Gauss map and the topology of constant mean curvature hypersurfaces of $\mathbb{S}^{7}$ and $\mathbb{CP}^{3}$
Fidelis Bittencourt, Pedro Fusieger, Eduardo Longa, Jaime Ripoll

TL;DR
This paper introduces a Gauss map for hypersurfaces in spheres and complex projective spaces, establishing its harmonicity characterizes constant mean curvature, and explores the geometric and topological implications of this relationship.
Contribution
It defines a new Gauss map for hypersurfaces in $ ext{S}^7$ and $ ext{CP}^3$, linking harmonicity to CMC and analyzing geometric and topological properties.
Findings
Gauss map is harmonic iff hypersurface has CMC
Results relate the image of the Gauss map to hypersurface topology
Similar constructions and results extend to $ ext{CP}^3$
Abstract
We define a Gauss map of an oriented hypersurface of the unit sphere and prove that is harmonic if and only if has CMC. Results on the geometry and topology of CMC hypersurfaces of , under hypothesis on the image of , are then obtained. By a Hopf symmetrization process we define a Gauss map for hypersurfaces of and obtain similar results for CMC hypersurfaces of this space.
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Gauss map and the topology of constant mean curvature hypersurfaces of
and
Fidelis Bittencourt
Pedro Fusieger
Eduardo R. Longa
Jaime Ripoll
Abstract
We define a Gauss map of an oriented hypersurface of the unit sphere and prove that is harmonic if and only if has CMC. Results on the geometry and topology of CMC hypersurfaces of , under hypothesis on the image of , are then obtained. By a Hopf symmetrization process we define a Gauss map for hypersurfaces of and obtain similar results for CMC hypersurfaces of this space.
1 Introduction
The image of the Gauss map of a minimal surface in the Euclidean space is a classical topic of study on Differential Geometry. A well known result says that if the Gauss image of a complete minimal surface of lies in a hemisphere of the sphere then the surface is a plane (see [2]). This result was extended to constant mean curvature (CMC) surfaces by D. Hoffman, R. Osserman and R. Schoen, who proved that if the Gauss image of a complete CMC surface of is contained in a closed hemisphere of the sphere then the surface is a plane or a right circular cylinder ([9]). An important ingredient used in [9], due to Ruh-Vilms, asserts that a surface has CMC if and only if its Gauss map is harmonic (the statement of Ruh-Vilms’ theorem is more general, see [15]). Several works extending and generalizing the Euclidean Gauss map to higher dimensions and to different ambient spaces have appeared during the last decades. However, to the best of authors’ knowledge, extensions or generalizations of Ruh-Vilms’ theorem were only investigated on the papers [3], [6], [7], [11], [13].
In this paper we use the multiplication of the unit sphere centered at the origin of induced by a normed division algebra structure of the so called octonionic multiplication, see to define a translation map by , , where is the tangent bundle of and is the unit of . The map provides a simple and natural definition of a Gauss map of an orientable hypersurface of . Indeed, if is a unit normal vector for , then we set .
We obtain an extension to of a well known formula for the Laplacian of the Euclidean Gauss map, and prove an extension of Ruh-Vilms’ theorem to a hypersurface of : is harmonic if and only if is a CMC hypersurface (Theorem 2). We then use formula (1) for the Laplacian of to obtain results on the topology of a CMC hypersurface of under certain conditions on the image of (Theorem 6). These constructions are only possible in the dimensional sphere (besides , studied in [6]) since, by a classical result of Hurwitz, the only normed division algebra structures of are , , the quaternions) and the octonions). By a process of symmetrization we introduce, from the translation of , a translation on minus a totally geodesic obtaining similar results on
2 The octonionic Gauss map and constant mean curvature hypersurfaces of
As mentioned in the introduction, we use here the multplication on called octonionic multiplication, induced by the unique normed division algebra structure of (we note that with this operation is not a Lie group since is not associative. See [1]). We define a translation by where is the neutral element of
Any vector at any given point determines a vector field on , which we call here a *translational vector field, *given by
[TABLE]
or
[TABLE]
A Hopf vector field in is any vector field which is -conjugated to the vector field of the form
[TABLE]
that is, a vector field of the form with .
Lemma 1
A translational vector field of is a multiple of a Hopf vector field of . In particular, translational vector fields are Killing fields without singularities.
Proof. It is easy to see that a translational vector field is of the form , for some . Assuming that is nonzero, then and we have . Since and it follows that is skew-symmetric and orthogonal (see Section 2.3 of [1]). The eigenvalues of are therefore pure imaginary and must be all equal to . The lemma then follows from elementary Linear Algebra.
Let be an oriented immersed hypersurface of and let be a unit normal vector field along . We define the Gauss map (octonionic Gauss map)
[TABLE]
of , where is the unit sphere centered at the origin of , by
[TABLE]
The Laplacian of is defined by setting
[TABLE]
where is the Laplacian in and is an orthonormal basis of . It is easy to see that does not depend on the choice of basis. One may prove that is harmonic if and only if , where
[TABLE]
is the orthogonal projection of onto the tangent spaces of (see [5]).
Theorem 2
Let be an oriented immersed hypersurface of , and let be the Gauss map of determined by a unit normal vector field along . Then
[TABLE]
where is the mean curvature function of with respect to , is its gradient on , is the second fundamental form of and is its norm.
Proof. Let be an orthonormal basis of . Since, by Lemma 1, the vector fields are Killing fields, we may use Proposition 1 of [8] to obtain, at any ,
[TABLE]
proving the theorem.
Corollary 3
Let be an oriented immersed hypersurface of and let be the Gauss map of . Then has constant mean curvature if and only if is harmonic. Equivalently, has constant mean curvature if and only, for any the function is harmonic in
A Gauss map of an orientable hypersurface of that have been often studied in the literature associates, to each the vector where is a unit normal vector field along E. De Giorgi ([4]) and J. Simons ([12]) proved that if is compact, has constant mean curvature and \gamma(M)\is contained in an open hemisphere of then must be a totally geodesic hypersphere of Using the octonionic Gauss map we obtain:
Theorem 4
Let be an orientable compact CMC hypersurface of and let be its (octonionic) Gauss map. Then is not contained in any open hemisphere of
Proof. Assume that is contained in a hemisphere of having as pole. This means that for all Since is compact, we may find linearly independent vector such that for all and The functions being harmonic and not changing sign must be constant. Hence must be a constant map and then From (1) must be zero, contradiction! This proves the corollary.
The case that the image of the Gauss map is contained in a *closed *hemisphere of the sphere is more complicated. Recall that in the dimensional Euclidean space, D. Hoffman, R. Osserman and R. Schoen proved that if the image of a complete CMC surface is contained in a closed hemisphere of then the surface is a plane or a right circular cylinder (Theorem 1 of [9]). With similar suitable hypothesis on the *Grassmanian *image of the Gauss map of a complete surface in , with non zero parallel mean curvature vector, they also prove in [9] that a surface is plane, a cylinder or a flat torus. A similar result holds when the ambient space is (Theorems 2 and 3 of [9]).
We obtain here a theorem for a CMC compact hypersurface of assuming that the image of the octonionic Gauss map of is contained in a closed hemisphere of . We are not able to prove an isometric rigidity theorem but only some topological rigidity (isometric rigidity seems to be a difficult problem in higher dimensions. To our knowledge no such a result was obtained for CMC hypersurfaces of or for ).
Observe that in the results of [9], mentioned above, the Euler characteristic of a CMC surface having the Gauss map contained in a closed hemisphere is zero. We obtain the same conclusion on the Euler characteristic of CMC hypersurfaces having the Gauss image contained in a closed hemisphere of (Corollary 7 below). In fact, we obtain some stronger topological theorem related to the ”size” of the image of the Gauss map. To state precisely our results we need to introduce some facts.
Given a totally geodesic -dimensional sphere of , let be the hyperplane through the origin of such that . We shall say that totally geodesic -dimensional spheres of , , are linearly independent, if the unit normal vectors orthogonal to each the hyperplanes are linearly independent in . Note that divides into two connected components. The closure of these connected components are called closed hemispheres of divides into connected components which closure are called closed quadrants; into connected components determining closed octants. In general, divides into connected components which closures are called *closed *-*orthants *of (see [14]).
By a -vector field on an -dimensional manifold , , we mean an ordered set of vector fields of which are linearly independent at each point of If a vector field is defined for all but a finite number of points we say that it is a vector field with finite singularities.
For reader’s sake, we recall now the definition of the index of a -vector field with finite singularities, as done in [17]. Let be a singularity of . Consider a simplicial triangulation of such that any singularity of is contained in the interior of a -simplex and that belongs to the interior of a simplex . The tangent bundle of restricted to is isomorphic to the product bundle , and we assume is an oriented manifold and that this isomorphism preserves orientation. We may also assume that is a ball in and that is a -vector field of . Recalling that the Stiefel manifold of is defined as the space of matrices with linearly independent rows, we have that for any . Since is a topological -sphere, the homotopy class of the map , given by is an element of the -homotopy group of . This homotopy class is, by definition, the *index * of at . We then define the index of in by
[TABLE]
The following result is well known in Differential Topology (see §34.2 of [16]).
Theorem 5
Let be an -dimensional manifold, , and let a -vector field with finite singularities on , . Then if and only if there is a -field with no singularities on which coincides with on the -skeleton of .
We note that the existence of -fields defined on the whole manifold or -fields with finite singularities and with index zero has strong influence on the topology of the manifold (see [17]).
Theorem 6
Let be a compact and oriented immersed hypersurface of constant mean curvature of and let be the Gauss map of . The following alternatives are equivalent:
- (i)
The image is contained in a closed -orthant of , that is, the closure of a connected component of , for some linearly independent totally geodesic spheres of ,
- (ii)
[TABLE]
- (iii)
Let be a basis of
[TABLE]
and let be the Lie algebra generated by the Killing fields . Then is a Lie subalgebra of the Lie algebra of the isometry group of .
Any of the above alternatives implies that , that is, it does not exist a compact connected oriented CMC hypersurface of such that is contained in a closed -orthant of . Moreover, and the index of any -vector field with finite singularities on is zero.
Proof. We prove that (i) implies (ii). Since is contained in a closed orthant of , there are linearly independents vectors such that , . From (1), with a fixed , we obtain
[TABLE]
It follows that is superharmonic on . Since is compact, we have that is a constant. But then and it follows from (2) that . Hence, given ,
[TABLE]
so that is a Hopf vector field of tangent to M\, proving that . Since this holds for all , it follows that (i) implies (ii).
As to the equivalence between (i) or (ii) and (iii), one only has to note that if are vector fields on , then so is the bracket of any two of them. Moreover, since the bracket of Killing fields is another Killing field, the assertion related to follows; in particular . Furthermore, since are linearly independent, it follows from Theorem 5 that the index of any -vector field with finite singularities on is zero. Finally, we have , otherwise , by (ii), would be orthogonal to linearly independent vectors.
Using the previous notation and definition of the index of a vector field with finite singularities, note that when , since has the homotopy type of the sphere and since , it follows that is an integer which is well known to be the Euler characteristic of the manifold. Then, as a consequence of Theorem 6, we have:
Corollary 7
Let be a compact hypersurface of constant mean curvature of . If the Gauss map of is contained in a closed hemisphere of then the Euler characteristic of is zero.
3 The Gauss map of constant mean curvature hypersurfaces of
An* *action of on is a Hopf action if the associated vector field
[TABLE]
is a Hopf vector field. The complex projective space with the Fubini-Study metric is the quotient of under a Hopf action of and with the metric such that the projection is a Riemannian submersion.
Recall that acts on by the octonionic multiplication (it is indeed an action since is associative in each subspace of octonions generated by two elements ([1])).
Lemma 8
The octonionic action of on is a Hopf action.
Proof. One may see that the vector field of determined by the octonionic action of in is
[TABLE]
where is the and the matrix obtained writting and as linear combination of the canonical basis of . We have that is a Hopf vector field. Indeed,
[TABLE]
where is the orthogonal matrix
[TABLE]
The Hopf symmetrization of a vector field is a vector field defined by
[TABLE]
We have
Lemma 9
The Hopf symmetrization of a vector field of is invariant by the Hopf action, that is
[TABLE]
for all and for all
Proof. We have
[TABLE]
Lemma 10
* is Hopf invariant if and only if .*
Proof. If then is Hopf invariant by Lemma 9. Conversely if then
[TABLE]
Note that a vector field of which is invariant by the Hopf action defines a vector field in . Indeed, if then
[TABLE]
We may then define
[TABLE]
where . Given set
[TABLE]
We claim that is a vector field of Indeed, given the map given by
[TABLE]
satisfies
[TABLE]
and
[TABLE]
Hence
[TABLE]
for all We also have
Lemma 11
* is a Hopf invariant vector field for any *
Proof. Let We prove that The lemma then follows from Lemma 10.
[TABLE]
Writing we have
[TABLE]
concluding with the proof of the lemma.
Note that since the symmetrization is an average process it may happen to be identically zero for a nonzero vector field . But this is not the case with if since . And indeed, defining the following vector fields of : , where and is the canonical octonionic basis (see [1]), we have the stronger fact:
Proposition 12
Let be the totally geodesic real codimension complex projective space which is the cut locus of Then Z_{1},~{}...,~{}Z_{6}\are Killing fields of which are linearly independent at any point of
Proof. We first note are Killing fields of . Indeed, the vector fields are Killing fields on since they are given as a sum of compositions of right and left octonionic translations. Since commutes with the Hopf action it belongs to the Lie algebra of the unitary group which is the isometry group of and hence projects into a Killing field of .
For proving that the are linearly independent it is enough to show that are orthogonal to the fibers of for and, since then
[TABLE]
that
[TABLE]
for all where is the totally geodesic codimension sphere
[TABLE]
Setting
[TABLE]
we have
[TABLE]
We may then see that
[TABLE]
Moreover, a calculation shows that
[TABLE]
concluding the proof of the proposition.
Define a translation by setting
[TABLE]
Any determines a Killing field on without singularities, by setting We have
[TABLE]
if If is an orientable hypersurface of and a unit normal vector field along the Gauss map of is defined by
[TABLE]
Using a similar proof to that of Theorem 2, we obtain:
Theorem 13
Let be an orientable hypersurface of , a unit normal vector field along and the associated Gauss map. Then
[TABLE]
where and are the mean curvature function and the second fundamental form of In particular, has constant mean curvature if and only if satisfies the vectorial PDE
[TABLE]
If one replaces a hemisphere by a half-space of a quadrant as one connected component of where are linearly independent hyperplanes through the origin of (that is, the unit normal vector to are linearly independent), an octant as a connected component of and so on, we have an extension of Theorem 6 to . Its statement is completely similar to Theorem 6 and therefore omitted. We think it is worthwhile however to state a corollary on the image of the Gauss map:
Corollary 14
Let be a compact oriented immersed hypersurface of and let be the Gauss map of . Then is not contained in a half space of
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