On conjugations of circle homeomorphisms with two break points

TL;DR

This paper investigates the conjugation properties of circle homeomorphisms with two break points, showing that under certain conditions, the conjugating map is a singular function with zero derivative almost everywhere.

Contribution

It establishes that conjugacies between such homeomorphisms are singular functions when the products of their jump ratios differ, extending understanding of their structural dynamics.

Findings

Conjugating maps are singular functions under specified conditions.

The derivative of the conjugacy is zero almost everywhere.

The result applies to circle homeomorphisms with two break points and identical irrational rotation numbers.

Abstract

Let $f_i\in C^{2+\alpha}(S^1\setminus \{a_i,b_i\}), \alpha >0, i=1,2$ be circle homeomorphisms with two break points $a_i,b_i$, i.e. discontinuities in the derivative $f_i$, with identical irrational rotation number $rho$ and $\mu_1([a_1,b_1])= \mu_2([a_2,b_2])$, where $\mu_i$ are invariant measures of $f_i$. Suppose the products of the jump ratios of $Df_1$ and $Df_2$ do not coincide, i.e. $\frac{Df_1(a_1-0)}{Df_1(a_1+0)}\times \frac{Df_1(b_1-0)}{Df_1(b_1+0)}\neq \frac{Df_2(a_2-0)}{Df_2(a_2+0)}\times \frac{Df_2(b_2-0)}{Df_2(b_2+0)}$. Then the map $\psi$ conjugating $f_1$ and $f_2$ is a singular function, i.e. it is continuous on $S^1$, but $D\psi = 0$ a.e. with respect to Lebesgue measure