Parabolic transmission eigenvalue-free regions in the degenerate isotropic case
Georgi Vodev (LMJL)

TL;DR
This paper investigates the distribution of transmission eigenvalues in isotropic media with boundary-restricted refraction indices, establishing the existence of parabolic regions free of eigenvalues under certain conditions.
Contribution
It introduces the concept of parabolic eigenvalue-free regions in the degenerate isotropic case, expanding understanding of eigenvalue distribution in this context.
Findings
Existence of parabolic transmission eigenvalue-free regions.
Conditions under which these regions occur.
Insights into eigenvalue distribution in degenerate isotropic media.
Abstract
We study the location of the transmission eigenvalues in the isotropic case when the restrictions of the refraction indices on the boundary coincide. Under some natural conditions we show that there exist parabolic transmission eigenvalue-free regions.
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Parabolic transmission eigenvalue-free regions in the degenerate isotropic case
Georgi Vodev
Université de Nantes, Laboratoire de Mathématiques Jean Leray, 2 rue de la Houssinière, BP 92208, 44322 Nantes Cedex 03, France
Abstract.
We study the location of the transmission eigenvalues in the isotropic case when the restrictions of the refraction indices on the boundary coincide. Under some natural conditions we show that there exist parabolic transmission eigenvalue-free regions.
1. Introduction and statement of results
Let , , be a bounded, connected domain with a smooth boundary . A complex number , , will be said to be a transmission eigenvalue if the following problem has a non-trivial solution:
[TABLE]
where denotes the Euclidean unit inner normal to , , are strictly positive real-valued functions called refraction indices. In the non-degenerate isotropic case when
[TABLE]
it has been recently proved in [16] that there are no transmission eigenvalues in the region
[TABLE]
for some constant . Moreover, it follows from the analysis in [6] (see Section 4) that the eigenvalue-free region (1.3) is optimal and cannot be improved in general. In the present paper we will consider the degenerate isotropic case when
[TABLE]
We suppose that there is an integer such that
[TABLE]
[TABLE]
It was proved in [1] (see Theorem 4.2) that in this case the eigenvalue-free region (1.3) is no longer valid. On the other hand, it follows from [5] that under the conditions (1.5) and (1.6) there are no transmission eigenvalues in , , . Our goal in the present paper is to improve this result showing that in this case we have a much larger parabolic eigenvalue-free region. Our main result is the following
Theorem 1.1**.**
Under the conditions (1.5) and (1.6) there exists a constant such that there are no transmission eigenvalues in the region
[TABLE]
where .
To prove this theorem we make use of the semi-classical parametrix for the interior Dirichlet-to-Neumann (DN) map built in [14]. It is proved in [14] that for , , the DN map is an DO of class OP, where is a semi-classical parameter such that . A direct consequence of this fact is the existence of a transmission eigenvalue-free region of the form
[TABLE]
under the condition (1.2). The most difficult part of the parametrix construction in [14] is near the glancing region (see Section 3 for the definition). Indeed, outside an arbitrary neighbourhood of the glancing region the parametrix construction in [14] works for and the corresponding parametrix belongs to the class OP. In other words, to improve the eigenvalue-free region (1.8) one has to improve the parametrix in the glancing region. Such an improved parametrix has been built in [15] for strictly concave domains and as a consequence (1.8) was improved to
[TABLE]
in this case. In fact, it turns out that to get larger eigenvalue-free regions under the condition (1.2) no parametrix construction in the glancing region is needed. It suffices to show that the norm of the DN map microlocalized in a small neighbourhood of the glancing region gets small if and are large. Indeed, this strategy has been implemented in [16] to get the optimal transmission eigenvalue-free region (1.3) for an arbitrary domain. In fact, the main point in the approach in [16] is the construction of a parametrix in the hyperbolic region valid for , , . The strategy of [16], however, does not work any more when we have the condition (1.4). In this case the parametrix in the glancing region turns out to be essential to get eigenvalue-free regions like (1.7). In Section 3 we revisit the parametrix construction of [14] and we study carefully the way in which it depends on the restriction on the boundary of the normal derivatives of the refraction index (see Theorem 3.1). In Section 4 we improve Theorem 3.1. In Section 5 we show how Theorem 4.1 implies Theorem 1.1. We also show that to improve (1.7) it suffices to improve the parametrix in the glancing region, only (see Proposition 5.2).
As in [9] one can study in this case the counting function , where . We have the following
Corollary 1.2**.**
Under the conditions of Theorem 1.1, there exists a constant such that the counting function of the transmission eigenvalues satisfies the asymptotics
[TABLE]
where
[TABLE]
* being the volume of the unit ball in .*
Note that the eigenvalue-free region (1.3) implies (1.10) with replaced by . Note also that asymptotics for the counting function with remainder have been previously obtained in [3], [7], [12] still under the condition (1.2).
2. Basic properties of the DOs
In this section we will recall some basic properties of the DOs on a compact manifold without boundary. Let , , be as in the previous section and recall that given a symbol , the DO, , is defined as follows
[TABLE]
We have the following criteria of - boundedness.
Proposition 2.1**.**
Let the function satisfy the bounds
[TABLE]
for all multi-indices . Then the operator is bounded on and satisfies
[TABLE]
with a constant independent of and .
Let the function satisfy the bounds
[TABLE]
for all multi-indices and . Then the operator is bounded on and satisfies
[TABLE]
with a constant independent of and , where is an integer depending only on the dimension.
Given , and a function on , we denote by the set of all functions satisfying
[TABLE]
for all multi-indices and with constants independent of . Given , , we also denote by the space of all symbols satisfying
[TABLE]
for all multi-indices and with constants independent of . It is well-known that the DOs of class OP have nice calculus (e.g. see Section 7 of [2]). The next proposition is very usefull for inverting such operators depending on additional parameters (see also Proposition 2.2 of [14]).
Proposition 2.2**.**
Let , , where are some numbers. Assume in addition that the functions satisfy
[TABLE]
, for all multi-indices , , , such that , , with constants independent of and . Then we have
[TABLE]
with a constant independent of and .
Given any real , we define the semi-classical Sobolev norm by
[TABLE]
Using the calculus of the DOs one can derive from (2.4) the following
Proposition 2.3**.**
Let , . Then, for every , we have
[TABLE]
Proposition 2.2 implies the following
Proposition 2.4**.**
Let . Then, for every , we have
[TABLE]
3. The parametrix construction revisited
In this section we will build a parametrix for the semi-classical Dirichlet-to-Neumann map following [14]. Note that in [14] there is a gap due to a missing term in the transport equations (4.11), which however does not affect the proof of the main results. Here we will correct this gap making some slight modifications.
Given , let solve the equation
[TABLE]
where is a strictly positive function, is a semi-classical parameter and , where , , . Given we also set . We define the semi-classical Dirichlet-to-Neumann map
[TABLE]
by
[TABLE]
where denotes the Euclidean unit inner normal to . Given an integer , denote by the Sobolev space equipped with the semi-classical norm
[TABLE]
We define similarly the Sobolev space . Note that this norm is equivalent to that one defined in Section 2. Throughout this section we will use the normal coordinates with respect to the Euclidean metric near the boundary , where denotes the Euclidean distance to the boundary and are coordinates on . We denote by the negative Laplace-Beltrami operator on equipped with the Riemannian metric induced by the Euclidean one in . Let be the principal symbol of written in the coordinates . Since the function is smooth up to the boundary we can expand it as
[TABLE]
for every integer , where , , and is a real-valued smooth function. Set
[TABLE]
The glancing region for the problem (3.1) is defined by
[TABLE]
Let , , for , for , and set . Clearly, taking small enough we can arrange that on supp. We also define the function , where is independent of and . Clearly, in a neighbourhood of , outside another neighbourhood of .
We will say that a function belongs to if and . Given any integer , it follows from Lemma 3.2 of [14] that
[TABLE]
In particular, (3.2) implies that
[TABLE]
Since as , it is easy to check that
[TABLE]
for every integer . Since for , and for or , (see Lemma 3.1 of [14]), it also follows from (3.2) that
[TABLE]
[TABLE]
[TABLE]
for every integer and , where if , if . Our goal in this section is to prove the following
Theorem 3.1**.**
Let , . Then, for every integer there is a function independent of all with such that
[TABLE]
where if , and for . If , then (3.8) holds with replaced by . Moreover, for we have
[TABLE]
where the function is independent of all with .
Proof. We will recall the parametrix construction in [14]. We will proceed locally and then we will use partition of the unity to get the global parametrix. Fix a point and let be a small open neighbourhood of . Let , , , be the normal coordinates. In these coordinates the Laplacian can be written as follows
[TABLE]
where , being a symmetric matrix-valued function with smooth real-valued entries, , and being smooth functions. We can expand them as follows
[TABLE]
[TABLE]
[TABLE]
for every integer . Clearly, .
Take a function . In what follows will denote either the function or the function . Following [14], we will construct a parametrix of the solution of (3.1) with in the form
[TABLE]
where , with if , , and if or , . Here is a parameter independent of and to be fixed later on. The phase is complex-valued such that and satisfies the eikonal equation mod :
[TABLE]
where is an arbitrary integer and the function is smooth up to the boundary . It is shown in [14], Section 4, that the equation (3.10) has a smooth solution of the form
[TABLE]
safisfying
[TABLE]
More generally, the functions satisfy the relations
[TABLE]
for every integer . Then equation (3.10) is satisfied with
[TABLE]
[TABLE]
where for so that the above sums are finite. Using (3.12) one can prove by induction the following lemma (see Lemma 4.1 of [14]).
Lemma 3.2**.**
We have
[TABLE]
[TABLE]
uniformly in and . Moreover, if is small enough, independent of , we have
[TABLE]
One can also easily prove by induction the following
Lemma 3.3**.**
For every integer the functions and are independent of all with .
It follows from (3.13) that for all . Define now the functions independent of all , , satisfying the relations
[TABLE]
, and , . Using (3.4) together with (3.12) and (3.16), one can easily prove by induction the following
Lemma 3.4**.**
For every integer , we have .
The amplitude is of the form
[TABLE]
where the functions satisfy the transport equations mod :
[TABLE]
, for , where and the functions are smooth up to the boundary . We will be looking for the solutions to (3.17) in the form
[TABLE]
We can write
[TABLE]
with
[TABLE]
[TABLE]
[TABLE]
where for . Similarly
[TABLE]
with
[TABLE]
[TABLE]
[TABLE]
[TABLE]
where for . We also have
[TABLE]
with
[TABLE]
[TABLE]
with
[TABLE]
[TABLE]
with
[TABLE]
where , for so that the above sums are finite. Inserting the above identities into equation (3.17) and comparing the coefficients of all powers , , we get that the functions must satisfy the relations
[TABLE]
[TABLE]
and , , , , . Then equation (3.17) is satisfied with
[TABLE]
Let us calculate . By (3.18) with , , we get
[TABLE]
On the other hand, by (3.12) with we get
[TABLE]
Using the identity
[TABLE]
we can write in the form
[TABLE]
[TABLE]
By (3.19) and (3.20),
[TABLE]
[TABLE]
[TABLE]
By (3.2) and (3.21) we conclude
[TABLE]
The next lemma follows from Lemma 3.2 and (3.22) together with equations (3.18) and can be proved in the same way as Lemma 4.2 of [14]. We will sketch the proof.
Lemma 3.5**.**
We have
[TABLE]
[TABLE]
uniformly in and .
Proof. Recall that . By (3.13) we have
[TABLE]
[TABLE]
We will prove (3.23) by induction. In view of (3.22) we have (3.23) with , . Suppose now that (3.23) is true for all and all , and for and . We have to show that it is true for and . To this end, we will use equation (3.18) with and . Indeed, the LHS is equal to modulo , while the RHS belongs to . In other words, belongs to . This implies that belongs to , as desired. Furthermore, (3.24) follows from (3.13) and (3.23) since the functions are expressed in terms of and . One needs the simple observation that
[TABLE]
implies
[TABLE]
Using Lemma 3.3 we will prove the following
Lemma 3.6**.**
For all , the function
[TABLE]
is independent of all with .
Proof. It follows from Lemma 3.3 that the function
[TABLE]
is independent of all with . We will first prove the assertion for and all by induction in . In view of (3.21) it is true for . Suppose it is true for all integers with some integer . We will prove it for . To this end, we will use equation (3.18) with and . Since the RHS is zero, we get that the function
[TABLE]
is independent of all with . Hence, so is the function
[TABLE]
as desired. We will now prove the assertion for all , by induction in . Suppose it is true for and all with some integer . We will prove it for and all . To this end, we will use equation (3.18) with and replaced by , . We have that, modulo functions independent of all with , the LHS is equal to , while the RHS is equal to . Hence the function
[TABLE]
is independent of all with , which clearly implies the desired assertion.
It follows from (3.23) that for all , . Define now the functions independent of all , , satisfying the relations
[TABLE]
[TABLE]
and , , , , , where is defined by replacing in the definition of all functions by . Using Lemma 3.4 we will prove the following
Lemma 3.7**.**
For all , we have .
Proof. By Lemma 3.4 together with (3.18) and (3.25) we obtain that the relations
[TABLE]
[TABLE]
[TABLE]
are satisfied modulo . We will proceed by induction. Suppose now that the assertion is true for all and all , and for and . This implies that the LHS of (3.26) with and is equal to modulo , while the RHS belongs to . Hence, belongs to , as desired.
In view of (3.11) we have
[TABLE]
where
[TABLE]
Lemma 3.8**.**
For every integer there are and such that for all we have the estimate
[TABLE]
if , , or , . If , , then (3.27) holds with replaced by .
Proof. Denote by the Dirichlet self-adjoint realization of the operator on the Hilbert space . It is easy to see that
[TABLE]
where if , if . Clearly, under the conditions of Lemma 3.8, we have . The above bound together with the coercivity of imply
[TABLE]
for every integer . We also have the identity
[TABLE]
where denotes the restriction on , and
[TABLE]
[TABLE]
where with
[TABLE]
[TABLE]
By the trace theorem we get from (3.28) and (3.29),
[TABLE]
[TABLE]
To bound the norm of we need to bound the kernel of the operator
[TABLE]
By Lemma 3.1 of [14] we have
[TABLE]
[TABLE]
where is some constant. Hence, by (3.15), for we have
[TABLE]
[TABLE]
On the other hand, by Lemmas 3.2 and 3.5, for and we have
[TABLE]
[TABLE]
for every multi-index with some independent of . By (3.31), (3.32) and (3.33), using that , , on supp, we conclude
[TABLE]
for , and
[TABLE]
otherwise, with possibly a new independent of . Similar estimates hold for the function , too. Indeed, observe that on supp we have , and hence
[TABLE]
[TABLE]
with some constant . Using (3.36) one can easily get that the estimates (3.34) and (3.35) are satisfied with replaced by . Therefore, the function satisfies the bounds
[TABLE]
Moreover, since on supp, in the case when we obtain that (3.37) holds with replaced by and replaced by . Note now that the kernel, , of the operator is given by
[TABLE]
If is taken large enough, (3.37) implies the bounds
[TABLE]
with a new independent of . When , (3.38) holds with replaced by and replaced by . Clearly, (3.27) follows from (3.30) and (3.38).
In the case when , by (3.23) we have
[TABLE]
on supp, and
[TABLE]
on supp. Since for , and for or , , we get
[TABLE]
for , , and
[TABLE]
otherwise. Hence , uniformly in , for . Therefore, we have
[TABLE]
for every integer , where is such that on supp. In view of (2.4) this implies
[TABLE]
[TABLE]
for every integer . In view of Proposition 2.3 we also have
[TABLE]
By (3.39) and (3.40) we conclude
[TABLE]
By Lemma 3.7 we also have
[TABLE]
In the case when , the functions vanish on supp, and hence for . Therefore, in this case the estimate (3.41) holds with replaced by and replaced by .
We are ready now to prove Theorem 3.1. If we put , and if we put
[TABLE]
In view of Lemma 3.6, the function is independent of all with . If we take big enough, we can decompose the function as
[TABLE]
where
[TABLE]
By (3.39), (3.41) and (3.42) we have
[TABLE]
Moreover, if , the estimate (3.43) holds with replaced by and replaced by . We would like to apply Lemma 3.8 with . To this end we take big enough to arrange that
[TABLE]
By (3.27) and (3.43) we get
[TABLE]
[TABLE]
if . Moreover, if , the estimate (3.44) holds with replaced by and replaced by .
We will now use a partition of the unity on . We can find functions such that and (3.44) is valid with replaced by each , where is defined by replacing in the definiton of the function by . Summing up all the estimates we get (3.8) and (3.9), respectively.
4. Improved estimates
To prove Theorem 1.1 we actually need the following improved version of Theorem 3.1.
Theorem 4.1**.**
Let , . Then, for every integer there are an operator independent of all with and an operator
[TABLE]
independent of all with such that
[TABLE]
where denotes the identity. If , then (4.2) holds with replaced by .
Proof. Recall that by (3.5), (3.6), (3.7), we have that for every integer , uniformly in and if . We would like to apply Proposition 2.2 with
[TABLE]
Using (3.2) one can easily check that (2.5) is satisfied with . By (2.6) we get
[TABLE]
if is taken small enough. It follows from (4.3) that the operator is invertible with an inverse
[TABLE]
Since uniformly in , by Proposition 2.3 we have
[TABLE]
which implies (4.1). By (3.27) and (4.1),
[TABLE]
if is taken large enough, where . On the other hand, we can write
[TABLE]
where
[TABLE]
[TABLE]
Clearly, the operator is independent of all with because so is the function . Therefore, it follows from (4.4) that to prove (4.2) it suffices to prove the bound
[TABLE]
In view of Lemmas 3.5 and 3.7, we have with uniformly in as long as . Thus, (4.5) is equivalent to
[TABLE]
To prove (4.6) observe that uniformly in , which yields the bounds
[TABLE]
By (2.4) and (4.7) we get
[TABLE]
On the other hand, applying Proposition 2.2 with and yields the bound
[TABLE]
[TABLE]
Clearly, (4.6) follows from (4.8) and (4.9).
5. Proof of Theorem 1.1
Define the DN maps , , by
[TABLE]
where is the Euclidean unit inner normal to and is the solution to the equation
[TABLE]
and consider the operator
[TABLE]
Clearly, is a transmission eigenvalue if there exists a non-trivial function such that . Thus Theorem 1.1 is a consequence of the following
Theorem 5.1**.**
Under the conditions of Theorem 1.1, the operator sends into . Moreover, there exists a constant such that is invertible for with an inverse satisfying in this region the bound
[TABLE]
where the Sobolev space is equipped with the classical norm.
Proof. We make our problem semi-classical by putting , , if , , and , , if . Clearly, . We set and
[TABLE]
We now apply Theorem 4.1 with . In view of the conditions (1.5) and (1.6), we get
[TABLE]
for , where
[TABLE]
When , the estimate (5.3) holds with replaced by . It follows from (5.3) that the operator is invertible for , , and for , small enough. Hence so is and we have the bound
[TABLE]
Now (5.2) follows from (5.4) after passing from to and using the fact that the semi-classical norm in is bounded from above by the classical norm in .
It is worth noticing that it follows from the estimate (3.9) that the operator can be inverted outside the glancing region for much smaller . In other words, to improve the eigenvalue-free region (1.7) one has to improve the parametrix in the glancing region, only. More precisely, we have the following
Proposition 5.2**.**
Let . Then, under the conditions of Theorem 1.1, there exists an operator
[TABLE]
such that
[TABLE]
When , the estimate (5.5) holds with replaced by [math].
Proof. By (3.9) with we have
[TABLE]
for . Let be such that on supp, in a neighbourhood of , and set
[TABLE]
We have , and . We now apply Proposition 2.4 with and in place of and . We have
[TABLE]
Clearly, (5.5) follows from (5.6) and (5.7) with .
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