Equal relation between the extra connectivity and pessimistic
diagnosability for some regular graphs
Mei-Mei Gu
[email protected],
Rong-Xia Hao
[email protected],
Jun-Ming Xu
[email protected]
Yan-Quan Feng
[email protected],
Department of Mathematics, Beijing Jiaotong University, Beijing, 100044, China
School of Mathematical Sciences, University of Science and Technology of China, Hefei, Anhui, 230026, China
Abstract
Extra connectivity and the pessimistic diagnosis are two crucial subjects
for a multiprocessor system’s ability to tolerate
and diagnose faulty processor. The pessimistic diagnosis strategy is a classic strategy based
on the PMC model in which isolates all faulty vertices
within a set containing at most one fault-free vertex.
In this paper, the result that the pessimistic
diagnosability tp(G) equals the extra connectivity κ1(G) of a regular graph G
under some conditions are shown. Furthermore, the following new results are gotten: the pessimistic diagnosability tp(Sn2)=4n−9 for split-star networks Sn2; tp(Γn)=2n−4 for Cayley graphs generated by transposition trees Γn; tp(Γn(Δ))=4n−11 for Cayley graph generated by the 2-tree Γn(Δ); tp(BPn)=2n−2 for the burnt pancake networks BPn. As corollaries, the known results about the extra connectivity and the pessimistic diagnosability of many famous networks including the alternating group graphs; the alternating group networks; BC networks; the k-ary n-cube networks etc. are obtained directly.
keywords:
Pessimistic diagnosability; Extra connectivity; PMC model; Regular graph; Interconnection network.
1 Introduction
It is well known that a topological structure of an interconnection network can be modeled by a loopless undirected graph G=(V,E), where vertices in V represent the processors and the edges in E represent the communication links. In this paper, we use graphs and networks interchangeably. The connectivity κ(G) of a connected graph G is the minimum number of vertices removed to
get the graph disconnected or trivial. In a multiprocessor system, some processors may fail, connectivity is used to determine the reliability and fault tolerance of a network. However, connectivity is not suitable for large-scale processing systems because it is almost impossible for all processors adjacent to, or all links incident to, the same processors to fail simultaneously. To
compensate for this shortcoming, it seems reasonable to
generalize the notion of classical connectivity by imposing
some conditions or restrictions on the components
of G when we delete the set of faulty processors.
J. Fábrega and M.A. Fiol [16] introduced the extra connectivity of interconnection networks as follows.
Definition 1**.**
A vertex set S⊆V(G) is called to be an h-extra vertex cut if G−S is disconnected and every component of G−S has at least h+1 vertices. The h-extra connectivity of G, denoted by κh(G), is defined as the cardinality of a minimum h-extra vertex cut, if exists.
It is obvious that κ0(G)=κ(G) for any graph G that is not a complete graph. The 1-extra connectivity is usually called extra connectivity.
The problem of determining the extra connectivity of numerous networks has received a great deal of attention in recent years. Interested readers may refer to [1, 20, 21, 25, 32, 33] or others for further details.
The diagnosis of a system is
the process of appraising the faulty processors.
A number of models
have been proposed for diagnosing faulty processors in
a network. Preparata et al. [34]
first introduced a graph theoretical model, the so-called PMC model (i.e., Preparata, Metze and Chien s model), for system level diagnosis in multiprocessor systems.
The pessimistic diagnosis strategy proposed by Kavianpour and Friedman [30] is a classic diagnostic model based on the PMC model. In this strategy, all faulty processors to be isolated within a set having at most one fault-free processor.
Definition 2**.**
A system is t/t-diagnosable, provided the number of faulty processors is bounded by t, all faulty processors can be isolated
within a set of size at most t with at most one fault-free vertex mistaken as a faulty one.
The pessimistic diagnosability of a system G, denoted by tp(G), is the maximal number of faulty processors so that the system G is t/t-diagnosable.
The pessimistic diagnosability of many interconnection networks has been explored. For example, see [17, 19, 30, 37, 38, 41] etc.
Based on the important of the extra connectivity and
the pessimistic diagnosability and motivated by the recent researches
on the extra connectivity and pessimistic diagnosability
of some graphs, including some famous networks, our object is to propose
the relationship between extra connectivity and pessimistic
diagnosability of regular graphs with some
given conditions. In this paper, the result that the pessimistic
diagnosability tp(G) equals the extra connectivity κ1(G) of a regular graph G
under some conditions are shown. Furthermore, the following new results are gotten: the pessimistic diagnosability tp(Sn2)=4n−9 for split-star networks Sn2;
tp(Γn)=2n−4 for Cayley graphs generated by transposition trees Γn; tp(Γn(Δ))=4n−11 for
Cayley graph generated by the 2-tree Γn(Δ); tp(BPn)=2n−2 for the burnt pancake networks BPn. As corollaries, the known results about the extra connectivity
and the pessimistic diagnosability of many famous networks including the alternating group graphs, the alternating group networks, BC networks and the k-ary n-cube networks etc. are obtained directly.
The remainder of this paper is organized
as follows. Section 2 introduces necessary definitions and properties of some graphs.
In Section 3, we determines the equal relationship between extra connectivity and pessimistic
diagnosability of regular graphs with some
given conditions. In Section 4, we concentrates on the applications to
some famous networks. The pessimistic
diagnosability and the extra connectivity of many famous networks,
such as the alternating group graph AGn, the alternating group network ANn,
the k-ary n-cube networks Qnk, the BC networks Xn, the split-star networks Sn2,
the Cayley graphs generated by transposition trees Γn,
the Cayley graphs generated by 2-trees Γn(Δ) and the burnt pancake networks BPn are obtained directly.
Finally, our conclusions are given in Section 5.
2 Preliminaries
In this section, we give some terminologies and notations of combinatorial network theory.
For notations not defined here, the reader is referred to [2].
We use a graph, denoted by G=(V(G),E(G)), to represent an interconnection network, where V(G) is the vertex set of G; E(G) is the edge set of G.
For a vertex u∈V(G), let NG(u) (or N(u) if there is no ambiguity) denote
a set of vertices in G adjacent to u.
For a vertex set U⊆V(G), let NG(U)=v∈U⋃NG(v)−U and G[U] be
the subgraph of G induced by U. If ∣NG(u)∣=k for any vertex in
G, then G is k-regular.
For any two vertices u and v in G, let
cn(G;u,v) denote the number of vertices who are the neighbors
of both u and v, that is, cn(G;u,v)=∣NG(u)∩NG(v)∣.
Let cn(G)=max{cn(G;u,v):u,v∈V(G)}, l(G)=max{cn(G;u,v):(u,v)∈E(G)}.
Let ∣V(G)∣ be the size of vertex set and ∣E(G)∣ be the size of edge set.
Throughout this paper, all graphs are finite, undirected without loops.
Let [n]={1,2,…,n} and ⟨n⟩={−1,−2,…,−n,1,2,…,n}.
For a finite group A and a subset S of A such that 1∈/S and S=S−1 (where 1 is the identity element of A),
the Cayley graph Cay(A;S) on A with respect to S is defined to have vertex set A and edge set {(g,gs)∣g∈A,s∈S}. A Cayley graph is ∣S∣-regular, and is connected if and only if S
generates Γ. Moreover, A Cayley graph is ∣S∣-connected if
S is a minimal generating set of Γ.
2.1 The alternating group graphs
Jwo et al. [29] introduced the alternating group graph as an interconnection network topology for computing systems.
Definition 3**.**
Let An be the alternating group of degree n
with n≥3. Set S={(1 2 i),(1 i 2) ∣ 3≤i≤n}.
The alternating group graph, denoted by AGn, is defined as
the Cayley graph AGn=Cay(An,S).
It is clear that AG3 is a triangle, AGn is a (2n−4)-connected and (2n−4)-regular graph with
n!/2 vertices. Each AGn contains n sub-alternating group graphs AGn0,AGn1,…,AGnn−1.
For each i∈[n], AGni is isomorphic to AGn−1.
For each vertex v∈AGni, v has exactly two neighbors that are not contained in AGni, which are called the extra neighbors of v.
Lemma 1**.**
([24])*
The extra neighbors of every vertex of AGn are in different subgraphs AGni for n≥4.
For any two different vertices u,v, cn(AGn:u,v)=1 if u and v are adjacent; otherwise, cn(AGn:u,v)≤2.*
Lemma 2**.**
([37])*
Let AGn be the n-dimensional alternating group graph for n≥4.
If U is a subset of V(AGn) and 2≤∣U∣≤8n−25, then ∣NAGn(U)∣≥4n−11.*
Lemma 3**.**
([24])*
Let F be a vertex-cut of AGn for n≥5. If ∣F∣≤4n−11, then AGn−F satisfies one of the following conditions:*
- (1)
AGn−F* has two components, one of which is a trivial component.*
2. (2)
AGn−F* has two components, one of which is an edge.
Moreover, if ∣F∣=4n−11, F is formed by the neighbor of the edge.*
2.2 The alternating group networks
The alternating group network ANn
was first proposed by Y. Ji [28] to improve upon the alternating
group graph AGn, studied by Jwo and others [29].
Definition 4**.**
([28])*
Let An be an alternating group of degree n≥3 and let
S={(1 2 3),(1 3 2), (1 2)(3 i) ∣ 4≤i≤n}. The
alternating group network, denoted by ANn, is defined as
the Cayley graph Cay(An,S).*
By the definition, we can get some properties about ANn [28]. ANn is a regular graph with
n!/2 vertices and n!(n−1)/4 edges. AN3 is a triangle. AN4 contains four copies of AN3.
ANn contains n copies of ANn−1, say ANn0,ANn1,…,ANnn−1.
For each i∈[n], ANni is isomorphic to ANn−1.
By Theorem 1 in [44], ANn is (n−1)-regular and (n−1)-connected.
Lemma 4**.**
([23])*
Let ANn be the alternating group network for n≥3 .*
- (1)
Each vertex in ANn has exactly one extra neighbor.
2. (2)
ANn* has no 4-cycle and 5-cycle.*
3. (3)
Let u and v be any two distinct vertices of ANn, then cn(ANn:u,v)≤1.
Lemma 5**.**
([45])*
Let F be a vertex-cut of ANn for n≥5. If ∣F∣≤2n−5, then ANn−F satisfies one of the following conditions:*
- (1)
ANn−F* has two components, one of which is a trivial component.*
2. (2)
ANn−F* has two components, one of which is an edge.
Moreover, if ∣F∣=2n−5, F is formed by the neighbor of the edge.*
2.3 BC networks
Definition 5**.**
The 1-dimensional BC network X1 is a complete
graph with two vertices. The n-dimensional BC
network Xn is defined as follows: V(Xn)=V(G1)∪V(G2)
and E(Xn)=E(G1)∪E(G2)∪M, where G1,G2∈Ln−1,
and M is a perfect matching between V(G1) and V(G2), where Lk={Xk:Xk is an k-dimensional BC network}.
Lemma 6**.**
Let G=Xn∈Ln for n≥1. Then
- (1)
([18])* ∣V(G)∣=2n, ∣E(G)∣=n⋅2n−1, G is n-regular and triangle-free.*
2. (2)
([18],[39])* κ(G)=n.*
3. (3)
([47])* cn(G)=2.*
Lemma 7**.**
([47])*
For any Xn∈Ln, let F⊆V(Xn) with ∣F∣≤2n−3 be a vertex-cut of Xn.
Then Xn−F has two components, one of which is a trivial component.*
2.4 The k-ary n-cube networks
Definition 6**.**
The k-ary n-cube, denoted by Qnk, where k≥2 and n≥1 are integers, is a graph consisting of kn vertices, each of these vertices has the form
u=un−1un−2⋯u0, where ui∈{0,1,…,k−1} for 0≤i≤n−1. Two vertices u=un−1un−2⋯u0 and v=vn−1vn−2⋯v0 in Qnk
are adjacent if and only if there exists an integer j, where 0≤j≤n−1, such that uj=vj±1(mod k) and ui=vi for every i∈{0,1,…,n−1}∖{j}.
In this case, (u,v) is a j-dimensional edge.
For convenience, ‘‘(mod k)" does not appear in similar expressions in the remainder of the paper.
Note that each vertex has degree 2n for k≥3 and has degree n for k=2. Clearly, Q1k is a cycle of length k,
Qn2 is an n-dimensional hypercube, Q2k is a k×k wrap-around mesh.
Qnk can be partitioned over the jth-dimension, for a j∈[n−1], into k disjoint subcubes, denoted by Qn−1k[0],Qn−1k[1],…,Qn−1k[k−1],
by deleting all the j-dimensional edges from Qnk. For convenience, abbreviate these as Q[0],Q[1],…,Q[k−1] if there is no ambiguity.
Moreover, Q[i] for 0≤i≤k−1 is isomorphic to the k-ary (n−1)-cube. For each vertex u∈V(Q[i]), the neighbor which is not in V(Q[i]) is called the extra neighbor.
For i∈[k−1], u∈V(Q[i]), the two extra neighbors of u are in different subgraphs Q[i+1] and Q[i−1], respectively.
Lemma 8**.**
Let Qnk be a k-ary n-cube, where k≥2 and n≥1 are integers.
- (1)
([14])* Qnk is 2n-regular and 2n-connected for k≥3
and n-regular and n-connected for k=2.*
2. (2)
([13, 20, 25])* For any x,y∈V(Qnk), k⩾2,*
[TABLE]
Lemma 9**.**
- (1)
([15])* If F⊆V(Qn2) with ∣F∣≤2n−3 is a vertex cut of Qn2 for n≥2, then Qn2−F has two components, one of which is a trivial component.*
2. (2)
([13, 20])*
If F⊆V(Qn3) with ∣F∣≤4n−4 is a vertex cut of Qn3 for n≥2, then Qn3−F has two components, one of which is a trivial component.*
3. (3)
([13, 21])*
If F⊆V(Qnk) is a vertex cut of Qnk with ∣F∣≤4n−3 for n≥2 and k≥4, then Qnk−F has two components, one of which is a trivial component.*
2.5 Split-star networks Sn2
Cheng et al. [7] propose the Split-star networks as alternatives to the star graphs and companion graphs with the alternating group graphs.
Definition 7**.**
Given two positive integers n and
k with n>k, note that [n]={1,2,…,n}, and let Pn be a set of n! permutations on [n]. The n-dimensional Split-star
network, denoted by Sn2, such that V(Sn2)=Pn, E(Sn2)={(p,q)∣ p (resp. q) can be obtained from q
(resp. p) by either a 2-exchange or a 3-rotation }. Where
- (1)
A 2-exchange interchanges the symbols in 1st position
and 2nd position.
2. (2)
A 3-rotation rotates the symbols in three positions
labeled by the vertices of a triangle in which three vertices of the triangle are 1,2 and k for some
k∈{3,4,…,n}.
Let Vnn:i be the set of all vertices in Sn2 with the nth position having value i, i.e.,
Vnn:i={p∣p=x1x2⋯xn−1i, xj∈{1,2,…,i−1,i+1,…n}
(1≤j≤n−1) are do not care symbols }.
The set {Vnn:i∣1≤i≤n} forms a partition V(Sn2).
Let Sn2:i denote the subgraph of Sn2 induced by Vnn:i, i.e., Sn2:i=Sn2[Vnn:i].
It is easy to know that Sn2:i is isomorphic to Sn−12.
Every vertex v∈Sn2:i has exactly two neighbors, called extra neighbors, outside of Sn2:i;
moreover these two neighbors belong to different Sn2:js where j=i.
We call these neighbors as the extra neighbors of v. We call these edges, whose end-vertices belong to different subgraphs, as cross edges. Let Sn,E2 be a subgraph of Sn2 induced by the set of even permutations, in which the adjacency rule is precisely the 3-rotation. We know that Sn,E2 is the alternating group graph AGn [29].
Let Sn,O2 be a subgraph of Sn2 induced by the set of odd permutations, in which the adjacency rule is precisely the 3-rotation. We have that Sn,O2 is also isomorphic to AGn and Sn,O2 is isomorphic Sn,E2 via the 2-exchange
ϕ(a1a2a3⋯an)=a2a1a3⋯an. Hence, there are 2n! matching edges between Sn,O2 and Sn,E2. Indeed, the Split-star network Sn2 is introduced in [8] which is the companion graph of AGn.
Lemma 10**.**
( [6, 7, 8])*
Let Sn2 be the n-dimensional split-star network.*
- (1)
Sn2* is (2n−3)-regular and κ(Sn2)=2n−3 for n≥2.*
2. (2)
Two extra neighbors of every vertex in Sn2:i are in distinct induced subgraphs and these two extra neighbors are adjacent. For any two vertices in the same subgraph Sn2:i, their extra neighbors in other subgraphs are different. There is one to one correspondence between the subgraph Sn,O2 and the subgraph Sn,E2.
3. (3)
Let x,y be any two vertices of Sn2, then
[TABLE]
Lemma 11**.**
( [32])*
If F⊆V(Sn2) with ∣F∣≤4n−10 is a vertex cut of Sn2 for n≥4, then Sn2−F has two components, one of which is a trivial component.*
2.6 Cayley graphs generated by transposition trees Γn
Note that Pn is a group of all permutations on [n]. For convenience,
(ij), which is called a transposition, denotes the permutation that swaps the elements at position i and j, that is (ij)p1p2…pi…pj…pn=p1p2…pj…pi…pn.
Definition 8**.**
Let Pn be symmetric group on [n], and the generating
set S to be a set of transpositions. A graph G(S) with vertex
set [n], where there is an edge between i and j if and only if the transposition (ij) belongs to S, is called the transposition generating graph.
When G(S) is a tree, we call G(S) a transposition tree.
The Cayley graphs Cay(Pn,S) obtained by transposition trees are called Cayley graphs generated by transposition trees, denoted by Γn.
If G(S)≅K1,n−1, Cay(Pn,S) is called the star graph, denoted by Sn. If G(S)≅Pn, that is the transposition tree is a path Pn with n vertices, then Cay(Pn,S) is called the bubble-sort graph, denoted by Bn.
Let Γni be the subgraph of Γn spanned by vertices corresponding to permutations with i in the last position. Then Γn can be divided into n subgraphs Γn−11, Γn−12, ⋯, Γn−1n and each Γn−1i is isomorphic to Γn−1 for i∈[n]. For u∈V(Γn−1i), denoted by u′=u(1n) the unique neighbor of u outside Γn−1i, called the extra neighbor of u.
Lemma 12**.**
Let Γn be the Cayley graphs generated by transposition trees for n≥3.
- (1)
([4])* κ(Γn)=n−1.*
2. (2)
([4])* Γn has the girth 4 unless Γn is the star graph which has girth 6. Γn does not have K2,3 as a subgraph.*
3. (3)
([42])* For any two distinct vertices u,v∈Γn, ∣NΓn(u)∩NΓn(v)∣=1 if Γn=Sn; Otherwise ∣NΓn(u)∩NΓn(v)∣≤2.*
Lemma 13**.**
([4, 42])*
If F⊆V(Γn) with ∣F∣≤2n−5 is a vertex cut of Γn for n≥4, then Γn−F has two components, one of which is a trivial component.*
2.7 Cayley graphs generated by 2-trees
Definition 9**.**
Let Γ be the alternating
group, the set of even permutations on {1,2,…,n},
and the generating set Δ to be a set of 3-cycles.
To get an undirected Cayley graph, we will assume
that whenever a 3-cycle (abc) is in Δ, so is its inverse,
(acb). Since (abc), (bca) and (cab) represent the
same permutation, the set {a,b,c} uniquely represents this
3-cycle and its inverse. So we can depict Δ via a hypergraph
with vertex set [n], where a hyperedge of size 3 corresponds
to each pair of a 3-cycle and its inverse in Δ.
It is easy to see that the Cayley graph generated by the
3-cycles in Δ is connected if its corresponding hypergraph H is
connected. Since an interconnection network needs to be
connected, we require H graph to be connected.
In general,
this graph may have extra K3’s formed by vertices
that do not correspond to a 3-cycle in Δ. We will avoid
this possibility by considering a simpler case when H has
a tree-like structure. Such a graph is built by the following
procedure. We start from K3, then repeatedly add a new
vertex, joining it to exactly two adjacent vertices of the previous
graph. Any graph obtained by this procedure is called
a 2-tree. If v is a vertex of a 2-tree H with the property
that H can be generated in such a way that v is the last
vertex added, then v is called a leaf of the 2-tree.
The alternating group graph AGn [28], can be viewed as the
Cayley graph generated by the graph having a
tree-like (in fact, star-like) structure of triangles.
It is easy to prove that if two 2-trees are isomorphic, then the corresponding Cayley graphs will also be isomorphic;
hence without loss of generality we may assume that vertex n is the tail of the 2-tree.
For n≥4, the vertices corresponding to even permutations ending with i
induce a subgraph Γn−1i(Δ) that is also a Cayley graph generated by a
2-tree Δ′, which is obtained by deleting the edges corresponding to the two 3-cycles in Δ containing n.
Thus we obtain the following result of the recursive structure of Γn(Δ):
Lemma 14**.**
([9])*
Let Γn(Δ) be a Cayley graph generated by the 2-tree Δ, Δ′=Δ−{n}, n≥4.
Then*
- (1)
Γn(Δ)* consists of n vertex-disjoint subgraphs, Γn−11(Δ),Γn−12(Δ),…,Γn−1n(Δ), each isomorphic to Γn−1(Δ′).*
2. (2)
Γn−1i(Δ)* has (n−1)!/2 vertices, and it is (2n−6)-regular for all i.*
3. (3)
There are exactly (n−2)! independent edges between Γn−1i(Δ) and Γn−1j(Δ) for all i=j.
4. (4)
Each vertex in Γn−1i(Δ) has exactly two neighbors outside Γn−1i(Δ); these two outside neighbors are in different Γn−1k(Δ)’s, and there is an edge between them. Thus every vertex forms a triangle with its two outside neighbors.
5. (5)
Γn(Δ)* does not contain K4−e, that is, K4
with an edge deleted, and K2,3 as a subgraph. For any two vertices u and v, ∣N(u)∩N(v)∣=1 if d(u,v)=1, ∣N(u)∩N(v)∣≤2 otherwise.*
Lemma 15**.**
([3])*
Let G=Γn(Δ) be a Cayley graph generated by the 2-tree Δ for n≥4. Then G is maximally
connected, i.e., G is (2n−4)-regular and (2n−4)-connected.*
Lemma 16**.**
([3])*
Let G=Γn(Δ) be a Cayley graph generated by the 2-tree Δ for n≥4,
and let T be a set of vertices in G such that ∣T∣≤4n−11. If n≥5, then G−T satisfies one of the following conditions:*
- (1)
G−T* is connected.*
2. (2)
G−T* has two components, one of which is a singleton.*
3. (3)
G−T* has two components, one of which is a K2. Moreover, ∣T∣=4n−11, and the set T is formed by the neighbors of the two vertices in the K2.*
When n=4, there are two additional possibilities. In both cases, G−T has two components, one of which is a 4-cycle. The other component is either a 4-cycle if ∣T∣=4 or a path with 3 vertices if ∣T∣=5.
2.8 Burnt pancake networks BPn
Gates and Papadimitriou [22] introduced the burnt pancake problem in 1979. Burnt pancake problem relates to the construction of networks of parallel processors.
Let n be a positive integer. We use [n] to denote the set {1,2,…,n}. To save space, the negative sign may be placed on the top of an expression. Thus, iˉ=−i. We use ⟨n⟩ to denote the set [n]∪{iˉ∣i∈[n]}. A signed permutation of
[n] is an n-permutation u1u2⋯un of ⟨n⟩ such that
∣u1∣∣u2∣⋯∣un∣ taking the absolute value of each element, forms a permutation of [n].
For a signed permutation u=x1x2⋯xi⋯xn of ⟨n⟩, the i-th prefix reversal of u,
denoted by ui is ui=xˉixˉi−1⋯xˉ1xi+1⋯xn,1≤i≤n.
For example, let u=12ˉ43ˉ5; then u is a signed permutation of [5],
u2=21ˉ43ˉ5, u5=5ˉ34ˉ21ˉ.
Definition 10**.**
An n-dimensional burnt pancake network BPn is
defined to be an n-regular graph G with n!2n vertices, each of which has a unique label from
the signed permutation of ⟨n⟩.
Two vertices u and v are adjacent in BPn if and only if ui=v for some unique i (1≤i≤n).
Such an edge uv is called an i-dimensional edge and v is called the i-neighbor of u.
It is seen that every vertex has a unique i-neighbor for 1≤i≤n.
Lemma 17**.**
([10, 12, 27])*
An n-dimensional burnt pancake network BPn has the following combinatorial properties.*
- (1)
BPn* is n-regular with n!×2n vertices and n!×2n−1 edges.*
2. (2)
κ(BPn)=n, the girth of BPn(n≥3) is g(BPn)=8.
3. (3)
BPn* can be decomposed into 2n vertex-disjoint subgraphs, denoted BPni, by fixing the
symbol in the last position n, in which the symbol in the nth position is i, where i∈[n]. Obviously,
BPni is isomorphic to BPn−1. The number of cross edges between any two subgraphs, BPni and BPnj
(i=j,i,j∈[n]), is ∣E(i,j)∣=(n−2)!×2n−2 if i=jˉ; otherwise, ∣E(i,j)∣=0.
For a vertex v∈V(BPni), v has exactly one neighbor outside BPni, called the extra neighbor of v.*
Lemma 18**.**
([35])*
For any subset F⊆V(BPn) with ∣F∣≤2n−2 is a vertex-cut of BPn for n≥4, then BPn−F satisfies
one of the following conditions.*
- (1)
BPn−F* has two connected components, one of which is a trivial component;*
2. (2)
BPn−F* has two connected components, one of which is an edge. Furthermore,
F is the neighborhood of this edge with ∣F∣=2n−2.*
3 Main result
In this section, the relationship between the pessimistic diagnosability
under the PMC model and the
extra connectivity with some restricted conditions will
be proposed.
Lemma 19**.**
Let G be a k-regular graph.
Let u and v be two distinct vertices
in G, if cn(G;u,v)≤2, then ∣NG({u,v})∣≥2k−2−l, where l=l(G)=max{cn(G;u,v):(u,v)∈E(G)}, i.e., l=l(G) be the maximum number of common neighbors between any two adjacent vertices.
Proof. Since cn(G;u,v)≤2, if u is non-adjacent to v,
then ∣NG({u,v})∣=∣NG(u)∣+∣NG(v)∣−cn(G;u,v)≥2k−2≥2k−2−l.
Otherwise, u is adjacent to v, ∣NG({u,v})∣=∣NG(u)∣−1+∣NG(v)∣−1−cn(G;u,v)≥2(k−1)−l.
As a result, ∣NG({u,v})∣≥2k−2−l.
∎
Tsai and Chen [36] derived the following result which characterizes a graph for t/t-diagnosability.
Lemma 20**.**
([36])*
A graph G is t/t-diagnosable if and only if for each vertex set S⊆V(G) with ∣S∣=p, 0≤p≤t−1,
G−S has at most one trivial component and each nontrivial component C of G−S satisfies ∣V(C)∣≥2(t−p)+1.*
The following result is useful.
Lemma 21**.**
([17])*
Let G be a connected graph and U⊆V(G). Then, ∣NV(G)−U(U)∣≥κ(G) if ∣V(G)−U∣≥κ(G), otherwise, ∣NV(G)−U(U)∣=∣V(G)−U∣.*
Theorem 1**.**
Let G be a k-regular k-connected (k≥5) graph with order N.
Let U be a subset of V(G) and l=l(G) be the maximum number of common neighbors between any two adjacent vertices.
Suppose further that all of the following conditions hold:
- (1)
N≥4k−2.
2. (2)
cn(G)≤2.
3. (3)
If 2≤∣U∣≤2(2k−4−l), then ∣NG(U)∣≥2k−2−l.
4. (4)
Let F⊆V(G) be a vertex-cut of G.
If ∣F∣≤2k−3−l, then G−F has a large component and a small component which is a trivial component.
Then, tp(G)=2k−2−l=κ1(G).
Proof. We first prove tp(G)≤2k−2−l. Suppose tp(G)≥2k−2−l+1,
then G is (2k−2−l+1)/(2k−2−l+1)-diagnosable.
Let (u,v) be an edge of G such that ∣NG(u)∩NG(v)∣=l.
Let S=NG({u,v}). Then ∣S∣=2k−2−l≤tp(G)−1. An edge {u,v} is a connected component of G−S, say C.
By Lemma 20, ∣V(C)∣≥2(tp(G)−∣S∣)+1≥2[(2k−2−l+1)−(2k−2−l)]+1=3, which is a contradiction. Thus, tp(G)≤2k−2−l.
Secondly, we show tp(G)≥2k−2−l, i.e., G is (2k−2−l)/(2k−2−l)-diagnosable. Suppose G is not (2k−2−l)/(2k−2−l)-diagnosable,
by Lemma 20, there exists a vertex set
S⊆V(G) with ∣S∣=p, 0≤p≤2k−3−l such that G−S contains more than one trivial components or
contains a nontrivial component C with ∣V(C)∣≤2(2k−2−l−p). The following cases should be considered.
Case 1. G−S contains more than one trivial components.
Suppose C1={u} and C2={v} are two distinct trivial components of G−S. By Condition (2) and
Lemma 19, ∣NG({u,v})∣≥2k−2−l.
Note that NG({u,v})⊆S, this implies that ∣S∣≥2k−2−l, which is a contradiction.
Case 2. G−S contains a nontrivial component C with 2≤∣V(C)∣≤2(2k−2−l−p).
Suppose p≤1. Since the connectivity of G is k≥5>p, G−S is connected.
It implies C=G−S. By ∣V(C)∣=∣V(G)∣−∣S∣=N−p≥N−1, Condition (1) and l≤cn(G)≤2,
one has ∣V(C)∣≥4k−3≥2(2k−2−l−p)+1 which is a contradiction.
Now consider 2≤p≤2k−3−l. Since 2≤∣V(C)∣≤2(2k−2−l−p), so 2≤∣V(C)∣≤2(2k−4−l).
By condition (3), ∣NG(V(C))∣≥2k−2−l. Since C is a connected component of G−S, NG(V(C))⊆S. This implies p=∣S∣≥2k−2−l,
which is a contradiction for the fact that p=∣S∣≤2k−3−l. Thus, tp(G)≤2k−2−l.
Next we prove 2k−2−l=κ1(G). Let (u,v) be an edge of G such that ∣NG(u)∩NG(v)∣=l.
Let S=NG({u,v}). Then ∣S∣=2k−2−l. If G−S={(u,v)}, then ∣V(G)∣=∣S∣+2=2k−l<4k−2
for k≥5 which contradicts with Condition (1). If G−S has a trivial component which contains only one vertex, say {x}, then G−S has at least
two components: {x} and the edge (u,v). By cn(G)≤2,
then ∣S∣≥2k−2−l+(k−4)=3k−6−l. Note 3k−6−l>2k−2−l for k≥5, it is a contradiction.
Thus, G−S has no trivial component, i.e., S is an extra vertex cut of G, which implies κ1(G)≤2k−2−l.
On the other hand, by condition (4), κ1(G)≥2k−2−l. Thus, κ1(G)=2k−2−l.
By above discussion, tp(G)=2k−2−l=κ1(G). ∎
4 Application to some interconnection networks
As applications of Theorem 1, in this section, we
determine the pessimistic diagnosability and extra connectivity
for some well-known interconnection networks,
including the alternating group graph AGn, the alternating group network ANn,
the k-ary n-cube networks Qnk, BC networks Xn, split-star networks Sn2,
Cayley graphs generated by transposition trees Γn,
Cayley graphs generated by 2-trees, burnt pancake networks BPn.
4.1 Application to the alternating group graphs AGn
Remark 1**.**
It is known that κ1(AGn)=4n−11 for n≥5
determined by Lin et al. [33]
and tp(AGn)=4n−11 obtained by Tsai [37].
As a corollary of Theorem 1, we immediately obtain the following result which contains the above result.
Corollary 1**.**
Let AGn be the n-dimensional alternating group graph for n≥5. Then tp(AGn)=4n−11=κ1(AGn).
Proof. Obviously, N=∣V(AGn)∣=2n!, k=2n−4≥6 for n≥5, l=l(AGn)=1.
Note that N=2n!≥4(2n−4)−2 for n≥5,
Conditions (1) in Theorem 1 holds.
Conditions (2)−(4) in Theorem 1 hold
by Lemmas 1, 2 and 3, respectively.
Thus, AGn satisfies all conditions in Theorem 1, tp(AGn)=4n−11=κ1(AGn) for n≥5. ∎
4.2 Application to the alternating group networks
Zhou [45] derived κ1(ANn)=2n−5 for n≥4.
However, tp(ANn) has not been determined so far.
We can deduce the result as a corollary of Theorem 1 as following.
Notice that for ANn, k=n−1, l=1 in Theorem 1.
Lemma 22**.**
Let ANn be the n-dimensional alternating group network for n≥4.
If U is a subset of V(ANn) and 2≤∣U∣≤2(2k−4−l)=4n−14, then ∣NANn(U)∣≥2n−5.
Proof. The Lemma can be proved by using the induction on n.
It is easy to verify that ∣NAN4(U)∣≥3 for ∣U∣=2 by Lemma 19.
We assume that the lemma is true for ANm, where m is an integer with 5≤m≤n−1, we will prove the result for ANn.
Recall that ANn is constructed by n disjoint ANn−1’s, denoted by ANni for i∈[n].
Let Ui=U∩V(ANni) and ANni=ANn−ANni for i∈[n]. Without loss of generality, we may assume that ∣U1∣≥∣U2∣≥…≥∣Un∣.
The following cases should be considered.
Case 1. ∣U1∣≤1.
In this case, ∣Ui∣≤1 for all i∈[n]. Clearly, 2≤∣U∣≤n because of i≤n.
The Lemma follows if ∣U∣=2 by Lemma 19.
Now assume that 3≤∣U∣≤n. Since ANn is (n−1)-regular and ANni is isomorphic to ANn−1, ∣NANn(U)∣≥3κ(ANni)=3(n−2)≥2n−5 for n≥7.
Case 2. 2≤∣U1∣≤4n−19.
By inductive hypothesis in ANn1, ∣NANn1(U1)∣≥2(n−1)−5=2n−7.
If U=U1, ∣NANn(U)∣=∣NANn1(U1)∣+∣NANn1(U1)∣≥2n−7+∣U1∣≥2n−5. Assume U=U1 in the following.
If ∣U2∣=1, ∣NANn2(U2)∣=κ(ANn2)=n−2.
Note that ANn1 and ANn2 are vertex disjoint, ∣NANn(U)∣≥∣NANn1(U1)∣+∣NANn2(U2)∣≥3n−9≥2n−5 for n≥5.
Now consider 2≤∣U2∣≤∣U1∣≤4n−19, by inductive hypothesis in ANn2, ∣NANn2(U2)∣≥2(n−1)−5=2n−7.
Thus, ∣NANn(U)∣≥∣NANn1(U1)∣+∣NANn2(U2)∣≥4n−14≥2n−5 for n≥5.
Case 3. 4n−18≤∣U1∣≤4n−14.
Since the connectivity of ANn1 is n−2, and 2(n−1)!−∣U1∣≥n−2=κ(ANn1) for n≥5, by Lemma 21, ∣NANn1(U1)∣≥n−2.
By Lemma 4, ∣NANn1(U1)∣=∣U1∣.
If U=U1, ∣NANn(U)∣≥∣NANn1(U1)∣+∣NANn1(U1)∣≥(n−2)+4n−18=5n−20≥2n−5 for n≥5.
In the following, we assume the case of U=U1.
Note that U=U1 and ∣U−U1∣≤3, so 1≤∣U2∣≤3.
If ∣U2∣=1, recall that ANn is (n−1)-regular and ANni is isomorphic to ANn−1, ∣NANn2(U2)∣=κ(ANn2)=n−2.
Hence, ∣NANn(U)∣≥∣NANn1(U1)∣+∣NANn2(U2)∣≥2n−4≥2n−5 for n≥5.
Now suppose that 2≤∣U2∣≤3. Since 2(n−1)!−∣U2∣≥n−2=κ(ANn2) for n≥5,
by Lemma 21, ∣NANn2(U2)∣≥n−2.
Thus, ∣NANn(U)∣≥∣NANn1(U1)∣+∣NANn2(U2)∣≥2(n−2)≥2n−5 for n≥5.
By the above cases, the Lemma holds. ∎
Corollary 2**.**
Let ANn be the n-dimensional alternating group network for n≥6. Then tp(ANn)=2n−5=κ1(ANn).
Proof. Note that N=∣V(ANn)∣=2n!≥4(n−1)−2 for n≥6, Condition (1) in Theorem 1 holds.
Conditions (2)-(4) in Theorem 1 hold by Lemmas 4, 5 and 22, respectively.
So ANn satisfies all conditions in Theorem 1, and
tp(ANn)=2n−5=κ1(ANn) for n≥6. ∎
4.3 Application to BC networks
Note that Ln={Xn:Xn is an n−dimensional BC network}.
For a BC network Xn∈Ln, the connectivity is k=n≥5, l=0, N=∣V∣=2n≥4n−2 for n≥5 in Theorem 1.
As a directive corollary of Theorem 1, we can get the result κ1(Xn)=tp(Xn)=2n−2 in which
Zhu [47] determined κ1(Xn)=2n−2 for n≥4. Fan and Lin [19] obtained tp(Xn)=2n−2 for n≥4.
Lemma 23**.**
For any Xn∈Ln, if U⊆V(Xn) with 2≤∣U∣≤4n−8 for n≥3, then ∣NXn(U)∣≥2n−2.
Proof. We prove the lemma by using introduction on n.
If n=3, 2≤∣U∣≤4n−8=4, it is not difficult to see that ∣NX3(U)∣≥4.
Assume that the lemma is true for Xm−1, where m is an integer with 4≤m≤n−1.
We consider Xn for n≥4 as follows.
Since Xn is n-regular n-connected triangle-free and C(Xn)=2, if ∣U∣=2, then ∣NXn(U)∣≥2n−2.
Now consider 3≤∣U∣≤4n−8. Note that Xn contains two copies of Xn−1,
say Xn−11 and Xn−12, respectively. Let
Ui=U∩V(Xn−1i) for i∈{1,2}.
Without loss of generality, we may assume that ∣U1∣≥∣U2∣.
It implies that 2≤∣U1∣.
Case 1. 2≤∣U1∣≤4n−12.
By the inductive hypothesis in Xn−11, ∣NXn−11(U1)∣≥2n−4.
If ∣U2∣=0, then U=U1.
∣NXn(U)∣≥∣NXn−11(U1)∣+∣NXn−11(U1)∣≥(2n−4)+2≥2n−2.
If ∣U2∣=1, ∣NXn−12(U2)∣=κ(Xn−12)=n−1.
Thus ∣NXn(U)∣≥∣NXn−11(U1)∣+∣NXn−12(U2)∣≥(2n−4)+(n−1)=3n−5≥2n−2 for n≥4.
Now consider 2≤∣U2∣≤∣U1∣≤4n−12 for n≥4, so ∣NXn−12(U2)∣≥2n−4.
Thus, ∣NXn(U)∣≥∣NXn−11(U1)∣+∣NXn−12(U2)∣≥2(2n−4)=4n−8≥2n−2 for n≥4.
Case 2. 4n−11≤∣U1∣≤4n−8.
If U=U1, by definition, ∣NXn−11(U1)∣=∣U1∣≥4n−11.
Thus, ∣NXn(U)∣≥∣NXn−11(U1)∣≥4n−11≥2n−4 for n≥4.
Now assume that U=U1. Since the connectivity of Xn−11 is n−1 and
∣V(Xn−11)∣−(4n−8)≥κ(Xn−11)=n−1 for n≥4, by Lemma 21, ∣NXn−11(U1)∣≥n−1.
Note that U=U1 and ∣U−U1∣≤3, so 1≤∣U2∣≤3.
If ∣U2∣=1, ∣NXn−12(U2)∣=κ(Xn−12)=n−1.
Hence, ∣NXn(U)∣≥∣NXn−11(U1)∣+∣NXn−12(U2)∣≥2n−2 for n≥4.
Now suppose that 2≤∣U2∣≤3. Since ∣V(Xn−12)∣−3≥κ(B2)=n−1 for n≥4,
by Lemma 21, ∣NXn−12(U2)∣≥κ(Xn−12)=n−1.
So ∣NXn(U)∣≥∣NXn−11(U1)∣+∣NXn−12(U2)∣≥2n−2 for n≥4.
By the above cases, the proof is completed.
∎
By Lemmas 6, 7 and 23 and Theorem 1, we obtain the following Corollary 3.
Corollary 3**.**
For any Xn∈Ln, tp(Xn)=2n−2=κ1(Xn) for n≥5.
It is not difficult to check that the hypercube Qn, the crossed cube CQn,
the Mo¨bius cubes MQn, the twisted cubes TQn are all n-regular n-connected triangle-free BCs, then the following known result is derived directly.
Corollary 4**.**
([19])*
Every pessimistic diagnosability of the hypercube Qn, the crossed cube CQn, the
Mo¨bius cubes MQn and the twisted cubes TQn is 2n−2 for n≥6..*
4.4 Application to the k-ary n-cube networks Qnk
Lemma 24**.**
Let Qnk be a k-ary n-cube, where k≥2 and n≥1 are integers.
- (1)
For n≥3, let U be a subset of V(Qn2) with 2≤∣U∣≤4n−8. Then ∣NQn2(U)∣≥2n−2.
2. (2)
For n≥3, let U be a subset of V(Qn3) and 2≤∣U∣≤8n−10, then ∣NQn3(U)∣≥4n−3.
3. (3)
For n≥3 and k≥4, let U be a subset of V(Qnk) and 2≤∣U∣≤8n−8, then ∣NQnk(U)∣≥4n−2.
Proof. Since the proof for the three cases are similar, we take (2) as an example, the details for (1) and (3) are omitted.
Let Q[0],Q[1],Q[2] represent the three disjoint subcubes obtained from Qn3 by partition over one dimension.
Let Ui=U∩V(Q[i]) and Q[i]=Qn3−Q[i] for i∈{0,1,2}. Without loss of generality, we may assume that ∣U0∣≥∣U1∣≥∣U2∣.
The lemma is proved by the induction on n. When n=3, it is easy to check ∣NQ33(U)∣≥9 for 2≤∣U∣≤8n−10=14.
We assume that the lemma is true for Qm−13, where m is an integer with 4≤m≤n−1. We consider Qn3 for n≥4 as follows.
Case 1. ∣U0∣≤1.
In this case, ∣Ui∣≤1 for all 0≤i≤2. Clearly, 2≤∣U∣≤3 because of i≤2. The Lemma follows if ∣U∣=2 by Lemma 19.
Now assume that ∣U∣=3. Since Qn3 is 2n-regular and Q[i] is isomorphic to Qn−13, ∣NQn3(U)∣≥3κ(Qn−13)=3(2n−2)≥4n−3 for n≥3.
Case 2. 2≤∣U0∣≤8n−18.
By inductive hypothesis in Q[0], ∣NQ[0](U0)∣≥4(n−1)−3=4n−7.
If U=U0, then ∣NQn3(U)∣=∣NQ[0](U0)∣+∣NQ[0](U0)∣≥4n−7+2∣U0∣≥4n−7+4=4n−3. Assume U=U0 in the following.
Note that ∣U∣≤8n−10 and ∣U0∣≥∣U1∣≥∣U2∣, ∣U1∣≤4n−5.
If ∣U1∣=1, ∣NQ[1](U1)∣=κ(Q[1])=2n−2.
Note that Q[0] and Q[1] are vertex disjoint, ∣NQn3(U)∣≥∣NQ[0](U0)∣+∣NQ[1](U1)∣≥(4n−7)+(2n−2)=6n−9≥4n−3 for n≥4.
Now consider 2≤∣U1∣≤4n−5≤8n−18 for n≥4, by inductive hypothesis in Q[1], ∣NQ[1](U1)∣≥4(n−1)−3=4n−7.
Thus, ∣NQn3(U)∣≥∣NQ[0](U0)∣+∣NQ[1](U1)∣≥2(4n−7)=8n−14≥4n−3 for n≥4.
Case 3. 8n−17≤∣U0∣≤8n−10.
If U=U0, ∣NQn3(U)∣≥∣NQ[0](U0)∣=2∣U0∣≥2(8n−17)≥4n−3 for n≥4.
In the following, we assume the case of U=U0. Since the connectivity of Q[0] is 2n−2, note that U=U0, so 2≤∣U0∣≤8n−11.
Since ∣V(Q[0])−U0∣=3n−1−∣U0∣≥3n−1−(8n−11)≥2n−2=κ(Q[0]) for n≥4, and by Lemma 21, ∣NQ[0](U0)∣≥2n−2.
Note that U=U0 and ∣U−U0∣≤7, so 1≤∣U1∣≤7.
If ∣U1∣=1 and ∣U2∣=0, recall that the connectivity of Qn3 is 2n and Q[i] is isomorphic to Qn−1k, ∣NQ[1](U1)∣=κ(Q[1])=2n−2.
Note that each vertex in Q[0] (resp. Q[1]) has an extra neighbor in Q[2].
Hence, ∣NQn3(U)∣≥∣NQ[0](U0)∣+∣NQ[1](U1)∣+∣NQ[2](U0)∣≥4n−4+(8n−17)=12n−21≥4n−3 for n≥4.
If ∣Ui∣=1 for i=1,2, ∣NQ[i](Ui)∣=κ(Q[i])=2n−2.
Hence, ∣NQn3(U)∣≥∣NQ[0](U0)∣+∣NQ[1](U1)∣+∣NQ[2](U2)∣≥3(2n−2)=6n−6≥4n−3 for n≥4.
Now suppose that 2≤∣U1∣≤7.
Since 7<8n−17 for n≥4, by inductive hypothesis in Q[1], ∣NQ[1](U1)∣≥4(n−1)−3=4n−7.
Thus, ∣NQn3(U)∣≥∣NQ[0](U0)∣+∣NQ[1](U1)∣≥(2n−2)+(4n−7)=6n−9≥4n−3 for n≥4.
The proof is complete. ∎
Remark 2**.**
Esfahanian [15] obtained κ1(Qn2)=2n−2 for n≥3 and Day [13] got κ1(Qn3)=4n−3, κ1(Qnk)=4n−2 for k≥4. Kavianpour and Kim [30] proved that tp(Qn2)=2n−2 for n≥3 and Wang et al. [41] derived
tp(Qn3)=4n−3, tp(Qnk)=4n−2 for k≥4 and n≥4.
These results can be gotten directly as corollary of Theorem 1 as following.
Since kn≥4κ(Qnk)−2 for k≥3 and n≥3 (k=2 and n≥5),
Condition (1) in Theorem 1 holds. By Lemmas 8, 9 and 24, Condition (2)-(4) in Theorem 1 holds.
Corollary 5**.**
Let Qnk be a k-ary n-cube, where k≥2 and n≥1 are integers. Then
- (1)
tp(Qn2)=2n−2=κ1(Qn2)* for n≥5;*
2. (2)
tp(Qn3)=4n−3=κ1(Qn3)* for n≥3;*
3. (3)
tp(Qnk)=4n−2=κ1(Qnk)* for n≥3 and k≥4.*
4.5 Application to the split-star networks Sn2
Lin et al. [32] proved κ1(Sn2)=4n−9 for n≥4. However,
tp(Sn2) has not been determined so far.
We can deduce the result by Theorem 1 in which for Sn2, k=2n−3, l=1.
Lemma 25**.**
Let Sn2 be the n-dimensional split-star network for n≥4.
If U is a subset of V(Sn2) and 2≤∣U∣≤8n−22,
then ∣NSn2(U)∣≥4n−9.
Proof. We prove the lemma by using the induction on n. Since S42 is constructed by four disjoint triangles S32, it is easy to verify that ∣NS42(U)∣≥7 for 2≤∣U∣≤10.
By the inductive hypothesis, we assume that the lemma is true for Sm2,
where m is an integer with 5≤m≤n−1.
Now we consider Sn2.
Recall that Sn2 is constructed by n disjoint Sn−12s, denoted by Sn2:i for i∈[n].
Let Ui=U∩V(Sn2:i) and Sn2:i=Sn2−Sn2:i for i∈[n].
Without loss of generality, we may assume that ∣U1∣≥∣U2∣≥…≥∣Un∣.
The following cases should be considered.
Case 1. ∣U1∣≤1.
In this case, ∣Ui∣≤1 for all i∈[n]. Clearly, 2≤∣U∣≤n because of U=i=1⋃nUi.
If ∣U∣=2, by Lemma 19, ∣NSn2(U)∣≥2(2n−3)−2−1=4n−9, the lemma follows.
Now assume that 3≤∣U∣≤n. Since Sn2 is (2n−3)-regular and Sn2:i is isomorphic to Sn−12, ∣NSn2(U)∣≥3κ(Sn2:i)=3(2n−5)≥4n−9 for n≥5.
Case 2. 2≤∣U1∣≤8n−30.
By inductive hypothesis in Sn2:1, ∣NSn1(U1)∣≥4(n−1)−9=4n−13.
Since ∣U∣≤8n−22 and ∣U1∣≥∣U2∣≥…≥∣Un∣, ∣U2∣≤4n−11.
If U=U1, by Lemma 10(2), ∣NSn2(U)∣=∣NSn2:1(U1)∣+∣NSn2:1(U1)∣≥4n−13+2∣U1∣≥4n−9.
Assume U=U1 in the following. If ∣U2∣=1, ∣NSn2:1(U1)∣=κ(Sn2:1)=2n−5.
Note that Sn2:1 and Sn2:2 are vertex disjoint, ∣NSn2(U)∣≥∣NSn2:1(U1)∣+∣NSn2:2(U2)∣≥4n−13+2n−5=6n−18≥4n−9 for n≥5.
Now consider 2≤∣U2∣≤4n−11. Note that 4n−11≤8n−30 for n≥5, by inductive hypothesis in Sn2:2, ∣NSn2:2(U2)∣≥4(n−1)−9=4n−13.
Thus, ∣NSn2(U)∣≥∣NSn2:1(U1)∣+∣NSn2:2(U2)∣≥8n−26≥4n−9 for n≥5.
Case 3. 8n−29≤∣U1∣≤8n−22.
By Lemma 10(2), ∣NSn2:1(U1)∣=2∣U1∣.
If U=U1, ∣NSn2(U)∣≥∣NSn2:1(U1)∣=2∣U1∣≥16n−58≥4n−9 for n≥5.
In the following, we assume the case of U=U1.
Since the connectivity of Sn2:1 is 2n−5,
and (n−1)!−∣U1∣≥2n−5=κ(Sn2:1) for n≥5, by Lemma 21, ∣NSn2:1(U1)∣≥2n−5.
Note that U=U1 and ∣U−U1∣≤7, so 1≤∣U2∣≤7.
If ∣U2∣=1, recall that Sn2 is (2n−3)-regular
and Sn2:i is isomorphic to Sn−12, ∣NSn2:2(U2)∣=κ(Sn2:2)=2n−5.
Hence, ∣NSn2(U)∣≥∣NSn2:1(U1)∣−∣U−U1∣≥16n−65≥4n−9
for n≥5. Now suppose that 2≤∣U2∣≤7.
Since 7≤8n−30 for n≥5, by inductive hypothesis in Sn2:1,
∣NSn2:1(U1)∣≥4(n−1)−9=4n−13.
Thus, ∣NSn2(U)∣≥∣NSn2:1(U1)∣+∣NSn2:2(U2)∣≥(2n−5)+(4n−13)=6n−18≥4n−9 for n≥5.
By the above cases, the lemma holds. ∎
Corollary 6**.**
Let Sn2 be the n-dimensional split-star network for n≥4. Then
tp(Sn2)=4n−9=κ1(Sn2).
Proof. To prove the theorem, we only need to verify that Sn2 satisfies conditions in Theorem 1.
Note that k=2n−3≥5 for n≥4, l=1,
N=∣V(Sn2)∣=n!≥4(2n−3)−2 for n≥4, Condition (1) in Theorem 1 holds.
By Lemmas 10 and 25, Conditions (2)-(3) in Theorem 1 holds. Condition (4) holds by Lemma 11. Sn2 satisfies all conditions in Theorem 1, and thus
tp(Sn2)=4n−9=κ1(Sn2).
∎
4.6 Application to the Cayley graphs generated by transposition trees Γn
Let Γn be Cayley graphs generated by transposition trees.
Yang et al. [42] determined κ1(Γn)=2n−4 for n≥3.
However, tp(Γn) has not been known so far. By Theorem 1,
we immediately the following result which contains the above result.
Note that for Γn, k=n−1, l=0 in Theorem 1.
Lemma 26**.**
Let Γn be Cayley graphs generated by transposition trees for n≥4.
If U is a subset of V(Γn) and 2≤∣U∣≤4n−12, then ∣NΓn(U)∣≥2n−4.
Proof. The lemma is proved by induction on n. When n=4, it is easy to check ∣NΓn(U)∣≥4
for 2≤∣U∣≤4n−12=4. We assume that the lemma is true for Γm, where m is an integer with 4≤m≤n−1. We consider Γn for n≥5 as follows.
Recall that Γn can be decomposed into n copies of Γn−1′s, namely Γn−11,Γn−12,…,Γn−1n.
Let Ui=U∩V(Γn−1i) and Γn−1i=Γn−Γn−1i for i∈[n]. Without loss of generality, we may assume that ∣U1∣≥∣U2∣≥∣U3∣≥…≥∣Un∣.
Case 1. ∣U1∣≤1.
In this case, ∣Ui∣≤1 for all 1≤i≤n. Since ∣U∣≥2, it implies ∣U1∣=∣U2∣=1.
Since Γn is (n−1)-regular and Γn−1i is isomorphic to Γn−1,
∣NΓn(U)∣≥2κ(Γn−1i)=2(n−2)=2n−4 for n≥5.
Case 2. 2≤∣U1∣≤4n−16.
By inductive hypothesis in Γn−11, ∣NΓn−11(U1)∣≥2(n−1)−4=2n−6.
Note that ∣Ui∣≤∣U1∣≤4n−16 for i∈{2,3,…,n}.
If ∣U2∣=1, ∣NΓn−12(U2)∣≥κ(Γn−12)=n−2,
so ∣NΓn(U)∣≥∣NΓn−11(U1)∣+∣NΓn−12(U2)∣≥(2n−6)+(n−2)=3n−8≥2n−4 for n≥5.
If 2≤∣U2∣≤4n−16, by inductive hypothesis in Γn−12, ∣NΓn−12(U2)∣≥2(n−1)−4=2n−6.
Thus, ∣NΓn(U)∣≥∣NΓn−11(U1)∣+∣NΓn−12(U2)∣≥2(2n−6)=4n−12≥2n−4 for n≥5.
Now consider ∣U2∣=0, then ∣Ui∣=0 for i∈{3,4,…,n}, it implies that U=U1.
So ∣NΓn(U)∣≥∣NΓn−11(U1)∣+∣NΓn−11(U1)∣≥2n−6+∣U1∣≥2n−6+2=2n−4 for n≥5.
Case 3. 4n−15≤∣U1∣≤4n−12.
If U=U1, by Lemma 12, ∣NΓn−11(U1)∣=∣U1∣≥4n−15.
Since (n−1)!−(4n−12)≥n−2 for n≥5, by Lemma 21, ∣NΓn−11(U1)∣≥κ(Γn−11)=n−2. Thus,
∣NΓn(U)∣=∣NΓn−11(U1)∣+∣NΓn−11(U1)∣≥4n−15+(n−2)=5n−17≥2n−4 for n≥5.
In the following, we assume that U=U1.
It implies that ∣U−U1∣≤3, so 1≤∣U2∣≤∣U∣−∣U1∣≤3.
If ∣U2∣=1, ∣NΓn−12(U2)∣=κ(Γn−12)=n−2.
Recall that ∣NΓn−11(U1)∣≥n−2.
Hence, ∣NΓn(U)∣≥∣NΓn−10(U0)∣+∣NΓn−11(U1)∣≥2n−4 for n≥5.
Now suppose that 2≤∣U2∣≤3. Since ∣U2∣≤3≤4n−16 for n≥5, by inductive hypothesis in Γn−12, ∣NΓn−12(U2)∣≥2(n−1)−4=2n−6.
Thus, ∣NΓn(U)∣≥∣NΓn−11(U1)∣+∣NΓn−12(U2)∣≥(n−2)+(2n−6)=3n−8≥2n−4 for n≥5.
By the above cases, the proof is completed.
∎
Corollary 7**.**
Let Γn be Cayley graphs generated by transposition trees for n≥6.
Then tp(Γn)=2n−4=κ1(Γn) for n≥6.
Proof. Note that k=n−1≥5 and N=∣V(Γn)∣=n!≥4(n−1)−2 for n≥6, Condition (1) in Theorem 1 holds.
By Lemma 12 and 26, Condition (2)-(3) in Theorem 1 holds.
Condition (4) holds by Lemma 13.
Thus, Γn satisfies all conditions in Theorem 1, tp(Γn)=2n−4=κ1(Γn) for n≥6. ∎
Since the star graph and the bubble-sort graph are Cayley graph generated by transposition trees,
The following corollary is gotten directly from Corollary 7.
Corollary 8**.**
Let Sn and Bn are the star graph and the bubble sort graph,
then tp(Sn)=2n−4=κ1(Sn) for n≥6, and tp(Bn)=2n−4=κ1(Bn) for n≥6.
4.7 Application to the Cayley graphs generated by 2-trees Γn(Δ)
Lemma 27**.**
Let Γn(Δ) be a Cayley graph generated by the 2-tree Δ.
For n≥4, let U be a subset of V(Γn(Δ)) and 2≤∣U∣≤8n−26.
Then, ∣NΓn(Δ)(U)∣≥4n−11.
Proof. The lemma is proved by the induction on n.
Since Γ4(Δ) is constructed by 4 disjoint triangles,
it is easy to verify that ∣NΓ4(Δ)(U)∣≥5 for 2≤∣U∣≤7.
By the inductive hypothesis, we assume that the lemma is true for Γm(Δ),
where m is an integer with 5≤m≤n−1.
Note that Γn(Δ) is constructed by n disjoint Γn−1(Δ),
denoted by Γni(Δ) for i∈[n].
Let Ui=U∩V(Γn−1i(Δ)) and
Γn−1i(Δ)=Γn(Δ)−Γn−1i(Δ) for i∈[n].
Without loss of generality, we may assume that ∣U1∣≥∣U2∣≥…≥∣Un∣.
The following three cases should be considered.
Case 1. ∣U1∣≤1.
In this case, ∣Ui∣≤1 for all i∈[n]. Clearly, 2≤∣U∣≤n because of i≤n.
The Lemma follows if ∣U∣=2 by Lemma 19.
Now assume that 3≤∣U∣≤n. Since Γn(Δ) is (2n−4)-regular and Γn−1i(Δ) is isomorphic to Γn−1(Δ),
∣NΓn(Δ)(U)∣≥3κ(Γn−1i(Δ))=3(2n−6)≥4n−11 for n≥5.
Case 2. 2≤∣U1∣≤8n−34.
By inductive hypothesis in Γn−11(Δ), ∣NΓn−11(Δ)(U1)∣≥4(n−1)−11=4n−15.
If U=U1, ∣NΓn(Δ)(U)∣=∣NΓn−11(Δ)(U1)∣+∣NΓn−11(Δ)(U1)∣≥4n−15+2∣U1∣≥4n−11.
Assume U=U1 in the following.
If ∣U2∣=1, ∣NΓn−12(Δ)(U2)∣=κ(Γn−12(Δ))=2n−6.
Note that Γn−11(Δ) and Γn−12(Δ) are vertex disjoint,
∣NΓn(Δ)(U)∣≥∣NΓn−11(Δ)(U1)∣+∣NΓn−12(Δ)(U2)∣≥4n−15+(2n−6)≥6n−21 for n≥5.
Now consider 2≤∣U2∣≤∣U1∣≤8n−34,
by inductive hypothesis in Γn−12(Δ), ∣NΓn−12(Δ)(U2)∣≥4(n−1)−11=4n−15.
Thus, ∣NΓn(Δ)(U)∣≥∣NΓn−11(Δ)(U1)∣+∣NΓn−12(Δ)(U2)∣≥8n−30≥4n−11 for n≥5.
Case 3. 8n−33≤∣U1∣≤8n−26.
By Lemma 14, ∣NΓn−11(Δ)(U1)∣=2∣U1∣.
It is clear that the lemma holds if U=U1.
In the following, we assume the case of U=U1.
Since the connectivity of Γn−11(Δ) is 2n−6, and
by Lemma 21,
∣NΓn−11(Δ)(U1)∣≥2n−6.
Note that U=U1 and ∣U−U1∣≤7, so 1≤∣U2∣≤7.
If ∣U2∣=1, ∣NΓn(Δ)(U)∣≥∣NΓn−11(Δ)(U1)∣+∣NΓn−11(Δ)(U1)∣−∣U−U1∣≥(2n−6)+2∣U1∣−7≥18n−79≥4n−11 for n≥5.
Now suppose that 2≤∣U2∣≤7.
Since 7≤8n−32 for n≥5, by inductive hypothesis in Γn−12(Δ),
∣NΓn−12(Δ)(U2)∣≥4(n−1)−11=4n−15.
Thus, ∣NΓn(Δ)(U)∣≥∣NΓn−11(Δ)(U1)∣+∣NΓn−12(Δ)(U2)∣≥(2n−6)+(4n−15)=6n−21≥2n−5 for n≥5.
By the above cases, the lemma holds. ∎
Corollary 9**.**
Let G=Γn(Δ) be a Cayley graph generated by the 2-tree Δ for n≥5.
Then κ1(G)=4n−11=tp(G).
Proof. Note that k=2n−4≥5 and 2n!≥4(2n−4)−2 for n≥5, Condition (1) in Theorem 1 holds.
By Lemma 14 and 27, Condition (2) and (3) in Theorem 1 holds.
Condition (4) holds by ∣F∣≤2k−3−l=2(2n−4)−3−1=4n−12<4n−11 and Lemma 16.
Thus, Γn(Δ) satisfies all conditions in Theorem 1, and so
tp(Γn(Δ))=4n−11=κ1(Γn(Δ)) for n≥5. ∎
4.8 Application to the burnt pancake networks BPn
Lemma 28**.**
Let BPn be the n-dimensional burnt pancake network.
For n≥3, let U be a subset of V(BPn) and 2≤∣U∣≤4n−8, then ∣NBPn(U)∣≥2n−2.
Proof. If ∣U∣=2, by Lemma 17 and Lemma 19,
for any two distinct vertices u and v, so ∣NBPn(U)∣≥2n−2.
Recall that BPn can be decomposed into 2n copies of BPn−1’s, namely BPn−1i, for i∈⟨n⟩.
Let Ui=U∩V(BPn−1i) and BPn−1i=BPn−BPn−1i for i∈⟨n⟩.
Without loss of generality, we may assume that ∣U1∣≥∣U2∣≥∣U3∣≥…≥∣Un∣≥∣Unˉ∣≥∣Un−1∣≥∣U1ˉ∣.
The lemma is proved by using the induction on n.
If n=3, it is easy to check ∣NBPn(U)∣≥4 for 2≤∣U∣≤4n−8=4.
We assume that the lemma is true for BPm, where m is an integer with 4≤m≤n−1. We consider BPn for n≥4 as follows.
Case 1. ∣U1∣≤1.
In this case, ∣Ui∣≤1 for all 1≤i≤n. Since ∣U∣≥2, it implies that ∣U1∣=∣U2∣=1.
Since BPn is n-regular and BPn−1i is isomorphic to BPn−1, ∣NBPn(U)∣≥2κ(BPn−1i)=2(n−1)=2n−2 for n≥4.
Case 2. 2≤∣U1∣≤4n−12.
By inductive hypothesis in BPn−11, ∣NBPn−11(U1)∣≥2(n−1)−2=2n−4.
Note that ∣Ui∣≤∣U1∣≤4n−12 for i∈[n]∖{1}.
If U=U1, ∣NBPn(U)∣=∣NBPn−11(U1)∣+∣NBPn−11(U1)∣≥4n−12+∣U1∣≥4n−11.
Assume U=U1 in the following.
If ∣U2∣=1, ∣NBPn−12(U2)∣≥κ(BPn−12)=n−1,
so ∣NBPn(U)∣≥∣NBPn−11(U1)∣+∣NBPn−12(U2)∣≥(2n−4)+(n−1)=3n−5≥2n−2 for n≥4.
If 2≤∣U2∣≤4n−12, by inductive hypothesis in BPn−12, ∣NBPn−12(U2)∣≥2(n−1)−2=2n−4.
Thus, ∣NBPn(U)∣≥∣NBPn−11(U1)∣+∣NBPn−12(U2)∣≥2(2n−4)=4n−8≥2n−2 for n≥4.
Case 3. 4n−11≤∣U1∣≤4n−8.
Since (n−1)!−(4n−8)≥n−1 for n≥5, by Lemma 21,
∣NBPn−11(U1)∣≥κ(BPn−11)=n−1.
If U=U1, by Lemma 17, ∣NBPn−11(U1)∣=∣U1∣≥4n−11. Thus,
∣NBPn(U)∣=∣NBPn−11(U1)∣+∣NBPn−11(U1)∣≥4n−11+(n−1)=5n−2≥2n−2
for n≥4. In the following, we assume that U=U1.
It implies that ∣U−U1∣≤3, so 1≤∣U2∣≤∣U∣−∣U1∣≤3.
If ∣U2∣=1, ∣NBPn−12(U2)∣=κ(BPn−12)=n−1. Recall that ∣NBPn−11(U1)∣≥n−1.
Hence, ∣NBPn(U)∣≥∣NBPn−11(U1)∣+∣NBPn−12(U2)∣≥2n−2 for n≥4.
Now suppose that 2≤∣U2∣≤3. Since ∣U2∣≤3≤4n−12 for n≥4, by inductive hypothesis in BPn−12, ∣NBPn−12(U2)∣≥2(n−1)−2=2n−4.
Thus, ∣NBPn(U)∣≥∣NBPn−11(U1)∣+∣NBPn−12(U2)∣≥(n−1)+(2n−4)=3n−5≥2n−2 for n≥4.
By the above cases, the proof is completed. ∎
Remark 3**.**
The extra connectivity of BPn was obtained by Song et al. [35], κ1(BPn)=2n−2 for n≥4.
But tp(BPn) is not known so far. By Theorem 1, we immediately the following result which contains the above result.
Corollary 10**.**
Let BPn be the n-dimensional burnt pancake network for n≥5. Then
tp(BPn)=2n−2=κ1(BPn).
Proof. Note that k=n≥5 and N=∣V(BPn)∣=n!≥4n−2 for n≥5, Condition (1) in Theorem 1 holds.
By Lemmas 17 and 28, Conditions (2) and (3) in Theorem 1 hold.
Condition (4) holds by Lemma 18.
BPn satisfies all conditions in Theorem 1, and so
tp(BPn)=2n−2=κ1(BPn) for n≥5. ∎
5 Concluding remarks
This paper establishes the close relationship between these two parameter:
the extra connectivity and pessimistic diagnosability under the PMC model, by
proving tp(G)=κ1(G) for some regular graphs G with some conditions.
As applications, the pessimistic
diagnosability for each of split-star networks Sn2, Cayley graphs generated by transposition trees Γn, Cayley graph generated by the 2-tree Γn(Δ) and the burnt pancake networks BPn is gotten.
As corollaries, the known results about the extra connectivity and the pessimistic diagnosability of many famous networks including the alternating group graphs [33], [37], the alternating group networks [45] , BC networks [47], [19] and the k-ary n-cube networks [15], [13], [30], [41] are obtained directly.
Acknowledgments
This work was supported by the National Natural Science Foundation of China (No.11371052, No.11271012 and No.11171020).
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