Physics Potential of a Long Baseline Neutrino Oscillation Experiment Using J-PARC Neutrino Beam and Hyper-Kamiokande

TL;DR

This paper evaluates the physics potential of a long baseline neutrino experiment using Hyper-Kamiokande and J-PARC, focusing on measuring CP violation and neutrino oscillation parameters with high precision.

Contribution

It presents a detailed analysis of the expected sensitivity of Hyper-Kamiokande to leptonic CP violation and neutrino mixing parameters using realistic systematic uncertainties.

Findings

CP phase $ heta_{CP}$ can be determined within 19 degrees.

CP violation can be established at more than 3σ significance for 76% of $ heta_{CP}$ values.

Uncertainty in $ heta_{23}$ measurement is as low as 0.006.

Abstract

Hyper-Kamiokande will be a next generation underground water Cherenkov detector with a total (fiducial) mass of 0.99 (0.56) million metric tons, approximately 20 (25) times larger than that of Super-Kamiokande. One of the main goals of Hyper-Kamiokande is the study of $CP$ asymmetry in the lepton sector using accelerator neutrino and anti-neutrino beams. In this paper, the physics potential of a long baseline neutrino experiment using the Hyper-Kamiokande detector and a neutrino beam from the J-PARC proton synchrotron is presented. The analysis uses the framework and systematic uncertainties derived from the ongoing T2K experiment. With a total exposure of 7.5 MW $\times$ 10$^7$ sec integrated proton beam power (corresponding to $1.56\times10^{22}$ protons on target with a 30 GeV proton beam) to a $2.5$-degree off-axis neutrino beam, it is expected that the leptonic $CP$ phase $\delta_{CP}$ can be determined to better than 19 degrees for all possible values of $\delta_{CP}$, and $CP$ violation can be established with a statistical significance of more than $3\,\sigma$ ($5\,\sigma$) for $76\%$ ($58\%$) of the $\delta_{CP}$ parameter space. Using both $\nu_e$ appearance and $\nu_\mu$ disappearance data, the expected 1$\sigma$ uncertainty of $\sin^2\theta_{23}$ is 0.015(0.006) for $\sin^2\theta_{23}=0.5(0.45)$.