Divergence of wavelet series: A multifractal analysis
C\'eline Esser, St\'ephane Jaffard

TL;DR
This paper investigates the divergence behavior of wavelet series using multifractal analysis, establishing bounds on divergence sets' Hausdorff dimensions and demonstrating their optimality under generic conditions.
Contribution
It introduces a multifractal framework to analyze pointwise divergence of wavelet series and provides deterministic bounds that are shown to be generically optimal.
Findings
Deterministic upper bounds for Hausdorff dimensions of divergence sets
Bounds depend on the sequence space of wavelet coefficients
Bounds are generically optimal under various notions of genericity
Abstract
We show the relevance of a multifractal-type analysis for pointwise convergence and divergence properties of wavelet series: Depending on the sequence space which the wavelet coefficients sequence belongs to, we obtain deterministic upper bounds for the Hausdorff dimensions of the sets of points where a given rate of divergence occurs, and we show that these bounds are generically optimal, according to several notions of genericity.
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Taxonomy
TopicsImage and Signal Denoising Methods
Divergence of wavelet series:
A multifractal analysis
Céline Esser111Corresponding author: [email protected] Université Lille 1, Laboratoire Paul Painlevé, Cité Scientifique, 59655 Villeneuve d’Ascq, France. This author is supported by the the Labex CEMPI (ANR-11-LABX-0007-01) and Stéphane [email protected] Université Paris-Est - LAMA, UMR 8050, CNRS, UPEC, 61 Av. du Gal. de Gaulle, F-94010, Créteil, France
Abstract
We show the relevance of a multifractal-type analysis for pointwise convergence and divergence properties of wavelet series: Depending on the sequence space which the wavelet coefficients sequence belongs to, we obtain deterministic upper bounds for the Hausdorff dimensions of the sets of points where a given rate of divergence occurs, and we show that these bounds are generically optimal, according to several notions of genericity.
MSC2010 : Primary 42C40, 40A30 ; Secondary 28A80
Keywords : *Baire genericity, Besov sequence spaces, divergence properties, Hausdorff dimension, lineability, multifractal analysis, prevalence, wavelet series *
Contents
1 Introduction
Pointwise convergence properties of Fourier series have been a major challenge in analysis, culminating in the famous Carleson-Hunt theorem. Later, one direction of research has been to estimate the “divergence rate” of partial sums at exceptional points where divergence occurs. The relevant tool to measure the size of these exceptional sets is the Hausdorff dimension, thus leading to a multifractal analysis of divergence: Denote by the partial sums of the Fourier series of a periodic function , i.e.
[TABLE]
and consider the sets
[TABLE]
J.-M. Aubry proved that, if , and , then (where denotes the Hausdorff dimension of the set ) and he showed the optimality of this result, see [2]. This was later extended and refined by F. Bayart and Y. Heurteaux, who, in particular, showed that optimality holds for generic functions of (in the sense supplied by Baire categories and prevalence), see [4, 5].
Such properties were also studied in the setting of wavelet series: J.-M. Aubry obtained upper bounds on the dimensions of the sets of points where a given divergence rate of the wavelet series of an function occurs, see [2]. Additionally, he showed their optimality by a specific construction in the case of the Haar wavelet. This last result was recently extended by F. Bayart and Y. Heurteaux who showed that it holds generically in (in the sense supplied by Baire categories), as a consequence of a general framework that they introduced in order to study multifractal phenomena, see [6].
The present paper extends these results in several directions: The Hausdorff dimensions of the divergence sets of wavelet series will be bounded under the assumption that the wavelet coefficients satisfy a Besov type condition, and the optimality of these bounds will be proved in several senses: We will show that, generically (in the sense of prevalence, Baire categories and lineability), they turn out to be equalities, under general conditions on the wavelet system used. We will also prove irregularity everywhere, which will yield the complete divergence spectrum of such series.
A wavelet basis in variables denotes a collection of functions , , such that the collection of functions
[TABLE]
forms an orthonormal basis of . Let
[TABLE]
Convergence properties can either be studied for the wavelet expansion of a function (or a distribution) i.e. for partial sums of the series
[TABLE]
(note that, if wavelets have sufficient regularity and decay properties, the duality products are well defined even if is not a function). They can also concern the partial reconstruction operators
[TABLE]
which can also be rewritten under the form
[TABLE]
for a specific function ; this sequence is referred to as the multiresolution expansion of .
Wavelet expansions have many remarkable properties: Under mild hypotheses on the , wavelet bases are known to form unconditional bases of many functions spaces, such as spaces for , and most Sobolev or Besov spaces, see [24] (for such characterizations, the sum corresponding to negative s in (1) may have to be replaced by the term ). This implies that the wavelet expansion of an element of the space converges with respect to the corresponding norm. However, the introduction of the first wavelet basis was motivated by a different question: A. Haar defined the Haar basis in 1909 in order to give an example of an orthonormal basis for which the expansion of a continuous function converges uniformly (in contradistinction with the Fourier series case). Not surprisingly, for other wavelet bases, the expansion of a bounded continuous function also converges uniformly, see [27].
Additionally, the expansion of an function () converges almost everywhere, and in particular at its Lebesgue points, as shown by S. E. Kelly, M. A. Kon, and L. A. Raphael in [20]; these results were extended by T. Tao to hard and soft sampling in [26]; related pointwise convergence questions were also investigated in [22, 28]. These results, however, left open the study of the rate of divergence at exceptional points where divergence occurs.
The point of view that we will adopt is different: We will not consider directly the wavelet expansion of a function in a given function space, but rather wavelet series where the sequence of wavelet coefficients satisfies a given (discrete Besov) convergence property. These two points of view often coincide because of the wavelet characterizations of function spaces, which are precisely given by such conditions, but it is not always the case: Indeed, on one hand, some spaces (such as or ) do not have a characterization bearing on the moduli of their wavelet coefficients, and on other hand, these characterizations only hold if the wavelets are smooth enough, an assumption that will not be required. Additionally, we will not need wavelets to form an orthonormal basis. More precisely, we will consider the following setting.
Definition 1.1**.**
Let , , denote bounded functions with fast decay defined on (where needs not be equal to ). The associated wavelet system is the collection of the
[TABLE]
Formally, a wavelet series will denote a series of the form
[TABLE]
Remark 1.1**.**
Comparing with (1), we do not consider the “low frequency part” corresponding to negative values of , the convergence properties of which are straightforward.
Remark 1.2**.**
We do not assume orthogonality, or vanishing moments, so that this setting also covers biorthogonal bases, frames,…
The purpose of this paper is to develop an analysis of generic convergence and divergence properties of wavelet series. In Section 2 we define appropriate notions of convergence and divergence rates, and we bound the Hausdorff dimensions of the corresponding divergence sets assuming that the coefficients satisfy a Besov-type condition. In Section 3, we study a particular example of random wavelet series which will play a key role: Theorem 3.2 asserts that the upper bounds obtained are generically reached in the sense of prevalence (which is a natural extension to infinite dimensional spaces of the concept of “almost everywhere”, see Definition 3.1). In Section 4, these prevalent properties are shown to hold for other notions of genericity: Baire categories and lineability. In Section 5, the divergence rate of a generic wavelet series at a given arbitrary point is determined.
2 Convergence and divergence of wavelet series
In contradistinction with one-variable trigonometric series, which have a “natural” ordering, simple convergence of a wavelet series at a point does not have a canonical definition; this problem has been addressed in [20] where definitions fitted to simple convergence were introduced, for which the wavelet expansion of functions converges almost everywhere. Such results raise the problem of precisely estimating the size of the divergence set if is smoother, or of determining how fast the wavelet series diverges, when it does. A first result in this direction stated that, if for an , then the wavelet series of is absolutely convergent outside of a set of dimension at most (see Prop. 13.6 of [17]). Let and let denote the set of points where the partial sums of the wavelet series (up to scale ) are not bounded by ; J.-M. Aubry put into light a similarity between Fourier series and wavelet series, showing that, if , then , see [2].
From now on, we assume that a wavelet system generated by the , , has been fixed.
Definition 2.1**.**
Let , be a collection of coefficients and be a wavelet system; the corresponding series (3) diverges at rate at least at if there exist a constant and a sequence of indices such that and
[TABLE]
which we will denote by .
The divergence exponent of the wavelet series associated with at is
[TABLE]
and the -divergence sets are the sets
[TABLE]
The mapping
[TABLE]
is the wavelet divergence spectrum of the sequence .
Remark 2.1**.**
In this definition, the reference to the wavelet system used is implicit. When needed by the context, if denotes the wavelet system which is used, we will write for the corresponding divergence exponent.
Note that (4) implies a divergence of the wavelet series only if . On other hand, if , the negation of (4) actually expresses a convergence rate for the partial reconstruction operators
[TABLE]
as illustrated in Proposition 2.1 below. Though we are mainly interested in convergence and divergence properties of wavelet series, we also give results concerning the sequence . In order to state them, we introduce a divergence criterium for multiresolution sequences.
Definition 2.2**.**
Let and ; the sequence diverges at rate if
[TABLE]
Proposition 2.1**.**
Assume that
[TABLE]
- •
Let and ; if
[TABLE]
then has a limit when and
[TABLE]
- •
Let and ; if the sequence diverges at rate , then , the corresponding wavelet series diverges at rate at least at .
Proof.
We will use the convention that is a generic constant which only depends on the wavelet system and its value may change from one line to another.
We first prove the first point. For every , let
[TABLE]
First note that, if the wavelets are compactly supported, then has a bounded number of terms (which only depends on the size of the support), so that and the sequence decays geometrically; thus (6) follows with . Otherwise, let ; we split the sum into two terms. First, if the sum has less that terms, and we conclude as in the compactly supported case. Second, if , then using the fast decay of the wavelets
[TABLE]
and (5) implies that
[TABLE]
which is bounded by if we pick large enough, hence the first point.
As regards the second point, we note that, if diverges at rate , then for every
[TABLE]
Next, we proceed by contradiction assuming that (4) does not hold for a rate . The end of the proof lies then on arguments similar to those used for the proof of the first point.
∎
Remark 2.2**.**
Sets of divergence of and of wavelet series can differ: Indeed, one easily checks that a wavelet series can diverge at a given point at a rate and nonetheless may converge at the same point at a rate .
2.1 Upper bound for the wavelet divergence spectrum
We will start by proving upper bounds on the Hausdorff dimensions on the -divergence sets when belongs to a discrete Besov space. In order to state them, we need to recall the classical wavelet indexing. If and , let denote the dyadic cube of generation :
[TABLE]
We will index wavelets and wavelet coefficients by or by , writing indifferently or . We will use similar notations for wavelets, denoting by . We define as the set of indices such that is of generation . We will use the following sequence spaces.
Definition 2.3**.**
Let and . A sequence belongs to if it satisfies
[TABLE]
In this definition we do not write down explicitly the dependency of in the space dimension . Moreover, we use the standard conventions if or take the value . In particular, if the sequence belongs to .
Remark 2.3**.**
The chosen normalization of the coefficients in this definition of the discrete Besov spaces is not the one usually considered, see [25]: this is justified by the fact that if the wavelets system is composed of smooth enough functions, and forms an orthonormal basis, a biorthogonal basis or a frame, (7) characterizes the function space , see e.g. [24]. Therefore, Proposition 2.2 below can be reinterperted as yielding bounds on the wavelet divergence exponents of functions (or distributions) in these spaces. Additionally, the embeddings between Besov and Sobolev spaces implies that the same results hold for functions in the Sobolev space .
Proposition 2.2**.**
Let and . Let ; then
[TABLE]
and
[TABLE]
Remark 2.4**.**
The inequality (8) implies that the wavelet divergence spectrum of a sequence satisfies . Note also that, when , the first statement is in the same spirit as the results concerning rates of convergence proved in [21].
Remark 2.5**.**
The definition of the divergence exponent is very similar to the opposite of an Hölder exponent. This explains why the upper bound (8) obtained for the wavelet divergence spectrum of any sequence of coincides with the classical upper bound (if one considers it as a function of ) of the Hölder spectrum of any function in the corresponding functional Besov space , see [19]. However, an important difference is that divergence properties rely on the exact values of the wavelets at given points, while pointwise Hölder regularity does not depend on the (smooth enough) wavelet basis used. More precisely, the dyadic covering property introduced in Definition 2.5 will play an crucial role in the construction of sequences that saturate the inequality (8).
Proof of Proposition 2.2.
For each , the space is included in so that it suffices to prove the results for i.e. to assume that the wavelet sequence satisfies
[TABLE]
This bound implies that each coefficient with satisfies and since the wavelets are bounded functions, the first statement follows.
If is a dyadic cube of width , for any , let denote the cube of same center as , which is homothetical to and of width . Let . We define
[TABLE]
and, for any ,
[TABLE]
It follows from (9) that
[TABLE]
Let us set
[TABLE]
Because of (10), is composed of at most cubes of width ; using these cubes for as a covering of , we obtain that
[TABLE]
Let us now estimate for . We consider two cases: First, assume that ; then , so that
[TABLE]
Assume now that ; using the fast decay of the wavelets,
[TABLE]
Since and , it follows that, for large enough, where is such that . We obtain that
[TABLE]
Using (9), , so that
[TABLE]
and choosing large enough yields that (12) also holds.
Thus, outside of , the wavelet series diverges at rate at most , i.e. . Since (11) holds for any ,
[TABLE]
This last property holds for any . Consequently, for a given and any ,
[TABLE]
and the upper bounds stated in Proposition 2.2 follows by taking . ∎
2.2 Maximally divergent wavelet series
A particularly relevant case is supplied by the following wavelet series, which are as divergent as allowed by Proposition 2.2.
Definition 2.4**.**
Let and . Let be a non-empty open subset of and let ; the corresponding wavelet series (3) is maximally divergent in if it satisfies the following properties:
- •
for every point of ,
- •
for almost every point of , ,
- •
for every non-empty open set and for every ,
[TABLE]
Note that (13) states that the wavelet divergence spectrum is locally invariant inside (see [3] for a precise definition and the basic properties of the related notion of local spectrum). Remark also that if , then this definition boils down to the condition: , .
We will not only prove the existence of maximally divergent wavelet series (thus proving that the bounds in Proposition 2.2 are sharp), but we will also show that this extremal behavior is generic, for several notions of genericity. In order to prove such results, we need that a sufficient number of wavelets do not vanish at a point. This will be insured by the following property.
Definition 2.5**.**
A wavelet system satisfies the dyadic covering property of depth if there exist and a finite collection of triplets , , such that , and
[TABLE]
the depth denotes the largest value taken by the .
This definition will be the key property in order to obtain divergence results at every point. It is clearly satisfied by the Haar system with (if properly defined at dyadic points, e.g. taking or taking the definition which ensures that every point is a Lebesgue point), but it is not satisfied by the Schauder system (divergence does not hold at dyadic numbers, see the end of Section 2 for implications of this remark).
Definition 2.6**.**
If a wavelet system satisfies the dyadic covering property, we define affine mappings , , by the condition that is the dilation-translation which maps to the dyadic cube defined by . If is an arbitrary dyadic cube, we call the collection of the the dyadic covering of .
Remark 2.6**.**
A consequence of this definition is that, for every , there exists an such that , and the scale of the dyadic cube exceeds the scale of by at most . Note however that the cubes need not be included in , which will lead to technicalities in the following proofs; this is in contradistinction with the case of the Haar system, which is remarkable since one can take for the a unique mapping which is the identity (hence simpler proofs in [2, 6] for the Haar setting).
We now check that this condition is satisfied by the wavelet systems commonly used. First, recall that, in a Hilbert space , a sequence of vectors is a frame if there exist such that
[TABLE]
When such is the case, there exists a sequence such that
[TABLE]
The constitute a dual frame of the (see e.g. [7, 12, 13] for basics on wavelet frames).
Definition 2.7**.**
A wavelet frame system is a couple of wavelet systems and such that the and the form dual frames (for , , ).
This setting covers a wide range of wavelet expansions, since it is fitted to wavelet orthonormal or bi-orthogonal bases, see [1], or finite unions of such bases, or dyadic wavelet frames such as developed in [7].
Proposition 2.3**.**
*Any wavelet frame system composed of continuous functions satisfies the dyadic covering property. *
Proof.
Let us first check that, for a given , there exists at least one triplet with and such that
[TABLE]
We will prove this result by contradiction. Let and be a compactly supported function such that
- •
- •
and .
The restatement of (14) for in the wavelet frame system setting states that
[TABLE]
where
[TABLE]
where the series converges in . However, note that
[TABLE]
so that the sum for converges absolutely and uniformly on any compact set and the corresponding sum is bounded by .
We pick such that , and we now consider the sum for . Since is continuous and compactly supported, the sum converges uniformly on compact sets. Since , and since the whole series (16) converges to , it follows that
[TABLE]
if all the vanished, then this sum would also vanish; hence a contradiction, and (15) follows.
We now prove Proposition 2.3. Let be given. Because of the continuity of the wavelet, for the triplet supplied by (15), there actually exists an open ball , centered at and on which
[TABLE]
Since the collection of these balls covers , we can extract a finite covering, thus yielding the wavelets in the statement of the lemma. ∎
Remark 2.7**.**
The same argument easily applies to more general wavelet frames where the dilation parameters are not dyadic but of the form for an and translation parameters of the form instead of (see [13]), as long as the dual frame is of the same form (i.e. of wavelet type).
We now show the necessity of the dyadic covering property in order to prove maximal divergence of wavelet series. We consider the Schauder basis, where the generating wavelet is the function defined by
[TABLE]
The Schauder basis on the interval is composed of the functions , and the
[TABLE]
but we can also consider the wavelet system composed of the for and . This system clearly does not satisfy the dyadic covering property because, for , all wavelets vanish at the integers. It follows that, whatever the coefficients are, the series
[TABLE]
converges at dyadic numbers simply because it has a finite number of nonvanishing terms, and the first condition of maximal divergence does not hold ( at dyadic points).
Note that the same idea also yields counterexamples in several variables: One picks (smooth) wavelets supported in . The corresponding wavelet series boils down to finite sums on the hyperplanes of equation so that on a set of dimension (at least) , and the first point of Definition 2.4 never holds.
3 Saturating random series and prevalence
Up to now, prevalence-type results in multifractal analysis were obtained by the rather technical method of constructing high dimensional probe spaces, see e.g. [15, 14]. Our strategy will be more direct, through a probabilistic construction: We introduce stochastic processes that allow to obtain prevalent properties about the divergence of wavelet series associated to sequences of . More precisely, we construct random wavelet series, referred as saturating series, whose coefficients belong to and which are almost surely maximally divergent. We then prove the optimality of Proposition 2.2 in a strong sense: We show how saturating series yield the prevalent set of sequences having a maximally divergent wavelet series in .
3.1 Saturating random series
Let us assume that a wavelet system satisfying the dyadic covering property of depth has been chosen. From now on, we work on ; we will show afterwards how to extend the results to . We fix and . Let and be given, and denote by the corresponding dyadic cube. The integer is defined as follows: Consider the irreducible representation
[TABLE]
and are not all even, and set
[TABLE]
for every .
Remark 3.1**.**
An important remark is that the sequence is hierarchical, i.e. there exists such that decreases on the dyadic tree when increases.
Additionally, let be I.I.D. random variables of density
[TABLE]
The random sequence of coefficients is defined as follows: Let and be a dyadic cube of scale . If there exists at least one cube of scale and one such that , then we set
[TABLE]
otherwise, we set . The purpose of this definition is to ensure that, for each dyadic cube of of scale , the dyadic covering of has coefficients at least equal to (note that some of these coefficients can be larger because a given cube can be the image of different cubes through several mappings), i.e.
[TABLE]
for all . As mentioned in Remark 2.6, the cube is not necessary included in (therefore, we do not have a priori relations between and ).
We then define
[TABLE]
and we denote by the random sequence . The aim of this section is to obtain the following result.
Theorem 3.1**.**
The random sequence takes values in a compact subset of , and its associated wavelet series (3) is almost surely maximally divergent on .
This statement motivates the name of saturating sequence, since this random sequence “saturates” the upper bound of the wavelet divergence spectrum. Theorem 3.1 will follow from several intermediate results.
Lemma 3.1**.**
The random sequence belongs to .
Proof.
Let us first check that it is the case for the sequence . Let us fix . For every , there are less than coefficients satisfying (17); thus,
[TABLE]
and (7) is satisfied since
[TABLE]
The construction of the sequence consists in affecting to a finite number of cubes the size , and these cubes belong to the dyadic covering of so that their scale exceeds the scale of by at most . It follows that the Besov norm of exceeds the one of by, at most, a constant factor. The result for the random sequences follows because the random variables are bounded. ∎
The first part of the theorem follows from the following lemma.
Lemma 3.2**.**
Let be a positive sequence such that and be the subset of defined by the conditions
[TABLE]
Then is a compact subset of .
Proof.
This result is a direct consequence of the compacity of the operator
[TABLE]
see e.g. Chap. 27 of [23]. ∎
We will now prove that the random coefficients (21) are “large enough and well spread”, which implies maximal divergence for the corresponding wavelet series. We start by proving that the cannot be simultaneously small at many successive scales. Let be a multiple of , and for every dyadic cube of scale , let be the event
[TABLE]
Lemma 3.3**.**
The events satisfy
[TABLE]
If holds, then , there exists such that
[TABLE]
Furthermore, the which correspond to different values of (multiples of ) are independent.
This lemma follows from (19), (20), (21) and Definition 2.6.
Proposition 3.1**.**
Almost surely, for every , the divergence exponent of the wavelet series (3) associated with at satisfies: , and, for almost every point of ,
Proof.
Let us fix a scale of the form and consider a given dyadic cube of scale . We denote by the dyadic cubes of scales respectively which contain . Because of Lemma 3.3, the probability that none of the holds is bounded by
[TABLE]
Therefore, the probability that at least one of the cubes of scale satisfies the property “none of the holds” is bounded by and the Borel-Cantelli Lemma allows to conclude that, almost surely, for large enough, all cubes at scales satisfy that there is at least one cube of scale such that which contains and such that holds. By Lemma 3.3, this in turns implies that , for any , there exist a cube of scale such that and an index such that
[TABLE]
It follows that almost surely, there exists a sequence of cubes of scales (which grows at most arithmetically) and a sequence of indices such that
[TABLE]
so that , . This result, together with Proposition 2.2 implies that .
The a.e. divergence rate is because, on one hand, it is everywhere at least , and, on other hand, by Proposition 2.2, , the set of points where it is larger than has a dimension less that , hence a vanishing Lebesgue measure. ∎
We will now determine the almost sure wavelet divergence spectrum of the sequence defined by (21). We will use a variant of Lemma 3.3: Let and for every dyadic cube of scale , let be the event
[TABLE]
Lemma 3.4**.**
The events satisfy
[TABLE]
If holds, then , there exists such that
[TABLE]
Furthermore, the which correspond to different values of (multiples of ) are independent.
The proof is similar to the proof of Lemma 3.3, using (19), (20), (21) and the definition of the dyadic covering property. We now prove that the divergence exponents of the wavelet series associated to is controlled by the divergence exponents of the deterministic series
[TABLE]
Lemma 3.5**.**
Let us denote by the sequence whose coefficients are given by (18) and by the wavelet system define by the functions for every . Almost surely, for every ,
[TABLE]
Proof.
Let us fix a scale of the form ; let be a given dyadic cube of scale , and consider the sequence of length dyadic cubes of scales that contain . As done in Proposition 3.1, for large enough, the probability that none of the corresponding holds is bounded by
[TABLE]
A Borel-Cantelli type argument similar as before yields that almost surely, for large enough, all cubes at scales satisfy that there is at least one cube of scale which contains and such that holds. Again, it gives a cube of scale belonging to the dyadic covering of and an index such that
[TABLE]
Let us now consider such that . Then for any , there exist a constant and infinitely many indices for which
[TABLE]
For every , let be the integer satisfying and be the dyadic cube of scale which contains . Then, if is large enough, we have obtained that there is a cube of scale which contains , a cube of scale belonging to the dyadic covering of and an index such that
[TABLE]
Thanks to the hierarchical property of the sequence given in Remark 3.1, up to a factor which does not affect the divergence exponent since the difference is of order , the size of is comparable with the size of . This gives then a control of the size of and since , we get that . The conclusion follows. ∎
Proposition 3.2**.**
Almost surely, for any non-empty open set ,
[TABLE]
Proof.
Let and denote by the set of points of for which there exists infinitely many indices with such that
[TABLE]
We denote by the sequence of dyadic cubes of scale that contain . If , then for any index ,
[TABLE]
so that
[TABLE]
Lemma 3.5 implies then that
[TABLE]
The computation of the Hausdorff dimension of is standard; we will need the definition of the modified Hausdorff measure. If , and , let
[TABLE]
where denotes an -covering of , i.e. a covering of by bounded sets of diameters . The infimum is therefore taken on all possible -coverings. For any and , the quantity
[TABLE]
defines the -dimensional (outer) Hausdorff measure of . A standard result of dyadic approximation (for instance, see the mass transference principle of [8] and Theorem 2 of [18]), yields that, for any ball of non-empty interior,
[TABLE]
On other hand, (8) implies that the set of points for which the wavelet series associated to has a divergence exponent strictly larger than have a -Hausdorff measure that vanishes (it follows from interpreting it as a countable union of the set of points where the divergence exponent is larger than , which, by Proposition 2.2 have a Hausdorff dimension bounded by and therefore have a vanishing -Hausdorff measure). It follows that the set of points with a divergence exponent has positive -Hausdorff measure, and thus has a Hausdorff dimension equal to . ∎
Proof of Theorem 3.1.
It is a direct consequence of Lemma 3.2, Proposition 3.1 and Proposition 3.2. ∎
The next remark will be used in the proof of Theorem 4.2.
Remark 3.2**.**
A careful inspection of the previous proofs shows in particular that if is a sequence such that, for every , there are infinitely many cubes containing and of increasing scales , and infinitely many indices such that
[TABLE]
then the wavelet series associated to is maximally divergent in .
Remark 3.3**.**
We have constructed a random sequence whose sample paths almost surely yield a maximally divergent wavelet series on . In order to obtain the same result on the whole , it suffices to consider the process
[TABLE]
where the are independent copies of translated by .
We end this section by the following corollary, which states that the results obtained for the sequence also hold for “translates” of . This result will be the key step to obtain generic results of maximal divergence in the sense of prevalence below.
Corollary 3.1**.**
Let be a given sequence in . Then the wavelet series associated to is almost surely maximally divergent in .
Proof.
This corollary is a direct consequence of the fact that all the properties that we have obtained for also hold for . Indeed the only difference is that the random variables defining its coefficients are no more centered, but are shifted by deterministic quantities. Beside their independence (which still holds), the only property that we used for these coefficients is lower bounds for the quantities , but these quantities become smaller when the densities are shifted, as a straightforward consequence of the explicit density (19) that we have chosen (because this density is an even function, which is non-increasing on ). ∎
3.2 Prevalence
The notion of prevalence supplies an extension of the notion of “almost everywhere” (for the Lebesgue measure) in an infinite dimensional setting. In a metric infinite dimensional vector space, no measure is both -finite and translation invariant. However, a natural notion of “almost everywhere” which is translation invariant can be defined as follows, see [11, 16]; “zero-measure sets” thus defined are called Haar-null.
Definition 3.1**.**
Let E be a complete metric vector space. A Borel set is Haar-null if there exists a compactly supported probability measure such that
[TABLE]
If this property holds, the measure is said to be transverse to .
A subset of E is called Haar-null if it is contained in a Haar-null Borel set. The complement of a Haar-null set is called a prevalent set.
The following results of [11] and [16] enumerate important properties of prevalence:
- •
If S is Haar-nul, then , is Haar-nul.
- •
If the dimension of is finite, S is Haar-null if and only if has Lebesgue measure [math].
- •
Prevalent sets are dense.
- •
The intersection of a countable collection of prevalent sets is prevalent.
- •
If the dimension of is infinite, compact subsets of are Haar-nul.
Remark 3.4**.**
In order to prove that a set is Haar-nul, one can often use for transverse measure the Lebesgue measure on the unit ball of a finite dimensional subset V; Condition (23) becomes
[TABLE]
In this case is called a probe for the complement of .
Remark 3.5**.**
If is a function space, choosing a probability measure on is equivalent to choosing a random process the sample paths of which almost surely belong to a compact subset of . Thus, the definition of a Haar-null set can be rewritten as follows: Let be a property that can be satisfied by points of and let
[TABLE]
The condition means the event has probability zero. Therefore, a way to check that a property holds only on a Haar-null set is to exhibit a random process whose sample paths are in a compact subset of E and is such that
[TABLE]
With a slight abuse of language, when a property holds on a prevalent set, we will say that it holds almost everywhere. In the following theorem, we obtain the optimality of Proposition 2.2 in a prevalent sense.
Theorem 3.2**.**
Let and . If the wavelet system satisfies the dyadic covering property, then the wavelet series of almost every sequence of is maximally divergent in .
Proof.
Let us consider the random sequence introduced in (21). Corollary 4.1 yields that for every given sequence of , almost surely, the wavelet series associated to is maximally divergent in . Moreover, it follows from Theorem 3.1, that the random sequence takes values in a compact subset of . Hence the result when we consider the divergence at points of . Since a countable intersection of prevalent sets is prevalent, the conclusion is obtained by covering with a countable family of cubes. ∎
4 Other generic results of divergence
As soon as an object with some extremal behavior has been exhibited, it is natural to wonder if this behavior is generic, in some sense. Prevalence allows to show that the set formed by these special objects is large in a measure sense. One can also consider the Baire categories genericity, called residuality: There exists a dense set of elements sharing this behavior in a well chosen topological vector space. More recently, the algebraic structure of this kind of sets has also been investigated, using the notion of lineability.
In this section, we obtain the equivalent of Theorem 3.2 in the senses supplied by Baire categories and lineability.
4.1 Residuality
The aim of this section is to construct a countable intersection of dense open sets of the elements of which have maximally divergent wavelet series.
Theorem 4.1**.**
Let and . If the wavelet system satisfies the dyadic covering property, then the set of sequences of whose wavelet series is maximally divergent in is residual in .
Proof.
As usual, it is sufficient to consider divergence rates at points of the unit cube. The idea of the construction is that any sequence whose coefficients are sufficiently close to those of the sequence , whose wavelet coefficients are defined by (18), on infinitely many dyadic cubes will have a maximally divergent wavelet series. Let us study separately different cases.
The case :
We consider the norm
[TABLE]
on . Since , the space is separable and finite sequences with rational coefficients form a dense subspace in this space. Let denote such a dense sequence. For every , there is such that the coefficients of are equal to [math] at scales . Without loss of generality, one can assume that the sequence is increasing. For every , let us define
[TABLE]
By construction, the sequence is dense in . Finally, let us consider the set
[TABLE]
where
[TABLE]
The set is clearly a countable intersection of dense open sets. Moreover, let us remark that if denotes the coefficients of a sequence in , then for every with ,
[TABLE]
If belongs to the residual set , it belongs to infinitely many balls . Clearly, the dyadic covering property and inequality (24) give that at every , the divergence exponent is at least equal to , and as done at the end of the proof of Proposition 3.1, that it is equal to for almost every . Let us now compute the divergence spectrum of . For , let us denote by the set of points satisfying the following property: for infinitely many , there exists such that
[TABLE]
Remark that the definition of is very similar to that of introduced in Proposition 3.2, except that only a subsequence of the integers is used. Consequently, if , we have
[TABLE]
for any index , where denote the dyadic cubes of scale that contain . Using the dyadic covering property, there exists a dyadic cube of scale and an index such that . Together with (24), it gives
[TABLE]
Remark 3.1 concerning the hierarchic property of the coefficients and inequality (25) imply that the divergence rate of at is larger than . The computation of the Hausdorff dimension of is then computed as done for in Proposition 3.2. It follows that the set of points where the divergence rate of is exactly has dimension . The theorem follows.
The case :
This case corresponds to the Hölder space . We consider the norm
[TABLE]
on . For each integer , let us denote by the set of sequences of whose coefficients are each a non-vanishing multiple of . If , then its coefficients satisfy
[TABLE]
Let us set
[TABLE]
and let us notice that the coefficients of any sequence satisfy
[TABLE]
Using this last inequality, Proposition 8 and the dyadic covering property, one directly obtains that the divergence exponent of the wavelet series associated with is exactly at every point.
Let us now define
[TABLE]
If has coefficients and if we define for every , the sequence by
[TABLE]
then . Therefore, is a dense open set (hence a set) of whose element have a divergence exponent equal to at each point, and the conclusion follows.
The cases and :
It suffices to proceed as in the previous cases, with obvious adaptations.
∎
4.2 Lineability
In a nutshell, proving a generic result in the sense of lineability consists in proving that this result holds for every (non zero) element of a subspace of infinite dimension (the cardinality of the space allowing for different variants of the notion). We will define this subspace by defining explicitly an uncountable Hamel basis (indeed, the space considered in the definition of lineability is understood as a space generated by the finite linear combinations of the elements of the basis).
Definition 4.1**.**
Let be a vector space, a subset of , and a cardinal number. The subset is said to be -lineable if contains a vector subspace of dimension . The set is lineable if the existing subspace is infinite dimensional. When is a topological vector space and when the above vector space can be chosen to be dense in , we say that is -dense-lineable (or, simply, dense-lineable if is infinite).
This recent concept has attracted the attention of many authors, see e.g. the detailed review of L. Bernal-González, D. Pellegrino and J.B. Seoane-Sepúlveda [10]. Recently, L. Bernal-González [9] introduced the notion of maximal lineability (and that of maximal dense-lineability) meaning that the dimension of the existing vector space is equal to the dimension of .
The aim of this subsection is to obtain the equivalent of Theorem 4.1 and Theorem 3.2 in the context of lineability. First, let us introduce the sequences which will form the basis of the linear subspace. For every , let us consider the sequence , with
[TABLE]
for every , where the coefficients are defined by (18). Since the sequence belongs to , it is clear that for every . The result of lineability will direcly follow from the next straightforward lemma which states that the coefficients of any linear combination of the sequences are of the order of magnitude of its “largest” component. Therefore, it has the same divergence properties as this component. Moreover, it gives the linear independence of the sequences since no non-zero linear combination of these sequences can be identically equal to [math].
Lemma 4.1**.**
Let and . Let , and , and consider the sequence
[TABLE]
Then, the coefficients of satisfy that
[TABLE]
for every , with large enough.
Theorem 4.2**.**
Let and . If the wavelet system satisfies the dyadic covering property, then the set of sequence of whose wavelet series is maximally divergent in is maximal lineable in .
Proof.
Using the dyadic covering property, Remark 3.2 and Lemma 4.1, one directly gets that any non-zero sequence in the linear span of the sequences has a maximally divergent wavelet series. ∎
Actually, in the separable case, one can slightly modify the above construction in order to get a dense subspace of sequences with maximally divergent wavelet series. It is given by the next result.
Corollary 4.1**.**
Let and . If the wavelet system satisfies the dyadic covering property, then the set of sequence of whose wavelet series is maximally divergent is maximal dense-lineable in .
Proof.
As done in the proof of Theorem 4.1, let denote the dense sequence of finite sequences with rational coefficients. Let us also choose a sequence of different positive numbers. For every , we fix such that
[TABLE]
and we define . By construction, the sequences , , form a dense subspace of . Finally, we consider the subspace generated by the sequences , , and the sequences , , where . Clearly, since it contains the sequences , , the subspace is dense in . Moreover, it has maximal dimension since it contains the linearly independent sequences , . It remains to prove that any non-zero element of has maximally divergent wavelet series. Such an element has, for large scales, the same coefficients as a non-zero linear combination of the sequences , . The conclusion follows then with the same arguments as in Theorem 4.2. ∎
Remark 4.1**.**
In contradistinction with the Baire or prevalence case, the notion of lineability is not stable under intersection. Therefore different lineability results can hold simultaneously: This is the case for Theorem 4.2. In order to be clearer we now mark the dependence in and of the sequence , whose coefficients are given by (18), and denote it by . We now pick such that and . Classical Besov embeddings give . Then, the subspace constructed in Theorem 4.2 or in Corollary 4.1 can also be constructed starting with the sequence instead of , and (13) is replaced by .
5 Maximal divergence at a given point
We now determine the generic divergence exponent at a given (fixed) point of wavelet series associated with sequences in a Besov space.
Proposition 5.1**.**
Let , and . There exist a sequence whose divergence exponent at satisfies
[TABLE]
Proof.
Let be fixed. Using the dyadic covering property, let us consider a sequence of cubes of strictly increasing scales and a sequence of indices such that
[TABLE]
Let us define the sequence by setting for every
[TABLE]
Since there is at most one non-vanishing wavelet coefficients at each scale,
[TABLE]
and clearly belongs to the Besov space . Furthermore, the choice of implies that the divergence exponent of at is larger than , and Proposition 2.2 gives the conclusion. ∎
Let us now extend Proposition 5.1 in the setting of genericity, using the three different notions.
Theorem 5.1**.**
Let , and . The set of sequences such that
[TABLE]
is prevalent, residual and maximal lineable in .
Proof.
Let us start with the notion of prevalence. We will use for probe the space generated by the sequence whose coefficients are given by (26) and prove that, , and for any sequence , the line contains at most one sequence whose wavelet series diverges at rate at most at .
Indeed, suppose that there exist two such sequences corresponding to two values and . Then, by the triangular inequality and the definition of , there are infinitely many scales for which there is such that
[TABLE]
and . Consequently, for infinitely many ,
[TABLE]
and making , we get that .
The proof of residuality relies on arguments similar to those used in the proof of Theorem 4.1: in the case , it suffices to construct the sequence via the coefficients (26) instead of (18) and to consider as radius . Let us notice that one can assume that the sequence of scales of the cubes which appear in the construction (26) grows at most arithmetically (with common difference ). As done previously, it ensures that the wavelet coefficients of the elements of are closed enough to those defined by (26).
The other cases follow from straightforward modifications of these arguments.
As regards lineability, consider for every , the sequence , with
[TABLE]
for every , where the coefficients are defined by (26). As in Lemma 4.1, we notice that the coefficients of any non zero linear combination of the , , are of the order of magnitude of for some . The conclusion follows then directly from Proposition 5.1. ∎
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