Equivalence of domains with isomorphic semigroups of endomorphisms
Sergei Merenkov

TL;DR
This paper extends a 1993 result by Eremenko, demonstrating that for bounded domains in complex n-space, isomorphic semigroups of analytic endomorphisms imply the domains are equivalent via a conformal or anticonformal map.
Contribution
It generalizes Eremenko's 1993 theorem from the complex plane to higher-dimensional complex spaces, establishing domain equivalence through semigroup isomorphisms.
Findings
Semigroups of endomorphisms determine domain equivalence
Isomorphism implies conjugation by conformal or anticonformal maps
Generalization from to n in complex analysis
Abstract
For two bounded domains in the complex plane whose semigroups of analytic endomorphisms are isomorphic, Eremenko proved in 1993 that the isomorphism is given as a conjugation by a conformal or anticonformal map. In the present paper we prove an analogue of this result for the case of bounded domains in \mathbb C^n.
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Taxonomy
TopicsHolomorphic and Operator Theory · Advanced Topics in Algebra · Algebraic and Geometric Analysis
