
TL;DR
This paper studies the stratification of the Fano scheme of lines on smooth hypersurfaces based on the splitting types of their normal bundles, providing dimension and class computations for general hypersurfaces.
Contribution
It introduces a stratification of lines on hypersurfaces by normal bundle splitting types and computes their classes and dimensions for general cases.
Findings
For general hypersurfaces, the strata have the expected dimension.
The class of the closure of each stratum is computed in the Chow ring.
Upper bounds on the dimension of certain strata are established for all smooth hypersurfaces.
Abstract
Let be a smooth hypersurface. Given a sequence of integers with , let be the parameter space of lines on such that . The loci form a stratification of the Fano scheme of lines on . We show that for general hypersurfaces, the have the expected dimension and, in this case, compute the class of in the Chow ring of the Grassmannian of lines in . For certain splitting types , we also provide non-trivial upper bounds on the dimension of that hold for all smooth .
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Normal bundles of lines on hypersurfaces
Hannah K. Larson
Department of Mathematics, Harvard University, One Oxford Street, Cambridge MA 02138
Abstract.
Let be a smooth hypersurface. Given a sequence of integers with , let be the parameter space of lines on such that . The loci form a stratification of the Fano scheme of lines on . We show that for general hypersurfaces, the have the expected dimension and, in this case, compute the class of in the Chow ring of the Grassmannian of lines in . For certain splitting types , we also provide non-trivial upper bounds on the dimension of that hold for all smooth .
1. Introduction
Let be a smooth hypersurface of degree over the complex numbers. This paper is concerned with the geometry of the Fano scheme parameterizing lines on , defined by
[TABLE]
where is the Grassmannian parameterizing lines in . Let and let be the open subset parameterizing smooth hypersurfaces of degree in . We define the universal Fano scheme to be
[TABLE]
The condition that a hypersurface contain a fixed line is linear conditions on the parameter space , so looking at the projection , one readily sees that is smooth and irreducible of dimension
[TABLE]
This dimension count gives rise to an expected dimension of for the Fano scheme of lines on hypersurface of degree in . It is a well-known result that this expected dimension is indeed achieved for general hypersurfaces. A prominent conjecture of Debarre-de Jong states that the expected dimension should be achieved for all smooth hypersurfaces of degree . The Debarre-de Jong Conjecture has been proved for by Beheshti [1] and for by Harris et al. [5].
Here, we study the normal bundles of lines in , which govern the local geometry of at . For each , there is a short exact sequence of normal bundles
[TABLE]
in which the middle term is and the rightmost term is . Since every vector bundle on splits as a direct sum of line bundles, it follows that
[TABLE]
for integers with . To study the behavior of the normal bundle, for each sequence of integers satisfying the above conditions, we define
[TABLE]
and its universal counterpart
[TABLE]
For convenience of notation, we will abbreviate by .
The loci can be realized as the loci where the members of a family of vector bundles on acquire certain splitting types. Let
[TABLE]
be the universal line over and let be the projection map. In addition, let
[TABLE]
be the universal hypersurface over . Then, the vector bundle has the property that for any , the restriction is . It follows that the form a stratification of with
[TABLE]
where the partial ordering is defined by
[TABLE]
See for example Section 14.4.1 of [4]. There is a unique maximal element with respect to this partial ordering, which is determined by the condition for all and . We call this the balanced splitting type and all others unbalanced.
In this scenario of a family of vector bundles on , deformation theory gives rise to an expected codimension for the loci . Suppose is any family of vector bundles on with base , and let be the projection map. For each point there is an analytic neighborhood of and a map from to the deformation space of the vector bundle such that is equal to the pullback of the versal family on the deformation space. The codimension of the locus of points where therefore has codimension at most the dimension of the deformation space of . We call this quantity the expected codimension for the locus where members acquire splitting type and denote it by
[TABLE]
Our main results are the following.
Theorem 1.1**.**
* is smooth and irreducible of codimension in .*
Remark*.*
Although the open strata are smooth, their closures can and will be singular along the more unbalanced splitting types.
Example 1.2**.**
For degree hypersurfaces in , the following diagram indicates which strata lie in the closure of others and the codimension of each strata in . Here, the balanced splitting type is at the far right.
{\overline{\Sigma_{(-3,0,0)}}}$${\overline{\Sigma_{(-5,1,1)}}}$${\overline{\Sigma_{(-4,0,1)}}}$${\overline{\Sigma_{(-3,-1,1)}}}$${\overline{\Sigma_{(-2,-1,0)}}}$${\overline{\Sigma_{(-1,-1,-1)}}}$${\overline{\Sigma_{(-2,-2,1)}}}$${10}$${7}$${5}$${4}$${1}$${0}
Note that the splitting types and cannot specialize to each other, showing that in general the splitting types are not totally ordered.
Theorem 1.3**.**
If then is empty for general . If , then has codimension inside for general . In this case, the class of in the Chow ring of is computed by the formula in Proposition 6.1.
Theorem 1.4**.**
If , then for all smooth hypersurfaces of degree . If , then for all smooth hypersurfaces of degree .
Remark*.*
The questions in this paper could just as well be asked for higher degree rational curves. Recent work of Riedl and Yang [6] shows that when , the locus of rational curves of degree on general hypersurfaces of degree has the “expected codimension” . However, the results of Coskun and Riedl in [3] on normal bundles of rational curves in suggest that the normal bundles of higher degree rational curves on hypersurfaces may be less well behaved.
This paper is organized as follows. In the next section, we put a scheme structure on and explain how to compute the class of for certain splitting types , assuming they have the expected codimension. We also provide explicit local equations for and describe its functor of points. In Section 3, we prove Theorem 1.1. We then describe the tangent space to and prove Theorem 1.3 in Section 4. In Section 5, we study singularities on when is a cubic threefold and give an important example of the scheme structure of for the Fermat quartic threefold. In Section 6, we find the class of and compute the number of lines with unbalanced normal bundle on a general quintic fourfold as an example. Finally, in Section 7, we prove Theorem 1.4.
Acknowledgements.
First and foremost, I would like to thank Professor Joe Harris for all of his encouragement and advice, and meeting with me weekly to discuss ideas. I am also grateful to the 2017 Harvard Program for Research in Science and Engineering (PRISE) and the Herchel Smith Fellowship for their support last summer, when I began working on this project. Finally, thanks to James Hotchkiss for many helpful conversations about this topic and algebraic geometry in general.
2. The scheme
Here, we give the structure of a scheme by realizing it as an intersection of loci where certain maps of vector bundles drop rank. We work on the closure of the universal Fano scheme
[TABLE]
and introduce incidence correspondences
[TABLE]
and
[TABLE]
which are just the closures in of the varieties defined earlier with the same letters. Next, we set
[TABLE]
so that we have a short exact sequence of sheaves on ,
[TABLE]
Note that and are vector bundles, but since is singular, is not. Let be the universal quotient bundle on . Labeling the relevant projections
[TABLE]
one readily identifies the vector bundles and as
[TABLE]
For each , tensoring (2.1) with gives rise to a new short exact sequence
[TABLE]
Applying pushforward by to the above sequence (2.3), we obtain an exact sequence of sheaves on ,
[TABLE]
Since
[TABLE]
and
[TABLE]
are constant as vary over , the theorem on cohomology and base change tells us that and are vector bundles on . Indeed, using the push-pull formula for vector bundles and denoting by the dual of the universal subbundle on , we identify
[TABLE]
Given any map of vector bundles on some base , let denote the subscheme of where has rank at most , defined by the minors of . Furthermore, let be the locally closed subscheme where has rank exactly . For each and , looking at (2.3), we see that the locus where has rank exactly is
[TABLE]
Meanwhile, given a splitting type , the locus can be described as
[TABLE]
where
[TABLE]
Thus, we can give the structure of a scheme by taking an appropriate intersection of schemes . For convenience, let
[TABLE]
Definition 2.1**.**
We define the scheme as
[TABLE]
The loci then inherit a scheme structure as the fibers of under projection to the parameterizing hypersurfaces of our given degree and dimension.
Example 2.2** (Cubic hypersurfaces).**
There are only two splitting types for the normal bundle of a line on a cubic hypersurface: either
[TABLE]
Let denote the unbalanced splitting type and the balanced splitting type. We have
[TABLE]
Since for all , the locus is all of for these . Therefore, the only non-trivial term in the intersection (2.7) comes from when , giving
[TABLE]
2.1. The class of certain
As seen in the previous example, sometimes is equal to for some and . In this case, assuming has the correct codimension, Porteous’ formula will give rise to a formula for the class of in the Chow ring of .
To set up this formula we need some notation. Given an element of the Chow ring of a projective scheme , let be the component of in degree . Then, given any and natural numbers and , let
[TABLE]
In general, Porteous’ formula says that if is any map of vector bundles of ranks and on and the scheme has codimension in , then the class of in the Chow ring of is
[TABLE]
where and are the total Chern classes of and .
The for which we will calculate the class of have the form
[TABLE]
The closure of such in consists of pairs where has at least copies of in it, whose closure in is exactly In addition, for such , we always have
[TABLE]
where . Applying Porteous’ formula, we immediately arrive at the following.
Proposition 2.3**.**
Suppose has the form (2.9), and set . If has the expected codimension in , then its class in the Chow ring of is given by
[TABLE]
Remark*.*
Given that each has the “expected codimension”, it is natural to wonder if a similar formula can be found for all . One obstacle to following the same approach as above is that for , the loci pick up components of larger dimension. For example, when and , so that the rank of the normal bundle is and its degree is , we have
[TABLE]
To use Proposition 2.3 in practice, we need to describe the Chow ring of and find the Chern classes of and . This is easily done since is a projective bundle over and the vector bundles and are tensor products of vector bundles with known Chern classes, and hence their Chern classes are determined by the splitting principle.
2.2. Explicit local equations
For each line , we can choose coordinates on so that and affine coordinates on where
[TABLE]
Over the product of this affine open with , the map in (2.1) is given by homogeneous polynomials of degree ,
[TABLE]
where the are bihomogeneous polynomials in the and the coefficients of , which are our coordinates on .
Over this open subset, the vector bundle is naturally identified with the trivial bundle with fiber and similarly is naturally identified with . In terms of the standard basis of monomials on each copy of and , the map is represented by the matrix
[TABLE]
The local equations for are exactly the minors of this matrix. The collection of all these minors as runs from to are thus local equations for .
Example 2.4** ().**
We have , which is defined by the single equation
[TABLE]
Since this equation is non-zero, this provides a direct proof that has codimension , which is the expected codimension for this locus.
2.3. The functor of points
As one might hope, has a nice description in terms of its functor of points. Given any morphism , one obtains a diagram
[TABLE]
where is a family of vector bundles on with base . We say that such a family has constant local splitting type if can be covered by open sets over which and
[TABLE]
where is the projection map. With this notion, we have the following.
Lemma 2.5**.**
Let as before. Then
[TABLE]
Proof.
First we check that the restriction of to has constant local splitting type . For each , let be an open set containing over which can be trivialized, i.e.
[TABLE]
By the theorem on cohomology and base change, is a vector bundle on . After passing to a possibly smaller open set , we can assume that
[TABLE]
can be trivialized for all . An inclusion of into the vector bundle is specified by a collection of polynomials of degree in with coefficients rational functions on that do not simultaneously vanish, i.e. a non-zero section of
[TABLE]
Such a section will define an inclusion of into exactly when the section lies in the kernel of .
Now let be the number of ’s in the list . Suppose we have a local frame of the kernel of ,
[TABLE]
We observe that the elements
[TABLE]
are in the kernel of . Since has rank , we can find another independent sections of in the kernel of . These sections define an inclusion which is independent from our previous inclusion of .
Continuing in this way, the conditions on the rank of guarantee that we can find sections in its kernel that define inclusions of independent from those defined before for lower . Hence, the restriction of to has constant local splitting type .
It remains to show that if is such that has constant local splitting type then factors through . If the restriction of to some is , then the minors of vanish. But this is given locally by applied to the minors of , where is the map of structure sheaves. Thus, kills the ideal of , which is to say factors through the subscheme . ∎
3. Proof of Theorem 1.1
In this section, we prove Theorem 1.1, providing two proofs of the dimension statement. The first uses a standard dimension-counting argument with an incidence correspondence and also proves smoothness and irreducibility. The second uses deformation theory to obtain the dimension statement directly. Recall the statement of the theorem.
Theorem 3.1**.**
* is smooth and irreducible of codimension in .*
Proof.
First note that, like the universal Fano scheme, the projection onto the second factor is a fiber bundle. Thus, to prove the theorem, it will suffice to prove that the fibers of are smooth and irreducible of codimension in the fibers of the projection of the universal Fano scheme onto its second factor, .
So, fix a line and let
[TABLE]
where is the open subset parameterizing smooth hypersurfaces. First consider the projection . The image of is exactly , and makes into a fiber bundle over its image with smooth fibers isomorphic to . Irreducibility and smoothness of will thus follow from the same properties of .
Next, we construct a map by setting to be the composition
[TABLE]
The image of is certainly contained in the open subset of injective maps, and we claim that all injective maps are in the image. Indeed, given any
{0}$${\mathcal{O}(\vec{a})}$${\mathcal{O}(1)^{n-1},}$$\scriptstyle{A}
the cokernel is a line bundle of degree , so we have a short exact sequence
[TABLE]
Explicitly, if we think of as being represented by an matrix with polynomials of degree in the th column, then the are the maximal minors of . We claim that
[TABLE]
If is any hypersurface containing , then we have a short exact sequence
[TABLE]
where . So for to be in , we must have , and hence has the claimed form. On the other hand, whenever has this form, the right hand maps in (3.1) and (3.3) are equal, so by the universal property of kernel there exists a unique isomorphism of their kernels such that , implying .
Next, observe that the have no common zeros, so every of the form in (3.2) is smooth along . Thus, Bertini’s theorem tells us that the general such is smooth. That is, is an open dense subset of this linear system. In particular, is smooth and irreducible of dimension
[TABLE]
Our assumption that for all guarantees that the image , which is equal to the injective maps, is an open dense subset of . It follows that is smooth and irreducible of dimension
[TABLE]
Finally, since the fibers of are copies of , we have
[TABLE]
Hence,
[TABLE]
Next, observe that
[TABLE]
After substituting this in above, applying to the short exact sequence
{0}$${\mathcal{O}(\vec{a})}$${\mathcal{O}_{L}(1)^{n-1}}$${\mathcal{O}(d)}$${0,}
and setting the alternating sum of the dimension of terms in the long exact sequence in cohomology to zero, we see that
[TABLE]
as desired. ∎
Given that has the expected codimension coming from deformation theory, one might wonder if there is a direct proof of this fact using deformation theory. This can be carried out as follows.
Alternative proof of dimension count.
For each point , there exists an analytic neighborhood of and a map so that
[TABLE]
where is the miniversal family. The claim will follow from showing that the differential of is surjective at . To do this, we construct a set containing which lifts an open neighborhood of the distinguished point .
Consider the projections
{\mathcal{F}}$${\Delta\times\mathbb{P}^{1}}$${\Delta}$${\mathbb{P}^{1}.}$$\scriptstyle{\alpha}$$\scriptstyle{\beta}
First, we will show that there exists a neighborhood of so that admits an inclusion into the trivial family . This is equivalent to finding a local section of which is corresponds to an injective map on each fiber. Since each subbline bundle of for has degree at most , we have
[TABLE]
which is constant as varies over . Hence, the theorem on cohomology and base change tells us that is a vector bundle. Let be the inclusion
[TABLE]
Since the rank of a family of maps drops on closed subsets, we can find a local section of which is over the origin and injective on each fiber for in some neighborhood .
This gives rise to a short exact sequence
[TABLE]
where is a line bundle that restricts to on each fiber of . For each , the map restricted to is given by a collection of homogeneous polynomials of degree . Fixing coordinates so that if is the defining equation of , then
[TABLE]
Next, let
[TABLE]
and consider the polynoimals
[TABLE]
Note that all of the vanish on and we have which is smooth. Since singular hypersurfaces are a closed subset, after restricting to a possibly smaller neighborhood , we will have smooth for all . In particular, the collection of hypersurfaces defined by for is a slice around that maps one-to-one onto . ∎
4. The dimension of in general
In this section, we determine the dimension of for general . It follows immediately from Theorem 1.1 that if , then is empty for general . On the other hand, if , then provided dominates , it follows that for general . Moreover, by upper semicontinuity of the dimension of fibers of , to prove this holds, it suffices to find some such that . In the following, we give an explicit description of the tangent space to , and then exhibit such an .
Let be the incidence correspondence
[TABLE]
and let . Every in gives rise to a diagram
[TABLE]
where is a first order deformation of the vector bundle . Given such an , let be the projection map onto the second factor.
Lemma 4.1**.**
The tangent vector in is in the subspace if and only if the associated first order deformation of is trivial, meaning
[TABLE]
Proof.
Restricting our description of the functor of points for to the fiber of over , we see that
[TABLE]
Since has only one open set, having constant local splitting type is the same as splitting as above. Thus, is the claimed subspace of . ∎
Using the inclusion , We can represent every by a collection of linear forms where . Such a collection corresponds to the first order deformation
[TABLE]
Equivalently, if are affine coordinates on the Grassmannian around the line , i.e.
[TABLE]
this corresponds to the morphism determined by the map of rings
[TABLE]
Given , we have seen that the splitting type of is determined by the polynomials
[TABLE]
We will now see that if has splitting type , then the tangent space to at is in turn determined by the and the higher derivatives
[TABLE]
As always, choose coordinates so that . We can write
[TABLE]
If , then pulling back the short exact sequence
{0}$${N_{P/X\times F(X)}}$${N_{P/\mathbb{P}^{n}\times F(X)}}$${N_{X\times F(X)/\mathbb{P}^{n}\times F(X)}|_{P}}$${0}
to , we see that fits into a short exact sequence
{0}$${\mathcal{E}_{v}}$${\beta^{*}\mathcal{O}(1)^{n-1}}$${\beta^{*}\mathcal{O}(d)}$${0}
where the map on the right is given by the collection of polynomials
[TABLE]
The deformation will be trivial — i.e. a direct sum of — if and only if the satisfy the same syzygies as the , now with coefficients in . To make this precise, suppose that the maps in the normal bundle sequence at our line are given explicitly by
[TABLE]
where the are homogenous polynomials of degree degree in and which necessarily satisfy . Then for to lie in , there must exist of degree such that
[TABLE]
Equivalently, this shows the following.
Lemma 4.2**.**
A tangent vector is in the subspace if and only if for each ,
[TABLE]
This appears to be a somewhat complicated condition, but with nice choices of the and , the linear conditions in the lemma become clear. We use this strategy to prove the following.
Theorem 4.3**.**
If , then has codimemsion for general .
Proof.
First note that if , then , so we may restrict our attention to lines with
[TABLE]
Since , such a line is always a smooth point of with
[TABLE]
The expected codimemension of lines with this splitting type is , so we can assume . To prove the theorem, it suffices to find with this normal bundle where has codimension at least . Then upper semicontinuity of dimension of fibers together with Theorem 3.1 will imply that for general .
Now, consider the map
[TABLE]
given by
[TABLE]
The map to the cokernel of this inclusion is given by the maximal minors of . If is with the th row deleted, then we have
[TABLE]
Since the have no common zeroes, we can apply Bertini’s theorem to find some smooth hypersurface containing such that are the partial derivatives of restricted to . For , we have , so the condition (4.2) that becomes that the coefficient of in
[TABLE]
must vanish for odd . The general form of an element
[TABLE]
is
[TABLE]
If we can find a smooth with appropriate , then setting the coefficient of in (4.3) to zero will give an independent linear condition on the coordinates and for each of the possible values of and possible values of , showing that . Suppose that
[TABLE]
Above, if the exponent on a variable is negative, it is understood that we omit that term. With this choice, setting the coefficient of to zero in (4.3) forces each . Similarly, if , setting the coefficient of to zero forces each . Then for the remaining values and each , the only contribution to comes from the
[TABLE]
term of the sum in (4.3), when meets . This gives more conditions . Finally, Bertini’s theorem guarantees that there exists a smooth hypersurface with these and , so we are done. ∎
5. Important examples
5.1. Cubic hypersurfaces
As we have seen, there are only two possible splitting types for the normal bundle of a line on a cubic hypersurface : either
[TABLE]
Since for either splitting type, the Fano scheme is always smooth of that dimension. To simplify notation, let be the locus of unbalanced lines. The expected codimension of is .
Specializing our analysis in the previous section gives rise to a concrete description of the tangent space to . Given a line , we can always choose coordinates so that . Looking at our favorite short exact sequence of normal bundles,
[TABLE]
where , we see that
[TABLE]
Given , we can thus choose coordinates so that for all . Next, note that the span of two quadratic polynomials with no common zeros contains exactly two squares. Hence, we can choose coordinates and on so that the two squares in the span of and are and . Finally, after a possible linear change of variables between and , we can write
[TABLE]
With this set up, the tangent space to the Fano scheme is simply
[TABLE]
Then Lemma 4.2 tells us that the condition for to be in the tangent space is that the coefficient of in vanishes for each . Writing and identifying coordinates on as the coefficients and for , we have shown the following.
Lemma 5.1**.**
In our chosen coordinates,
[TABLE]
The codimension of is thus the rank of this matrix.
Because is smooth, Sard’s theorem tells us that is smooth in general. However, for some , the locus may be singular, and we can ask: what sorts of singularities occur? We use the above description of the tangent space to to answer this question for cubic threefolds.
Theorem 5.2**.**
For a smooth cubic hypersurface, is a curve that has at worst nodes as singularities.
Proof.
Suppose and . Then , so after choosing coordinates so that has the form in (5.1), Lemma 5.1 tells us that . Geometrically, this says that the intersection of with the -plane defined by is .
We now use the explicit local equations Example 2.4 to compute the tangent cone to at . Let be local coordinates on as in that section. First, note that the Fano scheme is cut out by polynomials. These polynomials are the coefficients of the polynomial in and that results from plugging for into . With having the form (5.1), the leading terms of these four polynomials are and , so the tangent plane to the Fano scheme is
[TABLE]
Note also that since , the quadratic terms of these four polynomials are in the ideal
The locus is cut out by the equations of together with the determinant of the matrix.
[TABLE]
where are polynomials in defined implicitly by
[TABLE]
We claim that, modulo the ideal , the leading term of is a multiple of . First, observe that and are the only entries that begin with constant terms, the rest being linear or higher order in the . Next, we have
[TABLE]
so the linear terms of the entries in the last column are all in the ideal .
Putting these observations together, we see that the leading term of modulo is mod , which is . Thus, can be generated by five polynomials whose leading terms are , and . The leading term of any polynomial in is therefore in the ideal generated by these leading terms. This shows that the tangent cone to is a union of the two distinct lines and in the tangent plane, so must be a node. ∎
5.2. The Fermat quartic threefold
Although we know that has the expected dimension for general , sometimes has larger dimension for certain .
One illuminating example of this is when is the Fermat quartic threefold. If is a hyperplane defined by for a th root of , then the hyperplane section is a cone over a smooth quartic curve in . We claim that for any line on this cone, we have . After possibly permuting coordinates (which preserves the equation of ), we can assume has the form
[TABLE]
for some with . From this, we see that
[TABLE]
which is two-dimensional. In particular, the right hand map in the sequence
[TABLE]
is given by a collection of three necessarily linearly dependent polynomials, implying includes into its kernel, . It follows by degree considerations that . Because , the family of lines on each of these hyperplane sections corresponds to a nonreduced quartic curve on . Since there are such hyperplanes — corresponding to the choices of two coordinates and choices of — computing the class in the Chow ring of the Grassmannian shows that is exactly the union of these non-reduced curves.
This is important example in that every line on has normal bundle . That is, the underlying sets of and are equal. Nevertheless, and are not equal as schemes. In fact, is the reduced subscheme of , as can be seen from computing the tangent space for general . Suppose has the form in (5.2). Let
[TABLE]
Then , and we can rewrite the defining equation of in these coordinates as
[TABLE]
This tells us that
[TABLE]
The inlcusion can thus be represented by
[TABLE]
so Lemma 4.2 tells us that is determined by the condition
[TABLE]
This is equivalent to
[TABLE]
If and are both non-zero, then plugging in we find
[TABLE]
Thus, for general lines we have , showing that is reduced. On the other hand, if one of or is zero, then because the left-hand side of (5.4) is zero, so the condition is automatically satisfied. These lines correspond points where two components of intersect.
6. The class of
For general , knowing that has the expected codimension in allows us to compute the class of in the Chow ring of . As noted at the beginning of the proof of Theorem 4.3, for general , is only nonempty when
[TABLE]
where and .
Proposition 6.1**.**
Let as above. Then for general , the class of in the Chow ring of the Grassmannian is
[TABLE]
where is defined in (2.8).
Proof.
Restricting the vector bundles and from Section 2.1 to the fibers , we may realize as
[TABLE]
We have
[TABLE]
so if denotes the inclusion of in the Grassmannian, the class of in the Chow ring of is
[TABLE]
Finally, the push-pull formula tells us that the pushforward of this class to the Chow ring of the Grassmannian is given by intersecting with . ∎
Example 6.2** ().**
For general quintic hypersurfaces , we have . The following table lists the possible splitting types for the normal bundle and the expected codimension of lines with that splitting type
[TABLE]
Thus, Theorem 4.3 says that a general contains no lines with splitting type or and finitely many lines with splitting type . So we can ask: how many unbalanced lines are there? Since is smooth, Sard’s theorem tells us that is smooth, and hence reduced, for general . Thus, the answer is the degree of the class given in Proposition 6.1:
[TABLE]
Here, means we need the degree piece of the quotient in the brackets. Writing
[TABLE]
where , we see that the degree part is
[TABLE]
Using the splitting principle, we calculate
[TABLE]
so
[TABLE]
Another application of the splitting principle shows that
[TABLE]
Putting this all together, we find
[TABLE]
That is, there are unbalanced lines on a general quintic fourfold.
7. Dimension bounds for certain
In Section 5, we determined the dimension of for general . In this section, we give upper bounds on the dimension of lines with two particular splitting types which are valid for all smooth hypersurfaces.
7.1. Completely unbalanced lines
There is a unique splitting type which is the “most unbalanced” allowed by the conditions and , namely . For a given degree , let denote the locus of lines with this splitting type. The expected codimension of lines with this splitting type is , so Theorem 3.1 tells us
[TABLE]
It follows that
[TABLE]
and if , the locus is empty for general . However, for certain , a priori, could be as large as , which is in turn only bounded above by . The following provides an upper bound of half this amount.
Theorem 7.1**.**
If is a smooth hypersurface of degree , then .
Remark*.*
This is proved for cubics in Corollary 7.6 of [2].
Note that for cubics, the lower bound (7.1) then determines the dimension of exactly. Given that for , the lower bound in (7.1) is trivial, one might expect that Theorem 7.1 is far from the truth of what is actually achieved. However, the bound is sharp, as demonstrated by the following proposition.
Proposition 7.2**.**
Let for . Then .
Proof of Theorem 7.1.
Suppose that we have some . Choose coordinates so that and write the defining equation of as
[TABLE]
In the short exact sequence of normal bundles
[TABLE]
each inclusion of defines an independent linear relation of . Hence, the span of is -dimensional. The other partial derivatives and vanish along , so the Gauss map
[TABLE]
sends the line with degree onto a line.
Now consider the incidence correspondence
[TABLE]
Let be projection onto the first factor, and projection onto the last factor. Every point in is a point where the fiber of the Gauss map consists of or more points. Since the Gauss map is generically one-to-one, cannot be all of . Hence,
[TABLE]
Meanwhile, since the Gauss map is finite, the fibers of , which consist of points with the same image under , must be finite. It follows that as well. Finally, our work in the previous paragraph shows that the fibers of are one-dimensional, so we can conclude that . ∎
Proof of Proposition 7.2.
Let and let be the hyperplane defined by where . Then is a cone over the smooth hypersurface . Let be any line passing through the vertex of this cone. Then any line in the tangent plane along to is on to first order. Hence,
[TABLE]
For , the only way that can be greater than or equal to is when has copies (the maximal number) of ’s. Thus, all lines on , which form a family of dimension at least , are in . Hence, , and Theorem 7.1 shows that we have equality. ∎
7.2. Almost completely unbalanced lines
A similar trick involving the Gauss map works to find an upper bound on the dimension of the locus of lines whose normal bundle has the form
[TABLE]
Let denote the locus of such lines. The expected codimension of is
[TABLE]
giving rise to the lower bound on the dimension
[TABLE]
Note that for cubics, and are both forced to be zero and these are the balanced lines. In this case, this lower bound coincides with the dimension of the tangent space , so . For , we have the following upper bound on the dimension.
Theorem 7.3**.**
If , then for all smooth hypersurfaces of degree .
Proof.
Suppose that we have some . Choose coordinates so that and write the defining equation of as
[TABLE]
In the short exact sequence of normal bundles
[TABLE]
each inclusion of defines an independent linear relation of . Hence, the span of is -dimensional. The other partial derivatives and vanish along , so now the Gauss map
[TABLE]
sends the line with degree onto a plane curve. Since the genus of a smooth degree plane curve is for , such a map cannot be an embedding. Hence, there exists some point on where the differential is zero, or two points on that have the same image (or both).
First consider the incidence correspondence
[TABLE]
with projections and . If has , then . The dimension of the locus of points in where the differential of the Gauss map has this rank is at most . We conclude that , and so as well.
Next consider the incidence correspondence
[TABLE]
Because the image of onto the first factor consists of points where fails to be one-to-one, we must have . On the other hand, the fact that the Gauss map is finite guarantees that the fibers are finite, so , and hence .
The fact that is not an embedding for any tells us that . In particular, we have
[TABLE]
which is the desired result. ∎
The reference list from the paper itself. Each links out to its DOI / PubMed record.
- 1[1] R. Beheshti, Lines on projective hypersurfaces , J. Riene Angew. Math. 592 (2006), 1–21.
- 2[2] C. H. Clemens, P. A. Griffiths, The intermediate Jacobian of the cubic threefold , Ann. of Math. Second Series, 95 :2 (1972), 281–356.
- 3[3] I. Coskun and E. Riedl, Normal bundles of rational curves in projective space , ar Xiv:1607.06149
- 4[4] D. Eisenbud and J. Harris, 3264 & All That Intersection Theory , Cambridge University Press, 2016.
- 5[5] J. Harris, B. Mazur, R. Pandharipande, Hypersurfaces of low degree , Duke Math. J. 95 :1 (1998), 125-160.
- 6[6] E. Riedl and D. Yang, Kontsevich spaces of rational curves on Fano hypersurfaces , 2014, ar Xiv:1409.3802
