# Parity of Sets of Mutually Orthogonal Latin Squares

## TL;DR

This paper extends the concept of parity from Latin squares to sets of mutually orthogonal Latin squares and orthogonal arrays, establishing bounds on their information content and restrictions on their configurations, especially related to projective planes.

## Contribution

It introduces a new parity measure for MOLS and OA, derives bounds on their information content, and explores restrictions on Latin square ensembles, providing insights into the construction of projective planes.

## Key findings

- Bound on the information content of OA parity: im(k,n)leqinom{k}{2}-1
- Tighter bounds for projective plane cases depending on nven or odd
- Restrictions on Latin square ensembles depending on n mod 4

## Abstract

Every Latin square has three attributes that can be even or odd, but any two of these attributes determines the third. Hence the parity of a Latin square has an information content of 2 bits. We extend the definition of parity from Latin squares to sets of mutually orthogonal Latin squares (MOLS) and the corresponding orthogonal arrays (OA). Suppose the parity of an $\mathrm{OA}(k,n)$ has an information content of $\dim(k,n)$ bits. We show that $\dim(k,n) \leq {k \choose 2}-1$. For the case corresponding to projective planes we prove a tighter bound, namely $\dim(n+1,n) \leq {n \choose 2}$ when $n$ is odd and $\dim(n+1,n) \leq {n \choose 2}-1$ when $n$ is even. Using the existence of MOLS with subMOLS, we prove that if $\dim(k,n)={k \choose 2}-1$ then $\dim(k,N) = {k \choose 2}-1$ for all sufficiently large $N$. Let the ensemble of an $\mathrm{OA}$ be the set of Latin squares derived by interpreting any three columns of the OA as a Latin square. We demonstrate many restrictions on the number of Latin squares of each parity that the ensemble of an $\mathrm{OA}(k,n)$ can contain. These restrictions depend on $n\mod4$ and give some insight as to why it is harder to build projective planes of order $n \not= 2\mod4$ than for $n \not= 2\mod4$. For example, we prove that when $n \not= 2\mod 4$ it is impossible to build an $\mathrm{OA}(n+1,n)$ for which all Latin squares in the ensemble are isotopic (equivalent to each other up to permutation of the rows, columns and symbols).