Reaction of electron-positron to omega and pi mesons and rho(1450) and rho(1700) mesons in quark model

TL;DR

This paper models the e+e- to omega pi0 reaction using a nonrelativistic quark model, showing that intermediate rho mesons dominate the process and supporting the classification of rho(1450) and rho(1700) as 2S and 1D states respectively.

Contribution

It demonstrates that the 3P0 quark model accurately reproduces experimental cross sections and clarifies the nature of rho(1450) and rho(1700) mesons.

Findings

The reaction is dominated by a two-step process involving rho and rho' mesons.

The model reproduces experimental cross sections well.

Supports rho(1450) as a 2S meson and rho(1700) as a 1D meson.

Abstract

The investigation in the work of the reaction electron-positron to omega and pi0 mesons in the 3P0 nonrelativistic quark model reveals that the reaction electron-positron to omega and pi0 mesons process at the energy region from the omega and pi mesons threshold to 2.0 GeV is dominated by the two-step process in which the primary quark-antiquark pair first forms rho and rho' mesons and then the vector mesons decay into omega and pi. With rho(1450) and rho(1700) mainly in 2S and 1D states respectively, the experimental data for the cross section of the reaction electron-positron to omega and pi0 mesons are well produced in the 3P0 quark model. The work supports the argument that rho(1450) is mainly a 2S meson and rho(1700) a 1D meson.