This paper establishes the existence and properties of Chebyshev-type cubature formulas for doubling weights on spheres, providing bounds on the number of nodes and their distribution, extending recent spherical design results.
Contribution
It proves the existence of Chebyshev-type cubature formulas for doubling weights on spheres with optimal node bounds and separation, extending recent spherical design research.
Findings
01
Existence of cubature formulas with N nodes for doubling weights.
02
Optimal bounds on the minimal number of nodes for such formulas.
03
Construction of regular convex partitions of the sphere with respect to the weight.
Abstract
This paper proves that given a doubling weight w on the unit sphere Sdβ1 of Rd, there exists a positive constant Kwβ such that for each positive integer n and each integer Nβ₯maxxβSdβ1βw(B(x,nβ1))Kwββ, there exists a set of N distinct nodes z1β,β―,zNβ on Sdβ1 which admits a strict Chebyshev-type cubature formula (CF) of degree n for the measure w(x)dΟdβ(x), w(Sdβ1)1ββ«Sdβ1βf(x)w(x)dΟdβ(x)=N1βj=1βNβf(zjβ),Β Β βfβΞ ndβ, and which, if in addition wβLβ(Sdβ1), satisfies 1β€iξ =jβ€Nminβd(ziβ,zjβ)β₯cw,dβNβdβ11β for some positive constant cw,dβ. Here, dΟdβ and d(β ,β ) denote the surface Lebesgue measure and the geodesic distanceβ¦
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TopicsMathematical Approximation and Integration Β· Mathematical functions and polynomials Β· Matrix Theory and Algorithms
Full text
Chebyshev-type cubature formulas for doubling weights on spheres, balls and simplexes
Feng Dai
Department of Mathematical and Statistical Sciences
This paper shows that given a doubling weight w on the unit sphere Sdβ1 of Rd
there exists a positive constant Kw,dβ
such that for each positive integer n and
each integer Nβ₯maxxβSdβ1βw(B(x,nβ1))Kw,dββ, there exists a set of N distinct nodes z1β,β―,zNβ on Sdβ1 for which
[TABLE]
where dΟdβ, B(x,r) and Ξ ndβ denote the surface Lebesgue measure on Sdβ1, the spherical cap with center xβSdβ1 and radius r>0, and the space of all spherical polynomials of degree at most n on Sdβ1, respectively, and w(E)=β«Eβw(x)dΟdβ(x) for EβSdβ1.
If, in addition, wβLβ(Sdβ1), then the above set of nodes can be chosen to be well separated:
[TABLE]
It is further proved that the minimal number of nodes Nnβ(wdΟdβ) required in (β)
for a doubling weight w on Sdβ1 satisfies
[TABLE]
Proofs of these results rely on new convex partitions of Sdβ1 that are regular with respect to a given weight w and integer N. Similar results are also established on the unit ball and the standard simplex of Rd.
Our results extend the recent results of Bondarenko, Radchenko, and Viazovska on spherical designs.
Key words and phrases:
Chebyshev-type cubature formulas for doubling weights; Spherical designs; Spherical harmonics; Convex partitions of the unit spheres.
1991 Mathematics Subject Classification:
41A55, 41A63, 52C17, 52C99,
65D32
This work was supported
by NSERC Canada under
grant RGPIN 04702. It was conducted when the second author was a Ph.D student at the University of Alberta.
Bernsteinβs methods have been extended and developed in a series of papers of Kuijlaars (see, for instance, [20, 21, 22, 23, 24]), who,
in particular, proves that for the Jacobi measures dΞΌΞ±,Ξ²β(t)=(1βt)Ξ±(1+t)Ξ²dt on [β1,1] with nonnegative parameters Ξ±,Ξ²β₯0,
[TABLE]
Kuijlaars [20, 21] also noticed that his techinique in general does not work for the Jacobi measures dΞΌΞ±,Ξ²β(t) with negative parameters Ξ±,Ξ²>β1, although he was able to prove a stronger result in [25] implying the estimate (1.2) for the case of Ξ±=β21β, β21ββΞ»0ββ€Ξ²<β21β and some positive constant Ξ»0β. The estimate (1.2) was proved recently by Kane[17] for Ξ±,Ξ²β₯β21β, and by Gilboa and Peled [14] for the general case of Ξ±,Ξ²>β1. The very interesting work of Gilboa and Peled [14] also uses the method of Kane[17] to establish sharp bounds on the size of the Chebyshev-type CFs in one dimension for all doubling weights with some excellent discussions on non-doubling case.
For more information on the Chebyshev-type CFs in one variable, we refer to [15, 16, 13, 18, 32] and references within.
For the Chebyshev-type CFs in several variables, the most well studied case is that of spherical designs, introduced by Delsarte, Goethals, and Seidel [1] in 1977.
Let Sdβ1:={xβRd:Β Β β₯xβ₯=1} denote the unit sphere of Rd equipped with the usual surface Lebesgue measure dΟdβ(x), where β₯β β₯ denotes the Euclidean norm.
A spherical n-design on Sdβ1 is a
Chebyshev-type CF of degree n for the measure dΟdβ(x) on Sdβ1. It is not difficult to show a spherical n-design on Sdβ1 must have size at least cdβndβ1; that is, Nnβ(dΟdβ)β₯cdβndβ1,
(see, for instance, [1]). It was conjectured by Korevaar and Meyers [19] that
Nnβ(dΟdβ)β€cdβndβ1.
Much work had been done towards this conjecture (see [17] and the references thererin). This conjecture was recently confirmed in the breakthrough work of Bondarenko, Radchenko, and Viazovska [5, 6],
which shows that there exist positive constants Kdβ and cdβ depending only on d such that given every integer N>Kdβndβ1 there exists a spherical n-design consisting of N distinct nodes z1β,β―,zNββSdβ1 with
min1β€iξ =jβ€Nβd(ziβ,zjβ)β₯cdβNβdβ11β.
In the above mentioned interesting paper [17],
Kane develops techniques different from those of [5, 6] to
establish bounds on the size of Chebyshev-type CFs on rather general path-connected topological spaces.
In particular, his techniques can be applied to prove the existence of spherical n-designs on Sdβ1 of size Odβ(ndβ1(logn)dβ2), which is only slightly worse than the asymptotically optimal estimate Odβ(ndβ1).
In the very general setting of path-connected topological spaces, the work of Kane [17] proves the existence of the Chebyshev-type CFs
whose size is
roughly the square of the optimal size conjectured in [17].
Using the method of [5], Etayo, Marzo and Ortega-CerdΓ [12] establish asymptotically optimal bounds on the size of the Chebyshev-type CFs
on compact algebraic manifolds, confirming Kaneβs conjecture in certain sense for this specific setting.
Some earlier related works regarding the Chebyshev-type CFs on certain multi-variate domains can be found in the papers of Kuperberg [27, 28, 29].
One can also find some interesting results on Chebyshev-type CFs on discrete spaces such as combinatorial designs and Hadamard matrices, in [30] and the references therein.
One of the main purposes in this paper is to extend the methods of Bondarenko, Radchenko, and Viazovska [5, 6] to determine the asymptotically optimal bounds on the size of the Chebyshev-type CFs for doubling weights on the unit sphere Sdβ1 and other related domains. Our results are mainly for the case of more variables, whereas the results in one variable were mostly established in the recent paper [14].
Let us start with some necessary notation.
Denote by Ξ ndβ the space of all real algebraic polynomials of total degree at most n in d variables:
[TABLE]
where N0β denotes the set of all nonnegative integers.
Let d(x,y) denote the geodesic distance on Sdβ1; that is, d(x,y):=arccos(xβ y) for x,yβSdβ1.
Denote by B(x,r) the spherical cap {yβSdβ1:Β Β d(x,y)β€r} with center xβSdβ1 and radius r>0.
A weight function w on Sdβ1 (i.e., a nonnegative integrable function on Sdβ1 ) is said to satisfy the doubling condition if there exists a positive constant L such that
[TABLE]
where we write w(E):=β«Eβw(x)dΟdβ(x) for EβSdβ1, and
the least constant L=Lwβ is called the doubling constant of w. Given a doubling weight w on Sdβ1, there exists a constant dβ1β€swββ€log2logLwββ such that
[TABLE]
Many of the weights
that appear in analysis on Sdβ1 satisfy the doubling condition; in
particular, all weights of the form
[TABLE]
In this paper, we will prove the following weighted extension of the result of Bondarenko, Radchenko, and Viazovska [5, 6] on spherical designs:
Theorem 1.1**.**
Let w be a doubling weight on Sdβ1 normalized by w(Sdβ1)=1. Then there exists a positive constant Kwβ depending only on the doubling constant of w and the dimension d such that for each given positive integer n, and
every integer Nβ₯maxxβSdβ1βw(B(x,nβ1))Kwββ, there exist N distinct nodes z1β,β―,zNββSdβ1 for which
[TABLE]
If, in addition, wβLβ(Sdβ1), then the set
of nodes {z1β,β―,zNβ} above can be chosen to be well separated:
[TABLE]
where cββ is a positive constant depending only on β₯wβ₯ββ and the doubling constant of w.
Given a doubling weight w on Sdβ1, the minimal sizes of the strict Chebyshev-type CFs
for the measure w(x)dΟdβ(x) on Sdβ1 satisfy
[TABLE]
with the constants of equivalence depending only on d and the doubling constant of w.
Several remarks are in order.
Remark 1.3*.*
(i)
By (1.3), it is easily seen that
maxxβSdβ1βw(B(x,nβ1))1ββ€2Οswβnswβ. Thus, Corollary 1.2 particularly implies that
Nnβ(wdΟdβ)β€Cnswβ<β for every doubling weight w on Sdβ1.
2. (ii)
For the weights wΞ±β given in (1.4), a straightforward calculation shows that
where
Ξ±minβ=min1β€iβ€dβΞ±iβ and IΞ±β={i:Β Β 1β€iβ€d,Β Β Ξ±iββ₯0}.
3. (iii)
Note that only Chebyshev-type CFs with distinct nodes are involved in Theorem 1.1. However,
it is worthwhile to point out that a slight modification of our proof shows that for each integer Nβ₯maxxβSdβ1βw(B(x,nβ1))Kwββ there exists a Chebyshev-type CF of degree n and size N for the measure w(x)dΟdβ(x) consisting of a large number of multiple nodes (i.e., repeated notes), and with the number Nnβ of distinct nodes satisfying NnββΌndβ1.
While the proof of Theorem 1.1 follows the methods of the papers [5, 6], it is more technical and involved than the corresponding unweighted case due to the fact that the measure w(x)dΟdβ(x) is not rotation-invariant, which means that in general, the weighted measure w(B(x,r)) of a spherical cap not only depends on radius r but also on the center x.
An important ingredient used in our proof is
the convex partition of Sdβ1 that is regular with respect to a given weight.
Recall that a subset AβSdβ1 is geodesically convex if any two points x,yβA can be joined by a geodesic arc that lies entirely in A, whereas a finite collection {R1β,R2β,β―,RNβ} of closed geodesically convex subsets of Sdβ1 is called
a convex partition of Sdβ1 if Sdβ1=βj=1NβRjβ and the interiors of the sets Rjβ are
pairwise disjoint.
Our result on regular convex partitions of the weighted sphere can be stated as follows:
Theorem 1.4**.**
Let w be a normalized weight on Sdβ1 (i.e., w(Sdβ1)=1) satisfying that w(B)>0 for every nonempty spherical cap BβSdβ1. Assume that rβ(0,Ο] and N is a positive integer satisfying minxβSdβ1βw(B(x,r))β₯N1β. Then
there exists a convex partition
{R1β,β―,RMβ} of Sdβ1 satisfying that
B(xjβ,cdβ²βr)βRjββB(xjβ,cdβr) and Nw(Rjβ)βN for every 1β€jβ€M, where cdβ,cdβ²β are two positive constants depending only on d.
Theorem 1.4 seems to be of independent interest. It may have other applications in discrepancy theory and optimization of discrete energies on the sphere (see, for instance, [26, 34]).
2. (ii)
In the case of wβ‘1, Theorem 1.4 with M=N and Οdβ(Rjβ)=N1β for j=1,β―,N is due to Bondarenko, Radchenko, and Viazovska
[6, Proposition 1].
The proof of Theorem 1.4 is, however, much more involved than the corresponding case of the surface Lebesgue measure dΟdβ due to the fact that the measure w(x)dΟdβ(x) is not rotation-invariant.
3. (iii)
Since the weight w may have zeros or discontinuities on Sdβ1, the integers kjβ:=Nw(Rjβ) in Theorem 1.4 in general depend on the location of Rjβ, which is different from the corresponding unweighted case. This difference also increases the technical difficulties of the proof of Theorem 1.1.
4. (iv)
If, in addition, the weight w satisfies the doubling condition, then according to (1.3), there exists a constant cwβ such that the condition, minxβSdβ1βw(B(x,r))β₯N1β, is satisfied whenever rβ₯cwβNβ1/swβ.
If we drop the convexity requirement in the partition in Theorem 1.4, we may deduce the following corollary:
Corollary 1.6**.**
Under the conditions of Theorem 1.4,
there exists a partition {R1β,β―,RNβ} of Sdβ1 such that
w(Rjβ)=N1β and diam(Rjβ)β€Cwβr for j=1,β―,N.
Corollary 1.6 follows directly from Theorem 1.4 due to the fact that if EβSdβ1 and 0<Ξ±<w(E), then there exists a subset F of E such that w(F)=Ξ±.
In order to establish similar results on other domains, we also need to consider weights on Sdβ1 that are symmetric under certain reflection groups, in which case it can be shown that the set of nodes in the corresponding Chebyshev cubature formula enjoys the same symmetry. Let us first describe briefly some necessary notation.
Given j=1,2,β―,d, we denote by Οjβ the reflection with respect to the coordinate plane xjβ=0; that is,
[TABLE]
Denote by Z2dβ the abelian
reflection group generated by the reflections Ο1β,β―,Οdβ.
A weight w on Sdβ1 is called Οjβ-invariant for a given j if w(xΟjβ)=w(x) for all xβSdβ1, and is called Z2dβ-invariant if
it is Οjβ-invariant for every j=1,2,β―,d.
Similarly, we say a finite subset Ξ of Sdβ1 is Οjβ-invariant for a given jβ{1,2,β―,d} if Ξ={xΟjβ:Β Β xβΞ}, whereas it is Z2dβ-invariant if it is Οjβ-invariant for every j=1,2,β―,d.
For simplicity, we set \SSinterdβ1β:={xβSdβ1:Β Β xiβξ =0,Β Β i=1,2,β―,d}.
A slight modification of the proof of Theorem 1.1 yields the following result.
Corollary 1.7**.**
Let w be a Z2dβ-invariant (resp. Οdβ-invariant) doubling weight on Sdβ1 normalized by w(Sdβ1)=1. Then the conclusions of Theorem Β 1.1 hold with the set of nodes Ξ:={z1β,β―,zNβ} being Z2dβ-invariant (resp. Οdβ-invariant) and contained in the set \SSinterdβ1β, (i.e. none of the nodes lies in the coordinate planes).
The rest of the paper is organized as follows. The first two sections are devoted to the proof of Theorem Β 1.4. To be more precise, in Section Β 2 we prove Theorem Β 1.4 under the additional condition 2dβ2NββN, which is technically easier, but already contains some crucial ideas. The proof of Theorem 1.4 for the general case of positive integer N is more complicated and involved, and is given in Section Β 3. A crucial ingredient used in the proof in Section Β 3 is the family of nonlinear dilations TΞ±β on the sphere that preserve geodesic simplexes.
Section Β 4 contains some preliminary lemmas that are either known or relatively easy to prove, but will be needed in the proof of Theorem 1.1. The final section, Section 5, is devoted to the proofs of Theorem 1.1 and Corollary 1.2. One of the main difficulties in our proofs comes from the fact that the positive integers Nw(Rjβ) in Theorem 1.4 ( i.e., the theorem on convex partition) may not be equal to one, which is different from the unweighted case.
For the rest of the paper, we use the notation
Cwβ, Lwβ , etc. (cwβ , Ξ»wβ, etc.) for sufficiently large (small) constants depending only on the dimension d and the doubling constant of w.
Sor simplicity, we will always assume that dβ₯3 (i.e., Sdβ1ξ =\SS1). The case of d=2 (i.e., Sdβ1=\SS1) can be treated similarly and is, in fact, much simpler.
This section is devoted to the proof of Theorem 1.4 under the additional assumption 2dβ2NββN.
2.1. Preliminaries
We start with the concept of geodesic simplex, which will play a crucial role in our proof.
Definition 2.1**.**
A subset S of Sdβ1 is called a geodesic simplex of Sdβ1 spanned by a set of linearly independent vectors ΞΎ1β,β―,ΞΎdββSdβ1 and is denoted by S=convSdβ1β{ΞΎ1β,β―,ΞΎdβ} if
[TABLE]
A geodesic simplex S is called admissible if, in addition, the vectors ΞΎ2β,β―,ΞΎdβ are mutually orthogonal, arccosΞΎ1ββ ΞΎ2ββ[6Οβ,2Οβ] and ΞΎ1ββ ΞΎjβ=0 for j=3,β―,d, in which case {ΞΎ1β,β―,ΞΎdβ} is called an admissible subset of Sdβ1.
Next, we introduce some necessary notation.
For any two distinct points ΞΎ,Ξ·βSdβ1, we denote by Arc(ΞΎ,Ξ·) the geodesic arc connecting ΞΎ and Ξ·; that is, Arc(ΞΎ,Ξ·)={t1βΞΎ+t2βΞ·:Β Β t1β,t2ββ₯0,Β Β t1βΞΎ+t2βΞ·βSdβ1}.
For xξ =yβRd, let [x,y] denote the line segment {(1βt)x+ty:Β Β tβ[0,1]}.
A partition {E1β,β―,Enβ} of a set EβRd is called convex if each Ejβ is a convex subset of Rd. Denote by convRdβ(E) the regular convex hull of a set E in Rd.
Given a set A={Ξ·1β,β―,Ξ·dβ} of d linearly independent vectors in Rd, the convex hull T=convRdβ(A) is called a surface simplex spanned by the set A.
The following lemma can be verified by straightforward calculations.
Lemma 2.2**.**
Let
T:=convRdβ{Ξ·1β,β―,Ξ·dβ}
denote a surface simplex in Rd and S=convSdβ1β{Ξ·1β,β―,Ξ·dβ}
a geodesic simplex in Sdβ1 both being spanned by a set of linearly independent vectors Ξ·1β,β―,Ξ·dββSdβ1. Let HTβ denote the hyperplane passing through the points Ξ·1β,β―,Ξ·dβ. Let g(x)=β₯xβ₯xβ for xβRdβ{0}.
Then the following statements hold:
(i)
xβS* if and only if xβSdβ1 and x=βj=1dβtjβΞ·jβ
for some t1β,β―,tdββ₯0.*
2. (ii)
g:xβ¦β₯xβ₯xβ* is a bijective continuously differentiable mapping from T onto S that maps each convex subset of T to a geodesically convex subset of S. Furthermore, g([x,y])=Arc(g(x),g(y)) for any two distinct points x,yβT.*
3. (iii)
For each nonnegative measurable function F:Sβ[0,β),
[TABLE]
where a:=minxβTββ₯xβ₯.
4. (iv)
If minxβTββ₯xβ₯=a, then
[TABLE]
The following geometric fact, which can also be easily verified through straightforward calculations, will be used frequently in our proof.
Lemma 2.3**.**
Assume that x=ΞΎcosΞΈ1β+Ξ·1βsinΞΈ1β and y=ΞΎcosΞΈ2β+Ξ·2βsinΞΈ2β, where ΞΎ,Ξ·1β,Ξ·2ββSdβ1, Ξ·iββ ΞΎ=0 and 0β€ΞΈiββ€Ο for i=1,2. Then
[TABLE]
Thus,
[TABLE]
Finally, we need the following geometric property concerning convex sets in Rd.
Lemma 2.4**.**
If G is a convex subset of Rd with diameter 2r and volume β₯cdβrdβ1a for some aβ(0,r], then G contains a Euclidean ball of radius cdβ²βa for some positive constant cdβ²β.
Proof.
We use induction on the dimension d. The conclusion holds trivially for d=1 since every convex subset of R must be an interval. Now assume that the conclusion has been proven in Rdβ1, and we will deduce it for the case of Rd as follows.
We denote by mdβ the d-dimensional Lebesgue measure (i.e., the d-dimensional Hausdorff measure). Let p,qβG be such that 2r=β£pβqβ£=diam(G), and let ΞΎ denote the unit vector in the direction of qβp. Then
Gβ{xβRd:Β Β 0β€(xβp)β ΞΎβ€2r}.
For 0β€tβ€2r, let
G(t)={xβG:Β Β (xβp)β ΞΎ=t}.
It is easily seen that each slice G(t) is a compact convex subset of the hyperplane S(t):={xβRd:Β Β (xβp)β ΞΎ=t}, and moreover,
[TABLE]
Thus, there must exist 0<t0β<2r such that
mdβ1β(G(t0β))>cβ²rdβ2a>0.
Since diam(G(t0β))β€diam(G)=2r, it follows by the induction hypothesis that
G(t0β) contains a (dβ1)-dimensional ball B={xβS(t0β):Β Β β£xβz0ββ£β€ca} for some z0ββS(t0β) and c=cdβ>0.
Without loss of generality, we may assume that rβ€t0ββ€2r since otherwise we interchange the order of the points p and q.
It suffices to show that the convex hull H of the set Bβͺ{p} contains a ball of radius cdβa. Indeed, by rotation invariance, we may assume that
p=0 and ΞΎ=edβ.
We then write z0β=(u0β,t0β) and let Q denote the cube in Rdβ1 centered at u0β and having side length Ξ΅dβa for a sufficiently small constant Ξ΅dβ. Clearly, the rectangle R=QΓ[(1βrΞ΅dβaβ)t0β,t0β] contains a d-dimensional ball of radius cdβ²βa. However,
a straightforward calculation shows that RβH.
β
2.2. Organization of the proof
We divide the proof into two main steps. At the first step, we prove
Proposition 2.5**.**
Let w be a weight on Sdβ1 normalized by w(Sdβ1)=1. If 2dβ2NββN and Nβ₯maxxβSdβ1βw(B(x,10βd))1β, then there exists a partition {T1β,β―,Tmβ} of Sdβ1 such that each Tjβ is an admissible geodesic simplex in Sdβ1 satisfying Nw(Tjβ)βN.
To state our main result in the next step, we need to introduce some notation. Given a surface simplex T in Rd, we denote by HTβ the hyperplane in which the surface simplex T lies, and B(x,r)HTββ the ball {yβHTβ:Β Β β₯xβyβ₯β€r} with center xβHTβ and radius r>0 in the hyperplane HTβ. For a weight function w on T, we write w(E)=β«Eβw(x)dx for EβT, where dx denotes the surface Lebesgue measure on T.
At the second step, we prove
Proposition 2.6**.**
Let
T be a surface simplex in Rd spanned by a admissible subset of Sdβ1 with dβ₯3, and let w be a weight on T such that Nw(T)βN for some NβN. Assume that there exists rNββ(0,1) such that w(B)β₯N1β for every ball B=B(x,rNβ)HTβββT.
Then there exists a convex partition {E1β,β―,En0ββ} of T such that Nw(Ejβ)βN and B(xjβ,cdβ²βrNβ)HTβββEjββB(xjβ,cdβrNβ)HTββ for some xjββEjβ and all 1β€jβ€n0β.
For the moment, we take Proposition 2.5 and Proposition 2.5 for granted and proceed with the proof of Theorem 1.4.
Assume that 2dβ2NββN, and set Ξ΄0β=minxβSdβ1βw(B(x,10βd)).
We consider the following two cases:
Case 1:Β Β 1β€Nβ€Ξ΄0β1β.
In this case, rβ₯10βd. Thus, by Lemma 2.2 and Lemma 2.4,
it suffices to prove the following assertion: given any integer Mβ₯1 and any weight w such that w(B)>0 for every spherical cap BβSdβ1, there exists a convex partition R1β,β―,RMβ of Sdβ1 with w(Rjβ)=M1β for 1β€jβ€M.
We prove this last assertion by induction on the dimension d. If d=2, then the stated assertion follows directly by continuity.
Now assume that the assertion holds on the sphere \SSdβ2 with dβ₯3. Let
wdβ1β(ΞΎ)=β«0Οβw(cosΞΈ,ΞΎsinΞΈ)sindβ2ΞΈdΞΈ for ΞΎβ\SSdβ2.
Clearly, wdβ1β(B)>0 for every spherical cap B in \SSdβ2.
By the induction hypothesis, there exists a convex partition E1β,β―,EMβ of \SSdβ2 with wdβ1β(Ejβ)=M1β for 1β€jβ€M.
Now set
[TABLE]
It is easily seen that {R1β,β―,RMβ} is a convex partition of Sdβ1. Moreover, for each 1β€jβ€M,
[TABLE]
This completes the induction.
Case 2.Nβ₯Ξ΄0β1β.
In this case, w(B(x,10βd))β₯Ξ΄0ββ₯N1β for any xβSdβ1. Hence,
applying Proposition 2.5, there exists a partition Sdβ1=βj=1mβSjβ of Sdβ1 such that each Sjβ is an admissible geodesic simplex in Sdβ1 with Nw(Sjβ)βN.
Let Tjβ be the surface simplex in Rd such that g(Tjβ)=Sjβ.
Set ajβ:=minxβTjβββ₯xβ₯ and define
wjβ(x)=w(g(x))β₯xβ₯dajββ for xβTjβ. Itβs easily seen that 2d1ββ€ajββ€1. Moreover,
according to Lemma 2.2 (iii) and (iv), wjβ is a weight on Tjβ satisfying the following two conditions: (a)
wjβ(E)=w(g(E)) for each EβTjβ, and (b) there exists a constant rNββΌdβr such that
[TABLE]
whenever B(x,rNβ)HTjββββTjβ. Thus, applying Proposition 2.6 to the weight wjβ on each surface simplex Tjβ, we obtain a convex partition
Tjβ=βi=1njββEj,iβ such that
B(xj,iβ,c1βrNβ)HTjββββEj,iββB(xj,iβ,c2βrNβ)HTjβββ and Nwjβ(Ej,iβ)βN for all 1β€iβ€njβ. Finally, setting Rj,iβ=g(Ej,iβ) for 1β€jβ€m and 1β€iβ€njβ, and applying Lemma 2.2 (ii), we obtain a convex partition {Rj,iβ:Β Β 1β€jβ€m,Β 1β€iβ€njβ} of Sdβ1 such that Nw(Rj,iβ)βN and
B(g(xj,iβ),c1β²βrNβ)βRj,iββB(g(xj,iβ),c2β²βrNβ) for all 1β€iβ€njβ and 1β€jβ€m.
For simplicity,
we say that a set EβSdβ1 has a regular geodesic simplex partition with respect to the integer N and the weight w on Sdβ1 if it can be written as a finite union of admissible geodesic simplexes S1β,β―,Snβ whose interiors are pairwise disjoint and such that Nw(Sjβ))βN for each 1β€jβ€n.
First, we claim that Proposition 2.5 is a consequence of the following assertion:
(A) Β Β *The spherical cap B(edβ,2Οβ)βSdβ1 has a regular geodesic simplex partition with respect to the integer N and the weight w on Sdβ1 whenever N and w satisfy the following conditions (i) w(B(edβ,2Οβ))=21β; (ii) 2dβ2NββN; and (iii) Nβ₯maxxβSdβ1βw(B(x,10βd))1β, where edβ=(0,0,β―,0,1)βSdβ1.
To see this, let w be a weight on Sdβ1 satisfying the conditions of Proposition 2.5. Then w(B(x,2Οβ))+w(B(βx,2Οβ))=w(Sdβ1)=1 for all xβSdβ1. It follows by continuity that
w(B(x0β,2Οβ))=w(B(βx0β,2Οβ))=21β for some x0ββSdβ1. Let ΟβSO(d) be a rotation such that Οedβ=x0β and set w(x):=w(Οx) for xβSdβ1. Applying Assertion (A) to the weight w on Sdβ1 and the integer N, we conclude that the spherical cap B(x0β,2Οβ) has a regular geodesic simplex partition with respect to N and w. A similar argument also yields the same conclusion for the spherical cap B(βx0β,2Οβ). Since {B(x0β,2Οβ),B(βx0β,2Οβ)} is a partition of Sdβ1, it follows that the sphere Sdβ1 itself has a regular geodesic simplex partition with respect to N and w. This shows the claim.
Assertion A can be proved using induction on the dimension d.
We start with the case of d=3. For simplicity, we write ΞΎΟβ:=(cosΟ,sinΟ,0)
for 0β€Οβ€2Ο, and set T(Ξ±,Ξ²):=conv\SS2β{e3β,ΞΎΞ±β,ΞΎΞ²β} for 0β€Ξ±<Ξ²β€2Ο; that is,
[TABLE]
By Lemma 2.3, it is easily seen that for any Οβ[0,2Ο),
[TABLE]
which in particular implies that
[TABLE]
By continuity, we conclude that for any Οβ[0,2Ο], there exists Ξ±β[Ο+6Οβ,Ο+3Οβ] such that Nw\Bigl{(}T(\varphi,{\alpha})\Bigr{)}\in{\mathbb{N}}. Invoking this fact iteratively, we
obtain a sequence of numbers {Ξ±jβ}j=0k0ββ1β such that Ξ±0β=0,
[TABLE]
where k0ββ€12 is the smallest positive integer such that Ξ±k0ββ1β+6Οβ<2Ο.
Setting Ξ±k0ββ=2Ο, we have that
6Οβ<2ΟβΞ±k0ββ1β=Ξ±k0βββΞ±k0ββ1ββ€2Οβ. Since N is even, we have
[TABLE]
Thus,
Nw\bigl{(}T({\alpha}_{k_{0}-1},{\alpha}_{k_{0}})\bigr{)}\in{\mathbb{N}}. Since B(e3β,2Οβ)=βj=1k0ββT(Ξ±jβ1β,Ξ±jβ), we prove Assertion (A) for the case of d=3.
Now assume that Assertion A holds on the sphere Sdβ1 for some dβ₯3, which in turn implies Proposition 2.5 for the sphere Sdβ1.
To show Assertion (A) on \SSd,
assume that 2dβ1NββN and let wdβ be a weight on \SSd such that wdβ(B(ed+1β,2Οβ))=21β and Nβ₯maxxβSdβ1βw(B(x,10βdβ1))1β. For EβSdβ1, we write,
[TABLE]
Define
[TABLE]
Clearly, wdβ1β is a weight on the sphere Sdβ1 satisfying that for each EβSdβ1,
[TABLE]
In particular, w_{d-1}(\mathbb{S}^{d-1})=2w_{d}\Bigl{(}B_{\SS^{d}}(e_{d+1},\frac{\pi}{2})\Bigr{)}=1.
Next, setting Ξ΄dβ=10βdβ1 and N1β=N/2,
we claim that
[TABLE]
where the notation B\SSββ(x,r) is used for the spherical cap in \SSβ.
For the proof of (2.4), it is sufficient to show that for any xβSdβ1,
[TABLE]
yxβ=(xsin4Οβ,cos4Οβ)β\SSd.
Indeed, once (2.5) is proved, then
[TABLE]
To show (2.5), let
z=(ΞΎsinΞΈ,cosΞΈ)βB\SSdβ(yxβ,Ξ΄dβ) with ΞΈβ[0,Ο] and ΞΎβSdβ1.
Then by Lemma 2.3, β£ΞΈβ4Οββ£β€d(yxβ,z)β€Ξ΄dβ (which implies 6Οββ€ΞΈβ€3Οβ), and
[TABLE]
This means that ΞΎβBSdβ1β(x,Ξ΄dβ1β) and hence
z=(\xi\sin{\theta},\cos{\theta})\in S\Bigl{(}B_{\mathbb{S}^{d-1}}(x,{\delta}_{d-1})\Bigr{)}.
(2.5) then follows.
Now applying the induction hypothesis to the weight wdβ1β on Sdβ1 and the integer N1β, we conclude that there exists a regular geodesic simplex partition {E1β,β―,Emβ} of Sdβ1 with respect to the integer N1β and the weight wdβ1β on Sdβ1.
Setting Sjβ=S(Ejβ) for 1β€jβ€m, we obtain a partition {S1β,β―,Smβ} of the spherical cap B\SSdβ(ed+1β,2Οβ) satisfying that for each 1β€jβ€m,
[TABLE]
Thus, to complete the proof, it remains to show that each Sjβ is an admissible geodesic simplex on \SSd. Since each Ejβ is an admissible geodesic simplex in Sdβ1, there exists an admissible subset {ΞΎj,1β,β―,ΞΎj,dβ} of Sdβ1 such that Ejβ=convSdβ1β{ΞΎj,1β,β―,ΞΎj,dβ} for each 1β€jβ€m. Using Lemma 2.2 (i), it is easily seen that
[TABLE]
where ΞΎj,iββ=(ΞΎj,iβ,0)β\SSd for i=1,β―,d.
Since {ΞΎj,1ββ,β―,ΞΎj,dββ,ed+1β} is an admissible subset of \SSd, we conclude that each Sjβ is an admissible geodesic simplex of \SSd. This completes the proof.
Remark 2.7*.*
If w is a Οdβ-invariant weight on Sdβ1 with w(Sdβ1)=1, then the condition (i) of Assertion (A) always holds.
Remark 2.8*.*
If w is a normalized Z2dβ-invariant weight on Sdβ1, and S=convSdβ1β{e1β,β―,edβ}, then SΟβ:={xΟ:Β Β xβS} is an admissible geodesic simplex with w(SΟβ)=2d1β for each ΟβZ2dβ. Moreover, {SΟβ:Β Β ΟβZ2dβ} is a partition of Sdβ1. Thus, Proposition Β 2.5 holds trivially if w is Z2dβ-invariant, w(Sdβ1)=1 and 2dNββN.
Let e1β=(1,0,β―,0),β―,edβ=(0,β―,0,1) denote the standard canonical basis in Rd.
Without loss of generality, we may assume that T=convRdβ{ΞΎ1β,e2β,β―,edβ} with
ΞΎ1β=(sinΞΈ,cosΞΈ,0,β―,0) for some 6Οββ€ΞΈβ€2Οβ,
in which case T can be written explicitly as
[TABLE]
For the rest, we fix ΞΈβ[6Οβ,2Οβ], and denote by Tdβ the simplex in Rd given by
[TABLE]
Also, we will use the notation B(x,r)Rdβ to denote the Euclidean ball {yβRd:Β Β β₯yβxβ₯β€r} in Rd.
For the proof of Proposition 2.6, we claim that
it is sufficient to show the following assertion:
(B) *If dβ₯2, NβN, rβ(0,1) and w is a weight on Tdβ such that Nw(Tdβ)βN, and \inf\bigl{\{}w(B):B=B(x,r)_{{\mathbb{R}}^{d}}\subset T_{d}\bigr{\}}\geq\frac{1}{N}, then Tdβ has a convex partition {R1β,β―,Rn0ββ} which satisfies that Nw(Rjβ)βN and B(xjβ,cdβ²βr)RdββRjββB(xjβ,cdβr)Rdβ for each 1β€jβ€n0β and some constants cdβ²β,cdβ>0.
To show the claim, for dβ₯3, we
let Ξ¨:Tdβ1ββT denote the mapping given by xβ¦(x,Ο(x)) with Ο(x)=1βx1βtan2ΞΈβββj=2dβ1βxjβ for xβTdβ1β. Clearly, Ξ¨:Tdβ1ββT is a bijective mapping that maps convex sets to convex sets and satisfies β₯xβyβ₯β€β₯Ξ¨(x)βΞ¨(y)β₯β€Cdββ₯xβyβ₯ for any x,yβTdβ1β. Moreover, for each nonnegative function f:Tβ[0,β), we have
[TABLE]
where aΞΈβ:=dβ1+tan22ΞΈββ. Thus, setting wdβ1β(x)=aΞΈβw(Ξ¨(x)) for xβTdβ1β, we have that wdβ1β(E)=w(Ξ¨(E)) for each EβTdβ1β. In particular, this implies that Nwdβ1β(Tdβ1β)=Nw(T)βN
and wdβ1β(B)=w(Ξ¨(B))β₯N1β whenever B=B(x,rNβ)Rdβ1ββTdβ1β.
Thus, applying AssertionΒ (B) to the integer N and the weight wdβ1β on Tdβ1β, we get a partition {R1β,β―,Rn0ββ} of Tdβ1β. It follows that {Ejβ=Ξ¨(Rjβ):Β Β j=1,β―,n0β} is a convex partition of the surface simplex T with the stated properties in Proposition 2.6.
This shows the claim.
It remains to prove AssertionΒ (B). We shall use induction on the dimension d.
Let Ldββ₯10 be a large constant that will be specified later.
Let r1β=Ldβr. Without loss of generality,
we may assume that 0<rβ€100Ldβ1β since otherwise Assertion (B) holds trivially with n0β=1.
We start with the case of d=2. Note that T2β is an isosceles triangle with vertices at (0,0), (0,1) and (sinΞΈ,cosΞΈ) in the x1βx2β-plane. By rotation invariance of Assertion (B),
we may assume, without loss of generality, that T2β is the triangle with vertices at A=(βsin2ΞΈβ,cos2ΞΈβ), B=(sin2ΞΈβ,cos2ΞΈβ) and O=(0,0) in the x1βx2β-plane.
For
0β€t<sβ€1, we set
β³(t,s):={(ux,uy):Β Β (x,y)βT2β,Β Β tβ€uβ€s}.
It is easily seen that for any 0β€sβ€1β3r1β, the set β³(s+r1β,s+3r1β) contains a ball of radius r, and hence w(β³(s+r1β,s+3r1β))β₯N1β. By continuity, this implies that for each sβ[0,1β3r1β], there exists tβ[s+r1β,s+3r1β] such that Nw(β³(s,t))βN. Using this fact iteratively, we can construct a partition 0=t0β<t1β<β―<tkβ=1 of [0,1] such that
tjβ1β+r1ββ€tjββ€tjβ1β+3r1β and Nw(β³(tjβ1β,tjβ))βN for 1β€jβ€kβ1,
where k is the largest positive integer so that 3r1ββ€1βtkβ1ββ€6r1β. Since Nw(T2β)βN, we also have that Nw(β³(tkβ1β,1))βN.
Note that for 0β€jβ€kβ1,
[TABLE]
For simplicity, we set β³jβ:=β³(tjβ1β,tjβ) for 1β€jβ€k.
We construct a convex partition of the domain β³jβ for each 10β€jβ€k as follows.
Let Ajβ(s)=tjβA+tjβ(BβA)s, sβ[0,1] denote the parametric representation of the line segment from tjβA to tjβB.
For 0β€s<tβ€1, we denote by Tjβ(s,t) the
trapezoid with vertices at Ajβ1β(s), Ajβ1β(t), Ajβ(s) and Ajβ(t). It follows from (2.6) that for 0β€sβ€1βjβ1
[TABLE]
and diam(Tjβ(s,s+jβ1))βΌr1β .
By Lemma 2.4, this implies that Tjβ(s,s+jβ1) contains a ball of radius c2βL2βr. Thus, taking L2β>c2β1β, we conclude that w\Bigl{(}T_{j}(s,s+j^{-1})\Bigr{)}\geq\frac{1}{N} for all sβ[0,1βjβ1]. By continuity, this implies that for any sβ[0,1β3jβ1], there exists tβ[s+jβ1,s+3jβ1] such that Nw(Tjβ(s,t))βN. Applying this fact iteratively, and recalling that Nw(β³jβ)βN, we may construct a partition 0=sj,0β<sj,1β<β―<sj,mjββ=1 of [0,1] such that
sj,iβ1β+jβ1β€sj,iββ€sj,iβ+3jβ1 for 1β€iβ€mjββ1, jβ1β€sj,mjβββsj,mjββ1ββ€6jβ1 and Nw\Bigl{(}T_{j}(s_{j,i-1},s_{j,i})\Bigr{)}\in{\mathbb{N}} for 1β€iβ€mjβ.
Using Lemma 2.4, we know that each set Tjβ(sj,iβ1β,sj,iβ) contains a ball of radius r and has diameter βΌr.
Now putting the above together, we obtain a convex partition of T2β:
[TABLE]
Assertion (B) for d=2 then follows.
Now assume that Assertion (B) has been proven for the simplex Tdβ1ββRdβ1. Let N and w be a positive integer and a weight on Tdβ satisfying the conditions of Assertion (B).
Note that for any nonnegative function f on Tdβ,
[TABLE]
For 0β€t<1βr1β, define
[TABLE]
It is easily seen that Etβ is a convex set in Rd with diameter βΌt+r1β. Furthermore, by (2.7), we have Voldβ(Etβ)βΌ(t+r1β)dβ1r1β. Thus, according to Lemma 2.4, for each 0β€t<1βr1β, the set Etβ must contain a ball of radius at least cdβr1β=cdβLdβr. Taking the constant Ldβ sufficiently large so that cdβLdβ>1, we obtain from the assumption of Assertion (B) that that w(Etβ)β₯N1β for all 0β€tβ€1βr1β.
This together with the fact that Nw(Tdβ)βN implies that there is a partition 0=t0β<t1β<β―<tmβ=1 of [0,1] such that tjβ1β+r1ββ€tjββ€tjβ1β+3r1β for 1β€jβ€mβ1, tmβ1β+r1ββ€tmββ€tmβ1β+3r1β and
Nw(Ajβ)βN for 1β€jβ€m, where
A_{j}:=\Bigl{\{}(sx^{\prime},1-s):x^{\prime}\in T_{d-1},\ \ t_{j-1}\leq s\leq t_{j}\Bigr{\}}.
Next, for each 1β€jβ€m, we define a weight function wjβ on Tdβ1β by
[TABLE]
We claim that for each ball BβTdβ1β with radius r1β, wjβ(B)β₯N1β. Indeed, setting
[TABLE]
and using (2.7),
we see that Bjβ is
a convex subset of Tdβ with diameter βΌr1β and volume βΌr1dβ, By Lemma 2.4, this implies that Bjβ contains a ball of radius cdβr1ββ₯r. Using (2.7), we obtain
wjβ(B)=w(Bjβ)β₯N1β.
This shows the claim.
Now applying the induction hypothesis to the integer N, the radius r1β and the weights wjβ on Tdβ1β, we conclude that for each 1β€jβ€m, the simplex Tdβ1β has a convex partition Rj,1β,β―,Rj,kjββ such that B(xj,iβ,cdβr1β)Rdβ1ββRj,iββB(xj,iβ,cdβ²βr1β)Rdβ1β and Nwjβ(Rj,iβ)βN.
Setting
[TABLE]
we get a convex partition Ajβ=βi=1kjββTj,iβ of the set Ajβ
satisfying that Nw(Tj,kβ)=Nw1β(Rj,kβ)βN, diam(Tj,kβ)βΌr1β and Voldβ(Tj,kβ)βΌr1dβ.
This shows that {Tj,iβ:Β Β 1β€jβ€m,Β Β 1β€iβ€kjβ} is a convex partition of Tdβ with the stated properties in Assertion (B).
2.5. Concluding remarks
Combining Remarks 2.7 and 2.8 with Proposition 2.6, we obtain
Corollary 2.9**.**
Let w be a weight on Sdβ1 that is either Οdβ-invariant or Z2dβ-invariant and which satisfies the conditions of Theorem 1.4 for some rβ(0,Ο) and positive even integer N. Assume in addition that 2βdN is an integer if w is Z2dβ-invariant.
Let S denote either the semisphere {xβSdβ1:Β Β xdββ₯0} or the geodesic simplex {xβSdβ1:Β Β x1β,β―,xdββ₯0} according to whether w is Οdβ-invariant or Z2dβ-invariant.
Then S has a convex partition
{R1β,β―,RMβ} for which the sets RjββS satisfy Conditions (i) and (ii) of Theorem 1.4.
3. Proof of Theorem 1.4: the general case of NβN
Our goal in this section is to prove Theorem 1.4 without the extra condition 2dβ2NββN. Assume that w is a weight on Sdβ1 normalized by w(Sdβ1)=1 and satisfying that
w(B)>0 for every spherical cap BβSdβ1. Let rβ(0,1) and a positive integer N satisfying that infxβSdβ1βw(B(x,r))β₯N1β. We will keep these assumptions throughout this section. For convenience, we introduce the following concept.
Definition 3.1**.**
Given a parameter Ξ΅β(0,1), we say a subset A={Ξ·1β,β―,Ξ·mβ} of m distinct points (mβ€d) on Sdβ1 is strongly Ξ΅-separated if for each j=1,β―,m,
[TABLE]
A geodesic simplex in Sdβ1 is said to be in the class SΞ΅β
if it is spanned by a set of d strongly Ξ΅-separated points Ξ·1β,β―,Ξ·dβ in Sdβ1.
Theorem 1.4 is a direct consequence of the following two propositions.
Proposition 3.2**.**
Let Ξ΅β(0,1) be a given parameter and
S a geodesic simplex from the class SΞ΅β. If Nw(S)βN,
then there exists a convex partition {R1β,β―,Rnβ} of S such that Nw(Rjβ)βN and BSdβ1β(xjβ,cd,Ξ΅βr)βRjββBSdβ1β(xjβ,cd,Ξ΅β²βr) for each 1β€jβ€n.
Proposition 3.3**.**
There exists a partition {S1β,β―,Smβ} of Sdβ1 such that each Sjβ is a geodesic simplex from the class SΞ΅dββ satisfying that Nw(Sjβ)βN, where Ξ΅dβ is a positive parameter depending only on d.
Proposition 3.2 is a direct consequence of Proposition 2.6. For completeness, we write its proof below.
Firstly, assume that S is spanned by a set of strongly Ξ΅-separated points Ξ·1β,β―,Ξ·dββSdβ1 for some Ξ΅β(0,1), and let T=convRdβ{Ξ·1β,β―,Ξ·dβ}. We claim that a:=minxβTββ₯xβ₯β₯Ξ΅/d. To see this, let x=βj=1dβtjβΞ·jββT be such that a=β₯xβ₯, where t1β,β―,tdββ₯0 and βj=1dβtjβ=1. Without loss of generality, we may assume that t1β=max1β€jβ€dβtjβ. Then t1ββ₯d1β, and
[TABLE]
Secondly,
let A:=[Ξ·1βΒ Ξ·2βΒ β―Β Ξ·dβ] denote the nonsingular dΓd real matrix with column vectors Ξ·1β,β―,Ξ·dβ. We assert that
[TABLE]
Without loss of generality, we may assume that xβSdβ1 and β£x1ββ£=max1β€jβ€dββ£xjββ£. On the one hand, by the Cauchy-Schwarz inequality,
[TABLE]
On the other hand, however, since β£x1ββ£β₯dβ1β, we have
Finally, we prove the assertion of Proposition 3.2. Consider the bijective mapping Ξ¦:xβ¦g(Ax) from the surface simplex T0β=convRdβ{e1β,β―,edβ} to the geodesic simplex S. According to Lemma 2.2 (ii), Ξ¦ maps convex sets to geodesic convex sets, and by
(3.1) and Lemma 2.2 (iv),
[TABLE]
Since Ξ¦ maps boundary of T0β to boundary of S, (3.2) in particular implies that if B(x,t)HT0ββββT0β for some xβT0β and tβ(0,1), then
[TABLE]
On the other hand,
using Lemma 2.2 (iii), we obtain by a change of variable that
for each nonnegative function f on S,
[TABLE]
Thus, setting
w0β(x)=aβ£detAβ£w(Ξ¦(x))/β₯Axβ₯d for xβT0β, we have Nw0β(T0β)=Nw(S)βN and
[TABLE]
with c=1/c1,dβΞ΅2.
Thus, according to Proposition 2.6, T0β has a convex partition T0β=βj=1mβT0,jβ with the properties that
B(xjβ,cdβr)HT0ββββT0,jββB(xjβ,cdβ²βr)HT0βββ and Nw0β(T0,jβ)βN for all
1β€jβ€m. Setting
[TABLE]
and using (3.3) and Lemma 2.2, we conclude that {R1β,β―,Rmβ} is a convex partition of the geodesic simplex S with the stated properties in Proposition 3.2.
β
Finally, we turn to the proof of Proposition Β PropsitionΒ 3.3, which is more involved. The important ingredient used in the proof is a family of nonlinear dilations on Sdβ1, which we shall introduce and study in the subsection that follows.
3.1. A family of nonlinear dilations
Throughout this subsection, we write x(Ο,ΞΎ)=(cosΟ,ΞΎsinΟ)βSdβ1
for (Ο,ΞΎ)β[0,Ο]Γ\SSdβ2.
Definition 3.4**.**
For 0β€Ξ±<Ξ²β€2Ο, define
[TABLE]
where it is agreed that \SS0={Β±1} when d=3.
Next, for 0<Ξ±<2Οβ, we define the function hΞ±β:[β1,1]β(0,1] by
[TABLE]
It is easily seen that Ο2βΞ±β€hΞ±β(t)β€1 for tβ[β1,1] and
[TABLE]
Using the function hΞ±β, we may define a nonlinear dilation TΞ±βx of xβSdβ1 with respect to the angle between x and e1β as follows:
Definition 3.5**.**
Given 0<Ξ±<2Οβ,
define the mapping TΞ±β:\SSdβ1β{βe1β}β\SSdβ1β{βe1β} by
T_{\alpha}(x):=\mathbf{x}\bigl{(}h_{\alpha}(\xi_{1})\varphi,\xi\bigr{)} for x=x(Ο,ΞΎ)β\SSdβ1β{βe1β}
with Οβ[0,Ο) and ΞΎ=(ΞΎ1β,β―,ΞΎdβ1β)β\SSdβ2.
The following lemma collects some useful properties of TΞ±β:
Lemma 3.6**.**
Let 0<Ξ±<2Οβ and let \SS0dβ1β:={xβ\SSdβ1:Β Β x1β=0,Β x2ββ₯0}. Then the following statements hold:
(i)
If x,yβSdβ1 and 0β€d(x,e1β),d(y,e1β)β€43Οβ, then
[TABLE]
2. (ii)
TΞ±β* is a bijective mapping from S(0,2Οβ) to S(0,Ξ±) that maps boundary of S(0,2Οβ) to the boundary of S(0,Ξ±).*
3. (iii)
For every nonnegative measurable function f on S(0,Ξ±),
[TABLE]
where
[TABLE]
4. (iv)
If SβS(0,2Οβ) is geodesic simplex spanned by e1β and a set of independent vectors Ξ·1β,β―,Ξ·dβ1ββ\SS0dβ1β, then the set TΞ±β(S)βS(0,Ξ±) is a geodesic simplex spanned by the set {TΞ±β(Ξ·1β),TΞ±β(Ξ·2β),β¦,TΞ±β(Ξ·dβ1β),e1β}.
5. (v)
If {Ξ·1β,β―,Ξ·dβ1β} is a set of strongly Ξ΅-separated points in \SS0dβ1β for some Ξ΅β(0,1), then {TΞ±β(Ξ·1β),β―,TΞ±β(Ξ·dβ1β),e1β} is a set of strongly cd,Ξ±βΞ΅-separated points on Sdβ1.
Proof.
(i) Assume that x=x(ΞΈ1β,ΞΎ) and y=x(ΞΈ2β,Ξ·) with 0β€ΞΈ1ββ€ΞΈ2ββ€43Οβ. According to Lemma 2.3, we have
which combined with (3.7) and (3.8) implies that
d(TΞ±βx,TΞ±βy)β€Cd,Ξ±βd(x,y).
On the other hand, a similar argument shows that
[TABLE]
which, using (3.7) and (3.8) once again, implies the inverse inequality d(x,y)β€d(TΞ±βx,TΞ±βy). This completes the proof of (i).
(ii) Since (Ο,ΞΎ)β¦x(Ο,ΞΎ) is an injective mapping from (0,Ο)Γ\SSdβ2 to Sdβ1, it follows that TΞ±β:Sdβ1β{βe1β}βSdβ1β{βe1β} is injective. To show that TΞ±β is a mapping from S(0,2Οβ) onto S(0,Ξ±), we need the following fact, which is a direct consequence of Definition 3.4:
Fact 1.Β Β If 0<Ξ±β€2Οβ,
then x(Ο,ΞΎ)βS(0,Ξ±) if and only if Ο=0 or 0<Οβ€2Οβ, ΞΎ1ββ₯0 and tanΟβ€ΞΎ1βtanΞ±β, where is agreed that tan2Οβ=β and 0tanΞ±β=β.
Note also that according to Definition 3.5, if x=(x1β,x2β,β―,xdβ)βSdβ1β{βe1β} with x2β=0, then TΞ±βx=x, which in particular implies TΞ±β(e1β)=e1ββS(0,Ξ±).
If x=x(Ο,ΞΎ)βS(0,Ο/2)β{e1β}, then 0<Οβ€2Οβ, ΞΎ1ββ₯0 and
tan(hΞ±β(ΞΎ1β)Ο)β€tan(2ΟβhΞ±β(ΞΎ1β))=ΞΎ1βtanΞ±β,
which, by Fact 1, implies that TΞ±β(x)βS(0,Ξ±). Conversely, if y=x(Ο1β,ΞΎ)βS(0,Ξ±)β{e1β}, then by Fact 1, 0<Ο1ββ€2Οβ, 0β€ΞΎ1ββ€1, tan(Ο1β)β€ΞΎ1βtanΞ±β,
and hence
[TABLE]
This implies that x=x(hΞ±β(ΞΎ1β)Ο1ββ,ΞΎ)βS(0,2Οβ) and y=TΞ±β(x). Finally, we show TΞ±β maps boundary of S(0,2Οβ) to boundary of S(0,Ξ±). Indeed,
if x=(r,01βr2βΞ·)βS(0,2Οβ) with 0β€rβ€1, then TΞ±βx=xβS(0,Ξ±).
On the other hand, it can easily verified that
if x=(0,ΞΎ)βS(0,2Οβ) with ΞΎ1β>0, then TΞ±βx=(rcosΞ±,ΞΎ1β(rsinΞ±)ΞΎβ)βS(0,Ξ±) with r=ΞΎ12βcos2Ξ±+sin2Ξ±βΞΎ1ββ.
(iii) Using Fact 1, we obtain
[TABLE]
which, by a change of variable Ο=hΞ±β(ΞΎ1β)ΞΈ, equals
[TABLE]
(iv) We start with the proof of the following fact:
Fact 2.Β Β If x=(0,xΛ)βS0dβ1β, then TΞ±βx=β₯EΞ±β(x)β₯EΞ±β(x)β,
where
EΞ±β:RdβRd is a linear operator given by
EΞ±βy=(y2βcosΞ±,yΛβsinΞ±) for y=(y1β,y2β,β―,ydβ)=(y1β,yΛβ)βRd.
To see this, let x=(0,x2β,β―,xdβ)βS0dβ1β.
If x2β=0, then TΞ±βx=x and Fact 2 holds trivially. If x2β>0, then setting h=2ΟβhΞ±β(x2β)=tanβ1x2βtanΞ±β, we have
[TABLE]
This proves Fact 2.
Next, we prove that for V=convSdβ1β{Ξ·1β,β―,Ξ·dβ1β},
[TABLE]
Indeed,
if xβV, then x=βj=1dβ1βtjβΞ·jββ\SS0dβ1β for some t1β,β―,tdβ1ββ₯0, and hence, by Fact 2,
[TABLE]
which implies that TΞ±β(x)βconvSdβ1β{TΞ±β(Ξ·1β),β¦,TΞ±β(Ξ·dβ1β)}.
Conversely, if yβconvSdβ1β{TΞ±β(Ξ·1β),β¦,TΞ±β(Ξ·dβ1β)}, then
y=βj=1dβ1βsjβTΞ±β(Ξ·jβ) for some s1β,β―,sdβ1ββ₯0, and by Fact 2,
[TABLE]
where sjβ²β=β₯EΞ±β(Ξ·jβ)β₯sjββ and
c1β=β₯βj=1dβ1βsjβ²βΞ·jββ₯.
Third, we show that for any Ξ·β\SS0dβ1β,
[TABLE]
Assume that Ξ·=(0,ΞΎ) with ΞΎ=(ΞΎ1β,β―,ΞΎdβ1β)β\SSdβ2 and ΞΎ1ββ₯0. Then
\operatorname{Arc}(e_{1},\eta)=\Bigl{\{}(\cos{\theta},\xi\sin{\theta}):\ \ {\theta}\in[0,\frac{\pi}{2}]\Bigr{\}}.
If x=(cosΟ,ΞΎsinΟ)βArc(e1β,Ξ·) with Οβ[0,2Οβ], then setting hΞ±β=Ο2βtanβ1ΞΎ1βtanΞ±β, we have
[TABLE]
where s1β=sinΞ±sin(hΞ±βΟ)ββ₯EΞ±β(Ξ·)β₯β₯0 and s2β=cos(hΞ±βΟ)βtanΞ±sin(hΞ±βΟ)βΞΎ1β.
Since
tan(hΞ±βΟ)β€tan(2ΟβhΞ±β)=ΞΎ1βtanΞ±β,
it follows that s2ββ₯0, and hence TΞ±βxβArc(e1β,TΞ±β(Ξ·)).
Conversely, if y=t1βe1β+t2βTΞ±β(Ξ·)βArc(e1β,TΞ±β(Ξ·)) for some t1β,t2ββ₯0, then
[TABLE]
Finally, we prove
[TABLE]
Indeed, it is easily seen that each xβS can be written in the form x=1βt2βΞ·+te1ββArc(e1β,Ξ·) for some tβ₯0 and Ξ·βV=convSdβ1β{Ξ·1β,β―,Ξ·dβ1β}. It follows by (3.10) that
TΞ±β(x)βArc(e1β,TΞ±β(Ξ·)). However, by (3.9),
[TABLE]
Thus,
[TABLE]
Conversely, if yβconvSdβ1β{TΞ±β(Ξ·1β),β―,TΞ±β(Ξ·dβ1β),e1β}, then
y=s0βe1β+βj=1dβ1βsjβTΞ±β(Ξ·jβ) for some s0β,s1β,β―,sdβ1ββ₯0. According to (3.9),
there exists Ξ·βV such that
βj=1dβ1βsjβTΞ±β(Ξ·jβ)=c2βTΞ±β(Ξ·),
with c2β=β₯βj=1dβ1βsjβTΞ±β(Ξ·jβ)β₯. It then follows by (3.10) that
[TABLE]
(v)Β Β According to Fact 2, we have
[TABLE]
By symmetry, it remains to show that
[TABLE]
Indeed, since sinΞ±β€β₯EΞ±β(Ξ·1β)β₯β€2β, we obtain from Fact 2 that
Without loss of generality, we may assume that Nβ₯Nd,wβ.
Given 0β€Ξ±<Ξ²β€2Ο, let S(Ξ±,Ξ²) denote the subset of Sdβ1 given in Definition 3.4.
The following assertion plays an important role in the proof of Proposition 3.3.
Assertion A.Β Β If Nw(S(0,2Οβ))βN, then there exists a convex partition {S1β,β―,Sn0ββ} of the set S(0,2Οβ) such that each Sjβ is a geodesic simplex spanned by the vector e1β and a set of dβ1 strongly Ξ΅dβ-separated points in \SS0dβ1β={xβSdβ1:Β Β x1β=0,Β Β x2ββ₯0}, and satisfying the condition Nw(Sjβ)βN.
For the moment, we take Assertion A for granted and proceed with the proof of the proposition. Note that if 0β€Ξ±<Ξ²β€2Ο and Ξ²βΞ±β₯6Οβ, then S(Ξ±,Ξ²) contains a spherical cap of radius β₯201β. It follows by continuity that Sdβ1 has a partition Sdβ1=βj=1β0ββS(Ξ±jβ1β,Ξ±jβ) with 1β€β0ββ€12 such that Ξ±0β=0, 6Οββ€Ξ±iββΞ±iβ1β<2Οβ and Nw(S(Ξ±iβ1β,Ξ±iβ))βN for i=1,β―,β0β.
Thus, replacing w with wβQ for some rotations QβSO(d), we reduce to proving the following assertion:
Assertion B:Β Β If Ξ±β[6Οβ,2Οβ] and Nw(S(0,Ξ±))βN, then there exists a convex partition {S1β,β―,Sn0ββ} of the set S(0,Ξ±) such that SjββSΞ΅dββ and Nw(Sjβ)βN for j=1,β―,n0β.
The proof of Assertion B relies on Assertion A and the nonlinear bijective mapping TΞ±β:S(0,2Οβ)βS(0,Ξ±) introduced in Definition 3.5.
Let w1β(x):=w(TΞ±β(x))Ο(x) for xβS(0,2Οβ), where Ο is the function given in (3.6).
According to (3.5), w1β(E)=w(TΞ±β(E)) for each EβS(0,2Οβ). Moreover, by By Lemma 3.6 (i), (ii) and (iii), we may apply Assertion A to the weight w1β on S(0,2Οβ) and obtain a partition {V1β,β―,Vn0ββ} of S(0,2Οβ) with the stated properties of Assertion A (with w1β in place of w). Now setting Sjβ=TΞ±β(Vjβ), we get a partition {S1β,β―,Sn0ββ} of S(0,Ξ±).
By Lemma 3.6 (iv) and (v), each Sjβ is a geodesic simplex in the class SΞ΅dββ, whereas by Lemma 3.6 (iii),
Nw(Sjβ)=Nw1β(Tjβ)βN for 1β€jβ€n0β. This proves Assertion B.
It remains to show Assertion A.
We start with the case of d=3. Note that
[TABLE]
By continuity, there exists a point ΞΎ=(0,sinΞΈ,cosΞΈ)β\SS02β for some ΞΈβ(6Οβ,2Οβ) such that S(0,2Οβ)=S1ββͺS2β with S1β:=conv\SS2β{e1β,βe3β,ΞΎ} and S2β:=conv\SS2β{e1β,e3β,ΞΎ}, and such that
Nw(S1β),Nw(S2β)βN. This shows Assertion A and hence Proposition 3.3 for d=3.
Next, we show Assertion A for dβ₯4.
We use induction on the dimension d. Assume that the conclusion of Proposition 3.3 holds on the spheres \SSββ1, β=3,β―,dβ1. We shall prove that Assertion A holds for dβ₯4, which in turn implies Proposition 3.3 for dβ₯4.
The proof relies on the following formula:
[TABLE]
where f is a nonnegative function on S(0,Ο/2).
For Ξ·β\SSdβ3,
define
[TABLE]
where Ο=w(S(0,Ο/2))=Nk0ββ for some positive integer k0β.
Given a set Eβ\SSdβ3, set
[TABLE]
It can be easily seen that if E is a geodesic simplex in \SSdβ3 spanned by a set of linearly independent points Ξ·1β,β―,Ξ·dβ2ββ\SSdβ3, then E is a geodesic simplex in \SSdβ1 spanned by the set
{e1β,e2β,Ξ·β1β,β―,Ξ·βdβ2β},
with Ξ·βjβ=(0,0,Ξ·jβ)β\SS0dβ1β for j=1,β―,dβ2, and moreover,
by (3.13),
w(E)=Οβ1w(E).
Now applying the induction hypothesis to the weight w on the sphere \SSdβ3 with k0β in place of N, we obtain a partition {E1β,β―,Em0ββ} of the sphere \SSdβ3, where each Ejβ is a geodesic simplex in \SSdβ3 spanned by a set of strongly Ξ΅dβ2β-separated points Ξ·j,1β,β―,Ξ·j,dβ2ββ\SSdβ3 and satisfying
k0βw(Ejβ)βN. It then follows that {E1β,β―,Em0ββ} is a partition of S(0,2Οβ) where each Ejβ is a geodesic simplex spanned by the vector e1β and the set of strongly Ξ΅dβ-separated points Ξ·βj,1β,β―,Ξ·βj,dβ2β,e2ββ\SS0dβ1β, and satisfies that
Nw(Ejβ)=k0βw(Ejβ)βN for each j.
This proves Assertion A for dβ₯4.
4. Preliminary lemmas
For the proof of Theorem 1.1, in addition to the convex partitions of the weighted sphere (i.e., TheoremΒ 1.4), we shall also need several preliminary lemmas, which we state or prove in this section.
Throughout this section, w denotes a normalized doubling weight on Sdβ1 with doubling constant Lwβ. All the general constants cwβ,Cwβ,Ξ΄wβ depend only on d and the doubling constant of w. Given 1β€pβ€β, we denote by β₯β β₯p,wβ the Lp-norm defined with respect to the measure w(x)dΟ(x) on Sdβ1.
A finite subset Ξ of Sdβ1 is called Ξ΅-separated for a given Ξ΅>0 if d(Ο,Οβ²)β₯Ξ΅ for every two distinct points Ο,Οβ²βΞ.
A Ξ΅-separated subset Ξ is called maximal if βΟβΞβB(Ο,Ξ΅)=Sdβ1.
The following weighted polynomial inequalities were established in [9] (see also [10, Theorem 5.3.6.] and [10, Theorem 5.3.4.]):
Lemma 4.1**.**
[9]** Let n be a positive integer and Ξ΄ a parameter in (0,1). Assume that 1β€p<β and Ξ is a nΞ΄β-separated subset
of Sdβ1 .
(i)
For every spherical polynomial fβΞ ndβ,
[TABLE]
where BΟβ=B(Ο,nβ1Ξ΄)
and osc(f)(Ο)=maxyβBΟβββ£f(y)β£ for ΟβΞ.
2. (ii)
If, in addition, Ξ is maximal nΞ΄β-separated with 0<Ξ΄<cwβ and cwβ being a small constant, then for each given parameter Ξ³>1, and every fβΞ ndβ,
[TABLE]
where BΟβ=B(Ο,nβ1Ξ΄) for ΟβΞ, and the constants of equivalence depend only on d, Ξ³ and the doubling constant of w.
The weighted
Christoffel function on Sdβ1 is defined by
[TABLE]
where the infimum is taken over all spherical polynomials of degree n on Sdβ1 that take the value 1 at the point xβSdβ1. The following pointwise estimate of Ξ»nβ(w,x) is proved in [11]. (See also [31] for the case of d=2).
where the constant of equivalence depends only on d and Lwβ.
The tangential gradient of fβC1(Rd) is defined as
[TABLE]
where F(y)=F_{x}(y)=f\Bigl{(}\frac{\|x\|y}{\|y\|}\Bigr{)} for yβRdβ{0}.
We shall need the following lemma from [5], whose detailed proof can be found in the book [10, p.145-147].
Lemma 4.3**.**
[5]** For Ξ΅>0, xβSdβ1 and
each fixed spherical polynomial PβΞ ndβ, the differential equation
[TABLE]
has a unique solution y=y(P,s)β‘y(P,x;s)βSdβ1 on [0,β) with the following properties:
(i)
y(P,x;s)βSdβ1* for all sβ₯0, xβSdβ1 and PβΞ ndβ;*
2. (ii)
for each fixed sβ₯0 and xβSdβ1,
Pβ¦y(P,x;s) is a continuous mapping from Ξ ndβ to Sdβ1;
3. (iii)
If x,xβ²βSdβ1 and xξ =xβ², then
[TABLE]
As a consequence of Lemma 4.3, we have the following useful corollary:
Corollary 4.4**.**
Let RβSdβ1 be a closed geodesically convex subset of Sdβ1 with maxx,yβRβd(x,y)<2Οβ. Assume that PβΞ ndβ and zmaxββR is such that P(zmaxβ)=maxzβRβP(z). Then for each xβR,
[TABLE]
where d(x,β(R))=infyββ(R)βd(x,y).
Corollary 4.4 was used without proof in [6]. For completeness, we include a proof here.
Proof.
Without loss of generality, we may assume that x is an interior point of R and minzβRββ£β0βP(z)β£=Ξ΅>0. By Lemma 4.3, there exists a continuously differentiable function y:[0,β)βSdβ1 satisfying the equation (4.3).
We claim that there exists s>0 such that y(s)β/R. Assuming otherwise, we then have that
[TABLE]
and hence, for any t>0,
[TABLE]
Letting tββ, and taking into account the fact that y(t)βSdβ1, we conclude that
the polynomial P is not bounded on Sdβ1, which contradicts the extreme value theorem. This proves the claim.
Now set
[TABLE]
Since y:[0,β)βSdβ1 is continuous and x is an interior point of R, it follows that 0<t0β<β, y(t0β)ββ(R)βR, and
[TABLE]
This implies that
[TABLE]
β
We will use the following lemma from algebraic topology.
For convenience, we introduce the following definition:
Definition 4.6**.**
For x,yβSdβ1 with ΞΈ:=d(x,y)β(0,2Οβ), let Ξ³[x,y]β:[0,1]βArc(x,y) denote the parametric representation of Arc(x,y)given by
[TABLE]
where ΞΎβSdβ1 is such that ΞΎsinΞΈ is the orthogonal projection of y on the space {yβRd:Β Β yβ x=0}; that is,
ΞΎ=ΞΎx,yβ=sinΞΈyβxcosΞΈβ .
In the case when x=y, we also set Ξ³[x,y]β(t)=x for tβ[0,1].
A convex set G in Rd is said to be strictly convex if for any two distinct points p,qβG and any tβ(0,1), tp+(1βt)q is an interior point of G.
Lemma 4.7**.**
[6]** Let R be a closed geodesically convex subset of Sdβ1 with maxp,qβRβd(p,q)<Ο/2. Assume that x0β is a given interior point of R and let T0β:={yβRd:Β Β x0ββ y=0}. Then the following statements hold:
(i)
For each yβT0ββ{0}, there exists a unique point xyββR such that xyββ y=maxzβRβzβ y. Furthermore, yβΌxyβ is a continuous mapping on the set T0ββ{0} with the property that the function tβ¦yβ (Ξ³[xyβ,w]β(t)) is decreasing on [0,1]
for each given yβT0ββ{0} and wβRβ{xyβ}.
2. (ii)
Let z0β be an arbitrary interior point of R. Given Ξ΄,Ξ΅β(0,1/2), define
[TABLE]
Then yβ¦A(y) is a continuous mapping from T0β to R.
Lemma 4.7 was essentially proved in [6]. However,
since the proof there is rather sketchy, we include a more detailed proof of the lemma here.
Proof.
(i)
Let P0β(z)=zβ(zβ x0β)x0β denote the orthogonal projection of zβSdβ1 onto the space T0β. Firstly, we prove that D0β=P0β(R) is a strictly convex set in the space T0β.
To see this, let S0+β={yβSdβ1:Β Β yβ x0β>0} and U0β:={yβT0β:Β Β β₯yβ₯<1}. Clearly, RβS0+β, D0ββU0β, and P0β is a continuous mapping from S0+β onto the set U0β with continuous inverse given by
Pβ1(u)=u+1ββ₯uβ₯2βx0β for uβU0β. Thus, to show D0β is strictly convex, it suffices to prove that for any two distinct points u,vβD0β, and every w=tu+(1βt)v with tβ(0,1), P0β1β(w) is an interior point of R.
Note first that
[TABLE]
with Ξ±0β=1ββ₯wβ₯2ββt1ββ₯uβ₯2ββ(1βt)1ββ₯vβ₯2β.
We claim that Ξ±0β>0. Indeed, since g(x)=β₯xβ₯2 is a strictly convex function on Rd, we have β₯wβ₯2<tβ₯uβ₯2+(1βt)β₯vβ₯2. Since Ο(s)=sβ is a concave function on [0,β), this implies that
[TABLE]
which in turn implies that Ξ±0β>0.
Now setting
[TABLE]
we have pβArc(P0β1β(u),P0β1β(v))βR. (4.6) then implies that
P0β1β(w)βArc(p,x0β)βR.
To show that P0β1β(w) is in fact an interior point of R, let Ξ΄β(0,1) be such that {β₯x0β+Ξ·β₯x0β+Ξ·β:Β Β β₯Ξ·β₯<Ξ΄}βR. Then for z=P0β1β(w)+Ξ±0βΞ·βSdβ1 with Ξ·βRd satisfying β₯Ξ·β₯<Ξ΄, we use (4.6) to obtain
[TABLE]
This shows that P0β1β(w) is an interior point of R, and hence proves that D0β is a strictly convex subset of T0β.
Secondly, we show that for each yβT0ββ{0}, there exists a unique xyββR such that
xyββ y=maxzβRβzβ y. Indeed, this follows directly from the facts that D0β is strictly convex and maxzβRβzβ y=maxzβRβP0β(z)β y.
On the other hand, since D0β is strictly convex,
Ο(2p+uβ,Hp,yβ)>0 for any uβD0ββ{p}. Thus, given any Ξ΅>0,
[TABLE]
In particular, if β₯xyββxzββ₯β₯Ξ΅/CRβ, then β₯pβqβ₯β₯Ξ΅ and hence by (4.7), 0<Ξ΄β₯yβ₯β€β₯yβzβ₯. This shows the continuity of the mapping yβ¦xyβ.
Finally, we show that given each yβT0ββ{0} and wβRβ{xyβ}, the function tβ¦yβ (Ξ³[xyβ,w]β(t)) is decreasing on [0,1]. Let G denote the great circle passing through xyβ and w, and Ξ· the orthogonal projection of y onto the plane spanned by the vectors xyβ and w. Let ΞΎ=β₯Ξ·β₯Ξ·ββG. Then
[TABLE]
Since wβ ΞΎβ€xyββ ΞΎ, it suffices to show that the arc Arc(xyβ,w) lies between the points ΞΎ and βΞΎ on the great circle G.
Indeed, since maxu,vβRβd(u,v)<2Οβ, we have xyββ ΞΎ=β₯Ξ·β₯β1xyββ y>0. Hence, ΞΎ cannot be in the interior of the geodesic arc Arc(w,xyβ) since otherwise ΞΎβR and β₯Ξ·β₯=ΞΎβ Ξ·=ΞΎβ y>xyββ y. Similarly, one can also show that that βΞΎ can not lie in the interior of Arc(w,xyβ). Indeed, assuming otherwise, we have that βΞΎβR, which would imply that xyββ y=β₯Ξ·β₯ΞΎβ xyβ<0, yielding a contradiction.
(ii) Let Ξ΄1ββ(0,21β) be such that B(z0β,Ξ΄1β)βR. Since xyβ is on the boundary of R, it follows by (i) that ΞΈ(y)=d(xyβ,z0β)β[Ξ΄1β,2Οβ) for each yβT0ββ{0}, and is continuous in yβT0ββ{0}. Furthermore, according to (4.4),
for yβT0ββ{0},
[TABLE]
where
[TABLE]
Since 0<Ξ΄1ββ€ΞΈ(y)<2Οβ, yβ¦ΞΎyβ is a continuous mapping from T0ββ{0} to Sdβ1.
Since the function hΞ΅β(y):=min{1,Ξ΅β₯yβ₯β} is continuous on T0β, it follows by (4.8) that
A(y)={\gamma}_{[z_{0},x_{y}]}\Bigl{(}(1-{\delta})h_{\varepsilon}(y)\Bigr{)}
is continuous on T0ββ{0}.
On the other hand, setting tyβ:=(1βΞ΄)hΞ΅β(y)ΞΈ(y) for yβT0ββ{0}, we have that
limyβ0yβT0βββtyβ=0,
and hence
[TABLE]
This shows that A(y) is continuous at y=0 as well.
β
This section is devote to the proofs of Theorem 1.1 and Corollary 1.2.
Let Ξ n,0,wdβ denote the set of all spherical polynomials P of degree at most n on Sdβ1 with β«Sdβ1βP(x)w(x)dΟ(x)=0. Then Ξ n,0,wdβ is a finite dimensional real Hilbert space equipped with the inner product of the space L2(Sdβ1;w(x)dΟ(x)).
Let Gn,wβ(β ,β ) denote the reproducing kernel of the Hilbert space Ξ n,0,wdβ.
Clearly, (1.5) is equivalent to the following
[TABLE]
Finally,
we recall that β₯fβ₯1,wβ=β«Sdβ1ββ£f(x)β£w(x)dΟ(x).
For each integer Nβ₯KwβMn,wβ, there exists a set {xΞ±β}Ξ±βΞβ of N continuous functions Pβ¦xΞ±β(P) from the space Ξ n,0,wdβ to Sdβ1 such that xΞ±β(P)ξ =xΞ±β²β(P) for PβΞ n,0,wdβ, Ξ±,Ξ±β²βΞ and Ξ±ξ =Ξ±β², and such that
[TABLE]
where Ξ is an index set with cardinality N.
If, in addition, wβLβ(Sdβ1), then the set of points {xΞ±β(P)}Ξ±βΞβ is cwβNβdβ11β-separated for every PβΞ n,0,wdβ; that is,
[TABLE]
for some positive constant cwβ depending only on β₯wβ₯ββ and the doubling constant of w.
Throughout the proof, Kwβ denotes a sufficiently large constant depending only on the doubling constant of w. Set Ξ΄=2swβ1βKwβswβ1βββ(0,1).
By (1.3), for any xβSdβ1,
[TABLE]
Let N,nβN be such that Nβswβ1β=nΞ΄β, where Ξ΄β(0,1) is a small constant depending only on the doubling weight of w. According to Theorem 1.4, there exists a convex partition
R={R1β,β―,RMβ} of Sdβ1 with the properties that for each 1β€jβ€M, there exist a positive integer kjβ and a point xjββRjβ such that w(Rjβ)=Nkjββ and B(xjβ,ncdβΞ΄β)βRjββB(xjβ,ncdβ²βΞ΄β).
For each 1β€jβ€M, set
r_{j}=\frac{{\delta}^{2}}{n}\bigl{(}Nw(R_{j}))\bigr{)}^{-\frac{1}{d-1}}.
Since k_{j}r_{j}^{d-1}={\delta}^{d-1}\Bigl{(}\frac{{\delta}}{n}\Bigr{)}^{d-1},
there exists a set of kjβ points
xj,1β,β―,xj,kjββ in the set Rjβ which are 2rjβ-separated and satisfy xj,1β=xjβ, and B(xj,iβ,rjβ)βRjβ for all 1β€iβ€kjβ.
If, in addition, wβLβ, then
[TABLE]
which implies
[TABLE]
Let PβΞ n,w,0dβ. It is easily seen that xβ β0βP(x)=0 for all xβSdβ1. Thus,
according to LemmaΒ 4.7, if β0βP(xjβ)ξ =0, there exists a unique point zj,PββRjβ such that z_{j,P}\cdot\Bigl{(}\nabla_{0}P(x_{j})\Bigr{)}=\max_{z\in R_{j}}z\cdot\Bigl{(}\nabla_{0}P(x_{j})\Bigr{)}.
Now for each PβΞ n,0,wdβ, we define
[TABLE]
We claim that for each 1β€jβ€M and 1β€iβ€kjβ, Pβ¦xj,iβ(P) is a continuous function from Ξ n,w,0dβ to Sdβ1. Indeed, by LemmaΒ 4.7, we may write xj,iβ(P)=A(β0βP(xjβ)), where A is defined in (4.5) with xjβ,xj,iβ,β0βP(xjβ) in place of x0β,z0β and y respectively. According to LemmaΒ 4.7 (ii), xj,iβ(P) is a continuous function of β0βP(xjβ). On the other hand, however, since Ξ n,w,0dβ is a finite dimensional vector space, the mapping Pβ¦β0β(P)(xjβ) is continuous on Ξ n,0,wdβ. This proves the claim.
Now we set Ξ:={(j,i):Β Β 1β€jβ€M,Β Β 1β€iβ€kjβ}, and turn to the proof of (5.2).
Assume that PβΞ n,0,wdβ and β₯β0βPβ₯1,wβ=1. Let zj,Pβ, xj,iβ be defined as above.
For convenience, we also set
[TABLE]
Let Ξ΄β(0,1) be a parameter to be specified later. Define
[TABLE]
Let zj,maxββRjβ be such that P(zj,maxβ)=maxzβRjββP(z).
We then split the sum \frac{1}{N}\sum_{j=1}^{M}\sum_{i=1}^{k_{j}}P\bigl{(}\mathbf{x}_{j,i}(P)\bigr{)} on the left hand side of (5.2) into the following four parts:
[TABLE]
Firstly, we estimate the first sum Ξ£1β from below. Use LemmaΒ 4.4, we obtain
[TABLE]
where we used the fact that B(xjβ,ncdβΞ΄β)βRjββB(xjβ,ncdβ²βΞ΄β) and the doubling property of w in the third step, and LemmaΒ 4.1(ii) in the last step.
Secondly, we prove the following upper estimate of the second sum Ξ£2β:
[TABLE]
For simplicity, we write Ξ³j,iβ(t)=Ξ³[zj,i,Pβ,zj,maxβ]β(t).
If β0βP(xjβ)ξ =0, then zj,i,Pβ=zj,Pβ, and hence, by Lemma 4.7 (i), the function β0βP(xjβ)β Ξ³j,iβ(t) is decreasing on [0,1], namely,
[TABLE]
On the other hand, note that if β0βP(xjβ)=0, then zj,i,Pβ=xj,iβ and then the inequality (5.10) holds trivially. Thus,
[TABLE]
It follows that
[TABLE]
where the second step uses LemmaΒ 4.1 (i). This proves the estimate (5.9).
Thirdly, we show the following upper estimate of Ξ£3β:
[TABLE]
For simplicity, we set Ξ±j,iβ(t)=Ξ³[xj,iβ,zj,i,Pβ]β(t).
Recall that yj,iβ=Ξ±j,iβ(1βΞ΄).
We have
Fourthly, we estimate above the last sum Ξ£4β. Fix temporarily 1β€jβ€M and a small parameter Ξ΅β(0,1). We consider the following three cases. If β₯β0βP(xjβ)β₯=0, then xj,iβ=xj,iβ(P)=zj,i,Pβ=yj,iβ, and hence,
P(xj,iβ(P))βP(yj,iβ)=0.
If β₯β0βP(xjβ)β₯β₯Ξ΅>0, then
[TABLE]
and hence in this case we also have P(xj,iβ(P))βP(yj,iβ)=0.
Finally, if 0<β₯β0βP(xjβ)β₯<Ξ΅, then
[TABLE]
Putting the above together, we obtain
[TABLE]
Finally, combining the estimates (5.8), (5.9), (5.11), (5.12) with (5.7), we obtain
[TABLE]
To conclude the proof of (5.2), we just need to choose the parameters Ξ΅,Ξ΄ small enough so that 0<Ξ΅,Ξ΄<4Cwβcwββ.
It remains to show the separation property (5.3) under the additional condition wβLβ(Sdβ1). To this end,
we need the following simple lemma.
Lemma 5.2**.**
Let z,ΞΎ1β,ΞΎ2ββSdβ1 be such that ΞΎ1ββ z=ΞΎ2ββ z=0.
Given ΞΈ1β,ΞΈ2ββ(0,4Οβ], define
[TABLE]
where Ξ·iβ=zcosΞΈiβ+ΞΎiβsinΞΈiβ.
Then for any tβ(0,1),
[TABLE]
For the moment, we take Lemma 5.2 for granted and proceed with the proof of (5.3). Without loss of generality, we may assume that β₯wβ₯ββ=1. Set Ξ={(j,i):Β Β 1β€jβ€M,Β Β 1β€iβ€kjβ}.
It is enough to prove that for (j,i)ξ =(jβ²,iβ²)βΞ and every PβΞ n,0,wdβ with β₯β0βPβ₯1,2ββ€1,
[TABLE]
We first prove (5.13) for the case of j=jβ² and 1β€iξ =iβ²β€kjβ. In this case, if β0βP(xjβ)=0, then xj,iβ(P)=xj,iβ, xj,iβ²β(P)=xj,iβ²β, and hence by (5.5), d(xj,iβ(P),xj,iβ²β(P))β₯rjββ₯CNβdβ11β. If β0βP(xjβ)ξ =0, then
Next, we prove (5.13) for the case of 1β€jξ =jβ²β€M. Assume that 1β€iβ€kjβ and 1β€iβ²β€kjβ²β. To prove (5.13), it suffices to show that d(xj,iβ(P),βRjβ)β₯cwβrjββ₯cNβdβ11β.
Without loss of generality, we may assume that β₯β0βP(xjβ)β₯>0 since otherwise xj,iβ(P)=xj,iβ and the claim is obvious.
We first recall that B(xj,iβ,rjβ)βRjβ, and
[TABLE]
with t_{j}=(1-{\delta})\min\Bigl{\{}\frac{\|\nabla_{0}P(x_{j})\|}{\varepsilon},1\Bigr{\}}.
Hence, setting ΞΈj,iβ=d(xj,iβ,zj,Pβ), we have
[TABLE]
Let h:RjββTxj,iββ, zβ¦zβ(zβ xj,iβ)xj,iβ denote the orthogonal projection onto the tangential space Txj,iββ:={yβRd:Β Β yβ xj,iβ=0}. According to the proof of Lemma 4.7, the set S=h(Rjβ) is strictly convex in the space Txj,iββ, h(xj,iβ)=0, and β₯h(z)β₯=sin(d(xj,iβ,z)) for zβRjβ. Furthermore,
[TABLE]
Write
[TABLE]
where
[TABLE]
Then,
[TABLE]
This implies that
[TABLE]
where
[TABLE]
Here we used the fact that the function tsintβ is decreasing on [0,2Οβ].
Since the function d(u,βS) is concave on S, it follows that
follows directly from Theorem 1.1. It remains to show the matching lower estimate.
Assume that Ξ={Οjβ}j=1Nβ is a set of N distinct nodes on Sdβ1 such that
[TABLE]
According to [9, Lemma 4.6], given a positive integer ββ₯swβ+d+1, there exists a nonnegative algebraic polynomial Pnβ of degree at most n/4 on [β1,1] such that
where β₯β β₯p,wβ denotes the Lebesgue Lp-norm defined with respect to the measure w(x)dΟdβ(x) on Sdβ1.
Since the norm β₯β β₯βpβ is a decreasing function in p>0, it follows that
Thus, using (5.17) and (5.16) , we deduce that for any xβSdβ1,
[TABLE]
It follows that
[TABLE]
Acknowledgement
We would like to express sincere gratitude to Professor Ron Peled from the Tel Aviv University for kindly pointing out to us several very helpful references on Chebyshev-type cubature formulas.
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