
TL;DR
This paper constructs new examples of Brody hyperbolic surfaces, specifically Horikawa surfaces and double covers of Hirzebruch surfaces, expanding the known classes of hyperbolic algebraic surfaces.
Contribution
It introduces explicit constructions of Brody hyperbolic surfaces as double covers with specific branch loci, including the first such examples of Horikawa surfaces.
Findings
Constructed a Brody hyperbolic Horikawa surface as a double cover of P^2.
Built Brody hyperbolic double covers of Hirzebruch surfaces with minimal branch degrees.
Expanded the catalog of known hyperbolic algebraic surfaces.
Abstract
We construct a Brody hyperbolic Horikawa surface that is a double cover of branched along a smooth curve of degree . We also construct Brody hyperbolic double covers of Hirzebruch surfaces with branch loci of the lowest possible bidegree.
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Construction of hyperbolic Horikawa surfaces
Yuchen Liu
Department of Mathematics, Princeton University, Princeton, NJ, 08544-1000, USA.
Abstract.
We construct a Brody hyperbolic Horikawa surface that is a double cover of branched along a smooth curve of degree . We also construct Brody hyperbolic double covers of Hirzebruch surfaces with branch loci of the lowest possible bidegree.
1. Introduction
A complex algebraic variety is said to be Brody hyperbolic if there are no non-constant holomorphic maps from to . Thanks to Brody Lemma [Bro78], we know that a proper Brody hyperbolic variety is Kobayashi hyperbolic, i.e. its Kobayashi pseudometric is non-degenerate. In [Lan86], Lang conjectured that a complex projective variety is Brody hyperbolic if every subvariety of is of general type. More generally, Green, Griffiths [GG79] and Lang [Lan86] proposed the following conjecture:
Conjecture 1.1** (Green-Griffiths-Lang).**
If a complex projective variety is of general type, then there exists a proper Zariski closed subset such that any non-constant holomorphic map will satisfy .
It is easy to see that Lang’s conjecture follows from the Green-Griffiths-Lang conjecture by a Noetherian induction argument. Even in the case of surfaces, these conjectures are still open. Based on works of Bogomolov [Bog77] and Lu-Yau [LY90], McQuillan [McQ98] showed that Conjecture 1.1 is true for minimal surfaces of general type with . Demailly and El Goul [DEG00] proved Conjecture 1.1 for some surfaces with . In principle, minimal surfaces of general type with minimal should be the most difficult case for these conjectures. For example, a very general quintic surface in (, ) does not contain any rational or elliptic curve by a result of Xu [Xu94], but we do not have a single example of quintic surface that is Brody hyperbolic.
Recall that the Chern numbers of minimal surfaces of general type satisfy the Noether inequality . In the extreme case, a surface that reaches the equality if is even and otherwise is called a Horikawa surface. A Horikawa surface with even is classified to be either a double cover of or of a Hirzebruch surface (see [Hor76]). For instance, a double cover of branched along a smooth curve of degree is Horikawa. Using orbifold techniques, Roulleau and Rousseau [RR13] showed that a very general member of this class of Horikawa surfaces is algebraic hyperbolic (in particular it has no rational or elliptic curve). Hence a very general member of this class of surfaces is expected to be Brody hyperbolic according to Conjecture 1.1.
Our first main result shows that there exists a Horikawa surface in this class that is Brody hyperbolic. This gives an analytic generalization of Roulleau-Rousseau’s result (in particular implies [RR13, Theorem 3.2]) and also provides evidence supporting Conjecture 1.1.
Theorem 1.2**.**
Let be an even integer. Then there exists a smooth plane curve of degree such that the double cover of branched along is Brody hyperbolic if and only if .
We remark that here that some Brody hyperbolic double covers of have been constructed in [Liu16, Theorem 5] with branch loci of minimal degree .
For an integer , let be the -th Hirzebruch surface. The surface has a natural fibration . Denote by a fiber, and by a section of the fibration such that . Any divisor on is linearly equivalent to for integers and , and we say that is of bidegree .
In [RR13], Roulleau and Rousseau also showed that a very general Horikawa surface that is a double cover of branched along a curve of bidegree does not contain a rational curve. In general it will contain an elliptic curve, so it cannot be Brody hyperbolic. In the next theorem, we construct smooth curves of the lowest possible bidegrees in along which the double covers of are Brody hyperbolic.
Theorem 1.3**.**
Let be even integers. Then there exists a smooth curve in the linear system such that the double cover of branched along is Brody hyperbolic if and only if one of the following is true:
- •
* and ;*
- •
, and .
The “only if” parts of Theorem 1.2 and 1.3 are somewhat easy which follow by showing the existence of a rational or elliptic curve on the double cover when the branch locus has a smaller (bi)degree.
Our strategy to prove the “if” parts of Theorem 1.2 and 1.3 is by using a degeneration process consisting of three steps. Denote by the base surface or . In step 1, we degenerate the branch locus to a non-reduced double curve where is smooth. As a result, the double cover degenerates to a union of two copies of glued along . Using stability of intersections of entire curves, it suffices to show that both and are Brody hyperbolic. In step 2, we degenerate into a line arrangement . By a variant of Zaidenberg’s method [Zai89], it suffices to show that is Brody hyperbolic. By classical results, we know that for or , is Brody hyperbolic. In step 3, we apply Zaidenberg-Duval’s method [Zai89, SZ02, Duv04, Duv17] of degenerating into line arrangements in order to deduce hyperbolicity of from hyperbolicity of which is known by classical results.
Historical remark. Note that Duval [Duv04] constructed a Brody hyperbolic sextic surface in by nicely adopting Zaidenberg’s method [Zai89], together with the hyperbolic non-percolation introduced in [SZ02]. In this paper, we follow precisely Duval’s approach [Duv04] which was further developed in [Huy16]. Thus we will use the term Zaidenberg-Duval’s method for this approach in our presentation.
The paper is organized as follows. In Section 2, we recall Zaidenberg-Duval’s method [Zai89, SZ02, Duv04, Duv17] in constructing a smooth curve satisfying the hyperbolicity of . We recall results in [Huy16, Section 4] in the surface case in Lemma 2.2, and we apply this lemma to and in Corollary 2.3 and 2.4. In order to deform into a smooth curve preserving the hyperbolicity of , we apply Zaidenberg’s method [Zai89] in Section 4 (see Lemma 4.2). Starting with a log smooth projective surface pair and a set of rational curves with being Brody hyperbolic, we introduce the concept of admissible deformation (see Definition 4.1) in order to preserve the hyperbolicity of under deformation. Using the technique of smoothing of rational trees in the deformation process (e.g. [Kol96, II.7]), we are able to translate an admissible deformation of rational curves into an admissible contraction of their dual graphs (see Lemma 4.4). In Section 3, we study dual graphs that can be admissibly contracted into singletons. Using these results, we construct a smoothing of preserving the hyperbolicity of under certain assumptions on the dual graph of (see Lemma 4.8). Applying this lemma to or gives smooth curves and with certain (bi)degrees such that is Brody hyperbolic. In Section 5, we prove Theorem 1.2 and 1.3. As an application of Theorem 1.2, we give new examples of Brody hyperbolic surfaces in of minimal degree that are cyclic covers of under linear projections (see Theorem 5.3). This also improves [Liu16, Theorem 25]. We mention that a Brody hyperbolic Horikawa surface of even has to be a double cover of branched along a degree curve (see Remark 5.5).
Notation
Throughout this paper, we work over the complex numbers . For a subset of a projective variety , we say that is Brody hyperbolic if any non-constant holomorphic map satisfies . A divisor on a smooth surface is normal crossing if is reduced and has only nodal singularities. Moreover, a normal crossing divisor is said to be simple normal crossing if all irreducible components of are smooth. We say that a surface pair is log smooth if is a smooth surface and is a simple normal crossing divisor on . A reduced projective curve is stable (in the sense of Deligne-Mumford) if it has only nodal singularities and its dualizing sheaf is ample.
Acknowledgement
I would like to thank Xavier Roulleau and Erwan Rousseau for fruitful discussions. I wish to thank Dinh Tuan Huynh, János Kollár and Ziquan Zhuang for helpful comments and suggestions, and Christian Liedtke for his interest. I also wish to thank the anonymous referees for their careful work. The author was partially supported by NSF Grant DMS-1362960.
2. Zaidenberg-Duval’s method
We first recall the following known facts from complex analysis whose proof is a simple application of the classical Hurwitz Theorem. (See also [Kob98, 3.6.11], [Duv17, Stability of intersections] or [Huy16, Section 3.1].)
Lemma 2.1** (Stability of intersections).**
Let be a normal proper complex analytic space. Let be an effective Weil divisor in , i.e. is a sum of closed analytic subvarieties of codimension . Suppose that a sequence of entire curves in converges to an entire curve . If , then
[TABLE]
where .
The following lemma was proved in [Huy16, Section 4] (see also [Duv17, Lemma]).
Lemma 2.2**.**
Let be a smooth projective surface. Let be a set of irreducible curves on such that is log smooth. Let be a globally generated line bundle on . Assume the following holds:
- (a)
* is Brody hyperbolic;* 2. (b)
For any , is a stable curve; 3. (c)
For any , there exists an effective Cartier divisor such that .
Then there exists a smooth curve such that is log smooth and X\setminus\big{(}(\cup_{i=1}^{m}C_{i})\setminus S\big{)} is Brody hyperbolic.
Proof.
See [Huy16, Section 4]. ∎
The following corollary was proved in [Huy16, Section 4] using Lemma 2.2.
Corollary 2.3** ([Huy16, Section 4]).**
Let be a set of lines in general position in with . Let be an integer. Then there exists a smooth plane curve of degree such that is log smooth and \mathbb{P}^{2}\setminus\big{(}(\cup_{i=1}^{m}C_{i})\setminus S\big{)} is Brody hyperbolic.
Corollary 2.4**.**
Let be a set of curves in . Assume that is a general curve in for any ; is a general curve in for any . Then there exists a smooth curve in such that is log smooth and \mathbb{F}_{N}\setminus\big{(}(\cup_{i=1}^{a+b}C_{i})\setminus S\big{)} is Brody hyperbolic if one of the following is true:
- •
* and ;*
- •
, and .
Proof.
Firstly, let us consider special cases where achieve their minima, i.e. , or , , . Since both linear systems and are base point free, for a general choice of the pair is log smooth. Let be a line bundle on . Then we only need to show that the assumptions (a), (b) and (c) of Lemma 2.2 are fulfilled for and .
If and , then and consists of vertical lines and horizontal lines in general position. It is clear that is Brody hyperbolic, so (a) is satisfied. For (b), each intersects four ’s with . So for any , intersects with at least three ’s with . Since , is stable, hence (b) is satisfied. Since , for and for , it is easy to see that (c) is also satisfied.
If , and , then the natural fibration maps , , to three distinct points in . It is clear that for . Hence for a general choice of , the set has at least three points for any fiber of . Since is Brody hyperbolic, the fiber and the base of are Brody hyperbolic. Hence (a) is satisfied. For (b), each with intersects each with . Since , each with intersects each with . As a result, each intersects with at least four ’s with . So (b) is satisfied by the same reason as in the last paragraph. Since , , for , and for , it is easy to see that (c) is also satisfied.
Up to now we have shown the corollary for cases where achieve their minima. More precisely, under the assumptions of , for general choices of and there exists a smooth curve in , such that is log smooth and \mathbb{F}_{N}\setminus\big{(}((\cup_{i=1}^{a_{\min}}C_{i})\cup(\cup_{j=a+1}^{a+b_{\min}}C_{j}))\setminus S\big{)} is Brody hyperbolic. If one of is strictly bigger than its minimum, then
[TABLE]
where the latter set is Brody hyperbolic. Hence \mathbb{F}_{N}\setminus\big{(}(\cup_{i=1}^{a+b}C_{i})\setminus S\big{)} is Brody hyperbolic. Besides, since is log smooth, for general choices of and we also have that is log smooth. This finishes the proof. ∎
3. Admissible contractions of multigraphs
Definition 3.1**.**
- (a)
A vertex-weighted multigraph is an ordered quadruple such that
- •
is a finite set of vertices;
- •
is a finite set of edges;
- •
assigns each edge an unordered pair of endpoint vertices;
- •
assigns to each vertex an integer as its weight. 2. (b)
For a vertex , we define the degree (respectively reduced degree) of to be its number of incident edges (respectively adjacent vertices). More precisely,
[TABLE] 3. (c)
Let be two vertex-weighted multigraphs. We say that is a submultigraph of if there exists injective maps and , such that and . If, moreover, is bijective, then we say that is a spanning submultigraph of . 4. (d)
A vertex-weighted multigraph is completely multipartite if there does not exist a triple of vertices such that both and are non-adjacent, but is adjacent.
Definition 3.2**.**
- (a)
Let be two vertex-weighted multigraphs. We say that is a contraction of with respect to a pair of adjacent vertices in if there exist maps and such that
- •
, and induces a bijection between and ;
- •
is bijective, and as maps from ;
- •
, and as maps from to . 2. (b)
A contraction of with respect to is said to be admissible if there exists a non-negative integer such that the following conditions hold:
- •
For each vertex other than and , ;
- •
and ;
- •
and . 3. (c)
A vertex-weighted multigraph is said to be admissibly contractible if there exists a sequence of vertex-weighted multigraphs such that , is a singleton, and is an admissible contraction of for each .
Example 3.3**.**
We give an illustration of an admissible contraction of vertex-weighted multigraphs.
3$$v_{1}$$3$$v_{2}$$3$$v_{3}
3$$w_{2}$$6$$w_{1}$$*
Here , , for any , and . Each vertex is represented as a circle in the picture. The name of each vertex is marked outside the circle, and its weight is marked inside the circle. Each edge connecting two vertices is represented as an arc connecting two circles.
In the illustration above, we see that is a contraction of with respect to , where is given by and . Each contraction is represented as an arrow. The two merging vertices of are represented as yellow filled circles, and we mark outside circles representing their images under . If a contraction is admissible, we mark the corresponding value of above the arrow. It is easy to verify that in the picture above, is an admissible contraction of with respect to .
The following lemma follows easily from the definitions.
Lemma 3.4**.**
Let be a vertex-weighted multigraph. Let be a spanning submultigraph of . If is admissibly contractible, then so is .
Proposition 3.5**.**
The following vertex-weighted multigraphs , , and are all admissibly contractible:
* * 2$$v_{1}$$2$$v_{2}$$2$$v_{3}$$2$$v_{4}$$2$$v_{5} * * 2$$v_{1}$$2$$v_{2}$$2$$v_{3}$$2$$v_{4}$$2$$v_{5}$$2$$v_{6} **
* * 2$$v_{1}$$2$$v_{7}$$2$$v_{6}$$2$$v_{2}$$2$$v_{3}$$2$$v_{5}$$2$$v_{4} * * 2$$v_{1}$$2$$v_{2}$$2$$v_{8}$$2$$v_{7}$$2$$v_{3}$$2$$v_{4}$$2$$v_{6}$$2$$v_{5} **
Proof.
For simplicity, we will omit the name of vertices in all pictures. A successive admissible contraction of is illustrated as below:
2$$2$$2$$2$$2
4$$*$$2$$2$$2
4$$4$$*$$2
4$$6$$*
10$$*
A successive admissible contraction of is illustrated as below:
2$$2$$2$$2$$2$$2
4$$*$$2$$2$$2$$2
4$$4$$*$$2$$2
4$$4$$4$$*
4$$8$$*
12$$*
A successive admissible contraction of is illustrated as below:
2$$2$$2$$2$$2$$2$$2
2$$2$$2$$4$$*$$2$$2
2$$2$$2$$4$$4$$*
It is clear that is a spanning submultigraph of . Since is admissibly contractible, so is . Hence is also admissibly contractible.
An admissible contraction of is illustrated as below:
2$$2$$2$$2$$2$$2$$2$$2
4$$*$$2$$2$$2$$2$$2$$2
It is clear that is a spanning submultigraph of . Since is admissibly contractible, so is . Hence is also admissibly contractible. ∎
Lemma 3.6**.**
Let be a vertex-weighted multigraph. Let be a submultigraph of . Assume the following conditions:
- (a)
* is completely multipartite;* 2. (b)
; 3. (c)
If is a set of mutually non-adjacent vertices of , then .
Then there exists a successive admissible contraction of such that is a spanning submultigraph of .
Proof.
We do induction on . If , then the lemma is proved by taking . Assume that the lemma is proved for . Let be an arbitrary vertex of . Let be the set of all vertices in that are not adjacent to in . Since is completely multipartite, is a set of mutually non-adjacent vertices of (hence of ). By assumption, we have . This implies that for any vertex of . Let us pick a vertex , then is adjacent to a vertex . Let be the contraction of with respect to . Since and each vertex of have reduced degree , is an admissble contraction of when . It is clear that is a also submultigraph of with , , and is also a completely multipartite. By the inductive hypothesis, there exists a successive admissible contraction of such that is a spanning submultigraph of . The proof is finished by taking . ∎
Remark 3.7**.**
It is easy to verify that satisfies assumption (c) of Lemma 3.6 for each .
Lemma 3.8**.**
Let be a completely multipartite vertex-weighted multigraph. Assume that for any vertex of we have and . Then is admissibly contractible.
Proof.
Since is completely multipartite, there exists a partition of vertices such that two vertices are non-adjacent if and only if they belong to the same . Denote . For simplicity we may assume that . Then implies . In particular, .
We divide the proof into five cases based on values of and . We will use Lemma 3.6 in all cases. Since satisfies assumptions (a)(b) of Lemma 3.6, we only need to verify assumption (c).
Case 1. .
Let us pick for . Let be the submultigraph of generated by . Since are mutually adjacent in , is a spanning submultigraph of . Hence satisfies condition (c). By Lemma 3.6, there exists a successive admissible contraction of such that (hence ) is a spanning submultgraph of . By Proposition 3.5, is admissibly contractible, hence is admissibly contractible.
Case 2. .
Since , we have that and . Let us pick , , and . Let be the submultigraph of generated by . It is easy to see that is a spanning submultigraph of , hence satisfies condition (c). By Lemma 3.6, there exists a successive admissible contraction of such that (hence ) is a spanning submultgraph of . By Proposition 3.5, is admissibly contractible, hence is admissibly contractible.
Case 3. and .
We know that . Let us pick , and . Let be the submultigraph of generated by . It is easy to see that is a spanning submultigraph of , hence satisfies condition (c). By Lemma 3.6, there exists a successive admissible contraction of such that (hence ) is a spanning submultgraph of . By Proposition 3.5, is admissibly contractible, hence is admissibly contractible.
Case 4. and .
Since , we have . Let us pick , and . Let be the submultigraph of generated by . It is easy to see that is a spanning submultigraph of , hence satisfies condition (c). By Lemma 3.6, there exists a successive admissible contraction of such that (hence ) is a spanning submultgraph of . By Proposition 3.5, is admissibly contractible, hence is admissibly contractible.
Case 5. .
Since , we have . Let us pick and . Let be the submultigraph of generated by . It is easy to see that is a spanning submultigraph of , hence satisfies condition (c). By Lemma 3.6, there exists a successive admissible contraction of such that (hence ) is a spanning submultgraph of . By Proposition 3.5, is admissibly contractible, hence is admissibly contractible. ∎
4. Zaidenberg’s method
Definition 4.1**.**
Let be a log smooth projective surface pair. Let be a reduced curve in . Let be a holomorphic flat family of reduced divisors on . Denote by the development of . We say that is an admissible deformation of if and the set is Brody hyperbolic. If, moreover, is normal crossing, an admissible deformation of is nodal if is normal crossing for any . Besides, we say that is a successive admissible deformation of if for each there exists , such that is an admissible deformation of where .
The following lemma is a generalization of Zaidenberg’s result [Zai89, Lemma-Definition 3.2] to surface pairs.
Lemma 4.2**.**
Let be a log smooth projective surface pair. Let be a reduced curve in such that is normal crossing. Let be an admissible deformation of . If is Brody hyperbolic, then is also Brody hyperbolic for any . (Note that being Brody hyperbolic is the same as saying that has the property of hyperbolic non-percolation through according to [SZ02].)
Proof.
The proof is similar to [Zai89, Proof of Lemma-Definition 3.2]. ∎
Lemma 4.3**.**
Let be a smooth projective rational surface. Let , be two intersecting rational nodal curves such that is normal crossing. Assume that and for some non-negative integer . Then for any subset , there exists a holomorphic flat family of divisors in such that and is an irreducible rational nodal curve singular at for any and any .
Proof.
Denote by the blow up of at . Let be the reduced exceptional divisor of . Let and be strict transforms of and under . It is easy to see that , and . It is clear that both and are irreducible rational nodal curves intersecting each other transversally. Denote by the normalization of . Since is an immersion, we have an exact sequence , where . Hence is nef and is ample. Denote by the gluing morphism of and at an intersection point of and . Then by [Kol96, II.7.5], so the deformation of is unobstructed. By [Kol96, I.2.17] there exists a holomorphic flat family of divisors such that and is an irreducible rational nodal curve whenever . After a reparametrization of if necessary we may also assume that is normal crossing for each . The lemma is proved by taking . ∎
Lemma 4.4**.**
Let be a log smooth projective surface pair with rational. Let be a reduced divisor on such that each is an irreducible nodal rational curve and is normal crossing. Assume
- •
;
- •
* for any ;*
- •
There exists a non-negative integer , such that and for any .
Then there exists a nodal admissible deformation of such that where is an irreducible rational nodal curve whenever .
Proof.
Let us pick distinct points in . By Lemma 4.3, there exists a holomorphic flat family of reduced divisors on such that and is an irreducible rational nodal curve singular at for any . By Bertini’s theorem, after a reparametrization of we may assume that is normal crossing for any . Let , then it suffices to show that is hyperbolic. As a divisor in , , where is the development of and . Thus is (analytically) reducible at if for some . By Lemma 4.3, we know that is analytically reducible at . Thus we have
[TABLE]
Since , we only need to show that is hyperbolic for any . For each , \#C_{i}\cap V=\#\big{(}\{x_{1},\cdots,x_{l}\}\cup(\cup_{j\geq 3}(C_{i}\cap C_{j}))\big{)}=l+(C_{i}\cdot(C-C_{1}-C_{2}))\geq 3. For each , \#C_{i}\cap V=\big{(}C_{i}\cdot(C-C_{i})\big{)}\geq 3. Hence is hyperbolic for each . The lemma is proved.∎
Definition 4.5**.**
Let be a smooth projective surface. Let be a reduced normal crossing divisor on . The dual graph of is a vertex-weighted multigraph defined as follows:
- •
;
- •
;
- •
For each , where is the unique unordered pair with ;
- •
For each , .
Lemma 4.6**.**
Let be a log smooth projective surface pair with rational. Let be a reduced divisor such that is normal crossing, and each is an irreducible rational curve. If the dual graph is admissibly contractible, then there exists a successive nodal admissible deformation such that is an irreducible rational nodal curve. If, moreover, is Brody hyperbolic, then can be chosen so that is Brody hyperbolic for any and any .
Proof.
The successive nodal admissible deformation can be constructed inductively by a successive admissible contraction of the dual graph using Lemma 4.4. The hyperbolicity part follows from Lemma 4.2 and taking reparametrizations of if necessary. ∎
Lemma 4.7**.**
Let be a log smooth projective surface pair with rational. Let be an irreducible rational nodal curve in such that is normal crossing. If and , then there exists a successive nodal admissible deformation of such that is an irreducible smooth hyperbolic curve. If, moreover, is Brody hyperbolic, then can be chosen so that is Brody hyperbolic for any and any .
Proof.
Let us pick two nodes of . Denote by the blow up of at . Let be the reduced exceptional divisor of . Let be the strict transform of under . We claim that is base point free in .
Since is rational, we have . Thus the claim is equivalent to saying that is globally generated. Since , we have
[TABLE]
By adjunction we have , so we have , where is the normalization of . Hence the global sections of separate any points on . In particular, this implies that is globally generated.
Now we have shown that is base point free on . By Bertini’s theorem, there exists a holomorphic flat family of irreducible divisors on such that and is log smooth for any . Let . Since intersects transversally at two points for any , it is clear that has two analytic branches intersecting in different points. Thus has two analytic branches at for each which implies that is hyperbolic. Besides, being log smooth implies that is nodal at , smooth elsewhere and intersects transversally with for any . Hence is a nodal admissible deformation of with being normal crossing for each .
Now let us fix an arbitrary . Since , we know that is hyperbolic for any . As we argued before in showing the base-point-freeness of , also implies that is base point free on . Hence by Bertini’s theorem there exists a holomorphic flat family of irreducible divisors on such that and is log smooth for any . Besides, is hyperbolic. Hence is a nodal admissible deformation of such that is normal crossing for any . Besides, for any , hence is hyperbolic for any . The lemma is proved by taking arbitrary . ∎
Lemma 4.8**.**
Let be a log smooth projective surface pair with rational. Let be a reduced divisor on such that is normal crossing. Assume that each is a base-point-free irreducible rational curve with , and it intersects with at least four other ’s. If X\setminus\big{(}(\cup_{i=1}^{m}C_{i})\setminus\Delta\big{)} is Brody hyperbolic, then there exists an irreducible smooth curve linearly equivalent to such that both and are Brody hyperbolic.
Proof.
Let be the dual graph of . Since each is base-point-free, is completely multipartite. By assumptions, for each vertex of we have and . Hence Lemma 3.8 implies that is admissibly contractible. By Lemma 4.6, there exists a successive nodal admissible deformation of such that is an irreducible rational curve and is Brody hyperbolic. Since each intersects with at least four other , we have , hence . Since , we have
[TABLE]
By applying Lemma 4.7 to , we know that there exists a successive nodal admissible deformation of such that is an irreducible smooth hyperbolic curve and is Brody hyperbolic. It is clear that is numerically equivalent to , hence they are linearly equivalent since is rational. The lemma is proved by taking . ∎
The following corollary is a generalization of [Zai89, Theorem 3.1] which says that there exists a smooth plane curve of degree whose complement is Brody hyperbolic for .
Corollary 4.9**.**
Let and be integers. Then there exists smooth plane curves and of degree and respectively, such that is log smooth and \mathbb{P}^{2}\setminus\big{(}C\setminus S\big{)} is Brody hyperbolic.
Proof.
Let be a set of lines in general position in . By Corollary 2.3, there exists a smooth plane curve of degree such that is log smooth and \mathbb{P}^{2}\setminus\big{(}(\cup_{i=1}^{m}C_{i})\setminus S\big{)} is Brody hyperbolic. We know that and each intersects all ’s whenever . Since , the corollary is proved by applying Lemma 4.8 to . ∎
The following corollary is related to [IT15, 1.2] where they studied hyperbolic imbeddedness of .
Corollary 4.10**.**
Let be integers. Then there exists smooth curves and in of bidegree and respectively, such that is log smooth and \mathbb{F}_{N}\setminus\big{(}C\setminus S\big{)} is Brody hyperbolic if one of the following is true:
- •
* and ;*
- •
, and .
Proof.
Let be a set of curves in , such that is a general curve in for any , and is a general curve in for any . By Corollary 2.4, there exists a smooth curve of bidegree such that is log smooth and \mathbb{F}_{N}\setminus\big{(}(\cup_{i=1}^{a+b}C_{i})\setminus S\big{)} is Brody hyperbolic. We know that for each and for each . From the proof of Corollary 2.4 we know that intersects with at least four ’s for each . Hence the corollary is proved by applying Lemma 4.8 to . ∎
5. Proofs
Lemma 5.1**.**
Let be a smooth projective surface. Let be a line bundle on . Let be an integer. Assume that there exists irreducible divisors and satisfying that is log smooth, and both and are Brody hyperbolic. Then there exists a smooth curve such that the degree cyclic cover of branched along is Brody hyperbolic.
Proof.
Let be the linear pencil of divisors on spanned by and . Then the development of is an effective Cartier divisor of . Since and intersect transversally, it is not hard to check in local charts that is smooth away from the finite set . Let be the degree cyclic cover of branched along . Then is smooth away from . From the construction it is clear that each fiber of is a degree cyclic cover of branched along . Since , is the union of irreducible components such that for any , and is an isomorphism for any .
Assume to the contrary that is not Brody hyperbolic for a sequence of non-zero complex numbers converging to [math]. Let be the sequence of entire curves. We may assume that tends to infinity after coordinate changes. By Brody Lemma (e.g. [Duv17]), after choosing a subsequence if necessary, there exists a sequence of reparametrizations where such that converges to an entire curve as . Notice that is Cartier away from , so Lemma 2.1 implies that is contained in at least one of the subsets of , where
[TABLE]
In particular, at least one of the subsets is not Brody hyperbolic. Under the projection , it is not hard to see that and for any . Thus is Brody hyperbolic for any , we get a contradiction.
As a result, is Brody hyperbolic for any sufficiently small. Since is smooth for general , the lemma is proved by choosing for sufficiently small. ∎
5.2****Proof of Theorem 1.2.
Let be the double cover of branched along .
For the “only if” part, if then is a rational surface; if then is a K3 surface. In both cases is not Brody hyperbolic. If , since Brody hyperbolicity is preserved under small deformation, we may deform a bit to ensure that there exists a bitangent line of that meets transversally in four further points. Hence by Riemann-Hurwitz formula, is an elliptic curve. Thus is never Brody hyperbolic when .
For the “if” part, Corollary 4.9 implies that there exist plane curves and of degree and respectively, such that is log smooth and is Brody hyperbolic. Since , is a smooth curve of genus at least , so it is Brody hyperbolic. Thus applying Lemma 5.1 to finishes the proof. ∎
The following theorem is an application of Corollary 4.9 and Lemma 5.1. It also improves [Liu16, Theorem 25].
Theorem 5.3**.**
Let be a composite number. Then there exists a smooth Brody hyperbolic surface of degree in that is a cyclic cover of under some linear projection.
Proof.
By assumption, for some integers , . Corollary 4.9 implies that there exist plane curves and of degree and respectively, such that is log smooth and is Brody hyperbolic. Since , is a smooth curve of genus at least , so it is Brody hyperbolic. Applying Lemma 5.1 to yields that there exists a smooth plane curve of degree such that the degree cyclic cover of branched along is Brody hyperbolic. Let be the degree cyclic cover of branched along , then there is a natural finite surjective morphism . Since is Brody hyperbolic, is also Brody hyperbolic. ∎
5.4****Proof of Theorem 1.3.
Let be the double cover of branched along .
For the “only if” part, assume to the contrary that , then . Since , there exists a curve such that is tangent to at some point. As a result, is a double cover of branched along a non-reduced divisor of degree . This implies that each irreducible component of is either a rational curve or an elliptic curve, so is not Brody hyperbolic. We get a contradiction. Hence we must have . If , then by the symmetry between and . If , assume to the contrary that , then . Let be the unique curve with negative self-intersection number, then . Hence . This implies that each irreducible component of is either a rational curve or an elliptic curve, so is not Brody hyperbolic. We get a contradiction. Therefore, the proof of the “only if” part is completed.
For the “if” part, Corollary 4.10 implies that there exist plane curves and of bidegree and respectively, such that is log smooth and is Brody hyperbolic. If , then implies that is a smooth curve of genus at least ; if , then and implies that is a smooth curve of genus at least . So is Brody hyperbolic for every . Thus applying Lemma 5.1 to finishes the proof. ∎
Remark 5.5**.**
- (a)
According to [Hor76], the canonical model of a Horikawa surface with even is either a double cover of branched along a degree or curve, or a minimal resolution of a double cover of branched along a bidegree curve where has finite choices depending on . Hence the “only if” parts of Theorem 1.2 and 1.3 imply that a Brody hyperbolic Horikawa surface with even has to be a double cover of branched along a degree curve (in fact one only needs to check algebraic hyperbolicity). However, our deformation method cannot be applied to exhibit other Brody quasi-hyperbolic Horikawa surfaces (i.e. satisfying the Green-Griffiths-Lang conjecture). 2. (b)
Smooth quintic surfaces in are natural examples of Horikawa surfaces with odd . It was shown by Xu [Xu94] that a very general quintic surface does not contain any rational or elliptic curve. However, no examples of Brody hyperbolic (even algebraic hyperbolic) quintic surfaces are known so far. Notice that the case of a (very) general quintic surface in corresponds to the case in the Kobayashi Conjecture (cf. [Kob70, Kob98]). 3. (c)
Since Brody hyperbolicity is open in the Euclidean topology (see e.g. [Kob98, 3.11.1]), Theorem 1.2 and 1.3 imply that there exist non-empty open subsets of certain moduli spaces of double covers of or that parametrize Brody hyperbolic ones. Besides, we know that Brody hyperbolicity implies algebraic hyperbolicity, and algebraic hyperbolicity is a very generic property in families. Hence Theorem 1.2 gives an alternative proof of [RR13, Theorem 3.2].
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