On branches of positive solutions for p-Laplacian problems at the extreme value of Nehari manifold method
Yavdat Il’yasov
Kaye Silva
( )
Abstract
This paper is concerned with variational continuation of branches of solutions for nonlinear boundary value problems, which involve the p-Laplacian, the indefinite nonlinearity, and depend on the real parameter λ. A special focus is made on the extreme value of Nehari manifold λ∗, which determines the threshold of applicability of Nehari manifold method. In the main result the existence of two branches of positive solutions for the cases where parameter λ lies above the threshold λ∗ is obtained.
Key words: p-Laplacian, extreme value of Nehari manifold method, indefinite nonlinearity, branches of solutions
††
Yavdat Il’yasov, Institute of Mathematics, Ufa Scientific Senter, Russian Academy of Sciences, 112, Chernyshevsky str., Ufa, RussiaE-mail address: [email protected]
Kaye Silva, Institute of Mathematics and Statistics, Federal University of Goias, Campus II, CEP 74690-900
E-mail address: [email protected]
1 Introduction
We study the following p-Laplacian problem with indefinite nonlinearity
[TABLE]
Here Ω denotes a bounded domain in RN with C1-boundary
∂Ω, λ is a real parameter, 1<p<γ<p∗, where
p∗ is the critical Sobolev exponent, f∈Ld(Ω) where d≥p∗/(p∗−γ) if p<N, and d>1 if p≥N. We suppose that (1.1)
has an indefinite nonlinearity, i.e., f change sign in Ω.
By a solution of (1.1) we mean a critical point u∈W:=W01,p(Ω) of the energy functional
[TABLE]
where W01,p(Ω) is the standard Sobolev space.
The problems with the indefinite nonliearity of type (1.1) have been intesively studied, see e.g., Alama & Tarantello [1], Berestycki, Capuzzo–Dolcetta & Nirenberg [2],
Ouyang [13]. One of the fruitful approaches in the study of such
problems is the Nehari manifold method [12] where solutions are
obtained through the constrained minimization problem
[TABLE]
with the Nehari manifold Nλ:={u∈W∖0:\leavevmode DuΦλ(u)(u)=0} (see e.g. Drabek & Pohozhaev [6],
Il’yasov [9, 8], Ouyang [13]).
The applicability of NM-method to (1.1) depends on the parameter λ.
Indeed, (1.1) possess the so-called extreme value of the Nehari
manifold method [8]
[TABLE]
which was known to be the first found by Ouyang [13]. A feature of
λ∗ is that it defines a threshold for the applicability of the Nehari
manifold method
so that for any λ<λ∗ the set Nλ is a
C1-manifold of codimension 1 in W wherein
for any λ≥λ∗ there is u∈Nλ such that
Φλ′′(u):=Duu2Φλ(u)(u,u)=0. Moreover,
Φλ is unbounded from below over Nλ if λ≥λ∗ (see e.g
[8]).
It is remarkable that once the extreme value (1.3) is detected, one is
able to directly find solutions for (1.1) as
λ<λ∗, by means of the Nehari minimization problems (1.2)
(see e.g. [13] for p=2 and [9] for 1<p<+∞).
A natural question which arises from this is whether there are any positive
solutions of (1.1) for λ>λ∗. An answer for this question, in
the case p=2, follows from the works of Alama & Tarantello [1],
Ouyang
[13], where the authors proved that (1.1) possess a branch of
minimal positive solution for λ belonging to the whole interval
(−∞,Λ) and does not
admit any positive solutions for λ>Λ. However, one approach used in [1, 13] is based on the application of the local continuation method [3],
which essentially involves an analysis of the corresponding linearized
problems.
The main aim of the present paper is to give a contribution in the
investigation of the branches of solutions for the problems where the
application of local continuation methods can cause difficulty.
Our approach is based on the development of the Nehari manifold method where
we focus also on obtaining a new knowledge on extreme value of the Nehari
manifold method.
Let us state our main results. Denote
[TABLE]
and Ω0=Ω∖(Ω+∪Ω−).
We write U=∅ if the interior int(U) of a set U⊂Rn is non-empty. We denote
(λ1(int(U)), ϕ1(int(U))) the first eigenpair of
−Δp on int(U) with zero Dirichlet boundary conditions. It is known
that λ1(int(U)) is positive, simple and isolated, and ϕ1(int(U)) is positive
[11].
To simplify notations, we write λ1:=λ1(Ω), ϕ1:=ϕ1(Ω).
Throughout the paper, we assume that Ω+=∅. Furthermore, we
shall need the following assumption
(f1): If Ω0=∅, then λ1(int(Ω0∪Ω+))<λ1(int(Ω0)).
Notice that if Ω0∪Ω+=∅, then λ∗<+∞
and there exists
λ>λ1 such that (1.1) has no positive solutions
for any
λ>λ (see e.g. [7]).
Our main result is the following
Theorem 1.1**.**
Let 1<p<γ<p∗ and suppose that Ω+=∅,
F(ϕ1)<0 and (f1) is satisfied. Then there exists
Λ>λ∗ such that for all λ∈(λ∗,Λ)
problem (1.1) admits two positive weak solutions
uλ,uλ.
Moreover,
(i)
Φλ′′(uλ)>0,Φλ′′(uλ)>0* and
Φλ(uλ)<Φλ(uλ)<0
for any λ∈(λ∗,Λ);*
(ii)
Φλ(uλ)↑Φλ∗(uλ∗)* as λ↓λ∗.
*
This paper is organized as follows. Section 2 contains preliminaries
results. In Section 3, we show the existence of solutions uλ. In Section 4 we show the existence of solutions uλ and conclude the proof of Theorem 1.1. In Appendix we provide some technical and auxiliary results.
2 Preliminaries
Denote
[TABLE]
Then
[TABLE]
To our aims, it is sufficient to use the following Nehari submanifold
[TABLE]
which we shall use in the fibering representation [9, 14]:
[TABLE]
where Θλ+={v∈W∖0:\leavevmode Hλ(v)<0,\leavevmode F(v)<0}
and
[TABLE]
Thus we are able to introduce
[TABLE]
where cp,γ=(γ−p)/pγ.
Observe, Jλ+ is the 0-homogeneous functional on Nλ+, i.e.,
Jλ+(su)=Jλ+(u) for any s>0, u∈Nλ+.
It is worth pointing out that (1.3) implies
[TABLE]
for any λ∈(λ1,λ∗). In
what follows, we denote ∂Θλ+={v∈W∖0: Hλ(v)=0}.
It is not hard to prove (see e.g. [9])
Proposition 2.1**.**
If DvJλ+(v)(η)=0 for any η∈W∖0, then
sλ+(v)v weakly satisfies (1.1).
In what follows, we shall use
Proposition 2.2**.**
Assume (wn)⊂Θλ+ for λ>λ1 and ∣∣wn∣∣=1, n=1,2,.... Then there exist w∈W∖0 and a subsequence, which we will still denote by (wn), such that wn⇀w weakly in W and wn→w strongly in
Lq(Ω) for 1<q<p∗.
Proof.
Once (wn) is bounded in W, the proof of the existence of the limit point w∈W follows from the Eberlein-Šmulian and Sobolev theorems. Since
Hλ(wn)<0, n=1,2,..., it follows that w=0.
∎
Consider the following Nehari minimization problem
[TABLE]
Lemma 2.1**.**
Suppose the assumptions of Theorem 1.1 are
satisfied. Then
(a)
λ1<λ∗<∞;
(b)
there exists a minimizer ϕ1∗ of the problem
(1.3)
such that ϕ1∗>0. Moreover, any minimizer ϕ1∗ of
(1.3) weakly satisfies, up to scalar multiplier, to (1.1) for
λ=λ∗ and Hλ∗(ϕ1∗)=F(ϕ1∗)=0;
(c)
J^λ∗+>−∞* and there exists a minimizer
vλ∗∈Θλ∗+ of Jλ∗+(vλ∗) so that
uλ∗:=s2(vλ∗)vλ∗ satisfies
(1.1) and uλ∗>0.*
Proof.
The proof of (a) can be found in [9, 7].
Furthermore, by
[9], there exists a nonzero minimizer ϕ1∗ of (1.3)
such that ϕ1∗≥0. Hence by Lagrange multiplier rule there exist
μ0,μ1≥0, ∣μ0∣+∣μ1∣=0 such that
[TABLE]
Since ϕ1∗ is a minimizer of (1.3) then
Hλ∗(ϕ1∗)=0 and threfore μ1F(ϕ1∗)=0.
Suppose μ0=0, then f∣ϕ1∗∣γ−2ϕ1∗=0 a.e. in Ω.
This is possible only if supp ϕ1∗ ⊂Ω0. Thus if
Ω0=∅ then we get a contradiciton. Assume that Ω0=∅. Then there exist eigenpairs (λ1(int(Ω0)),ϕ1(int(Ω0))) and (λ1(int(Ω0∪Ω+)),ϕ1(int(Ω0∪Ω+))). Since
ϕ1(Ω0)∈W01,p(Ω0) and Hλ∗(ϕ1∗)=0,
λ1(int(Ω0))≤λ∗. On the other hand, the
assumption (f1) entails the strong inequality λ1(int(Ω0∪Ω+))<λ1(int(Ω0)). Hence we get a
contradiction because λ∗≤λˉ≤λ1(int(Ω0∪Ω+)) (see [7]). Thus μ0=0.
Suppose μ1=0, then DuHλ∗(ϕ1∗)=0. By the Harnack
inequality (see [15]) we have ϕ1∗>0 in Ω. But this is
possible only if λ∗=λ1, ϕ1∗=ϕ1. However, by
(1.3), F(ϕ1∗)≥0 which contradicts the assumption
F(ϕ1)<0.
Hence μ1>0 and therefore F(ϕ1∗)=0 and there exists t(μ)>0 such
that
t(μ)ϕ1∗ satisfies (1.1). The maximum principle and regularity of
solutions for the p-Laplacian equation yields that ϕ1∗>0 and
ϕ1∗∈C1,α(Ω). Thus we have proved
(b).
Let us prove (c). By [9] there is a finite limit
[TABLE]
and there exists a weak positive solution uλ∗ of (1.1) such
that Jˉ+(λ∗)=Jλ∗+(uλ∗). It is clear that
J^λ∗+≤Jˉ+(λ∗). Thus, we will obtain the proof
if we show that J^λ∗+=Jˉ+(λ∗).
Suppose, contrary to our claim, that
J^λ∗+<Jˉ+(λ∗).
We prove that this is impossible if J^λ∗+=−∞. The proof
in the other case is similar.
Since J^λ∗+=−∞, for every K>0, one can find vK∈Θλ∗+ such that Jλ∗+(vK)<Jˉ+(λ∗)−K.
Since Jλ+(vK)→Jλ∗+(vK), for every ε>0,
there exists δ>0 such that ∣Jλ+(vK)−Jλ∗+(vK)∣<ε as ∣λ−λ∗∣<δ. In view
of (2.5), we may assume that there holds also ∣J^λ+−Jˉ+(λ∗)∣<ε if ∣λ−λ∗∣<δ. Then
[TABLE]
Since K>0, ε>0 may be chosen arbitrarily, we get a
contradiction.
∎
We need also
Corollary 2.1**.**
There exists μ0∈(λ1,λ∗) such that any minimizer wλ∗
of (2.3) for λ=λ∗ satisfies Hμ0(wλ∗)<0.
Proof.
Suppose the assertion of the corollary is false. Then there
exists a sequence wn∈Θλ∗+ such that J^λ∗+=Jλ∗+(wn)
and Hλ∗(wn)→0 as n→∞. By homogeneity of Jλ∗+(v) we may assume
∣∣wn∣∣=1. Hence by Proposition 2.2, there is w∈W∖0 such that
wn⇀w in W and wn→w in
Lq(Ω) for 1<q<p∗.
Observe
[TABLE]
From this and since Jλ∗+(wn)=J^λ∗+<0, it follows
that sλ∗+(wn)→∞ and F(wn)→0. Hence F(w)=0 and
therefore Hλ∗(w)=0 which implies by (2o), Lemma 2.1
that w=ϕ1∗>0. Note that
[TABLE]
Thus sλ∗+(wn)→∞ implies f∣ϕ1∗∣γ−1=0 a.a.
in Ω, which is an absurd.
∎
Corollary 2.2**.**
For each μ∈(λ1,λ∗), there is cμ<0 such that
F(v)≤cμ ∀v∈Θμ+.
Proof.
Let μ<λ∗ and assume contrary to our claim that there
exists a sequence vn∈Θμ+ such that
F(vn)→0 as n→∞. By homogeneity of Jλ∗+(v) and Proposition 2.2 there is v∈W∖0 such that
vn⇀v weakly in W and vn→v
strongly in Lq(Ω) in
Lq(Ω) for 1<q<p∗. Hence, by the weakly
lower-semicontinuity of ∫∣∇v∣pdx we conclude that
[TABLE]
But this contradicts to the definition of λ∗ since F(v)=0.
∎
3 Local Minima Solutions
In this section, we show the existence of local minima type solutions uλ for (1.1). Let us consider the following family of constrained minimization problems
[TABLE]
parametrized by λ≥λ∗ and μ∈(λ1,λ∗).
Proposition 3.1**.**
For each
λ≥λ∗ and μ∈(λ1,λ∗) there holds
(a)
J^λ+(μ)>−∞;
(b)
there exists a minimizer vλ(μ)
of (3.1).
Proof.
(a) follows immediately from Lemma
2.2. Let us prove (b). Take a minimizing sequence vn∈Θμ+ of
(3.1), that is Jλ+(vn)→J^λ+(μ)>−∞ as n→∞. By homogeneity of Jλ∗+(v) and Proposition 2.2 there is v∈W∖0 such that
vn⇀v in
W and vn→v in
Lq(Ω) for 1<q<p∗. Hence, by the
weak lower-semicontinuity we infer that
Hμ(v)≤liminfn→∞Hμ(vn)≤0, F(v)=limn→∞F(vn)<0 and therefore v∈Θμ+. By the
weak lower-semicontinuity of Jλ+(v),
[TABLE]
In view of (3.1), this is possible only if
Jλ+(v)=J^λ+(μ), that is v is a minimizer
of
(3.1).
∎
We denote the set of minimizers for (3.1) by
Sλ(μ)={v∈Θμ+: Jλ+(v)=J^λ+(μ)}
and let
Sλ∂(μ)={v∈Sλ(μ):\leavevmode Hμ(v)=0}.
Lemma 3.1**.**
Let λ0≥λ∗ and μ∈(λ1,λ∗) such
that
Sλ0∂(μ)=∅. Then there
exists ε>0 such that
Sλ∂(μ)=∅ for
each λ∈[λ0,λ0+ε).
Proof.
Suppose the lemma were false. Then we could find sequences
λn→λ0 such that vn:=vλn+(μ)∈∂Θμ+,
n=1,2,.... By By homogeneity of Jλ∗+(v) we may assume that
∣∣vn∣∣=1, n=1,2,..., and therefore by Proposition 2.2, vn⇀v
weakly in W and vn→v strongly in
Lq(Ω) for 1<q<p∗ and some v∈W∖0. Hence
Hμ(v)≤liminfn→∞Hμ(vn)=0, F(v)=limn→∞F(vn)<0 and therefore v∈Θμ+. Furthermore,
by
the weak lower semi-continuity
[TABLE]
Observe, from the Poincare’s inequality and Corollary 2.2, we have that
for all w∈Θμ2 and λ≥λ1
[TABLE]
Thus, Jλn+(w)→Jλ0+(w) uniformly on
w∈Θμ+ as n→∞ and therefore
J~=J^λ0+(μ). Hence if
Jλ0+(v)<J^λ0+(μ), we obtain a
contradiction
since v∈Θμ+. The case
Jλ0+(v)=J^λ0+(μ) entails that
Hμ0(v)=0
and v=vλ0(μ). Consequently vλ0(μ)∈Sλ0∂(μ) which contradicts to the assumption
Sλ0∂(μ)=∅.
∎
Let us prove the existence of the first solution uλ in Theorem 1.1.
Lemma 3.2**.**
Let 1<p<γ<p∗ and suppose that Ω+=∅,
F(ϕ1)<0 and (f1) is satisfied. Then there exists
Λ>λ∗ such that for all λ∈(λ∗,Λ)
problem (1.1) admits positive weak solution
uλ such that
(li)
Φλ′′(uλ)>0* and
Φλ(uλ)<0
for any λ∈(λ∗,Λ);*
(lii)
Φλ(uλ)↑Φλ∗(uλ∗)* as λ↓λ∗;*
Proof.
From Lemma 2.1 it follows that
there exists μ0∈(λ1,λ∗) such that Sλ∗∂(μ0)=∅. Thus Lemma 3.1 implies that there exist Λ>λ∗ such that Sλ∂(μ0)=∅
for all λ∈(λ∗,Λ). Since by Proposition 3.1, Sλ(μ)=∅ for λ≥λ∗, we conclude that for every λ∈(λ∗,Λ)
there exists a minimizer vλ(μ0) of (3.1) such that vλ(μ0)∈Θμ0+. This and Proposition 2.1 yield that uλ=sλ+(vλ(μ0))vλ(μ0) is a weak solution of (1.1) for λ∈(λ∗,Λ).
In virtue that Jλ+(v)=Jλ+(∣v∣) and ∣v∣∈Θμ0+ for any v∈Θμ0+, we may assume that uλ≥0 in Ω. Now by the Harnack inequality (see [15]) we conclude that uλ+>0 in Ω.
Since vλ+∈Θλ+, we get (li). Let us prove assertion (lii). Notice that from (3.1) it follows that Φλ∗(uλ∗)=J^λ∗+(μ0)≥J^λ+(μ0) for any λ>λ∗. Thus if we suppose that assertion (lii) were false then we could find a sequence λn↓λ∗ such that Jλn+(vλn(μ0))→Jλ∗+<J^λ∗+(μ0). Arguing as above, we may assume that vλn(μ0)⇀v weakly in W and vn→v strongly in Lp(Ω), Lγ(Ω) as n→∞ with v=0. This implies that v∈Θμ0+ and Jλ∗+(v)<J^λ∗+(μ0). Thus we get a contradiction.
∎
From the proof of Lemma 3.2 we see that the solution uλ may
depend on the parameter μ∈(λ1,λ∗). However, one can
prove that, at least locally by μ, there is no such dependence.
Corollary 3.1**.**
Let λ≥λ∗ and μ0∈(λ1,λ∗). Suppose
that
Sλ∂(μ0)=∅. Then there exists
ε>0 such that
Sλ(μ0)=Sλ(μ) for all μ∈(μ0−ε,μ0+ε).
Proof.
Conversely, suppose that there is (μn) such that μn→μ0 and ∃vn∈Sλ(μn)∖Sλ(μ0). Then
Jλ+(vn)<J^λ+(μ0) and vn∈Θμn+∖Θμ0+. Arguing as in the proof of Proposition
3.1
it can be shown that there exists a subsequence (which we denote again
(vn))
such that vn→v strongly in W1,2. Hence,
Jλ+(v)=J^λ+(μ0) and v∈∂Θμ0+ that is v∈Sλ∂(μ0)
which
is a contradiction.
∎
4 Mountain Pass Solutions
In this section, for λ∈(λ∗,Λ), we will find the second
branch of positive solution uˉλ of a mountain pass type.
Fix μ0∈(λ1,λ∗) such that any minimizer wλ∗
of (2.3) for λ=λ∗ satisfies Hμ0(wλ∗)<0. The existence of μ0 follows from Corollary 2.1.
Let λ∈(λ∗,Λ). Define
[TABLE]
Proposition 4.1**.**
For each λ∈(λ∗,Λ) there
holds
(a)
μ0<μλ<λ∗;
(b)
J^λ+(μλ)=J^λ+(μ0)* and Sλ∂(μλ)=∅.*
Proof.
(a) By Corollary 2.1, Sλ∗∂(μ0)=∅ and by Corollary 3.1, Sλ(μ0)=Sλ(μ) for μ∈(μ0,μ0+ε) and some ε>0. Hence,
μ0<μλ. Notice that by Proposition 5.1 from Appendix, the function J^λ+(μ) is continuous with respect to μ∈(μ0,λ∗). Hence and since J^λ+(μ)→−∞ as μ→λ∗, there is μ′∈(μ0,λ∗) such that
J^λ+(μ0)>J^λ+(μ) for each μ∈(μ′,λ∗). Thus
μλ≤μ′<+∞.
(b) Continuity of J^λ+(⋅) and (4.1) yield J^λ+(μλ)=J^λ+(μ0). Suppose, contrary to our claim, that Sλ∂(μλ)=∅. Then by
Corollary 3.1, there is ε′>0 such that for μ∈(μλ,μλ+ε′),
Sλ(μλ)=Sλ(μ) and consequently J^λ+(μ)=J^λ+(μλ)=J^λ+(μ0) which is a contradiction.
∎
Observe, for any λ∈(λ∗,Λ) and μ∈(λ1,λ∗), if w∈Sλ∂(μλ), then ∣w∣∈Sλ∂(μλ)
For each λ∈(λ∗,Λ), fix 0≤wλ∈Sλ∂(μλ) and let 0<uλ∈Θμ0+ be the local
minimum found in Lemma 3.2. Define
[TABLE]
where
[TABLE]
Proposition 4.2**.**
For each λ∈(λ∗,Λ) there exists jλ such that
[TABLE]
Proof.
Evidently, Sλ∂(μ0)=∅ implies
[TABLE]
Thus for any u∈∂Θμ0+, one has
[TABLE]
∎
Let us shows that every path from Γλ intersects
∂Θμ0+.
Proposition 4.3**.**
Let λ∈(λ∗,Λ). Then for any η∈Γλ
there exists t0∈(0,1) such that
η(t0)∈∂Θμ0+.
Proof.
Notice Hμ0(η(0))=Hμ0(vλ)<0 while
Hμ0(η(1))=Hμ0(wλ)>0 because wλ∈Θλ∗+∖Θμ0+. Thus by the continuity of Hμ0(η(⋅)), there is t0∈(0,1)
such that Hμ0(η(t0))=0.
∎
Using [4] we are able to prove
Proposition 4.4**.**
For each λ∈(λ∗,Λ), there is η∈Γλ such that Hλ∗(η(t))<c<0
for all t∈[0,1]
Proof.
Consider the path η(t)=[(1−t)vλp+twλp]1/p, t∈[0,1]. Once vλ>0, {x∈Ω: uλ(x)=wλ(x)=0}=∅.
Hence we may apply
Proposition 5.2 from the Appendix and thus η∈C([0,1],W) and
for t∈[0,1] we have
[TABLE]
∎
Corollary 4.1**.**
For all λ∈(λ∗,Λ) there holds
[TABLE]
Proof.
Let us start with the first inequality. Take any η∈Γλ. From Proposition 4.3, there is t0∈(0,1)
such that η(t0)∈∂Θμ0+,
therefore by Proposition 4.2, maxt∈[0,1]Φλ(η(t))≥Φλ(η(t0))>J^λ+(μ0) and
consequently J^λ+(μ0)<cλ. Let η be given by
Proposition 4.4. Then
[TABLE]
which implies that cλ<0.
∎
Now we are able to find the second solution uˉλ.
Lemma 4.1**.**
For each λ∈(λ∗,Λ),
cλ<0 is a critical value uλ of Φλ such that
Φλ(sλ+(uλ)=cλ,
uλ
is a weak
solution
of (1.1) and
uλ>0 in Ω.
Proof.
Since Φλ(u)=Φλ(∣u∣) for all u∈W, then by (4.2) there is a sequence of paths ηn≥0 in Ω such that
[TABLE]
Following [10], for each ϵ>0 introduce
[TABLE]
where Kcλ,2ϵ={u∈W:∣Φλ(u)−cλ∣≤2ϵ}. By Theorem E.5 from [10],
there is a sequence un∈W satisfying
[TABLE]
and
[TABLE]
By Corollary 4.1 we know that cλ<0. Thus,
by (4.4) we can apply Proposition 5.3 to conclude that un→uλ∈W∖0 so that Φλ(uλ)=cλ and
DuΦλ(uλ)=0. Moreover, once (4.5) is satisfied, we also have that uλ≥0. Now applying the Harnack inequality [15] we deduce that
uλ>0 in Ω.
∎
Conclusion of the proof of Theorem 1.1.
Let Λ>λ∗ be given by Lemma 3.2. Then Lemma 3.2 and Lemma 4.1 yield the existence of positive weak solutions
uλ,uλ. Since cλ<0, Φλ(uλ)<0. Thus in virtue that
uλ is a critical value of Φλ, implies that Φλ′′(uλ)>0. Corollary 4.1 and Lemma 4.1 imply that Φλ(uλ)<Φλ(uλ)<0 for any λ∈(λ∗,Λ). Hence and by (li), Lemma 3.2 we get assertion (i) of the theorem. The proof of (ii) follows from (lii), Lemma 3.2.
∎
5 Appendix
Proposition 5.1**.**
For any λ≥λ∗, the function μ↦J^λ+(μ) is continuous over the interval
(λ1,λ∗).
Proof.
Let μ∈(λ1,λ∗). Suppose, contrary to our claim, that there are μn→μ and r>0 such that
∣J^λ+(μn)−J^λ+(μ)∣>r for all n, or
equivalently
[TABLE]
for sufficiently large n. Suppose the first inequality is true, i.e.,
J^λ+(μn)>J^λ2(μ)+r. From (3.1) this is possible only if μn<μ.
Moreover, we can assume without loss of generality that μn is monotone
increasing and consequently J^λ2(μn) is decreasing. Thus
J^λ+(μn)→I>J^λ+(μ).
By Proposition 3.1, there is v∈Sλ(μ) that is
Jλ2(v)=J^λ+(μ). Suppose v∈Sλ(μ)∖Sλ∂(μ), then
convergence μn→μ entails that there is n such that v∈Θμn2. However Jλ+(v)≥J^λ+(μn) which
contradicts to Jλ+(v)=J^λ+(μ)<I≤J^λ+(μn). Suppose now that v∈Sλ∂(μ). Then, taking into account the continuity of Jλ+(u) on Θμ+, we can choose w∈Θμ+
such that Jλ+(v)≤Jλ+(w)<I. However, there is n such that
w∈Θμn+. This implies J^λ+(μn)≤Jλ+(w)<I which is an absurd.
Now suppose the second inequality in (5.1) is true. Then μ<μn and
we may assume that μn is decreasing. Consequently
J^λ+(μn) is increasing and J^λ+(μn)→I<J^λ+(μ). From Proposition 3.1, there is vn such
that vn∈Sλ(μn). If vn∈Θμ+ for some
n then J^λ+(μ)≤Jλ+(vn)=J^λ+(μn)
which is contradicts to the assumption J^λ+(μ)>J^λ+(μn). Thus it is only possible that vn∈Θμn+∖Θμ+ for all
n=1,2,....
By homogeneity of Jλ+(v) we may assume
∣∣vn∣∣=1. Hence by Proposition 2.2, vn⇀v in
W, vn→v in Lp(Ω),Lγ(Ω) for some v∈W∖0. By the weak lower-semicontinuity we have that
[TABLE]
which
implies that v∈Θμ+ and
[TABLE]
which is an absurd because I<J^λ+(μ).
∎
The next result can be found in [4]. We give a proof here for the
reader’s convenience.
Proposition 5.2**.**
Let u,v∈W∖0, u,v≥0 in Ω and define
η(t)=[(1−t)up+tvp]1/p for t∈[0,1]. Suppose that
the set {x∈Ω: u(x)=v(x)=0} has zero Lebesuge measure. Then
[TABLE]
and η∈C([0,1],W).
Proof.
First note that the weak derivative of η(t) is given by
∇η(t)=[(1−t)up+tvp](1−p)/p[(1−t)up−1∇u+tvp−1∇v]. Let p′ be the conjugate exponent of p, i.e., 1/p+1/p′=1. From the
Holder inequality, we have that
[TABLE]
for all t∈[0,1].
Once {x∈Ω: u(x)=v(x)=0} has zero Lebesuge measure, we have that
(1−t)u+tv>0 a.e. in Ω, for all t∈(0,1) and therefore, from (5.2), we
conclude that
[TABLE]
which implies
[TABLE]
Consequently η∈W for all t∈[0,1]. The continuity of η follows by a standard application of the
Lebesgue theorem.
∎
Proposition 5.3**.**
Suppose that un∈W∖0 is a (P.-S.) sequence,
i.e.
[TABLE]
Then un has a strong convergent subsequence with non-zero limit point u∈W∖0 satisfying Φλ(u)=c and
DuΦ(u)=0.
Proof.
The assumption DuΦλ(un)→0 entails Hλ(un)−F(un)=o(1) and
therefore
[TABLE]
This implies that ∥un∥ is bounded, ∣∣un∣∣≥δ>0 and
Hλ(un)<0 for sufficiently large n.
Thus we may assume un⇀u in W, un→u
in Lp(Ω) and Lγ(Ω) and u=0.
Hence and since DuΦ(un)→0 as n→∞, we have
[TABLE]
Thus by S+ property of the p-Laplacian operator (see [5]) we derive that un→u
strongly in W.
∎