On the switching behavior of sparse optimal controls for the one-dimensional heat equation
Fredi Troeltzsch, Daniel Wachsmuth

TL;DR
This paper investigates the switching behavior of sparse optimal controls for the 1D heat equation, analyzing how control switches occur and converge as regularization diminishes, with implications for control sparsity and structure.
Contribution
The study characterizes the countability and accumulation points of switching points in sparse controls and examines their convergence as the regularization parameter approaches zero.
Findings
Switching points are countable with the final time as the only accumulation point.
Convergence of switching points is established as the regularization parameter tends to zero.
The control structure exhibits specific sparsity and switching behavior under natural assumptions.
Abstract
An optimal boundary control problem for the one-dimensional heat equation is considered. The objective functional includes a standard quadratic terminal observation, a Tikhonov regularization term with regularization parameter , and the -norm of the control that accounts for sparsity. The switching structure of the optimal control is discussed for . Under natural assumptions, it is shown that the set of switching points of the optimal control is countable with the final time as only possible accumulation point. The convergence of switching points is investigated for .
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Taxonomy
TopicsStability and Controllability of Differential Equations · Numerical methods in inverse problems · Advanced Mathematical Modeling in Engineering
On the switching behavior of sparse optimal controls for the one-dimensional
heat equation
Abstract
An optimal boundary control problem for the one-dimensional heat equation is considered. The objective functional includes a standard quadratic terminal observation, a Tikhonov regularization term with regularization parameter , and the -norm of the control that accounts for sparsity. The switching structure of the optimal control is discussed for . Under natural assumptions, it is shown that the set of switching points of the optimal control is countable with the final time as only possible accumulation point. The convergence of switching points is investigated for .
Fredi Tröltzsch
Institut für Mathematik
Technische Universität Berlin
D-10623 Berlin, Germany
Daniel Wachsmuth 111Daniel Wachsmuth was partially supported by the German Research Foundation DFG under project grant Wa 3626/1-1.
Institut für Mathematik
Universität Würzburg
D-97974 Würzburg, Germany
1 Introduction
In this paper, we investigate the switching behavior of optimal controls for the following sparse optimal control problem with terminal observation:
[TABLE]
subject to the parabolic initial-boundary value problem
[TABLE]
and to the pointwise control constraints
[TABLE]
Bang-bang and switching properties for the solutions of optimal boundary control problems were extensively discussed in the 70ties. If , then it is well known that the optimal control is of bang-bang type provided that is not attained by the optimal state. This result was discussed in several papers for linear parabolic equations, see [9, 11, 19], cf. also [24]. For the case of the maximum norm as objective functional, the finite bang-bang principle was proved in [10]. Bang-bang principles for nonlinear parabolic equations were discussed in [17, 20].
For but , the switching behavior of optimal controls was investigated in [7, 23]. In particular, the convergence of switching points for was addressed. Numerical examples and numerical methods exploiting the switching structure were presented in [6, 14, 18]. Bang-bang properties for time-optimal parabolic boundary control problems were studied, e.g., in [8, 15, 28, 12, 29]. This list of references on bang-bang principles and switching properties is by no means exhaustive. We also refer to the references of these papers.
The main novelty of our paper is the discussion of the switching structure for sparse optimal controls of parabolic boundary control problems (i.e., for the case ). To our best knowledge, the switching properties of sparse optimal boundary controls for parabolic problems were not yet discussed in the literature. In particular, this refers to the convergence of switching points for the limit . In addition to proving convergence of switching points, we obtain also convergence rates with respect to for the approximation of switching points for .
However, the general bang-bang structure of optimal sparse controls has already been investigated in a sequence of papers on semilinear elliptic control problems. We refer to [2]. Our paper was inspired by these general results.
Assumption 1** (Data).**
In this setting, real numbers , , , , and are fixed. The sign restrictions on and are needed only for some of the structural properties of the optimal control, neither for the existence of optimal controls nor for the necessary optimality conditions. The parameter is the so called sparse parameter.
Moreover, we fix a desired final state function . We require in order to have continuity of the adjoint state up to the boundary. (For the optimality conditions, would suffice.)**
2 Well-posedness of the problem and necessary optimality conditions
2.1 Well-posedness of the problem
The linear initial-boundary value problem (1.1) is well posed. For each function , there exists a unique solution , where denotes the open space-time cylinder. Let us denote the state associated with by . The control-to-state mapping is linear and continuous from to .
Let us introduce the functionals ,
[TABLE]
and ,
[TABLE]
Then the reduced objective functional is given by
[TABLE]
Introducing the set of admissible controls by
[TABLE]
we can re-write the optimal control problem (1.1)–(1.3) in the short form
[TABLE]
The functional is continuous and convex, hence weakly lower semicontinuous. Moreover, the set is weakly compact and non-empty. Therefore, there exists at least one optimal control of the problem (), which will be denoted by to indicate the correspondence to the Tikhonov parameter . By we denote the optimal state associated with . In the case we will drop the index [math] and write and .
If , then is strictly convex and hence in this case the optimal control is unique. Under a natural assumption, we show later that this uniqueness also holds for . In addition, in the case the optimal state is uniquely determined due to the strict convexity of with respect to .
2.2 Fourier expansion for (1.2), Green’s function
For convenience of the reader, we recall some known facts on the representation of the weak solution by a Green’s function . We consider the inhomogeneous initial-boundary value problem
[TABLE]
where , , and are given. We mention also for the case , but later we will concentrate on positive . The weak solution of (2.0) can be represented by a Green’s function as
[TABLE]
where is given by the following Fourier expansions:
[TABLE]
Here, is the monotone increasing sequence of non-negative solutions to the equation
[TABLE]
and
[TABLE]
are normalizing constants. The numbers and are the eigenvalues of the differential operator subject to the homogeneous boundary conditions in (2.0) for and , respectively. For the eigenvalues, we know that . The functions and are associated eigenfunctions, respectively. After normalization by the factors , they form a complete orthonormal system in ; cf. [25].
Notice that, for our case and , the term in the objective functional has the series representation
[TABLE]
3 Necessary optimality conditions
3.1 The variational inequality
It is well known that the derivative of the differentiable functional can be represented in the form
[TABLE]
where is the adjoint state associated with . It is the unique weak solution to the adjoint equation
[TABLE]
Notice that is assumed to be continuous. Moreover, the function is also continuous, because . Therefore, we have and the continuity of the function on .
Theorem 1** (Necessary optimality condition).**
Let be given, and let be optimal for the problem (). Then there exists a function , such that the variational inequality
[TABLE]
is satisfied with the adjoint state .
This result is completely standard for the case , where is smooth, see [13]. If , the associated tools from subdifferential calculus can be found, for instance in [3, Thm. 3.1]. It is fairly obvious how these methods can be transferred to our problem. Therefore, we omit the proof. An equivalent formulation is obtained by replacing the subdifferential in (3.2) by directional derivatives, which is
[TABLE]
By a standard argument, we find that this variational inequality of integral type implies the following pointwise inequality:
[TABLE]
for a.a. . Here, we denote by the directional derivative of the real function at in the direction .
3.2 The case , bang-bang-bang properties
In the case , a detailed discussion of the variational inequality (3.2) leads to nice structural properties of the optimal control . We recall that for the optimal control and the optimal state are denoted by and , respectively.
Associated with , we introduce the following measurable sets
[TABLE]
The pointwise discussion of the variational inequality (3.2) yields the following result.
Lemma 1**.**
For almost all , the following implications hold true:
[TABLE]
Proof.
For a.a. , we have , hence . Therefore (3.2) almost everywhere implies
[TABLE]
On , the discussion is analogous. In , we have a.e. , hence the reduced gradient must vanish here, a.e. on . ∎
This discussion showed how the function depends on the sign of . Another investigation will reveal the switching structure of related to the function . To this end let us define the open sets
[TABLE]
Lemma 2**.**
For almost all , the following implications hold true:
[TABLE]
Proof.
We first prove the claim for . The equation is obtained as follows: We have , hence
[TABLE]
is satisfied a.e. in . Now the variational inequality (3.2) implies a.e. in . The continuity of the function yields that is an open set. The proof for is analogous. The statement of Lemma 1 shows that has measure zero. Hence it holds almost everywhere on . ∎
3.3 Switching points of
The switching behavior of the optimal control depends on the solutions of the two equations
[TABLE]
To estimate their number, we need the following result:
Lemma 3**.**
The function is continuous in . It can be extended to a holomorphic function in the complex half plane .
Proof.
The continuity of the function follows from and . Therefore, the terminal data for are continuous in , hence and the function is continuous. We refer to [1, 16], and [24, Thm. 5.5].
The fact that the function can be extended to a holomorphic function follows from its the Fourier expansion. By the transformation of time , we find from (2.1) and (2.2) that
[TABLE]
where
[TABLE]
The eigenvalues behave asymptotically like , . Therefore, the factor converges very fast to zero as provided that . For , fixed, the convergence of the series (3.7) and of all of its derivatives w.r. to is uniform in . The same holds true for the complex extension
[TABLE]
if . Therefore, the series defines a holomorphic function in the half plane and is obtained as its real part. ∎
Let us re-write the expansion of in the shorter form
[TABLE]
where the numbers
[TABLE]
correspond to the Fourier coefficients of (the exact Fourier coefficients are given by ). The decisive result for the switching behavior of is the following:
Lemma 4**.**
Let be given and assume . Then the equations
[TABLE]
have at most finitely many solutions in .
Therefore, in these equations have at most countably many solutions that may accumulate only at .
Proof.
Let us consider only the first equation,
[TABLE]
Assume to the contrary that it has infinitely many solutions in . Then they must have an accumulation point . By the identity theorem for holomorphic functions, we deduce
[TABLE]
Differentiating this equation, we obtain , hence
[TABLE]
We multiply (3.10) by and get
[TABLE]
Now, we pass to the limit . Since holds for and the series is uniformly convergent, it follows , hence
[TABLE]
and hence = 0. Notice that holds for all . Therefore, the first item in (3.10) is zero. Multiplying (3.10) by and passing to the limit , we find . Repeating this method infinitely many times, it follows for all .
The system of functions is complete in , hence must hold in the sense of . This contradicts the assumption that . ∎
Theorem 2**.**
Suppose . For each , the sets , , and are the union of finitely many open intervals. Consequently, , , and are the union of at most countably many open intervals (the components of , , and ) which can accumulate only at .
Proof.
The continuity of the function yields that is an open set. All components of are bounded by two zeros of the function in or by the numbers [math], . By Lemma 4, the number of solutions to the equation in is finite, hence the number of components of in is finite, too. The statement on the accumulation of components in is an obvious consequence. The claim for and can be proven analogously. ∎
In addition, it follows that the complement of , which is the set of solutions of (3.9), is countable. Hence, the switching conditions of Lemma 2 uniquely define almost everywhere on . This implies that almost everywhere attains values from the discrete set . Moreover, is piecewise constant on for all with discontinuities only located at the solutions of (3.9). These points will be called switching points in the sequel.
Definition 1**.**
All points , where one of the two functions and changes the sign, are said to be switching points of .
Theorem 3** (Bang-Bang-Bang Principle).**
Assume . Then the following switching properties hold true:
- (i)
For each , the number of switching points of in is finite. Therefore, the number of switching points of in is at most countable and switching points can only accumulate at .
Between two subsequent switching points, the optimal control is identically constant and equal to one of the values , or [math]. 2. (ii)
If and , then the number of switching points of is finite and there is a sufficiently small such that, for a.a. ,
[TABLE]
is fulfilled. 3. (iii)
If , then, in a certain neighborhood , the optimal control can switch at most countably many times between and [math]. In the case it can switch at most countably many times between and [math] in . 4. (iv)
Switching-over of between and cannot happen.
Proof.
(i) Switching points can only be boundary points of the sets , , and . Therefore, they must solve one of the two equations (3.9). By Lemma 4, the number of their solutions is at most countable and can accumulate only at . Between switching points, can only attain the values , , and [math], cf. Lemma 2. This proves (i).
(ii) If and , then we are in one of the cases , , or at . In either case, by continuity of the function , these inequalities remain valid for all in a sufficiently small interval .
Now we apply Theorem 1: In the first case, we have and hence in . In the second, we have , hence in , and in the third we obtain analogously that in .
(iii), (iv) If or is satisfied, we cannot exclude an accumulation of switching points at . By the continuity of , these can only be a switchover between and [math] or and [math], respectively. ∎
Theorem 4**.**
If , then the optimal control is unique.
Proof.
Let two optimal controls and be given. Due to strict convexity of , the optimal state is unique, which gives . Thanks to Theorem 3, both controls must be of bang-bang-bang type: Almost everywhere and in open intervals, they admit only the values , or [math]. Since the control problem is convex, every convex combination is an optimal control and bang-bang-bang. This is only possible if holds almost everywhere. ∎
Definition 2**.**
Assume that holds for the solution of (P0). Then the optimal control is has at most countably many switching points. The switching points in solving are denoted by and the ones solving are denoted by , These switching points are ordered such that and holds for all .
3.4 The case
Now we assume and consider the problem (Pν), i.e., the problem
[TABLE]
We recall that is defined as solution of the equation (1.2) associated to .
Again, this problem has an optimal control with associated optimal state . By strict convexity of the functional in (3.13), the optimal control is unique. The associated adjoint state is . The necessary optimality condition is stated in Theorem 1.
By a detailed pointwise discussion of the variational inequality (3.2), the following result is deduced completely analogous to a result of [3, 22] for a class of elliptic equations. We also refer to a later result for a parabolic problem in [4]. In the theorem, the projection function is defined by
[TABLE]
Theorem 5**.**
For almost all , the following equations are fulfilled:
[TABLE]
The relation (3.15) expresses the sparsity of the optimal control, while (3.16) extracts a single element out of the subdifferential of . We skip the proof, because it is completely analogous to the one in [3].
As a simple conclusion Theorem 5 we get that, for , the functions and are continuous on : Indeed, the function is continuous, hence (3.16) yields the continuity of . Inserting this in (3.14), we see the continuity of .
Let us determine the structure of . We might follow the presentation in [5], but for the convenience of the reader we prove the results again in our framework. Inserting (3.16) in (3.14), we find
[TABLE]
Discussing this representation, we find the following result:
Theorem 6**.**
Assume . Then the implications
[TABLE]
hold almost everywhere in .
Proof.
(a) The implication (3.20) follows immediately from (3.15).
(b) Now we show (3.19). Here, the inclusion for is equivalent to
[TABLE]
The left-hand side implies that , hence (3.17) yields
[TABLE]
The last inequality of (3.23) is equivalent with , hence
[TABLE]
i.e., (3.19) is shown. (c) To prove (3.18), we mention that the inclusion is equivalent with
[TABLE]
Again, we arrive at (3.24). However, the inclusion above also yields that and hence from (3.24) we obtain the conclusion of (3.18).
The implications (3.21) and (3.22) can be confirmed in the same way. ∎
This theorem reveals that the solutions of the four equations
[TABLE]
determine the switching behavior of . In other words, can only switch in the zeros of the four functions standing in the left-hand side of (3.25)–(3.28).
Definition 3**.**
Any , where one of the functions in the left-hand side of (3.25)–(3.28) changes its sign, is said to be a switching point of .
Lemma 5**.**
If , then each of the equations (3.25)–(3.28) can have at most countably many solutions that can accumulate only at . Therefore, can have at most countably many switching points that can accumulate only at .
Proof.
The proof is almost identical with that of Lemma 3, since the adjoint state solves the same adjoint equation as , but with terminal value . Therefore, we have
[TABLE]
where . Now we proceed as in the proof of Lemma 3. ∎
Definition 4**.**
The switching points of , i.e., the solutions in of (3.25), (3.26), (3.27), and (3.28), where the associated function changes its sign, are denoted by , and , respectively, for all that may occur.
Since the set of switching points is countable with possible accumulation only at , we can assume that the sequences of switching points are ordered w.r. to , namely holds for all that appear and .
4 Pass to the limit
In this section, we discuss the convergence of controls for . In addition, the convergence of switching points can be shown. First, we discuss the convergence of the sequences , and of optimal quantities for (Pν).
Theorem 7**.**
(i) For , the sequence contains a strongly convergent subsequence in , denoted w.l.o.g. by again, such that , . The control is optimal for (P0). The associated subsequences and converge uniformly in to and , respectively, as .
(ii) If the optimal control of (P0) is unique, then these convergence properties hold for the whole sequences , , and .
Proof.
(i) Since is weakly compact, the existence of a weakly convergent subsequence with weak limit is obvious. Let be optimal for (P0). Then we have
[TABLE]
Passing to the limit, we obtain from (4.1)
[TABLE]
where we used the weak lower semicontinuity of to get the last inequality. Therefore, must also be optimal for (P0).
From optimality of and for (Pν) and (P0), respectively, we get
[TABLE]
This implies
[TABLE]
and hence, dividing by we obtain
[TABLE]
This implies convergence of norms and strong convergence in for . The strongly convergent subsequence in is transformed to a uniformly convergent subsequence , i.e., in . Therefore, we also have in , because the mapping associating the solution of the adjoint equation to the final datum is continuous from to and we have .
(ii) If the optimal control of (P0) is unique, say , then all subsequences of contain a subsequence converging weakly to the same limit . Then the whole sequence converges to . This transfers to the sequences and . ∎
Lemma 6**.**
For each and , there is a constant such that
[TABLE]
holds for all .
Proof.
In , the formally differentiated Fourier series is given by
[TABLE]
It is uniformly convergent, since the series
[TABLE]
with is a convergent majorant. Let be given. Then has an analogous series representation. Hence, we can estimate
[TABLE]
which proves the claim for . The proof can be completed by an induction argument with respect to . ∎
The norm can be estimated with the help of the following result.
Lemma 7**.**
Let be optimal for (P0). Then it holds
[TABLE]
Proof.
This is an immediate consequence of the optimality conditions, see, e.g., [26, Lemma 2.5]. ∎
Combining these two results, we obtain a convergence rate for for the adjoint states.
Lemma 8**.**
Let be optimal for (P0). Then for each and , there is a constant such that
[TABLE]
holds for all .
Proof.
This is consequence of the previous two lemmas and the boundedness of . ∎
Now we are able to prove the convergence of switching points of optimal controls for .
Theorem 8**.**
Assume that is fulfilled. Let be such that , and let be the smallest positive integer such that
[TABLE]
Then there are and with the following properties:
- (i)
For all , each of the equations (3.27) and (3.28) has at most solutions in the interval . The equations (3.25) and (3.26) do not have solutions in . 2. (ii)
Additionally, there is such that
[TABLE]
for all and all solving one of the equations (3.27)–(3.28). 3. (iii)
If is odd, in particular if is a switching point of , then there is such that for all there exist switching points of in the interval that solve one of (3.27)–(3.28).
Analogous results hold for solutions of .
Proof.
Denote . Assume for the moment that holds in (4.2). Take such that and
[TABLE]
as well as
[TABLE]
are satisfied for all with . Thanks to Lemma 6, we have uniform convergence of to in . Therefore, there is such that
[TABLE]
and
[TABLE]
hold for all and with . Hence, the equation can have at most distinct solutions in . Analogously, the equation has at most distinct solutions in . In addition, by in , the equations and do not have solutions in .
Let now be given with . Then, performing a Taylor expansion and invoking the assumption, we find
[TABLE]
with some intermediate point .
Let be an odd integer. Setting and and taking (4.5) into account, yields
[TABLE]
By uniform convergence of the adjoint state, there is such that
[TABLE]
for all . This implies
[TABLE]
By the intermediate value theorem, there is a solution to in . At least one of these solutions is indeed a switching point of , as changes sign in the interval .
Analogously, we can show existence of solutions of . Here, we obtain for making smaller if necessary
[TABLE]
This shows existence of solutions of (3.28) close to for small .
Let now be a solution of (3.27). Then we get
[TABLE]
Since by Lemma 8, we obtain . If is a solution of (3.28) in , then we obtain
[TABLE]
This proves the estimate for all . The inequality (4.4) can be proven by using Lemma 6 instead of Lemma 8 to estimate .
With obvious modifications, the result can be proven if or holds. ∎
Remark 1**.**
- (i)
A finite integer satisfying (4.2) must exist, since the mapping is analytic in . 2. (ii)
For , we immediately obtain the following particular case of Theorem 8: Assume that is a switching point of such that (4.2) is satisfied with . Then for all exactly two switching points and of exist that solve equation (3.27) and (3.28), respectively. We have . An analogous result holds for with points and .
Corollary 1**.**
Under the same conditions as in the previous Theorem 8, for every point with there exists such that
[TABLE]
holds for all , where and are as in Theorem 8. Here we used again the notation .
Proof.
Let be a switching point of . As in the proof of Theorem 8, cf., (4.5) and (4.6), there is and such that for all it holds and
[TABLE]
In addition, we have for almost all in this interval. Define for
[TABLE]
Hence, due to (4.7), there is a constant such that it holds for all .
Let now be given. Take with . This implies and
[TABLE]
On the other hand, take with . As was chosen such that holds on , it follows and
[TABLE]
Invoking (3.4), we conclude
[TABLE]
Setting
[TABLE]
yields
[TABLE]
with . ∎
Theorem 9**.**
Assume that is fulfilled. Furthermore, we require that . Then there are constants , , and such that it holds
[TABLE]
for all .
Proof.
The condition implies that there are finitely many solutions of in . Let be the solutions of in . If , then we add the point to this set. Denote by and the constants given by Theorem 8 associated with the points , . Note that Theorem 8 is also true if is taken, with obvious modifications of the proof. Set , , , .
By continuity, there is such that \big{|}|\bar{\varphi}(1,t)|-\mu\big{|}\geq\sigma for all . Due to uniform convergence , there is such that it holds \big{|}|\varphi_{\nu}(1,t)|-\mu\big{|}\geq\sigma/2>\nu(b-a) for all and . Consequently and coincide on .
The intervals were constructed in Theorem 8 such that holds for all . Due to uniform convergence of the adjoint states, we get for all and for all by making smaller if necessary. Hence, the signs of and coincide on , which implies for all .
In the next step we will invoke Corollary 1. Let be the constant given by Corollary 1 associated to the point . Then we find
[TABLE]
Since and , we obtain with
[TABLE]
Testing the variational inequality (3.3) for with and adding it to the inequality (4.8), we obtain
[TABLE]
Since on and on it holds . Due to the definition of the adjoint equation, it holds
[TABLE]
Combining these facts, we find
[TABLE]
See also [21, Lemma 1.3] and [27, Lemma 3.1] for similar results. By Young’s inequality, we can estimate the right-hand side,
[TABLE]
The last item can be absorbed by the left-hand side. This shows that the convergence rates
[TABLE]
are satisfied for small enough with some constant independent of . Here, we used again that on , which implies . ∎
Remark 2**.**
Let us point out some possible extensions of the previous theorem. First, the assumption can be omitted if we require instead that there are finitely many solutions of in , and that there exists , , and such that it holds
[TABLE]
Then the conclusion of Corollary 1 is valid for the interval , and the proof of Theorem 8 remains valid with minor modifications.
5 Extensions
The results of this paper can be easily extended to the following slightly more general situations:
(i) We considered problems with homogeneous initial condition . All results remain true for the non-homogeneous initial condition with . To see this, we solve the heat equation with homogeneous boundary data and initial condition and denote the solution by . Then so that the results can be proven with .
(ii) For distributed controls of the form that act in the right-hand side of the heat equation with homogeneous boundary conditions, the solution is given by the series representation
[TABLE]
where
[TABLE]
In this way, the Fourier coefficients replace the numbers in (2.3). For proving the switching properties, in (3.11) we used the fact that holds for all . Therefore, an easy inspection of the proofs shows that all results of the paper remain true for distributed controls of the form with fixed , if the condition
[TABLE]
is fulfilled. In other words, the theory remains true for functions where all Fourier coefficients with respect to the system are non-vanishing.
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