Weighted Hardy's inequalities and Kolmogorov-type operators
Anna Canale, Federica Gregorio, Abdelaziz Rhandi, Cristian Tacelli

TL;DR
This paper establishes general conditions for weighted Hardy inequalities with respect to probability measures, determines the optimal constants, and explores their connection to Kolmogorov equations with singular potentials, including existence of solutions.
Contribution
It provides new criteria for weighted Hardy inequalities involving probability measures and links these to Kolmogorov operators with singular potentials, including optimal constant determination.
Findings
Derived conditions for weighted Hardy inequalities with probability measures.
Identified the optimal constant for the inequality.
Connected inequalities to the existence of solutions for perturbed Kolmogorov equations.
Abstract
We give general conditions to state the weighted Hardy inequality \[ c\int_{\mathbb{R}^N}\frac{\varphi^2} {|x|^2}d\mu\leq\int_{\mathbb{R}^N}|\nabla \varphi |^2 d\mu+C\int_{\mathbb{R}^N} \varphi^2d\mu,\quad \varphi\in C_c^{\infty}(\mathbb{R}^N),\,c\leq c_{0,\mu}, \] with respect to a probability measure . Moreover, the optimality of the constant is given. The inequality is related to the following Kolmogorov equation perturbed by a singular potential \[ Lu+Vu=\left(\Delta u+\frac{\nabla \mu}{\mu}\cdot \nabla u\right)+\frac{c}{|x|^2}u \] for which the existence of positive solutions to the corresponding parabolic problem can be investigated. The hypotheses on allow the drift term to be of type with .
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Taxonomy
TopicsAdvanced Mathematical Physics Problems · Advanced Harmonic Analysis Research · Spectral Theory in Mathematical Physics
Weighted Hardy’s inequalities and Kolmogorov-type operators
A. Canale
Dipartimento di Ingegneria dell’Informazione, Ingegneria Elettrica e Matematica Applicata, Universitá degli Studi di Salerno, Via Giovanni Paolo II, 132, I 84084 FISCIANO (Sa), Italy.
,
F. Gregorio
Facultät für Mathematik und Informatik, FernUniversität in Hagen, Universitätst. 11, 58084 Hagen, Germany.
,
A. Rhandi
Dipartimento di Ingegneria dell’Informazione, Ingegneria Elettrica e Matematica Applicata, Universitá degli Studi di Salerno, Via Giovanni Paolo II, 132, I 84084 FISCIANO (Sa), Italy.
and
C. Tacelli
Dipartimento di Ingegneria dell’Informazione, Ingegneria Elettrica e Matematica Applicata, Universitá degli Studi di Salerno, Via Giovanni Paolo II, 132, I 84084 FISCIANO (Sa), Italy.
Abstract.
We give general conditions to state the weighted Hardy inequality
[TABLE]
with respect to a probability measure . Moreover, the optimality of the constant is given. The inequality is related to the following Kolmogorov equation perturbed by a singular potential
[TABLE]
for which the existence of positive solutions to the corresponding parabolic problem can be investigated. The hypotheses on allow the drift term to be of type with .
2010 Mathematics Subject Classification:
35K15, 35K65, 35B25, 34G10, 47D03
The authors are members of the Gruppo Nazionale per l’Analisi Matematica, la Probabilitá e le loro Applicazioni (GNAMPA) of the Istituto Nazionale di Alta Matematica (INdAM)
1. Introduction
We denote by be the Kolmogorov operator
[TABLE]
defined on smooth functions. In the standard setting one considers for some and for all . In this case the elliptic operator has coefficients belonging to . Therefore, one can associate to a semigroup (not necessary strongly continuous) in the space of bounded continuous functions, cf. [5]. Considering the measure and the weighted space , the operator can also be defined via the bilinear form
[TABLE]
on , the Sobolev space of functions whose weak derivatives belong to Indeed, integrating by parts we get
[TABLE]
In particular, for every . Then is an invariant measure of and hence can be extended to a positivity preserving and analytic -semigroup on (see for example [5]).
Recently in [12] and [11], a special class of operators of type perturbed by the inverse square potential was considered and the associated evolution equation
[TABLE]
was studied.
It is well known that the potential is highly singular in the sense that it belongs to a borderline case where the strong maximum principle and Gaussian bounds fail, cf. [3]. Moreover, it is not in the Kato class potentials. If , then the initial value problem is well-posed. But for the problem may not have positive solutions. In [4] Baras and Goldstein show that the evolution equation associated to admits a unique positive solution if and no positive solutions exist if (see also [7]). When it exists, the solution is exponentially bounded, on the contrary, if , there is the so called instantaneous blowup phenomena.
Replacing the Laplacian by the Kolmogorov operator a similar behaviour was obtained in [12]. The result was given using a relation between the weak solution of and the bottom of the spectrum of the operator
[TABLE]
Cabré and Martel in [7] show that the boundedness of is a necessary and sufficient condition for the existence of positive and exponentially bounded in time solutions to the associated initial value problem. This result was extended in [12] to the operator .
For Ornstein-Uhlenbeck type operators , , , perturbed by multipolar inverse square potentials a weighted multipolar Hardy inequality and related existence and nonexistence results were stated in [8]. In such a case the invariant measure for these operators is .
Assuming that is a probability density on we recall the following result, see [12, Theorem 2.1].
Theorem 1.1**.**
If . Then the following hold:
- (i)
*If , then there exists a nonnegative weak solution *
* of satisfying*
[TABLE]
for some constants and . 2. (ii)
If , then for any there is no nonnegative weak solution of satisfying (1).
The existence of positive solutions to is related to Hardy’s inequality on the weighted space . The nonexistence of solutions is due to the optimality of the constant in the Hardy inequality. Therefore, studying the bottom of the spectrum is equivalent to studying the weighted Hardy inequality
[TABLE]
and the sharpness of the best constant possible.
A special case is given when , where is a positive real Hermitian matrix and is a normalizing constant. The operator becomes the well-known symmetric Ornstein-Uhlenbeck operator . Using this approach it was proved in [12] that if , then there exists an exponentially bounded weak solution provided that , and no positive exponentially bounded weak solution exists if .
The result was generalized in [11] for the density measure with . Furthermore, under more general hypotheses on the argument was extended to a larger class of Kolmogorov operators, including the case with and , for a suitable constant which is not the optimal one.
In this paper we generalize these results for a larger class of measures , including the case with and obtaining also the optimality of the constant. We observe that such requires to satisfy more general hypotheses, which allow degeneracy at one point. Indeed, for such a measure does not belong to since the gradient is not bounded in [math]. Then, we will consider measures which are not necessarily -Hölderian in the whole space but such that . Firstly, we need that the unperturbed operator generates a semigroup. Hence, further conditions on are required in order to guarantee generation results on . We consider the following hypotheses.
Hypothesis :
- i)
; 2. ii)
, , and for any compact .
By [2, Corollary 3.7] we have that the closure of on generates a strongly continuous Markov semigroup on , which is also analytic. Thanks to this result we can claim that, under Hypothesis , Theorem 1.1 holds.
The second step is, then, to obtain a weighted Hardy inequality. To this purpose we observe that the operator in is equivalent to the Schrödinger operator in , where
[TABLE]
Indeed, taking the transformation we have . Now, roughly speaking, if we expect Hardy’s inequality to hold if in a neighbourhood of the origin, that is .
Thus, we consider the following hypothesis on .
Hypothesis :
- i)
, , ; 2. ii)
the constant
[TABLE]
is finite; 3. iii)
for every the function
[TABLE]
is bounded from above in ; 4. iv)
there exists a such that
[TABLE]
Under the assumption we obtain the weighted Hardy inequality (2) for any . If condition of is not satisfied we still obtain the weighted Hardy inequality if we only assume
**Hypothesis : **
Conditions of hold.
In this case the constant is not achieved and we obtain (2) for any
As regards the optimality, we consider the following hypothesis.
**Hypothesis : **
- i)
- ii)
There exists \sup_{\delta\in\mathbb{R}}\big{\{}\frac{1}{|x|^{\delta}}\in L^{1}_{loc}(\mathbb{R}^{N},d\mu)\big{\}}=:N_{0}.
Under condition Hardy’s inequality does not hold if . If, instead, we have
**Hypothesis : ** Conditions and of hold and
- iii)
[TABLE]
then the inequality does not hold if .
It is obvious that we have the best result when and (respectively and ) hold and the constant coincides with the constant .
Therefore, we can state our main results.
Theorem 1.2**.**
Assume assumptions and and . Then the weighted Hardy inequality (2) holds if and only if .
Theorem 1.3**.**
Assume assumptions and with and . Then (2) holds if and only if .
Finally, putting together the weighted Hardy inequality (2) and Theorem 1.1, we can state the following.
Theorem 1.4**.**
Assume that hypotheses , and hold with and , then the following assertions are satisfied:
- (i)
*If , then there exists a weak solution of satisfying *
[TABLE]
for some constants , , and any . 2. (ii)
If , then for any there is no positive weak solution of with satisfying (3).
If instead, assumptions and with are fulfilled, the same statement holds but the constant is not achieved.
These hypotheses on the measure allow us to treat the case
[TABLE]
for , associated to the operator
[TABLE]
since one can see that satisfies , and with constant . Therefore, for such , Theorem 1.4 holds.
Moreover, under the same assumptions, one can also consider the measures . For such measures Hypothesis is not fulfilled, however we obtain the weighted Hardy inequality with best constant. Indeed, also in this case, the constant of coincides with the best constant of and it depends upon the parameter with . We have explicitly and .
For we recover the well known Caffarelli-Nirenberg inequality
[TABLE]
For measures behaving like a logarithm near the origin
[TABLE]
we obtain (2) with constant . If the constant is achieved and it is the best one. Indeed, satisfies , and provided that . If instead then satisfies , and . So, the constant is not achieved, but it still is the best one.
Finally, we also provide an example in which the constant in (2) of does not coincide with the optimal one of .
2. Weak solutions and bottom of the spectrum
In this section we prove that, under condition on , Theorem 1.1 holds. Firstly we observe that is dense in . This is given by the condition (see [15, Theorem 1.1] ) which is ensured by Hypothesis of . Indeed, implies and . Moreover, implies . Then and
[TABLE]
for every compact set . Moreover, one also obtains that is dense in by Hypothesis of (see the Appendix).
Now, we precise the definition of weak solutions. Let us recall the problem
[TABLE]
We say that is a weak solution to if, for each , we have
[TABLE]
[TABLE]
for all having compact support with , where denotes the open ball of of radius and center [math] and for , we write for .
Theorem 1.1 is based on Cabré-Martel’s idea and it was proved in [12, Theorem 2.1] for measures belonging to . The proof relies on certain properties of the operator and its corresponding semigroup in . Furthermore, the strict positivity on compact sets of , if is required.
Hence, in order to claim that Theorem 1.1 holds in our situation, we only have to ensure that these properties hold. This is stated in Proposition 2.1 and Lemma 2.2 below.
We recall that the measure is the infinitesimally invariant measure for the operator , i.e.
[TABLE]
Moreover, the operator is symmetric on , i.e.
[TABLE]
Hence, by [2, Corollary 3.7], we have that the closure of on generates a strongly continuous Markov semigroup on , which is also analytic.
Let be the self-adjoint operator defined by the closure of on .
Proposition 2.1**.**
The following assertions hold.
- i)
.
- ii)
For every we have
[TABLE]
- iii)
* for all .*
Proof.
i) and ii). Let . Then there exists such that in and in By (5) we have
[TABLE]
Then, converges to a function . On the other hand, one has
[TABLE]
for every . Taking the limit for , since and , we have
[TABLE]
By a density argument, this holds true for any
It remains to show that the components of are the weak derivatives of Fixing , one obtains
[TABLE]
Then, taking the limit as , one has
Indeed,
[TABLE]
where Similarly we have .
Assertion iii) follows from the analyticity of the semigroup (cf. [9, Theorem II.4.6], [10, Lemma 1.3.3]).
∎
Since is dense in , where , we can prove the following Lemma.
Lemma 2.2**.**
Let be a nonnegative function belonging to . Let be a nonnegative weak solution of . Then, for every compact set and there exists (not depending on such that
[TABLE]
Proof.
Let nonnegative and let be a nonnegative weak solution of . Let such that and let such that .
Consider the problem
[TABLE]
Then Problem admits a solution . Moreover,
[TABLE]
where is a strictly positive and continuous function on . Let . We have for every
[TABLE]
Furthermore, is a weak solution to in . In particular, for all with having compact support with , we have
[TABLE]
Comparing with (4), one obtains
[TABLE]
Fix , and consider the parabolic problem
[TABLE]
By [13, Theorem IV.9.1], one obtains a solution . By a standard argument, one can insert the solution in (6). Therefore,
[TABLE]
for all . Thus,
[TABLE]
Since the last inequality holds for any one obtains
[TABLE]
∎
Therefore, we can state the following theorem, for which we omit the proof because it is similar to that of Theorem 1.1, see [12, Theorem 2.1].
Theorem 2.3**.**
Assume that satisfies Hypothesis . Let . Then the following hold:
- (i)
*If , then there exists a nonnegative weak solution *
* of satisfying*
[TABLE]
for some constants and . 2. (ii)
If , then for any there exists no nonnegative weak solution of satisfying (7).
3. The Hardy inequality
Let be a positive measure (not necessary a probability measure) with density . Let us recall the definition of and the potential . We set
[TABLE]
and
[TABLE]
Consider
[TABLE]
So, we have
[TABLE]
We start by proving of the following improved Hardy inequality.
Proposition 3.1**.**
Assume of . Then, for any , the following inequality holds
[TABLE]
Proof.
One has
[TABLE]
By Minkowski’s inequality for integrals and by a change of variables we have
[TABLE]
Hence,
[TABLE]
Then, (9) follows from the relation
[TABLE]
∎
We recall, under assumption of , that is dense in . If moreover is bounded from above, the result below is a direct consequence of (9).
Corollary 3.2**.**
Assume of and assume that there exists such that . Then, for any ,
[TABLE]
If instead of the boundedness from above of in , we assume bounded only for large enough (that is ), then the following result holds.
Theorem 3.3**.**
Let us assume that Hypothesis holds, then for every there exists such that for any the weighted Hardy inequality holds
[TABLE]
Proof.
Since , it follows that for every there exists such that for all . Moreover, there exists depending on such that for every Then, by Proposition 3.1, we have
[TABLE]
The result follows by taking . ∎
We look now for weaker conditions with respect to the boundedness from above for in in order to get (10). To this purpose, we have to consider improved Hardy’s inequalities.
The first step is to state a relation between the weighted Hardy inequality and a special improved Hardy’s inequality.
Lemma 3.4**.**
Assume of , and the improved Hardy inequality
[TABLE]
Then, the weighted Hardy inequality holds
[TABLE]
Proof.
Let and set with compact support. By (11), which holds by density for such a function , integrating by parts and recalling the expression (8) for , one obtains
[TABLE]
Then, inequality (12) follows. ∎
Now, our aim is to prove (11). Brezis and Vázquez in [6] proved the following inequality
[TABLE]
with , for a bounded domain and for every . From this, by Hölder’s inequality, it follows an inequality of type
[TABLE]
with potential belonging to for . This gives us the desired result (12), but forces us to suppose .
Therefore, in order to prove (11), we will refer to the following improved Hardy inequality, see [14], [1].
Theorem 3.5**.**
For any the following inequality holds
[TABLE]
Now, we suppose that and satisfy condition . We finally obtain the weighted Hardy inequality (12).
Theorem 3.6**.**
Assume that Hypothesis holds. Then for any , the following inequality holds
[TABLE]
Proof.
By Proposition 3.4, we need to prove that
[TABLE]
By Hypothesis on , there exists a (otherwise one takes ) such that in . Then, for , by Theorem 3.5 and a change of variables, one has
[TABLE]
Let and , , such that in e in , and . Note that such a function exists. For instance, one can consider a translation and a dilatation of the function for and equals to 0 for .
Therefore, by (3) and Hypotesis , one obtains
[TABLE]
∎
Remark 3.7**.**
For define Take if and if . Then, by Theorem 3.6 (resp. Theorem 3.3), Inequality (2) with constant (resp. ) holds provided that (respectively ) is satisfied.
4. Optimality of the constant in the weighted Hardy inequality
In this section we give conditions in order to prove the sharpness of the constant in (2).
Theorem 4.1**.**
Let us assume Hypothesis . Then, there exists a function in for which the weighted Hardy inequality (2) does not hold if .
Proof.
Let be such that so that and from the definition of it follows that and .
Let and , , in and in . Set . We observe that
[TABLE]
The functions are in .
Let us assume that , then we have to prove that the bottom of the spectrum of the operator
[TABLE]
is . To this purpose we have
[TABLE]
On the other hand,
[TABLE]
Taking into account (4) and (15) we have
[TABLE]
We observe that . Taking the limit we get
[TABLE]
Hence . ∎
Therefore we obtain the following result.
Theorem 4.2**.**
Assume hypotheses and with . Then for any the following inequality holds
[TABLE]
and is the best constant.
If Hypotesis with holds, one obtains the following theorem.
Theorem 4.3**.**
Let us assume Hypothesis with . Then, there exists a function in for which the weighted Hardy inequality (2) does not hold if .
Proof.
Let be such that so that and and . Let , , in and in . Set . We observe that .
Let us set . We have to prove that
[TABLE]
is . One has
[TABLE]
On the other hand,
[TABLE]
Taking into account (4) and (17), we have
[TABLE]
Now, taking the limit , by Hypothesis , one obtains
[TABLE]
Then . ∎
Therefore, we obtain the following result.
Theorem 4.4**.**
Assume hypotheses and with and . Then for every the following inequality holds
[TABLE]
for all and is the best constant.
In conclusion, we have proved Theorem 4.2 and 4.4 which, together with Theorem 2.3, give Theorem 1.4.
5. Examples
We finally give some examples of measures for which the weighted Hardy inequality holds.
Proposition 5.1**.**
Let with , and . Then there exists a positive constant such that for all the following inequality
[TABLE]
holds with best constant.
Proof.
This measure satisfies assumptions and of . Then, by a simple computation one obtains
[TABLE]
and . Therefore, , is a bounded from above far from [math] and assumptions and are satisfied with . Then the assertion follows from Theorem 4.2. Moreover, satisfies also Hypothesis . ∎
Proposition 5.2**.**
Let us consider with as in Proposition 5.1, and . Then there exists a constant such that for all
[TABLE]
*holds with best constant. *
Proof.
This measure satisfies assumptions and of if . Moreover, by a simple computation, one has and
[TABLE]
Then and hold with , . The result follows from Theorem 4.2. ∎
By taking in Proposition 5.2 we can also state the Caffarelli-Nirenberg inequality.
Corollary 5.3**.**
If and then the following inequality holds
[TABLE]
The following is an example for a weight which behaves like logarithm near [math].
Proposition 5.4**.**
Let with such that on and on . Assume that
[TABLE]
If , then there exists a constant such that for all
[TABLE]
holds with best constant.
If , then there exist such that for all
[TABLE]
holds for every and is the best constant.
Proof.
One has that satisfies assumptions and with and for all . Moreover, satisfies if and only if and satisfies if and only if . Indeed, by a simple computation, one obtains
[TABLE]
We have , then the constant in Hardy’s inequality is . By (18) it is easy to check that assumption is satisfied if and only if Then, for Theorem 4.2 applies.
Now, to show that is satisfied for it suffices to prove that
[TABLE]
for some positive . To this purpose we have
[TABLE]
The second term is uniformly bounded for every . As regards the first term, it grows to infinity for if and only if Therefore, for , the assertion follows from Theorem 4.4. ∎
Finally, in the following example the constants and do not coincide.
Proposition 5.5**.**
Let be the density where
[TABLE]
and a nonnegative smooth function such that . Then satisfies , and with .
Proof.
We have
[TABLE]
Moreover, it can be seen that . Hence, . Since is bounded and positive, we have
[TABLE]
for some and for every and . Then ∎
6. Appendix
Let be a positive measure and . Set and for .
Proposition 6.1**.**
Let , where . If
[TABLE]
then is dense in .
Proof.
Let . We have to approximate with functions in with respect to the norm .
Let such that , and set . We observe that pointwisely in and . We have
[TABLE]
The first term of the right hand side converges to [math] by dominated convergence. As regards the second one we have
[TABLE]
So, the first integral converges to [math] by dominated convergence, the last one by Condition (19). Thus,
[TABLE]
∎
Corollary 6.2**.**
Let . If then is dense in .
Proof.
By Proposition 6.1, it suffices to verify Condition (19). Let us observe first that since , by Sobolev’s embedding theorem, it follows that with .
Then,
[TABLE]
One can easily verify that if ∎
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