Berezin symbols of operators on the unit sphere of $\mathbb C^n$
Erik I. D\'iaz-Ort\'iz

TL;DR
This paper develops a symbolic calculus for operators on the unit sphere in complex n-space using Berezin quantization, including explicit formulas for composition and star products, involving holomorphic spaces with hypergeometric kernels.
Contribution
It introduces a detailed symbolic calculus for Berezin operators on the unit sphere, including explicit composition formulas and star products, expanding the understanding of quantization in this setting.
Findings
Derived explicit formula for Berezin symbol composition
Established a noncommutative star product for operators
Introduced holomorphic spaces with hypergeometric kernels
Abstract
We describe the symbolic calculus of operators on the unit sphere in the complex n-space defined by the Berezin quantization. In particular, we derive a explicit formula for the composition of Berezin symbol and with that a noncommutative star product. In the way is necessary introduce a holomorphic spaces which admit a reproducing kernel in the form of generalized hypergeometric series.
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Taxonomy
TopicsAdvanced Topics in Algebra · Algebraic structures and combinatorial models · Advanced Algebra and Geometry
Berezin symbols of operators on the unit sphere of
Erik I. Díaz-Ortíz
CONACYT Research Fellow – Universidad Pedagógica Nacional - Unidad 201 Oaxaca
Abstract.
We describe the symbolic calculus of operators on the unit sphere in the complex -space defined by the Berezin quantization. In particular, we derive a explicit formula for the composition of Berezin symbol and with that a noncommutative star product. In the way is necessary introduce a holomorphic spaces which admit a reproducing kernel in the form of generalized hypergeometric series.
Contents
1. Introduction and summary
We start recalling some results of Berezin’s theory that will be used below. See Ref. [4] for details.
Let be a Hilbert space endowed with the inner product and some set with the measure . Let a family of functions in labelled by elements of , such that satisfies the following properties:
- a)
The family is complete, this is for any Parseval’s identity is valid
[TABLE] 2. b)
The map , defining by , is an embedding from into .
In 1970’s, Berezin [4] introduced a general symbolic calculus for bounded linear operators on . More specifically, for , the algebra of all bounded linear operator on , the Berezin symbol (or Berezin transform) of is the function on defined by
[TABLE]
The prototypes of the spaces are the Bergman spaces of all holomorphic functions in on a bounded domain with Lebesgue measure , or the Segal-Bargmann spaces of all entire functions in for the Gaussian measure , where denoting Lebesgue measure on . In these cases the functions are the reproducing kernel.
Moreover, for every and , we have the following formulas
[TABLE]
If we suppose that the Berezin’s symbol may be extended in a neighbourhood of the diagonal to the function
[TABLE]
then we have the following formulas
[TABLE]
The useful application of this symbolic calculus is that allows us to build a star product. In [4] Berezin applied this method to Kähler manifolds, in this case is the Hilbert space of functions in which are analytic so that the embedding from into is the inclusion, and the complete family are the reproducing kernel with one variable fixed.
The main goal of the present paper is to introduce a Berezin symbolic calculus for the Hilbert space of all functions in whose Poisson extension into the interior of is holomorphic, where and denote the Hilbert space of the square integrable function with respect to the normalized surface measure on and endowed with the usual inner product
[TABLE]
To achieve this, we build a family of functions in satisfying a), since coherent states meet this property and based of our experience in , , where (see Ref. [5]), we propose in Sec. 2 our coherent states in as a suitable power series of the inner product regarding and , where denoting the Planck’s constant. In addition, to ensure b) we define a new Hilbert space , whose measure is obtained such that the inner product of these coherent states is the reproducing kernel from range of mapping (see Sec. 2.1 for details of how this measure was obtained and Eq. (12) for definition of ).
In order to prove that the coherent states and the space constructed in Sec. 2 satisfy the conditions a) and b), in Sec. 3 we prove that the mapping , denoted by , is an isometry from to . In addition, in Sec. 4 we prove that the unitary transformation applied to our coherent states gives the reproducing kernel of the space , which allows us to prove that the family of coherent states form a complete system for .
From this and according to Berezin’s theory, in Sec. 5 we describe the rules for symbolic calculus on , further more we obtain asymptotic expansions of Berezin’s symbol of Toeplitz operator.
Finally, in Sec. 6 we define a star product on the algebra out of Berezin’s symbol for bounded operators with domain in and will prove that this noncommutative star-product satisfies the usual requirement on the semiclassical limit.
It should be noted, since and , in our construction there is no inclusion of into , further more, the complete family is not obtained by the reproducing kernel. This situation is thus slightly different from Berezin’s one.
In the present paper we will be used throughout the text the following basic notation. For every , , , let
[TABLE]
Furthermore, for every multi-index of length where is the set of non negative integers, let
[TABLE]
Given , let us denote its real and imaginary parts by and respectively.
2. A class of holomorphic spaces
In this section, we will give a description of how to define the special Hilbert space .
2.1. Construction of measure .
Based on the expression of coherent states obtained for spaces , with and (See [5] for more details). We consider the coherent states on as the functions
[TABLE]
where the constants are defined below, which will be obtained considering that is the reproducing kernel of some Hilbert space.
From Lemma 7.1, we have
[TABLE]
where denote the Gamma function. If the constants take the following values
[TABLE]
and a constant, then we have
[TABLE]
with denoting the modified Bessel function of the first kind of order (see Secs. 8.4 and 8.5 of Ref. [8] for definition and expressions for this special function). We are taking the branch of the square root function such that , where and .
The Aronszajn-Moore theorem [2] states that, every positive definite (Hermitian) function on determines a unique Hilbert function space for which is the reproducing kernel.
In order to construct the Hilbert space for which the right side of Eq. (5) is its reproducing kernel, let . Define the space as the set of all holomorphic functions in equipped with inner product
[TABLE]
where , are Taylor’s coefficients of and , respectively.
Note that the function belongs to as a function of for every fixed , and for any
[TABLE]
Thus, is the reproducing kernel of . From (6) we see that
[TABLE]
We now assume that the inner product (6) can be expressed by
[TABLE]
Substituting the value of in Eq. (7), using Eq. (8), polar coordinates and Lemma 7.1 we obtain
[TABLE]
So, we need find that satisfies the equation
[TABLE]
Note that expression (9) becomes essentially the Mellin transform (see Refs. [8], [12]). From this simple observation and the formula 6.561-16 of Ref [8] we immediately obtain
[TABLE]
with denoting the MacDonal-Bessel functions of order (see Secs. 8.4 and 8.5 of Ref. [8] for definitions and expressions for this special functions). Taking the constant such that we obtain
[TABLE]
2.2. The space
In the previous section we constructed a Hilbert space whose inner product can be expressed in the form (8) and its reproducing kernel is the right side of Eq. (5); in this section we proves rigorously all those results. From Eqs. (10) and (11) let us consider the following measure on
[TABLE]
with and denoting Lebesgue measure on .
Note that the measure is invariant under the rotation group (the group of orthogonal matrices with unit determinant and real entries). The action of on that we are considering is the natural extension of the usual action of on , this is: for defining by .
Let us consider the Hilbert space of square integrable functions on with respect to the measure and endowed with the inner product
[TABLE]
Let us denote by the corresponding norm of .
Definition 2.1**.**
For , the space of entire functions defined on such that is finite is denoted by .
Remark 1**.**
For , the spaces were used by Karp Dmitrii to derive an analytic continuation formula for functions on (see [10]).
Lemma 2.2**.**
Let
[TABLE]
with , , and . Then if , and if , then
[TABLE]
Proof.
From Eq. (12) and expressing L in polar coordinates
[TABLE]
where . From the formula 6.561-16 of Ref [8] and Lemma 7.1 we conclude the proof of Lemma 2.2 ∎
Proposition 2.3**.**
Let
- a)
The space of analytic polynomials defined on is dense on . 2. b)
For , let us denote by the space of homogeneous polynomials of degree . Then
[TABLE]
Further, the set is orthonormal basis of , where is defining by
[TABLE]
where, for , the Pochhammer symbol is given by
[TABLE] 3. c)
The space enjoys the property of having a reproducing kernel . Namely, for all we have
[TABLE]
where the reproducing kernel is given by
[TABLE]
*Even more *
[TABLE]
where are the reproducing kernel of the subspace
[TABLE]
Proof.
a) Is a consequence of the Stone-Weiertrass theorem.
b) Note that the space is contained in . Then by a), we only need prove that the spaces and are orthogonal for , which is a consequence of Lemma 2.2. The second part of this point too is a direct consequence of Lemma 2.2, since
[TABLE]
is orthogonal basis of .
c) By Eq. (15), it suffices to show that the function is the reproducing kernel in . That will appear as a simple consequence of Lemma 2.2. ∎
As a consequence of the existence of the reproducing kernel and the Cauchy-Schwartz inequality, we obtain the following estimate for any
[TABLE]
3. Unitary transform
In this section we introduce a unitary transform from onto Hilbert space , with and . In order to define this transformation, we first recall some results about the space .
For , let us define the space of homogeneous polynomials of degree as the vector space of restrictions to the -sphere of homogeneous polynomials of degree defined initially on the ambient space . We will use the fact that is equal to the direct sum of the space (see [13])
[TABLE]
Further, the set is orthogonal basis of , where is defining by
[TABLE]
For every , exist a natural transformation from to , this is the linear extension of the assignment , where , are defined in Eqs. (22) and (16) respectively, and with . Let us define this unitary transform by .
We now consider the linear extension of the operators defined as follows:
Given written as with , we define the partial sums and then
[TABLE]
The operator is well defined and unitary due to the unitarity of the operators and the fact that every element in the space can be written in a unique way as with . (See Eq. (15)).
Theorem 3.1**.**
The operator mapping isometrically onto the space . Even more
[TABLE]
where
[TABLE]
Proof.
Note that for fixed and , the series
[TABLE]
is bounded on and therefore it is a vector in as well. Then, by the Cauchy-Schwartz inequality, the right side of Eq. (24) is a well defined function.
Let , is not difficult show that
[TABLE]
Even more, by Eqs (22) and (16)
[TABLE]
Then, given , written as with , we obtain the Eq. (24) from definition of (see Eq. (23)), the integral expression the operator (see Eqs. (27) and (28)) and the dominated converge theorem.∎
We end this section with an inversion formula for the operator .
Theorem 3.2**.**
Let , then
[TABLE]
Proof.
Since the set is orthonormal basis of , then the reproducing kernel, , from is
[TABLE]
where denoting the Gauss hypergeometric function (see Secs. 9.1 of Ref. [8] for definition and expression for this special function).
Even more, for fixed, we obtain from Lemma 7.1
[TABLE]
Moreover, from the reproducing property of , the unitarity of the transform and the Eq. (29), we have
[TABLE]
∎
4. Coherent states for
We consider the set of functions defined by Eq. (26). In this section shows that the functions in satisfy the conditions to define a Berezin symbolic calculus on .
First notice that the unitary operator is a coherent states transform because its action on a function , in , is a function in whose evaluation in is equal to the -inner product of with the coherent states labeled by . This is
[TABLE]
Remark 2**.**
From Eq. (30) and theorem 3.2 is not difficult to prove
[TABLE]
Thus the system of coherent states provides a resolution of identity for , this is the so-called reproducing property of the coherent states.
Theorem 4.1**.**
The unitary operator applied to gives the reproducing kernel of the Hilbert space , , . Namely, for all in we have
[TABLE]
Proof.
From theorem 3.1, the dominated converge theorem and Lemma 7.1 we obtain
[TABLE]
And this is the expression for the reproducing kernel given in Eq. (19) as an infinity series. ∎
The proof of some theorems below uses an estimate of the norm of a coherent state which in turn is a consequence of the following estimate for the inner product of two coherent states:
Proposition 4.2**.**
Let fixed. Assume and . Then for
[TABLE]
Proof.
Since the transform is a unitary transformation, we obtain from theorem 4.1, the reproducing property of (see Eq. (17)) and the expression for the reproducing kernel given in Eq. (18) that
[TABLE]
The modified Bessel function , , has the following asymptotic expression when (see formula 8.451-5 of Ref. [8])
[TABLE]
From Eqs. (32) and (33) we conclude the proof of this proposition. ∎
Remark 3**.**
We are mainly interested in using proposition 4.2 for the cases (and then ) in this paper. The case when requires the use of an asymptotic expression valid in a different region than the one we are considering in proposition 4.2. Thus if we take the branch of the square root function given by with then by using formula 8.451-5 in Ref. [8] we obtain the asymptotic expression,
[TABLE]
Note that both asymptotic expressions in Eqs. (31) and (34) coincide up to an error of the order in the common region where they are valid.
From the proposition 4.2, we obtain an estimate for the norm of a given coherent states
Proposition 4.3**.**
For
[TABLE]
We end this section showing that the family of coherent states is complete
Proposition 4.4**.**
The family form a complete system for .
Proof.
Let , since the transform is a unitary transformation we have
[TABLE]
where we have used Eq. (30). ∎
5. Berezin symbolic calculus
According to Berezin’s theory (see Ref. [4]), from Theorem 3.1, Eq. (30) and the proposition 4.4, we may consider the following
Definition 5.1**.**
The Berezin’s symbol of a bounded linear operator with domain in is defined, for every , by
[TABLE]
From Eq. (32), we have that
[TABLE]
hence the coherent states are continuous, i.e. the map is continuous. Therefore, if is a bounded operator, its Berezin’s symbol, can be extended uniquely to a function defined on a neighbourhood of the diagonal in in such a way that it is holomorphic in the first factor and anti-holomorphic in the second. In fact, such an extension is given explicitly by
[TABLE]
Remark 4**.**
By Eqs. (32), the extended Berezin’s symbol has singularities in the zeros of the modified Bessel function , which are well known (see Ref. [11] Sec. 5.13) and where . Then the extended Berezin’s symbol is defined on , with
[TABLE]
where is a negative real number that satisfies .
We now give the rules for symbolic calculus
Proposition 5.2**.**
Let bounded linear operators with domain in . Then for and we have
[TABLE]
Proof.
This is a direct consequence from the formulas in Ref. [4] (see Eqs. (1), (2)), and the Eqs. (30) and (32). ∎
Corollary 5.3**.**
Let be a bounded operator, and the operator on with Schwartz kernel the function defined on , by
[TABLE]
Then
[TABLE]
Proof.
Let , and . From Eqs. (39), (37) and (32)
[TABLE]
∎
5.1. Asymptotic expansion of the Berezin’s symbol.
In this section, we obtain asymptotic expansion of Berezin’s symbol of Toeplitz operator.
Let the orthogonal projection and pseudo-differential operator on of order zero. The Toeplitz operator is defined as
[TABLE]
For , with be the algebra of complex-valued functions on , let the operator of multiplication by . For simplicity we use notation .
Theorem 5.4**.**
Let be a multi-index. Then
[TABLE]
where was define in Eq. (25).
Proof.
From Eq. (37) and properties the orthogonal projection
[TABLE]
Using the dominated convergence theorem, the Lemma 7.1 and Eq. (32) we conclude the proof of this theorem. ∎
Remark 5**.**
In the particular case when , we obtain from the last theorem
[TABLE]
Theorem 5.5**.**
Let , for any and a smooth function on , the Berezin symbol associated to the Toeplitz operator has the asymptotic expansion
[TABLE]
Proof.
First we observe from Eq. (26), since , that . Let , from Eq. (35) we have
[TABLE]
We identify with in the usual way: for , let with . Note that . Then, the argument of the exponential function in Eq. (42) is
[TABLE]
In order to estimate (41), we define
[TABLE]
where is the surface measure on and is a smooth function on .
Note that given , there exist a rotation in such that with and is canonical unit vector in . Thus we have
[TABLE]
where f_{\mathbf{z}}(\boldsymbol{\omega})=-2\imath r\big{[}\omega_{1}-1\big{]}.
Let us introduce spherical coordinates for the variables :
[TABLE]
with , .
The function appearing in the argument of the exponential function in Eq. (44) has a non-negative imaginary part and has only one critical point (as a function of the angles) which contributes to the asymptotic given by , . In addition, since
[TABLE]
with denoting the Kronecker symbol, then the determinate of the Hessian matrix of the function evaluated at the critical point is equal to .
From the stationary phase method (see Ref. [9]) we obtain
[TABLE]
For , we consider . Then from Eqs. (42), (43) and (45) we conclude the proof of this theorem. ∎
When we can give an asymptotic expression of the coherent states (see Appendix 8). This result will give us as a consequence an asymptotic expression for Berezin symbol to the Toeplitz operator.
Theorem 5.6**.**
Let , for any and a smooth function on , the Berezin transform associated to the Toeplitz operator has the asymptotic expansion
[TABLE]
Proof.
Let us define the following regions on , with the constant mentioned in the Lemma 8.1 taken greater than one
[TABLE]
Note that , implies and therefore we can use the asymptotic expression of coherent states (see proposition 8.2).
Let
[TABLE]
We affirm that the integral on V is actually . To try this, from Lemma 10.1 of Ref [5] (specifically Eq. 10.4), the function has a integral expression given by
[TABLE]
From the last equation we obtain
[TABLE]
for some constant . Note that, for
[TABLE]
Thus we get the estimate for
[TABLE]
From the norm estimate for the coherent states in Eq. (35) we obtain
[TABLE]
Hence . On the other hand, from proposition 8.2 and Eq. (35) we have
[TABLE]
Note that, for , . Thus, we can take the integral defining in Eq. (49) over the whole sphere with error . From Eq. (43), considering
[TABLE]
and (45) we conclude the proof of theorem. ∎
6. The star product
In Ref. [4], Berezin show that the formula (38) will allow us to define a start product (see Refs. [1] for the standard definition of star-product) on the algebra out of Berezin’s symbol for bounded operators with domain in (see Eq. (36)), i.e.
[TABLE]
In this section we verifies that this noncommutative star-product, which will be denoted by , satisfies the usual requirement on the semiclassical limit, i.e. as
[TABLE]
where is a certain bidifferential operator of first order.
Theorem 6.1**.**
Let , , a smooth function defined on , and with . Then for
[TABLE]
with denoting the generalized hypergeometric function (see Sec.9.14 of Ref. [11] for definition and expressions for this special function), and . Further, where is the scalar curvature defined by the Kähler metric , and , are functions described subsequently.
Proof.
Let us define the following two regions on
[TABLE]
The integral in Eq. (51) can be written as an integral on the region plus an integral on denoted by the letters and respectively. The integral on is the one giving us the main asymptotic and the integral on is actually . In order to estimate , from the equality
[TABLE]
(see formula 9.6.47 of Ref. [3] for details), and the integral representation of the function (see formula 8.431-1 of Ref. [8])
[TABLE]
we have
[TABLE]
for some constant . Note that, for ,
[TABLE]
Thus we get the estimate for
[TABLE]
where denoting the beta function (see 8.38 of Ref. [8] for definition and expression for this special function). From the equality (see Eq. (53)) and Eq. (33) we obtain for
[TABLE]
Hence . Let us now study the term , first we note that for , . So from Eqs. (53), (33), the expression for the measure (see Eq. (12)) and the asymptotic expression of the MacDonal-Bessel function of order , (see formula 9.7.2 of Ref. [3]) we find that
[TABLE]
with
[TABLE]
where the error term in (56) is uniformly with respect to because in such a region we have and .
Furthermore, from Eq. (54) for . Thus we can take the integral defining over the whole space with an error .
Let us now write with
[TABLE]
For obtain the asymptotic expansion (51), we express the integrals and , using the stationary phase method (see Ref [9]), as , respectively.
For our purpose, note that, using Schwartz inequality, the phase function satisfies . Moreover if and only if for some and . Therefore, if and only if . Thus is smooth function on a neighbourhood of the critical point . We also have
[TABLE]
Using that fact that for any complex numbers , , , we obtain
[TABLE]
From the stationary phase method, applied to the integral , we deduce
[TABLE]
Furthermore, the computation of and in Eq. (57) it is using theorem 3 in Ref. [6]. For this we consider the Kähler potential , and let be a sesqui-analytic extension of to a neighbourhood of the diagonal.
From it, we have
[TABLE]
and
[TABLE]
From theorem 3 in Ref. [6] and Eq. (59)
[TABLE]
and
[TABLE]
where we have use the definition and
[TABLE]
∎
We note that in Eq. (51) appears , which is not difficult to prove that
[TABLE]
which results in later use.
We remember that for , the law of multiplication in is
[TABLE]
where the functions , , which are the analytic continuation of to (see Eq. (37)).
Theorem 6.2**.**
Let , . The product satisfies
- a)
, for all , 2. b)
is associative, and 3. c)
for we have the following asymptotic expression when
[TABLE]
where and was defined in the theorem 6.1.
Proof.
a) Let , then with . From Eq. (37) and proposition 4.4
[TABLE]
Analogously .
b) The associativity follows from the fact that the composition in the algebra of all bounded linear operator on is associative.
c) The asymtotic expression given in the Eq. (65) is a direct consequence from the integral expression of star product (see Eq. (64)), the Eq. (53) and theorem 6.1. ∎
7. Appendix A. On the inner product on complex sphere
In this appendix we study the inner product of functions on from the form with , , and . We introduce the following notation, for multi-indices we will write if and only if for all .
Lemma 7.1**.**
Let
[TABLE]
with , , and . Then if , furthermore
- a)
If and , then
[TABLE] 2. b)
If , and , then
[TABLE]
Proof.
We note that the function is harmonic and homogeneous of order , then if . We suppose now that , and , then
[TABLE]
where we use (see Ref [13] for details). Similarly we get the other formula. ∎
8. Appendix B. Asymptotic of the Integral kernel of
In the particular case when , we can obtain the asymptotic expresion of the coherent states . First, based on the definition of (see Eqs. (26) and (25)) let us define the function by
[TABLE]
Note that the coherent states are equal to the function evaluated at . In this appendix we obtain the main asymptotic term for the function .
Lemma 8.1**.**
For and with a positive constant and , has the following asymptotic expansion:
[TABLE]
with some constants.
Proof.
This follows from Lemma 10.1, which appears in Ref. [5]. ∎
Using Lemma 8.1 with we obtain the following asymptotic expansion:
Proposition 8.2**.**
Let . Then for and , with a positive constant, we have
[TABLE]
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