Radial length, radial John disks and $K$-quasiconformal harmonic mappings
Shaolin Chen, Saminathan Ponnusamy

TL;DR
This paper studies the boundary behavior of $K$-quasiconformal harmonic mappings, providing growth theorems, characterizations of radial John disks, and analyzing distortion and continuity properties.
Contribution
It offers new sharp growth results, an alternative characterization of radial John disks, and insights into distortion and differential properties of these mappings.
Findings
Established a sharp growth theorem for radial length of $K$-quasiconformal harmonic mappings.
Provided an alternative characterization of radial John disks.
Analyzed linear measure distortion and Lipschitz continuity of these mappings.
Abstract
In this article, we continue our investigations of the boundary behavior of harmonic mappings. We first discuss the classical problem on the growth of radial length and obtain a sharp growth theorem of the radial length of -quasiconformal harmonic mappings. Then we present an alternate characterization of radial John disks. In addition, we investigate the linear measure distortion and the Lipschitz continuity on -quasiconformal harmonic mappings of the unit disk onto a radial John disk. Finally, using Pommerenke interior domains, we characterize certain differential properties of -quasiconformal harmonic mappings.
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Taxonomy
TopicsAnalytic and geometric function theory · Pelvic and Acetabular Injuries · Nonlinear Partial Differential Equations
††footnotetext: File: Ch-P-Kqc-2016_final.tex, printed: 19-3-2024, 22.41
Radial length, radial John disks and -quasiconformal harmonic
mappings
Shaolin Chen
S. L. Chen, College of Mathematics and Statistics, Hengyang Normal University, Hengyang, Hunan 421008, People’s Republic of China.
and
Saminathan Ponnusamy
S. Ponnusamy, Indian Statistical Institute (ISI), Chennai Centre, SETS (Society for Electronic Transactions and Security), MGR Knowledge City, CIT Campus, Taramani, Chennai 600 113, India.
[email protected], [email protected]
Abstract.
In this article, we continue our investigations of the boundary behavior of harmonic mappings. We first discuss the classical problem on the growth of radial length and obtain a sharp growth theorem of the radial length of -quasiconformal harmonic mappings. Then we present an alternate characterization of radial John disks. In addition, we investigate the linear measure distortion and the Lipschitz continuity on -quasiconformal harmonic mappings of the unit disk onto a radial John disk. Finally, using Pommerenke interior domains, we characterize certain differential properties of -quasiconformal harmonic mappings
Key words and phrases:
-quasiconformal harmonic mapping, radial John disk, radial length, Pommerenke interior domain.
This second author is on leave from IIT Madras.
2010 Mathematics Subject Classification:
Primary: 30C62, 30C75; Secondary: 30C20, 30C25, 30C45, 30F45, 30H10
1. Introduction and statement of main results
This paper continues the study of previous work of the authors [6] and is mainly motivated by the articles of Beardon and Carne [3], Carroll and Twomey [4], Chuaqui et al. [10], Pommerenke [29], and the monograph of Pommerenke [30]. In order to state our first result concerning the growth of the radial length of -quasiconformal harmonic mappings (see Theorem 1), we need to recall some basic definitions and some results which motivate the present work.
Let be a complex-valued and continuously differentiable function defined in the unit disk and let be the length of the -image (with counting multiplicity) of the radial line segment from [math] to , where is fixed and . Then (cf. [5])
[TABLE]
In [21], Keogh showed that if is a bounded, analytic and univalent function in , then, for each ,
[TABLE]
Throughout the discussion, we let
[TABLE]
Keogh also gave some examples to show that the exponent in (1.1) can not be decreased. Jenkins improved on these examples in [16], and Kennedy [20] presented further examples by showing that
[TABLE]
is false in general for every positive function in satisfying as . In [4], Carroll and Twomey established certain refinements and extension of these results without the boundedness condition in the following form.
Theorem A. * Suppose that is univalent in . Then, for any fixed , there is a constant such that*
[TABLE]
*If, further, as then (1.1) holds. *
Later, Beardon and Carne [3] gave a relatively simple argument to Theorem in hyperbolic geometry and provided with further examples. It is worth pointing out here two results which strengthened (1.3) and was inspired by the work of Sheil-Small [33] and Hall [14]. If is starlike, i.e. contains the line segment whenever it contains , then (see [19])
[TABLE]
and the inequality of course is not sharp for all , but the bound sharp as the Koebe function shows and is attained when approaches (see [14, 33]). Later in 1993, Balasubramanian et al. [1] showed that if is convex, i.e. is a convex domain, then
[TABLE]
and the inequality is sharp as the convex function shows. Note that is increasing on and and thus, the conjecture of Hall [15] was settled (see also [2]).
The first aims of this paper is to extend Theorem for the case of harmonic quasiconformal mappings (see Theorem 1 below). We need some preparation to state this result.
For a real matrix , we use the matrix norm and the matrix function . For , the formal derivative of the complex-valued function is given by the Jacobian matrix
[TABLE]
so that
[TABLE]
where f_{z}=(1/2)\big{(}f_{x}-if_{y}\big{)} and f_{\overline{z}}=(1/2)\big{(}f_{x}+if_{y}\big{)}. Let be a domain in , with non-empty boundary. A sense-preserving homeomorphism from a domain onto , contained in the Sobolev class , is said to be a -quasiconformal mapping if, for ,
[TABLE]
where and is the determinant of (cf. [18, 22, 35, 36]).
Let denote the family of sense-preserving planar harmonic univalent mappings in , with the normalization and . Recall that is sense-preserving if the Jacobian of given by
[TABLE]
is positive. Thus, is locally univalent and sense-preserving in if and only if in ; or equivalently if in and the dilatation has the property that in (see [11, 12, 23]). The family together with a few other geometric subclasses, originally investigated in detail by [11, 34], became instrumental in the study of univalent harmonic mappings (see [12, 31]) and has attracted the attention of many function theorists. If the co-analytic part is identically zero in the decomposition of , then the class reduces to the classical family of all normalized analytic univalent functions in . If , then the family is both normal and compact. See [11] and also [8, 6, 12, 31].
Theorem 1**.**
For , let be a -quasiconformal harmonic mapping. Then, for any fixed , there is a constant such that
[TABLE]
If, further, as then
[TABLE]
and the exponent in defined by (1.2) cannot be replaced by a smaller number.
First we remark that if , then Theorem 1 coincides with Theorem . Secondly, the proof of Theorem 1 is substantially harder than the proof of Theorem . This is because Beardon and Carne’s argument of Theorem in [3] is not applicable in the proof of Theorem 1.
We need further notation and terminology before stating our second result. Let be the Euclidean distance from to the boundary of . If , then we set .
Definition 1**.**
A bounded simply connected plane domain is called a -John disk for with John center if for each there is a rectifiable arc , called a John curve, in with end points and such that
[TABLE]
for all on , where is the subarc of between and , and is the Euclidean length of (see [6, 13, 17, 28, 30]).
Remark 1**.**
If is a complex-valued and univalent mapping in , and, for , in Definition 1, then we call -John disk a radial -John disk, where and . In particular, if is a conformal mapping, then we call -John disk a hyperbolic -John disk. It is well known that any point can be chosen as a John center by modifying the constant if necessary. When we do not wish to emphasize the role of , then we regard the -John disk simply as a John disk in the natural way (cf. [6, 13, 17, 28]).
Unless otherwise stated, throughout the discussion we consider the following terminology. Denote by if and is a -quasiconformal harmonic mapping in , where . Also, we denote by if and maps onto . We prove several results mainly when equals one of , , and , and equals either radial John disk or Pommerenke interior domain.
Further, for we define
[TABLE]
In the following, we continue our previous work of [6], and give an another characterization of the radial John disk.
Theorem 2**.**
Let . Then the following are equivalent:
- (i)
* is a radial John disk.* 2. (ii)
There is an such that
[TABLE] 3. (iii)
**
Next, we establish the linear measure distortion on -quasiconformal harmonic mappings of onto a radial John disk.
Theorem 3**.**
Let , where is a radial John disk. Then, for with , there is a positive constant such that
[TABLE]
where and is defined by (1.4).
We remark that , but the sharp value of is still unknown (see [6, 9, 12, 34]). We discuss the Lipschitz continuity on -quasiconformal harmonic mappings of onto a radial John disk, which is as follows.
Theorem 4**.**
Let , where is a radial John disk. Then, for with and , there are constants and such that
[TABLE]
Let , where is domain. For , let and denote the boundary of . Now, for , let be the smaller subarc of between and , and let
[TABLE]
where runs through all arcs from to that lie in except for their endpoints. If
[TABLE]
then we call a Pommerenke interior domain (cf. [6, 29]). In particular, if is bounded, then we call as a bounded Pommerenke interior domain.
Given a sense-preserving harmonic mapping in , fix and perform a disk automorphism (also called Koebe transform of ) to obtain
[TABLE]
A calculation gives,
[TABLE]
Now, we consider the class of all harmonic mappings satisfying
[TABLE]
This inequality obviously holds if and is not the Koebe function , . Note that for the Koebe function the supremum turns out to be . Our next two results are extension of [29, Theorem 3].
Theorem 5**.**
Let , where is a bounded Pommerenke interior domain. If there are positive constants and such that, for each and for
[TABLE]
then
[TABLE]
We remark that if , then Theorem 5 coincides with [29, Theorem 3].
By using similar reasoning as in the proof of Theorem 5, one can easily get the following result which replaces the assumption by a more general condition and thus, we omit its proof.
Theorem 6**.**
Let , where is a bounded Pommerenke interior domain. If there are constants , , and such that, for each and for
[TABLE]
then
[TABLE]
Also, the following result easily follows from Theorem 5 and [6, Theorem 1].
Corollary 1**.**
For , let be a -quasiconformal harmonic mapping from onto a bounded Pommerenke interior domain . If is a radial John disk, then
[TABLE]
The proofs of Theorems 1-5 will be presented in Section 2.
2. The proofs of the main results
Let stand for the hyperbolic distance (or Poincaré distance) on the unit disk . We have
[TABLE]
where the infimum is taken over all smooth curves in connecting and (cf. [30]). In [34], Sheil-Small proved that if , then
[TABLE]
and
[TABLE]
Unless otherwise stated, the number will be used throughout the discussion and is indeed called the order of the linear invariant family (see [34]).
Lemma 1**.**
Suppose that . Then, for ,
[TABLE]
In particular,
[TABLE]
Proof. By assumption is a -quasiconformal harmonic mapping, where and are analytic in . Thus, by (2.1), we have
[TABLE]
and thus, for we obtain
[TABLE]
On the other hand, let be the preimage under of the radial segment from [math] to . Again, because
[TABLE]
it follows that
[TABLE]
Let so that , where Then, by assumption,
[TABLE]
and is a -quasiconformal harmonic mapping, i.e. . Applying (2.4) and (2.5) to gives us the desired result if we take into account of the fact that
[TABLE]
The proof of the lemma is complete. ∎
Lemma 2**.**
Assume that . Then
[TABLE]
where
[TABLE]
Proof. Suppose that , where and are analytic in . Next, for fixed , consider the Koebe transform of given by (1.6). By assumption, and is also a -quasiconformal harmonic mapping. By letting in (1.6) and applying (2.2) to , we obtain (since )
[TABLE]
which gives
[TABLE]
Since this follows for each , by the first inequality in (2.3), we easily have
[TABLE]
where is given by (2.6). ∎
Lemma 3**.**
Let and, for any fixed , set
[TABLE]
where . Then, for and , there is a constant which depends only on such that
[TABLE]
where is a constant.
Proof. Without loss of generality, we assume that Clearly, (2.2) yields that
[TABLE]
which implies that is bounded in , where is a constant such that . Hence there is a constant such that
[TABLE]
where . For , let
[TABLE]
Then is increasing in , which, together with (2.2), yields that
[TABLE]
where . Therefore, (2.7) follows from (2.8) and (2.9). ∎
Lemma 4**.**
For , let be the Stolz-type domain consisting of the interior of the convex hull of the point and the disk . Then, for
[TABLE]
Proof. Assume without loss of generality that Let , , and represent the points , , and (see Figure 1), respectively.
As , it is clear that
[TABLE]
Then, because for , it follows that for
[TABLE]
Note that and, because
[TABLE]
the last above relation clearly implies that
[TABLE]
which gives the desired conclusion. Observe that is less than from which we also deduce that . ∎
Proof of Theorem 1
Assume without loss of generality that . For , we use to denote the Stolz-type domain, where is same as in Lemma 4. Let . Then, by Lemma 4, there is a constant which depends only on such that
[TABLE]
Suppose that . By calculations, we get
[TABLE]
Taking real part of (2.11) on both sides, and then using (2.10), (2.11) and Lemma 2, we see that there is a constant such that
[TABLE]
which gives that
[TABLE]
By (2.2), we see that (2.12) also holds for . Then, by (2.12), there is constant such that is contained in , which yields that
[TABLE]
where and is defined as in Lemma 3.
By [24, Theorem 2], there is a constant such that
[TABLE]
where is analytic in . For , let for . Then, by (2.14), we obtain
[TABLE]
which implies that
[TABLE]
where is a constant.
By Lemmas 2 and 3, for and , there is a constant such that
[TABLE]
Writing and then, applying (2.15) and (2.16), it follows that
[TABLE]
Therefore, by (2.17), we conclude that
[TABLE]
Now we prove the sharpness part. For any , by [16, 21], there is a function such that,
[TABLE]
where is a positive constant. Finally, consider
[TABLE]
and observe that and is a -quasiconformal harmonic mapping. Consequently,
[TABLE]
which, together with (2.18), implies that
[TABLE]
The proof of this theorem is complete.
Lemma 5**.**
Let . Then, for and ,
[TABLE]
Proof. Let , where and are analytic in . For every , consider the affine mapping
[TABLE]
Clearly, . For a fixed , we consider the Koebe transform of as given by (1.6). Then we can write which again belongs to and obviously,
[TABLE]
Since we see that
[TABLE]
where . Integration leads to
[TABLE]
which gives
[TABLE]
and the desired inequality (2.19) follows from this and the arbitrariness of . ∎
We remark that Mateljević [26] (see also [27, 25]) proved the following lemma for instead of . That is, the normalization condition on , namely, , is not necessary.
Lemma 6**.**
If and , then
[TABLE]
Proof. Let , where and are analytic in . Then the affine mapping defined by
[TABLE]
belongs to . By [11, Theorem 4.4], we have
[TABLE]
Recall again, for any fixed the Koebe transform of given by (1.6) belongs to and is again a -quasiconformal harmonic mapping. As a result, (2.21) applied to shows that
[TABLE]
which implies that
[TABLE]
The proof of this Lemma is complete. ∎
Lemma B. ([6, Lemma 2])* Let and be positive constants and let , where . If , and , then*
[TABLE]
*where *
Proof of Theorem 2
Let . First we show that . We assume that
[TABLE]
uniformly on and . Define and for , by
[TABLE]
Note that and thus, . Consequently, by (2.22), we have
[TABLE]
Let such that
[TABLE]
Then, for , by (2.23),
[TABLE]
By calculations, for ,
[TABLE]
which, together with (2.24) and Lemma 5, yields that there is a constant such that
[TABLE]
Hence, by (2.25) and [6, Theorem 1], we conclude that is a radial John disk.
. Suppose that is a radial John disk. Then, by [6, Theorem 1], there are constants and such that, for each and for
[TABLE]
It is not difficult to see that by taking sufficiently close to 1.
Next we show that . For and , by [6, Theorem 1] and Lemma , we see that there are positive constants , and such that
[TABLE]
which gives that
[TABLE]
where is the smaller subarc of between and .
Finally, we prove . For and , there is a positive constant such that
[TABLE]
which implies that
[TABLE]
By (2.26) and [6, Theorem 2], we conclude that is a radial John disk. The proof of this theorem is complete.
Proof of Theorem 3
Let , where is a radial John disk. Assume that and with , where Since is a radial John disk , by [6, Theorem 1], we see that there are constants and such that for each and for
[TABLE]
Then, by (2.27) and Lemma , there is a positive constant such that
[TABLE]
where
[TABLE]
where is the smaller subarc of between and . Combining the last two inequalities shows that
[TABLE]
Hence there is a constant such that
[TABLE]
Moreover, by Lemmas 6 and , we see that there is a constant such that
[TABLE]
By (2.28), (2.29) and Lemma 5, we conclude that
[TABLE]
and the proof of the theorem is complete.
Lemma 7**.**
For , suppose that . Let and be positive constants and let , where . Suppose further that and . Then
[TABLE]
where is defined in Lemma .
Proof. Follows from [6, Lemma 2], but for the sake of completeness, we include certain details.
Let and line in the line with (see Figure 2). Clearly the distance from to is less than .
Then the length of the circular arc from to is less than . As in [6, Lemma 2], it is easy to see that
[TABLE]
The desired conclusion follows if we use Lemma 1. ∎
The following result is an easy consequence of Lemmas 6 and 7.
Corollary 2**.**
Under the hypotheses of Lemma 7, we also have
[TABLE]
where is defined in Lemma .
Proof of Theorem 4
Let , and () with .
If , then
[TABLE]
which, together with [6, Theorem 2], Lemmas 6 and 7, imply that there are positive constants , , , , and such that
[TABLE]
where is the smaller subarc of between and , and
[TABLE]
If , then, by Lemma 7, there are positive constants and such that
[TABLE]
where . We see that there are positive constants and such that
[TABLE]
If , then, by [6, Theorem 2], we conclude that there are constants and such that
[TABLE]
The proof of this theorem is complete.
The following result is an improvement of [6, Lemma 3].
Lemma 8**.**
Let , where is a bounded domain. If there are constants and such that for each and for
[TABLE]
then, for , we have
[TABLE]
where
Proof. For , let with . For , by Lemma , we have
[TABLE]
where is the smaller subarc of between and , so that
[TABLE]
Therefore,
[TABLE]
Next, we have
[TABLE]
and, finally,
[TABLE]
Again, for , by (2.32), (2.33), (2.34) and the triangle inequality, we obtain
[TABLE]
which in turn implies that and the proof of the lemma is complete. ∎
For , the generalized Hardy space consists of all those functions such that is measurable, exists for all and , where
[TABLE]
and
[TABLE]
We refer to [7] for more details on .
Proof of Theorem 5
Let , where is a bounded Pommerenke interior domain. Then, by definition, (1.7) holds and thus (see for example, [29, Proof of Theorem 3]), there are constants and such that, for and ,
[TABLE]
For , by integrating both sides of (2.35), we have
[TABLE]
which, by (2.3), deduces that
[TABLE]
For , we choose a positive integer and with such that, for ,
[TABLE]
For let
[TABLE]
For and , let . Then, for ,
[TABLE]
By the assumption, we let
[TABLE]
where is given by (1.5). Then, by (1.8), (2.38) and [6, Theorem 4], Hence, for , by (1.8), (2.38), Lemma 8 and [6, Inequality (2.3)], there is a positive constant such that
[TABLE]
Let Since by (2.36) and (2.37), we see that
[TABLE]
where, by (2.39),
[TABLE]
and
[TABLE]
By (2.36), (2.40), (2.41) and the last inequality, we conclude that
[TABLE]
Thus,
[TABLE]
For and , by [6, Theorem 4], we have
[TABLE]
On the other hand, for ,
[TABLE]
In this case, Theorem 5 follows from the last two inequalities.
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