short , with some control on its boundary on a fixed polydisk. Theorem 5.10 is the main statement here – it shows the existence of a Short , whose boundary is very close to faces of the polydisk. In addition, this Short is almost a cylinder along the remaining direction. We will use some ideas from [12], [13] and [7].
First recall the following lemma from [13] and [7].
Lemma 5.1**.**
For a given , and , there exists such that if , then
[TABLE]
where \phi_{\alpha}\in{C}^{l}\big{(}\partial\Delta\times\overline{\Delta(0;R)}\big{)}. Moreover,
A proof of this for can be found in [13]. For , this was observed in [7] – See Lemma 5.3.4 therein.
It follows that if , then
[TABLE]
As in Section 2, let
[TABLE]
which is an automorphism of for any . For a sequence of automorphisms of , let and denote the following maps
[TABLE]
where Also for a given and a compact subset (say ) of we will denote the tube around by , i.e.,
[TABLE]
Lemma 5.2**.**
For a given , and there exists such that for every there exists \phi_{\alpha}\in{C}^{l}\big{(}\partial\Delta\times\overline{\Delta(0;R)}\big{)} with the following properties:
- (i)
Let (z_{1},z_{2},\ldots,z_{k})\in F_{\alpha}^{-1}\big{(}\Delta^{k}(0;1)\big{)}\cap\overline{\Delta^{k}(0;R)}. Then for every , the value of depends on recursively in the following way: for every and
[TABLE]
where , .
- (ii)
F_{\alpha}^{-1}\big{(}\partial\Delta^{k}(0;1)\big{)}\cap\overline{\Delta^{k}(0;R)}\subset N_{k\epsilon}\big{(}\overline{\Delta(0;R)}\times\partial\Delta^{k-1}(0;{1})\big{)}.**
Proof.
Let such that . If then
[TABLE]
From Lemma 5.1, there exists such that for every
[TABLE]
if for every . Here , , \phi_{\alpha}\in{C}^{l}\big{(}\partial\Delta\times\overline{\Delta(0;R)}\big{)} and
[TABLE]
Since , for every . Hence (i) follows.
For a fixed , , define
[TABLE]
From (5.2), the set F_{\alpha}^{-1}\big{(}\partial\Delta^{k}(0;1)\big{)}\cap\overline{\Delta^{k}(0;R)} can be realized as
[TABLE]
Also can be written as the union of its faces, i.e.,
[TABLE]
where
[TABLE]
for a fixed , . Now from the bound on it follows that the distance between and is less than . Thus (ii) follows. ∎
Remark 5.3*.*
The function obtained in Lemma 5.1 is actually a positive smooth function with
[TABLE]
Remark 5.4*.*
Using this, the conclusion of Lemma 5.2 can be improved slightly, i.e.,
[TABLE]
The next result is Lemma 5.3.5 from [7]. We will include the proof for the sake of completeness. Before stating the result, we introduce certain notations. Suppose is a sequence of automorphisms as in (5.1). For and , let
[TABLE]
and
[TABLE]
From Theorem 1.4 we know that is a Short if and and it is the non–autonomous basin of attraction of the sequence at the origin.
Lemma 5.5**.**
Fix . For a given compact connected set and , there exists such that if then \partial\Omega_{n,c}\cap K\subset N_{\epsilon}\big{(}\partial\Omega_{n,1}\cap K\big{)}.
Proof.
Let and V_{\epsilon}=F(n)\big{(}N_{\epsilon}(\partial\Omega_{n,1})\big{)}. Note that
[TABLE]
and that is an open cover of Then for every there exists such that The collection as varies in forms an open cover of . Since is compact there exists such that
[TABLE]
Let \tau_{1}=\min\Big{\{}\frac{r_{z_{i}}}{k}:1\leq i\leq N_{0}\Big{\}}. Let
[TABLE]
If , the distance between and is at most Thus and \partial\Omega_{n,c}\subset N_{\epsilon}\big{(}\partial\Omega_{n,1}\big{)}.
Now by the connectedness of , there exists such that if , the distance between and is at most . Let Hence, for every such that ,
[TABLE]
∎
Let . Suppose there exist real positive constants such that for every . Then this finite collection can be extended to a infinite sequence such that for every . This extension is evidently not unique. However, the basin of attraction of the sequence of automorphisms , where is a Short . Here, we will show that if there exist automorphisms such that we can control the following:
- (i)
the behaviour of on a large polydisk, 2. (ii)
the behaviour of for a collection of increasing real constants , and 3. (iii)
the behaviour of , where is the basin of attraction of the sequence obtained by some appropriate extension of the collection ,
then the finite collection of automorphisms can be appended with such that the collection will also satisfy the above three properties. Essentially our target is to show that we can inductively control appropriate these domains. This phenomenon is stated in the following result:
Proposition 5.6**.**
Suppose for some , there exist automorphisms of , with the following properties.
- (a)
For a given
[TABLE]
- (b)
*For every , there exist **increasing constants and *sequences
[TABLE]
such that if where
[TABLE]
for , then
[TABLE]
where is the basin of attraction of at the origin.
Then for a given , there exists and such that
- (i)
For where ,
[TABLE]
and
[TABLE]
- (ii)
* is contained in the *neighbourhood of , i.e.,
[TABLE]
- (iii)
There exists a sequence of positive real numbers such that if for every where
[TABLE]
and is the basin of attraction of at the origin, then
[TABLE]
Proof.
Fix such that F(n)\big{(}\overline{\Delta^{k}(0;R)}\big{)}\subset\subset\overline{\Delta^{k}(0;R_{n})}. By continuity of , for there exists such that for ,
[TABLE]
whenever
By Lemma 5.2, there exists such that if and , then
[TABLE]
and
[TABLE]
Looking at the proof of the above fact, we see that the neighbourhood is obtained by keeping the coordinate fixed. Hence (5.3) can be rewritten as
[TABLE]
This exactly means that
[TABLE]
Since the automorphisms satisfy condition (a),
[TABLE]
i.e.,
[TABLE]
As \overline{\Delta^{k}(0;R)}=F(n)^{-1}\circ F(n)\big{(}\overline{\Delta^{k}(0;R)}\big{)}, the above expression further simplifies as
[TABLE]
Now by continuity of , we have
[TABLE]
which using (5.4) says that
[TABLE]
This completes the proof of (i).
From Lemma 5.5, there exists such that for every
[TABLE]
Thus for , property (ii) is proved.
Now as in the proof of Theorem 3.1, note that if the ’s are chosen sufficiently small, i.e., for every , then there exists such that
[TABLE]
So for , if
[TABLE]
then
[TABLE]
This proves property (iii). ∎
Remark 5.7*.*
Note that the proof of Proposition 5.6 ensures that if , then
[TABLE]
also.
Let us recall the following definitions from [12]. For a given and for every , let
[TABLE]
Definition 5.8**.**
Fix . For a given and , let
[TABLE]
We will refer to this as the graph over given by
Definition 5.9**.**
Fix . For a given and , let
[TABLE]
This is called the standard domain over given by
Fix . For a given , and the neighbourhood of is the collection of all smooth functions such that
[TABLE]
Now using the above results appropriately it is possible to control the boundary of a Short on a large enough polydisk. This is stated as follows:
Theorem 5.10**.**
For given and an , there exists a Short , say such that:
- (i)
*For every , there exists such that is an -small *perturbation of 2. (ii)
For every , is the intersection of standard domains over given by ’s, i.e.,
[TABLE] 3. (iii)
* is contained in an *perturbation of , i.e.,
[TABLE]
Proof.
For every , let denote the constant function on , i.e.,
[TABLE]
and for every
Induction statement: For a given , there exist automorphisms of , say () such that:
- (i)
where for
- (ii)
For every and ,
[TABLE]
is given by the graph of where
[TABLE]
- (iii)
For every and , is increasing, i.e.,
[TABLE]
- (iv)
There exist such that and for every ,
[TABLE]
- (v)
For every , there exist sequences such that for every , if where
[TABLE]
and is the basin of attraction of the sequence , then
[TABLE]
Initial case: This corresponds to
Note that by Lemma 5.2 and 5.5, there exist and such that satisfies properties (i), (ii) and (iv) above. Also, from Remark 5.3, satisfies property (iii) as well.
Now using the same arguments as in the proof of property (iii) of Proposition 5.6, there exists a sequence such that if for every , where and is the basin of attraction of the sequence , then
[TABLE]
for every
So we may assume that the above conditions are true for some .
General case: Let be such that
[TABLE]
Recall Lemma 2.1 from [12].
Lemma 5.11**.**
Let and Let be a holomorphic automorphism of and let be so large that
[TABLE]
Let and assume that is a graph over Then for a given , there exists a such that if is a graph over in the neighbourhood of , then is smooth graph over belonging to the neighbourhood of
For , let . By assumption, each is a graph over Then for , there exists such that Lemma 5.11 is true for the automorphism with
Now choose
By applying Lemma 5.2 on , there exists such that if where , then for every
[TABLE]
is in the neighbourhood of Also from Proposition 5.6, there exists such that if , where , there exists such that
[TABLE]
and
[TABLE]
Choose
By assumption, is actually a smooth graph over , i.e., in particular a smooth graph over . Hence by Lemma 5.11, is a smooth graph over . Let denote the function for this graph and by the choice of , it is assured that for every ,
[TABLE]
Observe that for every , by Remark 5.3, is a smooth graph in Also is a graph over and is a smooth function. Hence
Note that by construction satisfies condition (5.5) and (5.6), for So satisfies properties (i), (ii) and (iv) of the induction statement.
From Remark 5.3, it follows that for every ,
[TABLE]
Hence property (iii) is also satisfied, i.e., for every
[TABLE]
Now as observed in the proof of Proposition 5.6, the sequence can be appropriately chosen such that if for every , where
[TABLE]
and is the basin of attraction of the sequence at the origin, then
[TABLE]
Thus the induction statement is true for every
So we have a sequence of automorphisms such that the following is true for every :
- •
The basin of attraction of at the origin, i.e., is a Short .
- •
There exists an increasing sequence such that and
[TABLE]
- •
By Remark 5.7,
[TABLE]
for every , if .
- •
For every , there exists an increasing sequence of positive functions such that
[TABLE]
and
[TABLE]
Case 1: Suppose for every Then from Theorem 3.1, there exists such that
[TABLE]
So
[TABLE]
But
[TABLE]
and as Hence
[TABLE]
Case 2: Suppose as In this case, for every
[TABLE]
Notice that by choice and . Hence
[TABLE]
i.e.,
[TABLE]
So
[TABLE]
and as Hence
[TABLE]
Now for every and for a fixed , the sequence of functions is an increasing Cauchy sequence in . Since is a Banach space and as , for every , i.e., for every Also
[TABLE]
i.e.,
[TABLE]
for every and
[TABLE]
Hence taking limits as on both sides,
[TABLE]
But is contained in the neighbourhood of , i.e., in , so we have that
[TABLE]
Note that by construction, for every ,
[TABLE]
i.e.,
[TABLE]
and this completes the proof. ∎
Corollary 5.12**.**
There exists a Short , say and a bounded domain which embeds holomorphically in .
Proof.
Consider the subspace of given by
[TABLE]
Let be the Short obtained from Theorem 5.10 and let be the component of which contains the origin. From Theorem 5.10, it follows that is an perturbation of the unit polydisk where is sufficiently small. ∎
6. Proof of Theorem 1.5 and Theorem 1.6
The main idea here is to use Theorem 5.10 for polydisks of increasing radii in , We will follow the same notations from Section 4. First we prove Theorem 1.5, i.e., when
Proof of Theorem 1.5.
Choose and a sequence of strictly increasing positive real numbers such that Let denote the constant function on all of , then for every ,
[TABLE]
Let for every
Induction statement: For a given , there exist automorphisms of , say () such that
- (i)
, where for
- (ii)
There exist increasing positive real numbers such that
[TABLE]
for every . Here Also
[TABLE]
- (iii)
For every and there exist functions r_{i}^{j}\in{C}^{\infty}\big{(}P_{2}(R_{i+1}^{\prime})\big{)} whose graphs over are the sets
[TABLE]
- (iv)
For every and ,
[TABLE]
and
[TABLE]
Moreover , i.e.,
- (v)
There exist such that and for every and ,
[TABLE]
- (vi)
For every , there exist sequences such that
[TABLE]
for and corresponding automorphisms with the property that if is the basin of attraction of the sequence at the origin, then
[TABLE]
Initial case: Suppose
By Lemma 5.2, for , and , there exists such that satisfies (i) and (ii) above. Let be such that
[TABLE]
But and hence (iii) holds by definition. Also, (iv) is vacuous, since is not yet defined. By Lemma 5.5, if K=F_{0}^{-1}\big{(}\overline{\Delta^{2}(0;R_{1}^{\prime})}\big{)}, there exists such that (v) holds.
Finally, as in Theorem 5.10, the same arguments as in the proof of property (iii) of Proposition 5.6, there exists a sequence such that if for every , where and is the basin of attraction of the sequence at the origin, then
[TABLE]
for every Hence satisfies all of (i)–(vi).
By induction we may assume that the above properties are true for some
General Case: By the induction hypothesis, there exists such that
[TABLE]
By Lemma 5.2, for , and , there exists such that if where , the above properties (i) and (ii) are true. Pick such that
[TABLE]
Also for every , pick such that
[TABLE]
Note that by definition is the graph Further, from the induction hypothesis,
is a graph over for every
For a fixed , , by an application of Lemma 5.11 on for , there exists a such that if is a graph over which lies in the neighbourhood of , then is a graph on . Moreover, lies in the neighbourhood of Now applying Lemma 5.2 repeatedly on each , there exists such that for , the set
[TABLE]
is the graph of a smooth function on Also, for every
[TABLE]
Let where
[TABLE]
Hence from Lemma 5.11, there exists such that
[TABLE]
and
[TABLE]
Moreover, by construction
[TABLE]
for and which is also a graph. From Remark 5.3 and the fact that , the sequence satisfies all the properties (i)–(iv).
For properties (v)–(vi) we will use the same arguments as in the proof of the initial case. Let
[TABLE]
Then by Theorem 5.5, there exists such that (v) holds. Finally, by imitating the argument in the proof of Proposition 5.6(iii) there exists a sequence such that for if where
[TABLE]
and is the basin of attraction of at the origin, then
[TABLE]
for To conclude, the induction statement is true for every Therefore we have a sequence of automorphisms such that the following is true for every .
- •
The basin of attraction of at the origin, i.e., is a Short .
- •
There exists an increasing sequence such that and
[TABLE]
- •
There exists an increasing sequence of compact sets, i.e, such that
[TABLE]
- •
By Remark 5.7,
[TABLE]
for every if
- •
For every , there exists an increasing sequence of positive functions such that
[TABLE]
[TABLE]
and
[TABLE]
To summarize
[TABLE]
for a fixed and for every . Here is a Cauchy sequence in . Since is complete, on Now following the same arguments as in the proof of Theorem 5.10,
[TABLE]
for a fixed . Also from (6.1), it follows that
[TABLE]
Hence F(p)^{-1}\big{(}\Gamma^{2}_{r_{p}}(R_{p+1}^{\prime})\big{)} is a smooth hypersurface on But note that the above arguments are true for every and is an exhaustion of . Hence, the boundary of is smooth in ∎
By extending these arguments to , in exactly the same manner as in the proof of Theorem 5.10, it is possible to obtain a Short whose boundary lies in the intersection of smooth hypersurfaces.
However, to complete the proof of Theorem 1.6, we will need to do a little more work. Recall the definition of a piecewise smooth pseudoconvex domain in ,
Definition 6.1**.**
Let and for be pseudoconvex domains in with boundary in Let be a defining function for i.e.,
[TABLE]
such that on . Then
[TABLE]
is a piecewise smooth pseudoconvex domain if
[TABLE]
on for every
Proof of Theorem 1.6.
The proof is divided into three steps.
Step 1: For a given algebraic variety of codimension 2 in , , Theorem 4.1 shows that for a given and for every ,
- •
There exists an appropriate change of coordinates, say such that
[TABLE]
- •
There exists a sequence of automorphisms of the form such that the non–autonomous basin of attraction at the origin, say is a Short . Further,
[TABLE]
Here , and are as defined in Section 2. Hence to complete the proof we only need to construct an appropriate sequence of automorphisms of the form
Step 2: We follow the arguments in Theorem 1.5 in , with intersections of graphs at each stage. The preliminary step will be the same as in Theorem 5.10. Then it is possible to construct a sequence of automorphisms and an exhaustion of , i.e., such that each
[TABLE]
where is the basin of attraction of at the origin, for every and is a strictly increasing sequence of positive real numbers. But now this observation is true for every and is increasing i.e., . Hence the domain is a Short whose boundary lies in the intersection of smooth hypersurfaces.
Step 3: Recall that is the standard domain of over . Let
[TABLE]
for each
Claim: is a smooth pseudoconvex domain for every
Note that for every and
[TABLE]
where and . So locally is a smooth defining function.
By construction, for a fixed and for a given arbitrarily small , we have that
[TABLE]
Case 1: For when
[TABLE]
i.e.,
[TABLE]
Case 2: For
[TABLE]
for some . When by similar computations we see that
[TABLE]
i.e., there exists such that
[TABLE]
Since as , it follows that if , then
[TABLE]
from (6.2)– (6.6). Since is an exhaustion of , is a pseudoconvex domain.
Observe that the basin of attraction of is the intersection of the domains where , i.e.,
[TABLE]
Lastly, by the same arguments as above and from (6.2)–(6.6)
[TABLE]
on \{w\in F(p)\big{(}\partial\Omega\cap K_{p}\big{)}:\rho_{p}^{i_{1}}=\rho_{p}^{i_{2}}=\cdots=\rho_{p}^{i_{l}}=0\} for every whenever . This completes the proof. ∎
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