Long Hitting time for translation flows and L-shaped billiards
Dong Han Kim, Luca Marchese, Stefano Marmi

TL;DR
This paper investigates the asymptotic behavior of hitting times in translation flows and L-shaped billiards, establishing bounds and relations with a generalized diophantine type across different surface topologies.
Contribution
It introduces a generalized diophantine type for higher genus surfaces and relates it to hitting time, providing bounds and exact cases for specific origamis and billiard tables.
Findings
Limsup of hitting time is bounded by the square of diophantine type for genus two surfaces.
For certain origamis, the diophantine type provides a lower bound for hitting time.
Equality between hitting time limsup and diophantine type holds for Eierlegende Wollmilchsau origami.
Abstract
We consider the flow in direction on a translation surface and we study the asymptotic behavior for of the time needed by orbits to hit the -neighborhood of a prescribed point, or more precisely the exponent of the corresponding power law, which is known as hitting time. For flat tori the limsup of hitting time is equal to the diophantine type of the direction . In higher genus, we consider a generalized geometric notion of diophantine type of a direction and we seek for relations with hitting time. For genus two surfaces with just one conical singularity we prove that the limsup of hitting time is always less or equal to the square of the diophantine type. For any square-tiled surface with the same topology the diophantine type itself is a lower bound, and any value between the two bounds can be realized, moreover this holds also for a larger class…
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Long Hitting time for translation flows and L-shaped billiards
Dong Han Kim
Department of Mathematics Education, Dongguk University – Seoul, 30 Pildong-ro 1-gil, Jung-gu, Seoul, 04620 Korea
,
Luca Marchese
Université Paris 13, Sorbonne Paris Cité, LAGA, UMR 7539, 99 Avenue Jean-Baptiste Clément, 93430 Villetaneuse, France.
and
Stefano Marmi
Scuola Normale Superiore and C.N.R.S. UMI 3483 Laboratorio Fibonacci, Piazza dei Cavalieri 7, 56126 Pisa, Italy
Abstract.
We consider the flow in direction on a translation surface and we study the asymptotic behavior for of the time needed by orbits to hit the -neighborhood of a prescribed point, or more precisely the exponent of the corresponding power law, which is known as hitting time. For flat tori the limsup of hitting time is equal to the diophantine type of the direction . In higher genus, we consider a generalized geometric notion of diophantine type of a direction and we seek for relations with hitting time. For genus two surfaces with just one conical singularity we prove that the limsup of hitting time is always less or equal to the square of the diophantine type. For any square-tiled surface with the same topology the diophantine type itself is a lower bound, and any value between the two bounds can be realized, moreover this holds also for a larger class of origamis satisfying a specific topological assumption. Finally, for the so-called Eierlegende Wollmilchsau origami, the equality between limsup of hitting time and diophantine type subsists. Our results apply to L-shaped billiards.
1. Introduction
Consider a minimal dynamical system in continuous time on a metric space , whose balls are the sets with and . For any pair of points in and any small enough, the hitting time of to the ball of radius around is
[TABLE]
We are interested to study the scaling law of when , that is to say we consider the two quantities
[TABLE]
One can consider also the return time of a point to its -ball and and define analogously
[TABLE]
The same quantities are also obviously defined for dynamical systems in integer time . In particular, in [KiSe] it is proved that for the irrational rotation by parameter , that is for the map , , we have
[TABLE]
where denotes the diophantine type of the irrational number , that is the supremum of those such that there exist infinitely many rational numbers such that
[TABLE]
Moreover it is easy to check (See [ChSe]) that
[TABLE]
In particular, since for almost any , then for any such and for generic points one has
[TABLE]
In [KiMa], the same result was shown replacing the generic rotation by the generic interval exchange map over any number of intervals. On the other hand, Equation (1.1) also implies the existence of many parameters with for generic , indeed according to Jarník Theorem (see [Ja]), for any
[TABLE]
where denotes the Hausdorff dimension. The result in Equation (1.1) stands in the same form replacing by the linear flow in direction with slope on the standard torus , that is the flow defined for any by
[TABLE]
Moreover, via a well known unfolding procedure, one can derive the same conclusion for the billiard flow in the square . The aim of this paper is to study the relation between hitting time and the diophantine exponent in translation flows in higher genus. Definitions and statements of main results are given in § 2. Here, as a motivational result, we state a consequence of our main Theorems for the billiard flow in L-shaped polygons.
Fix four real numbers and and let be the polygon whose vertices, listed in counterclockwise order, are , , , , , . An example of such polygon appears in Figure 1. Let be the billiard flow. Reflections at sides of are affine maps with linear part given by the linear reflections and defined respectively by
[TABLE]
Let be the group generated by and and consider its action on . Any direction has an orbit of four elements, thus the phase space decomposes into invariant subspaces where the directional billiard flow is defined, modulo the action of on the second factor. A generalized diagonal is a finite segment of billiard trajectory connecting two vertices of and without any other vertex in its interior. A direction is said rational if admits a generalized diagonal, the set of rational directions being of course countable. We give a preliminary version of the notion of diophantine type of a non rational direction in terms of the deviation of finite trajectories of from generalized diagonals.
Let be a generalized diagonal, parametrized as a continuous piecewise smooth path with unitary speed, that is when it is defined. Consider the sequence of instants such that for any the restricted path is a straight segment with , and in the interior of for . There exist an unitary vector in the first quadrant, depending only on , such that for any there exists an unique with
[TABLE]
The planar development of is the vector . Consider a non rational direction on the L-shaped polygon , and modulo replacing by an element in its orbit , assume that , where corresponds to the vertical direction. The diophantine type of on the L-shaped polygon is the supremum of those such that there exist infinitely many generalized diagonal with
[TABLE]
where and .
The notion of generalized diagonal can be given also for the billiard in the square , which has the same reflection group as any L-shaped polygon , thus the diophantine type of a direction can be defined in the same way. It is an exercise to check that such alternative notion of diophantine type in fact coincides with the quantity defined by Equation (1.2), modulo the change of variable . Moreover the two notions also coincide for a class of L-shaped billiards . More precisely, according to Equation (2.4) and to the discussion in § 2.4, we have whenever are rationally dependent. The next Theorem is a direct consequence (derived in § 2.4) of our main results, namely Theorem 2.1 and Theorem 2.2, stated in § 2.2 below. It is practical to introduce the function defined for any by
[TABLE]
Theorem 1.1**.**
Let be the L-shaped billiard with parameter and consider any non rational direction on .
- (1)
For any pair of points in we have
[TABLE]
Assume now that are rationally dependent, so that for any .
- (2)
For almost any in we have
[TABLE] 2. (3)
Finally, for any and any with there exists a set of directions with
[TABLE]
such that for any we have and moreover for almost any in we have
[TABLE]
When the Lebesgue measure is ergodic for , we also show that for Lebesgue almost any in . For recurrence times our results simply extend those obtained for rotations. More precisely, for any L-shaped billiard and for almost any we have . Moreover, when are rationally dependent we have for almost any . For more details see § 2.4.
Acknowledgements
The authors are grateful to J. Chaika, V. Delecroix, P. Hubert and S. Lelièvre. This research has been supported by the following institutions: CNRS, FSMP, National Research Foundation of Korea(NRF-2015R1A2A2A01007090), Scuola Normale Superiore, UnicreditBank.
2. Definitions and statement of main results
2.1. Translation surfaces
Let be a polygon in the plane. The polygon is not necessarily connected, that is we allow to be the disjoint union of finitely many connected polygons . We assume that is union of segments which come in pairs and are denoted , and that there exist vectors in such that for any the boundary segments and have the same direction and length of , and the opposite orientation induced by the interior of (that is any touches the interior of from the opposite side as ). A translation surface is the quotient space obtained identifying for any the sides et by a translation. We assume that the identification gives a connected quotient space . If is a parallelogram then is a flat torus. In general a translation surface is a compact surface of genus , with a metric which is flat outside of a finite set of points of , where the metric has a conical singularity with angle and . Any corresponds to a subset of the vertices of , all identified to the same point in by the equivalence relation on . We have . For a general overview on the subject we recommend the surveys [FoMat] and [Zo].
2.1.1. Dynamics in moduli spaces
A stratum is the set of all translation surfaces with the same order of conical singularities . Any stratum is an affine orbifold, the affine coordinates around some being the vectors defined above, possibly modulo some linear equations with coefficients in . Consider any and any translation surface , represented via the polygon . We define as the quotient space , where is the affine image of under the action of on and where the identifications in have the same combinatorics of those between the sides of . This gives an action of on any stratum . We will consider the subgroup action of rotations and diagonal elements, thus for and we set
[TABLE]
According to the celebrated results of Eskin, Mirzakani [EsMi] and Eskin, Mirzakaniand Mohammadi [EsMiMo], any subset on which is closed and invariant under , is a sub-orbifold defined by linear equations in the coordinates . Particularly simple closed invariant sets are closed orbits. It is known that the -orbit of a surface is closed in if and only if the stabiliser of under the action of , called the Veech group of , is a lattice in (see § 5 of [SmWe] for a proof). Such a surface is called Veech surface and its orbit is an isometric image of embedded in , and is locally defined by a system of linear equations in the coordinates , with real rank four. In general the Veech group of any translation surface is a discrete and non co-compact subgroup of , and it is trivial for generic .
2.1.2. Saddle connections, cylinders and planar developments
Let denote the Euclidian norm on , and recall that the flat metric of a translation surface is locally isometric to the Euclidian metric of . A saddle connection of a translation surface is a segment of a geodesic for the flat metric of connecting two conical singularities and and not containing other conical singularities in its interior. We consider also closed geodesics of . For any such there exists a family of closed geodesics which are parallel to with the same length and the same orientation. A cylinder for is a maximal connected open set foliated by such a family of parallel closed geodesics. By maximality, the boundary of a cylinder around a closed geodesic is union of saddle connections parallel to . The transversal width of is the length of a segment orthogonal to which connects the two components of the boundary , so that in particular .
Let be a finite segment of a geodesic for the flat metric of , for example either a saddle connection or a closed geodesic, and abusing the notation denote with the same symbol also a smooth parametrization of it , . There exists a vector with such that for any , and the segment has a planar development in the plane, denoted by and defined by
[TABLE]
Any such is a geodesic segment also on the surface for any , and we denote by its holonomy with respect to the surface . We have
[TABLE]
The set of relative periods of is the set of vectors , where is a saddle connection for .
2.1.3. Phase space dynamics
Fix a translation surface and a direction . One can define a constant vector field on , whose value at any point is equal to to the unitary vector
[TABLE]
then consider the integral flow of such field, that is denoted by . Orbits of are parallel lines in direction which wind on . They are defined for any , outside the set of leaves starting or ending at singular points , which we call -singular leaves, or simply singular leaves, when there is no ambiguity on the surface and the direction . A direction on a translation surface is completely periodic if every -singular leaf extends to a saddle connection. In this case, the set of saddle connections in direction separate the surface into a finite number of cylinders, any of which is foliated by periodic orbits of the linear flow . A direction is a Keane direction for the translation surface if there is no saddle connection in direction . Obviously, all but countably many directions are Keane. Moreover, if is a Keane direction on , then the flow is minimal, that is any infinite orbit is dense, both in the past and in the future (for a proof see Corollary 5.4 in [Yo]). According to Veech (see [Ve]), for Veech surfaces there is a sharp dynamical dichotomy between Keane directions and directions of saddle connections. More precisely, on a Veech surface the flow is uniquely ergodic whenever is Keane, otherwise is a completely periodic direction, moreover there are two constants and depending only on such that for any saddle connection and closed geodesic in direction we have and , where is the cylinder around .
2.1.4. Origamis
Origamis, which are also know as square-tiled surfaces, form a special class of translation surfaces. An origami is a translation surface tiled by copies of the square . It is a direct consequence of definitions that is an origami if and only if and the last condition is also equivalent to the existence of a ramified covering of the standard torus such that the following conditions are satisfied:
- (1)
The covering is ramified only over the origin , where denotes the coset of [math] in . 2. (2)
Local inverses of , that is maps defined over simply connected open sets such that , are all translations.
A third equivalence says that is an origami if and only if its Veech group shares a common subgroup of finite index with (see [GuJu]). In particular, origamis are all Veech surfaces.
2.2. Statement of main results
It can be seen that the set of relative periods of a translation surface is a discrete subset, whose projectivization is dense in , thus it is meaningful to consider diophantine approximations of a given direction by directions of vectors in . Given a saddle connection and a direction on the surface , the components of along the direction are the two real numbers and such that
[TABLE]
The diophantine type of a Keane direction on the surface is the supremum of those such that there exists infinitely many saddle connections for the surface with
[TABLE]
As in the classical case, which corresponds to Equation (1.2), we have for any and , indeed for Equation (2.2) has always infinitely many solutions. This corresponds to a version of Dirichlet’s theorem for translation surfaces, which was known to many authors and a proof of which is given in Proposition 4.1 in [MarTreWeil]. Moreover, the analogy with classical diophantine conditions extends also to Jarník Theorem, indeed in Theorem 6.1 [MarTreWeil] it is proved that
[TABLE]
Let be a Keane direction on the translation surface , so that the flow is minimal and the functions , , and are defined outside of singular leaves. According to Lemma 4.2 of this paper, these functions are also invariant under . A first relation with can be derived by an easy geometric argument (see Lemma 7.2 in [MarTreWeil]) which gives that for any not on any -singular leaf we have
[TABLE]
On the other hand, according to Proposition 4.5 of this paper, we prove that for Lebesgue almost any point we have
[TABLE]
Under the extra assumption that the Lebesgue measure is ergodic for , Equation (2.6) below establishes an uniform upper bound for for the generic . Moreover according to Proposition 4.6 of this paper, for Lebesgue almost any and we have also
[TABLE]
In general, if is a non-ergodic invariant probability measure along a Keane direction on , the function can exhibit a different behavior for the generic pair , as it can be deduced by results in [BoCh]. Our first main result establishes an upper bound for the hitting time on translation surfaces in .
Theorem 2.1**.**
Let be a surface in and let be a Keane direction on . Then for any pair of points not on any singular leaf we have
[TABLE]
The argument leading to Theorem 2.1 can be considered as the first step in a more general procedure by induction on genus (see § 5.2, and in particular Corollary 5.6). In the general stratum the function seems to be uniformly bounded by an expression which is a polynomial function of , whose degree is uniformly bounded for any genus. The situation in is more interesting because in this stratum there are many surfaces and directions for which the bound is sharp, according to Theorem 2.2 below.
Let be an origami and be the corresponding ramified cover over the standard torus. Any saddle connection on an origami gives rise to a closed geodesic on , passing though the origin , whose direction satisfies . Moreover, if denotes the degree of the map , then we have
[TABLE]
It follows that
[TABLE]
and observing that for any saddle connection , where is the number of squares of , we get that for any we have
[TABLE]
Since origamis are Veech surfaces, then the lower bound in Equation (2.8) below gives a simple counterpart to the upper bound in Theorem 2.1. In Theorem 2.2 below we show that under specific topological assumption on , both the upper and lower bound are sharp. An origami is said to be reduced if , that is the subgroup of generated by the set of relative periods is the entire lattice . Reduced origamis are relevant because they form a closed set for the subgroup action of (see § 6.1), moreover the -orbit of any origami contains a reduced origami (see § 7.6). In § 6.5 we introduce a non-trivial topological property of a reduced origami , which consists in the existence of a vertical splitting pair , where and are respectively a closed geodesic and a saddle connection in the vertical direction (satisfying a specific arithmetic condition), which splits the surface into a cylinder , where -orbits can be trapped for a long time, and a remaining non-empty open set. We say that an origami admits a splitting direction if there exists some such that is a reduced origami with a vertical splitting pair. In § 6.4 we also consider a reduced origami whose vertical direction is a one cylinder direction and we say that an origami admits an one cylinder direction if there exists some such that is a reduced origami whose vertical is a one cylinder direction. For any recall the function defined by Equation (1.4).
Theorem 2.2**.**
Let be any origami, so that in particular for any direction . Assume that admits both a splitting direction and a one cylinder direction . Then for any and any with there exists a set of directions with
[TABLE]
such that for any we have , and moreover for almost any in we have
[TABLE]
Recall that, by Jarník Theorem, we have \dim_{H}\big{(}{\mathbb{E}}(X,\eta,s)\big{)}\leq 2/(1+\eta) for any set as in Point (1) of Theorem 2.2 with respect to parameters and . Theorem 2.2 is completed by the following Proposition.
Proposition 2.3**.**
Let be any origami.
- (1)
If admits a one cylinder direction then the result in Theorem 2.2 holds for the parameter . 2. (2)
If admits a splitting direction , then for any there exists a set of directions with \dim_{H}\big{(}{\mathbb{E}}(X,\eta,2)\big{)}\geq f_{\eta}(2)=(1+\eta)^{-1} such that for any we have , and moreover for almost any in we have
[TABLE]
By Corollary A.2 in [Mc], any origami admits a one cylinder direction . Moreover, according to Lemma 6.5 of this paper, which is proved in Appendix A, any origami also admits a splitting direction . Therefore Theorem 2.2 can be applied to any origami , and combining it with the bounds given by Theorem 2.1 and Equation (2.8) below, the next Corollary follows.
Corollary 2.4**.**
Let be any origami in . Then for any and any with there exists a set as in Theorem 2.2. In particular, the spectrum of almost sure values of over the set of those with equals the interval .
Theorem 2.2 above implies that in higher genus there is no functional relation between the diophantine type and the almost sure value of the function (where we recall that such almost sure value does not even exist if in a non ergodic direction on ). In genus , the stratum contains an origami which is known by the German name Eierlegende Wollmilchsau, whose definition is given in § 8, and which exhibits several singular behaviors (see § 7 and § 8 in [FoMat]). In our case, such origami is special because it is a higher genus surface where the functional relation in Equation (1.1) subsists.
Proposition 2.5**.**
Let be the Eierlegende Wollmilchsau origami. Then for any and almost any in we have
[TABLE]
2.3. Other notions of diophantine type
One can consider also absolute periods of closed geodesics inside cylinders . For a Keane direction define as the supremum of those such that there exist infinitely many cylinders with area , where is a positive constant depending only on , such that
[TABLE]
According to § 2.1.3, if is a Veech surface we have for any Keane direction . When is a general translation surface, for any Keane direction on we always have
[TABLE]
indeed the boundary of any cylinder around a closed geodesic in is made of saddle connections parallel to . Moreover when , Equation (2.5) has always infinitely many solutions for any Keane direction on (replacing in the numerator by a bigger constant, see Proposition 4.1 in [MarTreWeil], which is derived from results in [Vo]). Finally, according to Theorem 6.1 [MarTreWeil] we also have
[TABLE]
and for these reasons can also be considered as a natural notion of diophantine type. According to Lemma 7.3 in [MarTreWeil], which was developed after joint discussions related to this paper, if the Lebesgue measure is ergodic under the flow in direction on the surface , then for almost any we have
[TABLE]
Moreover, according to Proposition 4.7 is this paper, if in an ergodic direction on the surface , then for almost any in we have
[TABLE]
In particular, let be a Keane direction on a Veech surface , so that . According to Equation (2.3) and Equation (2.6), for almost any we have
[TABLE]
Moreover, according to Proposition 4.7, for almost any we have
[TABLE]
The notion of diophantine type considered in this paper is also related to geodesic excursions in moduli space. This is known to many authors, we refer to § 6.3 in [MarTreWeil] for sake of completeness. There are other definitions of Diophantine type given by the size of continued fraction matrices in the Rauzy-Vecch induction algorithm [Ki], [KiMa2]. For example Roth type Diophantine condition form a full measure set [MMY] and can be used for obtaining Hölder estimates for the solution of the cohomological equation [MY]. See also [HuMarUl] and [KiMa] for more discussion on the size of the continued fraction matrices.
2.4. Back to billiards
Consider the billiard flow in a rational polygon, that is a polygon whose angles are all rational multiples of . Let be the finite group of linear isometries of , which are the linear part of affine isometries generated by reflections at sides of . The group acts on directions , so that any has a finite orbit and all orbits have the same cardinality. Therefore the phase space is foliated into invariant surfaces of the form , which are all mutually isometric, and the billiard flow acts as a linear flow on each of them. If is the -orbit of , then denoting by the restriction to of the billiard flow on , we have the commutative diagram
[TABLE]
Let be the L-shaped polygon defined by real numbers and and let be its reflection group. The surface related to in Equation (2.9) is obtained pasting the opposite sides of the cross-like polygon , thus . In particular, if are rationally dependent, then modulo an homothety one can assume that are all integers. In this case also the polygon has vertices with integer coordinates, thus is a square-tiled surface in . Theorem 1.1 follows from Theorem 2.1 and Theorem 2.2, via Equation (2.9). Similarly, Proposition 4.5 implies for almost any , and Proposition 4.6 implies for Lebesgue almost any , when the Lebesgue measure over is ergodic for . Finally, since origamis are Veech surfaces, when are rationally dependent Equation (2.7) implies for almost any .
2.5. Summary of the contents
The rest of the paper is organized as follows.
In § 3 we recall the representation of a translation surface by zippered rectangles pasted together along a Keane direction . Zippered rectangles (defined in § 3.1) are used in § 5 to prove Theorem 2.1. In § 3.3 we give a qualitative description of the Rauzy-Veech induction on zippered rectangles, which plays a role in § 4 in the proof of Proposition 4.5 and of Proposition 4.6.
In § 4 we first establish some general properties of the functions , , , . Then we prove Proposition 4.5 and of Proposition 4.6. We also prove Proposition 4.7, by a geometric argument only based on the flat geometry of cylinders.
In § 5 we prove Theorem 2.1. In § 5.2 we establish some general combinatorial Lemmas on zippered rectangles. In § 5.3 the general Lemmas are applied to the specific case of , completing the proof of Theorem 2.1.
In § 6 we explain the geometric constructions needed to prove Theorem 2.2. In § 6.1 we recall the graph structure of orbits of reduced origamis under the action of . In § 6.4 we consider origamis whose vertical is a one cylinder direction, which are used to obtain an upper bound for hitting time. In § 6.5 we consider vertical splitting pairs for reduced origamis, which are used to obtain a lower bound for hitting time.
In § 7 we prove Theorem 2.2 and Proposition 2.3. In § 7.1 we define a set of directions and in § 7.4 we give a lower bound for its dimension. The proof of Theorem 2.2 is completed in § 7.7. The proof of Proposition 2.3 is completed in § 7.8.
In § 8 we prove Proposition 2.5. The argument is an easy modification of the construction in § 6.4.
In § A we prove Lemma 6.5, which ensures that any origami in admits a splitting direction.
3. Zippered rectangles and Rauzy-Veech induction
Recall that a translation surface is defined as quotient space of the disjoint union of polygons in the plane under some identifications in their boundary. Here, for a Keane direction on , we describe a representation of the surface where all the polygons are rectangles , with sides alignes along the direction . The construction is originally due to Veech, here we follow the presentation in § 4.3 of [Yo].
An alphabet is a finite set with letters. A combinatorial datum is a pair of bijections . For us combinatorial data are assumed to be admissible that is for any . A length datum is any vector with all entries positive. For any such pair of data consider the interval and its two partitions and , where for any and we set
[TABLE]
An IET, or extensively interval exchange transformation, is the map uniquely determined by the data as the map that for any sends onto via a translation.
3.1. Veech’s zippered rectangles construction
A suspension datum for the combinatorial datum is a vector such that for any and we have
[TABLE]
Fix combinatorial-length-suspension data . The procedure below defines a translation surface . Details on the construction can be find in § 4.3 of [Yo]. A picture of a surface obtained by this construction can be seen in Figure 2 of this paper. Let us first set
[TABLE]
then let be the vector whose coordinates, for any , are defined by
[TABLE]
For any define the rectangle . These rectangles are the polygons to be pasted in order to define the translation surface . The identifications between their horizontal sides of the rectangles for are given by
[TABLE]
In order to describe the identification between the vertical sides of the rectangles above, it is convenient to introduce a copy of them, setting for any . We stress that this is just a convenient way to describe identifications, while in the quotient surface one has . For letters and with respectively and define the vertical segments
[TABLE]
Consider also the vertical segment whose endpoints are \big{(}\sum_{\chi\in{\mathcal{A}}}\lambda_{\chi},0\big{)} and \big{(}\sum_{\chi\in{\mathcal{A}}}\lambda_{\chi},\tau_{\ast}\big{)}. The identifications between vertical sides are given by the procedure below.
- (1)
For any with let be the letter with , then identify the common segment of and which coincide with the segment . 2. (2)
For any with let be the letter with , then identify the common segment of and which coincide with the segment . Since any is identified with , this induces identifications between segments in the vertical sides of the rectangles and not considered in the previous Point (1). 3. (3)
The last segment to be identified to some parallel one is . If then is identified with , where and are the letters with respectively and . If then is identified with , where and are the letters with respectively and .
Let be the translation surface obtained by the above construction. According to Proposition 5.7 in [Yo], if is any translation surface and if is a Keane direction on , then there exists data such that
[TABLE]
Moreover, modulo identifying I:=\big{[}0,\sum_{\chi\in{\mathcal{A}}}\lambda_{\chi}\big{)} with an horizontal segment , the IET corresponding to data is the first return of to .
3.2. On the position of conical points in the flat representation
This subsection contains some remarks that will be used in § 5.2. It can be skipped at the first reading. According to a standard notation, identify with . Fix combinatorial-length-suspension data , then for any consider the complex number and set
[TABLE]
which give the coordinates of conical singularity of the surface in the planar development corresponding to the data . We have if and whenever . Similarly if and whenever . Moreover for any the hight of the corresponding rectangle satisfies . It follows that points are always contained in the left vertical boundary side of the corresponding rectangle , that is for any we have
[TABLE]
For the right boundary side this is always true with one exception. Consider letters and with and , so that there exists letters and such that respectively and . Assume that .
- (1)
We have always , either by suspension condition, or by assumption , thus
[TABLE] 2. (2)
If we have by suspension condition, hence
[TABLE] 3. (3)
Finally, the exceptional case occurs when , indeed we have
[TABLE]
3.3. Rauzy Veech induction
Let be any translation surface and a Keane direction on , then consider combinatorial-length-suspension data representing the surface along the direction , that is data such that Equation (3.1) is satisfied. The so-called Rauzy-Veech induction algorithm defines inductively a sequence of data representing the same surface along the direction . In this subsection we just point out a qualitative property of the algorithm used in § 4, for more details see § 7 of [Yo].
Admissible combinatorial data over the alphabet are organized in Rauzy classes, which are always finite, since the number of admissible combinatorial data over a finite alphabet is finite. In any Rauzy class are defined two bijections and , where the symbols and stands respectively for top and bottom. For any and any value of , it is defined an integer matrix (see § 7.5 in [Yo]). For a pair of data with
[TABLE]
it is defined a type as follows. Let and be the letters with , then set if whereas if (see § 7.2 in [Yo]). Consider and assume the sequence of data is defined for , with . Then define inductively
[TABLE]
where the definition above is possible for any because if is a Keane direction on then any data satisfies Condition (3.2) (see § 5 in [Yo]), thus the type is always defined. For any , let be the IET determined by the data , which acts on the interval I^{(n)}:=\big{[}0,\sum_{\chi\in{\mathcal{A}}}\lambda^{(n)}_{\chi}\big{)}. The following holds
- (1)
We have and is the first return map of to (§ 7.2 in [Yo]). 2. (2)
The data are combinatorial-length-suspension data satisfying Condition (3.1). The interval is identified with an horizontal segment in and is the first return map of to (§ 7.4 in [Yo]). 3. (3)
Define as in the beginning of § 3.1. For any we have (§ 7.7 in [Yo])
[TABLE] 4. (4)
Let be any ergodic invariant measure for . According to § 8 in [Yo], the rectangles defined from the data as in § 3.1 give a partition of by open rectangles
[TABLE]
4. Generic bounds for Keane and ergodic directions
4.1. General measure preserving systems
In general measure preserving dynamical systems, the upper limit of the recurrence asymptote is bounded by the dimension. For example, in [BaSa] it was shown that if is a Borel measurable transformation on a measurable set for some and is a -invariant probability measure on , then for almost every we have
[TABLE]
For the hitting time, it’s also well known that the limit inferior of the hitting time asymptote is bounded by below. In [Ga] it was shown that, if is a discrete time dynamical system where is a separable metric space equipped with a Borel locally finite measure and is a measurable map for each fixed and for almost every , then we have
[TABLE]
4.2. General Keane directions on a translation surface
Let be a translation surface of genus with . For any Keane direction on the set of Borel probability measures invariant under is a finite dimensional simplicial cone of dimension at most , whose extremal points are the ergodic measures for (see § 8.2 in [Yo]). In particular, we have positive real numbers with such that
[TABLE]
Lemma 4.1**.**
Let be a Keane direction on and let be an invariant Borel probability measure for . Fix . Then for -a.e. we have
[TABLE]
Proof.
Let satisfying Equation (3.1), so that the surface is obtained by zippered rectangles in direction , pasted along a segment in direction orthogonal to , and the first return of to is a Keane IET . Continuous time for and discrete time for are comparable, the ratio between the two being bounded by the ratio between the tallest and the shortest rectangle. Moreover the -invariant measure corresponds to an invariant Borel probability measure for . Then the statement follows because, according to the results of [BaSa] and [Ga] reported in § 4.1, it holds for . ∎
Lemma 4.2**.**
Let be a Keane direction on a translation surface . Then for any pair of points in not on any singular leaf, and for any in we have
[TABLE]
Proof.
Just observe that since locally the flow is a translation, when is small enough we have
[TABLE]
∎
Lemma 4.3**.**
Fix any direction on a translation surface and let be an ergodic measure for . Then there exist constants
[TABLE]
depending on such that
[TABLE]
Proof.
It is well-known that if is a Borel function which is invariant under , and is ergodic under , then there exists a constant such that for -almost any (e.g. [Wa]). The first part of the statement follows trivially since and according to Lemma 4.1. We finish the proof for , the argument for being the same. The generalized Birkhoff Theorem recalled above implies that for any there exists such that
[TABLE]
Similarly for any there exists such that
[TABLE]
Then a standard Fubini argument gives the proof. ∎
The simple Lemma 4.4 below will be used in several arguments. For a countable family of measurable sets in a probability space we set
[TABLE]
Lemma 4.4**.**
For any countable family of sets in a probability space we have
[TABLE]
Proof.
Just observe that since is a decreasing sequence of sets, we have
[TABLE]
Proposition 4.5**.**
Let be any Keane direction on the translation surface . Then for Lebesgue almost any we have
[TABLE]
Proof.
According to the first part of the statement of Lemma 4.1, it is enough to prove that for Lebesgue almost any . Recall that , according to Equation (4.1), where are the ergodic measures for , and assume without loss of generality that strictly for any (otherwise just consider those with ). Fix any with and , with , so that for any Borel set . It is enough to prove that for almost any . Let be data satisfying Condition (3.1), that is . Following § 3.3, for any let be the data obtained by Rauzy-Veech induction from , so that . In particular we have a partition of into embedded and mutually disjoint open rectangles , as in Equation (3.3). Let be a letter such that for infinitely many . For simplicity, assume without loss of generality that for any . Thus for any set
[TABLE]
and recall that for and also for , since for . In the coordinate system of , consider the sub-rectangle
[TABLE]
Observe that for any we have because and
[TABLE]
thus Lemma 4.4 implies . On the other hand for any we have . It follows that for any we have
[TABLE]
where the last equality in the first line holds since and for and the last inequality follows observing that any rectangle satisfies
[TABLE]
Ergodicity of and Lemma 4.3 imply for a.e. . The Proposition is proved. ∎
4.3. Ergodic directions
In this subsection we assume that the Lebesque measure is ergodic for the flow in direction on the surface .
Proposition 4.6**.**
Let be an ergodic direction on the translation surface . Then for Lebesgue almost any in we have
[TABLE]
Proof.
Let be data satisfying Condition (3.1). Following § 3.3, for any let be the data obtained by Rauzy-Veech induction from , so that . Consider the open rectangles , given by Equation (3.3). Let be a letter such that for infinitely many . For simplicity, assume without loss of generality that for any . Since the rectangles are embedded in then , thus for any we have finally . For any set . Moreover, in the coordinate system of , set
[TABLE]
then note that , so that , according to Lemma 4.4. Observe that for any and , therefore for we have
[TABLE]
Since is ergodic, then Lemma 4.3 implies for almost any . The Proposition follows from the second part of Lemma 4.1. ∎
Proposition 4.7**.**
Let be an ergodic direction on the translation surface . Then for Lebesgue almost any in we have
[TABLE]
Proof.
Fix any with . Since is arbitrary, it is enough to prove that for almost any we have . Moreover, since is ergodic under , according to Lemma 4.3 it is enough to prove the last inequality for any pair of points is some subset of with positive measure with respect to .
According to the definition of , there exists infinitely many closed geodesic whose corresponding cylinder satisfies and such that
[TABLE]
Let be the direction of . Let also be the orthogonal width of with respect to , that is the length of a segment in direction contained in the interior of and with both endpoints on , so that in particular we have . Set
[TABLE]
Consider and assume that for small . The time needed to such to come back to is
[TABLE]
Let be the subset defined by
[TABLE]
then observe that , so that Lemma 4.4 implies . Observe that for any and any and we have , thus the Proposition follows because for any we have
[TABLE]
where the last equality follows because for any we have
[TABLE]
∎
5. Upper bound for hitting time: proof of Theorem 2.1
In this section we prove Theorem 2.1. Fix a surface and a Keane direction on . The Theorem follows directly from Proposition 5.1 below. Indeed, considering a positive sequence and applying the Proposition for any such , one gets a sequence of saddle connections on such that , thus the saddle connection must form an infinite family, because is a Keane direction. Theorem 2.1 of course holds also for translation surfaces with because an homothety of the surface does not change .
Proposition 5.1**.**
There exists a constant , specific of , such that the following holds. Fix and let be a surface in with and a Keane direction on . Consider small enough and points in with
[TABLE]
Then there exists a saddle connection on with such that
[TABLE]
5.1. Long hitting time implies tall rectangles
Let be a stratum of translation surfaces and be involutions induced by the elements acting by and on vectors . Let be the group generated by an . If is a Keane direction on the surface , in order to compute one can replace and by their images under any , indeed for any saddle connection in the action of leaves invariant the quantities and . We say that the pair is represented by data in the standard sense if there exists data such that Equation (3.1) is satisfied, that is . We say that the pair is represented by data in the general sense Equation (3.1) is satisfied by some surface with . Recall that we set . Moreover set also and .
Lemma 5.2**.**
Fix . Consider and points in with
[TABLE]
Then there are data with representing the pair in the general sense such that
[TABLE]
Proof.
In order to simplify the notation, assume that , which amounts to replace the surface by . The flow thus corresponds to the flow in the vertical direction , and is simply denoted . In particular write for points in and for . Replace by , that is invert the time of the vertical flow, and let be an horizontal interval in centered at and with length . Let be the first return to of the vertical flow of , which a priori is an IET on intervals. Condition implies that must belong to a rectangle with hight at least .
Step (1). Let be minimal such that , then set and let be the first return. We claim that , moreover the return time function has the same (constant) values on corresponding subintervals of and . This is because the vertical flow is trivial inside a flow box, that is an open set of the form which does not intersect . Then get just by extending a flow box to its maximum. Therefore a rectangle with hight at least persist for .
Step (2) Let be the biggest connected component of . We have (if is small enough than balls of radius around conical singularities are mutually disjoint, hence just 2 connected components). Let be the first return to . Since is a first return of onto a subset , then it also has a rectangle with hight at least . On the other hand, is an IET on intervals. Finally, modulo replacing by one can assume that the left endpoint of belongs to .
Step (3) Let be the right endpoint of , which a priori is not an element of . Thus in general has singularities whose positive -orbit ends at points of , plus one extra singularity whose -orbit ends in . The singularities of are the images , corresponding to first intersection with of positive -trajectories starting at points of , plus , corresponding to the first intersection with of the positive -orbit of . Let be the subinterval with same left endpoint as , and whose right endpoint is the rightmost of the points and , then let be the first return of to . Let be the data representing with . A rectangle with hight at least persist for , since the latter is a first return of . Modulo replacing by one can also assume . Finally, to see the estimate on , it is enough to observe that instead of shortening , one can extend it by a horizontal segment with whose endpoint belongs to the -orbit of , ans then recovering from by a finite number of Rauzy steps, as the first renormalized interval with length shorter than . We get
[TABLE]
5.2. Combinatorial Lemmas on zippered rectangles
In this subsection we state some properties of the zippered rectangles construction introduced in § 3.1, that we will use in the next subsection. We consider the direction on a surface , and we assume that is represented by data in the standard sense. No normalization is required on the total area, except for Corollary 5.6, where . The first is an easy Lemma, whose proof is left to the reader.
Lemma 5.3**.**
Let be a surface represented by data . Let be the letter with and assume that
[TABLE]
Then the straight segment connecting the center of the rectangles and corresponds to a closed geodesic on the surface with
[TABLE]
The next two Lemmas concern data with where all singularities touch the rectangles in the top line very close to their lower horizontal side. We recall that when the discussion in § 3.2 applies for the position of points relatively to the rectangles .
Quantitative relations are stated in term of a parameter , depending only on the number of intervals, with . For surfaces in , this situation leads to cylinder bounded by two homologous saddle connection, as in Figure 2. In general, Corollary 5.6 holds, which represents a starting point for a proof by induction on genus of a general result extending Proposition 5.1 to any stratum. Set
[TABLE]
Lemma 5.4**.**
Let be a triple of data with . Fix an integer and assume that
[TABLE]
Let be an integer with and be a letter with such that
[TABLE]
Then for any letter with we have
[TABLE]
Moreover we also have
[TABLE]
Proof.
We first prove the first part of the statement. If then the required property holds trivially. Otherwise, let be the letter with and observe that we have
[TABLE]
Consider two cases.
- (1)
If then the assumption implies
[TABLE] 2. (2)
Otherwise, calling the letter such that , we have
[TABLE]
Replacing by and repeating the argument recursively on with , we get that if is the letter with then we have
[TABLE]
The first part of the statement is proved. In order to prove the second part, observe that if is the letter with then we have and thus , hence
[TABLE]
∎
Lemma 5.5**.**
Let be a triple of data with . Fix an integer and assume that
[TABLE]
Then we have
[TABLE]
Moreover, if is the letter with the following holds
[TABLE]
Proof.
Since for any , then the assumption implies that there exists with and
[TABLE]
The second part of Lemma 5.4 with implies
[TABLE]
Now let be the letter with . We have
[TABLE]
The first part of Lemma 5.4 applied to the letter with implies that for all letters with we have
[TABLE]
Finally, assume by absurd that there exists some with and
[TABLE]
The first part of Lemma 5.4 applied to the letter with implies
[TABLE]
Then for the letter with it follows
[TABLE]
which is absurd. The Lemma is proved. ∎
Corollary 5.6**.**
Let be a triple of data with and . Fix an integer and assume that
[TABLE]
Then on the surface corresponding to data there exists a closed geodesic with
[TABLE]
Note: see the picture in Figure 2 for the special case .
Proof.
Let be the letter with and consider those with . For any such letter we have , since the total area is one, and . The Corollary follows directly from Lemma 5.5. ∎
5.3. End of the proof of Proposition 5.1
In order to simplify the notation, assume that , as in the proof of Lemma 5.2. This amounts to replace the surface by . The flow thus corresponds to the flow in the vertical direction . In particular, relative (or absolute) periods {\rm Hol}(\gamma,\theta)=\big{(}{\rm Re}(\gamma,\theta),{\rm Im}(\gamma,\theta)\big{)} take the form {\rm Hol}(\gamma,\theta=0)=\big{(}{\rm Re}(\gamma),{\rm Im}(\gamma)\big{)}. Moreover, for points in and for write .
Consider small enough and points in with . Let be data representing the surface in the general sense as in Lemma 5.2. Assume without loss of generality that represent in the standards sense. Moreover recall that we have
[TABLE]
Let be the alphabet for the Rauzy class of . Let also fix the names of the letters in the first row of , that is set
[TABLE]
The proof of Proposition 5.1 follows by separate analysis of the cases listed below.
Case (1) Suppose that there is a subset with such that for any . In this case the Proposition follows from an straightforward generalization of Lemma 5.3, which gives a closed geodesic with and .
Case (2) Suppose that there is a subset with such that for any . Then condition implies that there exists with such that for any we have and thus . Thus the proof follows as in Case (1).
Case (3) Suppose that there exists an unique with . Moreover assume also that such letter satisfies
[TABLE]
If then condition implies and thus for . Moreover , therefore corresponds to a saddle connection on the surface . Moreover such satisfies
[TABLE]
thus the Proposition is proved. The case is similar and corresponds to a saddle connection with the required properties. The last sub-case to consider is . In this case, observe first that arguing as above one has for . Then let be the letter with and observe since then we also have , indeed condition implies
[TABLE]
If then the Proposition follows as in Case (1). Otherwise , thus there is a letter with . If again the Proposition follows as in Case (1). Otherwise condition implies that is a saddle connection for the surface , and moreover we have thus such satisfies
[TABLE]
Case (4) The last case to consider is when for any with we have
[TABLE]
According to Lemma 5.5, where and we have for any with . If then the Proposition follows immediately as in Case (1). If and then , thus again we have 3 short intervals and we conclude as in Case (1). Finally, if and then the Proposition follows because Lemma 5.3 provides a closed geodesic on the surface with
[TABLE]
The last sub-case to consider is . In this case, let be the letter with and observe that , so that and
[TABLE]
whereas the remaining singularities with lie on the vertical boundary of both rectangles at their left and at their right. Moreover , since is admissible, thus let be the letter with . Let also be the letter with , where we may have . Finally, observe also that and corresponds to two homologous saddle connections on the surface , since they bound a cylinder (see Figure 2). We have , according to Lemma 5.5. If then the Proposition follows since the saddle connection (and too) satisfies
[TABLE]
Otherwise, since we have either and thus
[TABLE]
or and thus
[TABLE]
Since then in both cases the Proposition follows as in Case (1). The analysis of cases is complete and Proposition 5.1 is proved. ∎
6. Geometric constructions on reduced origamis
It is convenient to consider the slope of a direction on an origami , rather than the direction itself. That is for any we consider the linear flow , as the integral flow of the constant unitary vector field on defined by
[TABLE]
Modulo the same change of variable, we will also refer to -singular leaves as trajectories of starting or ending at singular points. In the following we will establish relations between flows and in different slopes and on different surfaces. In order to avoid ambiguities, when considering , for and for points in we introduce the extended notation
[TABLE]
6.1. Reduced origamis and their orbits
Recall from § 2.1.4 that a translation surface is an origami if and only if , where is the set of relative periods of , and this is equivalent to say that the Veech group of and share a finite index subgroup. We say that an origami is reduced if , that is the subgroup of generated by the set is the entire lattice . In this case Equation (2.1) implies for any , that is is a subgroup of with finite index . According to Equation (2.1), the action of on translation surfaces induces an action of on origamis. Moreover, it is also clear that the action of preserves the set of reduced origamis (see also Lemma 2.4 in [HuLe]). If is a reduced origami, denote by its orbit under , that is
[TABLE]
There is a natural identification , thus is a finite set with cardinality . The action of passes to the quotient and can be represented by a finite oriented graph, whose vertices are the elements and whose oriented edges correspond to the operations and for , where we introduce the two generators
[TABLE]
of . Fix and consider positive integers . Define the element of by
[TABLE]
Lemma 6.1**.**
Let be an orbit with elements. For any two elements and in there exists a word with even length with and for any , such that
[TABLE]
Proof.
Rational slopes are partitioned into cusps, the latter being identified also with -orbits over , see for example § 2.6 in [HuLe]. For any there exist two positive integers and with , called width of the cusp respectively of the horizontal and vertical slope of , such that and . Since is connected and has elements, there is a path in the letters and with length at most connecting to . Contract subpaths which are the product of terms into letters of the form , and do the same for the generator . This produces a word with length such that , moreover for any . If is not even, recalling that for , get a word of even length of the form , where . Finally observe that for . ∎
6.2. Continued fraction
For any real number let be its integer part and be its fractional part, where by construction. The so-called Gauss map is the application defined for by
[TABLE]
Fix positive integers and consider the rational number defined by
[TABLE]
Any admits an unique continued fraction expansion , where for any the entry is known as the -th partial quotient of . Setting for any and , the entries are given by
[TABLE]
For a finite word of positive integers, let be the interval of those such that is defined with for any . Set also , where and . It is well know (see for example § 12 in [Kh]) that for any word we have
[TABLE]
and moreover, for any pair of positive integers we have
[TABLE]
Finally, let be the element in defined in Equation (6.2). The group acts on by homographies, that is the maps acting on by
[TABLE]
Lemma 6.2**.**
The sequence of approximations of is given by
[TABLE]
Moreover, for any we have
[TABLE]
Proof.
Just recall that setting and , the numerator and the denominator in satisfy and for any . For and the same recursive relations take the form
[TABLE]
The first part of the statement is proved. In order to prove second part consider three consecutive iterates , and of the Gauss map and observe that
[TABLE]
The relation between and follows applying times the identity above to . Then the relation with follows because . ∎
6.3. Flow segments in a cylinder
Fix a reduced origami and let be a closed geodesic with slope , corresponding to the vertical direction. Let be the vertical cylinder corresponding to and let be the transversal width of , so that . We have an isometric embedding , and in order to establish coordinates with and for points we consider the inverse
[TABLE]
Let be the boundary of with respect to its intrinsic metric, and extend and continuously to points . We have a disjoint union , where and are the components of of those points with and respectively (on the other hand, the boundary of with respect to the metric of may have just one connected component). For points in set and . Fix a slope with
[TABLE]
then set
[TABLE]
Inside , trajectories of travel in direction close to the vertical, and Equation (6.7) implies that there are points such that for any . For the orbit comes back to the horizontal segment passing through and we have
[TABLE]
For any we have
[TABLE]
Moreover, for , the orbit comes back to with horizontal and vertical translation given by
[TABLE]
Now fix a reduced origami and assume that , that is and belongs to the same -orbit. Consider a slope on and for let be its -th image under the Gauss map. Fix and consider the first entries of the continued fraction of . Set , which is defined by Equation (6.2), and assume that
[TABLE]
Assume also that the renormalized slope satisfies Equation (6.7), that is
[TABLE]
The action of induces an affine diffeomorphism 111Actually, such is not unique, indeed there exist reduced origamis admitting non-trivial automorphisms, that is affine diffeomorphisms with . Nevertheless, non-unicity of does not affects the arguments in this paper. , that is a diffeomorphism between the surfaces and whose derivative is constant with value . Under such affine diffeomorphism, the flow with slope on the surface corresponds to the flow with slope on the surface , where the two slopes are related under the homographic action of by Equation (6.5).
Observe that if are linearly independent and is such that then for any with we have
[TABLE]
Let and be the unitary vectors with slopes and , which are defined in Equation (6.1), so that in particular is parallel to . Let also and be the unitary vectors with slope and respectively. Since for we have for any , then the estimate above can be applied to the cone spanned by and . Observe that and that we have
[TABLE]
Therefore, if is a segment of trajectory of , its image under has length such that
[TABLE]
6.4. One cylinder directions
Fix a reduced origami and let be a cylinder in the vertical slope . Let be a segment of straight line contained in the interior of and abusing the notation let be a parametrization of it with constant speed . The slope of such segment is . We say that such segment is transversal to if , and the slope is negative, that is
[TABLE]
Observe that if is horizontal then , thus it is simply transversal to . Recall that in the notation of § 6.3 we set .
Lemma 6.3**.**
Fix and as above and a slope satisfying Equation (6.7). Let be a point not on any -singular leaf and such that for . Then for any segment transversal to there exists such that
[TABLE]
Proof.
It is enough to prove the Lemma when is horizontal, and in this case the statement follows directly applying Equation (6.8) to the point ∎
Assume now that the vertical is a one cylinder direction on the reduced origami , that is there is only one cylinder in slope . Let be the corresponding vertical closed geodesic and observe that since is reduced, then the cylinder has transversal width . The boundary (with respect to the intrinsic metric of ) is composed by saddle connections parallel to , which appear in pairs, and the identification between paired saddle connection gives the surface . Now let be a reduced origami and assume that contains as above.
Proposition 6.4**.**
Fix a slope and assume that for we have
[TABLE]
Then for any pair of points in , where does not belong to any -singular leaf, we have
[TABLE]
Proof.
Following § 6.3, set and consider the corresponding affine diffeomorphism . Under the vertical cylinder corresponds to a cylinder with slope in the surface . Let be the slope related to by Equation (6.5), that is . Since , then Equation (6.7) is satisfied by the slope on the surface . Let be a point as in the statement and observe that does not belong to any -singular leaf. Either there exists some with such that , and in this case we set , or belongs to the interior of for , and in this case we set and . In both cases, since is the only vertical cylinder in , then the point satisfies the assumption of Lemma 6.3, that is for any with . Finally let be the segment in the surface passing through with slope , that is orthogonal to the direction of the cylinder , and with both endpoints on . The segment has length , indeed we have
[TABLE]
The segment in the surface has slope
[TABLE]
thus is transversal to . According to Lemma 6.3 there exists some with and such that , that is
[TABLE]
Consider such that and observe that
[TABLE]
The Proposition follows because Equation (6.11) implies
[TABLE]
and on the other hand, since both and belong to , then
[TABLE]
∎
6.5. Vertical splitting pairs
Let be a reduced origami. The vertical slope is completely periodic and is decomposed into vertical cylinders pasted together along their boundary. Let and be respectively a vertical closed geodesic and saddle connection on the surface . Let be the vertical cylinder corresponding to and be its transversal width. We say that is a vertical splitting pair for the surface if the following holds.
- (1)
The saddle connection belongs to both the two components of the boundary of the cylinder (with respect to its intrinsic metric). In other words touches both from the left and the right side. 2. (2)
The closure of does not fill the entire surface , that is there exists an other vertical cylinder . 3. (3)
We have , that is the positive integers and are co-prime.
Figure 3 gives an example of vertical splitting pair. In § A we prove the Lemma 6.5 below. The Lemma does not hold in all strata. For example in the stratum , a counterexample is given by an origami known by the German name Eierlegende Wollmilchsau, a picture of which appears in Figure 4 (see also § 8 of [FoMat]).
Lemma 6.5**.**
For any reduced origami in there exists which admits a vertical splitting pair . More precisely, we can always find a splitting pair with either or and even.
Let be a vertical splitting pair for the surface , consider the cylinder around and its boundary with respect to its intrinsic metric. Let and be the two representative of in , which are two vertical segments whose horizontal distance is . Consider the coordinates and given by Equation (6.6), and recall that . Then define as the unique integer with which gives the vertical distance between and , that is
[TABLE]
It is obvious that and . Given a vertical splitting pair , the next Lemma gives a condition on the slope for the existence of a subset with big measure of points whose -orbit remains in for a long time. It is practical to observe also that if and satisfy , since and since of course is an integer, we get
[TABLE]
Lemma 6.6**.**
Let be a vertical splitting pair on the surface and let be the corresponding cylinder. Fix a slope and consider the flow on . Assume that the following condition are satisfied
[TABLE]
Then there is a subset with measure such that for any we have
[TABLE]
Proof.
Recall the notation in § 6.3, and in particular the time needed by -orbits to travel from one component of to the other. Let and be the two vertical segments such that and , where is above . Consider the set of points
[TABLE]
We have obviously . According to the last assumption on , there exists some such that
[TABLE]
The last equation above, together with Equation (6.10), imply that for any we have
[TABLE]
and in particular , according to Equation (6.13). Since any belongs to the orbit of some then for any we have and in particular \delta_{H}\big{(}\phi_{\alpha}^{T_{1}}(p),p\big{)}=0. Moreover, the equation above and Equation (6.14) imply
[TABLE]
If is such that we can repeat the argument above times and we get that for any we have and
[TABLE]
Therefore any stays in for time at least
[TABLE]
∎
Proposition 6.7**.**
Let be a reduced origami and be an element in its orbit which admits a vertical splitting pair . Let be a slope on and assume that there exists with
[TABLE]
Then there exist two subsets with area and such that for any and we have
[TABLE]
Proof.
Following § 6.3, set and consider the corresponding affine diffeomorphism . Observe that according to the first two assumptions on and we have and , thus the first two assumptions in Lemma 6.6 are satisfied by the slope on the surface . Moreover, since , then we have according to Equation (6.14), thus the third condition on in the statement implies
[TABLE]
and the third assumption in Lemma 6.6 is also satisfied. Apply Lemma 6.6 to the slope on the surface , with respect to the vertical splitting pair . Let be the subset provided by the Lemma, whose area satisfies , since and . Recalling that is a splitting pair, let be a vertical cylinder in disjoint from and let be the open set obtained from removing the -neighborhood of its boundary , where . The set is foliated by vertical closed geodesics with length and has transversal with , thus its area satisfies . The two required sets are
[TABLE]
The lower bounds for the areas and follow trivially because the action of preserve the areas. According to Lemma 6.6, the time spent inside by orbits of points is at least
[TABLE]
The cylinders and in direction [math] on the surface correspond respectively to cylinder and in direction on the surface . According to Equation (6.11), the time spent inside by orbits of points is at least
[TABLE]
On the other hand the set has distance from . Therefore the set has distance from the boundary of which satisfies
[TABLE]
The Proposition follows observing that any has distance at least from any point in , thus for any pair of point and we have
[TABLE]
∎
7. A set of slopes with prescribed long hitting time
Let be a reduced origami and let be its orbit. Let be the cardinality of . Assume that the orbit contains both an element with a vertical splitting pair and an element whose vertical is a one cylinder direction, so that in particular . Denote the vertical closed geodesic in , and recall that since is reduced then the corresponding cylinder has transversal width . Let be the vertical splitting pair in and let and be the integers defined in § 6.5. We will use the following easy Lemmas.
Lemma 7.1**.**
There exists such that for any we have
[TABLE]
Proof.
Just recall that and are co-prime. ∎
Lemma 7.2**.**
Fix a word with for any and a pair of elements such that . Then there exists with
[TABLE]
such that .
Proof.
Recall the definition of in Equation (6.2), and that there exists with such that . Write and for in , then set and observe that for we have
[TABLE]
∎
7.1. Construction of a set of slopes
A Cantor-like set is a closed set of the form , where and where for any the set is a finite union of mutually disjoint closed intervals with . Fix and with . Denote
[TABLE]
Proposition 7.3 below defines a Cantor-like set by specifying conditions on the entries of the continued fraction of elements .
Proposition 7.3**.**
There exists a Cantor-like set such that for any we have
[TABLE]
Moreover for any there exist integers \big{(}p(k)\big{)}_{k\in{\mathbb{N}}} and \big{(}n(k)\big{)}_{k\in{\mathbb{N}}} with such that for any we have and
[TABLE]
Finally, there exists a constant , depending only on , , and such that
[TABLE]
The levels for of are defined inductively according to the procedure described in § 7.1.1, § 7.1.2, § 7.1.3, § 7.1.4, and § 7.1.5 below. Then the proof of Proposition 7.3 is completed in § 7.3. In particular, we will give two different definitions for odd levels and even levels . We will use the following notion: a finite family of finite words of even length is said disjoint if there are not two words and in such that and for . Moreover, in virtue of Lemma 6.1, for , we will consider blocks with
[TABLE]
and blocks with
[TABLE]
which, according to Lemma 7.2, are then modified into blocks with
[TABLE]
7.1.1. Level .
Let be the maximal disjoint family of finite words which satisfy Equation (7.1), where the first two entries are defined by and and where the block satisfies Equation (7.8). This is possible applying Lemma 6.1 with and , indeed we have
[TABLE]
For any , apply again Lemma 6.1 with and , and then Lemma 7.2, and let be the maximal disjoint family of words such that
[TABLE]
and which satisfy Equation (7.9). Let be the family of concatenated words
[TABLE]
Any such word satisfies Equation (7.3), that is
[TABLE]
For any let be the set of integers which satisfy Equation (7.4) and Equation (7.5). Let be the union, over , of the intervals defined by
[TABLE]
7.1.2. Level .
Let be the family of words of the form , where and where the last entry satisfies . For any let be the set of those which satisfy Equation (7.6). Finally let be the union, over , of the intervals
[TABLE]
7.1.3. Inductive assumption.
Fix and assume that the families are defined, where in particular is a family of words of odd length, such that removing the last entry Equation (7.3) is satisfied, that is
[TABLE]
Assume also that the closed sets are defined, where any is a finite union of mutually disjoint closed intervals. Assume in particular that the intervals in are labeled by words . Finally, assume that for any interval in the level , where is the corresponding word, there is a finite subset such that
[TABLE]
7.1.4. Level .
Fix
[TABLE]
then let be the maximal disjoint family of those words which satisfy Equation (7.8) and the condition
[TABLE]
This is possible applying Lemma 6.1 with and . Then let be the family of concatenated words
[TABLE]
where and where the last block satisfies
[TABLE]
Any such concatenated word satisfies Equation (7.1), indeed, according to the inductive assumption, we have
[TABLE]
Fix and apply first Lemma 6.1 with and , and then Lemma 7.2, and define as the maximal disjoint family of words which satisfy Equation (7.9) and are such that
[TABLE]
Let be the family of concatenated words
[TABLE]
Any such concatenation satisfies Equation (7.3), indeed we have
[TABLE]
Define the family as the union, over , of the families . For any let be the set of integers which satisfy Equation (7.4) and Equation (7.5). Finally, let be the union, over , of the intervals defined by
[TABLE]
7.1.5. Level .
Let be the family of words of the form , where and where the last entry satisfies . For any such word define as the set of those which satisfy Equation (7.6). Finally let be the union, over , of the intervals
[TABLE]
7.2. Growth of denominators
Fix and recall the notation in § 7.1. Consider any
[TABLE]
Since satisfies Equation (7.6), we have
[TABLE]
so that in particular
[TABLE]
Observe that the partial quotients relating and are the entries of the block in the family , so that
[TABLE]
Therefore, setting , Equation (7.10) implies
[TABLE]
Moreover, consider any . The partial quotients relating the denominator and are the entries of the block in the family , so that, setting we have
[TABLE]
Therefore, since , observing that Equation (7.4) implies
[TABLE]
recalling Equation (7.12) we get
[TABLE]
7.3. Proof of Proposition 7.3
The inductive definition of the levels of the set is given in § 7.1. The diophantine type of , which is defined in Equation (1.2), is also the supremum of those such that for infinitely many . Therefore for any , because for any the entries and of satisfy Equation (7.4) and Equation (7.6) respectively, while all other are uniformly bounded, according to Equation (7.8) and Equation (7.9). It only remains to prove Equation (7.7). To do so, set , in terms of the constants and defined in § 7.2, and observe that
[TABLE]
where the first equality follows from Equation (7.11) and the second from Equation (7.13). Proposition 7.3 is proved. ∎
7.4. Dimension estimate
Consider a Cantor-like set , where and for any the set is a finite union of mutually disjoint closed intervals with . For any and any interval in the level the spacing is the quantity defined by
[TABLE]
where the minimum is taken over all pair of distinct in and where for any pair of closed intervals with we set . Set also
[TABLE]
that is the number of intervals of level which are contained inside the interval . We define a probability measure with support in setting , then assuming that is defined for all and all intervals in level , for any in the level we define inductively
[TABLE]
where is the unique interval of the level such that . One can see that this defines a probability measure on Borel subsets of (see Proposition 1.7 in [Fa]). Moreover, for such a measure supported on , if there exists a constant with and constants and such that
[TABLE]
for any interval with and with endpoints in , then we have (see § 4.2 in [Fa]). We recall Lemma 7.4 below, which is a little variation of Example 4.4 in [Fa]. We provide a proof for sake of completeness.
Lemma 7.4**.**
Assume that there exists a constant with and a constant such that for any the following holds.
- (1)
For any in we have . 2. (2)
For any in and any in we have .
Then we have .
Proof.
Set . For any and any interval in the level there is a nested sequence of intervals , where belongs to the level for , so that the definition of and Assumption (2) imply
[TABLE]
Let be an open interval with endpoints in and with . Then there exists maximal such that . Let be the number of intervals in which intersect (where by maximality of ). Assumption (1) implies
[TABLE]
Recalling that any interval in has measure , then the Lemma follows because the two last estimates imply
[TABLE]
∎
Fix and with , then let be the set in Proposition 7.3.
Proposition 7.5**.**
We have \displaystyle{\dim_{H}\big{(}{\mathbb{E}}(X,\eta,s)\big{)}\geq\frac{\eta^{s-1}-1}{\eta^{s}-1}}.
Proof.
We check that Point (1) and Point (2) in Lemma 7.4 are satisfied. Referring to the notation in § 7.1, we consider separately intervals in even level and intervals in odd levels. Fix .
According to the definition in § 7.1.4, for any interval in the level Equation (7.4) and Equation (6.4) imply
[TABLE]
Therefore Equation (6.3) gives
[TABLE]
Moreover, according to § 7.1.5, we have
[TABLE]
On the other hand Lemma 7.1 implies for any two consecutive elements in , and for any we have , therefore
[TABLE]
Therefore we have
[TABLE]
Now consider any interval in the level , which is defined in § 7.1.5. Recalling Equation (7.6) and reasoning as above we get
[TABLE]
where the analogous estimate holds for any interval in the level . Moreover, referring to the definitions in § 7.1.4 and in § 7.1.5, we have
[TABLE]
where the last equality follows from Equation (7.6). On the other hand, observing that , we have
[TABLE]
where , where the third inequality follows from Equation (7.11) and Equation (7.12), and where the constants and are defined in § 7.2. It follows that
[TABLE]
Point (1) in Lemma 7.4 is established for all intervals in all levels of . Fix . For any interval in we have
[TABLE]
On the other hand for any interval , arguing as in § 7.2, we have
[TABLE]
where is a constant depending on and on . Therefore Condition (2) in Lemma 7.4 is satisfied for any big enough whenever
[TABLE]
For any interval in we have
[TABLE]
On the other hand for any interval we have
[TABLE]
where the second inequality follows from Equation (7.11) and Equation (7.12), and where is a constant depending on and on . Therefore Condition (2) in Lemma 7.4 is satisfied for any big enough whenever
[TABLE]
There is no loss in generality to assume that Condition (2) is verified for any . The Proposition follows recalling that and that . ∎
7.5. Hitting time estimates
Recall that we fix a reduced origami and we assume that its orbit contains both an element with a vertical splitting pair and an element whose vertical is a one cylinder direction. Fix and let be the set of slopes given by Proposition 7.3. For any consider the flow . consider also the integers \big{(}p(k)\big{)}_{k\in{\mathbb{N}}} and \big{(}n(k)\big{)}_{k\in{\mathbb{N}}} given by Proposition 7.3.
Lemma 7.6**.**
For any and for almost any in we have
[TABLE]
Proof.
According to Lemma 4.3, since is uniquely ergodic, it is enough to prove the inequality for any pair in a positive measure subset of . Fix an integer and apply Proposition 6.7 for , where we observe that the assumption in Proposition 6.7 are satisfied according to Equations (7.3), (7.4), (7.5) and (7.6) in Proposition 7.3. There exists two subsets with area and such that for any and and for r_{n(k)}=\big{(}12\cdot q_{2n(k)}\big{)}^{-1} we have
[TABLE]
where the second inequality corresponds to Equation (7.6) and the fourth holds because , according to Equation (7.4). Therefore for any pair
[TABLE]
The Lemma follows observing that
[TABLE]
∎
Lemma 7.7**.**
For any and for any with not on any -singular leaf we have
[TABLE]
Proof.
Fix and apply Proposition 6.4 for , where we observe that the assumption in Proposition 6.4 are satified according to Equation (7.1) and Equation (7.2) in Proposition 7.3. It follows that for any pair of points in as above and any we have
[TABLE]
Finally, fix any and let be the unique integer with . The Lemma follows observing that for any as above we have
[TABLE]
where the last inequality follows from Equation (7.7). The Lemma is proved. ∎
7.6. Reduced origamis are enough
Let be any origami and let and be integers such that , so that is reduced if and only if . If is not reduced, let and , then consider the combined action of and the homothety . The origami with is reduced, indeed we have
[TABLE]
The homographic action of on slopes is , which is a bijection from to itself. Moreover we have for any , indeed for any the change of variable gives the equivalence
[TABLE]
On the other hand consider the surface and let be the affine diffeomorphism with derivative , then for any let and consider the flow with slope on the surface . For any pair of points in we have
[TABLE]
Finally, it is obvious from the definition that admits a splitting direction or respectively a one cylinder direction if and only it does. Resuming, Theorem 2.2 holds for an origami if and only if it holds for the reduced origami as above.
7.7. Proof of Theorem 2.2
According to § 7.6, there is no loss of generality assuming that is reduced. Since the map preserves Hausdorff dimension, the proof can be done in the slope variable . Assume that contains both an element with a vertical splitting pair and an element whose vertical is a one cylinder direction. For the Theorem follows from Part (1) of Proposition 2.3, which will be proved later. For , consider the set given by Proposition 7.3, so that \dim_{H}\big{(}{\mathbb{E}}(X,\eta,s)\big{)}\geq f_{\eta}(s), according to Proposition 7.5. The Theorem follows combining Lemma 7.6 and Lemma 7.7. Modulo the proof of Proposition 2.3 (for the case ), Theorem 2.2 is proved. ∎
7.8. Proof of Proposition 2.3
As in § 7.7, assume that is reduced and consider the slope variable . Consider separately the two cases.
Case . Assume only that contains with a vertical splitting pair. Let be any element in , whose vertical is not necessarily a one cylinder direction. The set can be defined as in Proposition 7.3 and the dimension estimate in Proposition 7.5 still holds. Then Part (2) of Proposition 2.3 follows from Lemma 7.6.
Case . Assume only that contains whose vertical is a one cylinder direction. The set can be defined as in Proposition 7.3, replacing be any element in , not necessarily admitting a one cylinder direction, but for the dimension estimate in Proposition 7.5 gives the trivial bound \dim_{H}\big{(}{\mathbb{E}}(X,\eta,s=1)\big{)}\geq 0. Thus in this case we replace the set in Proposition 7.3 by the one provided by Lemma 7.8 below.
Lemma 7.8**.**
Fix . There exists a Cantor-like set with dimension such that for any we have and moreover there exist integers \big{(}p(k)\big{)}_{k\in{\mathbb{N}}} with such that for any we have , Equation (7.1) and Equation (7.2) are satisfied, and we have also
[TABLE]
Fix and consider . Replying the argument in Lemma 7.7, where the Equation (7.7) used in the proof of Lemma 7.7 is replaced by Equation (7.14), we get
[TABLE]
for any with not on any -singular leaf. For almost any the last inequality turns into an equality according to the general lower bound established by Equation (2.8), recalling that if is an origami. Modulo the proof of Lemma 7.8, Proposition 2.3 is proved. ∎
7.9. Proof of Lemma 7.8
The proof is a simplified version of the proof of Proposition 7.3. In particular for we define families whose elements are words which label the intervals in the level , so that the required Cantor-like set is . For a word define as the set of integers which satisfy
[TABLE]
then consider the interval
[TABLE]
In the construction below, just in order to refer to the notation in § 7.1, we introduce instants with for any .
Reasoning as in § 7.1.1, let be the maximal disjoint family of finite words which satisfy Equation (7.1), where the first two entries are defined by and and where the block satisfies Equation (7.8) with . Fix and assume that the family is defined. For any let be the set defined by Equation (7.15), then let be the family of concatenated words
[TABLE]
and where the block satisfies Equation (7.8) with , and the condition
[TABLE]
which is possible applying Lemma 6.1 with and . Arguing as in § 7.1.4 one can see that any satisfies Equation (7.1). Moreover, for any big enough, Equation (7.2) is also satisfied by the entry , according to Equation (7.15). Define the family as the union, over of the families , then define the level as the union, over of the intervals given by Equation (7.16). The definition of is complete. It is clear that for any . Moreover Equation (7.14) holds, indeed arguing as in § 7.2 we have
[TABLE]
where the first inequality follows from Equation (7.8), the second holds because and the third follows from Equation (7.15). Finally, in order to prove the dimension estimate on , recall the notation of § 7.4 and observe that reasoning as in the proof of Proposition 7.5, we have
[TABLE]
Therefore Condition (1) in Lemma 7.4 holds, indeed we have
[TABLE]
Moreover Condition (2) in Lemma 7.4 is also satisfied for any , which is equivalent to , indeed for any big enough we have
[TABLE]
Lemma 7.8 is proved. ∎
8. Proof of Proposition 2.5
This section follows § 6.4 and represents an adaptation of the arguments therein to the Eierlegende Wollmilchsau origami .
8.1. The Eierlegende Wollmilchsau origami
Following § 8.4 in [FoMat], recall that the quaternion group is the group of eight elements with relations
[TABLE]
It is easy to see that the other multiplication rules are , , , and . Moreover, recall from § 2.1.4 that we can describe an origami considering a finite family of labelled squares, each square being a copy of , and then defining identifications between their sides. The Eierlegende Wollmilchsau origami is the origami obtained considering the quaternion group as set of labels, with identifications given by the right multiplication by the two generators and . More precisely, for any consider the square , whose sides are , , and , where , , and are the sides of the standard square defined by
[TABLE]
The surface is obtained identifying, for any , the right side of the square with the left side of the square and the top side of with the bottom side of . Turning around the vertices of the squares and following the identifications, it is easy to check that has conical singularities, corresponding to the orbits of the right multiplication on by the commutator . Each singularity has conical angle , thus belongs to the stratum and has genus . Very specific dynamical and geometric properties of the surface are explained in § 7 and § 8 in [FoMat]. Two different representations of are given in Figure 4. In particular, by direct computation of the action on of the generators and of (see also Remark 87 in [FoMat]), one can see that the stabilizer of is the entire group , that is
[TABLE]
The surface has two cylinders and in the vertical slope , respectively around closed geodesics and . These closed geodesics have length and the corresponding cylinders have transversal width . Equation (8.1) implies that for any , there are two cylinders and in the rational slope , and in particular this holds for the horizontal slope .
Consider a line segment , that is a segment parametrized with constant speed , so that the slope of is . Any finite segment of trajectory of is a natural example, but in the following we will consider both flow segments and segments transversal to the flow. If , that is is not vertical, then it admits a vertical cutting sequence
[TABLE]
where we define and inductively for the instants by and the symbols by
[TABLE]
Similarly, if , that is is not horizontal, then it admits an horizontal cutting sequence
[TABLE]
where we define and inductively for the instants by and the symbols by
[TABLE]
It is convenient to express both vertical and horizontal cutting sequences of line segments in a reduced form. If is such cutting sequence, we write
[TABLE]
On the other hand, if the cutting sequence is in its non-reduced form, we write its -th letter as for .
Lemma 8.1**.**
Fix a subset and let be a line segment with slope , whose horizontal cutting sequence is . Let be such that
[TABLE]
Then .
Proof.
Recalling that , it is easy to see from the definition of that for a line segment with slope we have
[TABLE]
The Lemma follows observing that in order to have it is enough to have
[TABLE]
∎
8.2. Intersection Lemmas
Lemma 8.2 below establishes easy intersection criteria in terms of vertical and horizontal cutting sequences, corresponding to situations which are represented in Figure 4. The proof is left to the reader.
Lemma 8.2**.**
Let and be segments in with slopes respectively and . Let and in be such that and respectively . We have whenever there exists satisfying one of the conditions above.
- (1)
We have for some with and for some with . 2. (2)
We have for some with and for some with . 3. (3)
We have for some with and for some with .
Let be any of the two cylinders and in the vertical slope . Recall from § 6.4 that a line segment is said transversal to if it is contained in its interior, and moreover , and . A line segment is strongly transversal to the vertical if the restriction is transversal to either or for any . The vertical cutting sequence of such segment contains five letters, that is .
Lemma 8.3**.**
Let be a segment strongly transversal to the vertical, and consider any slope . Then for any not on any -singular leaf we have
[TABLE]
Proof.
Observe that, since then the cutting sequence satisfies . Observe also that there is no loss of generality to assume , so that the reduced form of the cutting sequence of is . Finally, since , then, reasoning as in the proof of Lemma 8.1, it is easy to see that the block admits only the four values , , and . We reason by absurd, considering separately the four cases. In each case, assuming that , for any with we obtain a set of forbidden letters for which Lemma 8.2 implies . The proof finishes when we get , which is of course absurd.
If , then contains the 2 blocks and , and also either the block or , all the blocks not in last position in . According to Points (1) and (2) of Lemma 8.2 we have . Lemma 8.1 gives the sequence of increasing sets of forbidden letters
[TABLE]
If , then contains the 2 blocks and , and also either the block or , all the blocks not in last position in . According to Points (1), (2) and (3) of Lemma 8.2 we have . Lemma 8.1 gives the sequence of increasing sets of forbidden letters
[TABLE]
If , then contains the 2 blocks and , and also either the block or , all the blocks not in last position in . According to Points (1), (2) and (3) of Lemma 8.2 we have . Lemma 8.1 gives the sequence of increasing sets of forbidden letters
[TABLE]
If , then contains the 2 blocks and , and also either the block or , all the blocks not in last position in . According to Points (1), (2) and (3) of Lemma 8.2 we have . Lemma 8.1 gives the sequence of increasing sets of forbidden letters
[TABLE]
∎
Now let be either or . A line segment is transversal to if it is contained in its interior and moreover , and . A line segment is said strongly transversal to the horizontal if is transversal either of for . Arguing as in Lemma 8.3 one can show the Lemma below, whose proof is left to the reader.
Lemma 8.4**.**
Let be a segment strongly transversal to the horizontal, and consider any slope . Then for any not on any -singular leaf we have
[TABLE]
8.3. End of the proof
Arguing as in § 6.4 and replacing Lemma 6.3 by Lemma 8.3 and Lemma 8.4, we get the Proposition below.
Proposition 8.5**.**
Fix any slope . Let be a point not on any singular leaf and be a point not on any saddle connection. Then for any we have
[TABLE]
Proof.
Consider the case of even , that is . Set and let be the slope related to by Equation (6.5), that is . Following § 6.3 and recalling Equation (8.1), consider the affine diffeomorphism , which sends the cylinders and to the cylinders and respectively, which have slope . Let be a segment passing through with slope , that is orthogonal to , and such that crosses exactly twice both cylinders and . Such segment exists because does not belong to any saddle connection. Moreover has length , indeed we have for any subsegment crossing perpendicularly exactly once. The slope of the segment is given by the same computation as in Equation (6.12), thus is strongly transversal to the vertical. Therefore, according to Lemma 8.3 we have with
[TABLE]
Reasoning as in Proposition 6.4, consider such that , that is . Equation (6.11) implies
[TABLE]
Finally, since both and belong to , we get
[TABLE]
In the case , set and let be the slope related to by Equation (6.5), that is . As above, consider the affine diffeomorphism which sends the cylinders and to the cylinders and respectively, which have slope . The required estimate follows by the same argument as above, replacing Lemma 8.3 by Lemma 8.4. Details are left to the reader. Proposition 8.5 is proved. ∎
Here we finish the proof of Proposition 2.5. It is no loss of generality to consider . Indeed, letting the integer part of and , we have obviously . On the other hand, reasoning as in § 7.6 and setting , it is also clear that the flow on corresponds to the flow on under some affine diffeomorphism , thus the two flows have the same hitting time.
Fix points , with not on any saddle connection and not on any -singular leaf. For any set . For any small enough consider such that . Since then for some and all big enough. Proposition 8.5 implies
[TABLE]
Therefore for any as above. The last inequality turns into an equality for almost any in according to Equation (2.8). Proposition 2.5 is proved. ∎
Appendix A Proof of Lemma 6.5
This subsection follows [HuLe] closely. It is more convenient to represent long cylinders along the horizontal direction. Thus we prove that any orbit in contains an origami with an horizontal splitting pair. The required origami is , where
[TABLE]
A.1. Separatrix diagrams
An origami in has a cone point of angle , thus for any there are outgoing -singular leaves at , also called separatrices. The horizontal direction is completely periodic, so that the horizontal separatrices are saddle connections. More precisely, each of them returns to the conical point making an angle , or with itself. Label the horizontal saddle connections with symbols in according to their counterclockwise order around the conical point, then define a permutation of by setting if the saddle connection comes back between the saddle connections and , that is with angle
[TABLE]
The combinatorics of these connections is called a separatrix diagram. The surface is obtained from such diagram by gluing cylinders along the saddle connections in the diagram, and is determined uniquely by the diagram and the metric data of the cylinders. At a conical point of angle , up to rotation by around the conical point, there are in total four separatrix diagrams, which correspond to return angles , , and and are shown in the upper part of Figure 5. These four separatrix diagrams correspond to conjugacy classes of permutations under cyclic permutations. Fix any such and consider an origami with separatrix diagram encoded by . A cycle of corresponds to the lower boundary of an horizontal cylinder in , the saddle connections composing it being those whose labels are the elements of the cycle. The upper boundaries of the horizontal cylinders in correspond to the cycles of the permutation defined by
[TABLE]
The separatrix diagram associated to can be realized geometrically by a surface in if the cycles of and appear as lower and upper boundaries of horizontal cylinders, which is a non-trivial condition. The first diagram in the upper part of Figure 5 corresponds to , that is the identity of , which gives , thus the diagram is not realizable because the cycles of correspond to horizontal cylinders while has only one cycle, which corresponds to just one cylinder. Similarly the fourth diagram is not geometrically realizable, because gives . The second diagram in the upper part of Figure 5 corresponds to , which gives , and is realized geometrically by the first surface in the lower part of the figure, which has two horizontal cylinders. Finally, the third diagram in the upper part of Figure 5 corresponds to , which gives , and is realized geometrically by the second surface in the lower part of the figure, which has just one horizontal cylinder.
A.2. Classification of orbits in
Any translation surface admits an unique affine diffeomorphism such that and , which is known as hyperelliptic involution. Such involution has fixed points on , which are known as Weierstrass points, and the conical point is always one of them. If is an origami in , then the conical point has always integer coordinates. According to Lemma 4.2 in [HuLe], the number of integer Weierstrass points, that we denote is an invariant of -orbits of origamis in . Moreover it gives a complete invariant, according to the Theorem below, which was first proved for prime in [HuLe] and then by [Mc] in the general case.
Theorem A.1**.**
Consider -orbits of reduced origamis in with squares. For any integer the following holds.
- (1)
If , there exist an unique orbit. We have for any in such orbit. 2. (2)
If is even, , then there exists an unique orbit . We have for any . 3. (3)
If is odd and , there there exist exactly two orbits and . We have for any and for any .
For an origami in there exist and explicit expressions for the involution and for the remaining 5 Weierstrass points (other than the conical point), according to the combinatorial type of the separatrix diagram of the horizontal direction (see also § 5.1 in [HuLe]).
If has type then has only one cylinder in the horizontal direction, with core curve . Since is reduced, we have . In this case is the central symmetry around the center of . The closed geodesic contains 2 Weirstrass points, one of them being the center of , the other being its opposite point in . They are never integer point, since . The remaining 3 Weierstrass points are the centers of the horizontal saddle connections , and , which may be integer or not, according to the values of the parameters for .
If has type then has two cylinders and in the horizontal direction, with core curves and respectively, which satisfy and . In this case the longer cylinder can be decomposed as , where is a parallelogram whose horizontal boundary is composed by and , and where is a parallelogram whose horizontal boundary is given by repeated on both sides. In this case acts separately on , and as the central symmetry around their centers, then compatibility at the boundary gives a global map on . The core curve contains 2 Weierstrass points, which are the center of and its opposite point. The core curve contains other 2 Weierstrass points, which are the centers of and of . The last Weierstrass point is the center of . These points may have integer coordinates or not, according to the values of the parameters and and for .
A.3. End of the proof: existence of splitting pairs in
Since Theorem A.1 gives a complete invariant for the classification of orbits in , then it is enough to find a representative with an horizontal splitting pair for any value of the invariant. In particular we need at least two cylinders in the horizontal direction , thus we will consider only surfaces were the horizontal has type . In Figure 6, for each integer and any value of the invariant IWP the pair is an horizontal splitting pair. The case is left to the reader. Lemma 6.5 is proved.
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