A multiplier inclusion theorem on product domains
Odysseas Bakas

TL;DR
This paper establishes a strict inclusion between two classes of multipliers on product domains, showing that multipliers from the Hardy space to L^2 are a proper subset of those from a specific Orlicz space to L^2.
Contribution
It proves a new multiplier inclusion theorem on product domains, clarifying the relationship between Hardy space multipliers and Orlicz space multipliers.
Findings
Multipliers from Hardy space to L^2 are strictly contained in those from L log^{d/2} L to L^2.
The inclusion between these multiplier classes is proper, not equal.
Provides a deeper understanding of multiplier spaces on product domains.
Abstract
In this note it is shown that the class of all multipliers from the -parameter Hardy space to is properly contained in the class of all multipliers from to .
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A multiplier inclusion theorem on product domains
Odysseas Bakas
Room 4606, James Clerk Maxwell Building, University of Edinburgh, Peter Guthrie Tait Road, Edinburgh, EH9 3FD.
Abstract.
In this note it is shown that the class of all multipliers from the -parameter Hardy space to is properly contained in the class of all multipliers from to .
1. Introduction
Let be a positive integer. If is a subspace of , then we denote by the class of all multipliers from to , namely the class consists of all functions such that for every one has .
In [1], it was shown that the class of all multipliers from the (real) Hardy space to is properly contained in the class of all multipliers from to . Our goal in this note is to extend this result to the multi-parameter setting. First of all, note that if denotes the -parameter (real) Hardy space over the -torus, then and hence, one automatically has . On the other hand, by adapting the argument given in [1] to the multi-parameter case, one deduces that the best we can expect is that . In this note we prove that this is indeed the case, namely we strengthen the trivial exponent in to the optimal one, . In particular, our main result in this note is the following theorem.
Theorem 1**.**
One has the inclusion
[TABLE]
Moreover, the above inclusion is proper and it is sharp, in the sense that the exponent in cannot be improved.
The multiplier inclusion (1.1) is obtained by a series of reductions. First, arguing as in [1] and by using D. Oberlin’s characterisation of the class given in [7], it follows that the proof of (1.1) is reduced to showing the following higher-dimensional version of an inequality due to Zygmund (see Theorem 7.6 in Chapter XII of [14]), a result of independent interest. To state this version of Zygmund’s inequality on , let denote the set of all “intervals” of integers of the form , , in other words, consists of all the sets in of the form , and , .
Proposition 2**.**
Let be as above.
If is a non-empty set satisfying the condition
[TABLE]
then there exists a positive constant , depending only on , such that
[TABLE]
In turn, (1.3) will be a corollary of a higher-dimensional extension of a result due to Seeger and Trebels [12] concerning sharp bounds of sums involving “smooth” Littlewood-Paley projections on . To state this result, fix a Schwartz function supported in such that and consider . For , set and for , set . One can easily see that for every . Then, for , the corresponding “smooth” Littlewood-Paley projection in the periodic setting is defined by
[TABLE]
for any, say, trigonometric polynomial on . On the -torus we put
[TABLE]
initially defined over trigonometric polynomials on . Then, Proposition 2 is a consequence of the following result.
Proposition 3**.**
There exists a constant , depending only on the dimension and our choice of , such that the following inequality holds
[TABLE]
for every trigonometric polynomial on and for each .
The proof of Proposition 3 is an adaptation of the work of Seeger and Trebels [12] to the higher-dimensional setting combined with a well-known inequality on multiple martingales, see section 2.2. At this point, it should be mentioned that, in fact, we expect that
[TABLE]
which, of course, implies (1.4). However, as our primary goal is to establish Theorem 1 and since (1.4) is enough for that purpose, we shall not pursue this in the present note.
The paper is organised as follows. In section 2 we give some notation and background and in section 3 we show how the proof of our multiplier inclusion theorem follows from Proposition 2. In section 4, we prove that Proposition 3 implies Proposition 2 and then, in section 5 we give a proof of Proposition 3. In the last section we briefly present some further applications of our work.
Acknowledgement
The author would like to thank his PhD supervisor Professor Jim Wright for his guidance on this work and for his useful comments that improved the presentation of this paper.
2. Notation and background
We denote by the set of integers, by the set of positive integers, and by the set of non-negative integers.
The cardinality of a finite set is denoted by .
If and are positive quantities such that , where is a constant, then we write . To specify the dependence of this constant on some additional parameters we write . If and , we write .
In this note, we identify with in the standard way.
2.1. Product Hardy spaces and the class
For , let denote the Poisson kernel on given by , . For , let , where denotes the unit disc in the complex plane. Then, the -parameter (real) Hardy space consists of all integrable functions on the -torus such that , where for one has
[TABLE]
It follows by the work of D. Oberlin [7] that belongs to the class if and only if,
[TABLE]
2.2. Dyadic square functions
If and , then the -th conditional expectation of is given by
[TABLE]
where is the unique dyadic interval in of the form , such that .
For , let denote the martingale differences acting on functions defined on . For , we set .
For a given -tuple of non-negative integers, we define
[TABLE]
and
[TABLE]
to be the corresponding operators acting on functions on the -torus.
In [3], Chang, Wilson, and Wolff obtained the“ good-” inequality
[TABLE]
which holds for all and , where is an absolute constant. In particular, this estimate implies that there exists a constant such that
[TABLE]
for all . By using (2.2), Chang, Wilson, and Wolff obtained in [3] an inequality analogous to (2.2) involving Lusin area integrals. In [8], Pipher extended (2.2) and its analogous version on Lusin area integrals to the two-parameter setting and in [5], R. Fefferman and Pipher extended the aforementioned inequality of Chang, Wilson, and Wolff involving Lusin area integrals to -valued functions. The argument of R. Fefferman and Pipher can be easily adapted to obtain an -valued extension of (2.2), see [4]. By using this -valued extension of (2.2) together with induction on , one deduces that there exists a constant , depending only on the dimension , such that
[TABLE]
for every , see also, e.g., [4, Proposition 4.5] and [2].
2.3. Thin sets in Harmonic Analysis
Let be a compact abelian group and let be a non-empty set in its dual . In this note, we shall only consider the case , . A trigonometric polynomial on whose spectrum lies in is said to be a -polynomial.
Let . We say that is a set if there exists a constant such that
[TABLE]
for every -polynomial . The smallest constant such that the above inequality holds is called the constant of .
A set is called Sidon if there is a constant such that
[TABLE]
for every -polynomial. It follows by the work of Rudin [11] and Pisier [9] that a spectral set is Sidon if and only if, it is a set for any and its constant grows like as .
Let . A set is said to be -Rider if there is a constant such that
[TABLE]
for every -polynomial. Here, we use the notation [|f|]=\mathbb{E}\big{[}\Big{\|}\sum_{\gamma\in\widehat{G}}r_{\gamma}\widehat{f}(\gamma)\gamma\Big{\|}_{L^{\infty}(G)}\big{]}, where denotes the set of Rademacher functions.
It is well-known that if is a set for all with constant growing like , , then is a -Rider set with , see [10, Théorème 6.3].
3. Proposition 2 implies Theorem 1
To prove that Proposition 2 implies Theorem 1, we adapt the argument given in [1] to the multi-parameter setting by using the characterisation of . To be more specific, assume that Proposition 2 holds and take an arbitrary in the class . Then, by definition, we need to show that for every one has
[TABLE]
Towards this aim, fix an and note that the sum
[TABLE]
is bounded by
[TABLE]
where is as in the introduction and the statement of Proposition 2. Hence, by (2.1), it follows that
[TABLE]
where is a set in defined as follows. Given , choose in so that
[TABLE]
Then, having chosen a set of -tuples as above, we define
[TABLE]
Notice that as the choice of -tuples is not necessarily unique, there might be several choices of sets . We just choose one of them to write
[TABLE]
Note that any such set satisfies condition (1.2) in Theorem 2 with . Therefore, as , it follows by (1.3) that
[TABLE]
as desired.
3.1. Sharpness of (1.1)
We remark that, in fact, the above argument shows that if , then there is a constant , depending only on , such that
[TABLE]
To see that the exponent in in (1.1) cannot be improved, we argue as in [1]. More specifically, assume that for some every multiplier from to is a multiplier from to . We shall prove that . To this end, for a large positive integer , take to be a trigonometric polynomial on given by , where denotes the de la Vallée Poussin kernel of order and is the Fejér kernel on of order . Since and , we deduce that
[TABLE]
So, if we take with for and otherwise, namely when at least one of the coordinates is less or equal than [math], then and hence,
[TABLE]
Since
[TABLE]
we see that, by choosing to be large enough, we must have .
Remark 4**.**
A similar argument shows that the Orlicz space in cannot be improved. Indeed, if is a set satisfying , then by making use of the argument presented above, we see that the exponent in in the right-hand side of higher-dimensional Zygmund’s inequality is sharp.
To show that the inclusion is proper, take to be a Sidon set in that cannot be written as a finite union of lacunary sequences, see [11, Remark 2.5(3)]. Then belongs to the class , see, e.g., [1, Proposition 4]. However, it can be easily checked that does not satisfy (2.1) and hence, we deduce that .
4. Proposition 3 implies Proposition 2
Our goal in this section is to prove that Proposition 3 implies Proposition 2. Towards this aim, take to be a set satisfying the assumption of Proposition 2, i.e. condition (1.2). Assume first that satisfies (1.2) with . By duality, to prove (1.3), it suffices to show that is a set in for every with constant growing like as . In other words, it is enough to show that for every -polynomial one has for every ,
[TABLE]
where is an absolute constant, independent of and . As we will see momentarily, if , then, in fact, depends only on and in particular, it can be taken to be independent of .
To prove (4.1), fix an -polynomial and note that for every one has by the triangle inequality
[TABLE]
where denotes the set , . Observe that, thanks to condition (1.2) for , the sum
[TABLE]
consists of at most terms and hence,
[TABLE]
and we thus deduce that
[TABLE]
Observe that the quantity on the right-hand side of the last inequality equals to , as . Hence, (4.1) follows from (1.4) and (4.2) in the case where . Moreover, note that, in the case where , the implied constant in (4.2) depends only on the dimension and on our choice of and, in particular, it is independent of .
In the case where , write , where are trigonometric polynomials on such that , where and . Then, by using the triangle inequality and the previous step we have
[TABLE]
since, by our construction and the -theory, for all .
5. Proof of Proposition 3
To prove Proposition 3, note that, as , it follows by Minkowski’s inequality that
[TABLE]
Moreover, since one trivially has
[TABLE]
we deduce by (2.3) that
[TABLE]
for all . Hence, to prove that (1.4) holds, it suffices, in view of (5.1), to show that
[TABLE]
This last inequality follows from the next lemma which is a -dimensional analogue of [12, Lemma 2.3].
Lemma 5**.**
Let be a Schwartz function that is even, supported in and such that .
Define . For , put and for , put . Consider the operator
[TABLE]
acting on functions defined over the torus. For we use the notation .
There exists a constant , depending only on the dimension and on , such that for all -tuples of non-negative integers and one has
[TABLE]
where A=\big{\{}j\in\{1,\cdots,d\}:m_{j}<k_{j}\big{\}} and
[TABLE]
In we make the convention that if , then .
The proof of Lemma 5 will be given in the next subsection. By using the above lemma and in particular estimate (5.3) one can easily complete the proof of Proposition 3. Towards this aim, we argue as in the proof of [12, Proposition 2.2]. More precisely, we consider a trigonometric polynomial on and write . For fixed (and ), if is as in the statement of Lemma 5, then and hence, . So, by using (5.3), we obtain
[TABLE]
and it thus follows that
[TABLE]
where the implied constant depends only on the dimension . Hence, by Minkowski’s integral inequality,
[TABLE]
Since we have
[TABLE]
the proof of Proposition 3 will be complete once we prove Lemma 5. This will be done in the following subsection.
5.1. Proof of Lemma 5
The proof of this Lemma is a straightforward adaptation of [12, Lemma 2.3] to the multi-parameter setting. For the sake of simplicity, we shall only present the proof of the two-dimensional case. A similar argument establishes the higher-dimensional case.
Let be as in the statement of Lemma 5. Following [12], we use the notation , and for we put
[TABLE]
For we write and . Notice that we may write
[TABLE]
where . Our assumption on the support of implies that is in fact a trigonometric polynomial on . By using the Poisson summation formula, see, e.g., Corollary 2.6 in Chapter VII of [13], it is straightforward to see that . Therefore, it follows that
[TABLE]
for all and we thus deduce that
[TABLE]
for all , where the summation is taken with respect to all possible choices of .
5.1.1. Proof of condition (for ).
We shall consider two cases; and .
Case 1: . In this case we have and and (5.2) easily follows from (5.4),
[TABLE]
Case 2: . First, consider the subcase where and . For , we denote by , , the unique dyadic interval in of length containing (). If we write , i.e. , , then we have
[TABLE]
Hence, one can write
[TABLE]
and thus, by (5.4), we obtain the desired estimate,
[TABLE]
Next, consider the subcase where but . In this case, for , , being as in the previous subcase, we have
[TABLE]
and so, can be written as
[TABLE]
Since the length of is equal to , we get
[TABLE]
and hence, by using (5.4), we have
[TABLE]
The subcase where and is symmetric to the previous one. Therefore, (5.2) is completely shown in the two-dimensional case.
5.1.2. Proof of condition (for ).
We shall consider two cases; and .
Case 1: . In this case we have and and (5.3) follows easily from (5.2). Indeed, observe that
[TABLE]
by (5.2), as and .
Case 2: . Assume first that , that is and . By using the definition of , we write
[TABLE]
Take and for let be the dyadic interval in of length containing . Let denote the dyadic interval of length such that . Note that since and are dyadic intervals with non-empty intersection and , one has , . Since
[TABLE]
by using the mean value theorem for integrals it follows that there exists an such that
[TABLE]
A similar analysis on shows that there exists an such that
[TABLE]
Therefore,
[TABLE]
If we assume, without loss of generality, that , then by the mean value theorem,
[TABLE]
for some . One can easily see that
[TABLE]
and so,
[TABLE]
Hence, by using the definition of and , it follows by the mean value theorem for integrals that there are and such that
[TABLE]
Without loss of generality we may assume that . Hence, by applying the mean value theorem, we deduce that
[TABLE]
for some . Since , we obtain
[TABLE]
as desired.
It only remains to consider the subcase where and , the other one ( and ) being symmetric. We need to show that
[TABLE]
To this end, write as
[TABLE]
and handle each of these two terms separately. Take and, for , consider the dyadic intervals and as above. For the first term, by applying the mean value theorem for integrals, we see that there are and such that
[TABLE]
Hence, if we assume that , then by the mean value theorem there is an such that
[TABLE]
Now, by considering the definition of , an explicit calculation shows that
[TABLE]
where is as above. Since , the last expression gives
[TABLE]
A similar argument shows that the second term also satisfies
[TABLE]
and we thus deduce that
[TABLE]
Hence, the proof of (5.3) for is complete.
6. Some Further remarks and applications
6.1. Applications in thin sets
Proposition 2 gives examples of sets in whose corresponding constant grows like as and they cannot be written as products of Sidon sets. Moreover, those sets, namely the class of the sets that cannot be written as -fold products of sets in and satisfy the condition \sup_{I_{1},\cdots,I_{d}\in\mathcal{J}}\#\big{\{}E\cap(I_{1}\times\cdots\times I_{d})\big{\}}<\infty, are examples of -Rider sets in that cannot be written as products of Sidon sets in .
Note that if are lacunary sequences in , then satisfies (1.2) and we thus recover the well-known fact that is a set in whose constant grows like as . However, Proposition 2 cannot handle spectral sets of the form , where is a Sidon set that is not a finite union of lacunary sequences ().
6.2. A version of (1.4) for “rough” projections
For consider the classical Littlewood-Paley projections
[TABLE]
For , set . For we write
[TABLE]
Since for every trigonometric polynomial on the -torus we may write , we have
[TABLE]
Observe that whenever there exists an index such that . We thus deduce that
[TABLE]
Therefore,
[TABLE]
and hence, it follows by (1.4) that for every trigonometric polynomial on one has
[TABLE]
for every . Estimate (6.1) is a multi-parameter version of an inequality due to C. Moore [6]. In particular, we obtain the following multi-parameter extension of [6, Theorem, p.30].
Corollary 6**.**
There exist positive constants and , depending only on the dimension , such that whenever
[TABLE]
one has
[TABLE]
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