Viability of Noether symmetry of F(R) theory of gravity
Kaushik Sarkar, Nayem Sk., Subhra Debnath, and Abhik Kumar Sanyal

TL;DR
This paper investigates the limitations of using Noether symmetry to analyze F(R) gravity theories, showing that it cannot accommodate non-linear forms or scalar fields, but highlights the existence of a non-Noether conserved current useful for cosmological solutions.
Contribution
It demonstrates the constraints of Noether symmetry in F(R) gravity, especially with scalar fields, and emphasizes the significance of non-Noether conserved currents for cosmological modeling.
Findings
Noether symmetry does not allow linear or non-linear F(R) forms with scalar fields.
Existing Noether symmetry in literature is not reproduced in this analysis.
A non-Noether conserved current exists and aids in finding cosmological solutions.
Abstract
Canonization of F(R) theory of gravity to explore Noether symmetry is performed treating R - 6(\frac{\ddot a}{a} + \frac{\dot a^2}{a^2} + \frac{k}{a^2}) = 0 as a constraint of the theory in Robertson-Walker space-time, which implies that R is taken as an auxiliary variable. Although it yields correct field equations, Noether symmetry does not allow linear term in the action, and as such does not produce a viable cosmological model. Here, we show that this technique of exploring Noether symmetry does not allow even a non-linear form of F(R), if the configuration space is enlarged by including a scalar field in addition, or taking anisotropic models into account. Surprisingly enough, it does not reproduce the symmetry that already exists in the literature (A. K. Sanyal, B. Modak, C. Rubano and E. Piedipalumbo, Gen.Relativ.Grav.37, 407 (2005), arXiv:astro-ph/0310610) for scalar tensor…
Peer Reviews
No public reviews on file for this paper yet. If you reviewed it on a platform where reviews are public (OpenReview, ICLR, NeurIPS, ICML), you can paste yours below so the community can read it here.
Videos
No videos yet. Explain this paper in a talk, walkthrough, or lecture? Add one.
