The Merrifield-Simmons conjecture also holds for parity graphs
Martin Trinks

TL;DR
This paper proves the Merrifield-Simmons conjecture for parity graphs, establishing a relationship between vertex distances and independent set counts in these graphs, with implications for graph theory conjectures.
Contribution
The paper confirms the Merrifield-Simmons conjecture specifically for parity graphs, providing the first proof for this class and suggesting limitations for generalization.
Findings
The conjecture holds for parity graphs.
Evidence suggests the conjecture may not extend to other graph classes.
Provides a new proof for a longstanding conjecture in a specific graph class.
Abstract
The Merrifield-Simmons conjectures states a relation between the distance of vertices in a simple graph and the number of independent sets, denoted as , in vertex-deleted subgraphs. Namely, that the sign of the term only depends on the parity of the distance of and in . We prove this statement in the case of parity graphs and give some evidence that this result may not be further generalized to other classes of graphs.
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Taxonomy
TopicsAdvanced Graph Theory Research · Graph theory and applications · Graph Labeling and Dimension Problems
