# On distributions determined by their upward, space-time Wiener-Hopf   factor

**Authors:** Lo\"ic Chaumont, Ron Doney

arXiv: 1702.00067 · 2017-11-29

## TL;DR

This paper investigates how probability distributions on the real line can be uniquely characterized by their upward Wiener-Hopf factor, especially under certain conditions like having exponential moments or analytic density, and explores related convolution properties.

## Contribution

It demonstrates that distributions can often be uniquely determined by their upward Wiener-Hopf factor, and conjectures this holds universally for all distributions with support outside negative reals.

## Key findings

- Distributions with exponential moments are characterized by their upward factor.
- Complete monotonicity of the tail function implies distribution determination.
- Knowledge of a distribution and its square's restriction to [0,∞) can suffice for identification.

## Abstract

According to the Wiener-Hopf factorization, the characteristic function $\varphi$ of any probability distribution $\mu$ on $\mathbb{R}$ can be decomposed in a unique way as \[1-s\varphi(t)=[1-\chi_-(s,it)][1-\chi_+(s,it)]\,,\;\;\;|s|\le1,\,t\in\mathbb{R}\,,\] where $\chi_-(e^{iu},it)$ and $\chi_+(e^{iu},it)$ are the characteristic functions of possibly defective distributions in $\mathbb{Z}_+\times(-\infty,0)$ and $\mathbb{Z}_+\times[0,\infty)$, respectively.   We prove that $\mu$ can be characterized by the sole data of the upward factor $\chi_+(s,it)$, $s\in[0,1)$, $t\in\mathbb{R}$ in many cases including the cases where:   1) $\mu$ has some exponential moments;   2) the function $t\mapsto\mu(t,\infty)$ is completely monotone on $(0,\infty)$;   3) the density of $\mu$ on $[0,\infty)$ admits an analytic continuation on $\mathbb{R}$.   We conjecture that any probability distribution is actually characterized by its upward factor. This conjecture is equivalent to the following: {\it Any probability measure $\mu$ on $\mathbb{R}$ whose support is not included in $(-\infty,0)$ is determined by its convolution powers $\mu^{*n}$, $n\ge1$ restricted to $[0,\infty)$}. We show that in many instances, the sole knowledge of $\mu$ and $\mu^{*2}$ restricted to $[0,\infty)$ is actually sufficient to determine $\mu$. Then we investigate the analogous problem in the framework of infinitely divisible distributions.

## Full text

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## References

10 references — full list in the complete paper: https://tomesphere.com/paper/1702.00067/full.md

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Source: https://tomesphere.com/paper/1702.00067