Carlsson's rank conjecture and a conjecture on square-zero upper triangular matrices
Berrin \c{S}ent\"urk, \"Ozg\"un \"Unl\"u

TL;DR
This paper explores a stronger conjecture related to Carlsson's rank conjecture, focusing on varieties of square-zero upper-triangular matrices, and proves it in specific cases, providing new insights and proofs for existing conjectures.
Contribution
It introduces a stronger conjecture involving matrix varieties and proves it for certain parameters, extending known results on Carlsson's conjecture.
Findings
Stronger conjecture holds when N<8 or r<3
New proofs for many cases of Carlsson's conjecture
Results for N>4 and r=2
Abstract
Let be an algebraically closed field and the polynomial algebra in variables with coefficients in . In case the characteristic of is , Carlsson conjectured that for any --module of dimension as a free -module, if the homology of is nontrivial and finite dimensional as a -vector space, then . Here we state a stronger conjecture about varieties of square-zero upper-triangular matrices with entries in . Using stratifications of these varieties via Borel orbits, we show that the stronger conjecture holds when or without any restriction on the characteristic of . As a consequence, we attain a new proof for many of the known cases of Carlsson's conjecture and give new results when and .
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Carlsson’s rank conjecture and a conjecture on square-zero upper triangular matrices
BERRİN ŞENTÜRK and ÖZGÜN ÜNLÜ
Department of Mathematics, Bilkent University, Ankara, 06800, Turkey.
[email protected] ](mailto:%[email protected]%20)
Abstract.
Let be an algebraically closed field and the polynomial algebra in variables with coefficients in . In case the characteristic of is , Carlsson [9] conjectured that for any --module of dimension as a free -module, if the homology of is nontrivial and finite dimensional as a -vector space, then . Here we state a stronger conjecture about varieties of square-zero upper triangular matrices with entries in . Using stratifications of these varieties via Borel orbits, we show that the stronger conjecture holds when or without any restriction on the characteristic of . As a consequence, we obtain a new proof for many of the known cases of Carlsson’s conjecture and give new results when and .
Key words and phrases:
rank conjecture, square-zero matrices, projective variety, Borel orbit
2010 Mathematics Subject Classification:
55M35 , 13D22, 13D02
The second author is partially supported by TÜBA-GEBİP/2013-22
1. Introduction
A well-known conjecture in algebraic topology states that if acts freely and cellularly on a finite CW-complex homotopy equivalent to , then is less than or equal to . This conjecture is known to be true in several cases: In the equidimensional case , Carlsson [8], Browder [6], and Benson-Carlson [5] proved the conjecture under the assumption that the induced action on homology is trivial. Without the homology assumption, the equidimensional conjecture was proved by Conner [11] for , Adem-Browder [1] for or , and Yalçın [25] for , . In the non-equidimensional case, the conjecture is proved by Smith [23] for , Heller [13] for , Carlsson [10] for and , Refai [20] for and , and Okutan-Yalçın [19] for products in which the average of the dimensions is sufficiently large compared to the differences between them. The general case is still open.
Let and be an algebraically closed field of characteristic . Assume that acts freely and cellularly on a finite CW-complex homotopy equivalent to a product of spheres. One can consider the cellular chain complex as a finite chain complex of free -modules whose homology is a -dimensional -vector space. Hence, a stronger and purely algebraic conjecture can be stated as follows: If is a finite chain complex of free -modules with nonzero homology then . However, Iyengar-Walker in [15] disproved this algebraic conjecture when , but the algebraic version for remains open.
Let be a graded ring. A pair is a differential graded -module if is a graded -module and is an -linear endomorphism of that has degree and satisfies . Moreover, a --module is free if the underlying -module is free.
Let be the polynomial algebra in variables, where is a field and each has degree . Using a functor from the category of chain complexes of -modules to the category of differential graded -modules, Carlsson showed in [7], [9] that the above algebraic conjecture is equivalent to the following conjecture when the characteristic of is :
Conjecture 1**.**
Let be an algebraically closed field, the polynomial algebra in variables with coefficients in , and a positive integer. If is a free --module of rank whose homology is nonzero and finite dimensional as a -vector space, then .
When the characteristic of is , Conjecture 1 was proved by Carlsson [10] for and Refai [20] for . Avramov, Buchweitz, and Iyengar in [4] dealt with regular rings and in particular they proved Conjecture 1 for without any restriction on the characteristic of . See also Proposition and Corollary in [2], Theorem in [24] for results in characteristic not equal to .
In this paper we consider the conjecture from the viewpoint of algebraic geometry. We show that Conjecture 1 is implied by the following in Section 2:
Conjecture 2**.**
Let be an algebraically closed field, a positive integer, and an even positive integer. Assume that there exists a nonconstant morphism from the projective variety to the weighted quasi-projective variety of rank square-zero upper triangular matrices with for some -tuple of nonincreasing integers . Then .
We will give a more precise statement of Conjecture 2 in Section 3 after discussing necessary definitions and notation. We propose the following, which is stronger than Conjecture 2:
Conjecture 3**.**
Let , , , and be as in Conjecture 2. Assume and the value of at every point in the image of is [math] whenever or . Then .
Note that in Conjecture 3 we have because and . The main result of the paper is a proof of Conjecture 3 when or , see Theorem 2 and Theorem 3. As Conjecture 3 is the strongest conjecture mentioned above, we obtain proofs of all the conjectures in this introduction under the same conditions, including the main result of Carlsson in [9]. Also note that for , taking gives novel results not covered in the literature. However, when the characteristic of the field is not , Iyengar-Walker [15] gave a counterexample to Conjecture 1 for each . Hence by Section 2, we can say that Conjectures 2 and 3 are also false when and the characteristic of the field is not . All these conjectures are still open in case the characteristic of is . In Section 4, we conclude with examples and problems.
We thank the referee for giving us extensive feedback, a shorter proof of Theorem 1 and encouraging us to extend our results to fields with characteristics other than . We are also grateful to Matthew Gelvin for comments and suggestions.
2. Some notes on Conjectures 1, 2, and 3
To show that Conjecture 3 is the strongest conjecture in Section 1, it is enough to prove the following theorem.
Theorem 1**.**
Conjecture 2 implies Conjecture 1.
Proof.
Let , , and be as in Conjecture 1. Let be a free --module of rank which satisfies the hypothesis in Conjecture 1. Without loss of generality, we can assume that is the smallest rank of all such --modules.
Suppose the image of the differential is not contained in . Then, there exists a basis of and there are some and so that for some non-zero and some . Replacing with gives a new basis such that . Now form the acyclic sub---module of spanned by , . The map is a surjective quasi-isomorphism and is free of rank . This is a contradiction. Hence, the image of the differential is contained in .
Now pick any basis of such that . Let m be such that and for all . For each , we have , for some homogeneous polynomials . Since the image of is contained in , no is a non-zero constant. Thus, whenever is non-zero, we have and hence . It follows that the differential on restricts to one on the submodule
[TABLE]
More precisely, for all we have where each nonzero is a linear polynomial. Hence, relative to the basis , the differential on is given by a matrix in the form where each is an matrix with entries in . Since we have and for all i,j. In case the characteristic of the field is , by a classical result about commuting set of matrices, for example see Theorem on page in [14], there exists an invertible matrix with coefficients in such that is upper triangular for all . In case the characteristic of the field is not , for every polynomial in noncommutative variables, the square of the matrix is zero. Therefore, by a theorem of McCoy as stated in [22](see also [12], [17]), again there exists a matrix as above which simultaneously conjugates all ’s to upper triangular matrices. In other words, there is a -linear change of basis in which each is upper triangular. It follows that, relative to this new basis of one has for all . Note that is a free --module whose differential has an image in and so, by inductive arguments on rank, we may assume that admits a basis which makes its differential upper triangular. The union of any lift of this basis to with the basis gives a basis for where is represented by an upper triangular matrix . Moreover, Propositions and in [10] work for any characteristic. Hence is divisible by and for any in the evaluation of at gives a matrix of rank .
Let be the polynomial algebra with . For , replace with in to obtain . Note that can be considered as a nonconstant morphism from the projective variety to the weighted quasi-projective variety of rank square-zero upper triangular matrices with where degree of the th element in . ∎
3. Varieties of square-zero matrices
We assume that is an algebraically closed field, a positive integer, , and an -tuple of nonincreasing integers.
3A. Statements of conjectures
We give here the notation for the affine and projective varieties used to prove the conjectures discussed above. First we fix an affine variety , a ring , and a subvariety as follows:
- •
is the affine variety of strictly upper triangular matrices over .
- •
is the coordinate ring of .
- •
is the subvariety of square zero matrices in .
Define an action of the unit group on by for . Using this action we set two more notation.
- •
is the weighted projective space given by the quotient of by the action of .
- •
is the homogeneous coordinate ring of . In other words, is considered as a graded ring with .
Note that the polynomial in is homogeneous of degree whenever . Similarly, the -minors of are homogeneous polynomials in . Hence, we define two subvarieties of as follows:
- •
is the projective variety of square zero matrices in .
- •
is the subvariety of matrices of rank less than in .
We can use this terminology to restate Conjecture 2:
Conjecture 4**.**
Let be an algebraically closed field, a positive integer, and an -tuple of nonincreasing integers. If there exists a nonconstant morphism from the projective variety to the quasi-projective variety , then .
Let be an open subset of . We say is a nonconstant morphism if is represented by so that the following conditions are satisfied:
- (I)
there exists a positive integer so that each is a homogeneous polynomial in the variables in of degree for , 2. (II)
for every there exists such that .
In particular, if is a nonconstant morphism, can be considered as a function from to represented by a nonconstant polynomial map from to the cone over such that does not contain the zero matrix in . Each indeterminate can be viewed as homogeneous polynomial in . Hence for we define an important subvariety of :
- •
is the subvariety of given by the equations for or .
Now we restate the Conjecture 3 as follows:
Conjecture 5**.**
Let be an algebraically closed field, a positive integer, and an -tuple of nonincreasing integers. If there exists a nonconstant morphism from the projective variety to the quasi-projective variety , then .
Hence, these varieties are the main interest in this paper.
3B. Action of a Borel subgroup on
Here we introduce an action of a Borel subgroup in the group of invertible matrices on the varieties discussed in the previous subsection. First we set a notation for the Borel subgroup.
- •
is the group of invertible upper triangular matrices with coefficients in .
The group acts on by conjugation.
- •
denotes the set of orbits of the action of on .
- •
denotes the -orbit that contains .
A partial permutation matrix is a matrix having at most one nonzero entry, which is , in each row and column. A result of Rothbach (Theorem in [21]) implies that each -orbit of contains a unique partial permutation matrix. Hence we introduce the following notation:
- •
denotes the set of nonzero strictly upper triangular square-zero partial permutation matrices.
There is a one-to-one correspondence between and sending to . We can identify these partial permutation matrices with a subset of the symmetric group :
- •
is the set of involutions in ; i.e., the set of non-identity permutations whose square is the identity .
For and ,
- •
denotes the permutation in that sends to if ;
- •
denotes the partial permutation matrix in that satisfies if and only if and .
Clearly the assignments and are mutual inverses and so define a one-to-one correspondence between and .
3C. A partial order on the set of orbits
There are important partial orders on , , , all of which are equivalent under the one-to-one correspondence mentioned above (cf. [21]). We begin with . For Borel orbits ,
- •
means the closure of , considered as a subspace of , contains .
Second, we define a partial order on . To do this, we consider ranks of certain minors of partial permutation matrices. In general, for an matrix ,
- •
denotes the rank of the lower left submatrix of , where .
For partial permutation matrices ,
- •
means for all .
Third, we define a partial order on . For positive integers , let denote the product of the permutations and and the conjugate of by . For ,
- •
if can be obtained from by a sequence of moves of the following form:
- –
Type I replaces with if and .
- –
Type II replaces with if .
- –
Type III replaces with if .
- –
Type IV replaces with if .
- –
Type V replaces with if .
The idea of describing order via these moves comes from [16]. Although we use different names for moves, the set of possible moves are same. We represent a permutation in by the matrix
[TABLE]
For example, we draw the Hasse diagram of in which each edge is labelled by the type of the move it represents:
When , the Hasse diagram for is too large to draw here. We are actually only interested in a small part of this diagram, which we discuss in Section 3F.
One can consider Figure 1 as a stratification of . In the next section, we use the stratification of to stratify .
3D. Stratification of
For an -tuple of nonincreasing integers, , and , we have
[TABLE]
where denotes the diagonal matrix with entries and is the scalar matrix with all diagonal entries . Let be the unique partial permutation matrix in the Borel orbit of . Consider such that
[TABLE]
Let be the diagonal matrix whose entry is if for some and otherwise. Then we have
[TABLE]
Hence, we have
[TABLE]
where is in . Thus, for any there exists a well-defined Borel orbit in that contains a representative of in . Hence we can set the following notation. For ,
- •
denotes the Borel orbit in that contains a representative of in .
Let be a nonconstant morphism. There is a lift of this morphism to a morphism from to the cone over that can be extended to a morphism . Since is an irreducible affine variety, there exists a unique maximal Borel orbit among the Borel orbits that intersects the image of nontrivially. Note that this maximal Borel orbit is independent of the lift and extension we selected because it is also maximal in the set . Hence we may associate a permutation to the nonconstant morphism :
- •
is the permutation that corresponds to the unique maximal Borel orbit where is in the image of .
Note that every point in the image of a morphism as above must have rank . Hence must be a product of distinct transpositions. In Section 3F, we will restrict our attention to such permutations.
3E. Operations on polynomial maps from to
Another way to see that is well-defined for is to consider the fact that a minor of a representative of is zero if and only if the corresponding minor of another representative is zero. We use this fact several times to prove our main result. Hence we introduce the following notation. For ,
- •
denotes the determinant of the submatrix obtained by taking the , rows and columns of .
First note that can be considered as a morphism from to , and hence can be composed with the morphism mentioned in the previous subsection. Here we discuss several other morphisms that we can compose with such morphisms. For ,
- •
is the function that takes a square matrix and multiplies the row of by and adds it to the row of while multiplying the column of by and adding it to the column of .
Note that is a conjugate of . In fact, they are in the same Borel orbit when and . Hence, for , we can consider as an operation that takes a morphism from to and transforms it to a morphism from to by considering as a new indeterminate and applying to the morphism. For ,
- •
denotes the function that takes a square matrix and multiplies the row of by and the column of by .
Let be a polynomial in indeterminates. We define as an operation that takes a rational map from the quasi-affine variety to and transforms it into a rational map from to by applying , using the following notation:
- •
is the variety determined by the equations .
We use the above notation also for varieties in projective spaces determined by the homogeneous polynomials .
3F. Rank of orbits and proof of first main result
Each is a product of disjoint transpositions. Hence for , we define the rank of to be the number of transpositions in . Note that under the one-to-one corespondence between and , the rank of a permutation is equal to the rank of the corresponding partial permutation matrix.
- •
denotes the permutations in of rank .
Note that all moves other than type I preserve the rank of . Indeed, the only way of obtaining of smaller rank by applying our moves is by deleting a transposition, which is the effect of move of type I. Also note that it is impossible to have a move of type II or a move of type IV between two permutations in . For example, we draw the Hasse diagram for where each dotted line denotes a move of type III and solid line denotes a move of type V:
Such Hasse diagrams, with particular attention paid to the maximal elements, will lead to the proof of our first main result.
Theorem 2**.**
Conjecture 5 holds for .
Proof.
Take , an -tuple of nonincreasing integers, and a nonconstant morphism. Then is in . By considering Figures 1 and 2, we note that there exists a unique maximal such that can be obtained from by a sequence of moves of type III. Since moves of type III do not change the number of leading zero rows and ending zero columns of the corresponding partial permutation matrices, the Borel orbit corresponding to is contained in if and only if the Borel orbit corresponding to is contained in for all . Hence it is enough to consider the cases where is less than or equal to a maximal element in for . We cover these cases by proving in the following eight statements:
(i) If then .
Assume to the contrary that and . If we also write for its restriction to , we get a map of the form
[TABLE]
where is a homogeneous polynomial in . Since is algebraically closed, there exists such that . This means is in , which is a contradiction.
**(ii) ** If then .
Suppose to the contrary that and . When we restrict to , we get a map of the form
[TABLE]
Note that there exists in such that
[TABLE]
Again this means . Hence this case is proved by contradiction as well.
(iii) If then .
Suppose we have
[TABLE]
Let be as in Section 3E and use the same notation to denote its composition with . Then there exists in such that
[TABLE]
This again gives a contradiction.
(iv) If then .
Suppose otherwise. We have
[TABLE]
If and are not relatively prime homogeneous polynomials then there exists such that
[TABLE]
Moreover, if and , then the rank of is at most , which leads to a contradiction. Hence we have or . Let
[TABLE]
Since , . By the fact that or , and are linearly dependent. Thus the rank of is at most , which is a contradiction.
Therefore we may assume and are relatively prime. Since , we have and . This implies that divides and , and similarly divides and . Then there exists in such that
[TABLE]
This means , , , , , and all vanish at . Hence , which is a contradiction.
(v) If then , and (vi) If then .
These cases are symmetric, so it is enough to prove (v). Consider
[TABLE]
We modify by the operations in Section 3E. First apply to for a new variable . If , apply and then to obtain a matrix of the form
[TABLE]
Hence by selecting a correct value for we would be done if . We may assume
[TABLE]
Similarly, we may also assume
[TABLE]
Therefore,
[TABLE]
Thus, is a regular sequence in . If and are not relatively prime, there exists such that , and . Hence, we may assume and are relatively prime, which leads a contradiction as we have
[TABLE]
(vii) If then .
To prove this case, consider
[TABLE]
Again by applying and for some we may assume that
[TABLE]
Hence must be a regular sequence in . However this is impossible because the determinant of
[TABLE]
divides both and .
(viii) If then .
It is enough to consider a root of to prove this case. ∎
Note that in the above proof the last two cases prove Conjecture 5 when and . In the rest of the paper we will generalize these ideas to prove the conjecture for . To do this we examine the dimensions of these varieties.
3G. Orbit dimensions and proof of second main result
We now introduce notation for dimensions of these varieties. In this subsection, for , if the rank of is , then we obtain two sequences of numbers and satisfying the following:
[TABLE]
with and for all . In [18], Melnikov gives a formula for the dimension of a Borel orbit for in as follows:
- •
for ,
- •
.
We define a new subset of :
- •
is the set of all in such that whenever is a permutation obtained by applying a single move of type I to .
For instance, the following is the Hasse diagram of .
Note that in the Hasse diagram of all moves are of type V. This is generally the case, which we will prove below. Before we do so, we will prove an easier result that will introduce the notation and argument style that will be necessary.
Fix . We use the our convention for at the beginning of this subsection which implies .
For , let be the result of applying the move of type I that deletes the th transposition of , so that
[TABLE]
As a matrix,
[TABLE]
Then by Melnikov’s formula we have
[TABLE]
[TABLE]
To simplify our calculation, we write for , where
[TABLE]
and we use the notation:
[TABLE]
for .
Lemma 1**.**
If and the transposition appears in , then .
Proof.
If appears in and , let and be the result of deleting the second transposition from . Since the ’s are increasing and for all , we have , so
[TABLE]
Thus . Let for some . Then
[TABLE]
and any number between and has to appear as a or an that is bigger than . Therefore,
[TABLE]
Hence, , so . ∎
Now we prove the main proposition of this subsection.
Proposition 1**.**
If , then for all , and therefore we cannot apply a move of type III to . Conversely, if and we cannot apply a move of type of III to , then .
Proof.
Assume that . We will prove the following statement by induction on :
[TABLE]
Suppose . To prove ( ‣ 3G), we need to show that , . Let be obtained by deleting th transposition of .
[TABLE]
Since , we have
[TABLE]
Since the total number of possible except is , and any number between and has to appear as , we have . By the equation (1), , so that , is true. Therefore .
Now assume the statement ( ‣ 3G) is true for . Then we can visualise as follows:
[TABLE]
We need to prove ( ‣ 3G) for , that is,
[TABLE]
By the second part of the inductive hypothesis for , we have so the first part of ( ‣ 3G) is already true, and we only need to show that the second part holds. In other words, it is enough to show that . Let be obtained by deleting th transposition of . Then we have
[TABLE]
Let . Then
[TABLE]
and
[TABLE]
By the fact that , we have . Thus the first claim is proved.
Conversely, given , suppose that is the result of applying the move of type I that deletes the -th transposition of . Note that and . Hence,
[TABLE]
Then,
[TABLE]
We also have the difference when . Therefore,
[TABLE]
Let and . Note that numbers between and must appear as for or as where . Let and . Then . Let and . We have . Therefore, .
[TABLE]
Since , . Then , and , so . ∎
Lemma 2**.**
For every in we have
[TABLE]
Proof.
The rank of is , so . The result follows from the inequality
[TABLE]
∎
We now define our last set of permutations:
- •
is the set of minimal permutations in that appear as a permutation in the form for some and nonconstant morphism .
We now state and prove our second main result.
Theorem 3**.**
Conjecture 5 holds for .
Proof.
We have (see Example 1). This means Conjecture 5 holds for , because . Hence it is enough to prove Conjecture 5 for .
Suppose that Conjecture 5 does not hold for . Then there exists an -tuple of nonincreasing integers , two positive integers , , and a nonconstant morphism such that , or equivalently . Write with and for all .
First assume that . By Proposition 1, we have . Therefore, and . Moreover, for every we have and . Set . Note that since . So, if . Similarly, if . Set
[TABLE]
and
[TABLE]
We have
[TABLE]
In particular, and , since we assumed that .
For and , let denote the submatrix of the partial permutation matrix obtained by considering the rows from to and columns from to . Note that has many ’s and has many ’s. Hence must have many ’s. However, there is no in ; otherwise there would exist such that and , which leads to a contradiction by considering the number of ’s in the region determined by the union of and . Similarly, there is no in . Hence the -submatrix contains many ’s. Thus, is the identity matrix of dimension .
[TABLE]
This in particular means that for every in the image of we have
[TABLE]
and
[TABLE]
Since is algebraically closed, there exists a root of the minor . Thus, there exists in the image of such that
[TABLE]
which means
[TABLE]
Lemma 2 implies that for every in the image of we have
[TABLE]
This is a contradiction, so we are done with the case .
Now assume that . We recursively define perturbations of so that we can again use the square submatrix to get a contradiction similar to that of the previous case. Set , , . We have a rational map . Now given
[TABLE]
we define when is not in .
Assume . By Proposition 1, there exists a move of type III that we can apply to . Hence, we may define
[TABLE]
and
[TABLE]
In case , we define
[TABLE]
Note that and so . Hence the affine variety can be considered as a subvariety of by considering . Here we write to denote a point in . Hence corresponds to the points where .
Represent by a matrix whose -entry is a rational function. Let denote the entry which is a polynomial. Also let be the greatest common divisor of . Set for . We define
[TABLE]
We obtain from by first applying , then where , then for , and finally applying for . Notice that also depends on , so we write instead of when is not clear.
We can repeat this process until it is no longer possible to find a move of type III with . At the end of this part of the process we obtain a rational map for some . Then we can continue with the symmetric (with respect to the diagonal of the matrix running from the lower left entry to the upper right entry) operations assuming is defined for . We define as follows:
[TABLE]
and
[TABLE]
We repeat the symmetric operations as long as we have . We define . Let denote the entry which is a polynomial. Also let be the greatest common divisor of . Similarly, we write instead of when is not clear.
At the end of this process we obtain a rational map from the quasi affine variety to where we have and for every in the image of this rational map. Denote the composition of with by . Notice that is a polynomial in . Define another polynomial in the same polynomial algebra as follows:
[TABLE]
For , we have are relatively prime. Similarly, for we have are relatively prime. Moreover, the polynomial has an irreducible factor in or for some , the polynomial has an irreducible factor in the form , where and are in so that is neither an associate of nor . Hence, there exists a solution to the equations and , which is again a contradiction by Lemma 2. ∎
4. Examples and Problems
The last inequality in Conjecture 5 is equivalent to
[TABLE]
One might ask how strict this upper bound for is.
In all the following examples, we define from to for different values of , and where . It follows that we do not have a better upper bound for in these cases.
Example 1**.**
For , , and , define
[TABLE]
Note that . This example shows that
[TABLE]
Example 2**.**
For and , and , define
[TABLE]
In this example, . Hence,
[TABLE]
Example 3**.**
For , , , and , set:
[TABLE]
Here, we have . Considering the Hasse diagram for in Figure 2 and symmetry it is clear that
[TABLE]
The above example can be generalized:
Example 4**.**
For , , , and , set:
[TABLE]
We can use the above examples to obtain new ones by the chess board construction:
Construction 1**.**
Let be an -tuple of positive integers and the subvariety of such that when for some . For example, the following matrix is in where is -tuple of nonincreasing integers:
[TABLE]
Take where is -tuple nonpositive integers and where is -tuple of nonincreasing integers. We arrange a matrix in a -chessboard as follows: The -square contains a matrix such that if is odd or if is even integer. Now we color the square black if and white if . Fill in the square with zeros if it is a black square and otherwise fill it in with where and part of where are defined by
[TABLE]
For instance, using chessboard construction we can obtain an example:
Example 5**.**
For , , , and we obtain an example by applying the chess board construction on the morphisms in Examples 2 and 3.
[TABLE]
We also have other well-known constructions like the Koszul complex construction [4] giving us examples as below.
Example 6**.**
For , and , define
[TABLE]
In this example, .
We end with a few questions for future research. Notice that all examples discussed above are in . Hence one can ask :
Question 1**.**
Is ?
For all these examples is an integer. For instance, we can find an example see Example 7 for , but we do not know the answer of the following question:
Question 2**.**
Is there any example for and ? More precisely, can we say that is nonempty?
Note that the following example can not be obtained by the constructions we mentioned above.
Example 7**.**
For , , and , consider
[TABLE]
Note that we can obtain an example for and for every by using the examples for , and the example for , and applying the chessboard construction as many times as necessary. If the answer to question 2 is negative, then one can ask the following question:
Question 3**.**
Do there exist any periodicity results about nonemptiness of ?
Another observation we make about these examples is that there always exists a sequence of permutations such that the image of the morphism contains a point from each Borel orbit corresponding to the these ’s and each pair of consecutive ’s consist of distinct transpositions. For example, putting and to in Example 2,we get a point in the Borel orbit corresponding to permutation . and putting and , we get . Hence one could ask the following question:
Question 4**.**
Given in does there always exists a morphism with a sequence permutations and points , , , in the image of such that and is in the Borel orbit of for all and and has no common transpositions?
If the answer is affirmative to this question then one can say that the inequalities
[TABLE]
and
[TABLE]
hold and they give the inequality .
Note that Allday and Puppe [3] have related results: If , , , , and are as in Conjecture 1, then they prove . Moreover, Avramov, Buchweitz and Iyengar [4] verified that in a more general case.
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