Arnold diffusion in arbitrary degrees of freedom and normally hyperbolic invariant cylinders
Patrick Bernard (DMA), K Kaloshin, K Zhang

TL;DR
This paper proves the existence of Arnold diffusion in nearly integrable Hamiltonian systems with arbitrary degrees of freedom, using geometric and variational methods to show orbits that traverse significant action space along resonances.
Contribution
It extends Arnold diffusion results to the a priori stable case with arbitrary degrees of freedom, employing new geometric and variational techniques.
Findings
Existence of diffusion orbits in a priori stable systems.
Diffusion occurs along co-dimension one resonances.
Finite set of additional resonances are the only obstructions.
Abstract
We prove a form of Arnold diffusion in the a priori stable case. Let H0(p) + H1(, p, t), T n , p B n , t T = R/T be a nearly integrable system of arbitrary degrees of freedom n 2 with a strictly convex H0. We show that for a "generic" H1, there exists an orbit (, p)(t) satisfying p(t) -- p(0) {\textgreater} l(H1) {\textgreater} 0, where l(H1) is independent of . The diffusion orbit travels along a co-dimension one resonance , and the only obstruction to our construction is a finite set of additional resonances. For the proof we use a combination geometric and variational methods, and manage to adapt tools which have recently been developed in the a priori unstable case.
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Arnold diffusion in arbitrary degrees of freedom
and normally hyperbolic invariant cylinders
P. Bernard111Université Paris-Dauphine (patrick.bernard ceremade.dauphine.fr), V. Kaloshin222University of Maryland at College Park (vadim.kaloshin gmail.com), K. Zhang333University of Toronto (kzhang math.utoronto.edu)
Abstract
We prove a form of Arnold diffusion in the a priori stable case. Let
[TABLE]
be a nearly integrable system of arbitrary degrees of freedom with a strictly convex . We show that for a “generic” , there exists an orbit satisfying
[TABLE]
where is independent of . The diffusion orbit travels along a co-dimension one resonance, and the only obstruction to our construction is a finite set of additional resonances.
For the proof we use a combination geometric and variational methods, and manage to adapt tools which have recently been developed in the a priori unstable case.
1 Introduction
On the phase space , we consider the Hamiltonian system generated by the time-periodic Hamiltonian
[TABLE]
where is the unit ball in around the origin, and is a small parameter. The equations
[TABLE]
imply that the momenta are constant in the case . A question of general interest in Hamiltonian dynamics is to understand the evolution of these momenta when is small (see e.g. [Ar1, Ar2, AKN]). In the present paper, we assume that is convex, and , more precisely,
[TABLE]
and prove that a certain form of Arnold’s diffusion occur for many perturbations. We assume that and denote by the unit sphere in .
Theorem 1**.**
There exist two continuous functions and on , which are positive on an open and dense set , and an open and dense subset of
[TABLE]
such that the following property holds for each Hamiltonian :
There exists an orbit of and a time such that
[TABLE]
The key point in this statement is that does not depend on . In section 1.1, we give a more detailed description of the diffusion path. Moreover, an improved version of the main theorem provides an explicit lower bound on (see Theorem 2.1 and Remark 2.1).
The present work is in large part inspired by the work of Mather [Ma3, Ma4, Ma5]. In [Ma3], Mather announced a much stronger version of Arnold diffusion for . Our set is what Mather called a cusp residual set. As in Mather’s work the instability phenomenon thus holds in an open dense subset of a cusp residual set. Our result is, however, quite different. We obtain a much more restricted form of instability, which holds for any . The restricted character of the diffusion comes from the fact that we do not really solve the problem of double resonance (but only finitely many, independent from , double resonances are really problematic). The proof of Mather’s result is partially written (see [Ma4]), and he has given lectures about some parts of the proof [Ma5]. 444 After a preliminary version of this paper was completed for the problem of double resonance was solved and existence of a strong form of Arnold diffusion is given in [KZ2].
The study of Arnold diffusion was initiated by the seminal paper of Arnold, [Ar1], where he describes a diffusion phenomenon on a specific example involving two independent perturbations. A lot of work has then been devoted to describe more general situations where similar constructions could be achieved. A unifying aspect of all these situations is the presence of a normally hyperbolic cylinder, as was understood in [Mo] and [DLS], see also [DGLS, DH, T1, T2, CY1, CY2, Be1]. These general classes of situations have been referred to as
- a priori unstable*.
The Hamiltonian studied here is, on the contrary, called a priori stable, because no hyperbolic structure is present in the unperturbed system . Our method will, however, rely on the existence of a normally hyperbolic invariant cylinder. The novelty here thus consists in proving that a priori unstable methods do apply in the a priori stable case. Application of normal forms to construct normally -dimensional hyperbolic invariant cylinders in a priori stable situation in degrees of freedom had already been discussed in [KZZ] and in [Mar]. The existence of normally hyperbolic cylinders with a length independent from in the a priori stable case, in arbitrary dimension, have been proved in [Be3], see also [Be5]. In the present paper, we obtain an explicit lower bound on the length of such a cylinder. The quantity in the statement of Theorem 1 is closely related to this lower bound (see also Remark 2.1). Let us mention some additional works of interest around the problem of Arnold’s diffusion [Be4, Be6, BB, BBB, Bs1, Bs2, Bo, BK, CL1, CL2, Cr, GR1, GR2, KS, KL1, KL2, KLS, LM, MS, Zha, Zhe, X] and many others.
1.1 Reduction to normal form
As is usual in the theory of instability, we build our unstable orbits around a resonance. A frequency is said resonant if there exists , , such that The set of such integral vectors forms a submodule of , and the dimension of this module (which is also the dimension of the vector subspace of it generates) is called the order, or the dimension of the resonant frequency .
In order to apply our proof, we have to consider a resonance of order or, equivalently, of codimension . For definiteness and simplicity, we choose once and for all to work with the resonance
[TABLE]
where
[TABLE]
Similarly, we use the notations
[TABLE]
which are the slow and fast variables associated to our resonance (see Section 2 for definitions). More precisely, we will be working around the manifold defined by the equation
[TABLE]
in the phase space. In view of (1), this equation defines a curve in , which can also be described parametrically as the graph of a function We will also use the notation .
We define the averaged perturbation corresponding to the resonance ,
[TABLE]
If the perturbation is expanded as
[TABLE]
then
[TABLE]
Our first generic assumption, which defines the set in Theorem 1 is on the shape of . We assume that there exists a subarc such that :
Hypothesis 1**.**
There exists a real number such that, for each , there exists such that the inequality
[TABLE]
holds for each .
1.2 Single maximum
This condition implies that for each the averaged perturbation has a unique non-degenerate maximum at . In Section 1.5 we relax this condition and allow bifurcations from one global maxima to a different one. The set of functions satisfying Hypothesis 1 on some arc is open and dense for each . As a consequence, the set of functions (the unit sphere in ) whose average satisfies Hypothesis 1 on some arc is open and dense in if .
The general principle of averaging theory is that the dynamics of is approximated by the dynamics of the averaged Hamiltonian in a neighborhood of . The applicability of this principle is limited by the presence of additional resonances, that is points such that the remaining frequency is rational. Although additional resonances are dense in , only finitely many of them, called punctures, are really problematic. More precisely, denoting by the -neighborhood of in and by the set of functions such that
[TABLE]
We will prove in section 2 that :
Proposition 1.1**.**
For each , there exists a locally finite subset and , such that :
For each compact arc disjoint from , each , and each , there exists a smooth canonical change of coordinates
[TABLE]
satisfying and such that, in the new coordinates, the Hamiltonian takes the form
[TABLE]
with .
The key aspects of this result is that the set is locally finite and independent from . Because it is essential to have these properties of , the conclusions on the smallness of are not very strong. Yet they are sufficient to obtain:
Theorem 1.2**.**
Let us consider the Hamiltonian
[TABLE]
and assume that and that () holds on some arc of the form
[TABLE]
Then there exist constants and , which depends only on , , and , and such that, for each , the following property holds for an open dense subset of functions (for the topology):
There exists an orbit and an integer such that and .
1.3 Derivation of Theorem 1 using Proposition 1.1 and Theorem 1.2
Given , we denote by the set of Hamiltonians with the following property: There exists an orbit and an integer such that . The set is clearly open.
We denote by the set of Hamiltonians with the following property: There exists an orbit and an integer such that . The set is clearly open.
We now prove the existence of a continuous function on which is positive on and such that each Hamiltonian with and belongs to the closure of .
For each , there exists a compact arc and a number such that the corresponding averaged perturbation satisfies Hypothesis 1 on with constant . We then consider the real given by Theorem 1.2 (applied with the parameter ). By possibly reducing the arc , we can assume in addition that this arc is disjoint from the set of punctures for this . The following properties then hold:
- •
The averaged perturbation satisfies Hypothesis 1 on with a constant .
- •
The parameter is associated to by Theorem 1.2.
- •
The arc is disjoint from the set of punctures.
We say that is a compatible set of data if they satisfy the second and third point above. Then, we denote by the set of which satisfy the first point. This is an open set, and we just proved that the union on all compatible sets of data of these open sets covers .
To each compatible set of data we associate the positive numbers , where are the extremities of , and , where is associated to by Proposition 1.1.
Using a partition of the unity, we can build a continuous function on which is positive on and have the following property: For each , there exists a compatible set of data such that and .
For this function , we claim that each Hamiltonian with and belongs to the closure of .
Assuming the claim, we finish the proof of Theorem 1. For , let us denote by the open set of Hamiltonians of the form , where satisfies and . The claim implies that is dense in for each . The conclusion of the Theorem (with ) then holds with the open set , which is open and dense in .
To prove the claim, we consider a Hamiltonian , with and . We take a compatible set of data such that and . We apply Proposition 1.1 to find a change of coordinates which transforms the Hamiltonian to a Hamiltonian in the normal form with . The change of coordinates is fixed for the sequel of this discussion, as well as . By Theorem 1.2, the Hamiltonian can be approximated in the norm by Hamiltonians admitting an orbit such that and for some . Let us denote by the expression in the original coordinates of . It can be made arbitrarily -close to by taking sufficiently close to . Since , the extended -orbit satisfies and , hence
[TABLE]
In other words, we have . We have proved that belongs to the closure of . This ends the proof of Theorem 1. ∎
The Hamiltonian in normal form has the typical structure of what is called an a priori unstable system under Hypothesis 1. Actually, under the additional assumption that , with sufficiently small with respect to , the conclusion of Theorem 1.2 would follow from the various works on the a priori unstable case, see [Be1, CY1, CY2, DLS, GR2, T1, T2]. The difficulty here is the weak hypothesis made on the smallness of , and, in particular, the fact that is allowed to be much smaller than .
1.4 Proof of Theorem 1.2
We give a proof based on several intermediate results that will be established in the further sections of the paper. The first step is to establish the existence of a normally hyperbolic cylinder. It is detailed in Section 3. As a consequence of the difficulties of our situation, we get only a rough control on this cylinder, as was already the case in [Be3]. Some norms might blow up when (see (4)).
The second step consists in building unstable orbits along this cylinder under additional generic assumptions. In the a priori unstable case, where a regular cylinder is present, several methods have been developed. Which of them can be extended to the present situation is unclear. Here we manage to extend the variational approach of [Be1, CY1, CY2] (which are based on Mather’s work). We use the framework of [Be1], but also essentially appeal to ideas from [Mag] and [CY2] for the proof of one of the key genericity results. A self-contained proof of the required genericity with many new ingredients is presented in Section 5.
The second step consists of three main steps:
- •
Along a resonance prove existence a normally hyperbolic cylinder and derive its properties (see Theorem 1.3).
- •
Show that this cylinlder contains a family of Mañé sets , each being of Aubry-Mather type, i.e. a Lipschitz graph over the circle (see Theorem 1.4).
- •
Using the notion of a forcing class [Be1] generically construct orbits diffusing along this cylinder (see Theorem 1.5).
1.4.1 Existence and properties of a normally
hyperbolic cylinder
Theorem 1.3**.**
Let us consider the Hamiltonian system (3) and assume that satisfies () on some arc of the form
[TABLE]
Then there exist constants , which depend only on , , and , and such that, for each in , the following property holds for each function :
There exists a map
[TABLE]
such that the cylinder
[TABLE]
is weakly invariant with respect to in the sense that the Hamiltonian vector field is tangent to . The cylinder is contained in the set
[TABLE]
and it contains all the full orbits of contained in . We have the estimate
[TABLE]
[TABLE]
A similar, weaker, result is proved in [Be3]. The present statement contains better quantitative estimates. It follows from Theorem 3.1 below, which makes these estimates even more explicit. The terms come from the fact that we only estimate on the -neighborhood of , see the definition of .
For convenience of notations we extend our system from to . It is more pleasant in many occasions to consider the time-one Hamiltonian flow and the discrete system that it generates on . We will thus consider the cylinder
[TABLE]
We will think of this cylinder as being -invariant, although this is not precisely true, due to the possibility that orbits may escape through the boundaries. If is large enough, it is possible to prove the existence of a really invariant cylinder closed by KAM invariant circles, but this is not useful here.
The presence of this normally hyperbolic invariant cylinder is another similarity with the a priori unstable case. The difference is that we only have rough control on the present cylinders, with some estimates blowing up when . As we will see, variational methods can still be used to build unstable orbits along the cylinder. We will use the variational mechanism of [Be1]. Variational methods for this problem were initiated by Mather, see [Ma2] in an abstract setting. In a quite different direction, they were also used by Bessi to study the Arnold’s example of [Ar1], see [Bs1].
1.4.2 Weak KAM and Mather theory
We will use standard notations of weak KAM and Mather theory, we recall here the most important ones for the convenience of the reader. We mostly use Fathi’s presentation in terms of weak KAM solutions, see [Fa], and also [Be1] for the non-autonomous case. We consider the Lagrangian function associated to (see Section 4 for the definition) and, for each , the function
[TABLE]
where the minimum is taken on the set of curves such that . It is a classical fact that this minimum exists, and that the minimizers is the projection of a Hamiltonian orbit. A (discrete) weak KAM solution at cohomology is a function such that
[TABLE]
where is the only real constant such that such a function exists. For each curve and each in we thus have the inequalities
[TABLE]
A curve is said calibrated by if
[TABLE]
for each in . The curve is then the projection of a Hamiltonian orbit , such an orbit is called a calibrated orbit. We denote by
[TABLE]
the union on all calibrated orbits of the sets , or equivalently of the sets . In other words, these are the initial conditions the orbits of which are calibrated by . By definition, the set is invariant under the time one Hamiltonian flow , it is moreover compact and not empty. We also denote by
[TABLE]
the suspension of , or in other words the set of points of the form for each and each calibrated orbit . The set is compact and invariant under the extended Hamiltonian flow. Note that . The projection
[TABLE]
of on is the union of points where is a calibrated curve. The projection
[TABLE]
of on is the union of points where and is a calibrated curve. It is an important result of Mather theory that is a Lipschitz graph above (hence is a Lipschitz graph above ). We finally define the Aubry and Mañé sets by
[TABLE]
where the union and the intersection are taken on the set of all weak KAM solutions at cohomology . When a clear distinction is needed, we will call the sets the suspended Aubry (and Mañé) sets. We denote by and the projections on , of and . Similarly, and are the projections on of and . The Aubry set is compact, non-empty and invariant under the time one flow. It is a Lipschitz graph above the projected Aubry set . The Mañé set is compact and invariant. Its orbits (under the time-one flow) either belong, or are bi-asymptotic, to .
In [Be1], an equivalence relation is introduced on the cohomology , called forcing relation. It will not be useful for the present exposition to recall the precise definition of this forcing relation. What is important is that, if and belong to the same forcing class, then there exists an orbit and an integer such that and . We will establish here that, in the presence of generic additional assumptions, the resonant arc is contained in a forcing class, which implies the conclusion of Theorem 1.2, but also the existence of various types of orbits, see [Be1], Section 5, for more details. To prove that is contained in a forcing class, it is enough to prove that each of its points is in the interior of its forcing class. This can be achieved using the mechanisms exposed in [Be1], called the Mather mechanism and the Arnold mechanism, under appropriate informations on the sets
[TABLE]
1.4.3 Localization and a graph theorem
The first step is to relate these sets to the normally hyperbolic cylinder as follows:
Theorem 1.4**.**
In the context of Theorem 1.3, we can assume by possibly reducing the constant that the following additional property holds for each function with :
For each , the Mañé set is contained in the cylinder . Moreover, the restriction of the coordinate map to is a Bi-Lipschitz homeomorphism for each Weak KAM solution at cohomology .
Proof.
The proof is based on estimates on Weak KAM solutions that will be established in Section 4. Let be as given by Theorem 1.3. Theorem 4.1 (which is stated and proved in Section 4) implies that the suspended Mañe set is contained in the set
[TABLE]
provided and (a constant depending on ). As a consequence, this inclusion holds for and , with . The suspended Mañé set is then contained in the domain called in the statement of Theorem 1.3. It is thus contained in , hence .
Let us consider a Weak KAM solution of at cohomology and prove the projection part of the statement. Let be two points in . By Theorem 4.2, we have
[TABLE]
Since the points belong to , the last estimate in Theorem 1.3 implies that
[TABLE]
We get
[TABLE]
If is small enough and , then
[TABLE]
hence
[TABLE]
thus
[TABLE]
∎
1.4.4 Structure of Aubry sets inside the cylinder and
existence of diffusing orbits
This last result, in conjunction with the theory of circle homeomorphisms, has strong consequences:
All the orbits of have the same rotation number , with . Since the sub-differential of the convex function is the rotation set of , we conclude that the function is differentiable at each point of , with .
When is rational, the Mather minimizing measures are supported on periodic orbits.
When is irrational, the invariant set is uniquely ergodic. As a consequence, there exists one and only one weak KAM solution (up to the addition of an additive constant), hence .
In the irrational case, we will have to consider homoclinic orbits. Such orbits can be dealt with by considering the two-fold covering
[TABLE]
The idea of using a covering to study homoclinic orbits comes from Fathi, see [Fa2]. This covering lifts to a symplectic covering
[TABLE]
and we define the lifted Hamiltonian . It is known, see [Fa2, CP, Be1] that
[TABLE]
where . On the other hand, the inclusion
[TABLE]
is not an equality. More precisely, in the present situation, the set is the union of two disjoint homeomorphic copies of the circle , and contains heteroclinic connections between these copies (which are the liftings of orbits homoclinic to ). More can be said if we are allowed to make a small perturbation to avoid degenerate situations. We recall that a metric space is called totally disconnected if its only connected subsets are its points. The hypothesis of total disconnectedness in the following statement can be seen as a weak form of transversality of the stable and unstable manifolds of the invariant circle .
Theorem 1.5**.**
In the context of Theorems 1.3 and 1.4, the following property holds for a dense subset of functions (for the topology): Each is in one of the following cases:
* for each weak KAM solution at cohomology .* 2. 2.
* is irrational, (hence, is an invariant circle), and is totally disconnected.*
The arc is then contained in a forcing class, hence the conclusion of Theorem 1.2 holds.
Proof.
By general results on Hamiltonian dynamics, the set of functions such that the flow map does not admit any non-trivial invariant circle of rational rotation number is -dense. This condition holds for example if is Kupka Smale (in the Hamiltonian sense, see [RR] for example).
Since the coordinate map is a homeomorphism in restriction to , this set is an invariant circle if . If , this implies that the rotation number is irrational. In other words, for , condition 1 can be violated only at points when is irrational, and then is an invariant circle.
When , it is possible to perturb away from in such a way that is totally disconnected for each value of such that is an invariant circle. This second perturbation procedure is not easy because there are uncountably many such values of . This is the result of Theorem 5.1. A result of this kind was obtained in [CY2], here we give a self-contained proof with many new ingredients, see Section 5.
We now explain, under the additional condition (1 or 2), how the variational mechanisms of [Be1] can be applied to prove that is contained in a forcing class. It is enough to prove that each point is in the interior of its forcing class. We treat separately the two cases.
In the first case, we can apply the Mather mechanism, see (0.11) in [Be1]. In that paper, the subspace , defined as the set of cohomology classes of closed one-forms whose support is disjoint from , is associated to each weak KAM solution at cohomology (in [Be1], the notation is used). In the present case, we know that the map restricted to is a bi-Lipschitz homeomorphism which is not onto. We conclude that . Since this holds for each weak KAM solution , we conclude that
[TABLE]
The result called Mather mechanism in [Be1] states that there is a small ball centered at [math] in such that the forcing class of contains . In the present situation, we conclude that is in the interior of its forcing class.
In the second case, we can apply the Arnold’s Mechanism, see Section 9 in [Be1]. We work with the Hamiltonian lifted to the two-fold cover. By Proposition (7.3) in [Be1], it is enough to prove that is in the interior of its forcing class for the lifted Hamiltonian ; this implies that is in the interior of its forcing class for .
The preimage \Xi^{-1}\big{(}\tilde{}\mathcal{N}_{N}(c)\big{)} is the union of two closed curves and . The set contains these two curves, as well as a set of heteroclinic connections from to , and a set of heteroclinic connections from to . Theorem (9.2) in [Be1] states that is in the interior of its forcing class provided and are totally disconnnected. Actually, the hypothesis is stated in [Be1] in a slightly different way, we explain in Appendix B that total disconnectedness actually implies the hypothesis of [Be1]. We conclude that each is in the interior of its forcing class. Since is connected, it is contained in a single forcing class. It is then a simple consequence of the definition of the forcing relation, see [Be1], Section 5, that the conclusion of Theorem 1.2 holds. This ends the proof of Theorem 1.2, using the results proved in the rest of the paper. ∎
1.5 Bifurcation points and a longer diffusion path
This section discusses some improvements on Theorems 1 and 1.2. There are two limitations to the size of the resonant arc to which the above construction can be applied.
The first limitation comes from the assumption that hypothesis () should hold on . Given a resonant arc , it is generic to satisfy this condition on a certain subarc , but it is not generic to satisfy () on the whole of . The presence of values of such that has two nondegenerate maxima can’t be excluded. In this section, we explain how a modification on the proof of Theorem 1.2 allows to get rid of this limitation.
The second limitation comes from the normal form theorem, and from the impossibility to incorporate a finite set of additional resonances (punctures) in the domain of our normal forms. This limitation is serious, and bypassing it would require a specific work around additional resonances which will not be discussed here. Some preprints on this issue appeared after the first version of the present works, see [C, KZ1, KZ2] (the latter ones being sequels to the present work, and the first one is independent). Here, the best we can achieve is to prove existence of diffusion orbits between two consecutive punctures. The number of punctures is independant from , it depends on the parameter in Theorem 1.2, which can be computed using the non-degeneracy parameter , see Remark 2.1.
In order to get rid of the first limitation, we consider a second hypothesis on :
Hypothesis 2**.**
There exists a real number and two points in such that the balls and are disjoint and such that, for each , there exists two local maxima and of the function in satisfying
[TABLE]
for each and each .
Given an arc , the following property is generic in :
The arc is a finite union of subarcs such that either Hypothesis 1 or Hypothesis 2 holds on each of these subarcs, with a common constant .
We have the following improvement on Theorem 1.2:
Proposition 1.6**.**
For the system (3), assume that there exists such that for each , either Hypothesis 1 or 2 hold for each . Then there exists , which depend only on , , and , and such that, for each , the following property holds for a dense subset of functions (for the topology):
There exists an orbit and an integer such that and .
Proof of Proposition 1.6.
We use the same framework as in the proof of Theorem 1.2, so it is enough to prove that each element of is in the interior of its forcing class.
Observe first that Theorem 3.1 can be applied to prove the existence of two invariant cylinders and in the extended phase space . Moreover, we can chose the parameter smaller than , in such a way that
[TABLE]
As earlier, we denote by and the intersections with the section . By Theorem 4.4, we have
[TABLE]
for each . Let us now introduce two smooth functions , , with the property that in , outside of , in and outside of
Considering the modified Hamiltonians will help the description of the Mather sets of . One can check by inspection in the proofs (using that does not depend on ) that Theorem 4.1 applies to , and allows to conclude that the Mañé set of is contained in . Let us denote by the function of . These objects are closely related to Mather’s local Aubry sets.
Lemma 1.1**.**
For each , are differentiable at , and Moreover,
- •
If , then ,
- •
If , then ,
- •
If , then .
Proof.
The functions are for the same reason as is in the one peak case.
Since , we have . On the other hand, we know that
[TABLE]
where the minimum is taken on the set of invariant measures . Since we know that , and since the maximizing measures are supported on the Aubry set, we conclude that each ergodic maximizing measure is supported either on or on . If the measure is supported in , then we have
[TABLE]
This proves the equality
As is explained in the proof of Theorem 4.4, there are two possibilities for the Mañé set : either it is contained in one of the , or it intersects both of them, and then also contains connections (because it is necessarily chain transitive).
If the Mañé set intersects , then the intersection is a compact invariant set, which thus support an invariant measure. This measure must be maximizing the functional , and thus also the functional . As a consequence, we must have . ∎
We can prove by the variational mechanisms of [Be1] that a point is in the interior of its forcing class in the following three cases:
First case, the Mañé set is contained in one of the cylinders , and it does not contain any invariant circle. Then the Mather mechanism applies as in the single peak case, and is contained in the interior of its forcing class.
Second case, the Mañé set is an invariant circle (then necessarily contained in one of the cylinders ), it is uniquely ergodic, and is totally disconnected. Then the Arnold’s mechanism applies as in the single peak case, and is contained in the interior of its forcing class.
Third case, the sets are both non-empty and uniquely ergodic, and \tilde{}\mathcal{N}(c)-\big{(}\tilde{}\mathcal{N}_{1}(c)\cup\tilde{}\mathcal{N}_{2}(c)\big{)} is totally disconnected. Then the Arnold’s mechanism applies directly (without taking a cover), and is contained in the interior of its forcing class.
Each is in one of these three cases provided the following set of additional conditions holds:
- •
The sets are uniquely ergodic.
- •
The equality has finitely many solutions on .
- •
The set \tilde{}\mathcal{N}(c)-\big{(}\tilde{}\mathcal{N}_{1}(c)\cup\tilde{}\mathcal{N}_{2}(c)\big{)} is totally disconnected (and not empty) when .
- •
The set is totally disconnected whenever is an invariant circle.
Let us now explain how these conditions can be imposed by a perturbation of .
We first consider a perturbation of such that, for each rational number , there exists a unique Mather minimizing measure of rotation number . Such a condition is known to be generic (because it concerns only countably many rotation numbers) see [Mn, CP, BC, Be7].
We then consider a perturbation of the form , with a small . It is easy to see that the functions associated to the Hamiltonian are
[TABLE]
where are the functions associated to . By Sard’s theorem, there exist arbitrarily small regular values of the difference . If is such a value, then [math] is a regular value of the difference , hence the equation has only finitely many solutions on . Note that the perturbation is locally constant around the cylinders , hence this second perturbation does not destroy the first property.
We then perform new perturbations supported away from , which preserve the first two properties. The third property is not hard to obtain since it now concerns only finitely many values of . The last property is obtained using arguments of Section 5.
We have proved that the Hamiltonian can be perturbed in such a way that each point of is in the interior of its forcing class. ∎
2 Normal forms
The goal of the present section is to prove Proposition 1.1 which allows to reduce Theorem 1 to Theorem 1.2. This reduction to the normal form does not use the convexity assumption. We put the initial Hamiltonian in normal form around a compact subarc of the resonance
[TABLE]
This global normal form is obtained by using mollifiers to glue local normal forms that depends on the arithmetic properties of the frequencies. This allows a simpler proof for instability, as we avoid the need to justify transitions between different local coordinates.
Recall that study a resonance of order or, equivalently, of codimension . The resonance of order is given by a lattice span by linearly independent vectors . Denote by and the slow angles and by the slow actions resp. Choose a complement angle so that form a basis.
For we have . We say that has an additional resonance if the remaining frequency is rational. In order to reduce the system to an appropriate normal form, we must remove some additional resonances. More precisely, we denote by the set of momenta such that
- •
, and
- •
for each satisfying .
The following result, which does not use the convexity of , is a refinement of Proposition 1.1:
Theorem 2.1**.**
[Normal Form] Let be a Hamiltonian. For each , there exist positive parameters such that, for each Hamiltonian with and each , there exists a smooth change of coordinates
[TABLE]
satisfying and and such that, in the new coordinates, the Hamiltonian takes the form
[TABLE]
with on . We can take , where is some constant depending only on and .
The proof actually builds a symplectic diffeomorphism of of the form
[TABLE]
and such that
[TABLE]
We have the estimates and .
Remark 2.1**.**
[Distance between punctures] On the interval, the distance between 2 adjacent rationals with denominator at most is . Choose as in Theorem 2.1, the distance between adjacent punctures is at least .
The length of is determined by the choice of , which can be chosen optimally in Theorem 1.3 and Theorem 4.1. Upon inspection of the proof, it is not difficult to determine that can be chosen to a power of , which shows the distance between punctures is polynomial in .
To prove Theorem 2.1 we proceed in steps. We first obtain a global normal form adapted to all resonances. We then show that this normal form takes the desired form on the domain However, the averaging procedure lowers smoothness, in particular, the technique requires the smoothness . To obtain a result that does not require this relation between and , we use a smooth approximation trick that goes back to Moser.
2.1 A global normal form adapted to all resonances.
We first state a result for autonomous systems. The time periodic version will come as a corollary. Consider the Hamiltonian , where (later, we will take ). Let be the unit ball in . Given any integer vector , let . To avoid zero denominators in some calculations, we make the unusual convention that . We fix once and for all a bump function be a such that
[TABLE]
and in between. For each and , we define the function , where is a parameter.
Theorem 2.2**.**
There exists a constant , which depends only on , such that the following holds. Given:
- •
A Hamiltonian ,
- •
A Hamiltonian with ,
- •
Parameters , , , , ,
satisfying
- •
,
- •
**
- •
,
there exists a symplectic diffeomorphism such that, in the new coordinates, the Hamiltonian takes the form
[TABLE]
with
- •
, here is the coefficient for the Fourier expansion of ,
- •
,
- •
* and *
If both and are smooth, then so is .
We now prove Theorem 2.2. To avoid cumbersome notations, we will denote by various different constants depending only on the dimension . We have the following basic estimates about the Fourier series of a function . Given a multi-index , we denote . Denote also .
Lemma 2.1**.**
For , we have
If , we have . 2. 2.
*Let be a series of functions such that the inequality holds for each multi-index with , for some . Then, we have *
. 3. 3.
Let . Then for , we have .
Proof.
- Let us assume that and take such that . Let and be two multi-indices such that . Finally, let , and let be the multi-index , where . We have
[TABLE]
hence
[TABLE]
Since , we conclude that
[TABLE]
- We have
[TABLE]
recall that .
- Using 1., we get
[TABLE]
∎
Proof of Theorem 2.2.
Let be the function that solves the cohomological equation
[TABLE]
where . Observing that when , we have the following explicit formula for :
[TABLE]
where each of the functions is extended by continuity at the points where the denominator vanishes. This function hence takes the value zero at these points. is well defined thanks to the smoothing terms we introduced, as whenever we also have and that term is considered non-present. Since as defined above is only , we will consider a smooth approximation
[TABLE]
where are smooth functions which are sufficiently close to in the norm.
Let be the Hamiltonian flow generated by . Setting , we have the standard computation
[TABLE]
from which follows that
[TABLE]
Let us estimate the norm of the function . It follows from Lemma 2.1 that
[TABLE]
We now focus on the term . To estimate the norm of , it is convenient to write , where . Notice that the coefficients of the Fourier expansion of is simply a constant times that of , Lemma 2.1 then implies that
[TABLE]
provided that , where we set .
We now have to estimate the norm of and . This requires additional estimates of the smoothing terms as well as the small denominators . We always assume that in the following estimates:
.
- -
on .
- -
and
We have been using the following estimates on the derivative of composition of functions: For and we have .
For each multi-index , we have that
[TABLE]
In these computations, we have used the hypothesis . Since , Lemma 2.1 implies (since ) :
We now turn our attention to :
.
- -
- -
, provided .
We obtain
[TABLE]
and
[TABLE]
Concerning the flow , we observe that , and get the following estimate (see e. g. [DH], Lemma 3.15):
- -
Finally, we obtain
[TABLE]
∎
2.2 Normal form away from additional resonances
We now return to our non-autonomous system and apply Theorem 2.2 around the resonance under study. To the non-autonomous Hamiltonian
[TABLE]
we associate the autonomous Hamiltonian
[TABLE]
where and . We denote the frequencies by , and define the set
[TABLE]
where we have denoted by the set of pairs of integers such that . Note that
[TABLE]
Corollary 2.2**.**
There exists a constant , which depends only on , such that the following holds. Given :
- •
A Hamiltonian ,
- •
A Hamiltonian with ,
- •
Parameters , , , , ,
satisfying
- •
,
- •
**
- •
,
there exists a symplectic diffeomorphism of such that, in the new coordinates, the Hamiltonian takes the form
[TABLE]
with
- •
* on ,*
- •
* and *
The symplectic diffeomorphism is of the form
[TABLE]
where is a diffeomorphism of fixing the last variable . The maps and are smooth if and are.
Proof.
We apply Theorem 2.2 with , and . We get a diffeomorphism of as time-one flow of the Hamiltonian . By inspection in the proof of Theorem 2.2, we observe that does not depend on , which implies that has the desired form. We have
[TABLE]
where and
[TABLE]
Let us compute this sum under the assumption that (or equivalently, that ). We have
[TABLE]
hence
[TABLE]
for such that . For the other terms, we have, by definition of ,
[TABLE]
hence
[TABLE]
and these terms vanish in the expansion of . We conclude that
[TABLE]
hence , with the notation of Lemma 2.1. Finally with . From Lemma 2.1, we see that
[TABLE]
On the other hand, , hence . ∎
2.3 Smooth approximation
We finally remove the restriction on and obtain a smooth change of coordinates. If , we use Lemma 2.3 below to approximate by an analytic function (with a parameter that will be specified later).
Lemma 2.3**.**
[SZ]** Let be a function, with . Then for each there exists an analytic function such that
[TABLE]
[TABLE]
for each , where is a constant which depends only on and .
In order to obtain a smooth change of variables, it is also convenient to approximate in by a smooth (using a standard mollification). We then apply Corollary 2.2 to the Hamiltonian
[TABLE]
with , with , and with some parameters and to be specified later. We find a smooth change of coordinates such that
[TABLE]
and , where and . As usual, we have denoted by and the automomized Hamiltonians and . With the same map , we obtain
[TABLE]
with
[TABLE]
In the expression above, the map is the trace on the variables of the map . Choosing , and assuming that we get
- -
- -
- -
- -
- -
.
and finally
[TABLE]
We now set
[TABLE]
and get . To apply Corollary 2.2 as we just did, we need the following conditions to hold on the parameters:
, which implies ,
- -
which implies ,
- -
which implies .
We apply the above discussion with and get Theorem 2.1. Note the estimate
[TABLE]
∎
3 Normally hyperbolic cylinders
In this section, we study the Hamiltonian
[TABLE]
In the above notations we denote by the solution of the equation . We recall also the notation from the introduction. We assume that , and that for some . To simplify notations, we will be using the notation, where means for a constant independent of , , , , , . We will not be keeping track of the parameter , which is considered fixed throughout the paper.
Given parameters
[TABLE]
we assume that for each there exists a local maximum of the map , and that is a function of . We assume in addition that
[TABLE]
for each , where as before is the identity matrix. We shall at some occasions lift the map to a map taking values in without changing its name.
Theorem 3.1**.**
The following conclusion holds if is a sufficiently small constant (how small does not depend on the parameters ): If the parameters , , , satisfy
[TABLE]
if , on the open set
[TABLE]
and if (7) holds for each , then there exists a map
[TABLE]
such that the cylinder
[TABLE]
*is weakly invariant with respect to in the sense that the Hamiltonian vector field is tangent to . The cylinder is contained in the set *
[TABLE]
and it contains all the full orbits of contained in . We have the estimates
[TABLE]
[TABLE]
[TABLE]
Notice that the domain is contained in the domain (8) where the assumption on is made.
*Proof of Theorem 1.3. * We derive Theorem 1.3 from Theorem 3.1 as follows. We assume that Hypothesis () holds on
[TABLE]
Then the inequality
[TABLE]
holds for . Since , the inequality
[TABLE]
holds for each in the -neighborhood of . The inequality
[TABLE]
implies that the function has a global maximum , which is contained in the ball , provided and is small enough. By a similar reasoning at , we extend the map to the interval in such a way that, for each in this interval, the point is a local (and even global) maximum of the function which satisfies the inequalities
[TABLE]
Taking a small , we set and . Assuming as in the statement of Theorem 1.3 that the estimate holds on , hence on
[TABLE]
and that , we apply Theorem 3.1 on the interval
[TABLE]
If (hence ) is small enough, then we have the inclusion
[TABLE]
∎
The proof of Theorem 3.1 occupies the rest of the section.
The Hamiltonian flow admits the following equation of motion :
[TABLE]
The Hamiltonian structure of the flow is not used in the following proof.
It is convenient in the sequel to lift the angular variables to real variables and to consider the above system as defined on We will see this system as a perturbation of the model system
[TABLE]
The graph of the map
[TABLE]
on is obviously invariant for the model flow. For each fixed , the point is a hyperbolic fixed point of the partial system
[TABLE]
where is seen as a parameter. This hyperbolicity is the key property we will use, through the theory of normally hyperbolic invariant manifolds. It is not obvious to apply this theory here because the model system itself depends on , and because we have to deal with the problem of non-invariant boundaries. We will however manage to apply the quantitative version exposed in Appendix A.
We perform some changes of coordinates in order to put the system in the framework of Appendix A. These coordinates appear naturally from the study of the model system as follows. We set
[TABLE]
If we fix the variable and consider the model system in , we observed that this system has a hyperbolic fixed point at . The linearized system at this point is
[TABLE]
To put this system under a simpler form, it is useful to consider the matrix
[TABLE]
which is symmetric, positive definite, and satisfies , as can be checked by a direct computation. We finally introduce the symmetric positive definite matrix
[TABLE]
In the new variables
[TABLE]
the linearized system is reduced to the following block-diagonal form:
[TABLE]
see [Be3] for more details. This leads us to introduce the following set of new coordinates for the full system:
[TABLE]
[TABLE]
[TABLE]
where is a parameter which will be taken later equal to . Note that
[TABLE]
Lemma 3.1**.**
We have for each .
Proof.
The matrix is symmetric, hence it satisfies , where is its smallest eigenvalue. The real number is then an eigenvalue of the matrix which is similar to Since both and are square matrices of equal size, we conclude that is an eigenvalue of . Since and , we have . We conclude that . ∎
The links between the various parameters , , , , which appear in the computations below will be specified later. We will however assume from the beginning that
[TABLE]
Let us first collect some estimates that will be useful to see that the system (9) is indeed a perturbation of the model system.
Lemma 3.2**.**
We have the estimates
[TABLE]
where .
Proof.
We recall that T=\big{(}B^{1/2}(B^{1/2}AB^{1/2})^{-1/2}B^{1/2}\big{)}^{1/2} and T^{-1}=\big{(}B^{-1/2}(B^{1/2}AB^{1/2})^{1/2}B^{-1/2}\big{)}^{1/2}. Since and , we obtain that and that . To estimate the derivative of , we consider the map defined on positive symmetric matrices. It is known that
[TABLE]
To verify this one can diagonalize , perform integration, and match terms in . This implies that
[TABLE]
As a consequence, if is a positive symetric matrix depending on , we have
[TABLE]
We apply this bound several times to estimate and . In our situation, we have , . Using and , we get and resp. Using we get , and then
[TABLE]
Recalling that
[TABLE]
we obtain (with )
[TABLE]
The other estimates are straightforward. ∎
Corollary 3.3**.**
Let be the image in the coordinates of the domain called in the statement. We have
[TABLE]
provided is small enough.
From now on, we work on the region
[TABLE]
In view of Lemma 3.2, this region is contained in the (image in the new coordinates of the) domain where the inequality was assumed.
Lemma 3.4**.**
The equations of motion in the new coordinates take the form
[TABLE]
where is assumed to satisfy . The expression for is not useful here.
Proof.
The last part of the statement is obvious. We prove the part concerning , the calculations for are exactly the same. In the original coordinates the vector field (9) can be written
[TABLE]
[TABLE]
As a consequence, we have
[TABLE]
We use the estimates of Lemma 3.2 to simplify (recall also that ):
[TABLE]
∎
Lemma 3.5**.**
In the new coordinate system , the linearized system is given by the matrix
[TABLE]
where .
Proof.
Most of the estimates below are based on Lemma 3.2. In the original coordinates, the matrix of the linearized system is:
[TABLE]
In our notations we have
[TABLE]
In the new coordinates, the matrix is the product
[TABLE]
We have
[TABLE]
hence
[TABLE]
This expression is the result of a tedious, but straightforward, computation. Let us just detail the computation of the coefficient on the first line, fourth row, which contains an important cancellation:
[TABLE]
We now write
[TABLE]
and compute that
[TABLE]
∎
In order to prove the existence of a normally hyperbolic invariant strip (for the lifted system), we apply Proposition A.4 to the system in coordinates . More precisely, with the notations of appendix A, we set: , and consider the domain
[TABLE]
We fix
[TABLE]
observe that , by Lemma 3.1. We assume, as in the statement of the Theorem, that and that . We apply Proposition A.4 with and under the constraint
[TABLE]
provided is small enough. Observe that, if is small enough, the inequalities
[TABLE]
holds under our assumptions on the parameters, hence values of satisfying (12) do exist. It is easy to check under our assumptions on the parameters that such values of exist. Let us check the isolating block condition under the condition (12). By Lemma 3.4, we have
[TABLE]
if . If in addition , then
[TABLE]
hence
[TABLE]
provided is small enough. Similarly, on provided is small enough. Concerning the linearized system, we have
[TABLE]
on . These inequalities holds when is small enough because and . Finally, still with the notations of Proposition A.4, we can take
[TABLE]
If is small enough, we have hence
[TABLE]
and Proposition A.4 can be applied. The invariant strip obtained from the proof of Proposition A.4 does not depend on the choice of , as long as (12) holds. It contains all the full orbits contained in
[TABLE]
where is the image in the new coordinates of the domain defined in the statement of Theorem 3.1 and where the last inclusion holds provided is small enough, as follows from Corollary 3.3. So our invariant strip contains all the full orbits contained in . On the other hand, we can take , and since
[TABLE]
(still for small enough, by Corollary 3.3), our invariant strip is contained in .
The possibility of taking now implies that the cylinder is actually contained in the domain where
[TABLE]
Moreover, with this choice of and using that , we can obtain an improved estimate of the Lipschitz constant (notation from the appendix):
[TABLE]
Observe finally that, since the system is -periodic in and -periodic in , so is the invariant strip given by Proposition A.4. We have obtained the existence of a map
[TABLE]
which is -Lipschitz, -periodic in and -periodic in , and the graph of which is tangent to the vector field. Our last task is to return to the original coordinates by setting
[TABLE]
All the estimates stated in Theorem 3.1 follow directly from these expressions, and from the fact that . This concludes the proof of Theorem 3.1. ∎
4 Localization and Mather’s projected graph theorem
We study the system in normal form of Theorem 1.2 from the point of view of Mather theory at a fixed cohomology such that (or in other words such that ). We assume that , and that on . We continue to assume (1), and, for simplicity, we assume that is large enough and small enough for the following inequality to also hold:
[TABLE]
Most of our statement depend on the shape of the function . We will most of the time assume that () holds at : There exists such that We will rewrite this inequality as
[TABLE]
with the notation . Later in section 4.4, we also consider the double peak case, which is not necessary for the proof of Theorem 1.2, but is very natural. Our first statement localizes the Mañé set.
Theorem 4.1**.**
In the single peak case (when () holds at ), if is small enough with respect to and is small enough with respect to , then the Mañé set at cohomology of the Hamiltonian satisfies
[TABLE]
This statement is proved in Section 4.2. Our second statement is a quantitative version of the celebrated Mather Lipschitz graph Theorem, it does not rely on any particular assumption on , besides :
Theorem 4.2**.**
For each Weak KAM solution of at cohomology , the set is contained in a -Lipshitz graph above .
This theorem is proved in Section 4.3. We will always assume in this section that is sufficiently small with respect to and , and that is sufficiently small with respect to and .
4.1 Some inequalities
We will denote by the Hamiltonian and by the associated Lagrangian function, which is defined by
[TABLE]
The function is then , and the maps
[TABLE]
are diffeomorphisms of , which are inverse of each other. The maximum in the definition of is reached at . Since , we have
[TABLE]
We will also denote by the Lagrangian associated to , or more explicitly . It satisfies
[TABLE]
Lemma 4.1**.**
For each , the image of the open set under the difféomorphism contains the set
[TABLE]
In particular, if is small enough, the image of contains .
Proof.
In view of the estimate , each of the applications sends the ball to a set which contains the ball ). Since , we conclude that the image contains . ∎
Lemma 4.2**.**
The estimates
[TABLE]
hold on .
Proof.
Note first that the estimates
[TABLE]
hold on the domain , which contains the image of under . Observing that which implies
[TABLE]
we deduce that on . The equality
[TABLE]
implies that on . ∎
Lemma 4.3**.**
We have the estimate
[TABLE]
if .
Proof.
On the domain , we have
[TABLE]
If , then by Lemma 4.1,
[TABLE]
and, by Lemma 4.1 applied with and
[TABLE]
∎
Let us now estimate the value of the Mather function of . We use the notation .
Lemma 4.4**.**
The value of the Mather function of satisfies
[TABLE]
The reason behind this inequality is that the value of the Hamiltonian is .
Proof.
On one hand, we have
[TABLE]
For the other inequality, we use that . We consider the Haar measure of the torus , where is any point maximizing . This measure is not necessarily invariant under the Lagrangian flow of , but it is invariant under the Lagrangian flow of (because ) hence it is closed, which means that for each smooth function . See [Ba, FS] (both inspired from [Mn]) for the notion of closed measures. Each closed measure has a rotation vector , and its action is not less than . Here, hence
[TABLE]
∎
Lemma 4.5**.**
If is small enough (with respect to and ), we have the estimates
[TABLE]
for each , where .
Proof.
It is a direct computation :
[TABLE]
[TABLE]
∎
It is useful to consider suspended weak KAM solutions. Recall that we defined Weak KAM solutions associated to a Lagrangian at cohomolgy as functions on such that, for each ,
[TABLE]
where the infimum is taken on the set of curves such that . We can similarly define suspended weak KAM solutions as functions such that
[TABLE]
for each real times , where the infimum is taken on the space of curves such that . There is a bijection between suspended weak KAM solution and genuine weak KAM solutions: Each suspended weak KAM solution restricts to a genuine weak KAM solution , and each genuine weak KAM solution is the restriction of a unique suspended weak KAM solution which can be defined by
[TABLE]
for each , where the infimum is taken on curves such that . We shall use the same notation for a weak KAM solution and the associated suspended weak KAM solution. Curves calibrated by the weak KAM solutions are also calibrated by the corresponding suspended weak KAM solution in the sense that
[TABLE]
for each time interval . Let us now estimate the oscillation of suspended weak KAM solutions. We consider a convex subset , meaning that it is the projection of a convex subset of , of diameter less than .
Lemma 4.6**.**
*Let be a suspended weak KAM solution of at cohomology .
Given two points , we have*
[TABLE]
where . We can take in particular , then and we conclude that .
Proof.
We have on . We take two points , or in the domain , and consider the curve
[TABLE]
where is a parameter to be fixed later, where and are representatives of the angular variables , and where is the component-wise integral part of . Note that and , hence
[TABLE]
This inequality holds for all , in particular, we can choose so that
[TABLE]
and obtain ∎
4.2 Localization of the invariant sets
We prove Theorem 4.1. It is enough to prove that the inclusion
[TABLE]
holds for each (suspended) weak KAM solution . We fix such a solution and prove the inclusion. The following preliminary localization, which does not use any assumption on the shape of , implies that the set is contained (when is small enough) in the domain where the assumption is made.
Lemma 4.7**.**
Let be an orbit calibrated by . If , then
[TABLE]
for each , where is a constant which depends on and . In particular,
[TABLE]
Proof.
We denote by various positive constants which depend on and . Since , we have . As a consequence, if . In view of Lemma 4.1, we thus have
[TABLE]
for each such that . Since is a calibrated curve, we have
[TABLE]
for each . In particular, by Lemma 4.6 we have . Therefore, there exists a time such that . Let be the time maximizing . We assume for definiteness that , and that for each (otherwise we reduce the interval). The equations of motion imply that on , hence , and using the above lower bound on
[TABLE]
which implies that . ∎
We now assume that or , equivalently, that and prove the horizontal part of Theorem 4.1, or more precisely that
[TABLE]
We consider the domain . On this domain, we have , hence, by Lemma 4.6, the oscillation of on satisfies
[TABLE]
For , we have
[TABLE]
by Lemma 4.5. Let be a curve calibrated by , and let be an excursion of outside of , meaning that for each , and that . We have the inequalities
[TABLE]
If the curve is not contained in on , then there exists a time interval such that on , , and . We then have hence
[TABLE]
which is a contradiction when is small enough with respect to and . We have proved (17). ∎
We can now prove a better vertical localization of the set than was obtained in Lemma 4.7. On the domain , we have . We deduce from Lemma 4.6 that
[TABLE]
for each curve calibrated by and each time interval . We can chose the time interval as a maximal excursion outside of . On , we have (by Lemma 4.1) hence
[TABLE]
We thus have
[TABLE]
hence (if is small enough). Since and , we conclude that on . This ends the proof of Theorem 4.1. ∎
4.3 The Lipschitz constant
We prove Theorem 4.2. We will work here with weak KAM solutions rather than suspended weak KAM solutions. We recall the concept of semi-concave function on . A function is called -semi-concave if the function
[TABLE]
is concave on , where is seen as a periodic function on . It is equivalent to require that, for each , there exists a linear form on such that the inequality
[TABLE]
holds for each . It is sufficient to check that, for each , there exists such that this inequality holds for . We will need the following regularity result of Fathi, see [Fa]:
Lemma 4.8**.**
Let and be -semiconcave functions, and let be the set of points where the sum is minimal. Then the functions and are differentiable at each point of , and the differential is -Lipshitz on .
The Weak KAM solutions of cohomology are the functions such that
[TABLE]
for each , where the minimum is taken on the set of curves satisfying the final condition .
Proposition 4.3**.**
For each , each Weak KAM solution at cohomology is -semi-concave.
Proof.
Given and , there exists a curve such that and which is calibrated by , which means that
[TABLE]
We assume that , which implies by Lemma 4.7 that , for a contant independant of and . We deduce that (with a higher constant ) for each . We lift (and the point ) to a curve in without changing its name, and consider, for each , the curve
[TABLE]
so that . Each of the curves , satisfy (provided is small enough). We have the inequality
[TABLE]
Use Lemma 4.2, we get
[TABLE]
Using the Euler-Lagrange equation and integrating by parts, we conclude that
[TABLE]
for each , . Taking , we obtain
[TABLE]
for each , . This ends the proof of the semi-concavity. ∎
*Proof of Theorem 4.2. * Let be a weak KAM solution, and let be the conjugated dual weak KAM solution. Then the set can be characterized as follows: Its projection on is the set where , and
[TABLE]
Since is semi-concave, it is a consequence of Lemma 4.8 that the differential exists for . Moreover, we can prove exactly as in Proposition 4.3 that is -semi-concave. Lemma 4.8 then implies that the map is -Lipschitz on . ∎
4.4 Double peak case
We now localize the Aubry and Mañé sets in the more general case where () is replaced by:
[TABLE]
It is natural to relax () in this way because, for a generic family of functions , there exist values of for which has two degenerate maxima. Note that Theorem 4.2 is still valid in this case, its proof does not use (). On the other hand, Theorem 4.1 is replaced by:
Theorem 4.4**.**
If is small enough with respect to and if is small enough with respect to , then the Aubry set at cohomology of the Hamiltonian satisfies
[TABLE]
If, moreover, the projection is contained in one of the (disjoint) balls , then the projection of the Mañé set is contained in the same ball .
Proof.
We assume that , and that is small enough for the balls to be disjoint. We first show that
[TABLE]
As in the single peak case, we set , and observe that
[TABLE]
for . The component of each orbit of the Aubry set spends a finite amount of time outside of . There are four type of excursions that the orbits of can perform outside of this union : From to for and . Exactly as in the single pick case, the orbits segments connecting to itself are contained in . So the claim holds, provided there exists no orbit segment in connecting to with .
Assume for example that there exists an orbit segment connecting to . Then, given any suspended weak KAM solution , the same action estimates as in the single peak case imply that
[TABLE]
Since the Aubry set is chain recurrent, there must exist an orbit segment connecting to , and we have
[TABLE]
By using Lemma 4.6 with and , we get that
[TABLE]
All these inequalities together imply that
[TABLE]
which does not hold if is small enough. This contradiction proves that no excursion connecting to can exist in the Aubry set. Note that we have used the chain recurrence of the Aubry set, and that the conclusion does not in general apply to the Mañé set. We have proved that
[TABLE]
The vertical part of the localisation follows exactly as in the single peak case.
In general, such a localization does not hold for the Mañé set, which may contain connections from one of the regions to the other (but, in view of the calculations above, not in both direction). If such a connection exists, then its -limit is contained in one of the domains , say , and its -limit is containedin the other domain . Recalling that the and limits of the Mañé set are contained in the Aubry set, we conclude that each of the intersections
[TABLE]
is non empty. This proves the last part of the statement ∎
5 Nondegeneracy of the barrier functions
In this section we prove:
Theorem 5.1**.**
In the context of Theorem 1.5, by possibly taking a smaller , for a residue set of the following hold: for any such that is irrational and , the set is totally disconnected.
This is a delicate perturbation problem, and a version of it for a priori unstable systems appeared in [CY2] and was discussed in [Mag]. In this section we give a self-contained proof with many new ingredients.
5.1 Outline of the proof
In this section we prove Theorem 5.1 assuming some statements to be proven in later subsections. Let denote the Lagrangian associated to .
- •
We define to be the set of such that whenever is rational. The set is a residue subset of . We also abuse notations and denote by the set of Hamiltonians of the form .
- •
We define
[TABLE]
according to the previous item, for and , we necessarily have irrational. In particular, contains a unique static class. In view of the upper semi-continuity of the Mañé set, is a compact subset of .
- •
If and , then the Aubry set contains exactly two static classes denoted (with projections ). Then the Mañe set is the disjoint union
[TABLE]
where (and ) is the set of heteroclinic orbits from to (and vice versa). Projections are denoted . Note that . We will also use the notations and when discussing the dependence on .
- •
For and , the static classes determine two elementary forward and two backward weak KAM solutions
[TABLE]
where the barrier functions are evaluated for and . The associated pseudographs are denoted and , respectively, they do not depend of the choices of points . Define
[TABLE]
and similarly defined with , switched. The functions do not depend on the choice of points , they are non-negative, and vanish, respectively, on and
Given , we consider the compact subset formed by points such that . There exists such that the Mañé set is disjoint from for each and . The compact set ( is the double covering) is then disjoint from . Moreover, for these and , the set intersects each orbit of .
Since the compact interval is the union of finitely compact segments, each contained in a ball of the form , it suffices to prove Theorem 5.1 for each segment. Therefore, we can assume without loss of generality that is actually contained in one of these balls. Then, there exists a compact set such that
- •
For each and , is disjoint from and intersects each orbit of .
We make this additional assumption for the sequel of the section.
Lemma 5.1**.**
For each , the set is totally disconnected if and only if the set
[TABLE]
is totally disconnected.
Proof.
The set is a compact metric space, so it is totally disconnected if and only if it has topological dimension zero, see [HW]. Assuming that this property holds, The set is the disjoint union of two homeomorphic copies of , hence it is compact and of zero topological dimension. As a consequence, each of the sets is compact and of zero topological dimension, where is the time Hamiltonian flow of . The countable union
[TABLE]
is then also of zero dimension. As a consequence the projection is of zero topological dimension, hence it is totally disconnected. ∎
We want to prove that a dense of Hamiltonians have the property that is totally disconnected for each . The part follows from the next Lemma.
Lemma 5.2**.**
Let and be compact subsets, then the set of such that all satisfies
[TABLE]
is totally disconnected is a set.
Proof.
Consider satisfying the conditions of the lemma, then for each , is compact and totally disconnected, and hence has zero topological dimension.
Let’s call a compact subset disconnected if it admits a finite disjoint covering by compact subsets of diameter at most . If satisfies the conditions of the Lemma, then is disconnected for each and each . Since the Mañe set is upper semi-continuous in the Hamiltonian (in the topology), so is and we have, for each fixed :
There exists an open set containing and a neighborhood of in such that the set is disconnected for all and .
We now use the observation that is upper semi-continuous in , hence so is since is compact. We deduce the existence of a smaller neighborhood of , such that for each . We have proved: the property that is disconnected for each is open (and hence open). The Lemma follows by taking the intersection on . ∎
We now adress the density part. Let us consider the product space with the standard norms on both spaces. Define the following subset
[TABLE]
The following proposition allows us to perturb the function locally simultaneously for an open set of . The proof is given in section 5.2.
Proposition 5.2**.**
Let and be a compact set disjoint from . Then there exists such that for all , , and with , there exists a Hamiltonian such that:
For all , the Aubry set coincides with , with the same static classes. In particular, . 2. 2.
For all , there exists a constant such that
[TABLE]
The same holds for , with replaced with in (21). Moreover, for each , when .
We will use Proposition 5.2 to perturb all barrier functions near a given simultaneously. Because we are perturbing an uncountable family of functions, we need an additional information on how the functions depends on . The proof is given in Section 5.3.
Proposition 5.3**.**
For each , the maps are -Hölder from to .
This regularity implies that the set is compact and has Hausdorff dimension at most 2 in . The following Lemma will allow to take advantage of this fact:
Lemma 5.3**.**
Let be a compact set of finite Hausdorff dimension. The following property is satisfied on a residue set of functions (with the uniform norm):
For each , the set of minima of the function on is totally disconnected.
As a consequence, for each open neighborhood of in , there exists arbitrarily -small compactly supported functions satisfying this property.
Proof.
We first consider the case The set is compact and of finite Hausdorff dimension (one more than the dimension of ). For each compact subinterval , the set is also compact and finite dimensional, since the restriction map is Lipschitz. If is non trivial, the complement
[TABLE]
is open and dense in . To prove density, we consider a subspace of finite dimension larger that the Hausdorff dimension of . We moreover assume that all functions of are compactly supported inside the interior of . Given , we consider the affine space . Considering the distance, the Hausdorff dimension of is not greater than the Hausdorff dimension of , hence it is less than the dimension of . This implies that the complement is dense in endowed with the distance. Since the and norms are equivalent on the finite dimensional space , we conclude that belongs to the closure of in .
Let be a sequence of compact subintervals of such that each open interval contains one of the . Then if (this intersection is a dense ), each of the functions has the property that it is not constant on any open interval, hence its set of minima in is totally disconnected.
Let us now turn to the general case. We denote by the projections on the factors. We associate to each function the functions
[TABLE]
For each and , the following property holds on an open and dense subset of functions : None of the functions is constant on .
To prove density, we consider a function . The map is Lipschitz hence the set is compact and has finite Hausdorff dimension. We can aplpy the result for to this family and obtain that for generic , none of the functions
[TABLE]
for is constant on the interval .
By taking the intersection on and , we obtain that, for generic , each of the functions has a totally disconnected set of minima in .
Since , this implies that is totally disconnected. ∎
Proof of Theorem 5.1.
Let be the set of Hamiltonians which have the property that is totally disconnected for each .
By Lemma 5.1, it is enough to prove that is a dense . By Lemma 5.2, is a , we have to prove density.
Let us fix . For each , we consider small enough so that Proposition 5.2 applies. We define the cube
[TABLE]
In view of Proposition 5.3, we can apply Lemma 5.3 to the family of functions on the cube for each . We find arbitrarily small functions compactly supported in and such that each of the functions have a totally disconnected set of minima in . If , we can apply Proposition 5.2 to get Hamiltonians approximating . We obtain:
- •
The set of Hamiltonians such that is totally disconnected for each is dense in . By Lemma 5.2, it is a .
Since is compact, there is a finite cover , such that the above can be applied on each some constant . For , we obtain:
- •
For a residue set of , the set is totally disconnected for all and .
Taking the intersection over , we obtain :
- •
For a residue set of , the set is totally disconnected for all .
In particular, is in the closure of . ∎
5.2 Perturbing the Peierls’ barrier functions
Let be the Lagrangian for . We define the generating function by
[TABLE]
Note that for all and . If is sufficiently small, there is a one-to-one correspondence between the time-1 map of the Euler-Lagrange flow of , and the generating function . We will also consider the generating function of the Hamiltonian (pull back of the double covering), which satisfies
[TABLE]
where we have lifted to a map . It is important to keep in mind that has an additional symmetry where , corresponding to the deck transformation of . We also denote
[TABLE]
and note that and therefore is completely determined by . We will perturb the barrier functions by perturbing .
Let be open sets which projects injectively to , namely for all . We define a perturbation block to be the set
[TABLE]
in other words, the set of such that and , where is the time--map of the Hamiltonian . We can also consider as a subset of since projects injectively to .
Given and as before, for , we define a perturbation of the generating function (depending on , ) as follows:
[TABLE]
and extends it by periodicity for all . Here is a standard mollifier function such that
[TABLE]
Lemma 5.4**.**
When is small enough, there exists a Tonelli Hamiltonian whose generating function is equal to . Moreover, as .
Proof.
Let , extended by periodicity, then for some depending on . Let be the generating function of the time- map of the Hamiltonian , we consider the following functions
[TABLE]
where is a mollifier function with on and on . When is small enough, the functions uniquely determines exact symplectic maps .
It’s easy to see that there exists an exact symplectic isotopy between and , then there is an exact symplectic isotopy between and . In view of Proposition 9.19 and Corollary 9.20 of [MDS], we get is a Hamiltonian isotopy. Moreover, since is periodic in , it must be generated by a time periodic Hamiltonian . The maps are in and in , the vector fields are and the Hamiltonians are .
Moreover, it’s easy to see that converges in to identity uniformly over as . Since has the Hamiltonian function (see [MDS] Proposition 10.2) we conclude that as . ∎
The following lemma prepares us for the perturbation. For an orbit contained in the psudograph , there exists a perturbation block that the orbit of never returns to in backward time. Moreover, the orbit also does not return to the “copy” of the perturbation block under the deck transformation of . This is important because we would like to perturb the generating function by perturbing only .
Lemma 5.5**.**
Consider , and . Then there exists , and open sets and , such that
- •
The covering map is injective on .
- •
, are disjoint from .
The following hold for each .
For , let be contained in the closure of the psudograph .
- (a)
. 2. (b)
The backward orbit is asymptotic to . 3. (c)
For , is not contained in or . 2. 2.
For , let be contained in the closure of the psudograph .
- (a)
The forward orbit is asymptotic to . 2. (b)
For , is not contained in or
Moreover, an analogous statement holds for , where the roles of , are replaced by and .
Proof.
First we claim: for any , there is such that: if , , then implies:
- (c1)
. 2. (c2)
The backward orbit is asymptotic to . 3. (c3)
There exists such that implies .
We note that implies the weak KAM solution is differentiable at , and therefore is the unique super-differential. Item (c1) then follows from semi-continuity of super-differentials, see Proposition C.1.
Since , we have for
[TABLE]
Assume by contradiction that for in , and with , the backward orbit of accumulates to . This implies
[TABLE]
Taking limit as (by Proposition C.1), we obtain
[TABLE]
Combine with (24) we get (omitting the subscript of )
[TABLE]
or this is a contradiction with .
To prove (c3) we again argue by contradiction. Let be as before, we assume that there exists such that . Denote , using the fact that backward orbit of is calibrated, we have
[TABLE]
Up to taking a subsequence, assume , take limit as , we obtain
[TABLE]
where are evaluated at . Since , the above minimum is not reached at . Therefor , but we showed (in the proof of (c2)) this is also impossible.
We now define the sets . Since is asymptotic to , project via implies is asymptotic to . There exists such that
[TABLE]
and for all .
Apply claim (c1)-(c3) to , and obtain the parameters . Since the orbit of is wondering, there exists such that , implies
[TABLE]
apply the relation we get
[TABLE]
For a later determined , choose using claim (c1) again to ensure any with implies . Define ,
[TABLE]
. Since , as , we can choose small enough such that
[TABLE]
We now verify that for and , due to (26). Moreover, since
[TABLE]
(25) implies 1(c) for . On the other hand, (c3) ensures the same for as well.
The proof of 2(a)(b) and the moreover part is analogous and we omit it. ∎
Proof of Proposition 5.2.
Given , let be the corresponding point in . Choose , as in Lemma 5.5. For , consider perturbation via (23) using the neighborhoods . Note that for , we have and we will use this notation throughout the proof. First, notice that according to Lemma 5.4, as .
Item 1. We first show that the perturbation does not affect Aubry set and static classes. Lemma 5.5 asserts are disjoint from . For and small enough, using semi-continuity, are disjoint from and . Then (23) and (22) implies the action and action coincide on orbits of and . As a result and must coincide with the same static classes.
Item 2. We proceed to prove (21). Let , then is a calibrated orbit (on ) for the weak KAM solution , with . Write . Since is backward asymptotic to , there is such that
[TABLE]
where in the last line is lifted to . In view of 1(c) and (23), for any , we have
[TABLE]
By the same reasoning, we have
[TABLE]
Using (27), we get
[TABLE]
Observe that the previous arguments holds when and are switched, the last displayed formula becomes an equality. By the same reasoning, using Lemma 5.5, 2(a),(b), we obtain
[TABLE]
These (21) follows. The proof for is identical with two static classes switched. ∎
5.3 Hölder continuity of the barrier functions
We prove Proposition 5.3 by relating the barriers to the stable and unstable manifolds of the Aubry sets.
Recall that the system admit a weakly invariant cylinder which contains the Aubry set for . Using the covering map , we obtain and denote , for all .
Recall that is the set of such that is an invariant curve contained in . Let be the with the smallest and largest component. Then the component of bounded by is an invariant set for , we denote it . Let be the lifts under , then are normally hyperbolic invariant manifolds for .
They admit center stable and center unstable manifolds , which are locally graphs above . These manifolds are foliated by the strong stable and unstable manifolds of the points of , see Appendix A. The leaves of this foliation are , they are locally graphs above . The foliation itself is .
Consider , then for , is a Lipshitz invariant curve. Define the sets
[TABLE]
Since are Lipshitz graphs over , and since are a foliation whose leaves are graphs over , are Lipshitz graphs over in a neighborhood of . We will show that they coincides with the pseudographs in a neighborhood of .
Lemma 5.6**.**
For , if is backward asymptotic to , then there exists such that for each .
Suppose an orbit is backward asymptotic to , then it is asymptotic to the normally hyperbolic set . This orbit is contained in the strong manifold of a point which is asymptotic to , but which in principle may not belong to . To prove that , we need an argument similar to Theorem 1.4.
We need the following version of Proposition 4.3.
Proposition 5.4**.**
Suppose , then for each semi-concave function , the function is semi-concave and Lipschitz. Similar statement holds for . As a result, for any weak KAM solution and , the set
[TABLE]
is a Lipschitz graph over the component.
Proof.
We observe that the proof of Proposition 4.3 applies as long as we replace by and by . The assumption ensures we can choose in that proof.
For the second part, observe that
[TABLE]
and the proof is similar to Theorem 4.1. ∎
For the rest of this section, denotes .
Proof of Lemma 5.6.
We only prove for the case as the others are similar. Since is backward asymptotic to , then there exists such that . Necessarily converges to . We will show .
Arguing by contradiction, suppose , then using the fact that is the central direction, converges at a maximal rate of .
Denote , projects onto component, for any , there is such that . According to Theorem 3.1, there exists such that is an graph over , which implies
[TABLE]
for some . Let , we have . Suppose is large enough such that , then
[TABLE]
Assume . We now use Proposition 5.4 to get for some ,
[TABLE]
keep in mind that . Since , using Theorem 1.4, we get for small ,
[TABLE]
Combine with (30), we get
[TABLE]
When we get , but this contradicts with (28) and (29). ∎
Lemma 5.7**.**
For , there is such that for all , we have for ,
[TABLE]
This also implies and is over . 2. 2.
For each , there exists such that
[TABLE]
Proof.
We prove item 1. for , the proof for is identical. We first prove the statement for then extend to a neighborhood by continuity. First of all, we refer to [Be1] Lemma 4.4, to get the existence of such that every with is backward asymptotic to . By Lemma 5.6, there exists such that . We now show that can be chosen uniformly for all . Arguing by contradiction, if there is and for all , after taking a convergent subsequence, we get whose backward orbit does not intersect . This is a contradiction. Using a similar compactness argument over , we obtain:
There exists and , such that for all and , we have for all .
Finally, we choose small enough so that . Since is semi-continuous in , this property extends to a small neighborhood of .
We now prove item 2, for . Assume there exists , , with , such that for all . Taking limit up to a subsequence, we obtain an orbit not backward asymptotic to , a contradiction. ∎
For each , the set is a graph over , hence there exists a map such that is the image of and .
Lemma 5.8**.**
There exists such that
[TABLE]
for each and in .
Proof.
We denote by different positive constants that may depend on and . Since is a Lipschitz graph over ,
[TABLE]
Each Weak KAM solution is differentiable on , and we have . We have
[TABLE]
hence the symplectic area of the domain of delimited by the curves and is
[TABLE]
Recall that the cylinder is given by a graph . The estimates (4) imply that, if are two vectors tangent to , then , hence, if is small enough,
[TABLE]
Note that given two Lipshitz functions with ,
[TABLE]
Let denote the region on between and . For , there is such that
[TABLE]
Combine with (31) we get our conclusion. ∎
Lemma 5.9**.**
In the context of Lemm 5.7, consider for , and and , denote
[TABLE]
Then for :
; 2. 2.
.
Moreover, the same holds with replaced with .
Proof.
For , let , and let be such that . We then define be the unique such point with . Finally, define such that , which is possible since is locally a graph over .
We note that within the center unstable manifold , the NHIC on one hand, and on the other hand serves as two transversals to the strong unstable foliation . Since the foliation is , there exists such that
[TABLE]
where is from Lemma 5.8. Denote , and noting which is locally a graph, we get for
[TABLE]
therefore
[TABLE]
Item 1 follows. For item 2, we consider , then integrating item 1 leads to
[TABLE]
Item 2 follows by taking . ∎
Proof of Proposition 5.3.
Fix , we consider in the context of Lemma 5.7. From item 2 of that lemma, for every , there exists a calibrated orbit with , such that whenever . Then (omitting the subscript )
[TABLE]
Since are uniformly Holder in for and , each are uniformly Lipshitz in , the family is Holder in . ∎
Appendix A Normally hyperbolic manifold
Let be a vector field. We give sufficient conditions for the existence of a Normally hyperbolic invariant graph of . We split the space as , and denote by the points of . We denote by the components of :
[TABLE]
We study the flow of in the domain
[TABLE]
where and are the open Euclidean balls of radius and in and , and is a convex open subset of . We denote by
[TABLE]
the linearized vector field at point . We assume that is bounded on , which implies that each trajectory of is defined until it leaves . We denote by the union of full orbits contained in . In other words, this is the set of initial conditions such that there exists a solution of the equation satisfying . We denote by the set of points whose positive orbit remains inside . In other words, this is the set of initial conditions such that there exists a solution of the equation satisfying . Finally, we denote by the set of points whose negative orbit remains inside . In other words, this is the set of initial conditions such that there exists a solution of the equation satisfying . These sets have specific features under the following assumptions:
Hypothesis 3** (Isolating block).**
We have:
- •
* on .*
- •
* on .*
- •
* on .*
Hypothesis 4**.**
There exist positive constants and such that:
- •
* for each in the sense of quadratic forms.*
- •
* for each .*
Theorem A.1**.**
Assume that Hypotheses 3 and 4 hold, and that
[TABLE]
Then the set is the graph of a function
[TABLE]
the set is the graph of a function
[TABLE]
and the set is the graph of a function
[TABLE]
Moreover, we have the estimates
[TABLE]
Proof.
This results could be reduced to several already existing ones, see [Fe, HPS, McG, Ch] or proved directly by well-known methods. We shall use Theorem 1.1 in [Ya] which is the closest to our needs because it is expressed in terms of vector fields. We first derive some conclusions from the isolating block conditions. We denote by the projection , and so on.
Lemma A.1**.**
If Hypothesis 3 holds, then
[TABLE]
Moreover, the closures of and satisfy
[TABLE]
Proof.
Let us define as the first positive time where the orbit of hits the boundary . Let us denote by the flow of . If (which is equivalent to ), we have , as follows from Hypothesis 3. Then, it is easy to check that the function is continuous, and even , at .
We prove the first equality of the Lemma by contradiction, and assume that there exists a point such that does not intersect the disc . Then, the first exit map
[TABLE]
extends by continuity to a continuous retraction from to its boundary . Such a retraction does not exist. The proof of the other equality is similar.
Finally, we have
[TABLE]
Hypothesis 3 implies that each point of has a neighborhood formed of points which leave after a small time. As a consequence, the set can’t intersect , and we have proved that The other inclusion can be proved in a similar way. ∎
In order to prove the statement of the Theorem concerning , we apply Theorem 1.1 of [Ya]. More precisely, using the notation of that paper, we set
[TABLE]
We have the estimates
[TABLE]
in the sense of quadratic forms. Moreover, we have the estimates
[TABLE]
Since
[TABLE]
we conclude that Hypothesis 2 of [Ya] is satisfied. Hypothesis 1 of [Ya] is verified by the domain , and Hypothesis 3 is precisely the conclusion of Lemma A.1. As a consequence, we can apply Theorem 1.1 of [Ya], and conclude that the set is the graph of a and -Lipschitz map above in coordinates, and therefore the graph of a -Lipschitz map in coordinates.
In order to prove the statement concerning , we apply Theorem 1.1 of [Ya] with
[TABLE]
[TABLE]
It is easy to check as above that all hypotheses are satisfied.
Let us now study the set . First, let us prove that is a graph above . We know that is the graph of a -Lipshitz function and that is the graph of a -Lipshitz function . The point belongs to if and only if
[TABLE]
or in other words if and only if is a fixed point of the -Lipschitz map
[TABLE]
For each , this contracting map has a unique fixed point in , which corresponds to a point of . It follows from Lemma A.1 that this point is contained in . Then, it depends in a way of the parameter . We have proved that is the graph of a function . In order to estimate the Lipschitz constant of this graph, we consider two points in . We have
[TABLE]
and
[TABLE]
Taking the sum gives
[TABLE]
and
[TABLE]
since . We conclude that is -Lipschitz. ∎
It is useful to go a bit further in the study of the invariant manifold . This manifold is a partially hyperbolic invariant set, hence by the usual theory, to each point is attached a strong stable manifold and a strong unstable manifold , which are (and even if is ). The manifolds partition , although this partition is not usually a foliation. For each , we denote by the strong unstable space, which is the tangent space at of the only unstable manifold which contains . We define the exponents
[TABLE]
where is the solutions of the linearized equation with initial condition , and is the solution of starting from .
Lemma A.2**.**
[TABLE]
Proof.
We consider an orbit , and a variational orbit tangent to . Observe that for each , which implies:
[TABLE]
∎
The next Lemma implies that the manifolds are the graphs of and -Lipschitz maps .
Lemma A.3**.**
If is an orbit of , then the linearized equation preserves the cone in forwad time, and the cone in backward time.
We have for each , for each .
Finally we have the estimate
[TABLE]
Proof.
Let be a solution of the linearized equation along . Then
[TABLE]
(this estimate will also provide the desired growth rate in the unstable direction) and
[TABLE]
This implies implies that
[TABLE]
recalling that . The estimates concerning are similar. ∎
In general, the maps and are not better than (Hölder)-continuous in , but we can obtain a better regularity under stronger hypotheses:
Theorem A.2**.**
In the context of Theorem A.1, let us assume the additional assumptions that is and (or equivalently, ). Then each of the manifolds is , and the manifolds form a foliation of (similarly for in ). The foliations are in the strongest possible sense, namely the map is on , which imply that the foliation admits charts, and that the local holonomies ar .
Proof.
An easy computations shows that , hence we obtain
[TABLE]
This implies that , hence is -normally hyperbolic, hence it is , as well as and , see [Fe, HPS].
Moreover, we have the bunching condition , which implies the regularity of the unstable foliation, see [Fe2, PSW, DLS]. ∎
We need the following easy addendum:
Proposition A.3**.**
Assume in addition that there exists a translation of such that
[TABLE]
Then we have
[TABLE]
Proof.
It follows immediately from the definition of the sets , and that , and . ∎
In applications the first condition of Hypothesis 3 is usually not satisfied, except in the case where . In view of the applications we have in mind, it is useful to split the central variables into two groups and consider
[TABLE]
where is a convex open set in , . Given a positive parameter , let be the set of points such that . This is a convex open subset of containing . We denote by the product and by the product . With the notation , and denoting by the set of positive half orbits (resp. negative half orbits, full orbits) of contained in , we have:
Proposition A.4**.**
Let be a vector field. Assume that there exists such that
- •
* on .*
- •
* on .*
- •
* for each in the sense of quadratic forms.*
- •
* for each .*
- •
* for each .*
Assume furthermore that
[TABLE]
then there exist maps
[TABLE]
satisfying the estimates
[TABLE]
the graphs of which respectively contain . Moreover, the graphs of the restrictions of and to, respectively, , and , are tangent to the flow.
There exists an invariant foliation of the graph of whose leaves are graphs of -Lipschitz maps above . The set is a union of leaves : it has the structure of an invariant lamination. Two points belong to the same leaf of this lamination if and only if is bounded on .
If in addition there exists a group of translations of such that for each , then the maps can be chosen such that
[TABLE]
for each . The lamination is also translation invariant.
In contrast to the earlier results of this section, the map is not uniquely defined, and neither is its restriction to . Moreover, the intersection with of the graph of is not necessarily positively invariant. It can contain strictly the set . Similar remarks apply to and .
Proof.
We take a function such that :
- •
near the boundary of ,
- •
on ,
- •
uniformly.
We claim that the vectorfield
[TABLE]
satisfies all the hypotheses of Theorem A.1 on . Note also that on . Denoting by the variational matrix associated to , we see that
[TABLE]
[TABLE]
and
[TABLE]
As a consequence, we have
[TABLE]
The claim is proved. We define as the maps given by Theorem A.1 applied to on . Since on , we have for or . These maps may depend on the choice of the function but, once the function is chosen, they are uniquely defined. In the case where a group of translation exists as in the statement, then we have for each . The uniqueness then implies (34). By definition, is the graph of , the statement follows from this observation. ∎
Appendix B Disconnectedness of Heteroclinics
We consider a Tonelli Hamiltonian , a cohomology , and the associated Aubry and Mañé sets and . We assume that the Aubry set is the union of two static classes . The Mañé set can then be written as the disjoint union
[TABLE]
where is a set of heteroclinic orbits from to , and is a set of heteroclinic orbits from to . Morever, the sets
[TABLE]
are invariant compact Lipschitz graphs. In the notations of [Be1], we have , .
In [Be1], Section 9, it is proved that the cohomology is in the interior of its forcing class provided each of the sets and is neat in the following sense:
The set is neat if there exists a compact subset which contains one and only one point in each orbits of and which is acyclic, which means that there exist an open neighborhood of in such that the inclusion of into generates the null map in homology.
In Section 1.4 of the present paper, we apply this result under the assumption that the sets and are totally disconnected. We can do so in view of the following:
Proposition B.1**.**
The set (or ) is neat if it is totally disconnected.
Proof.
We first recall that a compact metric space is totally disconnected if and only if it has dimension zero, which means that each of its points has a basis of neighborhood made of open and closed sets, see [HW], section II.4.
By removing small open neighborhoods of and in , we form a compact subset of which contains at least one point in each orbit. This compact subset is totally disconnected (it is a subset of ) hence each of its points is contained in an open and closed set which is disjoint from both and . We cover our compact by finitely many of these neighborhood. Their union is a compact and open subset of which contains at least one point in each orbit. The set is then compact and open, and it contains exactly one point of each -orbit. It is totally disconnected, and therefore acyclic, in view of the following Lemma. ∎
Lemma B.1**.**
Let be a manifold and let be a totally disconnected compact subset of . Then is acyclic.
Proof.
The subset has dimension [math], see [HW]. As a consequence, each point of is contained in an open, closed, and acyclic neighborhood (small open sets are contained in discs hence are acyclic). We cover by finitely many of these subsets and set , , . We obtain open acyclic subsets which are pairwise disjoint and cover . This implies that is acyclic. ∎
Appendix C Continuity property of the Peierls’ barrier function
We consider here a general Tonelli Lagrangian . We recall, see [Be2], section 4, that the difference of two weak KAM solutions is constant on each static class.
Proposition C.1**.**
Let be a sequence of Tonelli Lagrangians converging in the compact open topology, and . Assume that has finitely many static classes. Let be such that , then for any ,
[TABLE]
Proof.
First, since each is continuous in and , we obtain
[TABLE]
taking infimum over , we get . Since if either or is in , we obtain
[TABLE]
Given , let be a sequence of extremal curves such that , , and
[TABLE]
We note that on each interval , we have
[TABLE]
since and . Note we omit the subscript in the intermediate calculations.
Let be two consecutive visit of to , we first show that must be bounded as . Assume otherwise, then the curves converges in uniformly over compact sets to . Assume the weak KAM solutions converges uniformly to a weak KAM solution of , taking limit in (35) implies must be calibrated by . Therefore must accumulates to which is a contradiction.
Let be the static classes of . Denote and assume is small enough so that are all disjoint. Let us note each determines sequences , , and as follows.
- •
Set .
- •
Let be the first visit of to and is the set that visits. Let be the last visit to , namely .
- •
The process stops if , we set then set , and .
Otherwise, let be the first visits to for , and the set it visits. Define be the last visit to and continue.
Then
[TABLE]
where the subscript was omitted in the last two lines. By restricting to a subsequence, we may assume that for all , the ordering are identical. Our previous observation implies for , are bounded as . By restricting to another subsequence, we may assume is constant for all , and , as . Note that for , , therefore, there exists such that . Let us also note, by definition , . Define and . Up to taking a subsequence, assume the weak KAM solutions uniformly. Take limit as in (36), we obtain
[TABLE]
Since is arbitrary, we obtain . ∎
**Acknowledgement ** V.K. has been partially support of the NSF grant DMS-1402164. K.Z. is supported by the NSERC Discovery grant, reference number 436169-2013.
The reference list from the paper itself. Each links out to its DOI / PubMed record.
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