This paper establishes the existence and comparison theorems for reflected backward doubly stochastic differential equations with Poisson jumps, including solutions with continuous barriers and linear growth conditions.
Contribution
It introduces new existence results and a comparison theorem for RBDSDEPs with Poisson jumps, expanding the theoretical understanding of these stochastic equations.
Findings
01
Existence of solutions for RBDSDEPs with continuous barriers.
02
Comparison theorem for minimal and maximal solutions.
03
Solutions under linear growth and left continuity conditions.
Abstract
In this paper{\}we prove the existence of a solution for reflected backward doubly stochastic differential equations with poisson jumps (RBDSDEPs) with one continuous barrier where the generator is continuous and also we study the RBDSDEPs with a linear growth condition and left continuity in y on the generator. By a comparison theorem established here for this type of equation we provide a minimal or a maximal solution to RBDSDEPs.
No public reviews on file for this paper yet. If you reviewed it on a platform where reviews are public (OpenReview, ICLR, NeurIPS, ICML), you can paste yours below so the community can read it here.
Videos
No videos yet. Explain this paper in a talk, walkthrough, or lecture? Add one.
Taxonomy
TopicsStochastic processes and financial applications · Stability and Controllability of Differential Equations · Mathematical Biology Tumor Growth
Abstract. In this paper we prove the existence of a
solution for reflected backward doubly stochastic differential equations
with poisson jumps (RBDSDEPs) with one continuous barrier where the
generator is continuous and also we study the RBDSDEPs with a linear growth
condition and left continuity in y on the generator. By a comparison
theorem established here for this type of equation we provide a minimal or a
maximal solution to RBDSDEPs.
A new kind of backward stochastic differential equations was
introduced by Pardoux and Peng [11] in 1994, which is a class of
backward doubly stochastic
differential equations (BDSDEs for short)
[TABLE]
where ξ is a random variable termed the terminal condition, f:Ω×[0,T]×R×Rd→R, g:Ω×[0,T]×R×Rd→R are two jointly measurable processes, W and B are two mutually
independent standard Brownian motion, with values, respectively in Rd and R. Several authors interested in weakening this assumption see Bahlali et al [3], Boufoussi et al. [5], Lin. Q
[8] and [9], N’zi el al. [10], Shi et al. [12], Wu et al.
[14], Zhu et al. [16]. A class of backward doubly
stochastic differential equations with jumps was study by Sun el al. [13], Zhu et al. [15] They have proved the existence and
uniqueness of solutions for this type of BDSDEs under uniformly Lipschitz
conditions.
In addition, Bahlali et al [2] prove the existence and uniqueness of
solutions to reflected backward doubly stochastic differential equations
(RBDSDEs) with one continuous barrier and uniformly Lipschitz coefficients.
The existence of a maximal and a minimal solution for RBDSDEs with
continuous generator is also established.
In this paper, we study the now well-know reflected backward doubly
stochastic differential equations with jumps (RBDSDEPs for short):
[TABLE]
where Λs=(Ys,Zs,Us).
Motivated by the above results and by the result introduced by Fan. X, Ren.
Y [6] and Zhu, Q., Shi, Y [15, 16], we establish firstly the existence of
the solution of the reflected BDSDE with Poisson jumps (RBDSDEP in short)
under the continuous coefficient, also we prove the existence solution of a
RBDSDEP where the coefficient f satisfy a linear growth and left
continuity in y conditions on the generator of this type of equation.
The organization of the paper is as follows. In Section 2, we give some
preliminaires and we consider the spaces of processus also we define the Itô’s formula. In Section 3, we proof a comparison theorem, section 4 under a
continuous conditions on f we obtain the existence of a minimal solution
of RBDSDEP, and finally in section 5, we study RBDSDEP where the generator f satisfied a left
continuity in y and linear growth conditions.
2 Notation, assumptation and definition.
Let (Ω,F,P) be a complete
probability space. For T>0, We suppose that (Ft)t≥0 is generated by the following
three mutually independent processes:
(i) Let {Wt,0≤t≤T} and {Bt,0≤t≤T} be two standard Brownian motion defined on (Ω,F,P) with values in Rd and
R, respectively.
(ii) Let random Poisson measure μ on E×R+ with compensator ν(dt,de)=λ(de)dt, where the space E=R−{0} is equipped with its Borel field E
such that {μ~([0,t]×A)=(μ−ν)([0,t]×A)} is a martingale for any A∈E
satisfying λ(A)<∞. λ is a
σ finite measure on E and satisfies
∫E(1∧∣e∣2)λ(de)<∞.
Let FtW:=σ(Ws;0≤s≤t),
Ftμ:=σ(μs;0≤s≤t) and Ft,TB:=σ(Bs−Bt;t≤s≤T),
completed with P-null
sets. We put, Ft:=FtW∨Ft,TB∨Ftμ. It should be noted that (Ft) is not an increasing family of sub σ−fields, and hence it is not a filtration.
For d∈N∗,∣⋅∣ stands for the Euclidian norm in Rd×[0,T].
We consider the following spaces of processus:
•
We denote by S2(0,T,Rd), the set of continuous Ft−measurable processes {φt;t∈[0,T]}, which satisfy E(sup0≤t≤T∣φt∣2)<∞.
•
Let M2(0,T,Rd) denote the set of d− dimensional, Ft−measurable processes {φt;t∈[0,T]}, such that E∫0T∣φt∣2dt<∞.
•
A2 set of continuous, increasing, Ft−measurable process K:[0,T]×Ω→[0,+∞( with K0=0,E(KT)2<+∞.
•
L2 set of FT- measurable
random variables ξ:Ω→R with E∣ξ∣2<+∞.
•
We denote by L2(0,T,μ~,Rd), the space of mappings U:Ω×[0,T]×E→Rd which are P⊗E measurable such that
[TABLE]
where P⊗E denoted the σ−algebra of Ft−predectable sets of Ω×[0,T] and
[TABLE]
•
Notice also the space D2(R)=S2(0,T,R)×M2(0,T,Rd)×L2(0,T,μ~,R)×A2 endowed with the norm
[TABLE]
is a Banach space.
Definition 2.1**.**
A solution of a reflected BDSDEPs is a quadruple of processes
(Y,Z,K,U) wich satisfies
[TABLE]
We give the following assumptions (H) on the data (ξ,f,g,S):
(H.1) f:[0,T]×Ω×R×Rd×L2(0,T,μ~,R)→R;g:[0,T]×Ω×R×Rd×L2(0,T,μ~,R)→R be jointly measurable such that for any (y,z,u)∈R×Rd×L2(0,T,μ~,R)
[TABLE]
**(H.2) **There exist constant C>0
and a constant 0<α<1 such that for every (ω,t)∈Ω×[0,T] and (y,y′)∈R2,(z,z′)∈(Rd)2,(u,u′)∈(L2(0,T,μ~,R))2
[TABLE]
(H.3) The terminal valueξ be a
given random variable in L2.
(H.4) (St)t≥0, is a
continuous progressively measurable real valued process satisfying
[TABLE]
(H.5) ST≤ξ, P-almost
surely.
Theorem 2.1**.**
[6]
Assume that (H.1)−(H.5)
holds. Then Eq (1.1) admits a unique solution (Y,Z,U,K)∈D2(R).
The result depends on the following extension of the well-krown Itô’s
formula. Its proof follows the same way as lemma 1.3 of [11]
Lemma 2.1**.**
Let α∈S2(0,T,Rk),(β,γ)∈(M2(Rk))2,η∈M2(Rk×d) and σ∈L2(0,T,μ~,Rk) such that:
[TABLE]
then (i)
[TABLE]
(ii)
[TABLE]
3 Comparison theorem.
Given two parameters (ξ1,f1,g,T)
and (ξ2,f2,g,T), we considere the reflected BDSDEPs, i=1,2
[TABLE]
Theorem 3.1**.**
Assume that the reflected BDSDEP associated with dates (ξ1,f1,g,T),(resp(ξ2,f2,g,T)) has a solution (Yt1,Zt1,Kt1,Ut1)t∈[0,T)],(resp(Yt2,Zt2,Kt2,Ut2)t∈[0,T]). Each
one satisfying the assumption (H), assume moreover that:
[TABLE]
Then we have P−a.s.,
[TABLE]
**Proof: **Let us show that (Yt1−Yt2)+=0, using the equation (3.1), we get
[TABLE]
where ξˉ=ξ1−ξ2,Zˉ=Z1−Z2 and
Uˉ=U1−U2.
Since ∫tT(Yˉs)+(g(s,Ys1,Zs1,Us1)−g(s,Ys2,Zs2,Us2))dBs and ∫tT(Yˉs)+ZˉsdWs are a uniformly integrable martingale then taking expectation,
we get by applying Lemma 2.1
[TABLE]
Since
[TABLE]
we get
[TABLE]
we obtain, by hypothesis (H.2), and Young’s inequality the
following inequality
[TABLE]
also we applying the assumption (H.2) for g, we get
[TABLE]
Then, we have the following inequality
[TABLE]
choosing ϵ such that
0<ϵ−1+α≤1, we have
[TABLE]
using Gronwall’s lemma implies that
[TABLE]
finally, we have
[TABLE]
4 Reflected BDSDEPs with continuous coefficient.
In this section we are interested in weakening the conditions on f.
We assume that f and g satisfy the following assumptions:
**(H.6) **There exists 0<α<1 and C>0s.t. for
all (t,ω,y,z,u)∈[0,T]×Ω×R×Rd×L2(E,E,λ,R),
[TABLE]
**(H.7) **For fixed ω and t, f(t,ω,⋅,⋅,⋅) is continuous.
The theree next Lemmas will be useful in the sequel.
we recall the following classical lemma. It can be
proved by adapting the proof given in J. J. Alibert and K. Bahlali [1].
Lemma 4.1**.**
Let f:Ω×[0,T]×R×Rd×L2(E,E,λ,R)→R be a mesurable function such that:
For a.s. every (t,ω)∈[0,T]×Ω,f(t,ω,y,z,u) is a continuous.
2. 2.
There exists a constant C>0 such that for every (t,ω,y,z,u)∈[0,T]×Ω×R×Rd×L2(E,E,λ,R),∣f(t,ω,y,z,u)∣≤C(1+∣y∣+∣z∣+∣u∣).
Then exists the sequence of fonction fn
[TABLE]
is well defined for each n≥C, and it satisfies, dP×dt−a.s.
(i)* Linear growth: ∀n≥1,(y,z,u)∈R×Rd×L2, ∣fn(t,ω,y,z,u)∣≤C(1+∣y∣+∣z∣+∣u∣).*
(ii)* Monotonicity in n:∀y,z,u,fn(t,ω,y,z,u) is increases in n.*
(iii)* Convergence: ∀(t,ω,y,z,u)∈[0,T]×Ω×B2(R), if (t,ω,yn,zn,un)→(t,ω,y,z,u), then fn(t,ω,yn,zn,un)→f(t,ω,y,z,u).*
(iv)* Lipschitz condition: ∀n≥1,(t,ω)∈[0,T]×Ω,∀(y,z,u)∈B2(R) and (y′,z′,u′)∈B2(R), we have*
[TABLE]
Now given ξ∈L2, n∈N, we consider (Yn,Zn,Kn,Un) and (resp (V,N,K,M)) be solutions of the following reflected BDSDEPs:
[TABLE]
respectively
[TABLE]
where H(s,ω,V,N,M)=C(1+∣V∣+∣N∣+∣M∣).
Lemma 4.2**.**
(i)* a.s. for all, t and ∀n≤m,Ytn≤Ytm≤Vt.*
(ii)* Assume that (H.1),(H.3)−(H.7) is in force. Then there exists a constant A>0
depending only on C,α,ξ and T such that:*
[TABLE]
Proof: The prove of the(i)
follow from comparison theorem. It remains to prove (ii), by
lemma 2.1, we have
[TABLE]
By (i) in lemma 4.1, we have
[TABLE]
also by the hypothesis associated with g, we get
[TABLE]
Chossing γ1=γ2=2ϵ2. Then, we obtain
the following inequality
[TABLE]
Consequently, we have
[TABLE]
where
Λ=E∣ξ∣2+TC2+ϵ1+ϵE∫tT∣∣g(s,0,0,0)∣∣2ds+θ1E(sup0≤s≤T(Ss)2)+T(1+2C+ϵ24C2+(1+ϵ)C)E(supt∣Ytn∣2). Now chossing ϵ and α such that 0≤2ϵ2+(1+ϵ)α<1, we obtain
[TABLE]
On the other hand, we have from Eq.(4.1)
[TABLE]
Using the Hölder’s inequality and assupmtion (H.6), we have
[TABLE]
From inequality (4.2), we get
[TABLE]
Finally chossing θ such that 0≤θC2≤1, we obtain
[TABLE]
The prove of lemma 4.2 is complet.
Lemma 4.3**.**
Assume that (H.1),(H.3)−(H.7) is in force. Then the sequence (Zn,Un)
converges a.s. in M2(0,T,Rd)×L2(0,T,μ~,R).
**Proof: **Let n0≥C. From Eq.(4.1),
we deduce that there exists a process Y∈S2(0,T,R) such that Yn→Y a.s., as n→∞.
Applying Lemma 2.1 to ∣Ytn−Ytm∣2, for n,m≥n0
[TABLE]
Since ∫tT(Ysn−Ysm)(dKsn−dKsm)≤0, we deduce that
[TABLE]
Using Hölder’s inequality and assumption (H.6) for g, we
deduce that
[TABLE]
Applying assumption (H.6) for f and the boundedness of the
sequence (Yn,Zn,Un), we deduce that
[TABLE]
where the constant Cte>0 depend only ξ,C,α and T.
Which yields that (Zn)n≥0 respectively (Un)n≥0 is a Cauchy sequence in M2(0,T,Rd), respectively in L2(0,T,μ~,R). Then there exists (Z,U)∈M2(0,T,Rd)×L2(0,T,μ~,R) such that
[TABLE]
Theorem 4.1**.**
Assume that (H.1),(H.3)−(H.7) holds. Then Eq (1.1) admits a solution (Y,Z,U,K)∈D2(R). Moreover there is a minimal solution (Y∗,Z∗,U∗) of RBDSDEP (1.1) in the sense that for
any other solution (Y,Z,U) of Eq. (1.1), we
have Y∗≤Y.
Proof :
From Eq.(4.1), it’s readily seen that (Yn)
converges in S2(0,T,R), dt⊗dP−a.s. to Y∈S2(0,T,R). Otherwise thanks to Lemma 4.3 there exists two
subsequences still
noted as the whole sequence (Zn)n≥0 respectively (Un)n≥0 such that
[TABLE]
Applying Lemma 4.1, we have fn(t,Yn,Zn,Un)→f(t,Y,Z,U) and the linear growth of fn implies
[TABLE]
Thus by Lebesgue’s dominated convergence theorem, we deduce that for almost
all ω and uniformly in t, we have
[TABLE]
We have by (H.6) the following estimation
[TABLE]
using Burkholder-Davis-Gundy inequality, we have
[TABLE]
Let the following reflected BDSDEPs with data (ξ,f,g,S)
[TABLE]
By Itô’s formula, we derive that
[TABLE]
Using the fact that E∫tT(Ysn−Y^s)(dKsn−dKs)≤0, we get
[TABLE]
letting n→∞, we have Yt=Y^t,Ut=U^t and Zt=Z^tdP×dt−a.e.
Let (Y∗,Z∗,U∗,K∗) be a
solution of (1.1). Then by Theorem 3.1, we have for
any n∈N∗, Yn≤Y∗. Therefore, Y is a minimal solution of (1.1).
5 RBDSDEPs with discontinuous coefficient.
In this section we are interested in weakening the conditions on f.
We assume that f satisfy the following assumptions:
**(H.8) **There exists a nonnegative process ft∈M2(0,T,R) and constant C>0, such that
[TABLE]
(H.9) f(t,⋅,z,u):R→R is a left continuous and ** f(t,y,⋅,⋅)** is
a continuous.
(H.10) There exists a continuous fonctionπ:[0,T]×B2(R) satisfying for y≥y′, (z,u)∈Rd×L2(E,E,λ,R)
[TABLE]
(H.11) g satisfies (H.2,(ii)).
5.1 Existence result.
The two next Lemmas will be useful in the sequel.
Lemma 5.1**.**
Assume that π satisfies (H.10),g
satisfies (H.11) and h belongs in M2(0,T,R). For a continuous processes of finite variation A belong in A2 we consider the processes (Yˉ,Zˉ,Uˉ)∈S2(0,T,R)×M2(0,T,Rd)×L2(0,T,μ~,R) such that:
[TABLE]
Then we have,
(1)* The RBDSDEPs(5.1) admits
a
minimal solution (Yt,Zt,At,Ut)∈D2(R).*
(2)* if h(t)≥0 and ξ≥0, we have Yˉt≥0,dP×dt−a.s.*
Proof: (1) Obtained from a previous part.
(2) Applying lemma 2.1 to Yˉt−2, we
have
[TABLE]
Since h(t)≥0, ξ≥0 and using the fact that ∫0TYˉt−dAs≥0, we obtain
[TABLE]
According to assumptions (H.11), we get
[TABLE]
applying assumption (H.10) and using Young’s inequality, we
have
[TABLE]
Then
[TABLE]
Therefore, choosing ϵ, α and C such that 0<α+2ϵC2<1 and using Gronwall’s inequality, we have
[TABLE]
P−a.s. for all t∈[0,T]. Finally implies that Yˉt≥0,P−a.s. for all t∈[0,T].
Now by theorem (4.1), we consider the processes (Y~t0,Z~t0,K~t0,U~t0),(Yt0,Zt0,Kt0,Ut0) and sequence of processes (Y~tn,Z~tn,K~tn,U~tn)n≥0 respectively minimal solution of the following
RBDSDEPs for all t∈[0,T]
[TABLE]
[TABLE]
and
[TABLE]
Lemma 5.2**.**
Under the assumptions (H.1),(H.3),(H.5)
and (H.8)−(H.11), we have for any n≥1 and t∈[0,T]
[TABLE]
**Proof: **For any n≥0, we set
[TABLE]
Using Eq.(5.4), we have
[TABLE]
where
[TABLE]
According to it definition, on can show that θs0 and
Δgn, ∀n≥0 satisfy all assumption of lemma
5.1. Moreover, since K~tn is a continuous and
increasing process, for all n≥0, δK~sn+1
is a continuous process of finite variation. Using the same argument
as in first part, On can show that
[TABLE]
Applying lemma 5.1 we deduce that δY~tn+1≥0, i.e. Y~tn+1≥Y~tn , for all t∈[0,T], we have Y~tn+1≥Y~tn≥Y~t0.
Now we show prove that Y~tn+1≤Yt0, by
definition, we obtain
Also using lemma 5.1 we deduce that
Yt0−Y~tn+1≥0, i.e. Yt0≥Y~tn+1, for all t∈[0,T].
Thus, we have for all n≥0
[TABLE]
Now, our main result
Theorem 5.1**.**
Under assumption (H.1),(H.3),(H.5) and (H.8)−(H.11), the RBDSDEPs (1.1) has a minimal
solution (Yt,Zt,Kt,Ut)0≤t≤T∈D2(R).
**Proof: **Since Y~tn≤max(Y~t0,Yt0)≤Y~t0+Yt0 for all t∈[0,T], we have
[TABLE]
Therefore, we deduce from the Lebesgue’s dominated convergence theorem that (Y~tn)n≥0 converges in S2(0,T,R) to a limit Y.
On the other hand from (5.4), we deduce that
[TABLE]
applying lemma 2.1, we obtain
[TABLE]
From (H.8) and (H.10), we get
[TABLE]
Also applying (H.11), we obtain the following inequality
[TABLE]
Using Young’s inequality, we get
[TABLE]
Therefore, there exists a constant C independent of n such that for any ϵi, where i=1:4, we derive
[TABLE]
Moreover, since
[TABLE]
Using Hölder’s inequality and assumption (H.8),(H.10), there exists two constants C1 and C2 depend of ξ,C,α,ϵi,i=1,...,4, and we have that
[TABLE]
we come back to inequality (5.5), we obtain
[TABLE]
we taking ϵ1=ϵ2=ϵ0 and ϵ3=ϵ4=ϵˉ, we have
[TABLE]
we chossing ϵˉ,θ and α such that 0≤(ϵˉ+θC2+α)<1, we get
[TABLE]
Now chossing ϵ0,θ and C2 such that ϵ0+θC2<1 and notting E∫0T(Z~s02+∫EU~s02λ(de))ds<∞. We obtain
[TABLE]
consequently, we deduce that
[TABLE]
Now we shall prove that (Z~n,K~n,U~n) is a Cauchy sequence in M2(0,T,Rd)×A2×L2(0,T,μ~,R), set Γsn=f(s,Y~sn−1,Z~sn−1,U~sn−1)+π(s,δY~sn,δZ~sn,δU~sn), we have
[TABLE]
applying Lemma 2.1 to δY~sn,m2=Y~sn−Y~sm2, we have
[TABLE]
since ∫tT(Y~sn+1−Y~sn)(dK~sn−dK~sm)≤0, we obtain
[TABLE]
Applying Hölder’s inequality and assumption (H.11), we deduce
that
[TABLE]
The boundedness of the sequence (Y~n,Z~n,K~n,U~n), we deduce that Λ=supn∈N(E∫0T∣Γsn∣2ds)<∞, this yields that
[TABLE]
Which yields that (Z~n)n≥0 respectively (U~n)n≥0 is a Cauchy sequence in M2(0,T,Rd) respectively in L2(0,T,μ~,R). Then there exists (Z,U)∈M2(0,T,Rd)×L2(0,T,μ~,R) such that,
[TABLE]
On the other hand, applying Burkholder-Davis-Gundy inequality and (5.6), we obtain
[TABLE]
Therefore, from the properieties of (f,π), we have
[TABLE]
P−a.s., for all t∈[0,T] as n→∞. Then
follows by dominated convergence theorem that
[TABLE]
Since (Y~sn,Z~sn,U~sn,Γsn) converges in B2(R)×M2(0,T,R) and
[TABLE]
for any n,m≥0, we deduce that
[TABLE]
as n,m→∞. Consequently, there exists a Ft−measurable process K wich value in R such that
[TABLE]
Finally, we have
[TABLE]
Obviously, K0=0 and {Kt;0≤t≤T} is a increasing
and
continuous process. From (5.4), we have for all n≥0, Y~tn≥St, ∀t∈[0,T], then Yt≥St, ∀t∈[0,T].
On the other hand, from the result of Saisho, we have
[TABLE]
Using the identity ∫0T(Y~sn−Ss)dK~sn=0 for all n≥0, we obtain
∫0T(Ys−Ss)dKs=0. letting
n→+∞ in equation (1.1), we prove
that (Yt,Zt,Kt,Ut)t∈[0,T] is
the solution to (1.1).
Let (Y∗,Z∗,U∗,K∗) be a
solution of (1.1). Then by Theorem 3.1, we have for
any n∈N∗, Yn≤Y∗. Therefore, Y is a minimal solution of (1.1).
Remark 5.1**.**
Using the same arguments and the following approximating sequence
[TABLE]
one can prove that the RBDSDE (1.1) has a maximal solution.
Bibliography16
The reference list from the paper itself. Each links out to its DOI / PubMed record.
1[1] J.J. Alibert, K. Bahlali, Genericity in deterministic and stochastic differential equations. Séminaire de Probabilités XXXV, Lect. Notes. Math. 1755, 220-240, (2001), Springer Verlag, Berlin-Heidelberg.
2[2] K. Bahlali, M. Hassani, B. Mansouri, N. Mrhardy, One barrier reflected backward doubly stochastic differential equations with continuous generator. Comptes Rendus Mathematique, Volume 347, Issue 19, Pages 1201-1206, (2009).
3[3] K. Bahlali, R. Gatt, B. Mansouri, Backward doubly stochastic differential equations with a superlinear growth generator. Comptes Rendus Mathematique, Volume 353, Issue 1, Pages 25-30, January 2015.
4[4] J.M. Bismut, Conjugate convex functions in optimal stochastic control, J. Math. Anal. Appl. 44 (1973) 384–404.
5[5] B. Boufoussi, J. Van Casteren, N. Mrhardy, Generalized backward doubly stochastic differential equations and SPD Es with nonlinear Neumann boundary conditions. Bernoulli 13, no. 2 (2007), 423-446.
6[6] X. Fan, Y. Ren, Reflected Backward Doubly Stochastic Differential Equation with Jumps [J]. Math appl. (wahan), 2009, 22(4): 778-784.
7[7] G. Jia, A class of backward stochastic differential equations with discontinuous coefficients, Statist. Probab. Lett. 78 (2008), 231–237.
8[8] Q. Lin, A generalized existence theorem of backward doubly stochastic differential equations. Acta Mathematica Sinica, English Series, 26(8), 525–1534 (2010).