Resonances of 4-th Order Differential Operators
Andrey Badanin, Evgeny Korotyaev

TL;DR
This paper analyzes the resonances of fourth order differential operators, deriving asymptotics for their count at large radii and characterizing conditions for the absence of eigenvalues and resonances.
Contribution
It provides new asymptotic formulas for the number of resonances and characterizes when Euler-Bernoulli operators have no eigenvalues or resonances.
Findings
Asymptotics of resonance count at large radius are established.
Euler-Bernoulli operators have no eigenvalues or resonances iff coefficients are globally constant.
Resonance distribution is explicitly described for certain fourth order operators.
Abstract
We consider fourth order ordinary differential operator with compactly supported coefficients on the line. We determine asymptotics of the number of resonances in complex discs at large radius. We consider resonances of an Euler-Bernoulli operator on the real line with the positive coefficients which are constants outside some finite interval. We show that the Euler-Bernoulli operator has no eigenvalues and resonances iff the positive coefficients are constants on the whole axis.
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Resonances of 4-th Order Differential Operators
Andrey Badanin
and
Evgeny L. Korotyaev
Saint-Petersburg State University, Universitetskaya nab. 7/9, St. Petersburg, 199034 Russia, [email protected], [email protected], [email protected], [email protected]
Abstract.
We consider fourth order ordinary differential operator with compactly supported coefficients on the line. We define resonances as zeros of the Fredholm determinant which is analytic on a four sheeted Riemann surface. We determine asymptotics of the number of resonances in complex discs at large radius. We consider resonances of an Euler-Bernoulli operator on the real line with the positive coefficients which are constants outside some finite interval. We show that the Euler-Bernoulli operator has no eigenvalues and resonances iff the positive coefficients are constants on the whole axis.
Key words and phrases:
fourth order operators, resonances, scattering, trace formula
1991 Mathematics Subject Classification:
34L25 (47E05 47N50)
1. Introduction and main results
1.1. Introduction
There are a lot of results about resonances for 1-dim second order operators, see e.g., [F97], [H99], [K04], [S00], [Z87] and references therein. We can say that problems of resonances for these operators are well understood. The resonance scattering for third order operators on the line was considered in [K16]. There are a lot of papers [B85], [I88], [Iw88], …. and even a book [BDT88] about scattering for one dimensional higher order operators. Unfortunately, even the inverse scattering problems for higher order operators on the line are not solved and there are few results about resonances [K16], [BK17].
We discuss resonances of fourth order differential operators with compactly supported coefficients on the line given by
[TABLE]
where the operator is unperturbed. Below we assume that our coefficients , where , are the spaces of compactly supported functions
[TABLE]
for some . Our operator is self-adjoint on the corresponding form domain (see Sect. 2). The operator has purely absolutely continuous spectrum plus a finite number of simple eigenvalues on the real line, see Theorem 1.1.
We define the Fredholm determinant by (1.5), which is analytic on a four sheeted Riemann surface of the function . We define a resonance of the operator as a zero of the Fredholm determinant on the non-physical sheets of this surface.
Our main goal is to obtain estimates of and determine asymptotics of the number of resonances in the large disc. Moreover, we derive trace formulas in terms of resonances and prove a Borg type results about resonances for Euler-Bernoulli operator.
1.2. Schrödinger operator
In order to discuss resonances for fourth order operators we consider a Schrödinger operator on given by
[TABLE]
where is the unperturbed operator and the compactly supported potential . We recall the well known results for the operator , see, e.g., [DT79], [Fa64]. The operator has purely absolutely continuous spectrum plus a finite number of simple eigenvalues .
We define the resolvent and the operator for by
[TABLE]
Each operator , is trace class and thus we can introduce the Fredholm determinant by
[TABLE]
The function is analytic in and has an analytic extension onto the whole complex plane without zero. It has simple zeros (the eigenvalues) in and there are no other zeros in . Moreover, has an infinite number of zeros (resonances) in . The operator is self-adjoint and then the set of resonances is symmetric with respect to the imaginary axis, see Fig.1.
The problems of resonances for 1-dimensional Schrödinger operators with compactly supported potentials are well understood. Recall the following results:
Let and let be the number of zeros of in a disk . Zworski [Z87] determined the following asymptotics (see also [F97], [K05], [S00])
[TABLE]
For each the number of zeros of with modulus lying outside both of the two sectors is for large .
There are only finitely many resonances in the domain .
The resonances may have any multiplicity (see [K05]).
Inverse resonance problem (uniqueness, characterization and recovering) was solved in terms of resonances for the Schrödinger operator with a compactly supported potential on the real line [K05].
Stability estimates for resonances were determined in [K04x] and [MSW10].
Lieb-Thirring type inequalities for resonances were obtained in [K16xx].
1.3. Determinant
In order to define the Fredholm determinant for the operator we need a factorization of the perturbation in the form
[TABLE]
We introduce a new spectral variable by , where the spectral parameter belongs to the cut plane (see Fig 2) and the sector is given by
[TABLE]
Introduce the free resolvent and the operator by
[TABLE]
In Proposition 1.1 we show that each operator is trace class. Thus we can define the Fredholm determinant , by
[TABLE]
If is a zero of the determinant , then and is an eigenvalue of the operator . We present preliminary results about the determinant.
Proposition 1.1**.**
Let . Then
i) Each operator is trace class and the operator-valued function is entire in the trace norm.
ii) The Fredholm determinant is analytic in and has an analytic extension into the whole plane without zero such that the function is entire. In particular, the operator has a finite number of eigenvalues. Moreover, is real on the line and satisfies:
[TABLE]
[TABLE]
uniformly in .
Remark. The function is symmetric with respect to the line . Thus it is sufficiently to analyze this function in the half-plane .
The zeros of the function in are called resonances of . Let be the number of zeros of the function in the disc , counted with multiplicity. Introduce the domains
[TABLE]
Now we formulate our first main result.
Theorem 1.2**.**
Let . Then the determinant and the counting function satisfy
[TABLE]
[TABLE]
where . Moreover, if is a resonance, then
[TABLE]
Here is some constant depending on only.
Remark. 1) The estimate (1.10) gives that the domain is forbidden for resonances in and, due to the symmetry of the function , the domain is forbidden for resonances in , see Fig. 2. The proof repeats arguments from [K04].
-
Estimate (1.8) is crucial to prove trace formula (1.16) in terms of resonances.
-
Due to (1.6) the set of resonances is symmetric with respect to the line (with the same multiplicity).
We describe the main difference between the case of the second and fourth order operators.
Recall that for Schrödinger operators the Riemann surface in terms of the momentum is the complex plane. The upper half-plane corresponds to the physical sheet and the lower half-plane corresponds to the non-physical sheet. In order to determine asymptotics of the determinant of the Schrödinger operator in the complex plane it is sufficiently to obtain the asymptotics of the determinant and the scattering matrix in . The Birman-Krein formula (see (2.10)) gives the asymptotics of the determinant in .
In the case of fourth order operators the Riemann surface has 4 sheets and each quadrant of the variable corresponds to the sheet of the Riemann surface . Using arguments similar to the second order case we obtain asymptotics of the determinant in the domains only (and, by the symmetry, in ). In fact, if we have asymptotics of the determinant and asymptotics of the scattering matrix in , then using the identity (4.9) we obtain the asymptotics of the determinant in . In order to obtain the asymptotics in the domain we use additional arguments from [K16] (for third order operators), more complicated than for the sectors . We need to introduce an additional matrix-valued function , which satisfies the identity (4.10). Having asymptotics of the determinant and of this matrix in and using the identity (4.10) we obtain the asymptotics of the determinant in . Note that in order to determine asymptotics of determinants for order operators we need to introduce the corresponding matrix-valued functions.
1.4. Asymptotics of resonances
Introduce the Cartwright class of functions. Recall that an entire function is said to be of exponential type if there is a constant such that everywhere. The infimum of the set of for which such inequality holds is called the type of . For each exponential type function we define the types in by
[TABLE]
The function is said to belong to the Cartwright class if is entire, of exponential type, and satisfies the following conditions:
[TABLE]
for some . We recall the Levinson Theorem (see [Ko88]):
Let an entire function be in the Cartwright class . Let be the number of zeros of the function in the disc , counted with multiplicity. Then
[TABLE]
Roughly speaking the Fredholm determinants of second order operators on the real line with compactly supported potential belong to the Cartwright class:
Schrödinger operators with compactly supported potentials [Z87],
Schrödinger operators with periodic plus compactly supported potentials [K11],
Schrödinger operators with matrix-valued compactly supported potentials [N07],
Dirac operators with matrix-valued compactly supported potentials [IK14].
In all these cases the Fredholm determinants are entire and belong to the Cartwright class, and the corresponding Riemann surfaces are two sheeted. Thus the Levinson Theorem describes the distribution of resonances in the large disc.
We underline that the Fredholm determinants of the Stark operator with compactly supported potential does not belong to the Cartwright class, since the order of determinants is , see [K16x]. In this paper we show that the determinant for a fourth order operators does not belong to the Cartwright class also.
We determine asymptotics of resonances for fourth order operators under the stronger conditions for the coefficient and the standard one for :
[TABLE]
Introduce the model numbers (see Fig. 3) by
[TABLE]
where
[TABLE]
Theorem 1.3**.**
Let satisfy the conditions (1.12). Then for any there exists such that in each disk , there exists exactly one resonance and there are no other resonances in the domain . These resonances satisfy
[TABLE]
In particular, there are finitely many zeros of on . Moreover, let be the number of zeros of the function in a domain counted with multiplicity. Then
[TABLE]
as and the determinant does not belong to the Cartwright class.
Remark. From (1.14) we obtain . It means that the number of resonances in the large disc in the domain is in two times more than in the domain , see Fig. 4.
Our next results are devoted to trace formulas in terms of resonances. Recall that the function may have a pole at the point . Then the function satisfies
[TABLE]
for some , where is an order of the pole. Let , be the zeros of the function in labeled by counting with multiplicities.
Theorem 1.4**.**
Let and let . Then the following trace formula
[TABLE]
holds true for all , where the series converges absolutely and uniformly on any compact subset in , and are defined in (1.15).
Remark. 1) In the proof we use arguments from [K04], [K16].
- A trace formula for the scattering phase function is proved in Theorem 5.2.
1.5. Euler-Bernoulli operators.
We discuss resonances of the Euler-Bernoulli operator
[TABLE]
acting on . We assume that the coefficients are positive, outside a unit interval and satisfy . The Euler-Bernoulli operator describes the relationship between the thin beam’s deflection and the applied load, is the rigidity and is the density of the beam, see, e.g., [TW59].
In Sect 5.3 we show that the operator is unitarily equivalent to an operator with specific coefficients . Then we can define a determinant for the operator as the determinant for the operator with these . Applying the results for the operator to the operator we obtain the following corollary of Theorem 1.2.
Corollary 1.5**.**
Let and and let be positive. Then the determinant , the counting function and the resonances for the Euler-Bernoulli operator satisfy the estimates (1.8)–(1.10), where
[TABLE]
Now we formulate our result about the inverse resonance scattering for the Euler-Bernoulli operator .
Theorem 1.6**.**
Let and let be positive. Then the operator does not have any eigenvalues and resonances iff on the whole line.
1.6. Historical review
There are a lot of results about resonances. We recall that resonances, from a physicists point of view, were first studied by Gamov [Ga28]. Since then, properties of resonances have been the object of intense study and we refer to [SZ91] for the mathematical approach in the multi-dimensional case and references given therein. We discuss the one-dimensional case. A lot of papers are devoted to the resonances the one-dimensional Schrödinger operators with compactly supported potentials, see Froese [F97], Korotyaev [K04], Simon [S00], Zworski [Z87] and references given there. We recall that Zworski [Z87] obtained the first results about the asymptotic distribution of resonances for the Schrödinger operator with compactly supported potentials on the real line. Inverse problems (characterization, recovering, plus uniqueness) in terms of resonances were solved by Korotyaev for the Schrödinger operator with a compactly supported potential on the real line [K05] and the half-line [K04], see also Zworski [Z02] concerning the uniqueness.
There are few papers devoted to systems. Nedelec [N07] considered resonances for Schrödinger operators with compactly supported matrix-valued potentials on the real line. Iantchenko and Korotyaev [IK14] considered the Dirac operator on the real line with 2x2 matrix-valued compactly supported potentials. They obtained asymptotics of counting function of resonances, estimates on the resonances and the forbidden domain, a trace formula in terms of resonances. Lieb-Thirring type inequality for resonances of Dirac operators with compactly supported matrix-valued potentials on the real line is obtained in [K14]. Resonances for Stark operators on the real line are considered in [K16x]. Here we underline that for all these cases the corresponding Riemann surfaces are two-sheeted similar to the Schrödinger operator case.
A lot of papers are devoted to the inverse scattering theory for fourth order operators on the line, see papers Aktosun and Papanicolaou [AP08], Butler [Bu68], Iwasaki [I88], [Iw88], Hoppe, Laptev and Östensson [HLO06] and the book Beals, Deift, Tomei [BDT88] and references therein.
Resonances for higher order operators with compactly supported coefficients were considered by Korotyaev [K16] firstly for the case of third order operators. Here general properties of resonances were described. In particular, upper bounds of the number of resonances in complex discs at large radius and the trace formula in terms of resonances were obtained. Note that this case is very complicated for the consideration since the Born term roughly speaking is constant. Recall that for Schrödinger operators the corresponding Born term is the Fourier transformation of the potential. It is important for the global analysis of resonances, including inverse problems.
Resonances of fourth order operators with compactly supported coefficients on the half-line were studied by Badanin and Korotyaev [BK17]. Asymptotics of resonances and trace formulas in terms of resonances were determined. This case is simpler, than the case of the line considered in the present paper, because the scattering matrix is a scalar function. An extension of the determinant onto the third quadrant may be obtained using a matrix-valued function . Here the technique from [K16] was used. But it is important that the corresponding Born term is expressed in terms of the Fourier transformations of the compactly supported coefficients.
In the present paper the corresponding matrix for an operator on the line is a matrix-valued function and there are some algebraic difficulties in order to obtain this extension. Clearly, the problem for higher order operators will be much more complicated, especially for odd order case.
The usual applications of fourth order differential operators are bending vibrations of thin beams and plates described by the Euler-Bernoulli equation. Many problems of engineering involve solutions of scattering problem for the Euler-Bernoulli equation, see [Gr75] and references therein. Furthermore, the inverse spectral problem methods for some non-linear partial differential equations lead to fourth order operators, see [HLO06].
The plan of the paper is as follows. In Section 2 we study properties of the resolvent of the operator . In Sections 3 and 4 we consider the scattering matrix and the determinant. In Sections 5 we prove Proposition 1.1 and Theorems 1.2, 1.4. Moreover, there we consider the Euler-Bernoulli operator and prove Corollary 1.5 and Theorem 1.6. In Section 6 we obtain asymptotics of the resonances and prove Theorem 1.3.
2. Properties of the free resolvent
2.1. The well-known facts
By we denote the class of bounded operators. Let and be the trace and the Hilbert-Schmidt class equipped with the norm and correspondingly. We recall some well known facts. Let and . Then
[TABLE]
[TABLE]
[TABLE]
see e.g., Sect. 3. in the book [S05]. Let the operator-valued function be analytic for some domain and for any . Then for the function we have
[TABLE]
Introduce the space equipped by the norm and we write .
2.2. Schrödinger operator
We discuss a Schrödinger operator on given by
[TABLE]
where is the unperturbed operator and the potential .
The operator , is an integral operator having the kernel given by
[TABLE]
Define an operator-valued function , where . For each the operator and the mappings
[TABLE]
is analytic and it has an analytic extension into the whole complex plane without zero. Thus the operator-valued function is analytic. Moreover, we have the following estimate
[TABLE]
Define the Fourier transformation by
[TABLE]
Then , where is the multiplication by and we have
[TABLE]
since .
The Schrödinger equation , has unique Jost solutions satisfying the conditions and . For each the function is entire. The following identity holds true:
[TABLE]
where the functions are defined by
[TABLE]
and denotes the Wronskian. The scattering matrix for the pair has the following form
[TABLE]
where is the transmission coefficient and are the reflection coefficients. It is well known the following identity for all , where is the determinant defined by (1.2). Moreover, the scattering matrix satisfies
[TABLE]
The function satisfies
[TABLE]
uniformly on . Then we can define the function by the condition as , which satisfies
[TABLE]
2.3. The free resolvent
We rewrite the free resolvent in terms of the resolvent by
[TABLE]
Then the kernel of the free resolvent has the form , where
[TABLE]
and satisfies
[TABLE]
locally uniformly in . Each function , is entire in .
Define the operator-valued function where . The identity (2.11) yields that for each the operator and the mappings
[TABLE]
are analytic and they have analytic extensions into whole complex plane without zero. Moreover, from (2.12) we have the following estimate
[TABLE]
Moreover, we obtain , where is the multiplication by , is the multiplication by and we have
[TABLE]
since .
2.4. Resolvent estimates
The operator is self-adjoint on the form domain given by The quadratic form is defined by , , where is the scalar product in . Then the standard arguments (see e.g., [K03]) give
[TABLE]
for some constant . Then the KLMN Theorem (see [RS75, Th X.17]) yields that there exists a unique self-adjoint operator with the form domain and
[TABLE]
In order to study the determinant we need to consider . The definitions (1.3), (1.4) imply
[TABLE]
We introduce the operator-valued function by
[TABLE]
This function satisfies the standard identity
[TABLE]
where is the set of the zeros of the function in .
Lemma 2.1**.**
Let . Then
i) The operator for each , the operator-valued function is analytic and has an analytic extension into the whole complex plane without zero. The operator-valued function is entire. Moreover, satisfies
[TABLE]
[TABLE]
* for some constant .*
ii) The operator for each and the operator-valued function is analytic and has a meromorphic extension from into the whole complex plane. Moreover, satisfies
[TABLE]
[TABLE]
as and uniformly in .
Proof. i) Substituting the identity (2.12) into the definition (1.4) we obtain (2.21). Substituting the identities (2.11) into (2.18) and using the facts about the mappings in (2.6), (2.14) we deduce that the operator-valued function is analytic and has an analytic extension into the whole complex plane without zero. The asymptotics (2.13) shows that the operator-valued function is entire.
Using the estimates (2.9) we obtain for :
[TABLE]
and the similar estimates with . These estimates and the relations (2.15), (2.18) give
[TABLE]
which yields (2.22).
ii) For identity (2.20) gives
[TABLE]
and, since is analytic in , is analytic in . Due to the analytic Fredholm theorem, see [RS72, Th VI.14], the function has a meromorphic extension into the whole complex plane. The estimate (2.21) implies the asymptotics (2.23). Moreover,
[TABLE]
which yields (2.24).
3. The scattering matrix.
3.1. The spectral representation for
Define a unitary operator
[TABLE]
by
[TABLE]
The identity , implies that is the operator of multiplication by in .
Introduce the operators and for each by
[TABLE]
where and . Here and , and the kernels have the forms:
[TABLE]
It is clear that the operator-valued functions have analytic extensions from into the whole complex plane. Then we can introduce the operators and by
[TABLE]
Lemma 3.1**.**
Let . Then the operator-valued functions are entire and satisfy
[TABLE]
for all , where
[TABLE]
Proof. The operator has the kernel given by (3.3). Let . We have
[TABLE]
and
[TABLE]
This yields the estimates (3.5) for . The proof for is similar.
Introduce finite rank operators , acting on , by
[TABLE]
The operators are analytic in the domain . Below we need the following simple identities.
Lemma 3.2**.**
Let . Then for any the operators satisfy
[TABLE]
[TABLE]
Proof. The identities (2.5), (2.11) yield
[TABLE]
For all the definitions (3.2) imply
[TABLE]
This identity together with the identity (3.9) and the definition (1.4) gives
[TABLE]
which yields the identity (3.7).
The identities
[TABLE]
give (3.8).
3.2. The scattering matrix.
We define the S-matrix for the operators . It is well known that the wave operators for the pair , given by
[TABLE]
exist and are complete, i.e., . The scattering operator is unitary. The operators and commute and thus are simultaneously diagonalizable:
[TABLE]
here is the identity in the fiber space and is the scattering matrix (which is a matrix-valued function of in our case) for the pair .
The operator commutes with the operator and the operator is the operator of multiplication by in . Then the operator acts in the space as multiplication by a matrix-valued function .
The scattering matrix is a continuous matrix-valued function in , where is the set of the zeros of the function in , and satisfies
[TABLE]
(see, e.g., [RS79]), where is the identity matrix and is the scattering amplitude given by
[TABLE]
where the Born term and the term have the form
[TABLE]
The operator-valued functions are analytic in , then the matrix-valued function has an analytic extension from into the whole complex plane.
3.3. The scattering amplitude
Now we consider the scattering amplitude .
Lemma 3.3**.**
i) Let . Then the scattering amplitude has a meromorphic extension from into the whole complex plane. Moreover, the matrix-valued function is entire and satisfies
[TABLE]
for all , where
[TABLE]
[TABLE]
the matrix-valued functions satisfy
[TABLE]
[TABLE]
as uniformly in .
ii) Let . Then the functions satisfy
[TABLE]
[TABLE]
[TABLE]
as , uniformly in , where
Proof. i) The operator-valued functions are entire, then the function has an analytic extension from into the whole complex plane. Due to Lemma 2.1 ii), the function has a meromorphic extension from onto the whole complex plane. Then the scattering amplitude has a meromorphic extension from into the whole complex plane.
The definitions (3.2) and (3.13) give
[TABLE]
[TABLE]
Substituting the identities (3.3) into (3.21) we obtain the identity (3.14), which yields the asymptotics (3.16). The estimates (2.23) and (3.5) and the identity (3.22) give the asymptotics (3.17).
ii) Let . The integration by parts gives
[TABLE]
Substituting these asymptotics and the definition (3.15) into the identity (3.14) we obtain (3.18). Similarly,
[TABLE]
which yields (3.19).
The definition (3.13) and the estimates (2.24) and (3.5) give
[TABLE]
The identities (2.18) and (3.3) imply
[TABLE]
Substituting the kernel (2.12) into the last identity and integrating by parts in the first term we obtain
[TABLE]
Similarly,
[TABLE]
which yields
[TABLE]
Substituting this asymptotics into (3.23) we obtain the asymptotics (3.20).
4. The determinant
4.1. Asymptotics of the determinant
Lemma 2.1 i) shows that , then the determinant is well defined.
Lemma 4.1**.**
Let . Then
i) The determinant is analytic in and has an analytic extension from into the whole complex plane without zero, such that the function is entire.
ii) The function is real on the line .
Proof. i) Due to Lemma 2.1 i) the operator-valued function , and then the determinant , is analytic in and has an analytic extension from into the whole complex plane without zero. It is proved in [BK16] that the function is entire, the proof is rather technical.
ii) The identity (2.12) shows that is real on the line , then is real also. Therefore, is real on this line.
The identities (2.5), (2.11), (2.18) imply
[TABLE]
where The estimates (2.22) give as . We can define the branch , for and large enough, by
[TABLE]
We need the following standard results.
Lemma 4.2**.**
Let . Then the function satisfies
[TABLE]
[TABLE]
for any large enough, and for some , where the series converges absolutely and uniformly in . Furthermore, the function satisfies the asymptotics
[TABLE]
uniformly in .
Proof. Let . The estimate (2.21) gives
[TABLE]
Then the series (4.3) converges absolutely and uniformly and it is well-known that the sum is equal to (see [RS78, Lm XIII.17.6]). Using the estimates (4.5) we obtain (4.2). The estimate (4.2) together with the identity (4.1) gives the asymptotics (4.4).
4.2. Identities for the determinant and S-matrix
Asymptotics of the determinant in in the case of the Schrödinger operator is obtained from the asymptotics in and the identity (2.10). In order to determine asymptotics of the determinant in for the case of fourth order operators we need some additional identities. The situation for third order operators is described in [K16].
Recall that the -matrix is a meromorphic matrix-valued function and satisfies the identity S(k)=1\!\!1_{2}+c_{k}\big{(}{\mathcal{A}}_{0}(k)-{\mathcal{A}}_{1}(k)\big{)}, see (3.11), (3.12), where is the Born approximation for the scattering amplitude ,
Introduce the matrix-valued function by
[TABLE]
where the “Born” term has the form
[TABLE]
are given by (3.4), and
[TABLE]
The function has an analytic extension and the functions have meromorphic extensions from onto the whole complex plane.
Lemma 4.3**.**
Let , and let . Then the determinant satisfies
[TABLE]
[TABLE]
The function is continuous in .
Proof. The identities (3.6), (3.7) and (2.20) give
[TABLE]
The definitions (3.11), (3.12) give
[TABLE]
The identity (2.2) implies (4.9).
Similarly, the identities (3.6), (3.8) and (2.20) give
[TABLE]
Then the identity (2.2) and the definition (4.6) imply (4.10).
Due to Lemma 3.3, the function is continuous in and it has a meromorphic extension from onto . Moreover, if , then is a zero of the functions and of the same multiplicity. Due to the identity (4.9), is continuous at the point . Therefore, is continuous in .
4.3. Asymptotics of
We consider the matrix-valued function \Omega=1\!\!1_{4}+c_{k}\big{(}\Omega_{0}-\Omega_{1}\big{)}. Substituting the definitions (3.4) into (4.7), (4.8) we obtain
[TABLE]
Introduce entire matrix-valued functions
[TABLE]
The identities (4.11) and the definitions (3.13) (4.12) give
[TABLE]
[TABLE]
Introduce the domain
[TABLE]
Lemma 4.4**.**
Let . Then the functions , given by (4.12), satisfy
[TABLE]
where
[TABLE]
Moreover, the function satisfies
[TABLE]
as , uniformly in .
Proof. Substituting the definitions (3.2), (3.3) into (4.12) we obtain the identities (4.15).
Let . The definitions (4.16) give
[TABLE]
Substituting these asymptotics into the identities (4.15) we obtain
[TABLE]
Substituting these asymptotics and (3.16) into the identity (4.7) we obtain
[TABLE]
Let . The estimates (3.5) and (2.23) give
[TABLE]
Substituting these asymptotics and (3.17) into the identity (4.14) we obtain
[TABLE]
Substituting the asymptotics (4.18), (4.19) into the definition (3.2) we obtain the asymptotics
[TABLE]
as , which yields (4.17).
5. Proof of the main Theorems
5.1. Asymptotics of the determinant
We prove our preliminary Proposition 1.1.
Proof of Proposition 1.1. i) The statement is proved in Lemma 2.1 i).
ii) Due to Lemma 4.1, the function has an analytic extension from onto , it is real on the line and the function is entire. The asymptotics (4.4) yields the asymptotics (1.7). This asymptotics shows that the function has a finite number of zeros in . Then the operator has a finite number of eigenvalues.
We determine asymptotics of the determinant in the complex plane. Due to the symmetry of we need to get this asymptotics in the domains . The asymptotics in the domain is known due to (4.4). We analyze the function in the domains by the following way. We obtain the asymptotics of and in . Then we use the identities (4.9), (4.10) in order to determine the asymptotics of in , which gives the asymptotics of in .
Lemma 5.1**.**
Let . Then
[TABLE]
[TABLE]
as , uniformly in ,
[TABLE]
as , uniformly in .
Proof. Let . Substituting the asymptotics (3.16) and (3.17) into the identity (3.11) we obtain the asymptotics
[TABLE]
which yields the asymptotics (5.1). Substituting the asymptotics (1.7) and (5.1) into (4.9) we obtain the asymptotics (5.2).
Substituting the asymptotics (1.7), (4.17) into the identity (4.10) we obtain (5.3).
We prove Theorem 1.2.
Proof of Theorem 1.2. The asymptotics (1.7) gives the estimate (1.8) in , the asymptotics (5.2) gives (1.8) in , the asymptotics (5.3) gives (1.8) in . The estimate (1.8) in and the symmetry imply the estimate (1.8) in .
The asymptotics (5.2) yields for all for some . Let be a resonance. Then the identity gives the estimate (1.10).
We prove the estimate (1.9). Recall that the function is analytic in and may have a pole of order at the point . Let the function , be entire and satisfy . Let be the number of zeros of the function in the disc counted with multiplicity. If , then , if is a zero of of multiplicity , then . We have to prove that satisfies the estimate (1.9). The estimate (1.8) gives
[TABLE]
for all large enough and for some . Substituting the estimate (5.4) into Jensen’s formula
[TABLE]
we obtain
[TABLE]
for all large enough. Then there exists
[TABLE]
The estimate (1.9) follows from the following well known result, see, e.g., [Le96, Lm II.4.3]:
Let be non-decreasing function on , as for some , and let the function
[TABLE]
*has the limit as . Then as . *
5.2. Trace formulas
Let , be the zeros of the function in labeled by counting with multiplicities. The estimate (1.8) provides the standard Hadamard factorization
[TABLE]
absolutely and uniformly on any compact subset in , where are defined in (1.15). The identity (5.6) gives
[TABLE]
The following proofs use the approach from [K04].
Proof of Theorem 1.4. Let . The definitions (1.3), (2.12) show that the operators and are Hilbert-Schmidt. Then the operator
[TABLE]
is trace class. Due to the identities (2.2), (2.4), (2.20) and , the derivative of satisfies
[TABLE]
The identity (5.7) together with (5.8) yields the trace formula (1.16).
The S-matrix , is a complex matrix and . Thus we have
[TABLE]
Since is continuous in and as (see (5.1)), formula (5.9) determines by the identity , the continuity, and the asymptotics as .
Theorem 5.2**.**
Let . Then
[TABLE]
the series converges absolutely and uniformly on any compact subset in .
Proof. The function is continuous in , has a meromorphic extension onto the whole complex plane and, due to equations (5.9) and (4.9), it satisfies the identities
[TABLE]
Differentiating this identity we obtain
[TABLE]
Then the identity (5.7) implies (5.10).
5.3. The Euler-Bernoulli operator.
We consider the Euler-Bernoulli operator
[TABLE]
acting on , where the coefficients satisfy
[TABLE]
Now we consider the Liouville type transformation of the operator into the operator , defined by (1.1) with specific depending on . In order to define this transformation we introduce the new variable by
[TABLE]
Let be the inverse function for . Introduce the unitary transformation by
[TABLE]
Introduce the functions , by
[TABLE]
Then the functions are real, compactly supported and satisfy
[TABLE]
Let the operator be defined by (1.1), where the coefficients , have the forms
[TABLE]
[TABLE]
and the functions are given by
[TABLE]
[TABLE]
The coefficients satisfy: with given by (1.17).
Let the coefficients satisfy the conditions (5.12). Let the operator be defined by (5.11) and let the operator be defined by (1.1), where the coefficients have the forms (5.16), (5.17). Repeating the arguments from [BK15] we obtain that the operators and are unitarily equivalent and satisfy:
[TABLE]
where the operator is defined by (5.14).
Corollary 5.3**.**
Let and let be positive. Then the determinant satisfies
[TABLE]
uniformly in , where is given by the definition (5.18).
Proof. Identity (5.16) gives
[TABLE]
Substituting this identities into the asymptotics (1.7) we obtain the asymptotics (5.20).
The definition (5.18) shows that , moreover, iff . Then the second term in the asymptotics (5.20) vanishes iff . The proof of Theorem 1.6 is based on this observation.
Proof of Theorem 1.6. Assume that the operator does not have any eigenvalues and resonances. Then and the second term in the asymptotics (5.20) vanishes. The estimates (5.18) show that in this case, then on .
Conversely, assume that on . Then and the definitions (5.16), (5.17) imply . The identities (1.3) yield . Then the definition (1.4) gives , and the identity (1.5) implies . Therefore, there are not any eigenvalues and resonances.
6. Asymptotics of the resonances
6.1. Asymptotics of the determinant
The function has a finite number of zeros in the domain . The identity (4.9) shows that with large is a resonance in iff is a zero of the function in . Thus in order to determine asymptotics of resonances in we need to improve asymptotics of in . Similarly, the identity (4.10) shows that with large is a resonance in iff is a zero of the function in . Then in order to determine asymptotics of resonances in we have to improve asymptotics of the function in . Moreover, due to the symmetry of the determinant it is sufficiently to consider in this case the domain
[TABLE]
Lemma 6.1**.**
Let satisfy the conditions (1.12). Then the S-matrix and the matrix-valued function , defined by (4.6), satisfy
[TABLE]
as , uniformly in ,
[TABLE]
as , uniformly in .
Proof. Let . The definition (3.11) and the asymptotics (3.18) and (3.20) give
[TABLE]
where
[TABLE]
[TABLE]
The asymptotics (6.5) implies
[TABLE]
The identity (6.3) and the definitions (6.4) yield the asymptotics (6.1).
We prove the asymptotics (6.2). Substituting the identities (4.13), (4.14) into the definition (4.6) and using the definition (3.11) we obtain
[TABLE]
Let and let . Integrations by parts in the definitions (4.16) give
[TABLE]
Substituting these asymptotics into the identities (4.15) we obtain
[TABLE]
[TABLE]
Repeating the arguments from the proof of the asymptotics (3.20) we obtain
[TABLE]
[TABLE]
[TABLE]
The asymptotics (3.19) and (6.9) give
[TABLE]
where
[TABLE]
[TABLE]
The asymptotics (6.7) and (6.10) imply
[TABLE]
where
[TABLE]
The asymptotics (6.8) and (6.11) yield
[TABLE]
where
[TABLE]
Substituting the identities (6.3), (6.12), (6.15) and (6.17) into the relation (6.6) we obtain the identity
[TABLE]
The definitions (6.4), (6.13) and the identity (6.19) yield
[TABLE]
The standard matrix formula gives
[TABLE]
where
[TABLE]
Substituting this identity into (6.20) we obtain
[TABLE]
The definition (6.14) implies
[TABLE]
The asymptotics (6.5), (6.16), (6.18) and (6.22) yield
[TABLE]
[TABLE]
[TABLE]
which yields
[TABLE]
Substituting the asymptotics (6.22) and (6.23) into the identity (6.21) we obtain the asymptotics (6.2).
6.2. Asymptotics of resonances
We are ready to determine asymptotics of resonances.
Proof of Theorem 1.3. Let and let be a resonance. The identity (4.9) shows that is a zero of the function in . The asymptotics (6.1) and the identity imply that satisfies the equation
[TABLE]
Then lies on the logarithmic curve in , given by
[TABLE]
and satisfies
[TABLE]
and there are not any other large resonances in .
Let , let be a resonance and let be large enough. The identity (4.10) shows that is a zero of the function in . The identity and the asymptotics (6.2) gives
[TABLE]
Then lies on the curve and satisfies
[TABLE]
and there are not any other large resonances in . The asymptotics (6.24), (6.25) give the asymptotics (1.13), which yields the asymptotics (1.14).
The estimates (1.8) and (1.15) yield that the determinants is of exponential type. But the asymptotics (1.13) and the asymptotics of the Levinson Theorem (1.11) show that the determinants is not of the Cartwright class.
6.3. Further discussions
We will discuss what properties of resonances of the second and fourth order operators with compactly supported coefficients are common and which are specific.
Common properties:
-
The determinants and are exponentially type functions of the variable and each of them has an axis of symmetry.
-
For coefficients with steps the resonances have the logarithmic type asymptotics.
Specific properties of the determinant for a Schrödinger operator:
-
In terms of the spectral parameter the Riemann surface for the determinant is the two sheeted Riemann surface for the function . The function as on the physical sheet and on the non-physical sheet. It has a finite number of zeros (eigenvalues) on the physical sheet and an infinite number of zeros (resonances) on the non-physical one.
-
The determinant belongs to the Cartwright class . Then the Levinson Theorem gives the distribution of resonances in the large disc.
-
The number of resonances in the disk for large has asymptotics .
-
Using one identity (2.10) we obtain an analytic extension of the determinant from the physical sheet onto the non-physical one.
Specific properties of the determinant for a fourth order operator:
-
The Riemann surface for the determinant is the four sheeted Riemann surface for the function . The function satisfies: at on the first sheet, on the second and fourth sheets and on the third sheet. It has a finite number of zeros (eigenvalues) on the first (physical) sheet and an infinite number of zeros (resonances) on the other (non-physical) sheets. The number of resonances in the large disc on the third sheet is, roughly speaking, in two times more than on the second (or fourth) sheet.
-
The determinant is not in the Cartwright class.
-
The number of resonances in the disk has asymptotics as .
-
In order to obtain an analytic extension of the determinant from the first sheet onto the other sheets we need to use two identities (4.9), (4.10).
Acknowledgments. A. Badanin was supported by the RFBR grant No 16-01-00087. E. Korotyaev was supported by the RSF grant No. 15-11-30007.
The reference list from the paper itself. Each links out to its DOI / PubMed record.
- 1[AP 08] Aktosun, T., Papanicolaou, V. G. Time evolution of the scattering data for a fourth-order linear differential operator. Inverse Problems, 24(5) (2008), 055013.
- 2[BK 15] Badanin, A., Korotyaev, E. Inverse problems and sharp eigenvalue asymptotics for Euler-Bernoulli operators. Inverse Problems, 31 (2015), 055004.
- 3[BK 16] Badanin, A., Korotyaev, E. Determinant and fundamental solutions for 4-th order operators. Preprint, 2016.
- 4[BK 17] Badanin, A., Korotyaev, E. Resonances for Euler-Bernoulli operator on the half-line. Journal of Differential Equations, 263 (2017), 534–566.
- 5[B 85] Beals, R. The inverse problem for ordinary differential operators on the line. American Journal of Mathematics, 107(2) (1985), 281–366.
- 6[BDT 88] Beals, R., Deift, P., Tomei, C. Direct and inverse scattering on the line, Nathematical survays and monograph series, No. 28, AMS, Providence, 1988.
- 7[Bu 68] Butler, J. B. On the inverse problem for differential operators of fourth order with rational reflection coefficients. Journal of Differential Equations, 4(4) (1968), 573–589.
- 8[Ko 88] Koosis, P. The logarithmic integral I, Cambridge Univ. Press, Cambridge, London, New York 1988.
