This paper investigates the structure of Kähler differential algebras associated with 0-dimensional schemes in projective space, providing explicit calculations and bounds for their Hilbert functions and polynomials.
Contribution
It offers explicit presentations and detailed analysis of Kähler differential modules for 0-dimensional schemes, including bounds and specific cases like subschemes of P^1 and P^2.
Findings
01
Explicit Hilbert function values for differential modules
02
Bounds on Hilbert polynomials and regularity indices
03
Detailed results for schemes on a conic in P^2
Abstract
Given a 0-dimensional scheme in a projective space Pn over a field K, we study the K\"ahler differential algebra ΩR/K of its homogeneous coordinate ring R. Using explicit presentations of the modules ΩR/Km of K\"ahler differential m-forms, we determine many values of their Hilbert functions explicitly and bound their Hilbert polynomials and regularity indices. Detailed results are obtained for subschemes of P1, fat point schemes, and subschemes of P2 supported on a conic.
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Full text
Kähler Differential Algebras for 0-dimensional Schemes
Given a 0-dimensional scheme in a projective n-space Pn
over a field K, we study the Kähler differential algebra
ΩRX/K of its homogeneous coordinate ring RX.
Using explicit presentations of the modules ΩRX/Km
of Kähler differential m-forms, we determine many values
of their Hilbert functions explicitly and bound their Hilbert
polynomials and regularity indices.
Detailed results are obtained for subschemes of P1,
fat point schemes, and subschemes of P2 supported on
a conic.
Key words and phrases:
Kähler differential algebra, 0-dimensional scheme,
fat point scheme, regularity index, Hilbert function
1991 Mathematics Subject Classification:
Primary 13N05, Secondary 13D40, 14N05
1. Introduction
In the paper [DK], G. de Dominicis and the first author
introduced the application of Kähler differential modules
to the study of 0-dimensional subschemes X of a projective
space Pn over a field K of characteristic zero.
They showed that this graded module over the homogeneous
coordinate ring RX contains numerical and algebraic
information which is not readily available from
the homogeneous vanishing ideal or from RX.
Later, in [KLL], the authors extended and refined these
techniques for fat point schemes in Pn.
Following the classical construction described by E. Kunz
in his book [Kun], it is natural to define the
Kähler differential algebra
ΩRX/K=⨁m∈NΩRX/Km
of X as the exterior algebra of its Kähler
differential module ΩRX/K1.
This invites the question whether the Kähler differential
algebra contains numerical and algebraic information
about X which is not readily available in RX
or in ΩRX/K1.
Thus the following example provided the initial spark
to ignite the curiosity of the authors.
Let X and Y be two sets of six reduced K-rational
points in P2 such that X is contained in
a non-singular conic, and such that Y consists of
three points on a line and three points on another line.
Then the Hilbert functions of RX and RY agree,
as do the Hilbert functions of ΩRX/K1
and ΩRY/K1.
However, the Hilbert functions of ΩRX/K2
and ΩRY/K2 are different,
and also the Hilbert functions of ΩRX/K3
and ΩRY/K3 disagree:
[TABLE]
So, the Hilbert functions of the exterior powers
of ΩRX/K1 “know” whether X
is contained in an irreducible or a reducible conic.
This observation motivated the studies underlying
this paper. Let us now outline its contents in more detail.
In the second section we start by recalling the definitions
of the Kähler differential module ΩRX/K1
and the Kähler differential algebra
ΩRX/K=⋀RX(ΩRX/K1)
of a 0-dimensional subscheme X of Pn.
As explained in [Kun], we can calculate an explicit
presentation of ΩRX/Km=⋀RXm(ΩRX/K1)
for every m≥1.
Moreover, we show that ΩRX/Km=⟨0⟩
for m>n+1, provide a simplified presentation for
ΩRX/Kn+1, and show that the Koszul complex
yields an exact sequence
[TABLE]
where mX is the homogeneous maximal
ideal mX=⟨x0,…,xn⟩
of RX.
In Section 3 we have a brief glance at the case n=1,
i.e., at 0-dimensional subschemes of a projective line.
Unsurprisingly, in this case the Hilbert functions
and regularity indices of ΩRX/K1
and ΩRX/K2 can be written down explicitly.
In Section 4 we look at the Hilbert function of
ΩRX/Km in special degrees. We provide
explicit values in low degrees, show that the Hilbert
polynomial (i.e., the value in high degrees) is constant,
and examine monotonicity in intermediate degrees.
These insights are accompanied by a bound for the
regularity index of ΩRX/Km in terms
of the regularity index of ΩRX/K1
in Section 5.
Then, in the next four sections, we look at the modules
of Kähler differential m-forms for fat point
schemes W. Such schemes are defined by ideals
of the form IW=℘1m1∩⋯∩℘sms,
where the ideals ℘i are the vanishing ideals
of distinct K-rational points in Pn.
In Section 6 we prove a regularity bound for
ΩRW/Km which uses the regularity index
of the fattening of W, i.e., the scheme
V defined by
IV=℘1m1+1∩⋯∩℘sms+1.
For fat point schemes, we also give bounds on some specific
values of the Hilbert polynomial of ΩRW/Km.
In the reduced case (i.e., when m1=⋯=ms=1), these values
are zero for m≥2, but as soon as one of the exponents mi
satisfies mi≥2, not all of these values are zero anymore.
Thus the property of W to be reduced is reflected in
the values of the Hilbert polynomials of ΩRW/Km
(see Cor. 7.5).
More generally, Prop. 7.4 provides upper
and lower bounds for these Hilbert polynomials.
For the highest non-zero module of Kähler differentials
ΩRW/Kn+1, we can sometimes determine
its Hilbert polynomial explicitly. More precisely, we have formulas
for schemes W contained in a hyperplane
(see Prop. 8.1) and for equimultiple
schemes W (see Thm. 8.3).
Another case in which we have more detailed information
is the module ΩRW/K2 for an
equimultiple fat point scheme W
(i.e., a scheme satisfying m1=⋯=ms).
In this case we can extract the value of the Hilbert polynomial
of ΩRW/K2 from a complex connecting
it to its fattening and second fattening
(see Prop. 8.5).
We end the discussion of Hilbert polynomials with a conjecture
for their value for ΩRW/Kn+1.
In Section 9, a rich and detailed set of results describes
the Hilbert functions of ΩRW/Km,
where m=1,2,3, in the case of a fat point scheme W
in P2 supported on a non-singular conic.
In this case, the Hilbert function of ΩRW/K1
can be computed explicitly from the Hilbert functions
of suitable fat point schemes (see Thm. 9.2).
If W is an equimultiple fat point scheme, we construct
a special homogeneous system of generators of IW
in Prop. 9.4 and use it to compute the Hilbert
function of ΩRW/K3 explicitly
(see Thm. 9.6 and Prop. 9.7).
Consequently, we can use the exact sequence given by the
Koszul complex and determine the Hilbert function
of ΩRW/K2 explicitly
(see Prop. 9.9).
Finally, in the last section we point out the relation
between the Kähler differential algebra ΩRX/K
and the relative Kähler differential algebra
ΩRX/K[x0] and use it to deduce many properties
of the Hilbert function, the Hilbert polynomial, and the
regularity index of ΩRX/K[x0]
(see Propositions 10.1, 10.2
and 10.3).
Throughout the paper we illustrate all results with explicitly
computed examples. The necessary calculations were performed
using the second author’s package for the computer algebra
system ApCoCoA (see [ApC]). Unless explicitly stated
otherwise, we adhere to the definitions and notation
introduced in [KR1, KR2] and [Kun].
2. Definition and Basic Properties
Throughout this paper we work over a field K of characteristic
zero. By Pn we denote the projective n-space over K.
The homogeneous coordinate ring of Pn is S=K[X0,…,Xn].
It is equipped with the standard grading deg(Xi)=1
for i=0,…,n.
Let X be a 0-dimensional scheme in Pn, and
let IX be the (saturated) homogeneous vanishing
ideal of X. Then the homogeneous coordinate ring of X
is RX=S/IX.
The ring RX=⨁i≥0(RX)i is a
standard graded K-algebra. Its enveloping algebra is
RX⊗KRX=⨁i≥0(⨁j+k=i(RX)j⊗(RX)k).
By J we denote the kernel of the homogeneous
RX-linear map of degree zero
μ:RX⊗KRX→RX
given by μ(f⊗g)=fg.
It is well known that J is the homogeneous ideal
of RX⊗KRX generated
by {xi⊗1−1⊗xi∣0≤i≤n},
where xi is the image of Xi
in RX for i=0,…,n.
In this paper we are interested in looking at the
algebraic structure and Hilbert function of the
following objects.
Definition 2.1**.**
(a)
The graded RX-module
ΩRX/K1=J/J2 is called
the module of Kähler differential 1-forms
of RX/K, or simply the
module of Kähler differentials.
2. (b)
The homogeneous K-linear map
d:RX→ΩRX/K1 given by
f↦f⊗1−1⊗f+J2 is
called the universal derivation of RX/K.
3. (c)
The m-th exterior power of ΩRX/K1
over RX is called the module of
Kähler differential m-forms of RX/K
and is denoted by ΩRX/Km.
4. (d)
The direct sum
ΩRX/K:=⨁m∈NΩRX/Km
is an RX-algebra. It is called the
Kähler differential algebra of RX/K.
Here we use ΩRX/K0=RX.
More generally, for any graded K-algebra T/S, we can define
the module of Kähler differential m-forms
ΩT/Sm and the Kähler differential algebra
ΩT/S in analogously (cf. [Kun, Section 2]).
The Kähler differential algebra of ΩRX/K
is in fact a bigraded K-algebra whose homogeneous component
in degree (m,d) is given by (ΩRX/Km)d.
Notice that we have deg(dxi)=deg(xi)=1 for
i=0,…,n. For m≥0, the graded RX-module
ΩRX/Km is finitely generated and
its Hilbert function is defined by
[TABLE]
Note that ΩRX/K0=RX
and ΩRX/K1=RXdx0+⋯+RXdxn.
Hence we obtain ΩRX/Km=⟨0⟩
for m>n+1 and
ΩRX/K=⨁m=0n+1ΩRX/Km.
Furthermore, there is a presentation of ΩRX/K as
ΩRX/K≅ΩS/K/⟨IX,dIX⟩ΩS/K
(cf. [Kun, Proposition 4.12]).
From this we deduce the following presentation
of the module of Kähler differential m-forms.
Proposition 2.2**.**
Let m≥1 and let {F1,…,Fr} be a homogeneous system
of generators of IX. The graded RX-module
ΩRX/Km has a presenation
[TABLE]
where IXΩS/Km+dIXΩS/Km−1
is generated by
[TABLE]
In the case m=n+1, the presentation of ΩRX/Kn+1
can be described explicitly as follows.
Corollary 2.3**.**
Let {F1,…,Fr} be a homogeneous system of generators
of IX. There is an isomorphism of graded RX-modules
[TABLE]
Proof.
Note that ΩS/Kn+1 is a free S-module of rank 1
with basis {dX0∧⋯∧dXn}, and so
ΩS/Kn+1≅S(−n−1).
For F∈IX and G∈S, we have
FdG=d(FG)−GdF∈dIX.
It follows that
IXΩS/Km⊆dIXΩS/Km−1
for all m≥1.
Let I=⟨∂Xi∂Fj∣0≤i≤n,1≤j≤r⟩.
We need to show that
dIXΩS/Kn=IdX0∧⋯∧dXn.
Clearly, we have
[TABLE]
where dXi indicates that dXi
is omitted in the wedge product.
Hence we get the inclusion
dIXΩS/Kn⊇IdX0∧⋯∧dXn.
For the other inclusion, let F∈IX, and let
{i1,…,in}⊆{0,…,n}.
Write F=G1F1+⋯+GrFr with G1,…,Gr∈S.
Then we have
[TABLE]
and hence
(dF−(F1dG1+⋯+FrdGr))∧dXi1∧⋯∧dXin∈IdX0∧⋯∧dXn.
Since the field K has characteristic zero,
for j=1,…,r, Euler’s relation yields that
Fj=deg(Fj)1∑i=0nXi∂Xi∂Fj∈I.
In particular, we have IX⊆I.
This implies
dF∧dXi1∧⋯∧dXin∈IdX0∧⋯∧dXn.
Therefore we get the equality
dIXΩS/Kn=IdX0∧⋯∧dXn,
and the claim follows readily.
∎
Now let mX=⟨x0,…,xn⟩
be the homogeneous maximal ideal of RX, and let
e:RX→RX be
the Euler derivation of RX/K given by
f↦i⋅f for f∈(RX)i.
By universal property of ΩRX/K1
(cf. [Kun, Section 1]),
there is a unique homogeneous RX-linear map
γ:ΩRX/K1→RX
such that e=γ∘d.
In particular, we have γ(dxi)=xi
for all i=0,…,n and γ(df)=deg(f)⋅f
for every homogeneous element f∈RX∖{0}.
The Koszul complex of γ is the complex
[TABLE]
where γ:ΩRX/Km→ΩRX/Km−1 is a homogeneous RX-linear
map defined by
[TABLE]
for all ω1,…,ωm∈ΩRX/K1,
and where γ(ω∧ω′)=γ(ω)∧ω′+(−1)mω∧γ(ω′)
for ω∈ΩRX/Km and
ω′∈ΩRX/Kk
(cf. [BH, 1.6.1-2]). In our setting, this complex is
an exact sequence, as the following proposition shows.
Proposition 2.4**.**
The Koszul complex
[TABLE]
is an exact sequence of graded RX-modules.
Proof.
Let 1≤m≤n+1, let i≥0, and
let ω=fdxi1∧⋯∧dxim∈ΩRX/Km
with f∈(RX)i and 0≤i1<⋯<im≤n.
Then we have
[TABLE]
and
[TABLE]
This implies (γ∘d+d∘γ)(ω)=(m+i)ω.
Hence (γ∘d+d∘γ)(ω)=deg(ω)ω
for every homogeneous element ω∈ΩRX/Km.
Now suppose that ω∈ΩRX/Km∖{0}
is a homogeneous element with γ(ω)=0.
Set ω=deg(ω)1dω∈ΩRX/Km+1.
We get γ(ω)=ω,
and the proof is complete.
∎
Obviously, the ring RX is Noetherian and
the graded RX-module ΩRX/Km
is finitely generated, and so the Hilbert polynomial
of ΩRX/Km exists (cf. [KR2, 5.1.21])
and is denoted by HPΩRX/Km(z).
The number
\operatorname{ri}(\Omega^{m}_{R_{\mathbb{X}}/K})=\min\{i\in\mathbb{Z}\mid\operatorname{HF}_{\Omega^{m}_{R_{\mathbb{X}}/K}}(j)=\operatorname{HP}_{\Omega^{m}_{R_{\mathbb{X}}/K}}(j)\mbox{\ for all j\geq i}\}
is called the regularity index of ΩRX/Km.
In the following, we denote the Hilbert function of RX
by HFX and its regularity index by rX.
As a consequence of the exact sequence (K), we have
the following bound for ri(ΩRX/Kn+1).
Corollary 2.5**.**
We have
ri(ΩRX/Kn+1)≤max{rX,ri(ΩRX/K1),…,ri(ΩRX/Kn)}.
Let us examine the Hilbert functions of the
modules of Kähler differential m-forms
and their regularity indices in a concrete case.
Example 2.6**.**
Let X and Y be two sets of six reduced K-rational
points in P2 such that X is contained in
a non-singular conic and Y lies on the union of two lines
and no 5 points of Y are collinear.
Then the Hilbert functions of X and Y agree,
as do the Hilbert functions of ΩRX/K1
and ΩRY/K1, namely
[TABLE]
It is clear that rX=rY=3 and
ri(ΩRX/K1)=ri(ΩRY/K1)=6.
We also have HFΩRX/Km(i)=HFΩRY/Km(i)=0
for m=1,2,3 and i≤0.
However, the Hilbert functions of ΩRX/K2
and ΩRY/K2 are different,
and also the Hilbert functions of ΩRX/K3
and ΩRY/K3 disagree:
[TABLE]
In addition, we have
ri(ΩRX/K2)=ri(ΩRY/K2)=6,
ri(ΩRX/K3)=4, and
ri(ΩRY/K3)=5. In this case,
the inequality of regularity indices in
Corollary 2.5 is a strict inequality.
Moreover, the Hilbert functions of the exterior powers
ΩRX/K2 and ΩRX/K3 distinguish
a set X of six points on an irreducible conic from
a set Y of six points on a reducible conic.
3. Kähler Differential Algebras
for Subschemes of P1
In this section we consider the easiest case, namely
0-dimensional subschemes X of P1.
It is well known that
Hilbert functions do not change under base field
extensions (for instance, see [KR2, 5.1.20]).
Thus, in order to compute
the Hilbert function of the Kähler differential
algebra for the [math]-dimensional scheme X
of P1, we may assume that the field K
is algebraically closed.
In this case the homogeneous vanishing ideal
IX is a principal ideal generated by
a homogeneous polynomial F∈S=K[X0,X1].
Moreover, after a suitable change of coordinates,
we may also assume that F is of the form
F=∏i=1s(X1−aiX0)mi
where s≥1, m1,…,ms≥1 and
a1,…,as∈K
such that ai=aj for i=j.
In [Rob, Section 4], L.G. Roberts gave
a formula for the Hilbert function
of ΩRX/K when m1=m2=⋯=ms=1.
Now we extend his result to arbitrary exponents
m1,…,ms≥1 as follows.
Proposition 3.1**.**
Let X⊆P1 be a [math]-dimensional scheme,
and let IX=⟨F⟩, where
F=∏i=1s(X1−aiX0)mi for some s,
m1,…,ms≥1, and ai∈K with ai=aj
for i=j, and let μ=∑i=1smi.
Then the Hilbert functions of the Kähler differential
modules of RX/K are given by
[TABLE]
In particular, we have
ri(ΩRX/K1)=ri(ΩRX/K2)=μ+s−1.
Proof.
Let G=∏i=1s(X1−aiX0)mi−1,
let H1=∑i=1smiai∏j=i(X1−ajX0),
and let H2=∑i=1smi∏j=i(X1−ajX0).
Note that deg(G)=∑i=1s(mi−1) and
deg(H1)=deg(H2)=s−1.
We verify that gcd(H1,H2)=1.
Suppose for a contradiction that
gcd(H1,H2)=H with deg(H)≥1.
Euler’s relation μF=G(−X0H1+X1H2)
implies μ∏i=1s(X1−aiX0)=−X0H1+X1H2.
So, H is a divisor of ∏i=1s(X1−aiX0).
There exists an index i∈{1,…,s} such that
(X1−aiX0)∣H, but (X1−aiX0)∤H2,
a contradiction. Hence we obtain gcd(H1,H2)=1.
Thus the sequence {H1,H2} is an S-regular sequence.
Consequently, this sequence is also a regular
sequence for the principal ideal ⟨G⟩
which is regarded as a graded S-module.
So, for i∈Z, we have
[TABLE]
Thus the Hilbert function of ΩRX/K2 is
[TABLE]
Moreover, it is clear that HFmX:0234⋯μ−1μμ⋯.
By Proposition 2.4, we have the exact
sequence of graded RX-modules
[TABLE]
Hence the Hilbert function of ΩRX/K1 satisfies
HFΩRX/K1(i)=HFmX(i)+HFΩRX/K2(i)
for all i∈Z.
More precisely, it is of the form
[TABLE]
as claimed.
∎
Let us apply this proposition in an explicit example.
Example 3.2**.**
Let X⊆P1 be the 0-dimensional scheme
with the homogeneous vanishing ideal
IX=⟨X1(X1−X0)2(X1−2X0)3⟩.
Clearly, we have s=3 and μ=6 and
HFmX:0234566⋯.
An application of Proposition 3.1 yields
[TABLE]
In this case we have
ri(ΩRX/K1)=ri(ΩRX/K2)=μ+s−1=8.
4. Special Values of the Hilbert Function of ΩRX/Km
In this section we describe the values of the Hilbert function
of the module of Kähler differential
m-forms for a [math]-dimensional scheme X at
some special degrees.
From now on, the coordinates {X0,…,Xn} of Pn
are always chosen such that no point of X lies on
the hyperplane Z+(X0).
By the choice of the coordinates, x0 is a non-zerodivisor
of RX. Moreover, x0 is also a non-zerodivisor
for any nontrivial graded submodule of a graded free
RX-module, as the following lemma shows.
Lemma 4.1**.**
Let d≥1, let δ1,…,δd∈Z,
and let V be a non-trivial graded submodule
of the graded free RX-module
⨁j=1dRX(−δj).
Then x0 is not a zerodivisor for V, i.e.,
if x0⋅v=0 for some v∈V then v=0.
Proof.
Let {e1,…,ed} be the canonical RX-basis
of ⨁j=1dRX(−δj),
and let i∈Z. Then every homogeneous element
v∈Vi has a representation v=g1e1+⋯+gded
for some homogeneous elements g1,…,gd∈RX,
where deg(gj)=deg(v)−δj for j=1,…,d.
Suppose that x0⋅v=0.
This implies that x0g1e1+⋯+x0gded=0, and so
x0g1=⋯=x0gd=0 in RX.
Since x0 is a non-zerodivisor for RX,
we have g1=⋯=gd=0, and hence v=0.
Thus the claim follows.
∎
The number αX=min{i∈N∣(IX)i=0}
is called the initial degree of IX.
Using this notation, some basic properties
of HFΩRX/Km can be summarized as follows.
Proposition 4.2**.**
Let X⊆PKn be a [math]-dimensional scheme,
and let 1≤m≤n+1.
(a)
For i<m, we have HFΩRX/Km(i)=0.
2. (b)
For m≤i<αX+m−1, we have
HFΩRX/Km(i)=(mn+1)⋅(nn+i−m).
3. (c)
The Hilbert polynomial of ΩRX/Km is constant.
4. (d)
We have HFΩRX/Km(rX+m)≥HFΩRX/Km(rX+m+1)≥⋯, and if
ri(ΩRX/Km)≥rX+m then
[TABLE]
Proof.
(a) Obivously, every non-zero homogeneous element ω
of ΩRX/Km has degree deg(ω)≥m,
and hence HFΩRX/Km(i)=0 for all i<m.
(b) Let m≤i<αX+m−1. Notice that
IXΩS/Km⊆dIXΩS/Km−1.
Also, we have (dIXΩS/Km−1)i=⟨0⟩
for all i<αX+m−1, since a non-zero homogeneous
element of dIXΩS/Km−1 is always of the form
∑kdFk∧ωk, where
Fk∈(IX)≥αX
and ωk∈(ΩS/Km−1)≥m−1.
By Proposition 2.2, for all i<αX+m−1,
we obtain
for all i∈Z. Hence the Hilbert polynomial
of ΩRX/Km is a constant polynomial.
(d) The graded RX-module ΩRX/Km
has the following form:
[TABLE]
Observe that (RX)i=x0(RX)i−1 if
i>rX. Thus
(ΩRX/Km)i+m=x0(ΩRX/Km)i+m−1
for all i>rX. So, for all i>rX,
we have the inequality
[TABLE]
Now let G=⟨(∂x0∂F,…,∂xn∂F)∣F∈IX⟩RX.
By [DK, Proposition 1.3] and [SS, X.83],
there is an exact sequence of graded RX-modules
[TABLE]
Suppose i≥rX satisfies
HFΩRX/Km(i+m)=HFΩRX/Km(i+m+1).
Then it follows from the above exact sequence that
[TABLE]
For every j≥rX, HFX(j)=deg(X), and so
HF⋀RXm(RXn+1)(j)=HF⋀RXm(RXn+1)(j+1).
Consequently, we have
[TABLE]
In addition, Lemma 4.1 shows that x0 is
a non-zerodivisor for the graded RX-submodule
G∧RX⋀RXm−1(RXn+1)
of the graded-free RX-module
⋀RXm(RXn+1).
This implies
[TABLE]
In view of [GM, Proposition 1.1], the ideal IX
can be generated by homogeneous polynomials of degrees
≤rX+1.
So, the graded RX-module
G∧RX⋀RXm−1(RXn+1)
is generated in degrees ≤rX. Thus we obtain
[TABLE]
Altogether, we have
HFΩRX/Km(i+m+1)=HFΩRX/Km(i+m+2),
and the claim follows by induction.
∎
The following example shows that HFΩRX/Km(i)
may or may not be monotonic in the range
αX+m≤i≤rX+m.
Example 4.3**.**
Let K=Q, and let X⊆P2
be the set of nine points
X={(1:1:0),(1:1:1),(1:1:2),(1:1:3),(1:1:4),(1:1:5),(1:0:1),(1:2:1),(1:2:2)}.
Notice that X contains six points on a line
and three non-collinear points off that line.
It is clear that
HFX:1367899⋯,
αX=3, and rX=5.
The Hilbert functions of the Kähler differential modules
of RX/K are given by
[TABLE]
We see that HFΩRX/K1(αX+1)=14>13=HFΩRX/K1(αX+2)
and HFΩRX/K1(αX+2)=13<14=HFΩRX/K1(rX+1).
So, HFΩRX/K1(i) is not monotonic in the
range αX+1≤i≤rX+1.
Similarly, HFΩRX/K2(i) is not monotonic
in the range αX+2≤i≤rX+2.
Next we consider the set
Y=X∪{(1:0:2)}.
We have HFY:136891010⋯,
αY=3, and rY=5.
The Hilbert functions of the Kähler differential modules
of RY/K are
[TABLE]
Hence HFΩRY/K1(i) is monotonic
in the range αY+1≤i≤rY+1, and
HFΩRY/K2(i) is also monotonic
in the range αY+2≤i≤rY+2.
5. Bounds for the Regularity Index of ΩRX/Km
In this section we give an upper bound for the regularity
index of the module of Kähler differential m-forms
ΩRX/Km
for a 0-dimensional scheme X in Pn.
To do this, we need the following lemmas.
Lemma 5.1**.**
Let d≥1, let δ1,…,δd∈Z such that
δ1≤⋯≤δd, let
W=⨁j=1dRX(−δj)
be the graded free RX-module, and let V be
a non-trivial graded submodule of W.
Then, for 1≤m≤d, we have
[TABLE]
Proof.
First we note that the Hilbert polynomial of W is
HPW(z)=d⋅deg(X) and
that ri(W)=rX+δd.
This shows that the Hilbert polynomial of V is
a constant polynomial
HPV(z)=u≤d⋅deg(X). Let r=ri(V),
and let v1,…,vu be a K-basis of Vr.
By Lemma 4.1, the elements
{x0iv1,…,x0ivu}
form a K-basis of the K-vector space Vr+i for all
i∈N. We let {e1,…,ed} be the canonical
RX-basis of W, we let t=(md), and we let
{ε1,…,εt} be a basis of the
graded free RX-module ⋀RXm(W)
w.r.t. {e1,…,ed}.
We set δ=δd−m+1+⋯+δd, and let
[TABLE]
Let ϱ=dimKN, and let w1,…,wϱ
be a K-basis of N. It is not difficult to verify that
N=⟨w1,…,wϱ⟩K=(V∧RX⋀RXm(W))δ+r.
Moreover, for any i≥0, the set
{x0iw1,…,x0iwϱ} is K-linearly
independent. Indeed, assume that there are elements
a1,…,aϱ∈K such that
∑j=1ϱx0iajwj=0.
Since x0 is a non-zerodivisor
for V∧RX⋀RXm(W)
by Lemma 4.1, we get
∑j=1ϱajwj=0, and hence
a1=⋯=aϱ=0.
Now it suffices to prove that the set
{x0iw1,…,x0iwϱ} generates
the K-vector space
(V∧RX⋀RXm(W))δ+r+i for all i≥0.
Let w∈(V∧RX⋀RXm(W))δ+r+i
be a non-zero homogeneous element.
Then w=∑j,kvj∧hkεk=∑j,khkvj∧εk
for some homogeneous elements vj∈V
and hk∈RX such that
deg(vj)+deg(hk)=δ+r+i−deg(εk)
for all j,k. Note that
deg(hkvj)=δ+r+i−deg(εk)≥r+i.
Also, we have
[TABLE]
So, there are bjk1,…,bjku∈K such that
hkvj=∑l=1ubjklx0δ+i−deg(εk)vl.
This implies
[TABLE]
for some cjklq∈K. Thus we get
w∈⟨x0iw1,…,x0iwϱ⟩K,
and consequently
HFV∧RX⋀RXm(W)(i)=ϱ for all i≥δ+r.
Therefore ri(V∧RX⋀RXm(W))≤ri(V)+δ, as we wanted to show.
∎
Lemma 5.2**.**
Let V be a graded RX-module generated by the set
of homogeneous elements {v1,…,vd} for some
d≥1. Let δj=deg(vj) for j=1,…,d,
and let m≥1.
Assume that δ1≤⋯≤δd, and set
δ=δd−m+1+⋯+δd if m≤d.
Then the regularity index of ⋀RXm(V) satisfies
ri(⋀RXm(V))=−∞ if m>d and
[TABLE]
if 1≤m≤d. In particular, if 1≤m≤d and
δ1=⋯=δd=t then we have
ri(⋀RXm(V))≤max{rX+mt,ri(V)+(m−1)t}.
Proof.
If m>d, then ⋀RXm(V)=⟨0⟩,
and hence ri(⋀RXm(V))=−∞.
Now we assume that 1≤m≤d.
Obviously, the RX-linear map
α:W=⨁j=1dRX(−δj)→V
given by ej↦vj
is a homogeneous RX-epimorphism of degree zero.
Set G=Ker(α).
According to [SS, X.83], there is
an exact sequence of graded RX-modules
Here the last inequality follows from the fact that
ri(G)≤max{rX+δd,ri(V)}.
∎
Now we are able to give an upper bound for the regularity
index of the module of Kähler differential m-forms
ΩRX/Km.
Proposition 5.3**.**
Let X⊆Pn be a [math]-dimensional scheme,
and let 1≤m≤n+1.
The regularity index of the module of Kähler
differential m-forms ΩRX/Km satisfies
[TABLE]
Proof.
We set G=⟨(∂x0∂F,…,∂xn∂F)∈RXn+1∣F∈IX⟩.
By [DK, Proposition 1.3], we have the short exact sequence
of graded RX-modules
[TABLE]
Applying Lemma 5.2 to the graded RX-module
ΩRX/K1 which is generated by the set
{dx0,…,dxn}, we get
ri(ΩRX/Km)≤max{rX+m,ri(ΩRX/K1)+m−1},
as we wished.
∎
Remark 5.4**.**
We have ri(ΩRX/Kn+1)≤max{rX+n,ri(ΩRX/K1)+n−1}.
Indeed, the exact sequence (K) of graded
RX-modules yields
[TABLE]
Moreover, if we set ϱm=max{rX+m,ri(ΩRX/K1)+m−1}}
for m≥1, then we get the upper bound for
the regularity index of ΩRX/Km as
ri(ΩRX/Km)≤min{ϱn,ϱm}.
6. Bounds for ri(ΩRW/Km)
for a Fat Point Scheme W
Let s≥1, and let X={P1,…,Ps} be a set of
s distinct K-rational points in Pn.
For i=1,…,s, we let ℘i be the associated prime
ideal of Pi in S.
Definition 6.1**.**
Given a sequence of positive integers m1,…,ms,
the intersection IW:=℘1m1∩⋯∩℘sms
is a saturated homogeneous ideal in S and is therefore
the vanishing ideal of a [math]-dimensional subscheme W
of Pn.
(a)
The scheme W, denoted by W=m1P1+⋯+msPs,
is called a fat point scheme in Pn.
The homogeneous vanishing ideal of W is IW.
The number mj is called the multiplicity of
the point Pj for j=1,…,s.
2. (b)
If m1=⋯=ms=ν, we denote W also
by νX and call it an
equimultiple fat point scheme.
3. (c)
For i≥1, the fat point scheme
W(i)=(m1+i)P1+⋯+(ms+i)Ps
is called the i-th fattening of W.
We simple say the fattening of W instead of
the first fattening of W.
The regularity index of the module of Kähler differential
m-forms for fat point schemes can be bounded as follows.
Proposition 6.2**.**
Let W=m1P1+⋯+msPs be a fat point scheme
in Pn, and let V=W(1) be the fattening of W.
(a)
For 1≤m≤n+1, we have
[TABLE]
2. (b)
If m1≤⋯≤ms and if
Supp(W)={P1,…,Ps} is in general position,
then we have
[TABLE]
for 1≤m≤n+1.
Proof.
Claim (a) follows from Remark 5.4
and [KLL, Corollary 1.9(iii)].
Moreover, if Supp(W) is in general position,
then [CTV, Theorem 6] implies that
[TABLE]
Thus claim (b) follows from (a).
∎
The following example shows that the upper bounds
for the regularity index of ΩRW/Km
given in Proposition 6.2 are sharp.
Example 6.3**.**
Let K=Q, and let W be the fat point scheme
[TABLE]
where P1=(1:9:0:0), P2=(1:6:0:1), P3=(1:2:3:3),
P4=(1:9:3:5), P5=(1:3:0:4), P6=(1:0:1:3),
P7=(1:0:2:0), and P8=(1:3:0:10).
Let V be the fat point scheme
V=2P1+3P2+2P3+2P4+3P5+3P6+3P7+2P8.
We have rW=3 and rV=5, and so
max{rW+m,rV+m−1}=m+4 for m=1,…,4.
In this case the regularity index of ΩRW/Km
is m+4 for m=1,…,3 and ri(ΩRW/K4)=7.
Thus the bound for the regularity index in
Proposition 6.2(a) is sharp.
Next let Y be the scheme Y=P4+P5+P6+P7+P8
in P3. Then Y is in general position.
For m=1,2,3, the regularity index of ΩR2Y/Km
is 4+m. Thus, for m=1,2,3, we have
[TABLE]
In addition, for m=4, we have
[TABLE]
and hence the bound in Proposition 6.2(b)
is also sharp.
7. Bounds for the Hilbert Polynomial
of ΩRW/Km for a Fat Point Scheme W
First we determine the Hilbert polynomial of the module
of Kähler differential m-forms for a set of s
distinct K-rational points X={P1,…,Ps}
in Pn. Notice that all points of X are assumed
to lie outside the hyperplane Z+(X0),
so we may write Pj=(1:pj1:⋯:pjn)
with pj1,…,pjn∈K for j=1,…,s.
Furthermore, for every element f∈RX
and j∈{1,…,s}, we also write f(Pj)=F(Pj),
where F is any representative of f in S.
Recall that an element fj∈(RX)rX
is the normal separator of X∖{Pj} in X
if fj(Pj)=1 and fj(Pk)=0 for k=j.
The set
{x0i−rXf1,…,x0i−rXfs}
is a K-basis of (RX)i for all i≥rX.
For more details about separators of a 0-dimensional scheme
in Pn see [GKR, GMT, Kre1, Kre2].
The following proposition gives a description of
the Hilbert polynomial of the module of Kähler differential
m-forms ΩRX/Km for every 1≤m≤n+1.
Proposition 7.1**.**
Let X={P1,…,Ps}⊆Pn be a set of s
distinct K-rational points, and let 1≤m≤n+1. We have
[TABLE]
In particular, the regularity index of ΩRX/Km
satisfies ri(ΩRX/Km)≤2rX+m.
Proof.
For m=1, we have HPΩRX/K1(z)=deg(X) and
ri(ΩRX/K1)≤2rX+1
(see [DK, Proposition 3.5]). Assume that m≥2.
We see that ΩRX/Km is a graded RX-module
generated by the set of (mn+1) elements
[TABLE]
For j∈{1,…,s}, let fj be the normal separator
of X∖{Pj} in X.
Since the set {x0i−rXf1,…,x0i−rXfs}
is a K-basis of the K-vector space (RX)i for
i≥rX, the set
[TABLE]
is a system of generators of the K-vector space
(ΩRX/Km)k for all k≥rX+m.
Note that fj2=fj(Pj)x0rXfi=x0rXfi
and xifj=pjix0fj
(see, e.g., [GKR, Proposition 1.13]).
Therefore we get
[TABLE]
Since m≥2, we may use the same method as above to get
the equality
[TABLE]
This implies
x0rXfjdxi1∧⋯∧dxim=0
for j=1,…,s and
{i1,…,im}⊆{0,…,n}.
Thus we obtain
(ΩRX/Km)k=⟨0⟩
for all k≥2rX+m, and the claim follows.
∎
By combining Corollary 2.5 and
Proposition 7.1, we obtain upper bounds
for the regularity indices of modules of the Kähler
differential m-forms ΩRX/Km as follows.
The preceding bounds for the regularity indices
of ΩRX/Km
are sharp, as our next example shows.
Example 7.3**.**
Let K=Q, and let X⊆P3 be the set of four
K-rational points X={P1,P2,P3,P4}, where
P1=(1:9:0:0), P2=(1:6:0:1), P3=(1:2:3:3), and P4=(1:9:3:5).
It is clear that HFX:144⋯
and rX=1. Moreover, we have
[TABLE]
It follows that
ri(ΩRX/K1)=2rX+m=2rX+1=3,
ri(ΩRX/K2)=2rX+m=2rX+2=4,
and ri(ΩRX/K3)=ri(ΩRX/K4)=min{2rX+m,2rX+n}=2rX+n=5.
Hence we obtain the equality
ri(ΩRX/Km)=min{2rX+m,2rX+n}
for m=1,…,4.
Consequently, the bounds in Corollary 7.2 are sharp.
Now we give bounds for the Hilbert polynomial of the module
of Kähler differential m-forms for a non-reduced fat
point scheme.
Proposition 7.4**.**
Let W=m1P1+⋯+msPs be a fat point scheme
in Pn such that mi≥2 for some i∈{1,…,s},
and let 1≤m≤n+1.
The Hilbert polynomial of ΩRW/Km
is a constant polynomial which is bounded by
[TABLE]
Proof.
Let Y be the subscheme
Y=(m1−1)P1+⋯+(ms−1)Ps of W.
Since we have dIW⊆IYΩS/K1,
this implies
dIWΩS/Km−1⊆IYΩS/Km.
Obviously, we have the inclusion IW⊆IY,
and so IWΩS/Km⊆IYΩS/Km.
From this we deduce
[TABLE]
By Proposition 2.2,
the Hilbert function of ΩRW/Km satisfies
[TABLE]
for all i∈Z.
Also, we see that
HPΩS/Km/IYΩS/Km(z)=∑i=1s(mn+1)(nmi+n−2)>0
since mi≥2 for some i∈{1,…,s}.
Hence we get the stated lower bound for the Hilbert polynomial
of ΩRW/Km.
In particular, we have HPΩRW/Km(z)>0.
Furthermore, Proposition 4.2 shows that
HPΩRW/Km(z) is a constant polynomial.
Now we find an upper bound for HPΩRW/Km(z).
Clearly, the RW-module ΩRW/Km
is generated by the set
{dxi1∧⋯∧dxim∣0≤i1<⋯<im≤n}
consisting of (mn+1) elements. This implies
HFΩRW/Km(i)≤(mn+1)HFW(i−m)
for all i≥0. Hence we get
HPΩRW/Km(z)≤(mn+1)∑i=1s(nmi+n−1),
which completes the proof.
∎
Our next corollary is an immediate consequence
of Propositions 7.1 and 7.4.
Corollary 7.5**.**
Let W=m1P1+⋯+msPs be a fat point scheme
in Pn, and let mmax=max{m1,…,ms}.
The following conditions are equivalent.
(a)
The scheme W is not reduced, i.e., mmax>1.
2. (b)
There exists m∈{2,…,n+1} such that
HPΩRW/Km(z)>0.
3. (c)
HPΩRW/Kn+1(z)>0.
8. The Hilbert Polynomial of
ΩRW/Kn+1 for a Fat Point Scheme W
Given a fat point scheme W=m1P1+⋯+msPs
in Pn, the Hilbert function of
the RW-module ΩRW/K1
satisfies
HFΩRW/K1(i)=(n+1)HFW(i−1)+HFW(i)−HFV(i)
for all i∈Z, where V is the fattening of W
(see [KLL, Corollary 1.9(i)]).
Naturally, we still want to give a formula for
the Hilbert function of the module ΩRW/Km
for m≥2.
In fact, we can calculate the Hilbert function
of ΩRW/Kn+1 in the following special case.
Proposition 8.1**.**
Let W=m1P1+⋯+msPs be a fat point scheme
in Pn supported at a set of points
X={P1,…,Ps}, and let Y be
the subscheme Y=(m1−1)P1+⋯+(ms−1)Ps
of W. Suppose that X is contained in a hyperplane.
Then we have
[TABLE]
In particular, we have
HFΩRW/Kn+1(i)=HFY(i−n−1)
for all i∈Z.
Proof.
Assume that X⊆Z+(H), where
0=H=∑i=0naiXi∈S and
a0,…,an∈K. By letting
I=\big{\langle}\,\frac{\partial F}{\partial X_{i}}\mid F\in I_{{\mathbb{W}}},0\leq i\leq n\,\big{\rangle}
and by Corollary 2.3, we have
[TABLE]
Write IW=℘1m1∩⋯∩℘sms
where ℘j is the associated prime ideal of Pj
in S, and let F∈IW∖{0}.
Clearly, ∂Xi∂F∈℘jmj−1
for i=0,…,n and j=1,…,s, and so
∂Xi∂F∈IY for i=0,…,n.
Consequently, we get I⊆IY.
Now we prove I⊇IY.
Suppose for a contradiction that there exists
a homogeneous polynomial G such that
G∈IY∖I. Then we have HG∈IW.
Since H=0, we may assume that ai=0 for some
i∈{0,…,n}.
We have ∂Xi∂(HG)=aiG+H∂Xi∂G∈I.
Since G∈/I, we deduce
G1:=H∂Xi∂G∈IY∖I.
Futhermore, we continue to have HG1∈IW,
and so
[TABLE]
This implies that
G2:=H2∂Xi2∂2G∈IY∖I.
Repeating this process, we eventually get
Hdeg(G)∈IY∖I.
On the other hand, since G∈IY,
it follows that
deg(G)≥max{m1−1,…,ms−1}.
Thus we have Hdeg(G)+1∈IW, and consequently
Hdeg(G)=ai(deg(G)+1)1∂Xi∂Hdeg(G)+1∈I,
a contradiction. Therefore we get IY=I, and hence
ΩRW/Kn+1≅(S/IY)(−n−1),
as desired.
∎
Let us apply the preceding proposition to a concrete case.
Example 8.2**.**
Let K=Q, and let W and Y be the fat point schemes
W=2P1+3P2+4P3+2P4+P5+7P6+5P7 and
Y=P1+2P2+3P3+P4+6P6+4P7
in P5, where
P1=(1:1:1:1:1:615),
P2=(1:2:1:1:1:617),
P3=(1:1:2:1:1:618),
P4=(1:2:3:4:5:655),
P5=(1:2:2:1:1:620),
P6=(1:3:2:1:1:622),
and where P7=(1:0:0:1:1:610).
Then X={P1,…,P7} is contained in
the hyperplane Z+(X0−4X3+3X4).
Thus Proposition 8.1 yields
ΩRW/K6≅RY(−6). Hence
the Hilbert function of ΩRW/K6 is given by
[TABLE]
Although no formula for the Hilbert function of
the module of Kähler differential (n+1)-forms
of an equimultiple fat point scheme is known, the following
theorem provides a formula for its Hilbert polynomial.
Theorem 8.3**.**
Let X={P1,…,Ps}⊆Pn
be a set of s distinct K-rational points,
and let ν≥1. Then we have
HPΩR(ν+1)X/Kn+1(z)=HPνX(z).
Proof.
Let I=⟨∂Xi∂F∣F∈IX,0≤i≤n⟩.
By Corollary 2.3, we have
ΩRX/Kn+1≅(S/I)(−n−1).
So, Proposition 7.1 implies
HFΩRX/Kn+1(i)=HFS/I(i−n−1)=0
for i≫0. Let M denote the homogeneous
maximal ideal of S. There exists a number t1∈N
such that It1+i=Mt1+i
for all i∈N.
Moreover, by [HC, 4.2], there is t2∈N
such that (IνX)t2+i=(IXν)t2+i
for all i∈N.
Let t=max{t1,t2,rνX+1}, let
r=(nn+t)−s, let {F1,…,Fr}
be a K-basis of the K-vector space (IX)t,
and let
[TABLE]
Clearly, we have
I(ν+1)X⊆J⊆IνX.
Since ΩR(ν+1)X/Kn+1≅(S/J)(−n−1),
and since IνX is generated by elements of
degrees ≤t (cf. [GM, Proposition 1.1]),
it suffices to show that Ji=(IνX)i for
some i≥t.
We observe that
[TABLE]
Here the last two equalities follow from
Euler’s relation and the fact that
(IX)t+1=(IX)tM1=⟨Fj∣1≤j≤r⟩KM1.
(Note that IX can be generated in degrees ≤t.)
Therefore we get equalities
[TABLE]
Thus we only need to prove the inclusion
[TABLE]
To this end, we first prove that
Fj1ν−kFj2⋯Fjk+1∂Xi1∂Fj1⋯∂Xik+1∂Fj1∈J
for all i1,…,ik+1∈{0,…,n} and
j1,…,jk+1∈{1,…,r}
and 0≤k≤ν.
We proceed by induction on k. If k=0, for 0≤i1≤n
and 1≤j1≤r we have
[TABLE]
If k=1, for i1,i2∈{0,…,n} and
j1,j2∈{1,…,r}, we get
[TABLE]
Now we assume that 2≤k≤ν and
Fj1′ν−(k−1)Fj2′⋯Fjk′∂Xi1′∂Fj1′⋯∂Xik′∂Fj1′∈J
for all i1′,…,ik′∈{0,…,n} and
j1′,…,jk′∈{1,…,r}.
Let i1,…,ik+1∈{0,…,n} and
j1,…,jk+1∈{1,…,r}.
We have
[TABLE]
By the inductive hypothesis, we have
Fj1ν−(k−1)FjlFj2⋯Fjk+1∂Xi2∂Fj1⋯∂Xik+1∂Fj1∈J for all l=2,…,k+1.
Hence we get
Fj1ν−kFj2⋯Fjk+1∂Xi1∂Fj1⋯∂Xik+1∂Fj1∈J.
Consequently, if k=ν, then we have
Fj1Fj2⋯Fjν∂Xi1∂Fj⋯∂Xiν+1∂Fj∈J
for all i1,…,iν+1∈{0,…,n} and
j,j1,…,jν∈{1,…,r}.
On the other hand, the K-vector space
⟨∂Xi∂Fj∣0≤i≤n,1≤j≤r⟩Kνr+1
has a system of generators consisting of elements
of the form
[TABLE]
where αij∈N satisfy
∑j=1r∑i=0nαij=νr+1.
Set αj:=∑i=0nαij for j=1,…,r.
Since ∑j=1rαj=νr+1,
there is an index j∈{1,…,r} such that
αj≥ν+1. Also, we have νrn+1≥νr+1.
It follows that any element of the K-vector space
[TABLE]
is a sum of elements of the form
Fj1⋯Fjν∂Xi1∂Fj⋯∂Xiν+1∂FjG,
where i1,…,iν+1∈{0,…,n}, where
j,j1,…,jν∈{1,…,r},
and where G∈S is a homogeneous polynomial of degree
deg(G)=ν(rn−1)(t−1).
Therefore we get
[TABLE]
and this completes the proof.
∎
The following corollary follows immediately
from Theorem 8.3.
Corollary 8.4**.**
Let X={P1,…,Ps}⊆Pn
be a set of s distinct K-rational points, and
let ν≥1. Then we have
HPΩR(ν+1)X/Kn+1(z)=s(nν+n−1).
In the last part of this section we study
the module of Kähler differential 2-forms
of fat point schemes W in Pn.
Let us begin with the following sequence
of graded RW-modules.
Proposition 8.5**.**
Let W=m1P1+⋯+msPs be a fat point
scheme in Pn, and let
W(i) be the i-th fattening of W
for i≥1.
Then the sequence of graded RW-modules
[TABLE]
is a complex, where
α(F+IW(2))=dF+IW(1)ΩS/K1,
where β(GdXi+IW(1)ΩS/K1)=d(GdXi)+IWΩS/K2, and where
γ(H+IWΩS/K2)=H+(IWΩS/K2+dIWΩS/K1).
Moreover, the following statements hold true.
(a)
The map α is injective.
2. (b)
The map γ is surjective.
3. (c)
We have Im(β)=Ker(γ).
4. (d)
For all i≥0, we have
[TABLE]
Proof.
To prove (a), we note that the arguments in the
proof of [KLL, Theorem 1.7] shown that
the map α is a homogeneous injection.
Claims (b) and (c) are implied by the presentation
[TABLE]
Since d∘d=0, it follows that β∘α=0.
Therefore the sequence (C) is a complex.
In addition, claim (d) follows from
the fact that (C) is a complex and (c).
∎
Now we look at the special case of
an equimultiple fat point scheme W=νX
in P2. In this case, by taking the homogeneous
components at a large degree i of the
complex (C), we have the following
exact sequence of K-vector spaces.
Proposition 8.6**.**
Let X={P1,…,Ps}⊆P2 be
a set of s distinct K-rational points, and
let ν≥1. For i≫0, the sequence of
K-vector spaces
[TABLE]
is exact. Here the maps α, β and γ
are defined as in Proposition 8.5.
Proof.
By Proposition 8.5, we only need to prove
Im(α)=Ker(β). Hence it suffices to
show that the Hilbert polynomial of ΩRνX/K2
satisfies
[TABLE]
In P2, Proposition 2.4 yields
the exact sequence of graded RνX-modules
[TABLE]
Moreover, we have
HPΩRνX/K3(z)=HP(ν−1)X(z)
by Theorem 8.3.
Hence, by applying [KLL, Corollary 1.9], we get
[TABLE]
and the claim follows.
∎
The following formula for the Hilbert polynomial
of ΩRνX/K2 can be extracted
from the proof of this proposition.
Corollary 8.7**.**
Let X={P1,…,Ps}⊆P2
be a set of s distinct K-rational points, and
let ν≥1. Then we have
HPΩRνX/K2(z)=21(3ν2−ν−2)s.
In general, we do not have an explicit formula for the
Hilbert polynomial of ΩRW/Kn+1 for
a non-reduced fat point scheme W in Pn.
However, we propose the following conjecture.
Conjecture 8.8**.**
Let W be the fat point scheme
W=m1P1+⋯+msPs in Pn,
and let Y=(m1−1)P1+⋯+(ms−1)Ps.
Then we have
HPΩRW/Kn+1(z)=HPY(z).
The above conjecture holds true for n=1
by Proposition 3.1, and for n≥2
such that W is an equimultiple fat point
scheme in Pn by Theorem 8.3.
The following example provides a further instance
in which the conjecture holds.
Example 8.9**.**
Let X={P1,...,P10} be the set of 10 points
on the twisted cubic curve in P3 given by
P1=(1:1:1:1), P2=(1:−1:1:−1),
P3=(1:2:4:8), P4=(1:−2:4:−8),
P5=(1:3:9:27), P6=(1:−3:9:−27),
P7=(1:4:16:64), P8=(1:−4:16:−64),
P9=(1:−5:25:−125), and P10=(1:6:36:216).
Let W=P1+2P2+4P3+3P4+4P5+2P6+3P7+7P8+5P9+6P10, and let
Y=P2+3P3+2P4+3P5+P6+2P7+6P8+4P9+5P10.
A calculation yields that the Hilbert polynomials
of ΩRW/Kn+1 and of RY
are the same and equal to 141.
9. Fat Point Schemes Supported on Non-Singular Conics
In Proposition 3.1, we described concretely
the Hilbert function of the module of Kähler
differential m-forms when W is a fat point scheme
in P1. This result leads us to the following question:
Question 9.1*.*
Can one compute explicitly the Hilbert function
of the bi-graded RW-algebra
ΩRW/K for a fat point scheme
W=m1P1+⋯+msPs in P2?
In this section we answer some parts of this question.
In particular, we give concrete formulas for the Hilbert
function of the bi-graded algebra ΩRW/K
if W is an equimultiple fat point scheme in P2
whose support X lies on a non-singular conic.
In what follows, we let C=Z+(C)
be a non-singular conic defined by a quadratic polynomial
C∈S=K[X0,X1,X2], we let X={P1,…,Ps}
be a set of s distinct K-rational points on C,
and we let W=m1P1+⋯+msPs be a fat point
scheme in P2 supported at X.
Suppose that 0≤m1≤⋯≤ms and s≥4.
Then it was shown in [Cat, Proposition 2.2] that
the regularity index of W is
[TABLE]
Moreover, the Hilbert function of W can be effectively
computed from the Hilbert function of a certain subscheme
Y of W (see [Cat, Theorem 3.1]).
The Hilbert function of the module of Kähler differential
1-forms ΩRW/K1 satisfies the following
conditions.
Theorem 9.2**.**
In the setting above, let μ=∑j=1smj+s
and ϱ=ms+ms−1.
(a)
If μ≥2ϱ+4 then
[TABLE]
2. (b)
If μ≤2ϱ+3 and
Y:=(m1+1)P1+⋯+(ms−2+1)Ps−2+ms−1Ps−1+msPs, then
[TABLE]
Proof.
Let V be the fat point scheme
V=(m1+1)P1+⋯+(ms+1)Ps
containing W.
By [KLL, Corollary 1.9(i)], we have
[TABLE]
for all i∈Z.
Also, we have
rV=max{ϱ+1,⌊2μ⌋}.
(a) Consider the case μ≥2ϱ+4.
In this case, we have
rV=⌊2μ⌋.
Since s≥4, we get the inequality
[TABLE]
So, [KLL, Corollary 1.9(iii)] yields
ri(ΩRW/K1)≤rV=⌊2μ⌋.
Moreover, we see that
[TABLE]
for all i≥0,
and hence ri(ΩRW/K1)=rV.
Consequently, we can apply [Cat, Theorem 3.1]
to work out the Hilbert function
of ΩRW/K1 with respect to
the value of the degree i as follows:
(i)
For i≥rV=⌊2μ⌋,
the Hilbert function of ΩRW/K1 satisfies
[TABLE]
2. (ii)
Let rW+2≤i<⌊2μ⌋.
Then we have HFW(i−2)=HFW(i−1)=HFW(i)=deg(W)=∑j=1s(2mj+1)
and HFV(i)=2i+1+HFW(i−2).
It follows that
[TABLE]
3. (iii)
In the case i=rW+1, we have
HFW(i−1)=HFW(i)=∑j=1s(2mj+1)
and HFV(i)=2i+1+HFW(i−2). Thus
[TABLE]
4. (iv)
If 0≤i≤rW, we have
HFV(i)=2i+1+HFW(i−2) and
[TABLE]
Altogether, we have proved the formula for
the Hilbert function of ΩRW/K1
in the case μ≥2ϱ+4.
(b) Next we consider the case μ≤2ϱ+3.
In this case, the relation between Hilbert functions
of V and of Y follows from [Cat, Theorem 3.1].
Also, we have rV=ϱ+1
and rW=ϱ−1<rV, and hence
ri(ΩRW/K1)=rV.
Therefore a similar argument as in the first case
yields the desired formula for the Hilbert function
of ΩRW/K1.
∎
It is worth noting that [Cat, Theorem 3.1]
and Theorem 9.2 give us a procedure
for computing the Hilbert function of the module of
Kähler differential 1-forms of RW/K
from some suitable fat point schemes.
Moreover, HFΩRW/K1 is completely
determined by s and the multiplicities m1,…,ms.
Remark 9.3**.**
On a non-singular conic C, let W
be a complete intersection of type (2,d).
Let P∈W, and let Y=W∖{P}.
The regularity index of the scheme Y is d−1.
Using Theorem 9.2 we see that
the Hilbert function of ΩRY/K1
is independent of the choice of the point P.
The following proposition can be used to find out
a connection between the Hilbert functions
of ΩRW/K3
(as well as of ΩRW/K2)
and of a suitable subscheme of W if W
is an equimultiple fat point scheme, i.e.,
if m1=⋯=ms=ν.
This proposition follows from [Cat, Proposition 4.3].
otherwise. Further, let
q=max{ϱ,⌊2μ−s+1⌋},
let {G1,…,Gr} be a minimal
homogenous system of generators of IY,
and let L be the linear form passing through
Ps−1 and Ps.
(a)
If μ−s≥2ϱ and μ−s is odd,
there exist F1,F2∈(IW)q such that
the set {CG1,…,CGr,F1,F2}
is a minimal homogeneous system of generators
of IW.
2. (b)
If μ−s≥2ϱ and μ−s is even,
there exists F∈(IW)q such that
the set {CG1,…,CGr,F} is a minimal
homogeneous system of generators of IW.
3. (c)
If μ−s<2ϱ, there exists
G∈(IW)q such that the set
{LG1,…,LGr,G} is a minimal
homogeneous system of generators of IW.
In particular, if X={P1,…,Ps}
is a set of s distinct K-rational points on
a non-singular conic C, then,
for every k≥1, there is a minimal homogeneous system
of generators of IkX of the following form.
Corollary 9.5**.**
Let s≥4, let X={P1,…,Ps} be
a set of s distinct K-rational points
on a non-singular conic C=Z+(C),
let {C,G1,…,Gt} be a minimal homogeneous
system of generators of IX, and let k≥1.
(a)
If s=2v for some v∈N, then
there exists a minimal homogeneous system of generators
of IkX of the form
[TABLE]
where Fj1∈(IjX)jv for all j=2,…,k.
2. (b)
If s=2v+1 for some v∈N and k is even,
then there exists a minimal homogeneous system of generators
of IkX of the form
[TABLE]
where Fjl∈(IjX)qj with
qj=⌊2j(2v+1)+1⌋
for every j=2,…,k and l=1,2.
3. (c)
If s=2v+1 for some v∈N and k is odd,
then there exists a minimal homogeneous system of generators
of IkX of the form
[TABLE]
where Fjl∈(IjX)qj with
qj=⌊2j(2v+1)+1⌋
for every j=2,…,k and l=1,2.
Proof.
Since s≥4, we have
qk=max{2k,⌊2sk+1⌋}=⌊2sk+1⌋ for every k≥1.
By Proposition 9.4 and by induction on k,
we get the claimed minimal homogeneous system
of generators of the ideal IkX.
∎
Now we present a relation between the Hilbert
functions of the module of Kähler differential
3-forms ΩRνX/K3 and
of S/MI(ν−1)X, where
M=⟨X0,…,Xn⟩
is the homogeneous maximal ideal of S.
Here we make the convention that
I(ν−1)X:=⟨1⟩ if ν=1.
Theorem 9.6**.**
Let s≥4 and ν≥1, and let
X={P1,…,Ps}⊆P2
be a set of s distinct K-rational points
which lie on a non-singular conic
C=Z+(C). Then we have
ΩRνX/K3≅(S/MI(ν−1)X)(−3).
In particular, for all i∈N, we have
[TABLE]
Proof.
Let B1={C,G1,…,Gt} be a minimal
homogeneous system of generators of IX, and let
J(ν)=⟨∂Xi∂F∣F∈IνX,0≤i≤n⟩.
Note that rX=⌊2s⌋.
According to [GM, Proposition 1.1], we may assume that
2≤deg(Gj)≤⌊2s⌋+1
for j=1,…,t.
By Corollary 2.3, we have
ΩRνX/K3≅(S/J(ν−1))(−3).
Moreover, since C is a non-singular conic,
we have ⟨∂Xi∂C∣0≤i≤2⟩=M,
and hence J(1)=M.
Thus it suffices to prove the equality
J(ν+1)=MIνX for all ν≥1.
For k≥2, let Bk be the minimal
homogeneous system of generators of IkX
constructed in Corollary 9.5.
We see that deg(F(k+1)1)≥deg(Fk1)+2
for all k≥2 and that deg(F21)=s.
If s=4 then X is a complete intersection
of type (2,2), and so we may assume
B1={C,G1} with deg(G1)=2.
This implies deg(F21)=deg(G1)+2.
In the case s≥5 we have deg(F21)=s≥⌊2s⌋+3≥max{deg(Gj)∣1≤j≤t}+2.
Hence the inclusion
J(ν+1)⊆MIνX
holds true for all ν≥1.
Now we proceed by induction on ν to prove that
Ck−1MIνX⊆J(ν+k)
for all k≥1. In the following, let k≥1,
0≤i≤2 and 1≤j≤t. If ν=1, we have
[TABLE]
Since ∂Xi∂Gj∈M,
we also have
[TABLE]
Hence we get Ck−1MIX⊆J(1+k)
for all k≥1, and the claim holds true for ν=1.
Next we assume that ν≥2 and that
Ck−1MIlX⊆J(l+k)
for 1≤l≤ν−1 and all k≥1.
We distinguish the following two cases.
Case (a): Suppose that s is even.
Using Corollary 9.5(a) we write
[TABLE]
where Fl1∈(IlX)sl/2.
Note that ∂Xi∂Fl1∈MI(l−1)X for 2≤l≤ν.
It follows from the inductive hypothesis that
Ck+ν−l∂Xi∂Fl1∈Ck+ν−lMI(l−1)X⊆J(ν+k).
Thus, for 2≤l≤ν, we have
[TABLE]
As above we have Ck−1+νM⊆J(ν+k)
and Ck+ν−2G1M⊆J(ν+k).
Therefore we obtain
Ck−1MIνX⊆J(ν+k)
for all k≥1, as desired.
Case (b): Suppose that s is odd.
In this case the minimal homogeneous system of generators
Bν of IνX is given by
[TABLE]
if ν=2l and
[TABLE]
if ν=2l+1, where
Fju∈(IjX)⌊2js+1⌋
(see Corollary 9.5(b),(c)).
Thus we can use the same argument as in case (a)
and get Ck−1MIνX⊆J(ν+k)
for all k≥1.
Altogether, we have shown that
Ck−1MIνX⊆J(ν+k)
for all ν,k≥1.
In particular, if k=1, then we have
MIνX⊆J(ν+1), and
the proof is complete.
∎
If ν=1, we have HFΩRX/K3(i)=0
for i=3 and HFΩRX/K3(3)=1.
If ν≥2, this Hilbert function can be
described explicitly as follows.
Proposition 9.7**.**
In the setting of Theorem 9.6,
let B1={C,G1,…,Gt}
be a minimal homogeneous system of generators
of IX as constructed in Corollary 9.5,
let dj=deg(Gj) for j=1,…,t, and let ν≥2.
Suppose that d1≤⋯≤dt. Then we have
[TABLE]
Here we let hi=#{G∈B1∣deg(G)=i+1−2ν},
and δi is defined as follows.
(a)
If s=4 then δi=ν−2 if i=2ν+1
and δi=0 otherwise.
2. (b)
for all i∈Z. Note that we have
r(ν−1)X=⌊2s(ν−1)⌋.
If i≥r(ν−1)X+3, we obtain
HF(ν−1)X(i−3)=s(2ν).
Otherwise, we have
HF(ν−1)X(i−3)=HFνX(i−1)−2i+1
by [Cat, Theorem 3.1].
For every i≥0, we set
[TABLE]
Hence the claimed shape of the Hilbert function
of ΩRνX/K3 follows immediately.
Now we apply Corollary 9.5 to
compute the values of δi.
We look at degrees of the elements in the tuple
[TABLE]
and get the tuple of degrees
[TABLE]
Consider the following cases.
(a) Suppose that s=4.
Then B1={C,G1} with deg(G1)=2
and every element in A∗ equals 2ν−2.
Also, #(Bν−1)i−3>0 only if
i−3=2ν−2. In the case i=2ν+1, we have
#(Bν−1)i−3=ν and hi=2,
and so δi=ν−2.
Clearly, δi=0 if i=2ν+1.
(b) Suppose that s=5. We write
deg(Cν−(k+1)Fk1)=2ν−2(k+1)+⌊25k+1⌋
for k=2,…,ν−1. It is easy to see that
deg(Cν−(k+1)Fk1)=deg(Cν−(k+2)Fk+11)
if k is odd and deg(Cν−(k+1)Fk1)+1=deg(Cν−(k+2)Fk+11) otherwise.
(i)
If ν is even then we have
[TABLE]
(ii)
If ν is odd then we have
[TABLE]
(c) Suppose that s≥6.
In this case the sequence of elements in A∗
is strictly increasing.
(i)
If s is even then
[TABLE]
(ii)
If s is odd then
[TABLE]
Altogether, the claims follow.
∎
Example 9.8**.**
Let K=Q, and let X={P1,…,P8}⊆P2
be the set of 8 points given by
P1=(1:1:0), P2=(1:3:0),
P3=(1:0:1), P4=(1:4:1),
P5=(1:0:3), P6=(1:1:4),
P7=(1:4:3), and P8=(1:3:4).
Then X is contained in the non-singular conic
defined by C=3X02−4X0X1+X12−4X0X2+X22.
In particular, X is a complete intersection
of type (2,4), and hence the set B1
constructed in Corollary 9.5 is of the form
B1={C,G1} with deg(G1)=4.
The Hilbert functions of νX, 1≤ν≤3,
are given by
[TABLE]
Moreover, we have
HFΩRX/K3:000100⋯.
Now we apply Proposition 9.7 to
compute the Hilbert functions
of ΩRνX/K3, where ν=2,3.
Since s=8 is even, we have
Therefore we get
HFΩR3X/K3:00013610151823252424⋯.
Proposition 9.9**.**
Let s≥4 and ν≥1, and let
X={P1,…,Ps}⊆P2
be a set of s distinct K-rational points
which lie on a non-singular conic
C=Z+(C).
For i≥0, let hi,δi be defined
as in Proposition 9.7.
(a)
If ν=1, we have
[TABLE]
2. (b)
For every ν≥2, let
μ=⌊2sν⌋+2
and t=⌊2s(ν−1)⌋+3.
Then we have
[TABLE]
Proof.
Clearly, HFΩRνX/K2(i)=0
for i≤1. By Proposition 2.4,
we have an exact sequence of graded
RνX-modules
We consider the case ν=1.
We see that HF2X(3)=10, so
HFΩRX/K2(3)=3HFX(2)−10+1=3HFX(2)−9.
For i<s and i=3, we have
HFΩRX/K2(i)=3HFX(i−1)−(2i+1+HFX(i−2)).
For i≥s we get
HFΩRX/K2(i)=3HFX(i−1)−HF2X(i)=3s−3s=0.
Thus claim (a) follows.
for i≥⌊2s(ν+1)⌋.
If i<⌊2s(ν+1)⌋, then
HF(ν+1)X(i)=2i+1+HFνX(i−2)
by [Cat, Theorem 3.1].
So, for μ≤i<⌊2s(ν+1)⌋,
we have
[TABLE]
For t≤i<μ, we get
[TABLE]
For i<t, it follows from Proposition 9.7
again that
[TABLE]
Therefore claim (b) is completely proved.
∎
To end this section, we apply the preceding proposition
to compute the Hilbert function of ΩRνX/K2
in a concrete case.
Example 9.10**.**
Let X be the complete intersection given
in Example 9.8. For 1≤ν≤3,
an application of Proposition 9.9 yields
[TABLE]
10. The Kähler Differential Algebra of RX/K[x0]
Given a [math]-dimensional scheme X⊆Pn
such that no point in its support is contained in the
hyperplane Z+(X0), the element x0=X0+IX
is a non-zerodivisor of RX. Hence there is a short exact
sequence of graded RX-modules
[TABLE]
(see [Kun, Proposition 3.24]).
As noted in Section 2, the homogeneous RX-linear map
γ:ΩRX/K1→RX
satisfies γ(dxi)=xi for all i=0,…,n.
If fdx0=0 for some homogeneous element f∈RX,
then γ(fdx0)=fx0=0, and so f=0,
since x0 is a non-zerodivisor of RX.
Hence we have AnnRX(dx0)=⟨0⟩.
Consequently, we obtain
[TABLE]
for all i∈Z and
ri(ΩRX/K[x0]1)≤max{rX+1,ri(ΩRX/K1)}.
Thus the Hilbert functions of ΩRX/K1
and ΩRX/K[x0]1 are strongly related,
and it is straightforward to transfer our earlier results to results
about ΩRX/K[x0]m.
For instance, for a [math]-dimensional subscheme of P1,
an application of Proposition 3.1 yields
the following property.
Proposition 10.1**.**
Let X⊆P1 be a [math]-dimensional scheme,
and let IX=⟨F⟩, where
F=∏i=1s(X1−aiX0)mi for some s,
m1,…,ms≥1, and ai∈K with ai=aj
for i=j, and let μ=∑i=1smi.
Then the Hilbert functions of the modules of Kähler
differential m-forms of RX/K[x0] are given by
[TABLE]
and HFΩRX/K[x0]2(i)=0 for all i∈Z.
In general, for 1≤m≤n+1,
the module of Kähler differential m-forms
ΩRX/K[x0]m has a presentation
ΩRX/K[x0]m≅ΩS/K[x0]m/(IXΩS/K[x0]m+dS/K[x0]IXΩS/K[x0]m−1)
(cf. [Kun, Proposition 4.12]).
Moreover, according to [SS, X.83], the above exact
sequence induces an exact sequence of graded
RX-modules
[TABLE]
By using these results and by applying the methods given
in Propositions 4.2, 5.3,
6.2 and 7.4, we get the
following properties for the Hilbert function and
regularity index of ΩRX/K[x0]m.
We leave the detailed proofs of these properties to
the interested reader.
Proposition 10.2**.**
Let X⊆PKn be a [math]-dimensional scheme,
and let 1≤m≤n+1.
(a)
For i<m, we have
HFΩRX/K[x0]m(i)=0.
2. (b)
For m≤i<αX+m−1, we have
HFΩRX/K[x0]m(i)=(mn)⋅(nn+i−m).
3. (c)
The Hilbert polynomial
of ΩRX/K[x0]m is constant.
4. (d)
We have
HFΩRX/K[x0]m(rX+m)≥HFΩRX/K[x0]m(rX+m+1)≥⋯, and if
ri(ΩRX/K[x0]m)≥rX+m then
[TABLE]
5. (e)
The regularity indices of ΩRX/K[x0]m
satisfies
[TABLE]
Finally, for non-reduced fat point schemes in Pn,
the Hilbert function and regularity index
of ΩRW/K[x0]m have the following properties.
Proposition 10.3**.**
Let W=m1P1+⋯+msPs be a fat point scheme
in Pn, and let V be the fattening of W.
Suppose that mi≥2 for some
i∈{1,…,s}, and let 1≤m≤n+1.
(a)
The Hilbert polynomial
of ΩRW/K[x0]m is bounded by
[TABLE]
2. (b)
We have
[TABLE]
3. (c)
If m1≤⋯≤ms and
Supp(W)={P1,…,Ps} is in
general position, then
[TABLE]
Acknowledgment
This paper is partially based on
the second author’s dissertation [Lin].
The authors are grateful to Lorenzo Robbiano
for his encouragement to elaborate
some of the results presented here.
The first author thanks Hue University’s College
of Education (Vietnam) for the hospitality he experienced
during part of the preparation of this paper.
The second author would also like to acknowledge
her financial support from OeAD.
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