On distribution of points with conjugate algebraic integer coordinates close to planar curves
V.Bernik, F.G\"otze, A.Gusakova

TL;DR
This paper investigates the distribution of algebraic points with conjugate integer coordinates near planar curves, establishing bounds on their quantity based on degree, height, and approximation parameters.
Contribution
It provides bounds on the number of algebraic points with conjugate integer coordinates close to a given curve, extending understanding of their distribution in the plane.
Findings
Number of such points grows proportionally to Q^{n-γ}
Bounds are independent of Q for large Q
Results apply to functions with continuous derivatives
Abstract
Let be a continuously differentiable function on an interval and let be a point with algebraic conjugate integer coordinates of degree and of height . Denote by the set of points such that . In this paper we show that for a real and any sufficiently large there exist positive values , which are independent of , such that c_2\cdot Q^{n-\gamma}<# \tilde{M}^n_\varphi(Q,\gamma, J)< c_3\cdot Q^{n-\gamma}.
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Taxonomy
TopicsMeromorphic and Entire Functions · Mathematical Approximation and Integration · Analytic and geometric function theory
On distribution of points with conjugate algebraic integer coordinates close to planar curves
V. Bernik, F. Götze, A. Gusakova
Abstract
Let be a continuously differentiable function on an interval and let be a point with algebraic conjugate integer coordinates of degree and of height . Denote by the set of points such that . In this paper we show that for a real and any sufficiently large there exist positive values , which are independent of , such that .
1 Introduction
An important and interesting topic in the theory of Diophantine approximation is the distribution of algebraic numbers and algebraic integers [1, 5, 17, 18]. In this paper we consider problems related to the distribution of points with algebraic conjugate integer coordinates in the plane.
Let us start with some useful notation. Let be a positive integer and be a sufficiently large real number. Given a polynomial denote by the height of the polynomial , and by the degree of the polynomial . We define the following classes of integer polynomials with bounded height and degree:
[TABLE]
[TABLE]
Denote by the cardinality of a finite set and by the Lebesgue measure of a measurable set , . Furthermore, denote by , positive constants independent of . We are going to use the Vinogradov symbol , which means that there exists a constant independent of and such that . We will write when and .
Now let us introduce the concept of an algebraic integer point. A point is called an algebraic point if and are roots of the same irreducible polynomial . If the leading coefficient of polynomial is equal to 1, then a point is called an algebraic integer point. The polynomial is called the minimal polynomial of the point . Denote by the degree of the point and by the height of the point . We denote by (respectively ) the set of algebraic points (respectively integer algebraic points). Furthermore, we define the following sets:
[TABLE]
[TABLE]
The problem of determining the number of integer points in regions and bodies of can be naturally generalized to estimating the number of rational points in domains of Euclidean spaces. Let be a continuously differentiable function defined on a finite open interval . Let us consider the following set:
[TABLE]
where and . Thus, the quantity denotes the number of rational points with bounded denominators lying within a certain neighborhood of the curve parametrized by . The problem is to estimate the value . This question was considered by Huxley [15], Vaughan, Velani [19] and Beresnevich, Dickinson, Velani [13] and with some additional restrictions on the function it was proved that
[TABLE]
This result was obtained using methods of metric number theory introduced by Schmidt in [18].
The following natural extension of this question is the problem of distribution of algebraic points near smooth curves. Let be a continuously differentiable function defined on a finite open interval satisfying the conditions:
[TABLE]
Define the following set:
[TABLE]
where . The goal is to estimate the number . A first attempt to solve this problem for has been made in [14]. This result was complemented by lower bound of the right order for [21] and finally by lower and upper bounds of the same order for [22]. We are going to state the final result in the following form: for any smooth function with conditions (1.1) we have for and .
We will consider the same problem in the case of integer algebraic points. Let
[TABLE]
Theorem 1**.**
For any smooth function with conditions (1.1) there exist positive values such that
[TABLE]
for , , and a sufficiently large constant in definition of the set .
It should be noted that a lower bound of for was obtained earlier [23]. Hence we will assume for the lower bound that .
The proof of Theorem 1 is based on the following idea. We consider the strip and cover it with squares with sides of length , where (the full description of this scheme is given in [22]). Thus, in order to prove Theorem 1 we need to estimate the number of integer algebraic points lying in such a square .
Let us consider here a more general case, namely, the case of a rectangle , where .
Theorem 2**.**
Let be a rectangle with a midpoint and sides , . Then for , and the estimate
[TABLE]
holds, where
[TABLE]
The case of lower bound is more difficult. It is easy to prove that there exist rectangles of size such that , and since we have for such rectangles. It means that we cannot obtain non-zero lower bounds for all rectangles . In particular, it is easy to show that certain neighborhoods of algebraic points of small height and small degree do not contain any other algebraic points at all. In order to avoid such domains we use the concept of a -special square, which has been introduced in [22].
Definition 1**.**
Let be a square with midpoint , and sides such that . We say that the square satisfies the -condition if and there exist at most polynomials of the form satisfying the inequalities
[TABLE]
for some point , where , and
[TABLE]
Definition 2**.**
The square with sides such that is called a -special square if it satisfies the -condition for all .
The following theorem can be proved for -special squares.
Theorem 3**.**
For all -special squares with midpoints , and sides , where and , there exists a value such that
[TABLE]
for and .
2 Auxiliary statements
This section contains several lemmas which will be used to prove Theorems 2 and 3. Some of them are related to geometry of numbers, see [6]. The first paper discussing approximations by algebraic integers are due to Davenport and Schmidt [7]. Recently their approach has been further developed by Bugeaud [3] and we shall use ideas of this paper.
Lemma 1** (Minkowski 2nd theorem on successive minima).**
Let be a bounded central symmetric convex body with successive minima and volume . Then
[TABLE]
For a proof, see [6, pp. 203], [10, pp. 59].
Lemma 2** (Bertrand postulate).**
For any , there exists a prime such that .
It was proved by Chebyshev in 1850. A proof can be found, for example, in [11, Theorem 2.4].
Lemma 3** (Eisenstein’s criterion).**
Let be a polynomial of the form . If there exists a prime number such that:
[TABLE]
then is irreducible over the rational numbers.
For a proof see [8], [16, Theorem 2.1.3].
Lemma 4**.**
Consider a point and a polynomial with zeros where . Then
[TABLE]
Proof.
Evaluate the polynomial and its derivative at the point for . Since
[TABLE]
we obtain
[TABLE]
∎
Lemma 5** (see [12]).**
For any subset of roots , , of the polynomial we have .
Lemma 6** (see [22]).**
Let be a square with midpoint , and sides , where and . Given positive values such that , let be the set of points such that there exists a polynomial satisfying the following system of inequalities:
[TABLE]
where . If is a -special square, then
[TABLE]
for and .
Lemma 7** (see [22]).**
Let , where , be a set of points such that
[TABLE]
Then
[TABLE]
3 Proof of Theorem 2
Assume that . Take an integer algebraic point with minimal polynomial . Let us give an estimate for the polynomial at the points and . Since , we have
[TABLE]
for all and . From these estimates and Taylor expansion of in the intervals , , we obtain the following inequality:
[TABLE]
Let us fix the vector , where are the coefficients of the polynomial . Denote by the subclass of polynomials with the same vector of coefficients such that satisfies (3.1). The number of subclasses is equal to the number of vectors , which for can be estimated as follows:
[TABLE]
It should also be noted that every point of the set corresponds to some polynomial that satisfies (3.1). On the other hand, every polynomial satisfying (3.1) corresponds to at most points of the set . This allows us to write
[TABLE]
Thus, by the estimate (3.3) and Dirichlet’s box principle applied to vectors and polynomials satisfying (3.1), there exists a vector such that
[TABLE]
Let us find an upper bound for the value . To do this, we fix some polynomial and consider the difference between the polynomials and at the points , . From the estimate (3.1) it follows that
[TABLE]
Thus the number of different polynomials does not exceed the number of integer solutions of the following system:
[TABLE]
Now, let us use Lemma 7 for . Since and , we have for . This implies
[TABLE]
It follows that , which contradicts inequality (3.3) for . This leads to
[TABLE]
4 Proof of Theorem 3
Since we can assume that for the following inequality
[TABLE]
is satisfied for every point .
In order to prove the Theorem 3 we use Lemma 6. Given positive constants and satisfying the condition let be the set of points such that the following system of inequalities
[TABLE]
has a solution in polynomials . Lemma 6 implies that the measure of the set can be estimated as
[TABLE]
for and .
Let us consider the set . Using Minkowski’s linear form theorem [18, Ch. 2, §3] for every point there exists a polynomial such that
[TABLE]
Thus, we can assert that for every point there exists an irreducible polynomial such that
[TABLE]
and .
Consider an arbitrary point and let us examine the successive minima of the compact convex set defined by
[TABLE]
Assume that . Then for sufficiently small there exists a polynomial such that the inequalities
[TABLE]
hold. This leads to a contradiction, since . Thus . Since the volume of the compact convex set defined by the inequalities (4.2) is at least , it follows from Lemma 1 that and . Thus, by definition of successive minima, we can choose linearly independent polynomials , , satisfying
[TABLE]
Using well-known estimates from the geometry of numbers, see [6, pp. 219], we obtain for the polynomials , the inequality:
[TABLE]
For a prime not dividing , Lemma 2 yields
[TABLE]
Consider the system of linear equations for the variables
[TABLE]
It should be mentioned that in case the values and are equal, where and are the roots of the polynomial . It means that one of the equations numbered 2 and 3 can be removed.
In order to fined the determinant of this system, we transform it as follows. Multiply the equation numbered as by (respectively by ) and subtract it from the first (respectively the second) equation of the system (4.5). Similarly multiply the equation numbered as by (respectively by ) and subtract it from the third (respectively the fourth) equation. After these transformations the determinant of the system (4.5) can be written as
[TABLE]
Let us transform the first four rows of this matrix as follows. Multiply the third (respectively the fourth) row by (respectively by ) and subtract it from the first (respectively the second) row. Then we subtract the first (respectively the third) row from the second (respectively the fourth) row and obtain the following determinant:
[TABLE]
Now let us subtract the second row multiplied by from the first row. Similarly, subtract the fourth row multiplied by from the third row. Then subtract the third row multiplied by from the fourth row, and finally subtract the fourth row multiplied by , and from the first, the second and the third row respectively. We obtain the equation
[TABLE]
since the polynomials , are linearly independent and . By (4.6) the system (4.5) has a unique solution .
Consider integers satisfying
[TABLE]
and construct the following polynomial with integer coefficients
[TABLE]
where , .
The polynomial is irreducible if it satisfies the conditions of Lemma 3. Let us show that there exists a suitable combinations of the coefficients . Clearly, the first and the second condition of (2.1) hold for any . It remains to show that is not divisible by . Since doesn’t divide , there exists a number such that is not divisible by . From the condition (4.7), we have two possible values for , which can be denoted as , . Since is not divisible by , either or is also not divisible by . Therefore, choosing in this manner yields an irreducible polynomial .
We finally derive bounds for , and . By the inequalities (4.3), (4.5) and (4.7) we obtain the following estimates:
[TABLE]
[TABLE]
We now estimate the height . By equation to of the system (4.5), inequalities (4.3) and (4.7) we have:
[TABLE]
It remains to estimate , , and . By (4.8)– (4.10) and inequalities we get:
[TABLE]
where
[TABLE]
Consider the system of linear equations for , , and
[TABLE]
Since the determinant of the system (4.12) does not vanish, there exists a unique solution. We solve the system (4.12) subject to the estimates (4.11) and inequalities . We obtain
[TABLE]
Hence, by (4.4) and (4.10), we find that
[TABLE]
Consider the roots of the polynomial , where , . By Lemma 4, the following estimates hold
[TABLE]
[TABLE]
where . Let us prove that for . Assume the converse: let , then the number being complex conjugate to is also a root of the polynomial . Hence, by (4.13), (4.14) and Lemma 5 we conclude that
[TABLE]
This inequality contradicts (4.8) for .
Let us choose a maximal system of algebraic integer points satisfying the condition that rectangles , do not intersect. Furthermore, let us introduce the expanded rectangles
[TABLE]
and show that
[TABLE]
To prove this fact, we are going to show that for any point there exists a point such that . Since , there is an algebraic integer point satisfying the inequalities (4.14). Thus, either and , or there exists a point satisfying
[TABLE]
which implies that . Hence, from (4.15) and the estimate we have
[TABLE]
which yields the estimate
[TABLE]
The reference list from the paper itself. Each links out to its DOI / PubMed record.
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- 2[2] V. Beresnevich, On approximation of real numbers by real algebraic numbers , Acta Arith. 90 (1999), no. 2, 97–112.
- 3[3] Y. Bugeaud, Approximation by algebraic integers and Hausdorff dimension , J. London Math. Soc. 65 (2002), no. 2, 547–559.
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- 5[5] J.W.S. Cassels, An introduction to Diophantine approximation , Cambridge Tracts in Mathematics and Mathematical Physics, 45. Cambridge University Press, New York, 1957.
- 6[6] J.W.S. Cassels, An introduction to the geometry of numbers. Classics in mathematics , Springer, Berlin, 1997.
- 7[7] H. Davenport and W.M. Schmidt, Approximation to real numbers by algebraic integers , Acta Arith. 15 (1969), 393 – 416.
- 8[8] G. Eisenstein, Über die Irredicibilität une einige andere Eigenschaften der Gleichung von welche der Theilung der ganzen Lemniscate abhängt , Journal für die reine und angewandte Mathematik 39, 160 – 179.
