$\R^{n} \rtimes G(n)$ is Algebraically Determined
We'am M. Al-Tameemi, and Robert R. Kallman

TL;DR
This paper proves that the semidirect product of ^n and certain linear groups over ^n is algebraically determined, meaning algebraic isomorphisms are also topological, highlighting its unique structural rigidity among similar groups.
Contribution
It establishes the algebraic determinedness of ^n times G(n) for various linear groups G(n), a property not shared by some related groups, advancing understanding of their topological and algebraic structure.
Findings
^n times G(n) is algebraically determined for specified G(n).
^n times G(n) groups are topologically rigid under algebraic isomorphisms.
Key intermediate result: ^n times SO(n,) has an analytic subgroup structure.
Abstract
Let be a Polish (i.e., complete separable metric topological) group. Define to be an algebraically determined Polish group if for any Polish group and algebraic isomorphism , we have that is a topological isomorphism. Let be the set of matrices with real coefficients and let the group in the above definition be the natural semidirect product , where and is one of the following groups: either the general linear group , or the special linear group , or or . These groups are of fundamental importance for linear algebra and…
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Taxonomy
TopicsAdvanced Topology and Set Theory · Limits and Structures in Graph Theory · Mathematical and Theoretical Analysis
