Decorated Shastry-Sutherland lattice in the spin-1/2 magnet CdCu2(BO3)2
O. Janson, I. Rousochatzakis, A. A. Tsirlin, J. Richter, Yu. Skourski,, and H. Rosner

TL;DR
This paper develops a detailed magnetic model for CdCu2(BO3)2, a quantum magnet with a 1/2-magnetization plateau, revealing its relation to the decorated anisotropic Shastry-Sutherland lattice and explaining its magnetic ordering.
Contribution
The study presents the first comprehensive microscopic magnetic model for CdCu2(BO3)2, incorporating four exchange couplings and explaining its magnetic properties and long-range order.
Findings
Identified four key exchange couplings in CdCu2(BO3)2.
The model explains the 1/2-magnetization plateau.
CdCu2(BO3)2 is a realization of the decorated anisotropic Shastry-Sutherland lattice.
Abstract
We report the microscopic magnetic model for the spin-1/2 Heisenberg system CdCu2(BO3)2, one of the few quantum magnets showing the 1/2-magnetization plateau. Recent neutron diffraction experiments on this compound [M. Hase et al., Phys. Rev. B 80, 104405 (2009)] evidenced long-range magnetic order, inconsistent with the previously suggested phenomenological magnetic model of isolated dimers and spin chains. Based on extensive density-functional theory band structure calculations, exact diagonalizations, quantum Monte Carlo simulations, third-order perturbation theory, as well as high-field magnetization measurements, we find that the magnetic properties of CdCu2(BO3)2 are accounted for by a frustrated quasi-2D magnetic model featuring four inequivalent exchange couplings: the leading antiferromagnetic coupling J_d within the structural Cu2O6 dimers, two interdimer couplings J_t1 and…
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