Revolutionaries and Spies

TL;DR

This paper analyzes a pursuit-evasion game on graphs called 'Revolutionaries and Spies', establishing bounds on the minimum number of spies needed to prevent revolutionaries from capturing a vertex, with specific results on integer lattice graphs.

Contribution

It introduces the game 'Revolutionaries and Spies', formalizes the problem, and derives lower bounds for the number of spies needed on integer lattice graphs for certain parameters.

Findings

For $d \\geq 2$, $s(\\Z^d,r,2) \\geq 6 \\lfloor r/8 \\rfloor$

Defines the game and formalizes the problem of pursuit and evasion on graphs

Provides bounds on the minimum number of spies required to prevent revolutionaries from winning.

Abstract

Let $G = (V,E)$ be a graph and let $r,s,k$ be positive integers. "Revolutionaries and Spies", denoted $\cG(G,r,s,k)$, is the following two-player game. The sets of positions for player 1 and player 2 are $V^r$ and $V^s$ respectively. Each coordinate in $p \in V^r$ gives the location of a "revolutionary" in $G$. Similarly player 2 controls $s$ "spies". We say $u, u' \in V(G)^n$ are adjacent, $u \sim u'$, if for all $1 \leq i \leq n$, $u_i = u'_i$ or ${u_i,u'_i} \in E(G)$. In round 0 player 1 picks $p_0 \in V^r$ and then player 2 picks $q_0 \in V^s$. In each round $i \geq 1$ player 1 moves to $p_i \sim p_{i-1}$ and then player 2 moves to $q_i \sim q_{i-1}$. Player 1 wins the game if he can place $k$ revolutionaries on a vertex $v$ in such a way that player 1 cannot place a spy on $v$ in his following move. Player 2 wins the game if he can prevent this outcome. Let $s(G,r,k)$ be the minimum $s$ such that player 2 can win $\cG(G,r,s,k)$. We show that for $d \geq 2$, $s(\Z^d,r,2)\geq 6 \lfloor \frac{r}{8} \rfloor$. Here $a,b \in \Z^{d}$ with $a \neq b$ are connected by an edge if and only if $|a_i - b_i| \leq 1$ for all $i$ with $1 \leq i \leq d$.