Bounded Solutions to Boundary Value Hyperbolic Problems
R.Klyuchnyk, I.Kmit

TL;DR
This paper studies conditions for existence and uniqueness of bounded solutions to first-order hyperbolic boundary value problems in a strip, focusing on zero-order coefficients and dissipativity conditions.
Contribution
It provides new criteria for bounded solutions in hyperbolic systems, emphasizing the role of zero-order coefficients and boundary data.
Findings
Established conditions for existence and uniqueness of solutions.
Identified the importance of zero-order coefficient behavior at infinity.
Formulated dissipativity conditions related to boundary data.
Abstract
We investigate linear boundary value problems for first-order one-dimensional hyperbolic systems in a strip. We establish conditions for existence and uniqueness of bounded continuous solutions. For that we suppose that the non-diagonal part of the zero-order coefficients vanish at infinity. Moreover, we establish a dissipativity condition in terms of the boundary data and the diagonal part of the zero-order coefficients.
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Taxonomy
TopicsDifferential Equations and Numerical Methods · Stability and Controllability of Differential Equations · Advanced Mathematical Modeling in Engineering
Bounded Solutions to Boundary Value
Hyperbolic Problems
R. Klyuchnyk
I. Kmit Institute for Applied Problems of Mechanics and Mathematics, Ukrainian National Academy of Sciences, E-mail: [email protected] University of Berlin, E-mail: [email protected]. On leave from the Institute for Applied Problems of Mechanics and Mathematics, Ukrainian National Academy of Sciences.
Abstract
We investigate linear boundary value problems for first-order one-dimensional hyperbolic systems in a strip. We establish conditions for existence and uniqueness of bounded continuous solutions. For that we suppose that the non-diagonal part of the zero-order coefficients vanish at infinity. Moreover, we establish a dissipativity condition in terms of the boundary data and the diagonal part of the zero-order coefficients.
Key words: first-order hyperbolic systems, boundary value problems, bounded solutions, dissipativity conditions, Fredholm alternative, uniqueness of solutions
Mathematics Subject Classification: 35A17, 35F45, 35L40
1 Introduction
1.1 Problem setting and our result
We investigate the general linear first-order hyperbolic system in a single space variable
[TABLE]
subjected to the boundary conditions
[TABLE]
where are positive integers and is a linear bounded operator from to . Here and below by we will denote the vector space of all bounded and continuous maps , with the norm
[TABLE]
Similarly, by we will denote a Banach space of all such that , with the norm
[TABLE]
Also, we use the notation for the space of all bounded and continuous maps and the notation for the space of all with . For simplification, we will skip subscript if .
We make the following assumptions on the coefficients of (1.1):
[TABLE]
[TABLE]
Suppose also that
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and
[TABLE]
Let us introduce the characteristics of the hyperbolic system (1.1). Given , , and , the -th characteristic is defined as the solution of the initial value problem
[TABLE]
To shorten notation, we will simply write . Set
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Integration along the characteristic curves brings the system (1.1)–(1.2) to the integral form
[TABLE]
By straightforward calculation, one can easily show that a - map is a solution to the PDE problem (1.1)–(1.2) if and only if it satisfies the system (1.9)–(1.10). This motivates the following definition.
Definition 1.1
A function is called a bounded continuous solution to (1.1)–(1.2) if it satisfies (1.9) and (1.10).
Introduce an operator by
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Theorem 1.2
Suppose that the conditions (1.3)–(1.6) are fulfilled. Moreover, assume that there exists such that
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and
[TABLE]
Then the problem (1.1)–(1.2) has a unique bounded continuous solution .
Example 1.3
The following example shows that if the conditions (1.6) and (1.13) are not satisfied, then the statement of Theorem 1.2 is not true, in general. Specifically, we consider the problem
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[TABLE]
Obviously, (1.14)–(1.15) is a particular case of (1.1)–(1.2) and satisfies all assumptions of Theorem 1.2 with the exception of (1.6) and (1.13). It is straightforward to check that
[TABLE]
are infinitely many linearly independent bounded continuous (-periodic in ) solutions to the problem (1.14)–(1.15). This means that the kernel of the operator of (1.14)–(1.15) is infinite dimensional. Thus, the uniqueness conclusion of Theorem 1.2 is not true.
In Section 1.2 we give a brief motivation of our investigations. In Section 2 we prove the Fredholm alternative for (1.1)–(1.2) (Theorem 2.1), while in Section 3 – a uniqueness result for (1.1)–(1.2) (Theorem 3.1). Theorem 1.2 will then straightforwardly follow from Theorems 2.1 and 3.1.
1.2 Motivation and state of the art
Systems of the type (1.1)–(1.2) are used to model problems of laser dynamics [12, 14, 16], chemical kinetics [17], chemotaxis [15] and population dynamics [3]. Another area of applications of such models is boundary control problems [1, 13]. In many mathematical models the system (1.1) is controlled by the so-called reflection boundary conditions what is a particular case of (1.2).
In [2] Coppel proved the Dichotomy theorem for the linear ODE, namely . It claims that the inhomogeneous equation has a unique bounded continuous solution on for every bounded and continuous function if and only if the homogeneous equation has an exponential dichotomy on . In [10] the authors provide a criterion of the existence of exponential dichotomy on for a strongly continuous exponentially bounded evolution family on a Banach space in terms of existence and uniqueness of a bounded continuous mild solutions. In this respect, our result is an important step towards the existence of the exponential dichotomy for boundary value hyperbolic problems.
The correct posedness of a particular case of (1.1)–(1.2) was investigated in [5]. Specifically, the authors studied the system (1.1) with the boundary conditions
[TABLE]
and investigate existence and uniqueness of continuous but not necessarily bounded solutions solutions. The main assumption imposed in [5] is a smallness of all in a neighborhood of . It comes from the Banach fixed point argument used in the proof of the main result. In comparison, in the present paper, we allow for to be elements of only, and for with we impose the assumption (1.13). Moreover, after the changing of variables in (1.1) and (1.16) we get . This means that the dissipativity conditions (1.12) is satisfied here automatically (with ).
In [7, 8, 9] time-periodic solutions to the system (1.1) with reflection boundary conditions are investigated. It is suggested a rather general approach to proving the Fredholm alternative in spaces of time-periodic functions (in the autonomous case [8]) and in the space of continuous and time-periodic functions (in the non-autonomous case [9]). In the present paper, we extend this approach from the spaces of periodic functions to the spaces of bounded functions and prove the Fredholm alternative for quite general boundary conditions. Note that, when the problem (1.1)–(1.2) is considered in the space of continuous and periodic in time functions, then according to the standard terminology (1.12) means non-resonant behavior of (1.1)–(1.2).
2 Fredholm alternative
We use the notation
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Define linear bounded operators by
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and
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On the account of (1.11), (2.1), and (2.2), the system (1.9)–(1.10) can be written as the operator equation
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Theorem 2.1
Suppose that all conditions of Theorem 1.2 are fulfilled. Let denote the vector space of all bounded continuous solutions to (1.1)–(1.2) with . Then
* and the vector space of all such that there exists a bounded continuous solution to (1.1)–(1.2) is a closed subspace of codimension in .*
* If , then for any there exists a unique bounded continuous solution to (1.1)–(1.2).*
One of the technical tools we employ for the proof is a generalized Arzela-Ascoli compactness criteria for unbounded domains, see [11]. To formulate it, we need a corresponding notion of equicontinuity.
Definition 2.2
A family is called equicontinuous on if
- •
* is equicontinuous on any compact set in , and*
- •
for any there exists such that
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for all , all , and all .
Theorem 2.3
*(*a generalized Arzela-Ascoli theorem) A family is precompact in if and only if is bounded in and equicontinuous on .
Proof of Theorem 2.1. First observe that the operator is bijective, what straightforwardly follows from the Banach fixed-point theorem and the condition (1.12). Then the operator is Fredholm of index zero if and only if
[TABLE]
Nikolsky’s criterion [4, Theorem XIII.5.2] says that an operator on a Banach space is Fredholm of index zero whenever is compact. Hence, we are done with (2.5) if we show that the operator is compact. As the composition of a compact and a bounded operator is a compact operator, it is enough to show that
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Since and is bounded, it is sufficient to prove that
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To show (2.6), we use Theorem 2.3. Given , set . Fix an arbitrary bounded set . For (2.6) it is sufficient to prove the following two statements:
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and
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We start with the proving (2.7). Denote by (respectively ) the Banach space of continuous (respectively continuously differentiable) vector functions on . As is compactly embedded into (due to the Arzela-Ascoli theorem), it is sufficient to show that
[TABLE]
It should be noted that for all sufficiently large the functions and restricted to depend only on restricted to .
We will use the following formulas
[TABLE]
[TABLE]
being true for all , all , and all . Here and below by we denote the partial derivative with respect to the -th argument. Then for all sufficiently large the partial derivatives , , , and on exist and are continuous for all . Since is dense in , then the desired property (2.9) will follow from the bound
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This bound is proved similarly to [9, Lemma 4.2]:
We start with the estimate
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Given and , let us consider the following representation for obtained after the application of the Fubini’s theorem:
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where
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It is easy to see, that from (2.13) follows that
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Since
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for all , and , one can easily check that
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Hence the estimate will follow from the following one:
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We are therefore reduced to prove (2.15). To this end, we start with the following consequence of (2.13):
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Let us transform the second summand. Using (1.7), (2.10), and (2.11), we get
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Therefore,
[TABLE]
where the functions are fixed to satisfy (1.6). Note that are not uniquely defined by (1.6) for with . Nevertheless, as it follows from (2), the right-hand side (and, hence, the left-hand side of (2.17)) do not depend on the choice of , since if .
Write
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where are introduced by (2.14) and (1.8). Using (1.7) and (2.10), we see that the function is -smooth in due to the regularity assumptions (1.3) and (1.6). Similarly, using (2.11), we see that the functions and are -smooth in .
By (2.17) we have
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The desired estimate (2.15) now easily follows from the assumptions (1.3), (1.4), (1.6) and the equations (2.13) and (2).
To finish with (2.9), it remains to show that
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as the estimate for follows similarly to the case of . In order to prove (2.19), we consider an arbitrary integral contributing into , namely
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where
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and and are arbitrary fixed. From (2.20) follows that
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Differentiating (2.20) in , we get
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Our task is to estimate the second integral; for the first one the desired estimate is obvious. Similarly to the above, we use (1.7), (2.10), and (2.11) to obtain
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Taking into account (1.6), the last expression reads
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Set
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Using (2.10) and (2.22), let us transform the second summand in (2) as
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The bound (2.19) now easily follows from (2) and (2.23). This finishes the proof of the bound (2.12) and, hence the statement (2.7).
It remains to prove (2.8). Fix an arbitrary . We have to prove the estimates
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and
[TABLE]
for all and all , and some .
Let us prove (2.24). By (2.13), given and , we have
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the constant being dependent on , and but not on and with . Since is bounded on , the desired estimate (2.24) now straightforwardly follows from the assumption (1.13) and the fact that as .
The estimate (2.25) can be obtained by the same argument, what finishes the proof of (2.8). The theorem is proved.
3 Uniqueness of a bounded continuous solution
Theorem 3.1
Suppose that the conditions (1.3), (1.4), and (1.12) are fulfilled. Then there is and such a bounded continuous solution to (1.1)–(1.2) (if any) is unique whenever
[TABLE]
**Proof. ** Given , let and . Given , consider the problem (1.1)–(1.2) in . The system of integral equations can again be written in the operator form with operators given by the rules (1.11), (2.1) and (2.2), respectively. As the operator is bijective (by the condition (1.12)), the operator equation reads
[TABLE]
Because of assumption (3.26), the value of can be chosen so large that the norm of the operator is sufficiently small. Consequently, for such we have
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By the Banach fixed-point theorem, there exists a unique function satisfying (1.9)–(1.10) in .
Now consider the problem (1.1)–(1.2) in with the initial condition
[TABLE]
Existence and uniqueness of a continuous solution to the initial-boundary value problem (1.1), (1.2), (3.28) follows from [6]. Summarizing, the problem (1.1), (1.2) in the strip has a unique continuous solution bounded at . This immediately entails that a bounded continuous solution to the problem (1.1)–(1.2) (if any) is unique. The proof is therewith complete.
To finish with Theorem 1.2, it remains to note that, by Theorem 3.1, . Then Theorem 1.2 immediately follows from Theorem 2.1 .
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