An embedding relation for bounded mean oscillation on rectangles
Beno\^it F. Sehba

TL;DR
This paper investigates the properties of a specific function space called mean little BMO in a two-parameter setting, showing it is a strict subset of the Cotlar-Sadosky space, with implications for harmonic analysis.
Contribution
It establishes that the Cotlar-Sadosky space of bounded mean oscillation functions is a proper subset of the mean little BMO space in the two-parameter context.
Findings
Mean little BMO is introduced for functions on rectangles.
The Cotlar-Sadosky space is shown to be a strict subspace of mean little BMO.
Results relate to the multiplier algebra of product BMO.
Abstract
In the two-parameter setting, we say a function belongs to the mean little , if its mean over any interval and with respect to any of the two variables has uniformly bounded mean oscillation. This space has been recently introduced by S. Pott and the author in relation with the multiplier algebra of the product of Chang-Fefferman. We prove that the Cotlar-Sadosky space of functions of bounded mean oscillation is a strict subspace of the mean little .
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Taxonomy
TopicsNonlinear Differential Equations Analysis · Advanced Banach Space Theory · Spectral Theory in Mathematical Physics
An embedding relation for bounded mean oscillation on rectangles.
Benoît F. Sehba
Abstract.
In the two-parameter setting, we say a function belongs to the mean little , if its mean over any interval and with respect to any of the two variables has uniformly bounded mean oscillation. This space has been recently introduced by S. Pott and the author in relation with the multiplier algebra of the product of Chang-Fefferman. We prove that the Cotlar-Sadosky space of functions of bounded mean oscillation is a strict subspace of the mean little .
Key words and phrases:
Bounded mean oscillation, logarithmic mean oscillation, product domains.
2010 Mathematics Subject Classification:
Primary 42B15, 32A37; Secondary 42B35
1. Introduction and results
1.1. Introduction
In the two-parameter case, the mean little space consists of those functions such that their mean over any interval with respect to any of the two variables is uniformly in . This space was introduced recently in the literature by S. Pott and the author in their way to the characterization of the multiplier algebra of the product of Chang-Fefferman ([2, 6, 7]). Its definition is very close in spirit to the one of the little of Cotlar and Sadosky ([3]) and this is somehow misleading. It is pretty clear that the little embeds continuously into the mean little and it was natural to ask if both spaces are the same. To find out, we use an indirect method; we characterize the multiplier algebra of the Cotlar-Sadosky space and the set of multipliers from the little to the mean little .
1.2. Definitions and results
Given two Banach spaces of functions and , the space of pointwise multipliers from to is defined as follows
[TABLE]
When , we simply write .
The so-called small BMO space on , introduced by Cotlar and Sadosky and denoted consists of functions such that the quantity
[TABLE]
is finite, . Seen as a quotient space with the set of constants, is a Banach space with norm
Note that in the above definition, since is a rectangle in , is a constant. We will sometimes consider the case where is a rectangle in with an integer, , in which case is a function of variables.
Another notion of function of bounded mean oscillation was introduced in [7] in the two-parameter setting. This notion is inspired from the one of M. Cotlar and C. Sadosky ([3]). One of its higher-parameter versions is defined as follows.
Definition 1.1**.**
A function belongs to if there is a constant such that for any integers , and any rectangle ,
[TABLE]
The space seen as a quotient space by the set of constants is a Banach space under the norm
[TABLE]
where stands for the smallest constant in the above definition.
It is clear from the definitions above that embeds continuously into . We will be calling the mean little . Our main result is the following.
Theorem 1.2**.**
* is strictly continuously embedded into .*
To prove the above theorem, we first prove the following.
Theorem 1.3**.**
The only pointwise multipliers of are the constants.
We say a function has bounded logarithmic mean oscillation on rectangles, i.e if
[TABLE]
Let us introduce also the mean little space in product domains.
Definition 1.4**.**
A function belongs to if there is a constant such that for any decomposition , , and any rectangle ,
[TABLE]
If stands for the smallest constant in the Definition 1.4, then seen as a quotient space by the set of constants, is a Banach space with the following norm
[TABLE]
In terms of multipliers, to get close to the one parameter situation, we need to start from and take as the target space.
Theorem 1.5**.**
Let . Then the following assertions are equivalent.
- (i)
* is a multiplier from to .*
- (ii)
.
Moreover,
[TABLE]
where is the norm of the multiplication operator from to .
Theorem 1.3 and Theorem 1.5 clearly establish Theorem 1.2 since
contains more than constants. The proofs are given in the next section. The last section of this note also states that the only multiplier from a Banach space of functions (strictly) containing to is the constant zero.
As we are dealing only with little spaces of functions of bounded mean oscillation, we essentially make use of the one parameter techniques. This is not longer possible when considering the multipliers of the product of Chang-Fefferman for which one needs more demanding techniques ([5, 6, 7]).
2. Comparison via multiplier algebras
2.1. Proof of Theorem 1.3
The space has the following equivalent definitions ([3, 4]) that we need here.
Proposition 2.1**.**
The following assertions are equivalent.
- (1)
.
- (2)
* and there exists a constant such that for any decomposition , ,*
- (i)
, for all .
- (ii)
* for all .*
Proof.
The proof was given in the two-parameter case in [3]. It is essentially the same proof in the multi-parameter setting. We follow the simplified two-parameter proof from [9].
We first suppose that that is we have that for any , , ,
[TABLE]
If , then letting we get that
[TABLE]
for any
Repeating this process for , we obtain that
[TABLE]
and consequently that
[TABLE]
The same reasoning leads to
[TABLE]
For the converse, we write as follows
[TABLE]
Hence
[TABLE]
Integrating both sides of (2.1) over and with respect to the measure , we obtain
[TABLE]
Clearly,
[TABLE]
On the other hand,
[TABLE]
Thus for any and ,
[TABLE]
Hence . The proof is complete. ∎
Note that if is the smallest constant in the equivalent definition above, then is comparable to .
We make the following observation that can be proved exactly as in the one parameter case.
Lemma 2.2**.**
Let . Then
[TABLE]
Let us also observe the following.
Lemma 2.3**.**
The following assertions hold.
- (i)
Given an interval in , there is a function in , denoted such that
- –
the restriction of to is .
- –
* where is a constant that does not depend on .*
- (ii)
For any , the function
* belongs to . Moreover,*
[TABLE]
- (iii)
There is a constant such that for any and any rectangle ,
[TABLE]
and this is sharp.
Proof.
Assertion follows directly from the definition of .
is surely well known, we give a proof here for completeness: let be a fixed interval in . Let and be the intervals in with the same center as and such that , here and is the smallest integer such that . We define . Thus,
[TABLE]
Next, we define , , for . Now consider the function defined on by
[TABLE]
Clearly,
[TABLE]
Lemma 2.4**.**
For each interval , the function defined by (2.3) belongs to .
Proof.
We start by estimating the -norm of . We have
[TABLE]
It is clear that the last sum in the above equalities is finite and so .
For any dyadic interval , let be minimal such that , and be maximal such that . Let us estimate the length of for any .
If then and there is nothing to say. If then and .
Next, we consider the case . We remark that in this case, half of is contained in . Consequently, for any , we have . Finally, we have
[TABLE]
Hence,
[TABLE]
Thus, for each interval , the function given by (2.3) belongs to and there exists a positive constant independent of such that .
To prove , we observe that by definition, given , for any rectangle , , is uniformly bounded. It follows from the one parameter estimate of the mean of a function of bounded mean oscillation and the definition of that for any rectangle ,
[TABLE]
In particular, for any rectangle , we have
[TABLE]
The sharpness follows by applying the last inequality to the function
, , and using .
The proof is complete. ∎
Lemma 2.4 and its proof complete the proof of Lemma 2.3. ∎
We now reformulate and prove Theorem 1.3.
Theorem 2.5**.**
Let . Then the following assertions are equivalent.
- (a)
* is multiplier of .*
- (b)
* is a constant. *
Proof.
Clearly, . We prove that .
Assume that is a multiplier of . Then for any , and any integer , , is uniformly bounded for all fixed and . Let us take as the function , , , , . Then it follows that
[TABLE]
But from assertion of Lemma 2.3 we have that for any fixed,
[TABLE]
where is the norm of the multiplication by , .
Hence for any and ,
[TABLE]
Letting for example in (2.4), we see that necessarily,
for any . As runs through , we obtain
that for any ,
[TABLE]
The latter gives that is a constant. ∎
We have the following consequence which says that the only bounded functions in are the constants. This is pretty different from the one parameter case ([8]).
Corollary 2.6**.**
Assume that and
[TABLE]
Then is a constant.
Proof.
Following Theorem 1.3 we only need to prove that any bounded function which satisfies (2.5) is a multiplier of . For this we first recall that if , then for any rectangle , we have the estimate
[TABLE]
Now assume that and satisfies (2.5), and let . Then using the above estimate, we obtain for any ,
[TABLE]
It follows from the latter and Lemma 2.2 that if is bounded and satisfies (2.5), then for any , belongs to . That is is a multiplier of . The proof is complete. ∎
Remark 2.7**.**
Let us first recall that in the one parameter case, it is a result of D. Stegenga [8] that is the exact range of pointwise multipliers of . Let us define another little space in the two-parameter case as follows.
Definition 2.8**.**
A function is in if there is a constant such that for all and for all .
Clearly, is a subspace of . The one parameter intuition and the equivalent definition of in Proposition 2.1 may lead one to claim that any function is a multiplier of . This is not the case as the above results show and since contains more than constants. For example, for any , the function belongs to .
2.2. Proof of Theorem 1.5
We prove Theorem 1.5 in this section.
Proof of Theorem 1.5.
: we start by proving that any multiplier from to is a bounded function. We recall the following estimate of the mean over a rectangle of functions in :
[TABLE]
It follows that if is multiplier from to , then for any and for any rectangle ,
[TABLE]
Applying (2.6) to and using assertions and of Lemma 2.3, we see that there is a constant such that
[TABLE]
We conclude that .
To prove that , we only need by the definition of to check that for any integer , any rectangle , () is uniformly bounded. Let be a rectangle in and , be again the associated sum of functions which are uniformly in . We have
[TABLE]
Hence for any integer and for any , is uniformly bounded. Thus, by definition, .
: Let . To prove that
, we only need to check that for any integer , for any rectangle , and any , () is uniformly bounded. Let be a rectangle in . Then
[TABLE]
To estimate the first term, we only use that to obtain
[TABLE]
For the second term, we use the fact that as is uniformly bounded,
[TABLE]
. Consequently,
[TABLE]
The last term only uses the fact that .
[TABLE]
The estimates of , and , and Lemma 2.2 allow to conclude that
[TABLE]
This complete the proof of the theorem. ∎
3. Multipliers to
We would like to deduce some consequences of the above approach. We consider multipliers from any Banach space of functions on (strictly) containing to . We have the following general result.
Theorem 3.1**.**
Let be any Banach space of functions on that strictly contains . Then .
Proof.
Clearly, [math] sends any function of to by multiplication. Now let be any multiplier from to , then is also a multiplier from to itself. It follows from Theorem 1.3 that is a constant . Suppose that and recall that is a proper subspace of . Then for any , we have that . This contradicts the fact that is a strict subspace of . Hence is necessarily [math]. The proof is complete. ∎
Taking as , the Chang-Fefferman space or we have as corollary the following.
Corollary 3.2**.**
We have
[TABLE]
The author would like to thank the referee for comments and observations that improved the presentation of this note.
The reference list from the paper itself. Each links out to its DOI / PubMed record.
- 1[1]
- 2[2] S-Y. A. Chang and R. Fefferman, A continuous version of H 1 superscript 𝐻 1 H^{1} duality with BMO on the bidisc , Ann. of Math. (2) 112 (1980), no. 1, 179-201.
- 3[3] M. Cotlar, C. Sadosky, Two distinguished subspaces of product BMO and Nehari-AAK theory for Hankel operators on the torus , Integral Equations Operator Theory 26 (1996), no. 3, 273 304.
- 4[4] S. Ferguson, C. Sadosky, Characterizations of bounded mean oscillation on the polydisk in terms of Hankel operators and Carleson measures , J. Anal. Math. 81 (2000), 239-267.
- 5[5] S. Pott, B. Sehba, Logarithmic mean oscillation on the polydisc, endpoint results for multi-parameter paraproducts, and commutators on BMO , J. Anal. Math. 117 (2012), No. 1, 1-27.
- 6[6] S. Pott, B. Sehba, The multiplier algebra of product BMO BMO \mathrm{BMO} , preprint.
- 7[7] B. F. Sehba, Operators on some analytic function spaces and their dyadic counterparts , thesis, University of Glasgow 2009.
- 8[8] D. A. Stegenga, Bounded Toeplitz operators on H 1 superscript 𝐻 1 H^{1} and applications of the duality between H 1 superscript 𝐻 1 H^{1} and the functions of bounded mean oscillation , Amer. J. Math. 98 (1976), No. 3, 573–589
