One dimensional estimates for the Bergman kernel and logarithmic capacity
Zbigniew B{\l}ocki, W{\l}odzimierz Zwonek

TL;DR
This paper provides quantitative estimates relating the Bergman kernel, logarithmic capacity, and Green function sublevel sets, extending classical results and exploring their geometric implications for complex domains.
Contribution
It offers new bounds connecting the Bergman kernel and logarithmic capacity, and generalizes examples of non-convexity of Green function sublevel sets.
Findings
Quantitative bounds for the Bergman kernel in terms of logarithmic capacity.
Counterexamples showing non-convexity of Green function sublevel sets.
Extension of the Suita conjecture to broader classes of domains.
Abstract
Carleson showed that the Bergman space for a domain on the plane is trivial if and only if its complement is polar. Here we give a quantitative version of this result. One is the Suita conjecture, established by the first-named author in 2012, the other is an upper bound for the Bergman kernel in terms of logarithmic capacity. We give some other estimates for those quantities as well. We also show that the volume of sublevel sets for the Green function is not convex for all regular non simply connected domains, generalizing a recent example of Forn\ae ss.
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Taxonomy
TopicsHolomorphic and Operator Theory · Meromorphic and Entire Functions · Algebraic and Geometric Analysis
One dimensional estimates
for the Bergman kernel
and logarithmic capacity
Zbigniew Błocki, Włodzimierz Zwonek
Uniwersytet Jagielloński
a Instytut Matematyki
a Łojasiewicza 6
a 30-348 Kraków
a Poland
Abstract.
Carleson showed that the Bergman space for a domain on the plane is trivial if and only if its complement is polar. Here we give a quantitative version of this result. One is the Suita conjecture, established by the first-named author in 2012, the other is an upper bound for the Bergman kernel in terms of logarithmic capacity. We give some other estimates for those quantities as well. We also show that the volume of sublevel sets for the Green function is not convex for all regular non simply connected domains, generalizing a recent example of Fornæss.
Key words and phrases:
Bergman kernel, logarithmic capacity, Suita conjecture
2010 Mathematics Subject Classification:
30H20, 30C85, 32A36
The first named author was supported by the Ideas Plus grant no. 0001/ID3/2014/63 of the Polish Ministry of Science and Higher Education and the second named author by the Polish National Science Centre (NCN) Opus grant no. 2015/17/B/ST1/00996
1. Introduction
For , where is a domain in , Carleson [7] (see also [8]) showed the Bergman space of square integrable holomorphic functions in is trivial if and only if the complement is polar. The estimate conjectured by Suita [12] and proved in [4]
[TABLE]
gives a quantitative version of one of the implications. Here
[TABLE]
is the logarithmic capacity of with respect to ,
[TABLE]
is the (negative) Green function,
[TABLE]
is the Bergman kernel on the diagonal and .
Our first result is the following upper bound for the Bergman kernel:
Theorem 1**.**
Let be a domain in and . Assume that . Then
[TABLE]
As a consequence we will obtain the following quantitative version of the other implication in the Carleson characterization:
Theorem 2**.**
There exists a uniform constant such that for , where is a domain in , we have
[TABLE]
We will also consider the following counterparts of the Bergman kernel for higher derivatives for
[TABLE]
We will prove the following generalization of (1):
Theorem 3**.**
For and we have
[TABLE]
The inequality is optimal, one can easily check that the equality holds for , the unit disc, and .
It is clear that the dimension of is infinite if and only if, for a given , there exists infinitely many ’s such that . Therefore, Theorem 3 gives a quantitative version of a result of Wiegerinck [13] who showed that if is not polar then is infinitely dimensional.
Since the proof of Theorem 2 also easily gives the upper bound
[TABLE]
and by Proposition 6 below we have the following characterization of domains in dimension one:
Theorem 4**.**
For and the following are equivalent
i) is not polar;
ii) ;
iii) is smooth and strongly subharmonic;
iv) ;
v) .
A different proof of the Suita conjecture (1) was given in [5]. It follows from the lower bound
[TABLE]
for . This inequality was proved in [5] using the tensor power trick which requires a corresponding inequality for pseudoconvex domains in for arbitrary . As noticed by Lempert (see also [3]), (3) can also be proved using the variational formula for the Bergman kernel in of Maitani-Yamaguchi [11] (generalized by Berndtsson [2] to higher dimensions). Both proofs therefore make crucial use of several complex variables. It would be interesting to find a purely one-dimensional proof of (3).
It was shown in [6] that the right-hand side of (3) is non-increasing in (it is an open problem in higher dimensions). Also, a more general conjecture was given, namely that the function
[TABLE]
is convex. A counterexample was found by Fornæss [10]. It was also shown numerically in [1] that the conjecture does not hold in an annulus. Here we will generalize and simplify both results proving the following:
Theorem 5**.**
Assume that , where is a domain in , are such that for some , where . Then the function (4) is not convex near .
Note that for example any regular domain which is not simply connected satisfies the assumption of Theorem 5 for any : it is enough to take maximal such that is simply connected. Then there exists such that .
2. Upper bounds for the Bergman kernel
In this section we will prove Theorems 1 and 2.
Proof of Theorem 1.
We may assume that is bounded and smooth, , and . Take , without loss of generality we may take such an which is defined in a neighborhood of . Let , where , be harmonic in and such that on and on . Then
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Therefore
[TABLE]
where denotes the outer normal derivative of at . Denoting , we have
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and therefore on
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The required estimate now follows from the fact that
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∎
Proof of Theorem 2.
Denote , and assume that . Then by the Poisson formula
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By Theorem 1
[TABLE]
We can now take for example and the estimate follows. ∎
The smallest constant the above proof gives will be obtained for , then
[TABLE]
3. Proof of the lower bound for
In this section we prove Theorem 3. We follow the method from [4]. We could have also used another method from [5] but this would require to go to several complex variables and we prefer to have a purely one-dimensional argument.
Proof of Theorem 3.
We assume that , is bounded and smooth, and denote . Set
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and
[TABLE]
where , , will be defined later. We assume that is convex and nondecreasing (so that is subharmonic), , and that on the support of for some constant with . Then by Theorem 2 in [4] one can find such that is holomorphic and
[TABLE]
where
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Take and assume that . We choose such that . Since near [math], we may take .
Similarly as in [4] for we define
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so that
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and
[TABLE]
We now set
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and
[TABLE]
where will be determined later and are uniquely determined by the conditions , :
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We see that if we choose then and as .
On we have and
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so that is not locally integrable near 0. By (5) it implies that and . One can also check that on .
Since near 0, we have on . There we also have
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Therefore the right-hand side of (5) can bounded from above by
[TABLE]
where as . The optimal choice for is
[TABLE]
then (7) takes the form
[TABLE]
Note that
[TABLE]
where . Combining this with (6) and the fact that we will obtain
[TABLE]
∎
Using standard methods we will also prove the following formula for the Laplacian of . It is of course well known for and the proof is essentially the same in general.
Proposition 6**.**
For a domain in such that is not polar and we have
[TABLE]
Proof.
Denote and for a fixed and set
[TABLE]
Since is of codimension at most 1 in , we can find an orthonormal system in such that for all . This means that for . For we have
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Therefore
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and
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Since
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and
[TABLE]
[TABLE]
we will obtain
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and the proposition follows. ∎
4. Proof of Theorem 5
Let be a sequence of regular values for . It will be enough to show that , where . By the co-area formula we have
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and therefore
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It is convenient to assume that . Since is harmonic in , it follows that there exists a holomorphic near [math] such that and for some we have
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It follows that near [math] we have
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We can also find a biholomorphic near 0 such that . We then have
[TABLE]
and for some
[TABLE]
as . ∎
The reference list from the paper itself. Each links out to its DOI / PubMed record.
- 1[1] P. Åhag, R. Czyż, P. H. Lundow , A counterexample to a conjecture by Błocki-Zwonek , Experiment. Math. (to appear)
- 2[2] B. Berndtsson , Subharmonicity properties of the Bergman kernel and some other functions associated to pseudoconvex domains , Ann. Inst. Fourier 56 (2006), 1633–1662
- 3[3] B. Berndtsson, L. Lempert , A proof of the Ohsawa-Takegoshi theorem with sharp estimates , J. Math. Soc. Japan, 68 (2016), 1461–1472
- 4[4] Z. Błocki , Suita conjecture and the Ohsawa-Takegoshi extension theorem , Invent. Math. 193 (2013), 149-158
- 5[5] Z. Błocki , A lower bound for the Bergman kernel and the Bourgain-Milman inequality , Geometric Aspects of Functional Analysis, Israel Seminar (GAFA) 2011-2013, eds. B. Klartag, E. Milman, Lect. Notes in Math. 2116, pp. 53–63, Springer, 2014
- 6[6] Z. Błocki, W. Zwonek , Estimates for the Bergman kernel and the multidimensional Suita conjecture , New York J. Math. 21 (2015) 151–161
- 7[7] L. Carleson , Selected Problems on Exceptional Sets , Van Nostrand, 1967
- 8[8] J. B. Conway , Functions of One Complex Variable II , Springer, 1995
