On the Existence of Tableaux with Given Modular Major Index
Joshua P. Swanson

TL;DR
This paper characterizes when standard Young tableaux with a given shape and major index modulo n exist, generalizing previous results and confirming a recent conjecture, with implications for symmetric group representations.
Contribution
It provides necessary and sufficient conditions for the existence of tableaux with specified modular major index, extending prior work and proving a conjecture by Sundaram.
Findings
Conditions for existence of tableaux with given modular major index
Asymptotic equidistribution of shapes for large partitions
New estimates for symmetric group characters and hook lengths
Abstract
We provide simple necessary and sufficient conditions for the existence of a standard Young tableau of a given shape and major index mod , for all . Our result generalizes the case due essentially to (1974) and proves a recent conjecture due to Sundaram (2016) for the case. A byproduct of the proof is an asymptotic equidistribution result for "almost all" shapes. The proof uses a representation-theoretic formula involving Ramanujan sums and normalized symmetric group character estimates. Further estimates involving "opposite" hook lengths are given which are well-adapted to classifying which partitions have for fixed . We also give a new proof of a generalization of the hook length formula due to Fomin-Lulov (1995) for symmetric group characters at rectangles. We conclude with some remarks on unimodality of symmetric groupâŠ
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Taxonomy
TopicsAdvanced Combinatorial Mathematics · Advanced Mathematical Identities · Advanced Algebra and Geometry
On the Existence of Tableaux with
Given Modular Major Index
Joshua P. Swanson
Department of Mathematics, University of Washington, Seattle, WA 98195, USA http://www.math.washington.edu/Â jps314/
Abstract.
We provide simple necessary and sufficient conditions for the existence of a standard Young tableau of a given shape and major index mod , for all . Our result generalizes the case due essentially to Klyachko [Kly74] and proves a recent conjecture due to Sundaram [Sun17] for the case. A byproduct of the proof is an asymptotic equidistribution result for âalmost allâ shapes. The proof uses a representation-theoretic formula involving Ramanujan sums and normalized symmetric group character estimates. Further estimates involving âoppositeâ hook lengths are given which are well-adapted to classifying which partitions have for fixed . We also give a new proof of a generalization of the hook length formula due to Fomin-Lulov [FL95] for symmetric group characters at rectangles. We conclude with some remarks on unimodality of symmetric group characters.
Key words and phrases:
standard Young tableaux, symmetric group characters, major index, hook length formula, rectangular partitions
1. Introduction
We assume basic familiarity with the combinatorics of Young tableaux and the representation theory of the symmetric group. For further information and definitions, see [Ful97], [Sta99], or [Sag01].
Let be an integer partition of size , and let denote the set of standard Young tableaux of shape . We write for the transpose (or conjugate) of . Let denote the major index of . We are chiefly interested in the counts
[TABLE]
where is taken mod . To avoid giving undue weight to trivial cases, we take throughout. Work due to Klyachko and, later, KraĆkiewiczâWeyman, gives the following.
Theorem 1** ([Kly74, Proposition 2], [KW01]).**
Let and . The constant is positive except in the following cases, when it is zero:
- âą
* or ;*
- âą
* when ; or when .*
Indeed, the counts can be interpreted as irreducible multiplicities as follows, a result originally due to KraĆkiewiczâWeyman. Let be the cyclic group of order generated by the long cycle , let be the Specht module of shape , and let be the irreducible representation given by where is a fixed primitive th root of unity and . Let denote the standard scalar product for complex representations.
Theorem 2** (see [KW01, Theorem 1]).**
With the above notation, we have
[TABLE]
Moreover, depends only on and .
Remark 1**.**
KraĆkiewicz-Weyman gave the first equality in Theorem 2, and the second follows by Frobenius reciprocity. Klyachko [Kly74, Proposition 2] actually determined which contain faithful representations of in agreement with Theorem 1. One may see through a variety of methods that depends up to isomorphism only on .
The manuscript [KW01] was long-unpublished, the delay being largely due to Klyachko having already given a significantly more direct proof of their main application, relating to free Lie algebras, though we have no need of this connection. For a more modern and unified account of these results, see [Reu93, Theorems 8.8-8.12].
The following recent conjecture due to Sundaram was originally stated in terms of the multiplicity of in .
Conjecture 1**.**
[Sun17*]**.
Let and . Then is positive except in the following cases, when it is zero: and*
- âą
**
- âą
* when is odd*
- âą
* when is even.*
Conjecture 1 is the case of the following theorem, which is our main result.
Theorem 3**.**
Let and . Then is positive except in the following cases, when it is zero: and
- âą
, ; or , ; or , ;
- âą
* and ;*
- âą
, r=\begin{cases}0&\text{if nis odd}\\ \frac{n}{2}&\text{ifn is even};\end{cases}
- âą
, ;
- âą
, r\in\begin{cases}\{1,\ldots,n-1\}&\text{if nis odd}\\ \{0,\ldots,n-1\}-\{\frac{n}{2}\}&\text{ifn is even}.\end{cases}
Equivalently, using Theorem 2, every irreducible representation appears in each or except in the noted exceptional cases.
M. Johnson [Joh07] gave an alternative proof of Klyachkoâs result, Theorem 1, involving explicit constructions with standard tableaux. KovĂĄcsâStöhr [KS06] gave a different proof using the LittlewoodâRichardson rule which also showed that implies . Our approach is instead based on normalized symmetric group character estimates. It has the benefit of yielding both more general and vastly more precise estimates for .
Our starting point is the following character formula. See Section 3 for further discussion of its origins and a generalization. Let denote the character of at a permutation of cycle type . We write for the rectangular partition with columns and rows. Write .
Theorem 4**.**
Let and . For all ,
[TABLE]
where
[TABLE]
is a Ramanujan sum, is the classical Möbius function, and is Eulerâs totient function.
We estimate the quotients in the preceding formula using the following result due to Fomin and Lulov.
Theorem 5**.**
[FL95*, Theorem 1.1]**
Let where . Then*
[TABLE]
The character formula in Theorem 4 and the Fomin-Lulov bound are combined below to give the following asymptotic uniform distribution result.
Theorem 6**.**
For all and all ,
[TABLE]
In Section 4 we use âopposite hook lengthsâ to give a lower bound for , Corollary 2. These bounds, together with a somewhat more careful analysis involving the character formula, Stirlingâs approximation, and the Fomin-Lulov bound, are used to deduce both our main result, Theorem 3, and the following more explicit uniform distribution result.
Theorem 7**.**
Let be a partition where . Then for all ,
[TABLE]
In particular, if , , and , then and the inequality holds.
Indeed, the upper bound in Theorem 7 is quite weak and is intended only to convey the flavor of the distribution of for fixed . One may use Roichmanâs asymptotic estimate [Roi96] of to prove exponential decay in many cases. Moreover, one typically expects to grow super-exponentially, i.e. like for some (see [LS08] for some discussion and a more recent generalization of Roichmanâs result), which in turn would give a super-exponential decay rate in Theorem 7. We have no need for such explicit, refined statements and so have not pursued them further.
Theorem 5 is based on the following generalization of the hook length formula (the case), which seems less well-known than it deserves. We give an alternate proof of Theorem 8 in Section 5 along with further discussion. A ribbon is a connected skew shape with no rectangles. For , write to mean that is a cell in . Further write for the hook length of and write .
Theorem 8** ([JK81, 2.7.32]; see also [FL95, Corollary 2.2]).**
Let where . Then
[TABLE]
whenever can be written as successive ribbons of length (i.e. whenever the -core of is empty), and [math] otherwise.
Other work on -analogues of the hook length formula has focused on algebraic generalizations and variations on the hook walk algorithm rather than evaluations of symmetric group characters. For instance, an application of Kerovâs -analogue of the hook walk algorithm [Ker93] was to prove a recursive characterization of the right-hand side of (5) below. See [CFKP11, §6] for a relatively recent overview of literature in this direction.
The rest of the paper is organized as follows. In Section 2, we recall earlier work. In Section 3 we discuss and generalize Theorem 4. In Section 4, we use symmetric group character estimates and a new estimate involving âopposite hook products,â Proposition 1, to deduce our main results, Theorem 3 and Theorem 7. We give an alternative proof of Theorem 8 in Section 5. In Section 6, we briefly discuss unimodality of symmetric group characters in light of Proposition 1.
2. Background
Here we review objects famously studied by Springer [Spr74, (4.5)] and Stembridge [Ste89] and give further background for use in later sections. All representations will be finite-dimensional over .
Continuing our earlier notation, is a partition of size , is the set of standard Young tableaux of shape and which has cardinality , is the long cycle in the symmetric group , is the irreducible -module (Specht module) of shape with character at an element of cycle type given by , denotes a cell in the Ferrers diagram of , and denotes the hook length of that cell.
Let be a finite group, a fixed element of order , a finite dimensional -module, and a fixed primitive th root of unity. Suppose is the multiset of eigenvalues of acting on . The multiset lists the cyclic exponents of on ; these integers are well-defined mod . Following [Ste89], define the corresponding âmodularâ generating function as
[TABLE]
Write to denote the character of at . Note that
[TABLE]
so that for instance depends only on the conjugacy class of . When and has cycle type , we write .
Theorem 9** (see [Ste89, Theorem 3.3] and [KW01]).**
Let . The cyclic exponents of on are the major indices of , mod , and
[TABLE]
Remark 2**.**
Stembridge gave the first equality in Theorem 9. Equality of the first and third terms follows immediately from KraĆkiewicz-Weymanâs work using Theorem 2 and the observation that the multiplicity of in is the number of times appears as a cyclic exponent of in .
We also recall Stanleyâs -analogue of the hook length formula.
Theorem 10**.**
[Sta99*, 7.21.5]**
Let with . Then*
[TABLE]
where , , and .
The representation-theoretic interpretation of the coefficients in Theorem 2 is related to the following result due independently to Lusztig (unpublished) and Stanley. We record it to give our results context, though it will not be used in our present work. For and , define
[TABLE]
so that .
Theorem 11**.**
[Sta79*, Proposition 4.11]**
Let . The multiplicity of in the th graded piece of the type coinvariant algebra is .*
Indeed, the second equality in Theorem 2 follows from Theorem 11 and [Spr74, Prop. 4.5]. See also [ABR05, p. 3059] for a more recent refinement of Theorem 11 and some further discussion.
Finally, we have need of the so-called Ramanujan sums.
definition 1**.**
Given and , the corresponding Ramanujan sum is
[TABLE]
For instance, . The equivalence of this definition of and the formula in Theorem 4 is classical and was first given by Hölder; see [Kno75, Lemma 7.2.5] for a more modern account. These sums satisfy the well-known relation
[TABLE]
for all [Kno75, Lemma 7.2.2].
3. Generalizing the Character Formula
In this section we discuss Theorem 4 and present a straightforward generalization. We begin with a proof of Theorem 4 similar to but different from that in [Dés90]. It is included chiefly because of its simplicity given the background in Section 2 and because part of the argument will be used below in Section 5.
of Theorem 4.
Pick , so has cycle type . Evaluating (4) at gives
[TABLE]
since and is a primitive th root of unity. Equation (7) gives a system of linear equations, one for each such that , and with variables for each . The coefficient matrix is . For example, the linear equation reads
[TABLE]
which follows immediately from the fact that and that depends only on .
As it happens, the coefficient matrix is nearly its own inverse. Precisely,
[TABLE]
where is the identity matrix with as many rows as positive divisors of . It is easy to see that (8) is equivalent to the identity (6) above. Using (8) to invert (7) gives
[TABLE]
For the term, we have and . Tracking this term separately, dividing by and replacing with now gives Theorem 4, completing the proof. ââ
Variations on Theorem 4 have appeared in the literature numerous times in several guises, sometimes implicitly (see [Dés90, ThéorÚme 2.2], [Kly74, (7)], or [Sta99, 7.88(a), p. 541]). In this section we write out a precise and relatively general version of these results which explicitly connects Theorem 4 to the well-known corresponding symmetric function expansion due to H. O. Foulkes. Let denote the Frobenius characteristic map and let denote the power symmetric function indexed by the partition .
Theorem 12**.**
[Fou72*, Theorem 1]**
Suppose and . Then*
[TABLE]
The following straightforward result, essentially implicit in [Sta99, 7.88(a), p. 541], connects and generalizes Theorem 12 and Theorem 4.
Theorem 13**.**
Let be a subgroup of and let be a finite-dimensional -module with character . Then
[TABLE]
and, for all ,
[TABLE]
where
[TABLE]
and denotes the cycle type of the permutation .
Proof.
Write . By definition (see [Sta99, p. 351]),
[TABLE]
where is the order of the stabilizer of any permutation of cycle type under conjugation. From the induced character formula (see [Ser77, 7.2, Prop. 20]), we have
[TABLE]
Say . Each with appears in the preceding sum times, since and are conjugate and is also the number of ways to conjugate any fixed permutation with cycle type to any other fixed permutation with cycle type . Hence
[TABLE]
Equation (10) now follows from (12) and (13). Equation (11) follows from (10) in the usual way using the fact (see [Sta99, (7.76)]) that . ââ
Note that (10) specializes to Theorem 12 and (11) specializes to Theorem 4 when . In that case, the only possibly non-zero arise from for .
One may consider analogues of the counts obtained by inducing other one-dimensional representations of subgroups of . Motivated by the study of so-called higher Lie modules, there is a natural embedding of reflection groups . A classification analogous to Klyachkoâs result, Theorem 1, was asserted for by Schocker [Sch03, Theorem 3.4], though the ârather lengthy proofâ making âextensive use of routine applications of the Littlewood-Richardson rule and some well-known results from the theory of plethysmsâ was omitted. By contrast, our approach using Theorem 13 may be pushed through in this case using an appropriate generalization of the Fomin-Lulov bound, such as [LS08, Theorem 1.1], resulting in analogues of Theorem 3 and Theorem 7. Our approach begins to break down when is large relative to and (11) has many terms. However, we have no current need for such generalizations and so have not pursued them further.
4. Proof of the Main Results
We now turn to the proofs of Theorem 3, Theorem 6, and Theorem 7. We begin by combining the FominâLulov bound and Stirlingâs approximation, which quickly gives Theorem 6. We then use somewhat more careful estimates to give a sufficient condition, , for . Afterwards we give an inequality between hook length products and âoppositeâ hook length products, Proposition 1, from which we classify for which . Theorem 3 follows in almost all cases, with the remainder being handled by brute force computer verification and case-by-case analysis. Theorem 7 will be similar, except the bound will be used.
Lemma 1**.**
Suppose . Then
[TABLE]
Proof.
We apply the following version of Stirlingâs approximation [Spe14, (1.53)]. For all ,
[TABLE]
The FominâLulov bound, Theorem 5, gives
[TABLE]
Combining these gives
[TABLE]
Rearranging this final expression gives (14). ââ
We may now prove Theorem 6.
of Theorem 6.
For , applying simple term-by-term estimates to (14) gives
[TABLE]
Consequently,
[TABLE]
where . The Ramanujan sums have the trivial bound . The estimate in Theorem 6 now follows immediately from Theorem 4. ââ
Lemma 2**.**
Pick and . Suppose for all where may be written as successive ribbons each of length that
[TABLE]
Then for all ,
[TABLE]
Proof.
By Theorem 4, we must show
[TABLE]
Using the explicit form for in Theorem 4 and the fact that has fewer than proper divisors, it suffices to show
[TABLE]
for all , , so the result follows from our assumption (15). ââ
Corollary 1**.**
Let . If , then .
Proof.
Equation (14) gives
[TABLE]
At , the right-hand side of (16) is less than for . At , the same expression is less than for , respectively. At , applying simple term-by-term estimates to (16) gives
[TABLE]
which is less than for . Thus, Lemma 2 applies with for all , so that
[TABLE]
and in particular . The cases remain, but they may be easily checked by hand. ââ
We next give techniques that are well-adapted to classifying for which for fixed . We begin with a curious observation, Proposition 1, which is similar in flavor to [FL95, Theorem 2.3]. It was also recently discovered independently by MoralesâPanovaâPak as a corollary of the Naruse hook length formula for skew shapes; see [MPP17, Proposition 12.1]. See also [Pak] for further discussion and an alternate proof of a stronger result by F. Petrov.
definition 2**.**
Consider a partition with as a set of cells (in French notation)
[TABLE]
Given a cell , the opposite hook length at is . For instance, the unique cell in has opposite hook length , and the opposite hook length increases by for each north or east step.
It is easy to see that . On the other hand, we have the following inequality for their products.
Proposition 1**.**
For all partitions ,
[TABLE]
Moreover, equality holds if and only if is a rectangle.
Proof.
If is a rectangle, the multisets and are equal, so the products agree. The converse will be established in the course of proving the inequality. For that, we begin with a simple lemma.
Lemma 3**.**
Let and be real numbers. Then
[TABLE]
Moreover, equality holds if and only if for all either or .
Proof.
If , the result is trivial. If , we compute
[TABLE]
The result follows in general by pairing terms and and using these base cases. ââ
Returning to the proof of the proposition, the strategy will be to break up and in terms of (co-)arm and (co-)leg lengths, and apply the lemma to each column of when computing , or equivalently to each row of when computing . More precisely, let . Take and . Define the co-arm length of as , the co-leg length of as , the arm length of as , and the leg length of as ; see Figure 1. With these definitions, we have and . We now compute
[TABLE]
where Lemma 3 is used for the inequality with , , , . Moreover, if equality occurs, then since the strictly decrease, we must have for all , forcing to be a rectangle. ââ
It would be interesting to find a bijective explanation for Proposition 1. The appearance of rectangles is particularly striking. Note, however, that need not be an integer. In any case, we continue towards Theorem 3.
definition 3**.**
Define the diagonal preorder on partitions as follows. Declare if and only if for all ,
[TABLE]
Note that is reflexive and transitive, though not anti-symmetric, so the diagonal preorder is not a partial order. For example, the partitions , , and all have the same number of cells with each opposite hook length. A straightforward consequence of the definition is that
[TABLE]
Hooks are maximal elements of the diagonal preorder in a sense we next make precise.
definition 4**.**
Let for . The diagonal excess of is
[TABLE]
For instance, has opposite hook lengths ranging from to , so .
The following simple observation will be used shortly.
Proposition 2**.**
Let for . Take via . Then the fiber sizes are unimodal, and are indeed of the form
[TABLE]
for some unique .
Proof.
This follows quickly by considering the largest staircase shape contained in . Indeed, is the number of rows or columns in such a staircase. ââ
Example 1**.**
If is a hook, the sequence of fiber sizes in Proposition 2 is
[TABLE]
where there are twoâs and non-zero entries. In particular, , i.e. .
Proposition 3**.**
Let for . Set
[TABLE]
Then
[TABLE]
In particular, if , then the hook is maximal for the diagonal preorder on partitions of size with diagonal excess .
Proof.
Using Proposition 2, the sequence
[TABLE]
is of the form
[TABLE]
where the terms weakly decrease starting at . Given a sequence , define . We have . Iteratively perform the following procedure starting with as many times as possible; see Example 2.
- (i)
If and some , choose maximal with this property. Decrease the th entry of by and replace the first [math] term in with . 2. (ii)
If and some , choose maximal with this property. We will shortly show that there is some for which . Choose minimal with this property, decrease the th term in by , and increment the th term by .
Example 2**.**
Suppose , so and
[TABLE]
which we abbreviate as . Applying the procedure gives the following sequences, where modified entries are underlined:
[TABLE]
Returning to the proof, for the claim in (ii), first note that both procedures preserve unimodality and the initial in . Hence at any intermediate step, is of the form
[TABLE]
where and there are terminal âs. Since , we have
[TABLE]
forcing since by assumption some , giving the claim. The procedure evidently terminates.
In applying (i), decreases by , whereas is constant in applying (ii). For the final sequence , it follows that from (19). Both (i) and (ii) strictly increase in the natural diagonal partial order on sequences. The final sequence will be
[TABLE]
where there are twoâs and non-zero entries. This is precisely by Example 1, and the result follows. ââ
We may now give a polynomial lower bound on .
Corollary 2**.**
Let for and take as in (19). For any , we have
[TABLE]
Moreover,
[TABLE]
Proof.
Equation (21) in the case follows by combining (18) and (20). The general case follows similarly upon noting since .
For (22), use Proposition 1 and (21) to compute
[TABLE]
ââ
We now prove Theorem 3 and Theorem 7.
of Theorem 3.
We begin by summarizing the verification of Theorem 3 for . For , a computer check shows that one may use Corollary 1 for all but particular . However, the number of standard tableaux for these exceptional is small enough that the conclusion of the theorem may be quickly verified by computer. We now take .
Let be as in (19). If , by Corollary 2,
[TABLE]
for , so we may take . Since , we must have .
Write to denote the concatenation of partitions and , where we assume the largest part of is no larger than the smallest part of . Using Proposition 2, since and , we find that either or for .
To cut down on duplicate work, note that transposing complements the descent set of . It follows that , so that . Since the statement of Theorem 3 also exhibits this symmetry, we may thus consider only the case when .
There are twelve with . One may check that the five possible for all result in for , leaving seven remaining , namely . It is straightforward though tedious to verify the conclusion of Theorem 3 in each of these cases. For instance, for and , there are standard tableaux with major indexes (alternatively, (5) results in ). The remaining cases are omitted. ââ
of Theorem 7.
If , then (14) gives
[TABLE]
As before one can check that the right-hand side of (23) is less than for and . When , term-by-term estimates give
[TABLE]
which is less than for . The first part of Theorem 7 now follows from Lemma 2 with for . It remains true for .
For the second part, suppose , , and . It follows from Proposition 3 that from (19) satisfies . Hence by Corollary 2 we have
[TABLE]
ââ
5. Alternative Proof of the Hook Formula
The proof of Theorem 8 in [FL95] and [JK81] uses a certain decomposition of the -rim hook partition lattice and the original hook length formula. We present an alternative proof following a different tradition, instead generalizing the approach to the original hook length formula in [Sta99, Corollary 7.21.6]. A by-product of our proof is a particularly explicit description of the movement of hook lengths mod as length ribbons are added to a partition shape.
We are not at present aware of any other proofs or direct uses of Theorem 8, and it seems to have been neglected by the literature. Indeed, the author empirically rediscovered it and found the following proof before unearthing [FL95].
of Theorem 8.
Let , . If cannot be written as successive ribbons of length , then by the classical Murnaghan-Nakayama rule [Sta99, Eq. (7.75)] we have , so assume can be so written.
Combining (4), (5), and (7) shows that we may compute by letting in the right-hand side of (5). We may replace each -number with by canceling the âs, since . Since has order , the values of at depend only on mod . Moreover, has only simple roots, and it has a root at if and only if . The order of vanishing of the numerator at is then , and the order of vanishing of the denominator is . The following lemma ensures these counts agree. We postpone the proof to the end of this section.
Lemma 4**.**
Let , , and suppose can be written as a sequence of successive ribbons of length . Then for any ,
[TABLE]
Here \#\{a,-a\text{ (mod \ell)}\} is if and otherwise.
We may now compute the desired limit by repeated applications of LâHopitalâs rule. In particular, we find
[TABLE]
The second factor in the right-hand side of (24) equals the right-hand side of (2), so we must show the first factor in the right-hand side of (24) is . For that, note that at for is non-zero and is conjugate to at . By Lemma 4, it follows that the contribution to the overall magnitude due to cancels with the contribution due to for each . This completes the proof of the theorem.
ââ
As for Lemma 4, it is an immediate consequence of the following somewhat more general result.
Lemma 5**.**
Suppose is a ribbon of length . For any ,
[TABLE]
Proof.
We determine how the counts change when adding a ribbon of length ; see Figure 2. We define the following regions in , relying on French notation to determine the meaning of âleftmost,â etc.
- (I)
Cells where is not in the same row or column as any element of . 2. (II)
Cells which are in the same row as some element of and are strictly left of the leftmost cell in . 3. (III)
Cells which are in the same column as some element of and are strictly below the bottommost cell of . 4. (IV)
Cells which are in both the same column and row as some element(s) of . Region (IV) includes the ribbon itself.
We now describe how hook lengths change in each region, mod the ribbon length , in going from to . They are unchanged in region (I). Regions (II) and (III) are similar, so we consider region (II). This region is a rectangle, which we imagine breaking up into columns. Write or to denote the hook length of a cell as an element of or , respectively. For in region (II), let denote the cell in region (II) immediately below , with wrap-around. We claim . Given the claim, hook lengths mod in regions (II) and (III) are simply permuted in going from to , so changes to the counts arise only from region (IV).
For the claim, let be the cells of the column in region (II) containing , listed from bottom to top; see Figure 3. Begin by comparing hook lengths at and . Since is a ribbon, the rightmost cell of in the same row as is directly left and below the rightmost cell of in the same row as . It follows that . This procedure yields the claim except when . In that case, , and we further claim , which will finish the argument. Indeed, let denote the number of elements in in the same row as . Certainly . Further, . Putting it all together, we have
[TABLE]
We now turn to region (IV). It suffices to consider the case depicted in Figure 4, where regions (I), (II), and (III) are empty. We define two more regions as follows; see Figure 4.
- (A)
Cells in the first row or column. 2. (B)
Cells not in the first row or column.
Region (B) is precisely translated up and right one square. Moreover, this operation preserves hook lengths, so changes in the counts arise entirely from region (A). We have thus reduced the lemma to the statement
[TABLE]
We prove (25) by induction on the size of region (B). In the base case, region (B) is empty, so is a hook, and the result is easy to see directly (for instance, negate the hook lengths in only the âvertical legâ to get entries of precisely ). For the inductive step, consider the effect of adding a cell to region (B). Now is in the same column as some cell in region (A) and is in the same row as some cell in region (A); see Figure 5. Say the original hook length of is and the original hook length of is . It is easy to see that . Adding to region (B) increases the hook lengths and each by , but and , so the required counts remain as claimed in the inductive step. This completes the proof of the lemma and, hence, Theorem 8. ââ
We briefly contrast our approach with that of [FL95]. Let be the number of ways to write as successive ribbons each of length . If , by the Murnaghan-Nakayama rule is a signed sum over terms counted by . While there is typically cancellation in this sum, there is in fact none for rectangular cycle types [JK81, 2.7.26], i.e. . Indeed, [FL95] proved Theorem 8 using standard rim hook tableaux instead of character evaluations, though virtually every application of their result uses the character-theoretic inequality in Theorem 5.
The sign of can be computed in terms of abaci as in [JK81, 2.7.23]. The sign may also be computed âgreedilyâ by repeatedly removing -rim hooks from in any order whatsoever, which is a consequence of (among other things) the following corollary of Lemma 5 and Theorem 8. We have been unable to find part (iv) in the literature, though for the rest see [FL95, 2.5-2.7] and their references.
Corollary 3**.**
Let . The following are equivalent:
- (i)
; 2. (ii)
* can be written as successive length ribbons, i.e. the -core of is empty;* 3. (iii)
we have
[TABLE] 4. (iv)
for any ,
[TABLE]
Proof.
(i) and (ii) are equivalent by Theorem 8. (ii) implies (iv) by Lemma 4 and (iv) implies (iii) trivially. Finally, (iii) is equivalent to (i) as follows. The expression (5) is a polynomial, so the order of vanishing at of the numerator, namely , is at most as large as the order of vanishing of the denominator, namely . The limiting ratio is non-zero if and only if these counts agree, so (iii) is equivalent to (i). ââ
While Corollary 3 gives equivalent conditions for , [Sta84, Corollary 7.5] gives interesting and different necessary conditions for for general shapes .
6. Unimodality and
We end with a brief discussion of inequalities related to symmetric group characters. In applying Proposition 1, we essentially replaced with , since the latter is order-reversing with respect to the diagonal preorder by (18). Moreover, it is relatively straightforward to mutate partitions and predictably increase or decrease them in the diagonal preorder, as in the proof of Proposition 3. It would be desirable to instead work directly with symmetric group characters themselves and appeal to general results about how increases or decreases as is mutated and is held fixed, though we have found very few concrete and no conjectural results in this direction. Any progress seems both highly non-trivial and potentially useful, so in this section we record some initial observations.
We have for , so these values are unimodal in . Using Theorem 8 shows more generally that for all ,
[TABLE]
which is again unimodal in . However, does not seem to respect changes in under dominance order in general in any suitable sense. On the other hand, if we allow the cycle type to vary and consider the Kostka numbers as a surrogate for (since ), we have a series of well-known and very general inequalities. We write for the Kostka-Foulkes polynomial and for dominance order. We have:
Theorem 14** ([Sna71], [LV73], [Lam78]; [GP92]).**
* for all if and only if . Indeed, implies (coefficient-wise) for all .*
Question 1**.**
Are there any âniceâ infinite families besides hooks and rectangles for which is monotonic, unimodal, or suitably order-preserving as varies? What about as varies?
7. Acknowledgements
The author would like to thank Sheila Sundaram for sharing a preprint of [Sun17] which motivated the present work. He would also like to thank his advisor, Sara Billey, for her support, insightful comments, and a careful reading of the manuscript; his partner, R. Andrew Ohana, for numerous fruitful discussions and support, including an early observation which lead to Lemma 4; and Connor Ahlbach for valuable discussions on related work.
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