The 1-fixed-endpoint Path Cover Problem is Polynomial on Interval Graph

TL;DR

This paper proves that the 1-fixed-endpoint path cover problem on interval graphs can be solved efficiently in polynomial time, providing a simple $O(n^2)$ algorithm that also addresses the 1HP problem.

Contribution

It introduces a polynomial-time algorithm for the 1-fixed-endpoint path cover problem on interval graphs, resolving an open problem for this graph class.

Findings

The algorithm runs in $O(n^2)$ time.

It requires linear space.

It also solves the 1HP problem on interval graphs.

Abstract

We consider a variant of the path cover problem, namely, the $k$-fixed-endpoint path cover problem, or kPC for short, on interval graphs. Given a graph $G$ and a subset $\mathcal{T}$ of $k$ vertices of $V(G)$, a $k$-fixed-endpoint path cover of $G$ with respect to $\mathcal{T}$ is a set of vertex-disjoint paths $\mathcal{P}$ that covers the vertices of $G$ such that the $k$ vertices of $\mathcal{T}$ are all endpoints of the paths in $\mathcal{P}$. The kPC problem is to find a $k$-fixed-endpoint path cover of $G$ of minimum cardinality; note that, if $\mathcal{T}$ is empty the stated problem coincides with the classical path cover problem. In this paper, we study the 1-fixed-endpoint path cover problem on interval graphs, or 1PC for short, generalizing the 1HP problem which has been proved to be NP-complete even for small classes of graphs. Motivated by a work of Damaschke, where he left both 1HP and 2HP problems open for the class of interval graphs, we show that the 1PC problem can be solved in polynomial time on the class of interval graphs. The proposed algorithm is simple, runs in $O(n^2)$ time, requires linear space, and also enables us to solve the 1HP problem on interval graphs within the same time and space complexity.