$\Sigma$-pure-injective modules for string algebras and linear relations
Raphael Bennett-Tennenhaus, William Crawley-Boevey

TL;DR
This paper characterizes indecomposable $ ext{Sigma}$-pure-injective modules over string algebras as either string or band modules, using a splitting result for infinite-dimensional linear relations.
Contribution
It provides a classification of indecomposable $ ext{Sigma}$-pure-injective modules for string algebras, linking module theory with linear relations.
Findings
Indecomposable $ ext{Sigma}$-pure-injective modules are string or band modules.
A splitting theorem for infinite-dimensional linear relations is established.
The result advances understanding of module categories over string algebras.
Abstract
We prove that indecomposable -pure-injective modules for a string algebra are string or band modules. The key step in our proof is a splitting result for infinite-dimensional linear relations.
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Taxonomy
TopicsAlgebraic structures and combinatorial models · semigroups and automata theory · Logic, programming, and type systems
-pure-injective modules for string algebras and linear relations
Raphael Bennett-Tennenhaus and William Crawley-Boevey
Fakultät für Mathematik, Universität Bielefeld, 33501 Bielefeld, Germany
[email protected], [email protected]
Abstract.
We prove that indecomposable -pure-injective modules for a string algebra are string or band modules. The key step in our proof is a splitting result for infinite-dimensional linear relations.
Key words and phrases:
String algebra, Linear relation, Pure-injective module
2010 Mathematics Subject Classification:
Primary 16D70
Both authors are supported by the Alexander von Humboldt Foundation in the framework of an Alexander von Humboldt Professorship endowed by the German Federal Ministry of Education and Research.
1. Introduction
A string algebra is one of the form where is a field, is a quiver, is the path algebra, and denotes the ideal generated by a set of paths of length at least 2, satisfying
- (a)
any vertex of is the head of at most two arrows and the tail of at most two arrows, and
- (b)
given any arrow in , there is at most one path of length with and at most one path of length with .
For simplicity we suppose that has only finitely many vertices (so is finite), so that the algebra has a unit element.
It is well-known that the finite-dimensional indecomposable modules for a string algebra are classified in terms of strings and bands, see for example [3, 4]. It is also interesting to study infinite-dimensional modules, especially pure-injective modules, see [12, 9, 10]. In this paper we classify indecomposable -pure-injective modules for string algebras. Recall that a module is said to be pure-injective or algebraically compact if it is injective with respect to pure-exact sequences (where an exact sequence is pure-exact if it remains exact after tensoring with any module). A module is -pure-injective if any direct sum of copies of it is pure-injective. There are many equivalent formulations, see for example [8, §4.4.2]. Note that any countable-dimensional pure-injective module is -pure-injective, see [8, Corollary 4.4.10].
Associated to a string algebra there are certain words whose letters are the arrows of and their inverses. The words may be finite or (as in [12, 4]) infinite. Associated to such a word there is a module . (We recall the appropriate definitions in §3). By a string module one means a module with not a periodic word. If is periodic, then becomes a --bimodule, and given any indecomposable -module there is a corresponding band module . It is known that string modules are indecomposable, and Harland [7] has given a criterion in terms of a word , for when the string module is -pure-injective; for convenience we recall his criterion in §3. Our main result is as follows.
Theorem 1.1**.**
Every indecomposable -pure-injective module for a string algebra is either a string module or a band module with a -pure-injective -module.
The indecomposable -pure-injective -modules are the indecomposable finite-dimensional modules, the Prüfer modules, which are the injective envelopes of the simple modules, and the function field . It is easy to see that the corresponding -modules are also -pure-injective, for example using [8, Theorem 4.4.20(iii)]. Since any -pure-injective module is a direct sum of indecomposables, the theorem, combined with [4, Theorem 9.1], implies that is indecomposable for indecomposable -pure-injective.
The proof of our theorem uses the functorial filtration method, which goes back to the classification of Harish-Chandra modules for the Lorenz group by Gelfand and Ponomarev [6], and was used for the classification of finite-dimensional modules for string algebras by Butler and Ringel [3]. The method depends on a certain splitting result for finite-dimensional linear relations, see [6, Theorem 3.1], [11, §2] and [5, §7]. An extension of this splitting result to some infinite-dimensional relations was obtained in [4, Lemma 4.6]. A key step in the proof of our theorem is the generalization of this splitting result to the -pure-injective case, which we now explain.
Fix a base field . A linear relation consists of a vector space and a subspace of . The category of linear relations has as morphisms the linear maps with the property that for all . Any linear relation defines a Kronecker module
[TABLE]
where , and and are the first and second projections, and in this way the category of linear relations is equivalent to the full subcategory of the category of Kronecker modules, consisting of those modules such that the map is injective. Linear relations can be considered as generalizations of linear maps, and one defines for and for . If is a subspace of and is a relation on , then denotes .
Given a linear relation , we recall [4, Definition 4.3] that there are subspaces of defined by
[TABLE]
By [4, Lemma 4.5] the quotient is a -module with the action of given by if and only if . Using [4, Lemma 4.6] we prove the following.
Theorem 1.2**.**
As Kronecker modules, and are both pure submodules of .
We say that a relation is automorphic if both projection maps are isomorphisms. The theorem implies our splitting result for linear relations.
Corollary 1.3**.**
If is -pure-injective as a Kronecker module, then there is a decomposition such that is an automorphic relation. Moreover is a -pure-injective -module.
2. Linear relations
Products and inverses of relations on are defined by if and for some , and . Recall [4] that
[TABLE]
so that , , .
Lemma 2.1**.**
If is automorphic, then and .
Proof.
Clear. ∎
Lemma 2.2**.**
If is a relation, then and .
Proof.
Straightforward. ∎
The category of linear relations inherits an exact structure from the category of Kronecker modules, in which a sequence of relations
[TABLE]
is exact provided that and are exact.
Lemma 2.3**.**
Given a relation , there is an exact sequence
[TABLE]
where the third term is automorphic.
Proof.
We need to show that the third term is automorphic. Consider the map given by the first projection, say.
The map is onto since by definition any element of belongs to an infinite sequence of elements with for all , and then .
The kernel of the map is the set of pairs with and . But then , and by [4, Lemma 4.4] this is equal to , so the kernel is . ∎
A relation is said to be split provided that there is a subspace of such that and is an automorphic relation [4, §4].
Lemma 2.4**.**
A relation is split if and only if the exact sequence in Lemma 2.3 is split.
Proof.
It suffices to show that if is split, then , for then is a complement for as Kronecker modules. Suppose . Write with and . By assumption there is with . Since is linear, . Thus . But also . Thus by [4, Lemma 4.4]. Then . ∎
Lemma 2.5**.**
Consider an exact sequence of relations
[TABLE]
where we identify as a subspace of . Then
- (i)
if and then ;
- (ii)
if and then ; and
- (iii)
if and then .
Proof.
(i) By symmetry, it suffices to show that if then . By assumption , so . Thus for some . Since the map is onto, there is with and . Then , so we can identify as an element of , so , so there is with . But then , so , as required.
(ii) We show by induction on that if and then . The result then follows by symmetry, using that is onto. If then , so . If , then with . Now since the map is onto, there is with . By induction . Then , and , so . Also , so , so .
(iii) Clearly . Conversely, if , then , so , so . ∎
We recall the classification of Kronecker modules, see for example [2]. If is a finite-dimensional indecomposable Kronecker module, say of the form
[TABLE]
then either it is automorphic regular, meaning that and are isomorphisms, or is of one of the following types, where has basis , has basis , (or 0 if ) and (or 0 if ).
- (i)
Preprojectives (): , .
- (ii)
Preinjectives (): , .
- (iii)
0-Regulars (): , .
- (iv)
-Regulars (): , .
Linear relations correspond to Kronecker modules without as a direct summand.
Lemma 2.6**.**
Let be a linear relation, let be one of the following subspaces of and let be a finite-dimensional indecomposable Kronecker module of the indicated type:
- (i)
* and is preinjective, or*
- (ii)
* and is preinjective, or*
- (iii)
* and is automorphic regular.*
Then there is no non-zero map of Kronecker modules .
Proof.
(i), (ii) For the map consists of maps and , sending to the coset of for and to the coset of for , and such that for , where . Note .
We claim that all . This is true for ; if true for it follows for since ; and if true for it follows for since . The claim follows.
Dually, starting with , we see that all . Thus all . If then for in which case . So we may assume .
Now we claim that all . This is true for ; if true for it follow for since by [4, Lemma 4.4]; if true for it follows for since . Thus as above.
(iii) Let be a basis for , and so is a basis for where . There is an invertible matrix with and . The map consists of and , sending to the coset of and to the coset of , such that . It suffices to show .
Note since this is the sum of and . By [4, Lemma 4.4] we have and so there is some for which . Thus we have .
Since there exist for such that and for all . For let and let be the entry of the matrix . We define elements iteratively as follows. Let and , and for let
[TABLE]
By construction when . If this true for some then
[TABLE]
hence for all we have . Note that for all . We claim for all where , and for . For the claim holds by construction. If for some then
[TABLE]
by the above, and as this gives . Now let for . As above we have for , and so altogether we have , as required. ∎
Lemma 2.7**.**
Let be a relation with , and let be a finite-dimensional indecomposable preprojective, 0-regular or -regular Kronecker module. Then .
Proof.
We can reduce to the case or , since any as listed is an iterated extension of copies of or and possibly also the projective module . By symmetry we reduce to . Consider an extension
[TABLE]
and identify as a subspace of , so is a subspace of . Let and be sent to the basis elements and in . Then . Now for some , and where , and , giving a splitting of the extension. ∎
Proof of Theorem 1.2.
Let be or . We need to show that any map from a finitely presented, so finite dimensional, Kronecker module to the third term in the exact sequence
[TABLE]
lifts to a map to the middle term. It is enough to let be indecomposable and show the pullback sequence
[TABLE]
is split. By Lemma 2.2 we have and , so if is preprojective, 0-regular or -regular then the pullback sequence splits by Lemma 2.7. Assume instead that is preinjective or regular automorphic. There is nothing to prove if there are no non-zero maps . By Lemma 2.6 this means we can assume that and that is regular automorphic. Hence and by Lemma 2.5, and thus the pullback sequence is the exact sequence of Lemma 2.3 for the relation . This splits by [4, Lemma 4.6], since the quotient is finite dimensional. ∎
Proof of Corollary 1.3.
Assume that is -pure-injective as a Kronecker module. By [8, Corollary 4.4.13] any pure submodule of it is a direct summand. In particular, by Theorem 1.2, this applies to . Thus also is pure-injective.
Since is a pure submodule in , it is also pure in , see for example [8, Lemma 2.1.12]. Thus the exact sequence of Lemma 2.3 splits. By Lemma 2.4 we have
[TABLE]
Since is a pure submodule of the -pure injective module , is -pure injective, hence so is . This means the inclusion of Kronecker modules
[TABLE]
splits. Thus the inclusion of -modules splits, so is a -pure-injective -module. ∎
3. String algebras
We recall some notation from [4].
Words
([4, §1]) A letter is either an arrow or its formal inverse . Let be one of the sets (for some ), , or . For , an -word is a sequence of letters
[TABLE]
(a bar shows the position of and when ) satisfying:
- (a)
if and are consecutive letters, then the tail of is equal to the head of .
- (b)
if and are consecutive letters, then
- (c)
no zero relation , nor its inverse occurs as a sequence of consecutive letters in .
For there are trivial words for each vertex and each . By a word we mean an -word for some .
The inverse of is defined by inverting its letters (where ) and reversing their order. By convention , and the inverse of a -word is indexed so that
If is a -word and , the shift is the word We say that a word is periodic if it is a -word and for some . The minimal such is called the period. We extend the shift to -words with by defining .
Modules given by words
For any -word and any there is an associated vertex , the tail of or the head of , or for . Given an -word let be the -module generated by the elements subject to the relations
[TABLE]
for any vertex in and
[TABLE]
for any arrow in . Given a periodic -word of period , and a -module , there is an automorphism of the underlying vector space of given by . Hence is a --bimodule and we let .
By a string module we mean a module of the form where is not a periodic -word. By a band module we mean a module of the form where is a periodic -word and is an indecomposable -module.
Sign, heads and tails
([4, §2]) We choose a sign for each letter , such that if distinct letters and have the same head and sign, then for some zero relation .
The head of a finite word or -word is defined to be , so it is the head of , or for . The sign of a finite word or -word is defined to be that of , or for .
For a vertex and , we define to be the set of all -words with head , sign , and where .
Composing words
The composition of a word and a word is obtained by concatenating the sequences of letters, provided that the tail of is equal to the head of , the words and have opposite signs, and the result is a word.
By convention and the composition of a -word and an -word is indexed so that If is a non-trivial finite word and all powers are words, we write and for the -word and periodic word and If is an -word and , there are words and with appropriate conventions if is maximal or minimal in , such that .
Relations given by words
([4, §4]) If is a -module and is an arrow with head and tail , then multiplication by defines a linear map , and hence a linear relation from to .
By composing such relations and their inverses, any finite word defines a linear relation from to , where is the head of and is the tail of . We denote this relation also by .
Thus, for any subspace of , one obtains a subspace of . We write for the case and for the case .
Filtrations given by words
([4, §6]) For and any -module define subspaces as follows.
Suppose is finite. Let if there is an arrow such that is a word, and otherwise . Similarly let if there is an arrow such that is a word, and otherwise .
If instead is an -word let be the set of such that there is a sequence with and for all , and define to be the set of such that there is a sequence as above which is eventually zero.
Subgroups of finite definition
([8, §1.1.1]) A pp-definable subgroup of is an additive subgroup of of the form
[TABLE]
where and is a matrix in . If and this gives . If , , and A=(\begin{array}[]{cc}-1&a\end{array}) this gives . If is a finite word then is a pp-definable subgroup of (see [7, §5.3.2], [8, Example 1.1.2] or [10, §4]).
Lemma 3.1**.**
If is a pure-injective -module and is an -word then .
Proof.
Clearly so it suffices to pick such that for all and show . Suppose, for an arbitrary but fixed , we can choose . For the set is a non-empty coset of a pp-definable subgroup. We have for any finite subset of , so as is algebraically compact there exists such that (see [8, §4.2.1]). Setting gives the required sequence . ∎
Refined functors
([4, §7]) If and is a -module, let where
[TABLE]
If and is a periodic word, say and for some finite word , then , and the linear relation on induces an automorphism of (see §1). Hence defines a functor from -modules to -modules. Otherwise is a non-periodic word and we consider as a functor from the category of -modules to -vector spaces.
In general there is a natural isomorphism between and the functor defined by for any -module where .
Corollary 3.2**.**
Let be a homomorphism of -modules where is pure-injective . If is surjective for all then is surjective.
Proof.
For the contrapositive we suppose , and so we can choose a vertex and some element . The set contains but not [math], so by combining lemma 3.1 (ii) and [4, Lemma 10.3], there is a word such that meets but not . Following the proof of [4, Lemma 10.5] we have that meets but not for some . Following the second half of the proof of [4, Lemma 10.6], this shows is not surjective. ∎
Proof of Theorem 1.1.
We show that every -pure-injective -module is a direct sum of string modules and band modules with -pure-injective.
If and is periodic, say and for some finite word , then is split by Corollary 1.3. Following the proof of [4, Theorem 9.2], this means there is a homomorphism where is a direct sum of string and band modules, and is an isomorphism for all pairs of words such that is a word. By [4, Lemma 9.4] this means is injective, and is surjective by Corollary 3.2. ∎
Note that any -pure-injective module is a direct sum of indecomposables, but conversely not every direct sum of indecomposable -pure-injective modules is -pure-injective, see for example [8, Example 4.4.18].
Ringel has shown that is -pure-injective provided is a so-called contracting word [12, §5]. A more general result is due to Harland [7].
Harland’s criterion
For each vertex and each there is a total ordering on given by if
- (a)
and for arrows and and words , , and (with finite),
- (b)
is finite and for an arrow and a word , or
- (c)
is finite and for an arrow and a word .
For any -word and any the words and have the same head but opposite signs. Let be the one with sign . The following result is [7, Proposition 14 and Theorem 42]. (Note that Harland uses the opposite ordering on so has the ascending chain condition.)
Proposition 3.3**.**
Let be finite dimensional and be an -word. Then is -pure-injective if and only if for each vertex and each every descending chain in stabilizes.
On page 243 of [7, §6.9] there is an example of an aperiodic word where is pure-injective.
Acknowledgement. The first listed author is grateful to Rosanna Laking for many helpful conversations about string algebras and the model theory of modules.
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